How do you write 140% as a fraction, mixed number, or whole number?

Therefore, the standard deviation for the number of people with the genetic mutation in groups of 500 is approximately 6.726.

To find the standard deviation for the number of people with the genetic mutation in groups of 500, we can use the binomial distribution formula.

Given:

Probability of having the genetic mutation (p) = 0.09

Sample size (n) = 500

The standard deviation (σ) of a binomial distribution is calculated using the formula:

σ = √(n * p * (1 - p))

Substituting the given values:

σ = √(500 * 0.09 * (1 - 0.09))

Calculating the standard deviation:

σ ≈ 6.726 (rounded to three decimal places)

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As a result, for the same data set, a 99% confidence interval would have a greater margin of error than a 90% confidence interval.

Answer: If a 90% confidence interval is constructed based on a sample of data, and it is 74% + 3%, a 99% confidence interval based on this same sample of data would have a larger margin of error and probably a different center.

What is a confidence interval? A confidence interval is a statistical technique used to establish the range within which an unknown parameter, such as a population mean or proportion, is likely to be located. The interval between the upper and lower limits is called the confidence interval. It is referred to as a confidence level or a margin of error.

The confidence level is used to describe the likelihood or probability that the true value of the population parameter falls within the given interval. The interval's width is determined by the level of confidence chosen and the sample size's variability. The confidence interval can be calculated using the standard error of the mean (SEM) formula

.A 90% confidence interval indicates that there is a 90% chance that the interval includes the population parameter, while a 99% confidence interval indicates that there is a 99% chance that the interval includes the population parameter.

When the level of confidence rises, the margin of error widens. The center, which is the sample mean or proportion, will remain constant unless there is a change in the data set. Therefore, alternative A is the correct answer.

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Step-by-step explanation:

Hello!
I'd love to help you learn.
I see the formula attached is \(4*(\frac{1}{2})^{x} =-2^{x}-1\\\)

This problem is explaining you to graph, since algebraically it's a little more harder to try and find the solution.

Since they're both equal to each other, we can assign a variable like y, so we can make them into two individual lines.

You can use your scientific calculator to graph lines like this, or otherwise there are online sources (Desmos helps alot!) which can graph two equations as so.

Now that we have the corresponding system of equations, we can graph both.

\(y=4*(\frac{1}{2})^x\\ y=-2^x-1\)
Let's graph them on Desmos on the same plane. The answers are attached. Red is the first equation, blue is the second.

What determines the solutions of a system of equations?

-No solution: the two lines will never intersect/does not intersect ever, which means that there are no set point where it satisfies both equations.

-One solution: the two lines intersect once and only once, meaning that there is that one set point where the x and y values both satisfy both equations.

-Multiple solutions: the two lines will intersect each other multiple times, meaning there are multiple set points where the x and y values satisfy both equations. You usually will not have to worry about these problem sets.

-Infinite solutions: the two lines are both the same line, which means every x and y value will satisfy both equations.

Looking at the solution attached, we can see that there are no places where a system of equations intersect, therefore ruling it that they have no solution.

And to answer your last question, an asymptote is a imaginary line in which a equation can approach closely and closely, but will never touch that imaginary line. Think of a line at y=\(\frac{1}{x}\). When you graph it, you can see that the two lines never ever EVER intersect the y-axis, or x=0; giving that x=0 as a vertical asymptote.

Answer:

Amount

Rs 6345.30

Compound interest

Rs 1,345.30

Step-by-step explanation:

Here in this question, we are interested in calculating the amount and the compound interest on the value given.

To calculate the amount, we use the formula below;

A = P(1 + r/n)^nt

Where; A is the amount which we want to calculate

P is the principal which is Rs 5,000

r is the interest rate per annum = 10% = 10/100 = 0.1

n is the number of times per year in which it is compounded ( since it is annually, then it is 1)

t is the number of years which is 2.5 years( kindly know that 6 months is same 1/2 year , so 6 months is same as 0.5, and thus 2 years 6 months becomes 2.5 years)

now let’s substitute all these values;

A = 5000(1 + 0.1/1)^(1*2.5)

A = 5000(1 + 0.1)^2.5

A = 5000(1.1)^2.5

A = 6,345.2935314294

This is approximately Rs 6,345.30

The second part of the question asks to calculate compound interest

Mathematically ;compound interest = Amount - principal

= 6345.3 - 5000 = Rs 1,345.30

Sipho made two misconceptions in his calculation. Firstly, he incorrectly calculated 35 ÷ 14 as 5/2 instead of 2.5. Secondly, he subtracted a fraction from a whole number instead of converting the fraction to a decimal first.

