how many ways to arrange 12 identical apples and five distinct oranges in a row so no two oranges are side by side?

The calculations, we can see that the values of r, x, and y do not satisfy the equation r = x - y , it is not possible to determine the unknown value of x using the given data.

To find the value of x using the formula r = x - y, we need to determine the corresponding values of r, x, and y from the given data.

Based on the provided data, we have:

r | x | y

10 | 11 | 12

12 | 13 | 16

13 | 14 | 17

14 | 15 | 18

To calculate the r-value, we can use the formula r = x - y. Let's apply this formula to each row of the data:

r = 10, x = 11, y = 12

10 = 11 - 12

r = 12, x = 13, y = 16

12 = 13 - 16

r = 13, x = 14, y = 17

13 = 14 - 17

r = 14, x = 15, y = 18

14 = 15 - 18

From the calculations, we can see that the values of r, x, and y do not satisfy the equation r = x - y. Therefore, it is not possible to determine the unknown value of x using the given data.

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A pentagonal prism is a 3-dimensional shape with two pentagons as its base, five rectangular faces, and nine edges. It has ten vertices, five on each pentagon.

A pentagonal prism is a 3-dimensional shape with two parallel pentagons as its base. It has five rectangular faces, each with a pentagon at each end, and nine edges which connect the five faces. The pentagonal prism has ten vertices in total; five on each pentagon. The pentagons are in the same plane, with the rectangular faces in between them extending outwards. The pentagonal prism is a polyhedron, meaning that it has flat faces and straight edges. The edges of a pentagonal prism are all the same length, and each of its rectangular faces has the same area. The height of the prism is the distance between the two pentagons. Pentagonal prisms can be used to make various objects such as boxes, and can also be used to make tessellations.

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The two sets of three consecutive integers that meet the criteria, after the calculations are (-1, 0, 1) and (4, 5, 6).

To find three consecutive integers such that four times the sum of all three is two times the product of the larger two, follow these steps:

1. Let the three consecutive integers be x, x+1, and x+2.
2. According to the problem, 4 times the sum of these integers is equal to 2 times the product of the larger two. So, we can write the equation: 4(x + (x+1) + (x+2)) = 2((x+1)(x+2)).
3. Simplify the equation: 4(3x + 3) = 2(x^2 + 3x + 2).
4. Expand the equation: 12x + 12 = 2x^2 + 6x + 4.
5. Move all terms to one side of the equation to form a quadratic equation: 2x^2 - 6x - 8 = 0.
6. Factor the equation: 2(x^2 - 3x - 4) = 0.
7. Solve the quadratic equation: (x-4)(x+1) = 0.
8. Find the integer solutions: x = 4 or x = -1.

So, the two sets of three consecutive integers that meet the criteria are (-1, 0, 1) and (4, 5, 6).

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The 95% confidence interval for the mean is (1.6048, 1.6352).Hence, option (d) is the correct answer.

As given, a machine that is programmed to package 1.60 pounds of cereal is being tested for its accuracy in a sample of 40 cereal boxes, the sample mean filling weight is calculated as 1.62 pounds. The population standard deviation is known to be 0.06 pounds. We are required to find the 95% confidence interval for the mean. Here are the steps to solve this problem:

The formula to find the confidence interval is as follows;

Lower limit = x - zα/2 (σ/√n)

Upper limit = x + zα/2 (σ/√n)

Where,

x= sample mean

zα/2 = z-value of the level of significance

σ = population standard deviation

n = sample size

We are given;

x = 1.62 pounds

σ = 0.06 pounds

n = 40

We need to find the z-value of the level of significance, which can be found using the z-table or by using the calculator.Using the z-table, we get the z-value at 95% confidence interval as zα/2 = 1.96

Substituting the values, we get

Lower limit = 1.62 - 1.96(0.06/√40)

Upper limit = 1.62 + 1.96(0.06/√40)

Lower limit = 1.6048, Upper limit = 1.6352

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Answer:

Center  = (1,2)  radius = 2

Step-by-step explanation:

I used Demos to graph the circle.

Then I added two line to find the center of the circle

The radius is 2

just to clarify, bank loans over such a period and for such purposes are using a compound interest rate, and often, not always the compounding period is yearly, so we'll be assuming is a compound interest per year.

