Answer:
\(134.21g\text{ of C}_2H_4\text{ is needed}\)Explanation:
Here, we want to calculate the mass of ethene needed
From the balanced equation of reaction:
1 mole of ethene needed 3 moles of oxygen
x moles of ethene will need 14.38 moles of oxygen
To get the value of x, we have it that:
\(\begin{gathered} 1\times14.38\text{ = 3}\times x \\ x\text{ = }\frac{14.38}{3} \\ \\ x\text{ =4.793 moles} \end{gathered}\)To get the mass needed, we have to multiply the number of moles by the molar mass of ethene
The molar mass of ethene is 28 g/mol
Thus, we have the needed mass as:
\(\begin{gathered} Mass\text{ = number of moles }\times\text{ molar mass} \\ Mass\text{ = 4.793 }\times\text{ 28 = 134.21 g} \end{gathered}\)In a laboratory experiment a student found the pH of rain rain water sample to be 4.35 calculate H3O+ in the rainwater
The rainwater sample has a pH of 4.35, indicating that it is acidic. The concentration of \(H_3O^+\) ions in the sample is \(4.47 * 10^{-5} M\), which is higher than in neutral or basic solutions.
In a laboratory experiment, a student found the pH of a rainwater sample to be 4.35. In this context, the task is to calculate the concentration of hydronium ions (\(H_3O^+\)) in the given rainwater sample. The pH of the rainwater sample is an indication of how acidic it is. As per the pH scale, acidic solutions have a pH of less than 7. Since the pH of rainwater is acidic (pH = 4.35), it means that the concentration of \(H_3O^+\) ions is higher in the rainwater sample. To calculate the concentration of \(H_3O^+\) ions, we can use the following formula: pH = -log[\(H_3O^+\)], Where[\(H_3O^+\)] is the concentration of hydronium ions. By rearranging the above formula, we can get the concentration of \(H_3O^+\) ions as \([H_3O^+] = 10^{-pH}\). Substituting the given pH value of the rainwater sample in the above equation, we get\([H_3O^+] = 10^{-4.35} = 4.47 × 10^{-5} M.\)Therefore, the concentration of \(H_3O^+\) ions in the given rainwater sample is \(4.47 * 10^{-5} M.\)For more questions on acidic
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1. Calculate the standard cell potentials from the standard free energy changes (you may find the values from available references) for the following fuel cells: (1) H₂/0₂, (ii) methanol/O₂, (iii) ethanol/O₂, and (iv) glucose/O₂. Assume that the fuels are completely oxidized and the products of the reactions are water for H₂/O₂ fuel cells, and carbon dioxide / water for the carbonaceous fuel/O₂ fuel cells.
We can use the following formula to determine the standard cell potential from standard free energy changes:
ΔG° = -nFE°
where
ΔG° is the standard free energy change,
n is the number of moles of electrons transferred in the balanced chemical equation,
F is Faraday's constant (96,485 C/mol), and
E° is the standard cell potential.
You can find the standard free energy change (G°) for a specified fuel cell in readily available references. These values are listed:
1. Fuel cell for H2/O2: G° = -237.2 kJ/mol
The chemical formula is 2H2 + O2 -> 2H2O.
In this example, n is equal to 4 (transferring 4 moles of electrons).
After entering the values into the formula, we get:
-4 * 96,485 C/mol * E°1 = -237.2 kJ/mol
As we solve for E°1, we get:
E°₁ ≈ 1.23 V
2. G° = -326.7 kJ/mol for a methanol/O2 fuel cell.
The balanced chemical formula is: CO2 + 2H2O = CH3OH + 1.5O2.
In this example, n is equal to 6 (transferring 6 moles of electrons).
After entering the values into the formula, we get:
-6 * 96,485 C/mol * E°2 = -326.7 kJ/mol
As we solve for E°2, we get:
E ° ₂ ≈ 0.54 V
3. Fuel cell for ethanol and oxygen: G° = -329.6 kJ/mol
The chemical formula is: C2H5OH + 3O2 -> 2CO2 + 3H2O.
In this example, n is equal to 12 (12 electron moles are exchanged).