Sipho was given the sum 4310− 35÷14 to calculate. Let's analyze each step that Sipho did and identify any misconceptions:

Step 1: 35 ÷ 14 = 5/2

Misconception: Sipho seems to have divided 35 by 14 and obtained the result as a fraction of 5/2. However, this is incorrect. The correct result is 2.5. It appears that Sipho made a mistake while dividing 35 by 14.

Step 2: 4310 - 5/2

Misconception: Sipho subtracted the result of 35 ÷ 14 from 4310. However, since he obtained the result as a fraction, he should have converted it to a decimal first before subtracting. The correct calculation would have been 4310 - 2.5 = 4307.5.

Therefore, Sipho made two misconceptions in his calculation. Firstly, he incorrectly calculated 35 ÷ 14 as 5/2 instead of 2.5. Secondly, he subtracted a fraction from a whole number instead of converting the fraction to a decimal first.

It is essential to understand the basic principles and operations of Mathematics to avoid such errors. Careful attention to detail, practice, and clarification of doubts can help in avoiding such misconceptions.

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The equation

Is in point intercept form

The general equation of point intercept form is given as

Comparing the two equations

This implies

Hence, the slope in the equation is -2

Also, by comparing the equations

Thus the point in the equation is (2, 1)

Answer:

Step-by-step explanation:

You take the 15 he had and subtract 9.52 from that which would look like this

15 - 9.52 = 5.48

Now with our new value 5.48 we divide it by two.

5.48 / 2 = 2.74

So he saved $2.74

Answer:

45.00%

Step-by-step explanation:

The total answers count 40 - it's 100%, so we to get a 1% value, divide 40 by 100 to get 0.40. Next, calculate the percentage of 18: divide 18 by 1% value (0.40), and you get 45.00% - it's your percentage grade.

Please rate me brainliest

i hope this helps

..........

Answer:

only the mean; 4. the mean is 4 but the median is 5 so it can only be the mean unless i am an idiot lol

Step-by-step explanation:

- Zombie

The tangent vector to the curve at t = n is given by the derivative of the parametric equations: \(\frac{dx}{dt} = nt \ and\ \frac{dy}{dt} = n't^2\)

To find the principal unit normal vector to a curve at a specified value of the parameter, you will need to do the following:

Here is an example to illustrate this process:

Suppose we have a curve given by the parametric equations \(x = t^2\) and y = t^3. The tangent vector to the curve at t = 2 is given by the derivative of the parametric equations:

\(\frac{dx}{dt} = 2t \ and\ \frac{dy}{dt} = 3t^2\)

Evaluating these at t = 2, we find that the tangent vector is (4,12).

The normal vector to the curve at t = 2 is perpendicular to the tangent vector, so we can find it by rotating the tangent vector 90 degrees counterclockwise. This can be done by taking the negative of the second component and swapping the components: (-12,4).

To normalize the normal vector, we divide it by its magnitude:

\((-12,4)\sqrt((-12)^2 + 4^2) = (-12\sqrt164,4\sqrt164) = (-0.73,0.24)\)

This is the principal unit normal vector to the curve at t = 2.

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To solve the given initial-value problem using Laplace transform, we will first take the Laplace transform of the differential equation.

The Laplace transform of the second derivative of y with respect to t, denoted as Y'', can be found using the following property:    

L{y''(t)} = s² * Y(s) - s * y(0) - y'(0)  

Using this property, we can find the Laplace transform of the given differential equation:

s² * Y(s) - s * y(0) - y'(0) + 25 * Y(s) = L{cos(5t)}

Substituting the initial conditions y(0) = 2 and y'(0) = 3, and using the Laplace transform of cos(5t) from the table, we have:  

s² * Y(s) - s * 2 - 3 + 25 * Y(s) = s / (s² + 25)  

Simplifying this equation, we get:

(s² + 25) * Y(s) = s³ - 3s + 2s + 25

(s² + 25) * Y(s) = s³ - s + 25

Now, solving for Y(s), we have:

Y(s) = (s³ - s + 25) / (s² + 25)

To solve the given initial-value problem, we used the Laplace transform of the differential equation. Taking the Laplace transform of the equation involves applying the Laplace transform to each term in the equation and using the properties of the Laplace transform.
In this case, we applied the Laplace transform to the second derivative of y, denoted as Y''(s), using the property

L{y''(t)} = s² * Y(s) - s * y(0) - y'(0),

where Y(s) represents the Laplace transform of y(t).

