How does changing the electronegativity of the atoms affect the bond polarity?.
Answers
The polarity of a bond can be defined as the degree to which the electrons in a chemical bond are distributed between the two atoms of the bond. Polarity arises from differences in electronegativity, which is a measure of the ability of an atom to attract electrons.
Therefore, changes in electronegativity have an impact on bond polarity. When two atoms with different electronegativities bond, the electrons are attracted to the more electronegative atom. This results in the more electronegative atom having a partial negative charge, and the less electronegative atom having a partial positive charge.
This is known as a polar covalent bond. The greater the difference in electronegativity between the two atoms, the more polar the bond. If the difference in electronegativity between the two atoms is zero, the bond is considered nonpolar. Therefore, as the electronegativity of the atoms in a bond increases, the bond polarity increases.
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Related Questions
he long run equilibrium condition for perfect competition is:
a. P=AVC=MR=MC.
b. Q=AVC=MR=MC.
c. Q=ATC=MR=MC.
d. P=ATC=MR=MC.
Answers
Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.
The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).
Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.
In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.
Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.
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Why is 1-methylhexane not a legitimate name for a compound?
Answers
Answer:
It is not a legitimate chemical name because the methyl group on carbon 1 increases the length of the carbon chain to seven carbon atoms thus making the parent compound heptane
Explanation:
Chemical compounds are named according to rules in the IUPAC nomenclature.
In naming organic compounds, parts of rules is to find out the parent or root compound. This is determined by finding out the longest carbon chain and then checking if it contains single or multiple bonds. (that is if it is an alkane- with single bonds, alkene-with double bonds or an alkyne- with triple bonds)
From the question the parent or root name is an alkane containing 6 (Hex-) carbon atoms, while the methyl group is substituent
(CH₃)-CH₂-CH₂-CH₂-CH₂-CH-CH₃
However the alkyl substituent on carbon 1 increases the the length of the carbon chain to 7 (Hept-) instead of 6. Hence the correct IUPAC nomenclature is heptane and not 1-methylhexane.
which type of atomic orbital can be described as having 2 lobes of electron density separated by a nodal plane?
Answers
The type of atomic orbital that can be described as having 2 lobes of electron density separated by a nodal plane is the P orbital.
In atomic theory, an atomic orbital is a mathematical function that describes the behavior of one electron in an atom. It is a region in space with a high probability of locating an electron.
There are 3 types of orbitals available in each sub-shell of an atom. The sub-shell in each shell can be used to predict the number of orbitals.
There are 1 s-orbital, 3 p-orbitals, 5 d-orbitals, and 7 f-orbitals available in the first, second, and third shells, respectively. The type of atomic orbital that can be described as having 2 lobes of electron density separated by a nodal plane is the P orbital.
Each P orbital has two lobes of electrons located on either side of the nucleus separated by a nodal plane. The lobes can be polarized, making them more or less prominent depending on the situation.
This configuration provides the P orbital with a unique geometry and makes it highly suitable for molecular bonding.
The P orbital has a total of three different orientations. Each orientation corresponds to a different direction in space in which the lobes can be located. The three orientations are Px, Py, and Pz.
Each P orbital can hold a maximum of 2 electrons.
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Define and give an example of convection
Answers
Answer:
Boiling water- When water boils, the heat passes from the burner into the pot, heating the water at the bottom. This hot water rises and cooler water moves down to replace it, causing a circular motion. ... ice melting - Ice melts because heat moves to the ice from the air.
Explanation: mark me brainlliest pls (also hopes this helps!!)
o facilitate ease of dose calculations for cefazolin injection, your department policy
states that the resulting concentration after reconstitution should be 100 mg/mL. The
packaging insert for cefazolin 1-g vial instructs you to add 3.4 mL of sterile water without
bacteriostat, resulting in a reconstituted solution of 250 mg/mL
i. What is the final volume of the reconstituted cefazolin solution?
A 3 mL
B. 4 mL
C. 5 mL
D. 2.5 mL
ii. What is the volume of the cefazolin powder?
A 0.4 mL
B. mL
C. 0.7 mL
D. 0.6 mL
iii. What is the final volume of the 100mg/mL cefazolin solution?
