I need answer key to edmentum guided notes for Chemistry

\(K_{sp}\) of the compound is found to be  5.04 ×\(10^{-10}\).

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = \([A^{+} ]^{a}\) \([B^{-} ]^{b}\)

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × \(10^{-2}\) g/L

molar mass = 288 g/ mol

∴ s= 3.60 × \(10^{-2}\) g/L ÷ 288 g/ mol = 1.25 ×\(10^{-4}\) mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

\(K_{sp}\) =[ \(M^{+3}\)] [ \(X^{-1}\)\(]^{3}\) = solubility product

∴ \(K_{sp}\) =\([s]^{} [3s]^{3}\)

∴ \(K_{sp}\) = 3 \(s^{4}\)

∴ \(K_{sp}\) = 3 × (3.60 × \(10^{-2}\) \()^{4}\)

∴ \(K_{sp}\) = 503.8848 ×\(10^{-8}\)  = 5.04 ×\(10^{-10}\)

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Answer:

C) Children grow taller when they use the energy from the food molecule, but all of the molecules leave the body as waste.

hope it helps.

Answer:

C - Children grow taller when they use the energy from the food molecules, but all of the molecules leave the body as waste.

hope it is helpful to you ☺️☺️☺️☺️

Iron (II) tetraoxosulphate (VI) is always prepared freshly to be used for analysis as iron undergoes  chemical change of oxidation from+2 to +3 oxidation state.

Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.

There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical changes:

1) inorganic changes

2)organic changes

3) biochemical changes

During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.

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To identify the limiting reactant, excess reactant, and theoretical yield, we first need to determine the amount of each reactant in moles.

Using the molar masses of Ca and P:

Number of moles of Ca = 17.0 g / 40.08 g/mol = 0.424 mol

Number of moles of P = 18.0 g / 30.97 g/mol = 0.581 mol

Next, we need to determine the stoichiometric ratio of the reactants. From the balanced chemical equation, we see that the ratio of Ca to P is 3:2.

3 Ca + 2 P → Ca3P2

To use the stoichiometric ratio to determine the limiting reactant, we need to compare the actual ratio of the reactants to the stoichiometric ratio.

Actual ratio of Ca to P = (0.424 mol Ca) / (0.581 mol P) ≈ 0.73

Stoichiometric ratio of Ca to P = 3/2 = 1.5

Since the actual ratio is greater than the stoichiometric ratio, Ca is the excess reactant and P is the limiting reactant.

To find the theoretical yield of Ca3P2, we need to use the stoichiometric ratio to determine how many moles of Ca3P2 can be produced from the limiting reactant (P).

From the balanced chemical equation, we see that 2 moles of P react with 3 moles of Ca to produce 1 mole of Ca3P2.

So, the number of moles of Ca3P2 that can be produced from 0.581 mol of P is:

(0.581 mol P) × (1 mol Ca3P2 / 2 mol P) = 0.2905 mol Ca3P2

Therefore, the theoretical yield of Ca3P2 is 0.2905 mol.

Statement C is not true. A combination reaction is not called retrosynthesis.

Retrosynthesis is a term used in organic chemistry to describe the process of planning the synthesis of a complex molecule by breaking it down into simpler precursor compounds. On the other hand, a combination reaction refers to a chemical reaction where two or more substances combine to form a single compound.

Examples of combination reactions include the reactions mentioned in statements A and D, where magnesium reacts with oxygen to form magnesium oxide and sodium reacts with chlorine to form sodium chloride, respectively.

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The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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HTML5 has included particular components to structure websites. If you want to incorporate content that is directly connected to the topic of the document, use the <nav> structure element.

In chemistry, an element is a pure substance made up of atoms that have the same number of protons in their nuclei. Each element is identified by its atomic number, which represents the number of protons in the nucleus. Elements are the building blocks of matter, and they cannot be broken down into simpler substances by ordinary chemical reactions. The periodic table of elements organizes all known elements based on their properties and atomic structure. There are currently 118 known elements, each with its own unique properties and uses. Understanding the properties and behavior of elements is essential to understanding the behavior of matter and the chemical reactions that occur in the natural world and in industry.

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Answer:

Tetrahedral shape

Explanation:

The compound SiCl₄ has a molecular geometry of a tetrahedral shape. The shape of compound can be predicted using the valence shell electron pair repulsion theory model.

Answer:

255.732 g/mol

Explanation:

Molar mass of Ga(NO3)3 = 255.7322 g/mol. This compound is also known as Gallium(III) Nitrate.

In the given reaction, the limiting reactant is C₆H₆ (benzene).

To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.

