Answer:
The force and texture of an object matter a lot.
Explanation:
If you were to try and run up a glass hill, could you? You maybe could, but it would be harder to than up carpet.
A wave has a wavelength of 3.3 m and a speed of 5.6 m/s. What is the frequency of this wave
Answer: λ (wavelength) = 3.3 m → ΔS = 3.3 m
v (speed) = 5.6 m/s → ΔV = 5.6 m/s
T (period) → ΔT = ?
f (frequency) = ?
If:
Now: (if, ΔT = T), Using the formula of the period of a wave, find the frequency:
Explanation: Your Welcome u.u
The frequency of this wave is approximately 1.697 Hz.
To find the frequency of a wave, we can use the formula:
frequency (f) = speed (v) / wavelength (λ)
Given:
Wavelength (λ) = 3.3 m
Speed (v) = 5.6 m/s
Substituting these values into the formula, we can calculate the frequency:
f = v / λ
f = 5.6 m/s / 3.3 m
f ≈ 1.697 Hz
Therefore, the frequency of this wave is approximately 1.697 Hz.
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Two city buses are traveling at 24 miles per hour. The buses are the same model and year. One bus has 30 passengers. The other bus has 12 passengers. Which is the best prediction?
A. The buses’ kinetic energies will depend on their routes.
B. The bus with 12 passengers will have less kinetic energy.
C. The bus with 30 passengers will have less kinetic energy.
D. The buses will have the same amount of kinetic energy.
The bus with 12 passengers will have less kinetic energy.
option B.
What is kinetic energy?The kinetic energy of an object is the energy possessed by an object due to its motion.
Mathematically, the formula for kinetic energy is given as;
K.E = ¹/₂mv²
where;
m is the mass of the objectv is the speed of the objectThe bus with greater number of passengers will have more kinetic energy and vice versa.
Thus, the bus with 12 passengers will have less kinetic energy and the bus with 30 passengers will have more kinetic energy.
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How much heat is contained in 100 kg of water at 60.0 °C?
Answer:
so how much heat is there at 0 C? That's zero. But for every degree above that you have 4.184 J. You take it from there. Remember q = mc*delta T.
Two loudsspeakers emit identical sound waves along the x axis. THe osund at a point on the axis has maximum intensity when the speakers are 40 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 50 cm. If the distance between the speakers continuse to increase, at what separation will the sound intensity again be a maximum?
Answer: 30 cm.
Solving
The situation described is that of two sources of sound waves that are separated by some distance. The two waves interfere with each other constructively at some points and destructively at others. When they interfere constructively, the amplitude (and intensity) of the sound wave is greater than when they interfere destructively.
When the speakers are 40 cm apart, the waves that they produce are in phase at some points on the axis, leading to constructive interference and a maximum in the intensity of the sound. As the distance between the speakers is increased beyond 40 cm, the points of constructive interference move farther apart, and the intensity of the sound decreases. When the speakers are 50 cm apart, the waves that they produce are exactly out of phase at some points on the axis, leading to complete destructive interference and a minimum in the intensity of the sound.
If the separation between the speakers continues to increase, the points of constructive interference will move closer together again, and the intensity of the sound will increase. The separation between the speakers at which the intensity of the sound will again be a maximum can be found using the following equation:
d = λ/2 + nλ
where d is the separation between the speakers, λ is the wavelength of the sound wave, and n is an integer that represents the number of half-wavelengths between the speakers.
At the maximum, the separation is an even multiple of half the wavelength, so we can use the formula above with n = 1. The wavelength can be found from the distance between the speakers at the minimum, which is 50 cm, and the distance at the maximum, which is 40 cm:
λ = 2(d_max - d_min) = 20 cm
Substituting λ and n into the formula gives:
d = λ/2 + nλ = 10 cm + 20 cm = 30 cm
Therefore, the sound intensity will be a maximum again when the separation between the speakers is 30 cm.
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Three tension forces OA, OB and OC are equal in magnitude and magnitude of their summation is 200 N. What is the magnitude of each force
Answer:
The magnitude of each force is 66.67 N
Explanation:
Given that the magnitude of the tension forces are equal. Let the magnitude of the tension forces be represented by x, such that;
|OA| = |OB| = |OC| = x
Since their summation = 200 N, then;
|OA| + |OB| + |OC| = 200
This implies that;
x + x + x = 200
3x = 200
x = \(\frac{200}{3}\)
= 66.6667
x = 66.67 N
Therefore, the magnitude of each tension force is approximately 66.67 N
condition necessary for thermodynamic equilibrium
Answer:
For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.