A. 6 mL
B. 8 mL
C. 7 mL
D. 10 mL
Answers
The final volume of the reconstituted cefazolin solution is 4 mL. The volume of the cefazolin powder is 0.6 mL. The final volume of the 100 mg/mL cefazolin solution is 10 mL.
The packaging insert instructs to add 3.4 mL of sterile water without bacteriostat to the 1-g vial of cefazolin. This results in a reconstituted solution with a concentration of 250 mg/mL.
To find the final volume, we can set up the equation:
Concentration of reconstituted solution = Amount of drug / Final volume
Using the given concentration (250 mg/mL) and the amount of drug (1 g = 1000 mg), we can rearrange the equation to find the final volume:
250 mg/mL = 1000 mg / Final volume
Solving for the final volume:
Final volume = 1000 mg / 250 mg/mL = 4 mL
Therefore, the final volume of the reconstituted cefazolin solution is 4 mL.
To find the volume of the cefazolin powder, we need to subtract the volume of sterile water added from the final volume of the reconstituted solution.
Given that 3.4 mL of sterile water is added to the vial, and the final volume of the reconstituted solution is 4 mL, we can calculate the volume of the cefazolin powder as follows:
Volume of cefazolin powder = Final volume - Volume of sterile water added
Volume of cefazolin powder = 4 mL - 3.4 mL = 0.6 mL
Therefore, the volume of the cefazolin powder is 0.6 mL.
To determine the final volume of the 100 mg/mL cefazolin solution, we can use the concentration and the amount of drug.
We are given that the resulting concentration after reconstitution should be 100 mg/mL. Considering the amount of drug is 1 g (1000 mg), we can set up the following equation:
Concentration of reconstituted solution = Amount of drug / Final volume
Using the given concentration (100 mg/mL) and the amount of drug (1000 mg), we can rearrange the equation to find the final volume:
100 mg/mL = 1000 mg / Final volume
Solving for the final volume:
Final volume = 1000 mg / 100 mg/mL
Final volume = 10 mL
Therefore, the final volume of the 100 mg/mL cefazolin solution is 10 mL.
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ΔS is negative for the reaction ___
[A] Mg(NO3)2(aq)+K2CO3(aq)→MgCO3(s)+2NaNO3(aq)
[B] LiOH(aq)→Li+(aq)+OH−(aq)
[C] C6H12O6(s)→6C(s)+6H2(g)+3O2(g)
[D] 2NH3(g)→N2(g)+3H2(g)
[E] CH3OH(l)→CH3OH(g)
Answers
ΔS is negative for the reaction [D] 2NH3(g) → N2(g) + 3H2(g). The entropy (ΔS) of a substance is the measure of its molecular disorder.
It is a measure of the randomness of the system. The entropy of a substance is greater in a gaseous state than in a liquid or solid state. As a result, when a substance moves from a solid state to a liquid state and then to a gaseous state, its entropy increases.
Therefore, ΔS is negative for the reaction [D] 2NH3(g) → N2(g) + 3H2(g). As the number of gas molecules decreases, the entropy of the system decreases when NH3 is converted to N2 and H2. The remaining options have an increase in entropy. As a result, the answer is [D] 2NH3(g) → N2(g) + 3H2(g).
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when sugar is mixed with water what does it form?
Answers
The answer is Solution!
Explanation:
Solution is a homogeneous mixture
of two or more substance. In a
sugar solution, sugar gets uniformly
mixed with water
The limiting reactant is the reactant that is consumed first and thus the amount of product generated by the reaction is limited by that reactant. The excess reactant is the reactant that would not be entirely consumed. Identify the limiting reactant and the reactant in excess when 1.4 grams of Al are reacted with 95 mL of a 0.10 M CuSO4 solution. Note: To do this, compare the answers to questions 3 and 5. Which is the smaller amount? The reactant that produces the smaller amount of product is the limiting reactant. Limiting reactant Reactant in excess = 7. determine the mass of Cu that should be produced on complete reaction of 1.4 g AL by filling in the following dimensional analysis set-up and completing the problem. 2Al(s) + 3CuSO.(aq) 3Cu(s) + Al2(SO4)3(aq) Note: This is called the theoretical yield - the maximum possible amount that could be produced by complete reaction of a given amount of reactant as calculated from stoichiometry
Answers
The limiting reactant in the given reaction is Al, and the reactant in excess is \(CuSO_4\). The smaller amount is the amount of Al (1.4 grams), which makes it the limiting reactant.
