How many atoms are found in a 15.5g sample of Bismuth (Bi)?

There were 0.000871 moles of the diprotic acid present in the sample. It is important to note that without additional information, we cannot determine the identity of the diprotic acid present in the sample.

In order to determine the number of moles of the diprotic acid present in the sample, we need to first calculate the number of moles of NaOH that were required to neutralize the sample.

The balanced chemical equation for the reaction between NaOH and a diprotic acid is:

\(\mathrm{H_2A} + 2\mathrm{NaOH} \rightarrow \mathrm{Na_2A} + 2\mathrm{H_2O}\)

From this equation, we can see that two moles of NaOH are required to react with one mole of the diprotic acid, \(H_2A\). Therefore, if 0.001742 moles of NaOH were required to neutralize the sample, we can calculate the number of moles of \(H_2A\) the present as follows:

\(0.001742 \ \mathrm{mol \ NaOH} \times \dfrac{1 \ \mathrm{mol \ H_2A}}{2 \ \mathrm{mol \ NaOH}} = 0.000871 \ \mathrm{mol \ H_2A}\)

Further analysis, such as titration with a different reagent or spectroscopic analysis, may be necessary to determine the identity of the acid.

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The correct option is C;  II and III

The gases obtained from a landfill sites are ammonia, hydrogen sulfide, methane, and carbon dioxide.

Of these gases, ammonia and hydrogen sulfide are responsible for the odor at  landfill sites.

The odor from burning landfill gas can have deleterious effects on the health of residents owing to its smelly odors.

Also, many air pollutants are produced when the constituents of landfill gas  are burnt.

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Among the given gases, the gas that shows the greatest deviation from ideal behavior at 25 degrees Celsius and 1 atm is likely to be H2 (hydrogen).

1. Size and shape of molecules: Hydrogen gas (H2) consists of diatomic molecules that are very small in size. The size of the hydrogen molecule is relatively larger compared to other gases such as CH4 (methane), SO2 (sulfur dioxide), and O2 (oxygen). The small size of hydrogen molecules leads to a higher probability of molecular interactions and deviations from ideal behavior.

2. Intermolecular forces: Hydrogen gas has relatively weak intermolecular forces compared to other gases. Although it exhibits London dispersion forces, these forces are not as strong as the dipole-dipole interactions in molecules like SO2 and CH4 or the formation of double bonds in O2. The weaker intermolecular forces in hydrogen contribute to larger deviations from ideal behavior.

Based on the size and shape of molecules as well as the strength of intermolecular forces, hydrogen gas (H2) is expected to show the greatest deviation from ideal behavior among the given gases at 25 degrees Celsius and 1 atm.

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Answer: Well to begin with Hydroponics provides the exact needs to the plants appropriately; this simply means that plants will grow faster depending on their genetics and also compared to a plant grown to the normal soil, hydroponic plants grow faster and appear to be much healthier.

Here are some reasons why:

Space Savings. Hydroponics saves an incredible amount of space compared to traditional soil gardening.

Hydroponics Saves Water.

No Weeding Necessary.

Less Pests and Diseases.

The amount, in grams, of iron (III) oxide that will be produced if 4300 kJ of heat energy is released according to the reaction would be 3193.8 grams.

We can use the heat released and the enthalpy of the reaction to calculate the amount of iron (III) oxide produced.

First, let's convert the heat released from kJ to J:

4300 kJ = 4.3 × \(10^6\) J

Next, we can use the enthalpy of the reaction to calculate the moles of iron (III) oxide produced:

Thus:

Mass of \(Fe_2O_3\) = n x Molar mass

= 20 x 159.69

= 3193.8 g

Therefore, 3193.8 grams of iron (III) oxide will be produced if 4300 kJ of heat energy is released during the reaction.

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The amount of heat gained by the water is 500 calories. Thus, option D is correct.

Given:

Mass of water (m) = 100 g

Change in temperature (ΔT) = 30°C - 25°C = 5°C

The specific heat capacity of water (c) is approximately 1 calorie/gram°C.

Now, the amount of heat gained by the water,

Q = mcΔT

Where:

Q is the heat gained or lost by the substance

m is the mass of the substance

c is the specific heat capacity of the substance

ΔT is the change in temperature

Plugging in the values into the formula:

Q = 100 × 1 × 5

Q = 500 calories

Therefore, the amount of heat gained by the water is 500 calories.

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Yes the increase in temperature of sodium chloride will cause a decrease in it solubility.