After entering the values into the formula, we get:
-12 * 96,485 C/mol * E°3 = -329.6 kJ/mol
As we solve for E°3, we get:
E°₃ ≈ 0.27 V
4. Fuel cell for glucose and oxygen: G° = 2,840 kJ/mol
The chemical formula is C6H12O6 + 6O2 -> 6CO2 + 6H2O.
Since 24 moles of electrons are transported, n = 24 in this example.
After entering the values into the formula, we get:
-24 * 96,485 C/mol * E°4 = 2,840 kJ/mol.
Solving for E°4, we get:
E°₄ ≈ 0.37 V
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Let's do this!
Balance each equation so there are the same number of each type of atom on both sides of the
equation There is a chart above each problem to help you count the atoms
First-Count up the
number of atoms you
currently have Write
that number in the
chart for both sides of
the equation
Second-If the
numbers don't match,
try adjusting the
coefficients one at at
time Make sure to
change the number in
the chart
Remember- you can't
change the formulas!
2
Reactants
Mg
M
Mg
LI
Reactants
H
LO +
Products
Mg
N
L
O
H
но →
_Math
Products
LIOH
You should
do this in
pencil
The balanced chemical equations of the reactions are given below:
1. Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)
2. 2 Li (s) + 2 H₂O (l) ----> LiOH (aq) + H₂ (g)
What is a balanced equation?A balanced chemical equation is an equation in which the number of moles of atoms of elements in a given reaction is equal to the sum of the number of moles of atoms of each element that is produced.
A balanced chemical equation is in accordance with the law of conservation of mass which states that matter can neither be created nor destroyed.
When balancing chemical equations, numerical coefficients are added in front of moles of atoms of an element or moles of a given compound taking part in the reaction.
The balanced chemical equation of the reaction of magnesium and water as well as the reaction of lithium and water is given below:
Magnesium and water:
Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)
Lithium and water:
2 Li (s) + 2 H₂O (l) ----> LiOH (aq) + H₂ (g)
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Given 46.34 grams of Na, how many grams of N2 are used? Please look at screenshot.
As per the given balanced chemical equation of the reaction, 2 moles or 46 g of Na needs to react with 3 moles or 84 g of N₂. Then 46.34 g of Na needs 84.6 g of N₂.
What is sodium nitride?Sodium nitride, NaN₃ is an ionic compound formed by the donation of electron from the sodium metal to nitrogen atoms. The decomposition of sodium azide produce sodium metal and nitrogen gas.
As per the given balanced chemical equation of the reaction, 2 moles or 46 g of Na needs to react with 3 moles or 84 g of N₂.
molar mass of N₂ = 28 g/mol
mass of 3 moles = 84 g
atomic mass of Na = 23 g/mol
mass of 2 moles = 46 g.
Then , mass of nitrogen gas required to react with 46.34 g of sodium is:
(46.34 ×84)/46 = 84.62 g.
Therefore, 84.62 g of nitrogen gas is used up in this reaction.
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compared to pure water, an aqueous solution of calcium chloride has a
Topic
- Carbon in the environment .
-Fuels (types)
-Effects of fuels on the environment .
- Process of making charcoal
-Physical properties of co2 and it uses .
-Effects of co₂ concentration the atmosphere.
- Causes and effects of green house effects.
- Hard water.
- Allotropes of carbon.
Fuels are substances that release energy when burned, and they can be broadly categorized into three types: fossil fuels, renewable fuels, and nuclear fuels.
Fossil fuels, such as coal, oil, and natural gas, are formed from the remains of ancient plants and animals. When burned, they release carbon dioxide (CO₂) and other pollutants, contributing to air pollution, climate change, and environmental degradation. Renewable fuels, like solar, wind, and hydropower, are cleaner alternatives as they produce little to no greenhouse gas emissions. Nuclear fuels generate energy through nuclear reactions but produce radioactive waste.
The process of making charcoal involves heating wood in the absence of oxygen, a process known as pyrolysis. This removes moisture, volatile components, and impurities, resulting in a high-carbon content material that is used as a fuel source and in various industries.
CO₂ is a colorless and odorless gas that is a natural part of Earth's atmosphere. It has physical properties that allow it to absorb and re-emit heat, making it a greenhouse gas. While it is essential for life on Earth, excessive CO₂ concentrations contribute to the greenhouse effect, trapping heat and leading to global warming and climate change.