The number of moles for each reactant:

Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol

Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂

                     = 45 g / 71 g/mol

                     = 0.634 moles of Cl₂

Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol

Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆

                        = 45 g / 78 g/mol = 0.577 moles of C₆H₆

Determine the stoichiometry between Cl₂ and HCl:

Cl₂ + C₆H₆ → C₆H₅Cl + HCl

Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.

Thus, the limiting reactant is C₆H₆ (benzene).

Calculate the mass of HCl produced:

Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol

Moles of HCl produced = moles of C₆H₆ = 0.577 moles

Mass of HCl produced = moles of HCl produced × molar mass of HCl

Mass of HCl produced = 0.577 moles × 36.5 g/mol

                                     ≈ 21.04 g

Therefore, approximately 21.04 grams of HCl will be produced.

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Answer:

When acetylene reacts with silver nitrate, its acidic hydrogen reacts with silver nitrate to form a white precipitate. So here acetylene shows its acidic nature.

Explanation:

this is what i found

Answer:

Primary alcohols can be oxidized to form aldehydes and carboxylic acids; secondary alcohols can be oxidized to give ketones. Tertiary alcohols, in contrast, cannot be oxidized without breaking the molecule's C–C bonds.

A scientist goes to lab to synthesize Na₃AlF₆ via the balanced chemical reaction. If they need 780. grams of Na₃AlF₆, and the overall percent yield is 45.4 %,311.79 g of Al₂O₃ is required to form 780 grams of Na₃AlF₆.

The balanced chemical reaction is defined as the mass of total number of product is exactly equal to the total number of mass of reactant.

Given:

45.4% yield = 780 g

Then 100% yield would be =780 × (100/45.4)

= 1718 g

Molar mass of Na₃AlF₆ = 209.94 g/mol

Molar mass of Al₂O₃ = 101.96 g/mol

1mole of Al₂O₃ gives 2 moles of Na₃AlF₆ .

⇾ 101.96 g of Al2O3 gives 2 × 209.94 g of Na3AlF6

Therefore, x g of Al2O3 gives 1284 g of Na3AlF6

x = (1718 × 101.96)/ 2 × 209.94

= 311.79 g

Thus, 311.79 g of Al₂O₃ is required to form 780 grams of Na₃AlF₆.

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Answer:

\(\boxed {\boxed {\sf 77.35 \ K}}\)

Explanation:

The Celsius and Kelvin scales are used to measure the temperature of matter.  Their scales and unit differences are the same (1 K increase = 1 °C increase), but they have different starting points.

So, the conversion is quite simple and only requires addition because of the different starting points. The formula is:

\(T_K = T_C+ 273.15\)

The boiling point of liquid nitrogen is -195.8 °C. We can substitute this value into the formula.

\(T_K= -195.8 + 273.15\)

\(T_K= 77.35 K\)

The boiling point of liquid nitrogen is 77.35 Kelvin.

The amount of carbon dioxide in the air is increasing in a large city due to the growing number of vehicles. The mayor wants to plant more trees.  I totally agree with the mayor's suggestions.

Growing number of vehicles contributes towards carbon emissions into the atmosphere. Driving a car with gasoline as its fuel produces three carbon emissions. All of the emissions that take place across a company's value chain and are not covered by scope 2.

These emissions aren't caused by the business or the things it makes. Carbon emissions from operating a gasoline-powered vehicle are significant. Scope 3 applies since the product, not the company's machines, is what causes the emissions. There are three types of carbon emissions: 'Scope 1' or 'Direct Emissions' Direct GHG is produced at sources where the fuel is burned there and then. Examples of scope 1 emissions are personal automobiles and gas stoves. Planting more trees will result in minimizing the harmful effect of these gases upon the environment.

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If 60 grams of the substance are added to 100 g of water, the solution can be categorized as supersaturated.

The graph shows the number of grams that can be dissolved in 100 grams of water at different temperatures. In general, solubility increases with temperature.

According to the graph, at a temperature of 30°C, it is possible to dissolve a total of 48 to 49 grams of \(KNO_{3}\). This information implies that if we add 60 grams at this temperature not all the substance would be dissolved, and therefore the solution would be supersaturated.

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The (15-35-15) number on a bag of fertilizer is calculated by an outdated method.  Using the knowledge of the old methods, the number of moles of phosphorus found in 10.0 grams of phosphorus is 0.05 mole.

The (15-35-15) number on the bag of fertilizer is used for:

Thus, in a 100-gram bag of fertilizer, there are 35 grams of phosphorus pentoxide P₂O₅.