Answer is True

Sodium chloride is a type of salt whose solubility decreased with increased temperature, this is quite unusual to other solute.

With the case of Sodium Chloride, this principle is applied in purifications like re-crystallization which is used to recover solute in solvents

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The Bohr model is a representation of the electronic configuration of the atom. According to this model, each energy level can hold a certain number of electrons. In the first energy there can only be 2 electrons, in the second and the following energy levels there can be a maximum of 8 electrons.

Sodium, Na which has 11 electrons in total so in the first level it will have two electrons, in the second level it will have 8 electrons and in the third level it will have the missing electron.

In the model proposed by the student, the electrons are represented in blue. The model proposed by the student is incorrect.

We see that in the second energy level he drew 9 electrons, this is incorrect since from the second energy level there can only be 8 electrons, the remaining electron must be located in the third energy level.

Answer:

Liquid isopropanol.

Explanation:

Liquid isopropanol will evaporate earlier than water because the boiling point of isopropanol is less than water. That liquid which have high boiling point require more heat energy for change into vapor state as compared to those liquids that has low boiling point. The isopropanol has boiling point i.e. 82.5 °C while on the other hand, water has boiling point i.e. 100 °C so we can say that isopropanol will evaporate first.

The liquid that will be the first to evaporate within 5 minutes is; Liquid Isopropanol

We have the 2 liquids as;

Liquid Isopropanol

Liquid water

Now, since we are dealing with the one that will evaporate within five minutes, we need to know their boiling points.

From online research;

Boiling point of liquid isopropanol is 82.5°C

Boiling point of liquid water is 100°C

Now, we are told that the same energy is transferred for both liquids. However, boiling point of the liquid with the lower boiling point will be achieved first and as a result will evaporate first since the next stage after boiling point is evaporation of steam.

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Answer:

Answer:

This ammonium laurel sulfates anion consists of a nonpolar hydrocarbon chain and a polar sulfate end group. It means it has a hydrophilic head and hydrophobic tail. There are ammonium ions, sulfate, and fatty acids present.

Lauryl sulfate has lauric acid attach to sulfate ions with carbon-sulfur bond, the fatty acid formed by the covalent bonds between C-C attached to hydrogens. Sulfur also bound to oxygen by covalent bonds. Nitrogen is surrounded by the four hydrogen atoms in the hydrophilic head.

Answer:

Scandium (Sc)

Explanation:

Cr³⁺ is a chromium atom that has lost 3 electrons. A chemical specie becomes positively charged when the number of electrons is lower than the number of protons.

 In this regard, the number of protons is more.

Chromium originally has 24 electrons, on losing 3 electrons it will now have 21 electrons.

The atom with 21 electrons in its neutral state is scandium

Answer:

48 mph

Explanation:

divide time by distance - 20/25 = .8 miles per minute, multiple by 60 to get mph

The cοrrect statement that accοunts fοr the difference in pοlarity οf the twο mοlecules is:

B) N –F bοnds are pοlar, whereas B – F bοnds are nοnpοlar.

In NF₃, the nitrοgen (N) and fluοrine (F) atοms fοrm pοl  ar cοvalent bοnds, resulting in an uneven distributiοn οf electrοn density. This creates a pοlar mοlecule with a net dipοle mοment.

On the οther hand, in BF₃, the bοrοn (B) and fluοrine (F) atοms fοrm nοnpοlar cοvalent bοnds since the electrοnegativity difference between bοrοn and fluοrine is small.

As a result, BF₃ is a nοnpοlar mοlecule.

Thus, The cοrrect statement that accοunts fοr the difference in pοlarity οf the twο mοlecules is: B) N –F bοnds are pοlar, whereas B – F bοnds are nοnpοlar.

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Ammonium chloride is used as an electrolyte in dry cells. D. The solution is acidic is correct.

The salt NH4Cl is acidic. Since NH4Cl has a pH between 4.5 and 6 and a pKa of 9.24, it is just slightly acidic. It is a salt of hydrochloric acid and ammonia, which are both strong acids and weak bases.

NH4Cl is acidic because a salt's pH is determined by how acidic or basic its constituent constituents are. A salt that takes its qualities from its constituents, namely an acid and a base, is created when an acid and a base react.

This reaction is known as neutralization. The potency of the acid and base that combine to make salt determines whether it is acidic or basic.

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Carnot's work attracted little attention during his lifetime, but it was later used by Rudolf Clausius and Lord Kelvin to formalize the second law of thermodynamics and define the concept of entropy.