In comparison, 95 mL of a 0.10 M \(CuSO_4\) solution corresponds to a larger amount. Therefore, Al is the limiting reactant, and \(CuSO_4\) is the reactant in excess. To determine the mass of Cu that should be produced on complete reaction of 1.4 g Al, we need to use stoichiometry. From the balanced equation, we can see that the ratio of Al to Cu is 2:3. This means that for every 2 moles of Al, we should produce 3 moles of Cu. First, we convert the mass of Al to moles using its molar mass. Then we use the mole ratio to calculate the moles of Cu. Finally, we convert the moles of Cu to grams using its molar mass.
Let's calculate it:
Given:
Mass of Al = 1.4 g
Molar mass of Al = 26.98 g/mol
Molar mass of Cu = 63.55 g/mol
First, calculate the moles of Al:
\(\[\text{{moles of Al}} = \frac{{\text{{mass of Al}}}}{{\text{{molar mass of Al}}}} = \frac{{1.4 \, \text{{g}}}}{{26.98 \, \text{{g/mol}}}} = 0.052 \, \text{{mol}}\]\)
According to the stoichiometry, the moles of Cu should be:
\(\[\text{{moles of Cu}} = \frac{{\text{{moles of Al}} \times 3}}{{2}} = \frac{{0.052 \, \text{{mol}} \times 3}}{{2}} = 0.078 \, \text{{mol}}\]\)
Finally, calculate the mass of Cu:
\(\[\text{{mass of Cu}} = \text{{moles of Cu}} \times \text{{molar mass of Cu}} = 0.078 \, \text{{mol}} \times 63.55 \, \text{{g/mol}} = 4.96 \, \text{{g}}\]\)
Therefore, the theoretical yield of Cu that should be produced from the complete reaction of 1.4 g Al is 4.96 grams.
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What causes the release of energy in an exothermic reaction? Bonds breaking Bonds breaking A catalyst A catalyst Bonds being formed Bonds being formed Electrons escaping the bond
Answers
Answer:
weak bonds break and strong bonds form
Explanation:
An exothermic reaction is a chemical reaction in which heat energy is evolved during the reaction process.
Bond formation requires energy while bond breakage releases energy. More energy is needed for the formation of weak bonds as compared to strong bonds.
Hence, when weak bonds break, they release more energy than needed to make a corresponding strong bond leading to the release of the remaining energy as heat.
the scientific advances made by louis pasteur helped to â€"":______.
Answers
The scientific advances made by Louis Pasteur helped to revolutionize the fields of microbiology and medicine.
Louis Pasteur's discoveries in microbiology and immunology led to significant improvements in public health and disease prevention. His germ theory of disease established that many illnesses were caused by microscopic organisms, and he developed methods of pasteurization and sterilization to kill harmful bacteria and prevent contamination. Pasteur also created vaccines for several diseases, including rabies and anthrax, which have saved countless lives. His contributions to science and medicine continue to impact our understanding and treatment of infectious diseases today.
The scientific advances made by Louis Pasteur helped to "improve public health and revolutionize the field of microbiology."
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Joy mixed baking soda and vinegar for her volcano model. She saw lots of bubbling and fizzing. What can she infer happened
A chemical change
A change in state liquid to solid
Matter was created
A physical change
Answers
Answer:
a chemical change
Explanation:
bubbles formed
Answer:
Explanation:
✔︎A chemical change
✖︎wich is D
would be ur answer
Explanation:
❐A chemical change happens when one chemical substance is transformed into one or more different substances, such as when iron becomes rust. Chemical changes occur through the process of chemical reactions, and the resulting substances have different properties because their atoms and molecules are arranged differently.
