How many moles of SnO2 would need in order to produce 8.67 moles of Sn?

Answer:

10 g The change from ice to water is a phase change for the water. A phase change does not change the mass of the water. So if you end up with 10 g of water, and you originally started with ice, then that means you had to start with 10 g of ice. Therefore the best estimate of the mass of the ice cube is 10 g.

Explanation:

Answer:

this is not chemistry

Explanation:

not chemistry

This site is used for learning, so to give a better understanding, here is  a walkthrough.

So let's create a question:

Can a molecule have a dipole moment if it has no polar covalent bonds?

Here's the answer to that question:

Even though a molecule contains only one element, it can have a persistent dipole moment. The most common example is ozone (trioxygen). It is curved and has a partial positive charge on the center oxygen atom (similar to sulfur dichloride).

Permanent dipole moments are caused by an unequal, directed charge distribution within a molecule, not by changes in electronegativity. Such charge distributions are frequently caused by so-called "polar covalent bonds," which occur between atoms with markedly varying electronegativity. However, they are not the sole explanation.

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Answer:

1.41 moles H2O2(with sig figs)

Explanation:

okay so what is the molar mass of H2O2= (1.008 g/mol)2+(16.00g/mol)2= (2.016+ 32.00) g/ mol

= 34. 02 g/mol

48.0g H2O2* 1 mol H2O2/ 34.02 g H2O2= 1.41 mol H2O2

The hydronium ion concentration of a 0.163 M solution of aniline hydrochloride  is

[H30+]=1.95*10^{-3}m

This is further explained below.

Generally, The dissociation of salt

\(&\mathrm{C}_{6 \mathrm{HSNH}_3}^{+} \mathrm{Cl}^{-} \rightleftharpoons \mathrm{CoHSNH}_3^{+}+\mathrm{Cl}^{-}\\\\&\left.6 \mathrm{CHNH}_3^{+}+\mathrm{H}_2 \mathrm{O} \geqslant 645 \mathrm{MH}_2+4_3 \text { ( }\right) \text { (ka) }\\\\&\mathrm{CeHSSNH} 2+\mathrm{N}_2 \mathrm{O} \rightleftharpoons \mathrm{C64} \mathrm{CNM}_3^{+}+\mathrm{OH}(\mathrm{Kb}\)

Since C6C5NH_3CL is a salt of a weak base and strong acid, therefore

\(K_a=\frac{k \omega}{10 b}\\\\K_a=\frac{1 \times 10^{-14}}{4.3 \times 10^{-10}}\)

K_a=2.33*10^{-5}

using equation

\(\mathrm{C_6H_5NH}_3^{+}+\mathrm{H}_2 \mathrm{O} \underset{\mathrm{Ka}}{\rightleftharpoons} C_6H_5NH_2 \mathrm{NH}_2+ H_3O\)

Then,

\(\mathrm{ka}=\frac{x^2}{(0.163-x)}\\\\ka=0.33 \times 10^{-5}$\)

Since, the value of $x$ is negligible in comparison to 0.163, hence.

\(k a &=\frac{x^2}{0.163} \\\)

x^2 =k a* 0.163

x^2=2.33 * 10^{-5}*0.163

x^2 =3.798* 10^{-6}

x =1.949*10^{-3}

Hence, The hydronium ion concentration of a 0.163 M solution of aniline hydrochloride  is

[H30+]=1.95*10^{-3}m

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Ionic bonds are bonds that occur due to the handover of electrons to form positive ions and negative ions whose electron configuration is the same as that of the noble gasses.

Chemical bonds are the forces that hold atoms in elements and compounds together. Chemical bonds can occur with several types of bonds.

Based on the electron configuration that occurs in bond formation, chemical bonds are divided into 4 types:

1. Ionic or electrovalent bonds

This bond occurs because of the electrostatic attraction between positive ions and negative ions in a chemical compound

2. Covalent bonds

Covalent bonds occur when the sharing of electron pairs from each of the bonding atoms.

3. Coordinate covalent bond

Coordinate covalent bond is a bond that uses a shared pair of electrons, but the electrons only come from one of the atoms.

4. Metallic bond

This bond is formed due to the attractive force of the metal atomic nucleus with a sea of electrons.

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1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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Answer:

Co2

Explanation

An organic compound includes Carbon and Hydrogen both bonded

Answer:

65.0 K

Explanation:

To find the temperature, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (pKa)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (8.31 L*kPa/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find the temperature.