Sadi Carnot was a French physicist who is known for his studies on the efficiency of heat engines. In 1824, he published a book called "Reflections on the Motive Power of Fire," in which he laid out the principles of thermodynamics and introduced the concept of entropy. His work was crucial in the development of the steam engine, as it helped engineers to understand how to make engines more efficient. Carnot's studies on steam engine efficiency laid the groundwork for the development of the concept of entropy, which is a measure of the disorder or randomness of a system. (C)

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Iron combines with oxygen and water from the air to form rust. If an iron nail were placed in a beaker and allowed to rust for a month, one should find that the rusty nail weighs more than the original nail due to redox-reaction.

The increase in mass of the iron nail is due to the formation of hydrated iron oxide, which we commonly refer to as rust.The chemical formula for rust is Fe2O3. xH2O, where x is the number of water molecules that are present.

Rust is created when iron reacts with oxygen and water in the air. The chemical reaction can be represented as follows:4Fe + 3O2 + 6H2O → 4Fe(OH)3

The rust formation is caused by oxidation that occurs on the surface of the iron. During this reaction, the iron atom loses two electrons to form Fe2+ ions that combine with water molecules to form hydrated iron(II) ions.

The hydrated iron(II) ions react further with oxygen and water to form hydrated iron(III) oxide. The hydrated iron(III) oxide is then dehydrated to form rust.

Fe2+ + 2H2O → Fe(OH)2 + 2H+Fe(OH)2 + 1/2O2 → Fe(OH)3Fe(OH)3 → Fe2O3 + H2O

Therefore, if an iron nail is placed in a beaker and allowed to rust for a month, the rusty nail should weigh more than the original nail.

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6KOH + CO₃(PO₄)₂ → 2K₃PO₄ + 3CO(OH)₂

It is a double displacement reaction.

Double displacement reaction- In aqueous solutions, where ions precipitate and exchange occurs, double displacement processes are most common. For instance, a white precipitate of barium sulphate quickly forms when a solution of barium chloride and sodium sulphate are combined. These are ionic-based reactions.

In double displacement reactions, there is simply an ion exchange between the two reactants and no oxidation or reduction of any of the reactants. Double displacement processes are therefore not redox processes.

The positive ions trade partners with the negative ions during double displacement processes. Ionic chemicals that are dissolved in water undergo several double displacement reactions with one another.

Thus it is a double displacement reaction.

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The correct expression for the percentage yield of calcium oxide is approximately 4808%.

To find the theoretical yield, we need to calculate the stoichiometric ratio between calcium carbonate (CaCO3) and calcium oxide (CaO). The balanced equation for the reaction is:

CaCO3 → CaO + CO2

From the equation, we can see that one mole of calcium carbonate produces one mole of calcium oxide. We can calculate the molar mass of calcium carbonate and calcium oxide to convert the given masses into moles:

Molar mass of CaCO3 = 40.08 g/mol (calcium) + 12.01 g/mol (carbon) + (3 x 16.00 g/mol) (oxygen) = 100.09 g/mol

Molar mass of CaO = 40.08 g/mol (calcium) + 16.00 g/mol (oxygen) = 56.08 g/mol

Using the molar masses, we can convert the given masses into moles:

Moles of CaCO3 = 5.00 g / 100.09 g/mol = 0.04998 mol

Moles of CaO = 2.40 g / 56.08 g/mol = 0.04281 mol

The theoretical yield of calcium oxide is 0.04998 mol, as determined by the stoichiometry of the balanced equation.

Now, we can calculate the percentage yield using the formula:

Percentage yield = (actual yield / theoretical yield) x 100%

Percentage yield = (2.40 g / 0.04998 mol) x 100% ≈ 4808%

Therefore, the correct expression for the percentage yield of calcium oxide is approximately 4808%. However, it's important to note that a percentage yield above 100% suggests a possible error in the experimental procedure or measurements.

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The ionization constant of H₂S is approximately 1.0 x 10⁻⁷.

The ionization constant, also known as the acid dissociation constant (Ka), is a measure of the extent to which an acid dissociates in water. It indicates the degree of ionization of an acid and is typically expressed as the equilibrium constant for the reaction between the acid and water.