\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$300000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &25 \end{cases} \\\\\\ A=300000\left(1+\frac{0.08}{1}\right)^{1\cdot 25}\implies A=300000(1.08)^{25}\implies A\approx 2054542.56\)

Mrs. Morris wants to borrow $300,000 from the bank. If she gets an interest rate of 8% and has to pay off her loan in 25 years. Over the next 25 years, the total interest will be $ 600,000.

If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:

\(I = \dfrac{P \times R \times T}{100}\)

Mrs. Morris wants to borrow $300,000 from the bank. If she gets an interest rate of 8% and has to pay off her loan in 25 years.

Principal = P = $ 300,000

Rate = R= 8 %

Time = T= 25 years

Simple Interest

\(I = \dfrac{P \times R \times T}{100}\)

\(I = \dfrac{300,000 \times 8 \times 25}{100}\\\\I = 600000\)

SI= $ 600,000

Over the next 25 years, the total interest will be $ 600,000.

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The equation showing the relation between shorter and longer skirt is 3s+4t = 140.

Given that the Scottish dance team used 140 yards of tartan to make dancing skirts.

The skirt pattern for the shorter members is 3- yards of fabric, and the skirt pattern for the taller members is 4 yards of fabric.

So, we need to find the equation represents the relationship between the number of short skirts and the number of long skirts that were made,

So, if there are s short skirts and t long skirts,

So,

The relation will be =

3s + 4t = 140

Hence the equation showing the relation between shorter and longer skirt is 3s+4t = 140.

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If the assumption for using the chi-square statistic, which specifies the number of frequencies in each category, is violated, the researcher has a few options to address this issue:

1. Combine categories: If some categories have very low expected frequencies, they can be combined with adjacent categories to increase the expected frequencies. This helps to meet the assumption of having a minimum expected frequency in each category.

2. Recategorize data: The researcher can also recategorize the data by collapsing categories or creating new categories that have more balanced frequencies. This can help to ensure an adequate number of observations in each category.

3. Use alternative statistical tests: If the assumptions for using the chi-square statistic cannot be met, the researcher can consider using alternative statistical tests. For example, if the data have a small sample size or violate the assumption of expected frequencies, Fisher's exact test or Monte Carlo simulation can be used as alternatives.

It is important for the researcher to carefully consider the specific circumstances and consult with a statistician to determine the most appropriate approach when the assumptions for using the chi-square statistic are violated.

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The reciprocal relationship of the graph is graph (a)

The reciprocal relationship implies that:

The x and the y axes are swapped.

When the x and the y axes are swapped, the value on both axes swap their positions

As per the given graph, the reciprocal relationship is represented by graph (a)

This is shown in the attached graph

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Answer:

Choose 0 to substitute in for x to find the ordered pair. Remove parentheses. Simplify 3(0)−10 3 ( 0 ) - 10 .

Step-by-step explanation:

Answer:

\(x=\frac{-3d-9}{k-d}\)

Step-by-step explanation:

Step 1: Write out equation

d(-3 + x) = kx + 9

Step 2: Distribute

-3d + dx = kx + 9

Step 3: Subtract dx on both sides

-3d = kx - dx + 9

Step 4: Subtract 9 on both sides

-3d - 9 = kx - dx

Step 5: Factor

-3d - 9 = x(k - d)

Step 6: Divide both sides by k - d

\(x=\frac{-3d-9}{k-d}\)

Answer:

Step-by-step explanation:

Step 1: Write out equation

d(-3 + x) = kx + 9

Step 2: Distribute

-3d + dx = kx + 9

Step 3: Subtract dx on both sides

-3d = kx - dx + 9

Step 4: Subtract 9 on both sides

-3d - 9 = kx - dx

Step 5: Factor

-3d - 9 = x(k - d)

Step 6: Divide both sides by k - d

The system has no solution, there is no particular solution x₀, and the general solution does not exist in this case.

The equation Ax = b, where A is a 3x3 matrix and b is a 3x1 column vector, represents a system of linear equations. To find all solutions of this system, we can either use Gaussian elimination or Cramer's rule.

In this case, A = [[2, -5, 3], [-2, 6, -5], [-4, 7, 0]] and b = [[-3], [4], [3]].

