Answer:
In a transverse wave.ok now u know
ILL GIVE BRAINLIST PLS In which circuit does charge reverse direction many times per second?
A. A DC circuit
B. A combined circuit
C. A parallel circuit D. An AC circuit
Answer: D. An AC circuit
Explanation:
I took it on a test and it was correct ; )
when the mass of an object increases, the forcé of gravity
Answer:
increace
Explanation:
they are both going up
A column of argon is open at one end and closed at the other. The shortest length of such a column that will resonate with a 200 Hz tuning fork is 42.5 cm. The speed of sound in argon must be: Group of answer choices
Answer:
The speed of sound in the argon is 340 m/s.
Explanation:
Given;
fundamental frequency, f₀ = 200 Hz
length of the pipe, L = 42.5 cm = 0.425 m
A pipe that is open at one end and closed at another end is known as a closed pipe.
The wavelength for the first harmonic is calculated as;
L = Node -------> Antinode
L = λ/4
λ = 4L
The speed of the sound is calculated as;
v = fλ
where;
v is the speed of the sound
v = f x 4L
v = 200 x (4 x 0.425)
v = 340 m/s
Therefore, the speed of sound in the argon is 340 m/s.
The weight of the label in the figure is Ws = 32lb and acts at the point shown. The weight of the AD bar is 10lb and acts at the midpoint of the bar. Determine the tension at point AE and the reactions at point D.
The tension at point AE is 28.8 lb, and the reactions at point D are RD = 64.6 lb and RE = 145.4 lb.
the tension at point AE First, we need to calculate the weight of the CD bar, which is given by WC = Weight of CD bar = 5 × 32lbWC = 160 lb
Now we can find the total weight supported by the system as follows: W = Weight of AE bar + Weight of CD bar + Weight of AD bar W = 40 + 160 + 10 = 210 lb
As the weight is distributed evenly, the vertical forces at D and E should be equal: RD + RE = 210 lb
Next, we will determine the moments around point D.
This will help us find the tension at point AE.∑MD = 0(-32 × 2) + (40 × 4) + (160 × 7) + (10 × 5) + AE × 10 = 0Solving for AE,AE = 28.8 lb
Determine the reactions at point D
Now we can solve for the reactions at point D.
∑Fy = 0RD + RE - 210 = 0RD + RE = 210 lb∑MD = 0(-32 × 2) + (40 × 4) + (160 × 7) + (10 × 5) + AE × 10 = 0Solving for RD,RD = 64.6 lb
Now that we have RD, we can solve for RE:RE = 210 - RDRE = 145.4 lb
Therefore, the tension at point AE is 28.8 lb, and the reactions at point D are RD = 64.6 lb and RE = 145.4 lb.
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help me
Write your answer on the lines below.
4. Are the light waves reflecting off a red stop sign longer or shorter than the waves reflecting off a violet-colored jacket? Explain how you know.
The light waves reflecting off a red stop sign would be longer than the light waves reflecting off a violet-colored jacket. This is because red light has a longer wavelength than violet light.
Light waves and reflectionLight waves, like all waves, are characterized by their wavelength. The wavelength of a wave determines its color, with shorter wavelengths appearing as blue and violet, and longer wavelengths appearing as red and orange.
Because the wavelength of red light is longer than the wavelength of violet light, the light waves reflecting off the red stop sign would be longer than the light waves reflecting off the violet-colored jacket.
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HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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Q1: A pupil fires an elastic band gun. Just before it is released the band is at its most stretched point. If the band is extended by 0.36m and the band is fired with 412J of energy, what is the spring constant of the band?
The spring constant of the given band is equal to 6.36 × 10³ N/m.
What is Hooke's law?Hooke's law can be demonstrated as a law that states that the force (F) required to extend or compress a spring by displacement linearly w.r.t. that distance along a straight line.
The spring force can be represented in the form of mathematical equation:
F = -kx,
where k is a spring constant and x is the deformation of the spring. The negative sign shows that the spring returns to its original position.
The energy stored in the spring when it is extended is given by:
E = (1/2)kx²
Given, the energy stored in the band when it is extended, E = 412 J
The distance by which the band is extended, x = 0.36 m
412 = (1/2)×k (0.36)²
k = 6.36 × 10³ N/m
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Suppose a 115 N force is applied to a lawnmower handle at an angle of 25° with the ground and
the lawnmower moves along the surface of the ground. If the lawnmower moves 1,600 m, how
much work was done?
W=F d cos α
W=115 x 1600 x cos 25
W=1.67 x 10⁵ J
1. A charge of 6.4 C passes through a cross-sectional area or conductor in 2s. How much charge will pass through a cross sectional area of the conductor in 1 min?
The amount of charge that will pass through the cross-sectional area of the conductor in 1 min is 192 C.
What is the amount of charge?