The effects of increased CO₂ concentration in the atmosphere include rising temperatures, melting ice caps, sea-level rise, more frequent and severe weather events, and ecosystem disruptions. To mitigate these effects, reducing CO₂ emissions through sustainable practices and transitioning to cleaner energy sources is crucial.
The greenhouse effect occurs when certain gases, including CO₂, methane, and water vapor, trap heat in the Earth's atmosphere. Human activities, such as burning fossil fuels and deforestation, have significantly increased the concentration of these gases, intensifying the greenhouse effect. This leads to global warming, altered climate patterns, and negative impacts on ecosystems, agriculture, and human health.
Hard water contains high mineral content, particularly calcium and magnesium ions. These minerals can cause issues such as scale buildup in pipes and appliances, reduced soap efficiency, and dry skin or hair after bathing. Water softeners are commonly used to remove these minerals and convert hard water into soft water.
Carbon exhibits various allotropes, including diamond, graphite, and fullerenes. Diamond is a crystalline form of carbon with a rigid structure and exceptional hardness.
Graphite consists of stacked layers of carbon atoms arranged in a hexagonal lattice, and it is a good conductor of electricity. Fullerenes are carbon molecules in the form of hollow spheres, tubes, or other shapes, with unique physical and chemical properties that have applications in nanotechnology, electronics, and materials science.
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I need help with this!!!
Answer:
0.73g/cm^3
Explanation:
d=m/v
d=11/15
d=0.73
Metal D Most reactive
Sodium
Magnesium
Carbon
Metal E
Iron
Hydrogen
Copper Least reactive
As per the given details, Metal D is extracted from its oxide by reduction with hydrogen, and Metal E is removed from the earth as the metal itself.
Based on the provided information, we can match the metals to the methods used to extract them as follows:
Sodium - Extracted by electrolysis of a molten ionic compound.
Magnesium - Extracted from its oxide by reduction with carbon.
Carbon - Not a metal, so it doesn't apply in this context.
Metal E - Extracted from its oxide by reduction with hydrogen.
Iron - Removed from earth as metal itself.
Hydrogen - Not a metal, so it doesn't apply in this context.
Copper - Not a metal D or E, so it doesn't apply in this context.
Matching the metals to the extraction methods:
Sodium - extracted by electrolysis of a molten ionic compound.
Magnesium - extracted from its oxide by reduction with carbon.
Metal D - extracted from its oxide by reduction with hydrogen.
Metal E - removed from earth as metal itself.
Iron - removed from earth as metal itself.
Therefore, Metal D is extracted from its oxide by reduction with hydrogen, and Metal E is removed from the earth as the metal itself.
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Calculate the molar mass of menthol, C10H20O
Answer:
C10H200
Explanation:
The molecular formula C10H20O (molar mass : 156.27 g/mol) may refer to: Citronellol. Decanal.
The molar mass of menthol (\(\rm C_10H_{20}O\)) is 156.3 g/mol.
To calculate the molar mass of menthol (\(\rm C_10H_{20}O\)), we need to determine the sum of the atomic masses of all the individual atoms in the compound.
The atomic masses of the elements are as follows:
C (carbon) = 12.01 g/mol
H (hydrogen) = 1.01 g/mol
O (oxygen) = 16.00 g/mol
Now, let's calculate the molar mass of menthol:
Molar mass of menthol = (10 * molar mass of C) + (20 * molar mass of H) + (1 * molar mass of O)
= (10 * 12.01 g/mol) + (20 * 1.01 g/mol) + (1 * 16.00 g/mol)
= 120.1 g/mol + 20.2 g/mol + 16.0 g/mol
= 156.3 g/mol
Therefore, the molar mass of menthol (\(\rm C_10H_{20}O\)) is 156.3 g/mol.
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Which of the following is not an example of a modified silicate?
Ceramics
Glass
Cement
Quartz
Quartz is not regarded as an example of a modified silicate.
What is Quartz?This is defined as a hard, crystalline mineral composed of silica with a tetrahedral shape. Silica is also referred to as Silicon dioxide(SiO₂).
This type of mineral is a naturally occurring crystal and isn't a modified silicate but the rest can be modified using their respective constituents thereby making option D the most appropriate choice.
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how do you balance this equation
2h2s+3o2+so2
The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.