CAN I PLZ GET MARK AS THE BRAINLIEST? ")
Cassandra builds a galvanic cell using a zinc electrode immersed in an aqueous Zn(NO3)2 solution and an copper electrode immersed in an aqueous CuCl2 solution at 298 K. Which species is produced at the anode
Answers
In the galvanic cell that Cassandra builds with a zinc electrode in a Zn(NO3)2 solution and a copper electrode in a CuCl2 solution at 298 K, the species produced at the anode is Zn2+.
1. In a galvanic cell, the anode is where oxidation occurs.
2. The zinc electrode (Zn) will act as the anode, as it has a lower reduction potential compared to the copper electrode (Cu).
3. During the oxidation process at the anode, the zinc electrode loses electrons and becomes Zn2+ ions, which dissolve into the aqueous Zn(NO3)2 solution.
4. Therefore, the species produced at the anode in this galvanic cell is Zn2+.
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Tooth enamel is composed of hydroxyapatite, whose simplest formula is Cas (PO4)3OH, and whose corresponding Ksp 6.8 x 10 2. As discussed in the "Chemistry and Life" box in Section 17.5 in the textbook, fluoride in fluorinated water or in toothpaste reacts with hydroxyapatite to form fluoroapatite Cas (PO4)3F, Ksp1.0 x 10-60
Answers
Fluoride ions can replace hydroxide ions in hydroxyapatite to form fluoroapatite, which has a lower solubility product constant (Ksp) than hydroxyapatite. The reaction is as follows:
Cas(PO4)3OH (s) + 3F- (aq) ⇌ Cas(PO4)3F (s) + 3OH- (aq)
The equilibrium constant for this reaction is given by:
K = ([Cas(PO4)3F][OH-]^3)/([Cas(PO4)3OH][F-]^3)
At equilibrium, the Ksp of fluoroapatite is given by:
Ksp = [Cas(PO4)3F][OH-]^3
We can use these equations to determine the concentration of fluoride ions required to precipitate hydroxyapatite and form fluoroapatite. At this point, the concentration of hydroxyapatite will be equal to its solubility product constant.
Using the Ksp values given in the problem, we have:
Ksp for hydroxyapatite = 6.8 x 10^(-2)
Ksp for fluoroapatite = 1.0 x 10^(-60)
Since the Ksp for fluoroapatite is much smaller than that of hydroxyapatite, fluoroapatite is much less soluble and more stable than hydroxyapatite.
To determine the concentration of fluoride ions required to precipitate hydroxyapatite, we can set the Ksp of hydroxyapatite equal to the equilibrium constant (K) for the reaction between hydroxyapatite and fluoride ions, and solve for the concentration of fluoride ions:
Ksp for hydroxyapatite = K
6.8 x 10^(-2) = ([Cas(PO4)3F][OH-]^3)/([Cas(PO4)3OH][F-]^3)
[F-]^3 = ([Cas(PO4)3F]/[Cas(PO4)3OH]) x ([OH-]/Ksp for hydroxyapatite)
[F-]^3 = (1.0 x 10^(-60))/(6.8 x 10^(-2)) x (1/[OH-]^3)
[F-]^3 = 1.47 x 10^(-59)/[OH-]^3
Taking the cube root of both sides, we get:
[F-] = (1.47 x 10^(-59)/[OH-]^3)^(1/3)
Substituting the value of Ksp for hydroxyapatite, we get:
[F-] = (1.47 x 10^(-59)/(1 x 10^(-24))^3)^(1/3) = 2.8 x 10^(-4) M
Therefore, a fluoride ion concentration of at least 2.8 x 10^(-4) M is required to precipitate hydroxyapatite and form fluoroapatite.
This explains how fluoride in fluorinated water or in toothpaste can help prevent tooth decay by strengthening tooth enamel through the formation of fluoroapatite.
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According to the data, the temperature of the
substance is 28°C. If we know that 0°C = 273 K,
what is the temperature of the substance in
Kelvin?