Explanation:
hope it helps :)
Answer: For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.
Explanation:
Two identical bullets are used. Both are released at the same height - one fired out of a gun, the other is dropped. Ignoring air resistance, which hits the
ground first?
Answer:
Both bullets will hit the ground at the same time.
Explanation:
Let's only analyze the vertical problem.
Any object that is not in the floor or resting in some site is being affected by the gravitational force (remember that we are ignoring air resistance)
Then the acceleration of this object will be equal to the gravitational acceleration:
a = -9.8m/s^2
Where the minus sign is because this acceleration goes down.
To get the velocity equation we need to integrate over time, we will get:
v(t) = ( -9.8m/s^2)*t + v0
Where v0 is the initial vertical velocity.
To get the position equation we need to integrate over time again, we will get:
p(t) = (1/2)*( -9.8m/s^2)*t^2 + v0*t + H
Where H is the initial height.
p(t) = (-4.9 m/s^2)*t^2 + v0*t + H
The object will hit the ground when p(t) = 0
Then we need to solve for t the next equation:
(-4.9 m/s^2)*t^2 + v0*t + H = 0
Notice that the only things we need to know are:
H = initial height (we know that is the same for both bullets)
v0 = initial vertical velocity (also is the same for both bullets)
Notice that the horizontal velocity does not affect this equation, then we will get the same value of t for the dropped bullet and for the fired bullet.
This means that both bullets will hit the ground at the same time.
A capacitor of 0.75 F is charged to a voltage of 16 V. What is the magnitude of the charge on
each plate of the capacitor?
The magnitude of the charge on each plate of the capacitor is 12 ×10⁻⁶c
The capacity of the capacitor = 0.75F
Voltage = 16V
F = 0.75×10⁻⁶
A two-terminal electrical device known as a capacitor is capable of storing energy in the form of an electric charge. It is made up of two electrical wires that are spaced apart by a certain amount. A vacuum may be used to fill the space between the conductors.
Using the formula to determine the charge -
Q = CV
Where,
Q = Charge on each plate of the capacitor
C = Capacity of the capacitor
V = The potential difference across plates of the capacitor
Substituting the values -
Q = 0.75 × 10⁻⁶ x 16
Q = 12 x 10⁻⁶
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Which point on the standing wave is a node?
A.A
B.B
C.C
D.D
Point B on the standing wave is referred to as a node. The correct option is B.
In a standing wave, a node refers to a point or region of minimal or zero amplitude. It is a point where the displacement of the wave is always zero, and it remains stationary as the wave oscillates. At a node, the particles or elements that make up the medium through which the wave is propagating do not experience any displacement from their equilibrium positions.
Nodes occur due to destructive interference between two waves of equal frequency and amplitude traveling in opposite directions. The superposition of these waves results in the formation of a standing wave pattern, characterized by nodes and antinodes.
Nodes are important features of standing waves and have several properties:
Fixed position: Nodes maintain a fixed location within the standing wave pattern and do not move as the wave oscillates.
Zero displacements: At nodes, the amplitude of the wave is zero, and there is no displacement of the medium particles or elements.
Energy concentration: Nodes are regions of low energy in a standing wave. The energy of the wave is primarily concentrated in the regions between the nodes, known as antinodes.
Separation distance: The distance between adjacent nodes in a standing wave is equal to half the wavelength of the wave.
Therefore, The correct answer is option B.
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What is exerted when atoms collide with the walls of their container?
O gravity
O pressure
O stress
O friction
Answer:
B
Explanation:
Answer:
Pressure
Explanation: I took a test
Suppose that the stone is launched with a speed of 3 m/s and travels 40 m before coming to rest. What is the approximate magnitude of the friction force on the stone?.
The relationship between velocity, acceleration, and displacement is given by v2 = vo2 + 2as, which is derived from Newton's law of motion. Where a, and s are the acceleration and displacement, and v and vo are the final and starting velocities, respectively. Using the second law of Newton,
The problem mentions the stone's initial speed as 3 m/s. Moreover, the stone will stop after 40m. This indicates that the displacement is 40m, and the final speed is 0 m/s. Calculations for rock acceleration are as follows:
(0 m/s)^2 = (3 m/s)^2 + 2a (40m).