The unbalanced equation is:
2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)
Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)
Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:
2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
To remove the fractional coefficient, we can multiply all coefficients by 2:
4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:
4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
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suggest what the effect of using growth hormone on meat cattle might be
Answer:
Natural BGH and rBGH both increase the level of another hormone called insulin-like growth factor (IGF-1) in the cow.
Beef cattle are often given steroids to increase and speed growth. Common steroids include:
Natural steroids like estradiol, testosterone, and progesterone Man-made steroids from compoundsMajor groups such as FDA and Food and Agricultural Organization state track level of hormones in food. They state that the levels of hormones in food are safe to eat. Not everyone agrees.
Explanation:
Hormones are present in all animal products. Some are natural, others may be added through supplements. Hormones and steroids are given to livestock. It can increase the number of dairy products and beef.
FDA establishes the acceptable safe limits for hormones in meat. A safe level for human consumption is a level of drug in the meat that would be expected to have no harmful effect in humans based on extensive scientific study and review.
A 50.0 g sample of an unknown
compound contains 14.19 g Na,
19.76 g O, and 16.05 g Cr. What is
the percent composition of O in the
compound?
[?]% O
Round your answer to the hundredths place.
The percentage composition of oxygen (O) in the compound, given that it contains 19.76 g of O is 39.52%
How do I determine the percentage composition of O?The percentage composition of substance in a compound can be obtained by using the following formula:
Percentage = (mass of substance / mass of compound) × 100
Using the above formula, we can determine the percentage composition of the oxygen (O) as illustrated below:
Mass of compound = 50.0 gramsMass of O = 19.76 gramsPercentage composition of O =?Percentage = (mass of solute / mass of solution) × 100
Percentage of O = (19.76 / 50.0) × 100
Percentage of O = 39.52%
Thus, we can conclude that the percentage composition of the O is 39.52%
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Suppose 3.005 g of a nonvolatile solute is added to 20.02 g of water (the solvent), and the boiling point increases from 100.000 OC to 101.286 OC. Determine the TB, molality, moles, and molecular weight for the solute if kb for water is 0.512 OC/m. Report each value using the correct number of significant digits. Refer to Example 1.2 and pages 3-4 in the chapter 1 notes for general chemistry 1 to understand significant figures.
Answer:
* \(\Delta T_B=1.286\°C\)
* \(m=2.5m\)
* \(n=0.05mol\)
* \(M=59.76g/mol\)
Explanation:
Hello,
In this case, considering the boiling point rise problem, we consider its appropriate equation:
\(\Delta T_B=imK_b\)
Whereas i is the van't Hoff factor that for this nonvolatile solute is 1, m is the molality, Kb the boiling point constant of water as it is the solvent and ΔT the temperature difference. In such a way, with the given information we obtain:
- ΔT:
\(\Delta T_B=101.286\°C-100.000\°C\\\\\Delta T_B=1.286\°C\)
- Molality (mol/kg):
\(m=\frac{\Delta T_B}{i*K_b}=\frac{1.286\°C}{1*0.512\°C/m}\\ \\m=2.5m\)
- Moles for 20.02 g (0.02002 kg) of water:
\(n=2.5mol/kg*0.02002kg\\\\n=0.05mol\)
- Molar mass:
\(M=\frac{mass}{moles}=\frac{3.005g}{0.050mol} \\\\M=59.76g/mol\)
Best regards.
how does mercury differ from other metals?
a.it is not a solid under normal conditions
b. it does not conduct electricity
c. it does not chemically react with other elements
d. it is not lustrous
Is this statement true or false?
One body system maintains the constant internal environment of the whole body.
Based on the ideal gas law, there is a simple equivalency that exists between the amount of gas and the volume it occupies. At standard temperature and pressure (STP; 273.15 K and 1 atm , respectively), one mole of gas occupies 22.4 L of volume. What mass of methanol ( CH3OH ) could you form if you reacted 7.82 L of a gas mixture (at STP) that contains an equal number of carbon monoxide ( CO ) and hydrogen gas ( H2 ) molecules?
You could form approximately 5.8 grams of methanol (CH3OH) from the given gas mixture at STP.
What is the mass?