Using Gaussian elimination, we can transform the matrix A into its reduced row echelon form and then use back substitution to solve for the variables. The reduced row echelon form of A is:

[[1, 0, 1/2], [0, 1, -5/2], [0, 0, 0]]

Since the last row is all zeros except for the last entry, the system is inconsistent and has no solution.

Alternatively, we can use Cramer's rule to find the solution. The formula for Cramer's rule is:

x_i = det(A_i) / det(A), where A_i is the matrix A with the i th column replaced by the vector b.

In this case, det(A) = 0, so the system has no solution.

The general solution of this system of linear equations is the set of all linear combinations of the columns of A. If the system has a solution, the general solution can be expressed in the parametric vector form as:

x = x₀ + t₁ * v₁ + t₂ * v₂, where x₀ is a particular solution, v₁ and v₂ are the non-trivial solutions, and t₁ and t₂ are scalar parameters.

Since the system has no solution, there is no particular solution x_0, and the general solution does not exist in this case.

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Multiply the average by the number of exams to find total points:

8 x 55 = 440

9 x 60 = 540

The score of the 9th exam is the difference between the two totals:

540 - 440 = 100

They scored a 100

Geometics is a term that describes the computerization and digitization of data collection. The correct answer is C) computerization and digitization of data collection.

Geometics refers to the use of computers and digital instruments to collect, store, analyze, and display data related to measurement and mapping. It involves the use of technologies such as Geographic Information Systems (GIS), Global Positioning Systems (GPS), and remote sensing to capture and process spatial information.

Here is a step-by-step explanation:

1. Geometics involves the use of computers and digital instruments. This means that technology plays a crucial role in the process of collecting and managing data.

2. It focuses on global measurements. Geometics deals with data that is related to measurement and mapping on a global scale. This can include information about land features, topography, elevation, and other geographical characteristics.

3. Geometics also involves the computerization and digitization of data collection. This means that data is collected using digital devices, such as GPS receivers or satellite imagery, and stored in digital formats. This allows for efficient data management, analysis, and visualization.

4. Lastly, data measurements are an important part of geometics. The process of collecting data involves taking accurate measurements of various attributes, such as distances, angles, and coordinates. These measurements are then used to create maps, perform spatial analysis, and make informed decisions in fields like urban planning, transportation, and environmental management.

In summary, geometics is a term that describes the computerization and digitization of data collection, particularly in the context of global measurements. It involves the use of computers, digital instruments, and technologies like GIS and GPS to capture and process spatial information.

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The equation for the total amount of money spent in a given month using Net Films is y = 10 + 2x

An equation is a mathematical statement that shows the relationship between different variables. In this case, we want to find the total amount of money spent, which we'll call "y". The amount of money spent depends on two factors: the fixed monthly cost of $10, and the variable cost based on the number of videos rented. We'll call the number of videos rented "x".

So, the equation for the total amount of money spent in a given month using Net Films is:

y = 10 + 2x

Let's break down what this equation means. The "10" represents the fixed monthly cost of $10 charged by Net Films. The "2x" represents the variable cost, which depends on the number of videos rented. The "x" represents the number of videos rented, and the "2" represents the cost per video rented, which is $2.

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Complete Question:

Two online movie rental companies offer different plans. Net Films charges $10 per month plus $2 for each video you rent. Web Flix charges $3 per month plus $3 per film.

A) Write an equation that shows the total amount of money (x) spent in a given month (y) using Net Films.

Answer:

2697.24

Step-by-step explanation:

you have to do 1.69 times 2 and that equals 3.38 and now you do 3.38 times 798 and you get 2697.24

The spider's movement is an illustration of a parabola.

(a) The equation

The spider passes through the origin.

So, we have:

\(\mathbf{(x,y) = (0,0)}\)

The spider jumps to a maximum height of 20mm, midway 160mm.