9 m^2/s^2 = -2a(40m) (40m)
0.1 m/s2 is equal to a=-9m2/s2/80m.
This implies that the stone will slow down and come to a stop as a result.
F = 20 kg * -0.1 m/s2. To continue,
F = 2N = 20 kg * 0.1 m/s2. Thus, the frictional force is 2N in magnitude.
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HURRY FAST PLEASE 75 POINTS
A 50 kg block is accelerating
down a 40° incline. The
coefficient of friction (u) between
the block and the incline is 0.30.
Draw the free body diagram,
label the forces, and calculate
acceleration
1. 10.02 m/s2
2. 8.81 m/s2
3. 3.76 m/s2
4. 5.51 m/s2
5. 6.67 m/s2
so hi the answert is probably 4 or e
Answer:
5.51 m/s2
Explanation:
HOPE THIS HELPS!!!!
(Figure 1) is the potential-energy diagram for a 500 g particle that is released from rest at A . What is the particle's speed at B ?
Answer:
Explanation:
according to the graph at B the potential energy of the particle is 2J
therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.
\(E_{k} =1/2mv^{2}\)
2J= 1/2*1/2kg*v^2
8=v^2
v= 2√2 ms-1
During a NASCAR race a car goes 50 m/s around a curved section of the track that has a radius of 250 m. What is the car's
acceleration?
Answer:10
Explanation: Acceleration of car is given by a= v^2/r, v= 50m/s, r= 250m a= 10 m/s^2 2
Use the drop-down menus to complete each sentence.
A plant grows toward a sunny window. This response is an example of
✔ phototropism
.
Sometimes a plant grows around a tree for support. This response is an example of
✔ thigmotropism
.
The roots of a plant grow toward a water source. This response is an example of
✔ hydrotropism
.
The roots of a plant grow down into the soil. This response is an example of
✔ gravitropism
.
the answers are already there
Answer:
The correct answer is - phototropism, thigmotropism, hydrotropism, and gravitropism in order ( already match correctly).
Explanation:
phototropism is a phenomenon in which plants grow towards the light or sun which is accomplished by the hormone auxin in the cells far from the light.
Thigotropism is a type of plant growth that occurs around the tree to support itself which is a touch stimuli response.
The movement of the plant in the direction of the source of the water is known as hydrotropism. In which stimuli is humidity or the water concentration.
The movement of the plant or roots of the plants towards the soil or earth is known as gravitropism here gravity is the stimuli.
Answer:
Use the drop-down menus to complete each sentence.
A plant grows toward a sunny window. This response is an example of
phototropism
.
Sometimes a plant grows around a tree for support. This response is an example of
thigmotropism
.
The roots of a plant grow toward a water source. This response is an example of
hydrotropism
.
The roots of a plant grow down into the soil. This response is an example of
gravitropism
.
Explanation:
Callisto is a moon of Jupiter
(mass= 1.90 x 1027 kg), which orbits
the planet with a period of 16.9 days.
What is the radius of its orbit?
[?] x 10¹ m
Coefficient (green)
Exponent (yellow)
Enter
8.27 x 1013 meres is the orbital radius.
Additional details:-Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution
The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.
6.67 x 10⁻¹¹ N/m²kg
2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7
What distinguishes Callisto, a huge moon orbiting Jupiter, from all other large moons in the solar system?The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.
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2. When an object of mass m slides on a frictionless surface inclined at an angle as shown in the Figure below, the forces acting on it decides the a. acceleration of the object9jo b. speed of the object when it reaches the bottom h L 1 co a
The acceleration of the object in the inclined plane is g sinθ.
The velocity of the object on the inclined plane is √(2gL sinθ).
Given that the inclined surface is a frictionless surface. So, the force of friction is zero. Hence the components of the weight of the object provides the necessary forces to slide the object over the inclined plane.
a) Newton's second law is applied to masses on inclination.
Acceleration due to multiplied by the sine of the angle of inclination provides the acceleration for a frictionless slope of angle in degrees.