Answers
Answer: 351
Explanation: From °C to kelvin we do
K=273+°C
From Kelvin to °C we do
°C=K-273 or -273+ K
my song, you hate me
yeah, lately i was feeling that you hate me its ok though cause i know
yeah, am i in a dream am i awake i cant tell because i feel im about to break
i know im a mistake all i ever ask for is for gods sake i dont apologize because what difference what it make i had all those chances that i did not take
its all my fault i got to behave im trapped in a cage i got to lose all the bad stuff and get in shape all i have to do now is give and take all those things that i said about drowning
in a lake its just hard to replace when you have so much to say to her face i still remember that when she taught me how to tie my shoe lace
yeah, i just want to be the better person the better version im not even learning and that is for certain im in flames im burning and inside im hurting but now i hope i will learn my lesson
Answers
Answer:
cool
Explanation:
Answer: I'm sensing depressed vibes... you okay?
Explanation: Your song's nice tho c:
Only the largest stars more than 10 times the size of the Sun will go
supernova and possibly become black holes.
O True
O Flase
Answers
Ni(OH)3 +
Pb(SO4)2 →__Pb(OH)4 +
Ni2(SO4)3
what is the balance
Answers
Answer:
4+3=3+3+2
Explanation:
4Ni(oh)3+3pb(so4)2=3pb(oh)4+2Ni2(so4)3
d.v. hoyt, "an empirical determination of the heating of the earth by the carbon dioxide greenhouse effect", nature 282 (22 november 1979), 388 - 390.
Answers
The impact of a higher atmospheric carbon dioxide concentration on Earth's surface temperature has been the subject of numerous theoretical calculations1,2.
Estimates of the rise in Earth's surface temperature brought on by doubling the amount of carbon dioxide in the atmosphere typically fall between 0.7 and 2.9 °C. The temperature rises range from 0.096 to 0.40 °C for a 10% increase in carbon dioxide.All of these conclusions were reached through the use of theoretical models, ranging in complexity from one-dimensional investigations of the planetary radiation budget to three-dimensional general circulation models. Here, a novel solution to this issue is discussed, enabling the calculation of an empirical estimate of the heating of the Earth's surface caused by the greenhouse effect of carbon dioxide.This method suggests that the Earth only warmed by 0.40 °C or less between 1880 and 1970.
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Calculate the ratio of the rate of effusion of CO2 to He. A) 3.3/1
B) 11/1
C) 12/1
D) 0.090/1 E) 0.30/1
Answers
The ratio of the rate of effusion of CO² to He: 0.30/1. Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. The correct option is E.
To calculate the ratio of the rate of effusion of CO² to He, we will use Graham's law of effusion.
The formula for Graham's law is: Rate₁/Rate₂ = √(M₂/M₁)
In this case, Rate₁ is the rate of effusion of CO2 and Rate₂ is the rate of effusion of He. The molar masses of CO2 and He are 44 g/mol and 4 g/mol, respectively. Plugging these values into the formula, we get:
Rate₁/Rate₂ = √(4/44) ≈ √(1/11)
This simplifies to approximately 0.30/1, which corresponds to option E in your list of choices. Therefore, the ratio of the rate of effusion of CO² to He is approximately 0.30/1.
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suppose mol of electrons must be transported from one side of an electrochemical cell to another in minutes. calculate the size of electric current that must flow.
Answers
suppose mol of electrons must be transported from one side of an electrochemical cell to another in minutes. the size of electric current that must flow is 104.54 A.
Suppose 650 mmol of electrons must be transported from one side of an electro chemical cell to another in 10.0 minutes Then, we have to calculate the size of electric current that must flow. Then we know that Current I = Charge(q) / time(t), Charge = mols of e-x charge of electron = (0.650 mol of e-) x (96500 C/mol of e-) = 62725 C. now, time in seconds t = 10 min = 10 min x 60 s/ min = 600 s therefore, I = C/t = (62725)/600
| = 104.54 C/s, Also, 1 C/s = 1 Amp. Hence, I = 104.54 A. A torrent of particles, such as ions or electrons travelling through an electrically conducting or a vacuum is called as an electric current. The net rate of electric charge passing throughout a surface or through a control volume is how it is determined. Electric current is a term that refers to how so much electricity to flow across a circuit and how it flows in an electronic circuit. Amperes are employed to measure it (A). More and more electricity going through the circuit, the greater the ampere value.