Using the Ideal gas equation;
n = PV / RT
n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)
From the question;
nCO = n / 2
nH2 = n / 2
Then;
n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)
n = 0.362 mol
nCO = n / 2 = 0.362 mol / 2 = 0.181 mol
nH2 = n / 2 = 0.362 mol / 2 = 0.181 mol
By stoichiometry;
methanol= nCO = 0.181 mol
Mass of methanol = 0.181 mol * 32.04 g/mol
= 5.8 g
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The rotational spectrum of 79BrºF shows a series of equidistant lines spaced 0-714 33 cm - apart. Calculate the rotational constant B, and hence the moment of inertia and bond length of the molecule. Determine the wavenumber of the J = 9+= 10 transition, and find which transition gives rise to the most intense spectral line at room temperature (say 300 K).
and calculate the number of revolutions per second which the Brf molecule undergoes when in (a) the J = 0 state, (b) the J = 1 state, and (c) the J = 10 state. Hint: Use E = {lwin conjunction with Eqs (2.10) and (2.13), but remember that here w is in radians per second.[its Q season 2 from fundamentals of molcular spectruscopy . banwell.c.n]
In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.
To calculate the rotational constant B, we can use the formula:
B = 1 / (2 * π * Δν)
Where:
B = rotational constant
Δν = spacing between consecutive lines in the rotational spectrum
Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:
B = 1 / (2 * π * 0.71433 cm^(-1))
B ≈ 0.079 cm^(-1)
The moment of inertia (I) of the molecule can be calculated using the formula:
I = h / (8 * π^2 * B)
Where:
h = Planck's constant
Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:
I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))
I ≈ 2.11 x 10^(-46) kg·m^2
The bond length (r) of the molecule can be determined using the formula:
r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)
Where:
μ = reduced mass of the molecule
r_e = equilibrium bond length
To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:
ν = 2 * B * (J + 1)
Substituting J = 9 into the formula, we get:
ν = 2 * 0.079 cm^(-1) * (9 + 1)
ν ≈ 1.58 cm^(-1)
To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:
I ∝ exp(-E / (k * T))
Where:
E = energy difference between the levels
k = Boltzmann constant
T = temperature in Kelvin
At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.
To calculate the number of revolutions per second, we can use the formula:
ω = 2 * π * B * J
Where:
ω = angular frequency (in radians per second)
J = rotational quantum number
For J = 0:
ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s
For J = 1:
ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s
For J = 10:
ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s
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How do I arrange these from greatest to least?
-4.29 x 10^-5
-1.370 x 10^6
-9.3 x 10^-2
Answer:
-4.29 x 10^-5, -9.3 x 10^-2, and then the least is -1.370 x 10^6
Explanation:
-9.3 x 10^-2 = -0.093-4.29 x 10^-5 = -0.0000429-1.370 x 10^6 = -1,370,000Now use common sense.
-0.093 is the greatest number.
Then -429,000 is in the middle.
Lastly, -1,370,000 is the least number.
So -0.0000429 > -0.093 > -1,370,000Why?
Because as a negative number gets bigger, the more least the number is. It is the opposite of positive numbers. For positive numbers, as a number gets bigger, the more greater the number is. That is a rule.
Hope it helped!
Why are salt and sugar both able to dissolve in water, even though the
solutes have different types of chemical bonding?
• Everything can dissolve in water because water is considered
a universal solvent.
O Liquid water is cooler than solid salt and sugar, allowing them
to dissolve easily.
O Salt's ions and sugar's polar bonds are both attracted to the
polar water molecules.
O Small solutes like salt and
large water molecules.
sugar can fit in the spaces between
Answer:
A
Explanation:
Salt and sugar both able to dissolve in water because salt's ions and sugar's polar bonds are both attracted to the polar water molecules.
What is meant by polar covalent bond ?A polar covalent bond is defined as a bond created by exchanging electrons between two atoms with different electronegativities.
Here,
The salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding.
This is because, both sugar and salt are hydrophilic, thus they can both dissolve in water. The definition of hydrophilic is "loving water."
Due to polar covalent connections, these molecules either contain complete charges, like salt, or partial charges, like sugar.
Ions are created when salt separates in water.
Hence,
Salt and sugar both able to dissolve in water because salt's ions and sugar's polar bonds are both attracted to the polar water molecules.