So, the vertex is:

\(\mathbf{(h,k) = (80,20)}\)

The equation of a parabola is:

\(\mathbf{y = a(x - h)^2 + k}\)

So, we have:

\(\mathbf{0 = a(0 - 80)^2 + 20}\)

\(\mathbf{0 = 6400a + 20}\)

Subtract 20 from both sides

\(\mathbf{6400a =- 20}\)

Solve for a

\(\mathbf{a =- \frac{1}{320}}\)

Substitute \(\mathbf{a =- \frac{1}{320}}\) and \(\mathbf{(h,k) = (80,20)}\) in \(\mathbf{y = a(x - h)^2 + k}\)

\(\mathbf{y = -\frac{1}{320}(x - 80)^2 + 20}\)

(b) The focus, directrix and the axis of symmetry

The focus of a parabola is:

\(\mathbf{Focus = (h,k+p)}\)

Where:

\(\mathbf{p = \frac{1}{4a}}\)

So, we have:

\(\mathbf{p = \frac{1}{4\times -1/320}}\)

\(\mathbf{p = -\frac{320}{4}}\)

\(\mathbf{p = -80}\)

So, we have:

\(\mathbf{Focus = (80 , 20-80)}\)

\(\mathbf{Focus = (80 ,-60)}\)

The axis of symmetry is:

\(\mathbf{x = h}\)

So, we have:

\(\mathbf{x = 80}\)

The directrix is:

\(\mathbf{y = k - p}\\\)

So, we have:

\(\mathbf{y = 20+80}\)

\(\mathbf{y = 100}\)

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Answer:

1/x^3

Step-by-step explanation:

foil method

Burger Quick, because it has a larger median.

Burger Quick typically has more wait time because it has a larger range (30-2=28) compared to Super Fast Food (27-3=24) and also has a larger interquartile range (IQR) (24-9.5=14.5) compared to Super Fast Food (15.5-8.5=7), indicating more variability in the wait times. The fact that Burger Quick's median (15.5) is larger than Super Fast Food's median (12) reinforces this conclusion.

Therefore, the correct answer is: Burger Quick, because it has a larger median.

Answer 2: The appropriate measure of center for this data is the median, which is represented by the line in the box at 19. This is because the data is skewed, with a longer tail to the right, and the median is less sensitive to extreme values compared to the mean. Therefore, the correct answer is: The median is the best measure of center, and it equals 19.

Answer 3: The measure of variability that the charity should use to accurately represent the data is the IQR (Interquartile Range), which is the range of the middle 50% of the data. The reason for this is that the data is skewed to the right, with many values concentrated in the upper range of the data, and the IQR is less sensitive to outliers compared to the range.

The IQR for this data is 20-10=10, which represents the spread of the middle 50% of the data. Therefore, the correct answer is: The IQR of 20 is the most accurate to use, since the data is skewed.

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Answer:

(5x + 3)² + 3

Step-by-step explanation:

25x² + 30x + 12 =

= (25x² + 30x) + 12

How do we make 25x² + 30x into a perfect square?

25x² is the square of 5x, so our binomial that is squared will start with

(5x + ___)²

We need to find the number that is added to 5x inside the parentheses.

The middle term of the squared binomial is 2 times the first term times the second term.

2(5x)b = 30x

b = 3

The binomial is (5x + 3).

When we square it, the last term will be 9. We need to add 9 to 25x² + 30x to have a perfect square. Then we also need to subtract 9 to not change the value of the expression.

= (25x² + 30x + 9) + 12 - 9

= (5x + 3)² + 3

Answer:

B

Step-by-step explanation:

The explanation is attached below.

The points on the unit circle would be (− 7/25, ±(24/25)).

To find the points on the unit circle with only x-coordinate, we can make use of Pythagorean Identity. The fact of the unit circle is that the radius of the unit circle is 1. Assume that the points on the unit circle is (x, y) and 'y' is the Y co-ordinate we need to find.

So, by using the Pythagorean identity, we get:

x² + y² = 1

Substituting the x co-ordinate, we get:

(-7/25)² + y² = 1

y² = 1 - 49/625

y² = 576/625

y = ±(24/25)

Therefore, the points on the unit circle would be (-7/25, 24/25) and

(-7/25, -24/25).

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The first voltage minimum is located approximately 0.324 wavelengths from the load end, and the first current maximum is located approximately 0.824 wavelengths from the load end.

To find the location of the first voltage minimum (Vmin) and the first current maximum (Imax) from the load end, we can use the reflection coefficient (Γ) and the normalized load impedance (Z').