We can use the formula Q = I * t,
where;
Q is the amount of charge, I is the current, and t is the time.Given that a charge of 6.4 C passes through a cross-sectional area of the conductor in 2 s, we can find the current using the formula:
I = Q / t = 6.4 C / 2 s = 3.2 A
So, the current through the conductor is 3.2 A.
To find the amount of charge that will pass through the cross-sectional area of the conductor in 1 min (60 s), we can use the same formula:
Q = I * t = 3.2 A * 60 s = 192 C
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Find the force between charges of +10.0 C and -50.0 C located 20.0 cm apart.
Answer: SI
Explanation:
What happens to your kinectic energy when your gravitational potential energy decreases?
Answer:
As r decreases, we lose gravitational potential energy - in other words, U G U_G UGU, start subscript, G, end subscript becomes more negative. Because energy is conserved, the velocity must increase, resulting in an increase in kinetic energy.
Explanation:
If two vector are perpendicular to each other, how should you add them
Answer:
Using pythagoras theorem
Answer:
use the pythagorean theorem
Explanation:
Optical fibers can provide people with natural sunlight for free, but what are some disadvantages to using optical fibers to light a
room with sunlight?
The advantages are Optical fibers can be expensive to install and maintain. They require a direct line of sight to the sun, which may be blocked by tall buildings or trees. Without proper insulation, the light can be very hot and create a fire hazard.
What is Optical fibers?Optical fibers are thin strands of material, usually glass or plastic, that are used to transmit light signals over long distances. Optical fibers can be used for a variety of applications, including telecommunications, medical imaging, and sensing.
The light from optical fibers is very directional, so it can be hard to evenly distribute the light around a room. Optical fibers can be prone to breakage from natural disasters or other causes.To learn more about Optical fibers
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Suppose a rocket in space is accelerating at 1.5 m/s2. If, at a later time, the rocket quadruples its thrust (i.e., net propelling force), what is the new acceleration?
A car starts from rest and experiences a constant acceleration of 5 m/s2 until it reaches a speed of 650 meters
per second. How long does this process take?
What’s the unknown variable?
1. Final velocity
2. Distance
3. Acceleration
4. Initial velocity
5. Time
Answer: Time.
Explanation:
Hey there!!!
The reason is,
According to the question we have,
Initial velocity = 0m/s { as it starts from rest}.
Final velocity = 650 m/s
acceleration = 5m/s^2.
Looking on this formula,
\(a = \frac{v - u}{t} \)
Where "v" represents final velocity, "u" represents initial velocity and "a" represents acceleration. We dont have is time "t".
So, it's obvious that tine is an unknown variable.
Hope it helps...
The density of ice is 0.92 g/cm 3 . An ice sculptor orders a one cubic meter block of ice. What is the mass of the block? Hint: 1 m 3= 1,000,000 cm 3 . Give your answer in grams and kilograms.
Answer: The Volume is 1,000,000 cm3
Explanation:
I believe that the hint is giving you your volume and I know for a fact that mass =density x volume and if you follow that equation, you should be able to find the answer :) I hope that helped at all.... (If that was confusing, I think it's saying the volume is 1,000,000 cm3)
A baseball is tossed straight up in the air. The table shows the height and velocity of the ball at different times as it moves through the air.
Time in Air (seconds) Height of Ball Above Ground (feet) Velocity
(feet per second)
0.00 4 32
0.25 11 24
0.50 16 16
0.75 19 8
1.00 20 0
1.25 19 −8
1.50 16 −16
1.75 11 −24
2.00 4 −32
Which statement is true about the kinetic energy of the baseball at the moment it reaches its maximum height?
The baseball's kinetic energy is less than zero at that instant.
At that moment, all the baseball's kinetic energy has been lost as heat to the atmosphere.
The baseball's kinetic energy is greater than zero at that instant.
✅ At that moment, all the baseball's kinetic energy has been converted to potential energy. (correct answer)
Answer: At that moment, all the baseball's kinetic energy has been converted to potential energy.
Explanation: I took the test
A helicopter is ascending vertically witha speed of 5.40 m/s. At a height of 105 m above the earth a package is dropped from the helicopter. How much time does is take for the package to reach the ground
Answer: 5.21 s
Explanation:
Given
Helicopter ascends vertically with \(u=5.4\ m/s\)
Height of helicopter \(h=105\ m\)
When the package leaves the helicopter, it will have the same vertical velocity
Using equation of motion
\(\Rightarrow h=ut+\dfrac{1}{2}at^2\\\\\Rightarrow 105=-5.4t+0.5\times 9.8t^2\\\Rightarrow 4.9t^2-5.4t-105=0\\\\\Rightarrow t=\dfrac{5.4\pm \sqrt{5.4^2+4\times 4.9\times 105}}{2\times 4.9}\\\\\Rightarrow t=\dfrac{5.4\pm 45.68}{9.8}\\\\\Rightarrow t=5.21\ s\quad \text{Neglect negative value}\)
So, package will take 5.21 s to reach the ground
a roller coaster weighs 2000 kg This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.