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24. The Henry’s law constant for O2 is 1.3 × 10−3 M/atm at 25 °C. Assuming ideal solution behavior, what mass of oxygen, in grams, would be dissolved in a 40. L aquarium at 25 °C, assuming an atmospheric pressure of 1.00 atm, and that the partial pressure of O2 is 0.21 atm?
Please enter your answer with two sig figs, no units, no scientific notation.
Explain please <3
The aquarium has 0.35 g of dissolved oxygen in it.
What is mass?The quantity of matter in an object is expressed in terms of mass. It is a scalar number, and units like grams, kilograms, and pounds are used to measure it. Weight, the force of gravity acting on an object, is not the same as mass. An object's mass is a fundamental characteristic that exists regardless of where it is or the gravitational environment it is in.
How do you determine it?Henry's law, which connects the concentration of a gas in a solution to its partial pressure, can be used to determine the mass of oxygen (O2) that would be dissolved in a 40 L aquarium:
C = kH x P
where P is the partial pressure of the gas, kH is the Henry's law constant, and C is the concentration of the gas in the solution.
To solve the concentration by rearranging the equation, we obtain:
C = (kH x P)
Using the above values for kH and P, we obtain:
C = (1.3 10^-3 M/atm) x (0.21 atm) = 2.73 10^-4 M.
This indicates that the aquarium's dissolved oxygen concentration is 2.73 x 10^-4 M.
We can use the following equation to determine the mass of O2 dissolved in the aquarium:
Mass = concentration x volume x molar mass.
where O2 has a molar mass of 32 g/mol.
Inputting the values provided yields:
mass = (2.73 x 10^-4 M) x 40 L x 32 g/mol = 0.35 g
As a result, the aquarium has 0.35 g of dissolved oxygen in it.
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Help me out
On another planet, the isotopes of titanium have the given natural abundances.
The average atomic mass of titanium on the given planet is approximately 46.68164 atomic mass units (u). The average atomic mass may vary depending on the specific isotopic composition of titanium found on different celestial bodies or regions.
To calculate the average atomic mass of titanium on the given planet, we need to consider the natural abundances and masses of each isotope of titanium.
The average atomic mass is calculated by multiplying the natural abundance of each isotope by its respective mass and summing them up.
Let's perform the calculation step by step:
Step 1: Multiply the abundance of each isotope by its mass:
(73.700% * 45.95263 u) + (15.000% * 47.94795 u) + (11.300% * 49.94479 u)
Step 2: Calculate the individual contributions from each isotope:
= (0.737 * 45.95263) + (0.150 * 47.94795) + (0.113 * 49.94479)
Step 3: Add up the individual contributions:
= 33.84765431 + 7.1921925 + 5.64179347
Step 4: Sum up the contributions:
= 46.68164 u
Therefore, the average atomic mass of titanium on the given planet is approximately 46.68164 atomic mass units (u).
It's important to note that the calculation assumes the provided natural abundances are accurate and representative of the titanium isotopes on that planet.
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A gas is heated from 246 K to 289 K while its volume is increased from 22.0 L to 30.5 L by moving a large piston within a cylinder. If the original pressure was 0.98 atm, what would be the final pressure?
Sulfur has 6 valence electrons.
Which element could pair with it
in a 1 atom : 1 sulfur ratio?
Answer:
Any Group 2A element (Be, Mg, Ca, Sr, Ba, Ra)
Explanation:
According to the Octet Rule, Sulfur would want to gain two electrons in its outermost shell to achieve an octet (8 total electrons). The elements that could accomplish this in a one-to-one ratio would be Group 2A on the periodic table (alkaline earth metals).
There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, alkaline earth metals are the suitable elements.
What is chemical Compound?Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.
An ionic compound is a metal and nonmetal combined compound. Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.
The compound that is ionic in nature can be dissociated very easily in water. Since ionic compounds are polar in nature, they readily dissolve in water. The elements that could accomplish this in a one-to-one ratio would be alkaline earth metals
Therefore, alkaline earth metals are the suitable elements.
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Which molecule listed below is a nonpolar molecule?
(a) SO3
(b) PF5
(c) CCl4
(d) All of them.
(e) None of them.
convert 7.54 x 10^-8 m to nanometers
7.54 *\(10^8\) meters is 75.4 nanometers.
To convert 7.54 * \(10^8\) meters to nanometers, you can multiply the value by \(10^9\)
as, \(10^9\)nanometers = 1 meter.