∴

To determine the number of moles of 10 grams of phosphorus pentoxide in (15-35-15) bag of fertilizer, we have:

\(\mathbf{=10 \times \dfrac{35}{100} \ grams \ of \ P_2O_5}\)

= 3.5 grams of P₂O₅

Recall that:

\(\mathbf{Number of moles = \dfrac{mass}{molar \ mass}}\)

∴

\(\mathbf{Number of moles = \dfrac{3.5\ g}{ 142 \ g/mol}}\)

\(\mathbf{Number of moles = 0.0246 \ mol}\)

Provided that 1 mole of P₂O₅ harbors 2 moles of phosphorus;

Then;

The number of phosphorus present in 10.0 grams of (15-35-15) fertilizer is:

= 0.0246 moles × 2

= 0.0492 moles

≅ 0.05 moles

Therefore, we can conclude that the number of moles of phosphorus found in 10.0 grams of  (15-35-15) bag of fertilizer is 0.05 moles.

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Answer:

To resolve this, we need to place the coefficient “2” in front of the sodium in the reactant, to give the equation shown below. 2 Na (s) + Cl 2 (g) → 2 NaCl (s) In this equation, there are two sodiums in the reactants, two sodiums in the products, two chlorines in the reactants and two chlorines in the products; the equation is now balanced.

Explanation:

Answer:

Li + HCl = LiCl + H2 - Chemical Equation Balancer.

Explanation:

Answer:

Calcium Oxide is a drying agent, hence it dehydrates the reaction to give pure solid Iron ( III ) chloride, which cannot be done by calcium chloride.

It preferred to use calcium oxide rather than calcium chloride in preparation of iron (III) chloride because Calcium Oxide is a drying agent, hence it dehydrates the reaction to give pure solid Iron ( III ) chloride, which cannot be done by calcium chloride.

A process such as a chemical reaction that removes water.The atoms which constitute the molecule of water that is removed.

Hence,It preferred to use calcium oxide rather than calcium chloride in preparation of iron (III) chloride because Calcium Oxide is a drying agent,

Thus, it dehydrates the reaction to give pure solid Iron ( III ) chloride, which cannot be done by calcium chloride.

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Answer:

B

Explanation:

Generally, soil changes easier temperature than water. And it's warmer already, based on the picture.

At constant pressure and temperature, 3.0 L of nitrogen trichloride decomposes to produce 4.0 L of gases; option A.

The mole ratio of the reaction is detained from the equation of the reaction.

The equation of the reaction is given below as follows:

2 moles of nitrogen trichloride decomposes to produce 4 moles of gases.

The mole ratio of a gas is equivalent to the volume ratio of the gas.

Therefore, 3.0 L of nitrogen trichloride decomposes to produce 4.0 L of gases.

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Answer:

good question

Explanation:

probably because people like to say they know things and help people with "there stress" and think that there helping them but in reality there making it where they have more :)

Answer:

Answer:

Number of Significant Figures: 5

The Significant Figures are 3 0 6 7 0

Explanation:

hope this helps

The energy in joules of one mole of photons of visible light having a wavelength of 4.11×10^2 nm? can be expressed as 2.9*10^5 J

From the question we were told to find the energy and the parameters that is needed to calculate these are;

c=3*10^8

h= 6.626 * 10^-34 J.s

1 mol photons = 6.023x10^23 photon

λ = 4.11×10^2 nm  = 4.11 × 10-7 meters

The parameters can be input  as Energy of one mole photon (E) = ( 6.023x10^23 * 6.626 * 10^-34 * 3*10^8)/ (4.11 × 10^-7)

=291302

=2.9*10^5 J

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Este problema indica el volumen deseado de una solución (250 cm³) cuya concentration es de 5 g/L y pregunta la cantidad de sal que se debe disolver.

De este modo, dado que el volumen y la concentración están en distintas unidades, debemos convertir una de ellas a la de la otra, en este caso los cm³ a L como se muestra a continuación:

\(250cm^3*\frac{1L}{1000cm^3}= 0.250L\)

Seguidamente, multiplicamos el volumen previamente obtenido por la concentración con el fin the encontrar los gramos de sal:

\(0.250L*5\frac{g}{L} \\\\=1.25 g\)

Así, esto indica que se deben disolver 1.25 gramos de sal para este requerimiento.

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Answer:

A or 3 would be the right answer

A rainbow is produced through a proces that includes refraction, reflection, and dispersion of  sunlight.

A rainbow is formed when sulinght is refracted and reflected by rain drops in the atmospher.

The sunlight is split into its component colors, which is why rainbows appear as having an array of colors. This is due to each color being bent by a different amount during refraction.

The colors of a rainbow are always in the same order, with red on the outside and violet on the inside.

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