Given Z' = 0.6 + j0.4, we can first calculate the reflection coefficient (Γ): Γ = (Z' - 1) / (Z' + 1) Γ = (0.6 + j0.4 - 1) / (0.6 + j0.4 + 1) Γ ≈ -0.2 + j0.4 Now, we need to find the phase angle (θ) of Γ: θ = arctan(Im(Γ) / Re(Γ)) θ = arctan(0.4 / -0.2) θ ≈ 116.6°

Since there are 360° in a full wavelength, we can find the location of Vmin and Imax in terms of wavelengths (zλ): For voltage minimum (Vmin): zλ = (θ / 360) = (116.6° / 360) ≈ 0.324

For current maximum (Imax): zλ = (θ + 180°) / 360 = (116.6° + 180°) / 360 ≈ 0.824

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Answer:

Discrete

Step-by-step explanation:

Discrete is the type of variable in which the number of auto accidents reported in a given month q

Discrete data is a count that uses integers and has a finite number of potential values. This sort of information can't be broken down into smaller chunks. Discrete data consists of finite, numeric, countable, and non-negative integers with discrete variables.

As we know that the number of auto accidents that can be reported in a month will be always a whole number, therefore, the number of accidents can be represented as 0, 1, 2,..., 1000, etc.

Thus, the type of variable is the number of auto accidents reported in a given month is Discrete.

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SOLUTION

solve for x



-5/3n = -3​

cross - multiply we have:

-5 = 3 n X 3

-5 = 9n

Divide both sides by 9, we have;

n = -5 / 9

The estimated change in yy using differentials is -0.00679. This means that if xx is increased by 0.005, then yy is estimated to decrease by 0.00679. The differential of yy is dy=-5sin(5x)dxdy=−5sin⁡(5x)dx. We are given that y=cos(5x)=π/30y=cos⁡(5x)=π/30 and x=0.055x=0.055.

We want to estimate ΔyΔy, which is the change in yy when xx is increased by 0.005. We can use the differential to estimate ΔyΔy as follows:

Δy≈dy≈dy=-5sin(5x)dx

Plugging in the values of y, x, and dxdx, we get:

Δy≈-5sin(5(0.055))(0.005)≈-0.00679

Therefore, the estimated change in yy using differentials is -0.00679.

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\( \\ \)

\( \\ \)

\( \\ \)

We know:-

\( \bigstar \boxed{ \rm Area \: of \: rhombus = \frac{Diagonal_1 \times Diagonal_2}{2} }\)

By using this formula we can find second Diagonal as area of first Diagonal already given.

\( \\ \)

So:-

\( \\ \)

\( \leadsto\sf 0.15 = \dfrac{0.5 \times Diagonal_2}{2}\)

\( \\ \\ \)

\( \leadsto\sf 0.15 = \dfrac{5 \times Diagonal_2}{2 \times 10}\)

\( \\ \\ \)

\( \leadsto\sf 0.15 = \dfrac{\cancel5 \times Diagonal_2}{2 \times \cancel{10}}\)

\( \\ \\ \)

\( \leadsto\sf 0.15 = \dfrac{ Diagonal_2}{2 \times 2}\)

\( \\ \\ \)

\( \leadsto\sf 0.15 = \dfrac{ Diagonal_2}{4}\)

\( \\ \\ \)

\( \leadsto\sf \dfrac{ Diagonal_2}{4} = 0.15 \)

\( \\ \\ \)

\( \leadsto\sf Diagonal_2 = 0.15 \times 4\)

\( \\ \\ \)

\( \leadsto\sf Diagonal_2 = \dfrac{15}{100} \times 4\)

\( \\ \\ \)

\( \leadsto\sf Diagonal_2 = \dfrac{15}{\cancel{100}} \times\cancel 4\)

\( \\ \\ \)

\( \leadsto\sf Diagonal_2 = \dfrac{15}{25} \times1\)

\( \\ \\ \)

\( \leadsto\sf Diagonal_2 = \dfrac{15}{25} \)

\( \\ \\ \)

\( \leadsto\sf Diagonal_2 = \dfrac{3}{5} \)

\( \\ \\ \)

\( \leadsto\bf Diagonal_2 = 0.6 \: feet\)

\( \\ \)

\(\therefore\underline{ \textsf{ \textbf{Diagonal$_2$ of rhombus \: = \red{0.6 feet}}}}\)

The matrix A into a product XDX-1, where D is diagonal

(b) [[11/4, 7/4], [49/24, -1/4]]

(d) [[0, 0, 0], [0, 1, 0], [0, 0, 4]]

(b) A = [[5, 6], [-2, -2]]

Av = λv.