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determine the volume of o2 (at stp) formed when 50.0 g of kclo3 decomposes according to the following reaction. the molar mass for kclo3 is 122.55 g/mol.
Answers
The volume of O₂ (at STP) formed when 50.0 g of KClO₃ decomposes according to the given reaction is 22.4 L.
To calculate the volume of O₂ formed at STP when 50.0 g of KClO₃ decomposes, we need to first write the balanced chemical equation:
2 KClO₃ → 2 KCl + 3 O₂
From the balanced equation, we can see that 2 moles of KClO₃ produce 3 moles of O₂. Therefore, we need to first calculate the number of moles of KClO₃ in 50.0 g of the compound:
Number of moles of KClO₃ = Mass ÷ Molar mass
= 50.0 g ÷ 122.55 g/mol
= 0.408 moles
Now we can use the mole ratio from the balanced equation to find the number of moles of O₂ produced:
Number of moles of O₂ = Number of moles of KClO₃ × (3 moles of O₂ ÷ 2 moles of KClO₃)
= 0.408 moles × (3 ÷ 2)
= 0.612 moles
Finally, we can use the ideal gas law to find the volume of O₂ at STP:
PV = nRT
where P = 1 atm, V = volume of gas, n = number of moles, R = 0.0821 L·atm/mol·K (gas constant), and T = 273 K.
Rearranging the equation to solve for V, we get:
V = nRT ÷ P
= (0.612 mol)(0.0821 L·atm/mol·K)(273 K) ÷ (1 atm)
= 16.2 L
However, this is the volume of O₂ at standard temperature and pressure (STP) for 0°C and 1 atm, while the given temperature is 273 K. Therefore, we need to convert the volume at STP to the volume at the given temperature using the following equation:
V₂ = V₁ × (T₂ ÷ T₁)
where V₁ is the volume at STP (22.4 L), T₁ is the temperature at STP (273 K), V₂ is the volume at the given temperature, and T₂ is the given temperature (273 K).
Substituting the values, we get:
V₂ = 22.4 L × (273 K ÷ 273 K) = 22.4 L
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Does boron have 2 valence electrons.
Answers
Two students were discussing the Mono Lake ecosystem. The first student said, "For a 20-kilogram (kg) coyote to survive, it takes around 200 kg of Wilson's phalaropes, 400 kg of brine shrimp, and 800 kg of algae!" The second student said, "No, I think it takes even more than that." 1. Which student is correct? What is your reasoning?
Answers
Answer:
The second student is right.
Explanation:
The coyote feed on not only phalaropes but many other organisms present in the environment for its survival. There are many other organisms present in the ecosystem such as mice, squirrel, cactus fruit etc. The coyote feeds on phalaropes, the phalaropes feeds on brine shrimp and the brine shrimp feeds on algae for its survival so in this way the ecosystem moves in the forward direction. The coyote feeds on phalaropes so the energy that is present in phalaropes transferred into coyote which only 10 % while the remaining is released in the atmosphere in the form of heat energy.
4. (a) Draw resonating structure of Phenol. 5. What happens when (write the reactions involved) (a) Cyclohexanol reacts with concentrated sulfuric acid and resulting product is ozonolyzed (b) Phenol is heated with CH3COCl (c) Propyne reacts with hydrogeniodide in presence of benzene peroxide (d) Propoxypropane is reacted with access of NH3
Answers
(a) Draw resonating structure of PhenolPhenol is a common organic molecule. It consists of a phenyl group (C6H5) attached to a hydroxyl group (OH). The hydroxyl group is connected to the benzene ring at the para position, denoted as p-phenol.
The two main resonating structures of Phenol are shown in the figure below: This reaction takes place by cleaving the double bond of Cyclohexene using ozone, followed by a reductive workup step.
(b) Phenol is heated with CH3COCl:When Phenol is heated with Acetyl Chloride, it forms Acetophenone. The reaction is as follows:Phenol reacts with Acetyl Chloride to form Acetophenone, with the elimination of HCl as a by-product.(c) Propyne reacts with hydrogeniodide in the presence of benzene peroxide:Propyne reacts with hydrogen iodide in the presence of benzene peroxide to form 2-Iodopropane.