The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.
Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.
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Suppose that a public address system emits sound uniformly in all directions and that there are no reflections . The intensity at a location 22 m away from the sound source is 3.0×10−4W/m23.0×10 −4 W/m 2 . What is the intensity at a spot that is 78 m away?
Answer:
\(I_{2}=2.39*10^{-5} W/m^{2}\)
Explanation:
The definition of the intensity in terms of power is given by:
\(I=\frac{P}{A}\)
Where:
P is the powerA is the areaIf the sound emits uniformly in all directions and that there are no reflections, we can assume the geometry of the wave sound is spherical.
Let's recall the area of a sphere is \(A = 4\pi R^{2}\)
To the first location we have:
\(I_{1}=3*10^{-4} W/m^{2}=\frac{P}{4\pi 22^{2}}\)
and to the second location we have:
\(I_{2}=\frac{P}{4\pi 78^{2}}\)
Now, we can divide each intensity to find the second intensity.
\(\frac{I_{2}}{I_{1}}=\frac{\frac{P}{4\pi 78^{2}}}{\frac{P}{4\pi 22^{2}}}\)
\(I_{2}=I_{1}* \frac{22^{2}}{78^{2}}\)
\(I_{2}=3*10^{-4}\frac{22^{2}}{78^{2}}\)
\(I_{2}=2.39*10^{-5} W/m^{2}\)
I hope it helps you!
Answer:
I = 2.4*10⁻⁵ W
Explanation:
By definition the intensity of a sound source, is the power emitted from the source divided by the area of the surface covered by the sound waves.Assuming that the source is a point source, so it emits sound uniformly in all directions, and there are no reflections, this area is just the area of a sphere centered in the point source and with radius equal to the distance between the source and the point where the intensity is measured, as follows:\(I = \frac{P}{4*\pi *r^{2}} (1)\)
If I and r are givens of the problem, we can solve (1) for P, as follows:\(P = I*4*\pi *r^{2} = 3.0e-4*4*\pi * (22m)^{2} = 1.83 W (2)\)
Since the power is the same at any distance from the source, we can obtain the new value of I, replacing in (1) the value of P and the new value of r, as follows:\(I = \frac{P}{4*\pi *r^{2}} = \frac{1.83W}{4*\pi *(78m)^{2}} =2.4e-5 W/m2 (3)\)
If you have an applied force in the 4th quadrant what direction will the force have to be (what quadrant) to bring the force into equilibrium?
Answer:I’m not sure, but i believe it is the second quadrant.
Explanation: The forces need to add to zero and opposite vectors subtract, so if there is an equal force or vector moving opposite (in the second quadrant), it will sum to zero
An ant climbs vertically on a fence. Its motion is shown on the following graph of vertical position � yy vs. time � tt. Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec. Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec. What is the instantaneous speed of the ant at time � = 8 s t=8 st, equals, 8, start text, space, s, end text?
The instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s.
To find the instantaneous speed of the ant at time t=8s, we need to calculate the derivative of the displacement function with respect to time. Since the displacement of the ant is given by a piecewise function, we need to differentiate each segment of the function separately and then piece them together. From 0s to 4s, the displacement of the ant decreases linearly from 6m to 2m. The slope of this segment is -1m/s. From 4s to 7s, the displacement of the ant is constant at 2m. The slope of this segment is zero. From 7s to 9s, the displacement of the ant increases linearly from 2m to 5m. The slope of this segment is 1.5m/s. Finally, from 9s to 10s, the displacement of the ant is constant at 5m. The slope of this segment is zero.
Therefore, the instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s. This means that the ant is moving upwards at a constant speed of 1.5m/s at time t=8s. It's important to note that the instantaneous speed of the ant tells us how fast it's moving at a specific moment in time. It's not the same as the average speed over a given time interval, which would be calculated by dividing the total displacement by the total time elapsed.
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How much would a 10 kg suitcase weigh on the surface of…?
4.Briefly Describe how a Nuclear Power Plant works.
Nuclear Power plant are used to generate electrical energy.
In nuclear power plant, nuclear fission occurs.
Nuclear fission is a process in which one atom splits into two atoms.
During this process, large amount of heat energy is released.
This heat energy is used to generate steam.
Turbine starts moving due to the steam.
This turbine converts mechanical energy into electrical energy.
Using the information from the movie champions what is one conclusion about the history of the sports
One of the conclusion about the history of sports that can be drawn from the movie "Champions" is that sports have a long and rich history that is intertwined with the history of human civilization.