Rewriting the equation, we get

(A - λI) × v = 0

where I is the identity matrix.

(A - λI) = [[5 - λ, 6], [-2, -2 - λ]]

Setting the determinant of (A - λI) equal to 0, we get

det(A - λI) = (5 - λ)(-2 - λ) - (6 × -2) = λ² - 3λ - 22 = 0

Factoring the equation, we have

(λ - 5)(λ + 2) = 0

So, the eigenvalues are λ = 5 and λ = -2.

For λ = 5:

(A - 5I) = [[0, 6], [-2, -7]]

Solving the system of equations (A - 5I) × v = 0, we get v = [2, 1].

For λ = -2:

(A + 2I) = [[7, 6], [-2, 0]]

Solving the system of equations (A + 2I) × v = 0, we get v = [-2, 7].

The diagonal matrix D using the eigenvalues

D = [[λ1, 0], [0, λ2]] = [[5, 0], [0, -2]]

X = [[v1, v2]] = [[2, -2], [1, 7]]

X⁻¹ = (1 / (2 × 7 - (-2 × 1))) × [[7, 2], [-1, 2]] = [[7/24, 1/8], [-1/24, 1/8]]

Therefore, the factorization of matrix A = [[5, 6], [-2, -2]] into XDX^(-1) is:

A = XDX^(-1) = [[2, -2], [1, 7]] × [[5, 0], [0, -2]] × [[7/24, 1/8], [-1/24, 1/8]]

A =

(d) matrix A = [[2, 2, 1], [0, 1, 2], [0, 0, -1]]

Av = λv.

So, we have:

A × v = λ × v

Rewriting the equation, we get

(A - λI) × v = 0

where I is the identity matrix.

Now, let's find the eigenvalues λ

(A - λI) = [[2 - λ, 2, 1], [0, 1 - λ, 2], [0, 0, -1 - λ]]

Setting the determinant of (A - λI) equal to 0, we get

det(A - λI) = (2 - λ)(1 - λ)(-1 - λ) = λ³ - 3λ² + 2λ = 0

Factoring the equation, we have

λ(λ - 1)(λ - 2) = 0

So, the eigenvalues are λ = 0, λ = 1, and λ = 2.

Now, let's find the corresponding eigenvectors

For λ = 0

(A - 0I) = [[2, 2, 1], [0, 1, 2], [0, 0, -1]]

Solving the system of equations (A - 0I) × v = 0, we get v = [0, -2, 1].

For λ = 1

(A - I) = [[1, 2, 1], [0, 0, 2], [0, 0, -2]]

Solving the system of equations (A - I) × v = 0, we get v = [-1, 1, 0].

For λ = 2

(A - 2I) = [[0, 2, 1], [0, -1, 2], [0, 0, -3]]

Solving the system of equations (A - 2I) × v = 0, we get v = [-2, 1, 2].

The diagonal matrix D using the eigenvalues

D = [[λ1, 0, 0], [0, λ2, 0], [0, 0, λ3]] = [[0, 0, 0], [0, 1, 0], [0, 0, 2]]

The matrix X using the eigenvectors as columns

X = [[v1, v2, v3]] = [[0, -1, -2], [-2, 1, 1], [1, 0, 2]]

The inverse of matrix X

X^(-1) = (1 / (0 × (1 × 2 - 0 × 0) - (-1 × (-2) - (-2 × 0)))) × [[2, 1, 2], [2, 0, -1], [-1, -1, 0]] = [[1/2, 1/2, 1/2], [1/4, -1/4, -1/2], [-1/4, -1/4, 1/2]]

Therefore, the factorization of matrix A = [[2, 2, 1], [0, 1, 2], [0, 0, -1]] into XDX^(-1) is

A = XDX^(-1) = [[0, -1, -2], [-2, 1, 1], [1, 0, 2]] × [[0, 0, 0], [0, 1, 0], [0, 0, 2]]  ×[[1/2, 1/2, 1/2], [1/4, -1/4, -1/2], [-1/4, -1/4, 1/2]]

A = [[0, 0, 0], [0, 1, 0], [0, 0, 4]]

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Answer:

C.) I x - 1 I + 3

Step-by-step explanation:

Since the bottom of the line is 3 units up, the equation should have "+ 3". Since the bottom of the line is one unit to the right, the equation should have "x - 1"