How many moles of H2 would be formed from 2.26 mol of HCI?

Mg + _HCI → _MgCl2 + H2

Step 1 - Understanding the relation between temperature and pressure

There are three main variables that can modify the state of a gas: pressure (P), volume (V) and temperature (T). When one of them is kept constant, linear relationships arise between the remaining two.

So when we keep the volume constant (isovolumetric transformation), the pressure and the temperature become directly proportional, i.e., the greater the temperature, the greater the pressure and vice-versa.

We can state it mathematically as:

Step 2 - Using the equation to solve the question

Answer: True

Explanation:

Cellular Respiration is the process of the release of energy from food. Hence, option B is correct.

Cellular respiration is the process by which organisms use oxygen to break down food molecules to get chemical energy for cell functions.

Through the process of cellular respiration, the energy in food is converted into energy that can be used by the body's cells. During cellular respiration, glucose and oxygen are converted into carbon dioxide and water, and the energy is transferred to ATP.

Hence, option B is correct.

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Answer:

A) Decreasing solubility with increasing lattice energy.

B) Ionic compounds are more soluble in a polar solvent.

C) Increasing solubility with increasing enthalpy of hydration.

Explanation:

A) Lattice energy is the energy contained in the crystal lattice of a compound (mostly ionic). It is also the energy that would be released if the component ions were brought together from infinity to form the compound.

For a compound to dissolve, the solvation energy that the fluid would use to work on its ions must exceed the compound's lattice energy. Hence, the higher the lattice energy, the less soluble the compound would be.

B) The 'like dissolves like' law in dissolution is very true and applicable. The law explains that polar compounds will dissolve in polar solvents and not dissolve in non-polar solvents. Only non-polar compounds will dissolve in non-polar solvents.

Ionic compounds contain positive and negative ions, making them one of the most polar sets of compounds. So, they will easily dissolve in polar solvents.

C) Enthalpies of hydration of the cations and anions represent the total enthalpy of dissolution. This is the energy released when a compound undergoes hydration. A form of salvation of the ions, the enthalpy of hydration need to match or exceed the lattice energybof the compound For the compound to be soluble. Hence, the larger the enthalpies of hydration, the more likely the compound will be soluble.

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Answer:3.6 X 10-4 g

Explanation:

2.7 X 10^18 X (1 mole / (6.02 X 10^23) X ( 80.912 g / 1 mole) = 3.629 X 10-4 g HBr.  If needed to correct Sig Figs 3.6 X 10-4 g HBr

(a) Because acid is caustic, dolphins can perish from exposure to it. Acids are compounds that give other things protons (H+). Acid can react with the proteins and lipids in dolphins' skin when they come into touch with it, leading to chemical burns and damage to the underlying tissue. Systemic consequences from this include death.

(b) Because chlorine is a potent oxidizer, it interacts with red-hot iron powder to produce Iron(III) chloride (FeCl3) rather than Iron(II) chloride (FeCl2). FeCl3 is created when chlorine at high temperatures rapidly accepts electrons from iron atoms. Contrarily, iron interacts with HCl, a less potent oxidizer than chlorine, to produce FeCl2.

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Aluminum and chlorine react to generate aluminium chloride, according to a balanced chemical equation: 2Al + 3Cl2 2AlCl3. A quantity of aluminium chloride up to 139.5 g can be produced.

When the limiting reagent is totally transformed into products, the maximum amount of product is produced. Two moles of aluminium chloride are created by a full reaction between three moles of chlorine. Hence, 46.4 g of aluminium chloride is the maximum mass that can be produced.

The amount of aluminium and chlorine in the specified masses can be calculated as follows:

Number of moles of aluminum = 28.0 g / 27 g/mol = 1.04 mol

Number of moles of chlorine = 33.0 g / 35.5 g/mol = 0.93 mol

We may get the theoretical yield of aluminium chloride using the balanced equation: 2Al + 3Cl2 → 2AlCl3

1.04 mol Al × (2 mol AlCl3 / 2 mol Al) × (133.34 g AlCl3 / 1 mol AlCl3) = 139.5 g AlCl3

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Answer:

4

Explanation:

\(\int\limits^a_b {x} \, dwetjernjtnx\)

Answer:

Explanation:

a) For a first-order reaction, the rate of the reaction is proportional to the concentration of the reactant, i.e., rate = k[A]. The integrated rate law for a first-order reaction is given by:

ln([A]t/[A]0) = -kt

where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration, k is the rate constant, and t is time.