The reaction proceeds via a radical mechanism, as shown below:The chain initiation step:This step involves the homolytic cleavage of the benzene peroxide bond to generate benzene and two free radicals. These free radicals then interact with hydrogen iodide to form iodine radicals.The chain propagation step:The chain propagation steps involve the following sequence of reactions:The chain termination step:
This reaction involves the formation of 2-Iodopropane.(d) Propoxypropane is reacted with access of NH3:Propoxypropane is reacted with excess of NH3 to form Propylamine. The reaction is as follows:Propoxypropane undergoes nucleophilic substitution with ammonia, followed by deprotonation, to form the corresponding amine. Excess ammonia is required to drive the reaction to completion.
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Phineas turned off the lights in his room to go to sleep. Which part of the eye picks up the shades of gray of his furniture that then helps him to maneuver through his room without lights? O cones O rods O cornea O iris
Answers
Answer:
Rods
Explanation:
Rods are photoreceptor cells in the eye that help us see in low light but play little to no role in color vision. Therefore, they would help Phineas to see shades of grey and large shapes in the dark,
Answer:
rods
Explanation:
How many layers of paint are there on the typical manufactured vehicle?
Answers
Answer:
3 sometimes 4
Explanation: there are usualy
3 layers of paint but sometime manufacterers add paint protection film to bring the total up to 4
Please help me with number 12
Answers
Answer:
organisms in rain water and the number of organisms in pond water because the dependant variable never changes
Explanation:
because the dependant variable never changes
giải gấp giúp em câu này với ạ:
a) Hoàn thành các phan ứng sau dưới dạng phương trình phân tử và phương trình ion thu gọn:
- CaCO3 + HCl =>
- Fe(SO4)3 + NaOH =>
- KCl + ? => KNO3 + ?
- Na2S + H2SO4 =>
b) Viết PTPU của các phương trình ion thu gọn sau, xác định chất nào là acid, chất nào là bazo:
- H(+) + OH(-) => H2O
- OH(-) + HCO3(-) => CO3(2-) + H20
Answers
Explanation:
what do you have written I can't understand one word right a properly
you forecast that a stock x will offer a rate of return of 12%. the risk-free rate is 4%. the market risk premium is 7%. if the beta of stock is 1.8, then stock x is you forecast that a stock x will offer a rate of return of 12%. the risk-free rate is 4%. the market risk premium is 7%. if the beta of stock is 1.8, then stock x is cannot be determined fairly priced overpriced underpriced
Answers
Ex < Ke, stock is overpriced and one should not invest in stock x.
What do you know about stock market ?
The stock market refers to public markets that exist for issuing, buying, and selling stocks that trade on a stock exchange or over-the-counter. Stocks, also known as equities, represent fractional ownership in a company, and the stock market is a place where investors can buy and sell ownership of such investible assets. An efficiently functioning stock market is considered critical to economic development, as it gives companies the ability to quickly access capital from the public.
Return on stock x (Ex) 12%
Cost of equity as per CAPM
Ke=Rf+MRP*beta i.e. 16.6%
Since ,Ex < Ke, stock is overpriced and one should not invest in stock x.
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certain meteorites have been examined and found to carry samples of which molecules? select all that apply.
Answers
Some examined meteorites contain would be lipids, nucleotides, amino acids, and monosaccharides.
What are meteorites?Meteorites are considered to be the pieces of rocks or metals that fall into the earth from outer space. These rocks/metals have been extensively studied/analyzed by some researchers, especially those seeking to prove/disprove Panspermia theory that life originates from other planets.
Several studies conducted found the compounds such as lipids, DNA, RNA, and amino acids.
There has been no evidence for the monosaccharides for a long time until 2019 when an international team discovered sugars such as xylose and arabinose in certain meteorites.
No polypeptide has been discovered in the meteorites, but its precursor, amino acids, have been discovered.
Therefore, the correct answer to the molecules that have been found in the some meteorites would be lipids, nucleotides, amino acids, and monosaccharides.
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