What is Champions about?From the ancient Olympic Games to the modern-day Olympics, sports have been a way for people to come together and compete in a spirit of sportsmanship and competition. Sports have also been a way for people to express themselves, to build community, and to achieve personal goals.
The movie "Champions" tells the story of a group of young men who come together to form a football team. The team is made up of boys from different backgrounds and with different abilities. However, they are all united by their love of football and their desire to win.
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A big rock falls from a height towards water below, and hits water at a speed of 12 m/s. Rock was at a height of 15 m before falling and weighs 65 kg.
a) What was the average force of air resistance (e.g., friction) acting on the rock?
b) What is the force of friction underwater if the rock reaches a depth of 2.5 m before stopping and there is a buoyant force of 650 N [upward] acting on the rock once underwater.
The frictional force of air resistance is; 949N while the force of friction underwater is; 1859N.
What is the Frictional force of air resistance?The frictional force on the action rock can be evaluated as follows;
F - W = ma
However, the acceleration of fall a can be evaluated as follows;
a = (12² -0²)/2× 15
a = 144/30 = 4.8m/s².
a) Hence, the air resistance, frictional force, F = (65×9.8) + (65 ×4.8)
F = 949N.
b) When reaches a depth of 2.5m, it follows that the acceleration is;
a = (0²-12²)/(2×2.5)
a = 144/5 = 28.8m/s².
On this note, the force balance is;
F + 650 = 65(9.8 + 28.8)
F = 2509 - 650
F = 1859N.
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A hiker walks from
(x1, y1) = (−3.60 km, 3.25 km) to (x2, y2) = (3.05 km, 5.90 km). (Take east to lie along the positive x-axis and north to lie along the positive y-axis.)
(a) What distance has he traveled? (Assume the hiker walked in a straight line.)
(b) The hiker desires to return to his starting point. In what direction should he go? (Give the angle with respect to due east. Enter an angle between 0° and 360°.)
(a) The distance travelled by the hiker is 7.16 km
(b) If the hiker desires to return to his starting point, he should move at 201.71° with respect to east.
Form a right angled triangle with the distance between initial and final points as hypotenuse. The adjacent side will be the total distance travelled on x-direction and the opposite side will be the total distance travelled in y-direction.
Adjacent side = \(x_{2}\) - \(x_{1}\) = 3.05 - ( - 3.6 )
Adjacent side = 6.65 km
Opposite side = \(y_{2}\) - \(y_{1}\) = 5.9 - 3.25
Opposite side = 2.65 km
According to Pythagoras theorem,
\(Hypotenuse^{2}\) = \(Opposite side^{2}\) + \(Adjacent side^{2}\)
\(Hypotenuse^{2}\) = \(2.65^{2}\) + \(6.65^{2}\)
Hypotenuse = √ ( 7.02 + 44.22 )
Hypotenuse = 7.16 km
sin θ = Opposite side / Hypotenuse
sin θ = 2.65 / 7.16
θ = \(sin^{-1}\) ( 0.37 )
θ = 21.71°
This is the angle in which the hiker travelled from initial to final direction. The angle in which the hiker should travel to return to initial point with respect to east is
θ = 21.71° + 180°
θ = 201.71°
Therefore,
(a) The distance travelled by the hiker is 7.16 km
(b) If the hiker desires to return to his starting point, he should move at 201.71° with respect to east.
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Match the technology that uses radio waves to the field in which it is used.
research
communication
broadcasting
medicine
navigation
Correct!
AM and FM stations
CB radios
magnetic resonance imaging
global positioning system
radio telescopes
Checking the what will reduce the possibility of having to rebuild or replaced the engine?
Checking the oil will reduce the possibility of having to rebuild or replaced the engine.
what is an engine ?
A device created to transform one or more sources of energy into mechanical energy is known as an engine or motor. Potential energy, heat energy, chemical energy, electric potential, and nuclear energy are all forms of energy that are readily available.
The lubricating function of engine oil is crucial. It shields and stops all the moving parts from rubbing against one another. Metal-on-metal wear would quickly kill your engine without lubrication.
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a plastic rod is rubbed with cotton and it is observed that the rod acquires a negative charge. the same cotton is brought near the cap of a positively charged electroscope. state the observation and explain the observation on the leaf of the electroscope
This observation demonstrates the principle of electrostatics, which is the study of electric charges at rest. It highlights the fact that charged objects can interact with each other, and that opposite charges attract while like charges repel.
When a plastic rod is rubbed with cotton, electrons from the rod are transferred to the cotton, leaving the rod with an excess of positive charges, and the cotton with an excess of negative charges. This results in the rod acquiring a negative charge.
When the same cotton is brought near the cap of a positively charged electroscope, the leaves of the electroscope will diverge. This happens because the positively charged cap attracts the negative charges on the cotton, causing the electrons to move towards the cap. As a result, the leaves of the electroscope acquire a negative charge, and they repel each other due to their like charges.
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