7.54 * \(10^8\) m * \(10^9\) = 7.54 x \(10^1\) nm
Therefore, 7.54 *\(10^8\) meters is equal to 75.4 nanometers.
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To convert 7.54 x 10^-8 meters to nanometers, you multiply 7.54 x 10^-8 by 1 x 10^9 to get 75.4 nanometers.
Explanation:To convert meters to nanometers, you need to know that 1 meter is equivalent to 1 x 109 nanometers. Therefore, if you were to convert 7.54 x 10-8 m to nanometers, you would multiply 7.54 x 10-8 by 1 x 109.
Here's how you'd do it: 7.54 x 10-8 m * 1 x 109 nm/m = 75.4 nm. So, 7.54 x 10-8 meters is equivalent to 75.4 nanometers.
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A jet airplane flies from St. Louis, Missouri, to Phoenix, Arizona, in 3 hrs. The distance is
1,500 miles. What is the plane's speed ?
Answer:
Distance = 1500miles
time taken = 3 hours
speed of plane = distance/time taken = 1500/3= 500milesperhour
Explanation:
According to the distance formula , the speed of the plane is 500 miles per hour.
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit interval of time indicating that it is thus a scalar quantity.The average speed of an object in an interval of time is the distance traveled by the object divided by the duration of the interval; the instantaneous speed is the limit of the average speed as the duration of the time interval approaches zero. Speed is not the same as velocity.
Speed has the dimensions of distance divided by time. The SI unit of speed is the metre per second (m/s), but the most common unit of speed in everyday usage is the kilometre per hour (km/h) or in the US and the UK, miles per hour (mph).
Here, speed is calculated as distance /time= 1500/3= 500 miles per hour.
Thus, the speed of plane is 500 miles per hour.
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When equation for neutralization of HBr by Ca(OH)2 is correctly balanced, how many molecules of water will be formed
Answer:
When equation for neutralization of HBr by Ca(OH)₂ is correctly balanced, 1.2046*10²⁴ molecules of water will be formed
Explanation:
A neutralization reaction is one in which an acid (or acidic oxide) reacts with a base (or basic oxide). In the reaction a salt is formed and in most cases water is formed. A Salt is an ionic compound formed by the union of ions and cations through ionic bonds.
In the reactions of a strong acid (those substances that completely dissociate) with a strong base (they dissociate completely, giving up all their OH-), the complete neutralization of the species is carried out:
2 HBr (aq) + Ca(OH)₂ (s) → CaBr₂ (aq) + 2 H₂O (l)
The reaction is already balanced, complying with the law of conservation of matter. This law states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reactants must be equal to the number of atoms present in the products.
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), 2 moles of water H₂O are formed.
On the other hand, Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023 * 10²³ particles per mole. Avogadro's number applies to any substance.
Then you can apply the following rule of three: if 1 mole of H₂O contains 6.023*10²³ molecules, 2 moles of H₂O, how many molecules does it contain?
\(amount of molecules=\frac{2moles*6.023*10^{23}molecules }{1 mole}\)
amount of molecules= 1.2046*10²⁴ molecules
When equation for neutralization of HBr by Ca(OH)₂ is correctly balanced, 1.2046*10²⁴ molecules of water will be formed
John Dalton thought that atoms
1. Cannot be broken down further
2. Have no mass
3. Contain molecules
4. Are all composed of carbon
Answer:
cannot be broken down further
What mass of NO is it possible to make if 634 kJ of energy are used in the following chemical reaction,
The mass of the NO that can be produced is given as 210 g from the calculation.
What is a thermochemical reaction?When we talk about a thermochemical reaction, we are talking about the kind of reaction that we have to write the reactants and the products in the same line as we have to write the heat of reaction.
In this case, we have the reaction that is taking place and it has to occur between nitrogen and oxygen. The product of the reaction in this case is given as NO. We can see that the equation as it is written is an example of a thermochemical reaction.
If 2 moles of NO is produced when 180.6 kJ of energy is used
x moles of NO is produced when 634 kJ of energy is used
x = 2 * 634/ 180.6
x = 7 moles
If the molar mass of NO is 30 g/mol
The mass of NO = 7 mol * 30 g/mol
= 210 g
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