P = 202.65 pKa                          R = 8.31 L*kPa/mol*K

V = 2.0 L                                     T = ? K

n = 0.75 moles

PV = nRT

(202.65 pKa)(2.0 L) = (0.75 moles)(8.31 L*kPa/mol*K)T

405.3 = (6.2325)T

65.0 K = T

Answer:

Copper will start to react with the oxygen in the air to form copper oxide. The copper oxide will continue reacting to oxygen over time. As the copper oxide continues to react with carbon dioxide and water in the air it coats the surface with that iconic blue-green patina colour

Answer:

80mL of 1.00M NaOH

Explanation:

Using H-H equation, we can determine oH of a buffer as acetate buffer. First, we need to determine amount of acetate ion and acetic acid at pH 3.50 and 5.07. Then, with the reaction of NaOH with acetic acid we can find the amount of 1.00M NaOH that must be added:

At pH 3.50:

pH = pka + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

3.50 = 4.74 + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

0.057544 = [C₂H₃O₂⁻] / [HC₂H₃O₂] (1)

Using and replacing in (1):

[HC₂H₃O₂] + [C₂H₃O₂⁻] = 0.250 M

[HC₂H₃O₂] + 0.057544[HC₂H₃O₂] = 0.250 M

1.057544 [HC₂H₃O₂] = 0.250M

[HC₂H₃O₂] = 0.2364M * 0.500L = 0.1182 moles of acetic acid at first pH

At pH 5.07:

pH = pka + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

5.07 = 4.74 + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

2.13796= [C₂H₃O₂⁻] / [HC₂H₃O₂] (1)

Using and replacing in (1):

[HC₂H₃O₂] + 2.13796[HC₂H₃O₂] = 0.250 M

3.13796 [HC₂H₃O₂] = 0.250M

[HC₂H₃O₂] = 0.07967M * 0.500L = 0.0398 moles of acetic acid at first pH

Now, NaOH reacts with HC₂H₃O₂ as follows:

NaOH + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O

As moles of acetic acid decreases from 0,1198 moles - 0,0398 moles = 0,08 moles of acetic acid are consumed = 0,08 moles of NaOH

0,08 mol NaOH * (1L / 1mol) = 0,08L of 1.00M NaOH =

Answer:

30.8 grams O

Explanation:

In H₂O, there are 2 moles of hydrogen for every 1 moles of oxygen. You can use this to convert between moles of H and moles of O. Then, you can use the molecular weight of oxygen (15.998 g/mol) to convert between moles O and grams. The answer should have 3 sig figs because the given value (3.85) also has 3 sig figs.

3.85 moles H          1 mole O             15.998 g
--------------------  x  ------------------  x  --------------------  = 30.8 grams O
                              2 moles H            1 mole O

Nonmetals are found on the right side of the periodic table and they tend to gain electrons to achieve stable electronic configurations. These elements have high ionization energies and low electromagnetism which make it difficult for them to lose electrons and easier for them to gain electrons.

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Diamonds are composed of carbon in a tetrahedral lattice. That is option C.

A diamond of defined as an allotrope or one of the major forms of the element, carbon in nature.

These carbon atoms are arranged within the diamond in a face centered cubic tetrahedral lattice shape.

Therefore, Diamonds are composed of carbon in a tetrahedral lattice.

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Diamonds are composed of carbon in a tetrahedral lattice. The correct option is C.

Diamonds are one of the allotropes of carbon. The other allotrope of carbon is graphite.

Thus, diamonds are made up of carbon atoms that are tightly packed together. Each carbon atom in a diamond is strongly bonded to 4 other carbon atoms, resulting in the formation of a tetrahedral structure.

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Answer:

1120 gm

Explanation:

6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)

(a) Balance the equation.

(b) How many grams of oxygen are required to react with 10 moles of ethane for a complete

combustion reaction?

FIRST, CORRECT THE EQUATION THEN BALANCE

2C2H6(G) + 7O2------------>  4CO2  + 6H2O

so for 10 moles of ethane, we need

7 X 5 = 35 MOLES O2

=35 MOLES O2

O2 HAS A MOLAR MASS OF 2X16 = 32 gm

35 MOLES OF O2 HAS A MASS OF 35 X 32 =1120 gm

Answer:

There are 0.26 moles of neon.

Explanation:

From the information in the exercise we know that:

- Volume (V): 2.00L

- Temperature (T): 300.0K

- Pressure (P): 3.25atm

Using the Ideal Gases Law formula, we can calculate the number of moles (n), by replacing the values of V, T and P:

So, there are 0.26 moles of neon (0.3 rounded).

The specific heat of the metal can be calculated using calorimetric equation. The specific heat of the metal here is 0.61 J/g °C.

The specific heat capacity of  substance is the heat energy required to raise its temperature by one degree Celsius per one gram  of the substance.

The calorimetric equation connecting the heat energy q, mass m, specific heat c and temperature difference ΔT is:

q = m c  ΔT

Here, the heat released from the metal is equal to the heat absorbed by water.

Therefore,

q metal = q water. Let c  be the specific heat of the metal.

25 g  × ( 99 - 20.15°C) ×c = 50 g  × ( 20.15°C- 14.33) × 4.18 J/g °C

                                         = 1217.5 J

Then c = 1217.5 J/25 g  × ( 99 - 20.15°C)  = 0.61 J/g °C.

Therefore, the specific heat of the metal is 0.61 J/g °C.