In the case of H₂S (hydrogen sulfide), it is a weak acid that can partially dissociate in water to produce hydrogen ions (H⁺) and sulfide ions (HS⁻). The ionization reaction can be represented as follows:

H₂S ⇌ H⁺ + HS⁻

The ionization constant (Ka) represents the equilibrium expression for this reaction. The value of Ka determines the relative strength of the acid. For H₂S, the ionization constant is approximately 1.0 x 10⁻⁷, indicating that it is a weak acid.

This value indicates that H₂S only partially ionizes in water, with a small fraction of H₂S molecules dissociating into H⁺ and HS⁻ ions. The majority of H₂S remains in its molecular form.

It is important to note that the ionization constant can vary depending on factors such as temperature and concentration. The given approximation is a typical value at standard conditions.

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Answer:

hydrogen

Explanation:

Polarization is defined as the change in electrode potential of an electrode in an electrochemical cell as electric current is being passed through the cell. It is a kinetic deviation from equilibrium as current is passed through the electrochemical cell.

It is sometimes as a result of the over-potential caused by the accumulation of hydrogen gas at an electrode.

Answer:

Did u get the answers

Explanation:

Answer:

Compound

Explanation:

-compound is a chemical substance composed of many identical molecules composed of atoms from more than one element held together by chemical bonds.

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Two or more elements are combined to form a compound with a definite proportion.

\(\green {{{\sf Na+Cl = NaCl}}}\)

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Answer:

10.2 mol

Explanation:

given,pressure=240kpa

volume=31L

temperature=87.65°c

req,mole=?

now we have the equation

pv=nRt

When,p=pressure

v=volume

n=moles

R=gas constant

t=temperature

gas constant(R)=8.314L.kpa/k.mol

solution

from the first equation we have an equation

n=pv/Rt

=240×31/8.314×87.65

=7440/728.72

=10.2 mol

The gas-phase decomposition of SO2Cl2 is a first-order reaction, and the rate of the reaction is given by the equation: rate = k[SO2Cl2]

The half-life of a first-order reaction is given by the equation: T1/2 = 0.693/k (a) At 600 K, the half-life for the process is 2.3 x 105 s. To find the rate constant at this temperature, we can use the half-life equation to solve for k: T1/2 = 0.693/k ;2.3 x 105 s = 0.693/k ;k = 0.693 / 2.3 x 105 s = 3 x 10^-5 s-1 , (b) At 320 degree celcius  , the rate constant is 2.2 x 10^-5 s^-1. To find the half-life at this temperature, we can use the half-life equation and substitute in the given rate constant: T1/2 = 0.693/k;T1/2 = 0.693 / 2.2 x 10^-5 s-1 ;T1/2 = 3.15 x 10^4 s Therefore, the half-life of the reaction at 320 degree celcius is 3.15 x 10^4 seconds.

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Takes 30 mins for the egg to reach room temperature

Answer:

See explanation

Explanation:

The reaction between alcohol and acidified potassium dichromate  is a redox reaction. This reaction can be used to detect a drunken driver.

Alcohols can be oxidized to aldehydes, ketones and carboxylic acids depending on the structure of the alcohol. Primary alcohols yield adehydes and carboxylic acids while secondary alcohols are oxidized to ketones.

The colour of the acidified potassium dichromate turns from orange to green when exposed to alcohols from the breath of a drunken driver.

Answer:

2.5 g of platinum

Explanation:

Recall that a catalyst is a specie added to a reaction system to increase the rate of reaction. A catalyst does not participate in the chemical reaction hence it remains unchanged at the end of the chemical reaction. A catalyst merely provides an alternative reaction pathway by lowering the activation energy of the reaction system. Hence a catalysed reaction usually proceeds faster with less energy requirement than the uncatalysed reaction.

Since the catalyst does not participate in the reactions and remains unchanged at the end of the reaction, the mass of platinum will remain the same (2.5g). The mass can only change if a specie participates in the chemical reaction. Hence the answer.

2.5 g of platinum will there be left in the vessel at the end of the reaction

The following information should be considered:

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Latin was the language of learning at medieval and renaissance universities.

After about the 6th century, Latin ceased to be the mother tongue of peoples and nations. Nevertheless, knowledge and use of Latin persisted, partly because most of the Germanic peoples who settled in areas that were once part of the Western Roman Empire lacked a written culture. Therefore, Latin continued to be used for official documents. Of course, Latin was also the language of the Roman Church and its administration.

Latin maintained its role as the primary language for communicating the liberal arts and sciences from the Middle Ages through the Renaissance. Latin was the language of instruction and discussion in the schools and colleges established in the Middle Ages.

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