The acceleration of the object in the inclined plane is,
a = g sinθ
b) Applying the third equation of motion,
v²- u² = 2as
v² = 2as
v² = 2 x g sinθ x L
Therefore, the velocity of the object on the inclined plane is given by,
v = √(2gL sinθ)
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A 1 kg block of wood is attached to a spring, of force constant 200 N/m, which is attached to an immovable support. The block rests on a frictional surface with a coefficient of kinetic friction of 0.2. A 20 g bullet is fired into the block horizontally compressing the spring a maximum distance of 15 cm. Find the original velocity of the bullet before the collision.
Answer:
\(v=15.9499m/s\)
Explanation:
From the question we are told that:
Mass of wood \(m=1kg\)
force constants \(k= 200N-m\)
Coefficient of kinetic friction \(\mu= 0.2\)
Bullet mass \(m_b= 20 \approx 0.02kg\)
Spring compresion \(y=15cm \approx 0.15 m\)
Generally the equation for kinetic energy of bullet \(K>E_b\) is mathematically given by
Complete Question
\(K.E_b=spring potential energy+work done against friction\)
\(K.E_b=\frac{1}{2} mbv^2\)
\(\frac{1}{2} m_b v^2=\frac{1}{2} ky^2+\mu my\)
\(\frac{1}{2} (0.02)v^2=\frac{1}{2} (0.2)(0.15)^2+0.2(1)(0.15)\)
\(v=15.9499m/s\)
\(v\approx16m/s\)
How do you find the range of a data set?
Answer: You take the biggest number and subtract it from the smallest number.
Explanation: Hope this helps.
Answer:
Subtract the minimum data value from the maximum data value to find the data range.
Explanation:
\(Hope\) \(this\) \(helps!\)
________ is a thermodynamic function that increases with the number of energetically equivalent ways to arrange components of a system to achieve a particular state.
Answer:
entropy
Explanation:
Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a current of 4.33 A. (a) Find the force per meter exerted on the 2.75-A wire. (b) Is the force per meter exerted on the 4.33-A wire greater than, less than, or the same as the force per meter exerted on the 2.75-A wire
Answer:
a)\(\frac{F_1}{L}=1.95*10^-^5N\)
b)\(\frac{F_2}{L}=1.95*10^-^5N\)
Explanation:
From the question we are told that:
Distance between wires \(d=32.2\)
Wire 1 current \(I_1=2.75\)
Wire 2 current \(I_2=4.33\)
a)
Generally the equation for Force on \(l_1\) due to \(I_2\) is mathematically given by
\(F_1=I_1B_2L\)
Where
B_2=Magnetic field current by \(I_2\)
\(B_2=\frac{\mu *i_2}{2\pi d}\)
Therefore
\(F_1=I_1B_2L\)
\(F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L\)
\(\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }\)
\(\frac{F_1}{L}=1.95*10^-^5N\)
b)
Generally the equation for Force on \(I_2\) due to \(I_1\) is mathematically given by
\(F_2=I_2B_1L\)
Where
B_1=Magnetic field current by \(I_2\)
\(B_1=\frac{\mu *I_1}{2\pi d}\)
Therefore
\(\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})\)
\(\frac{F_2}{L}=1.95*10^-^5N\)
how do newton's 3 laws of motion effective everyday life?
Answer:
Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.
Explanation:
The half-life of Silver-105 is 3.57 x 106 seconds. A sample contains 5.78 x 1017 nuclei. What is the decay constant for this decay?
Answer:
The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:
16:42
λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.
Explanation:
A girl with a mass of 32 kg is playing on a swing. There are three main forces
acting on her at any time: gravity, force due to centripetal acceleration, and
the tension in the swing's chain (ignore the effects of air resistance). At the
instant shown in the image below, she is at the bottom of the swing and is
traveling at a constant speed of 4 m/s. What is the tension in the swing's
chain at this time? (Recall that g = 9.8 m/s²)
Tension
Weight
A. 333.6 N
OB. 817.8 N
C. 562.8 N
D. 441.6 N
4 m/s
The tension in the swing's chain at the instant shown in the image is 441.6 N.
option D
What is the tension at bottom swing?At the bottom of the swing, the girl is traveling at a constant speed, so her acceleration is zero. Therefore, the net force acting on her is also zero.