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Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

The reaction is given by

\(\\ \rm\Rrightarrow {}^{127}_{56}Ba\longrightarrow {}^{0}_{+1}\beta+{}^{127}_{55}Cs\)

Barium goes underneath beta decay to form Ceaseum

\(\sf {}^{127}_{56}Ba\longrightarrow {}^0_{1}\beta+{}^{127}_{55}Cs\)

Remember

The enthalpy change for the given reaction is -972.6 kJ/mol.

Using the temperatures of formation, the following equation must be used to get the enthalpy change of the given reaction:

ΔH = Σ(nΔHf(products)) - Σ(nΔHf(reactants))

where Hf is the standard heat of formation for each ingredient, and n is the stoichiometric coefficient of each substance in the balanced chemical equation.

replacing the specified values:

ΔH = [(1 x ΔHf(NCl3)) + (3 x ΔHf(HCl))] - [(1 x ΔHf(NH3)) + (3 x ΔHf(Cl2))]

ΔH = [(1 x 0) + (3 x (-92.3))] - [(1 x (-45.9)) + (3 x 232.0)]

ΔH = (-276.9) - (695.7)

ΔH = -972.6 kJ/mol

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Answer:

answer is a

Explanation:

ik cause i did this before

Answer:

High purity.

Stability (low reactivity)

Low hygroscopicity (to minimize weight changes due to humidity)

Explanation:

There are different primary standards that could be used in a standardization titration in order to achieve the best and accurate result possible. These standards include high purity,stability and low hygoscropicity .

A high purity means the reactants lack impurities which could affect the result. Stability also ensures that there is non reactivity with elements/compounds in the atmosphere while low hygroscopicity ensures weight changes are minimized due to humidity.

If a reaction has a negative ΔG and a positive ΔS, the reaction will be spontaneous at all temperatures.

If a reaction is spontaneous at all temperatures, it implies that the reaction will occur without the need for any external intervention, such as the addition of energy. For a reaction to be spontaneous, it must satisfy the criteria of thermodynamic favorability, which is determined by the change in Gibbs free energy (ΔG) associated with the reaction.

The relationship between ΔG, temperature (T), and the equilibrium constant (K) of a reaction is described by the equation ΔG = ΔH - TΔS, where ΔH is the change in enthalpy and ΔS is the change in entropy.

To ensure spontaneity at all temperatures, two conditions must be met:

ΔG must be negative: A negative ΔG indicates a thermodynamically favorable reaction, meaning the products have a lower Gibbs free energy than the reactants. If ΔG is negative, the reaction will proceed spontaneously in the forward direction.

ΔS must be positive: A positive ΔS signifies an increase in the overall entropy of the system. Higher entropy means more disorder, and spontaneous reactions often involve an increase in randomness. When ΔS is positive, it can compensate for the enthalpic term, ΔH, allowing the reaction to proceed spontaneously.

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The volume of the ethanol that has a density of ethanol is 0.789 g/cm³ is 209.13cm³.

The volume of a substance can be calculated by dividing the mass of the substance by its density as follows:

Volume = mass ÷ density

According to this question, the density of ethanol is 0.789 g/cm³. A flask holds 165.0 g of ethanol and the volume can be calculated as follows:

Volume = 165.0g ÷ 0.789g/cm³

Volume = 209.13cm³

Therefore, the volume of the ethanol that has a density of ethanol is 0.789 g/cm³ is 209.13cm³.

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Answer

c. Methyl bromide

Explanation

Ozone-depleting substances are:

i. chlorofluorocarbons (CFCs)

ii. halon.

iii. carbon tetrachloride (CCl4)

iv. methyl chloroform (CH3CCl3)

v. hydrobromofluorocarbons (HBFCs)

vi. hydrochlorofluorocarbons (HCFCs)

vii. methyl bromide (CH3Br)

viii. bromochloromethane (CH2BrCl)

Therefore the correct answer to you question is option:

c. Methyl bromide

"Option C" O¹⁵8 and O¹⁶8 atoms represent different isotopes of the same element.

Hope it helps...

a) Cl is the atom Atoms are expected to have the most negative (exothermic) electron affinities. 

Electron affinity is the amount of energy produced or released when an atom attracts an electron. Electron affinity can be used as a measure of the ease with which an atom captures electrons. The greater the energy released (electron affinity) indicates that the atom tends to attract electrons to become a negative ion.

Electron affinity can be used as a measure of the ease with which an atom captures electrons. The greater the energy released (electron affinity) indicates that the atom tends to attract electrons to become a negative ion.

The energy of an atom is defined when the atom loses or gains energy through a chemical reaction that causes the loss or gain of electrons. Chemical reactions that release energy are called exothermic reactions and chemical reactions that absorb energy are called endothermic reactions.

The energy of an exothermic reaction is negative, so the energy is given a negative sign; while the energy of the endothermic reaction is positive and the energy is given a positive sign. An example that demonstrates both processes is when someone drops a book. When he lifts the book, he gives the book potential energy (absorbed energy).

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Answer:

no. of H = 10

no. of C = 4

C4H10