If a reaction is 50% complete in 30.0 min, it means that [A]t/[A]0 = 0.5. Substituting these values into the equation above, we can solve for the rate constant:

ln(0.5) = -k(30.0 min)

k = 0.0231 min^-1

Now, if the reaction is 75% complete, it means that [A]t/[A]0 = 0.25 (since 50% is half of the initial concentration and 75% is a quarter of the initial concentration). Substituting this value and the rate constant into the equation above, we can solve for the time t:

ln(0.25) = -0.0231 min^-1 * t

t = 61.3 min

Therefore, for a first-order reaction, the reaction will be 75% complete after 61.3 min.

b) For a zero-order reaction, the rate of the reaction is independent of the concentration of the reactant, i.e., rate = k. The integrated rate law for a zero-order reaction is given by:

[A]t = -kt + [A]0

where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration, k is the rate constant, and t is time.

If a reaction is 50% complete in 30.0 min, it means that [A]t = 0.5[A]0. Substituting these values into the equation above, we can solve for the rate constant:

0.5[A]0 = -k(30.0 min) + [A]0

k = 0.0167 M/min

Now, if the reaction is 75% complete, it means that [A]t = 0.25[A]0. Substituting this value and the rate constant into the equation above, we can solve for the time t:

0.25[A]0 = -0.0167 M/min * t + [A]0

t = 45.0 min

Therefore, for a zero-order reaction, the reaction will be 75% complete after 45.0 min.

Answer:

aluminium is all of isotope with 14 neutrons .

Answer:

V2= 1.03L

Explanation:

Start off with what you are given.

V^1: 1.00L

T^1: 23°C

V^2?

T^2: 33°C

If you know your gas laws, you have to utilise a certain gas law called Charles' Law:

V^1/T^1 = V^2/T^2

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

(23+273 = 296)     (33+273 = 306)

Multiply crisscross

1.00/296= V^2/306

296V^2 = 306

Dividing both sides by 296 to isolate V2, we get

306/296 = 1.0337837837837837837837837837838

V2= 1.03L

Answer:

D) Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.

Explanation:

Step 1: Given data

Molarity (M): 2.00 M

Volume (V): 500 mL = 0.500 L

Molar mass of NaCl: 58.44 g/mol

Step 2: Calculate the required moles of NaCl

We will use the following expression.

n = M × V

n = 2.00 mol/L × 0.500 L

n = 1.00 mol

Step 3: Calculate the mass corresponding to 1.00 moles of NaCl

1.00 mol × 58.44 g/mol = 58.44 g

Step 4: Describe the procedure to prepare the solution

Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.

Answer:

D) Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.

Explanation:

I got it right in class!

Hope  this helps!! :))

Answer:

Can you attach a picture?

Explanation:

Answer:B) The Skin and The Skin cells

Explanation:

Hope this helped

The atomic number or proton number (symbol Z) of a chemical element is the number of protons found in the nucleus of every atom of that element.

Answer:

Hope It Helps You

Explanation:

1.35 g of H₂SO₄ would require approximately 46 mL of 0.30 M H₂SO₄.

To determine the volume of 0.30 M H₂SO₄ that would contain 1.35 g of H₂SO₄, we need to use the molar mass of H₂SO₄ and perform a conversion.

The molar mass of H₂SO₄ can be calculated by summing the atomic masses of its constituent elements:

2(1.01 g/mol of H) + 1(32.07 g/mol of S) + 4(16.00 g/mol of O) = 98.09 g/mol

Now, we can use the formula:

moles = mass / molar mass

moles of H₂SO₄ = 1.35 g / 98.09 g/mol = 0.0138 mol

The molarity (M) of a solution is defined as the number of moles of solute divided by the volume of the solution in liters. Rearranging this equation, we have:

volume = moles / Molarity

volume = 0.0138 mol / 0.30 mol/L = 0.046 L

Finally, we can convert the volume from liters to milliliters by multiplying by 1000:

volume = 0.046 L × 1000 mL/L = 46 mL

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Answer:

Explanation:

Here, we want to get the volume occupied at the new temperature

According to Boyle's law, volume and pressure are inversely proportional

Thus, mathematically:

P1 is the initial pressure which is 735 mmHg

V1 is the initial volume which is 4.5 L

P2 is the final pressure which is 1 atm( 760 mmHg)

V2 is the final volume that we want to calculate

Substituting the values, we have it that:

Answer:

Chemical and Mechanical

Explanation:

Answer:

choose the one with the least amount of electrons ex:iron

Explanation:

Answer:

D. Fluorine(F)

Explanation:

Answer:

solid

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Explanation:

Answer: 34 gram of chromium produced from 50g of \(Cr_2O_3\)

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)    

\(\text{Moles of} Cr_2O_3=\frac{50g}{152g/mol}=0.33moles\)

The decomposition of \(Cr_2O_3\) follows the equation :

\(2Cr_2O_3\rightarrow 4Cr+3O_2\)  

According to stoichiometry :

2 moles of \(Cr_2O_3\) produce = 4 moles of \(Cr\)

Thus 0.33 moles of \(Cr_2O_3\) will produce=\(\frac{4}{2}\times 0.33=0.66moles\)  of \(Cr\)

Mass of \(Cr=moles\times {\text {Molar mass}}=0.66moles\times 52g/mol=34g\)

Thus 34 gram of chromium produced from 50g of \(Cr_2O_3\)

To determine the specific heat of the unknown substance, we can use the principle of energy conservation. The heat lost by the unknown substance is equal to the heat gained by the water.Therefore, the specific heat of the unknown substance is approximately 2.68 J/g°C.

First, we calculate the heat lost by the unknown substance. Using the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat, and ΔT is the change in temperature, we have:

Q_substance = m_substance * c_substance * ΔT_substance

Next, we calculate the heat gained by the water. Again, using the same formula, we have:

Q_water = m_water * c_water * ΔT_water

Since the system reaches equilibrium, Q_substance = Q_water. Rearranging the equation and substituting the given values, we can solve for c_substance:

m_substance * c_substance * ΔT_substance = m_water * c_water * ΔT_water

c_substance = (m_water * c_water * ΔT_water) / (m_substance * ΔT_substance)

Plugging in the values, we find:

c_substance = (250.00 g * 4.18 J/g°C * (29.000 °C - 23.000 °C)) / (95.00 g * (98.000 °C - 23.000 °C))

c_substance ≈ 2.68 J/g°C

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Answer:

a) (CH3)3N

b) 4-methylpyridine

Explanation:

Let us bear in mind that the basicity of amines depend on;

1) the availability of the lone pair

2) the stability of the conjugate acid of the amine.

In the gaseous phase, the basicity of the amine strictly depends on the availability of the lone pair. The tertiary amine is better able to accept a proton in the gaseous phase since it is surrounded by three methyl groups having an electron pushing effect thereby reinforcing the lone pair on the nitrogen. This order is reversed in solution due to solvation.

Here again, the electron donation to the nitrogen bearing the lone pair is important. The 4-methylpyridine is more basic than 2-methylpyridine to BMe3 due to steric hindrance that hinders the bonding of 2-methylpyridine to BMe3.

Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

The given electron configuration 1s² 2s² 2p⁶ 3s² 3p⁴ denotes the elements helium (He), beryllium (Be), carbon (C), magnesium (Mg), and sulfur (S).

The given electron configuration represents the electron distribution of an atom. Let's break it down and determine the elements denoted by each part:

1s²: This indicates that there are two electrons in the 1s orbital. The first electron shell (n = 1) can hold a maximum of two electrons. Therefore, the first element denoted by this configuration is helium (He).

2s²: This signifies that there are two electrons in the 2s orbital. The second electron shell (n = 2) can hold a maximum of eight electrons. The element with this configuration is beryllium (Be).

2p⁶: This indicates that there are six electrons in the 2p orbitals. The p orbitals are a set of three orbitals within the second electron shell. The element with this configuration is carbon (C).

3s²: This signifies that there are two electrons in the 3s orbital. The third electron shell (n = 3) can also hold a maximum of eight electrons. The element with this configuration is magnesium (Mg).

3p⁴: This indicates that there are four electrons in the 3p orbitals. The p orbitals in the third shell are also a set of three orbitals. The element with this configuration is sulfur (S).

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