Thus, we have:
0 = T - mg - mv²/r
where;
T is the tension in the swing's chain, m is the girl's mass, g is the acceleration due to gravity, v is her speed, and r is the radius of the swing.At the bottom of the swing, the radius is equal to the length of the chain, so we have:
r = L = 4.0 m
Substituting the values we have:
T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m
Solving for T, we get:
T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m
T = 441.6 N.
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To perform a drug lookup to ensure that the new compound has been added to the computer system properly , select in the toolbar at the top of the screen . a ) Data b ) Close c ) New d ) Save
To perform a drug lookup to ensure that the new compound has been added to the computer system properly we have to select the new from the toolbar at the top of the screen
What is a computer system?A computer system is a collection of computers, related hardware, and related software. The central processing unit (CPU), memory, input/output, and storage devices are the four main components of a computer system. To produce the desired result, all of these parts operate in concert as a single unit.
Selecting the new from the toolbar at the top of the screen will allow us to run a drug lookup to make sure the new compound has been properly added to the computer system.
Therefore the correct answer is the option C
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Help! Il give brainlest to who answers first
Answer:
1. The density of the cube is 1.03 g/mL.
2. Dish soap
Explanation:
1. Determination of the density of the cube.
From the question given above, the following data were obtained:
Mass (m) of cube = 21.7 g
Volume (V) of cube = 21 mL
Density (D) of cube =?
The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Thus, density can be expressed mathematically as:
Density (D) = mass (m) / volume (V)
D = m / V
With the above formula, we can obtain the density of the cube as follow:
Mass (m) of cube = 21.7 g
Volume (V) of cube = 21 mL
Density (D) of cube =?
D = m / V
D = 21.7 / 21
D = 1.03 g/mL
Thus, the density of the cube is 1.03 g/mL.
2. Determination of the layer of density the cube will settle in.
From the question given above,
Subtance >>>>>>>> Density
Vegetable oil >>>>> 0.91 g/mL
Grape juice >>>>>> 0.97 m/L
Water >>>>>>>>>>> 1 g/mL
Dish soap >>>>>>>> 1.03 g/mL
Maple syrup >>>>>> 1.37 g/mL
Comparing the density of the cube (i.e 1.03 g/mL) with those in the table able, we can conclude that the cube will settle in the DISH SOAP layer since they both have the same density.
What is the takeoff distance for an airplane on a runway at
300km/hr with acceleration of 1 m/s 2
Answer:
x = 3472 [m]
Explanation:
To solve this problem we must use the following expression of kinematics:
\(v_{f}^{2}= v_{i}^{2}+(2*a*x)\\\)
where:
Vi = initial velocity = 0
Vf = final velocity = 300 [km/h]
a = acceleration = 1 [m/s^2]
x = takeoff distance [m]
Note: The initial velocity is equal to zero as avion starts its movement from rest.
Now we have to convert units of kilometers per hour to meters per second, the final velocity.
\(300 [\frac{km}{h}]*[\frac{1h}{3600s} ]*\frac{1000m}{1km} \\= 83.33 [\frac{m}{s} ]\)
(83.33)^2 = 0 + (2*1*x)
2*x = 6943.88
x = 3472 [m]
Calculate Suppose an
object weighs 15 g and has
a volume of 5 cm. What is
the density of the object?
If two point masses 1kg & 4kg are seperated by a distance of 2m. Magnitude of gravitational force exerted by 1kg on 4kg is ?
(A) G/4
(B) G
(C) G/2
(D) G/3
Answer:
F = G NewtonsExplanation:
Given:
Mass of 1st body = \(1\:kg\)Mass of 2nd body = \(4\:kg\)To Find:
Magnitude of gravitational forceSolution:
Here, we have a formula
\(F=\dfrac{G.M_{1}.M_{2}}{r^{2}}\)Substituting the values
\(\implies\:\:F = \dfrac{G(1)(4)}{2^{2}}\)
\(\implies\:\:F = \dfrac{4G}{4}\)
\(\implies\:\:F = \dfrac{\cancel{4}G}{\cancel{4}}\)
\(\implies\:\:\red{F = G}\)
Know More:
The applied formula for the above solution is
\({\boxed{F_{G}=\dfrac{G.M_{1}.M_{2}}{r^{2}}}}\)
where,
F\(_{G}\) = Gravitational forceG = Gravitational constantM\(_{1}\) = mass of 1st bodyM\(_{2}\) = mass of 2nd bodyr = distance between two bodies