After substituting the initial conditions y(0) = 2 and y'(0) = 3, and using the Laplace transform of cos(5t) from the table, we simplified the equation and solved for Y(s) as

(s³ - s + 25) / (s² + 25).

The Laplace transform of the given initial-value problem is

Y(s) = (s³ - s + 25) / (s² + 25).

This is the solution of the initial-value problem in terms of the Laplace transform variable s.

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The pH of the KOH solution made by mixing 0.251 g KOH with enough water to make 1.0 x 102 ml of solution is 12.65.

To determine the pH of a KOH solution made by mixing 0.251 g KOH with enough water to make 1.0 x 102 ml of solution, we need to first calculate the concentration of KOH in the solution.

The molar mass of KOH is 56.11 g/mol, so we can calculate the number of moles of KOH present in 0.251 g as follows:

0.251 g KOH / 56.11 g/mol = 0.00448 mol KOH

Next, we can calculate the concentration of KOH in the solution (in units of moles per liter, or M) as follows:

0.00448 mol KOH / 0.1 L = 0.0448 M KOH

Finally, we can use the fact that KOH is a strong base to calculate the pH of the solution. A strong base completely dissociates in water to form OH- ions, which can react with H+ ions to form water. Therefore, the pH of a solution of strong base can be calculated directly from the concentration of OH- ions present in the solution.

The concentration of OH- ions in the solution can be calculated from the concentration of KOH using the following balanced chemical equation:

KOH + H2O → K+ + OH- + H2O

For every mole of KOH that dissolves in water, one mole of OH- ions is produced. Therefore, the concentration of OH- ions in the solution is equal to the concentration of KOH.

pOH = -log [OH-] = -log (0.0448) = 1.35

pH = 14 - pOH = 14 - 1.35 = 12.65

Therefore, the pH of the KOH solution made by mixing 0.251 g KOH with enough water to make 1.0 x 102 ml of solution is 12.65.

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The answer is (a) $10,000.

The total cost of producing 200 units of output can be found by multiplying the output (200 units) by the average total cost (ATC) per unit, which is given as $50. Therefore, the total cost is:

Total Cost = Output x ATC

Total Cost = 200 x $50

Total Cost = $10,000

Therefore, the answer is (a) $10,000.

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Answer:

d = 1000 is the correct answer to that question

Answer:

d=4

Step-by-step explanation:

10^d=10000

Solve Exponent.

10d=10000

log(10d)=log(10000) (Take log of both sides)

d*(log(10))=log(10000)

d=

log(10000)

log(10)

d=4

Hope this helps :)

A. The raw score for a percentile rank of 80 is approximately 82.4.

B. The raw score that falls at the 93rd percentile is 114.324.
C. The score that falls at the 11th percentile is 30.93.

D. The raw score that would be equivalent to a percentile rank of 29 is 79.20.

E. The raw score that falls at the 95th percentile is 99.75.

F. The value of the equivalent raw score is 74.17.

A. To calculate the raw score for a percentile rank of 80 first convert percentile rank to a z-score using the standard normal distribution table or a calculator.

The z-score corresponding to a percentile rank of 80 is approximately 0.84.

Then use the z-score formula to find the corresponding raw score.

z = (x - μ) / σ where, x is the raw score, μ is the mean, and σ is the standard deviation.

Plugging in the given values, we get:

0.84 = (x - 75) / 10

Solving for x, we get:

x = (0.84)(10) + 75 = 82.4

Therefore, the raw score for a percentile rank of 80 is approximately 82.4.

B. We can calculate the z-score from the percentile rank:

PR = 93

=> area to the left of z-score is 0.93.

Using the standard normal distribution table, the corresponding z-score is 1.48.
z = (x - μ) / σ

=> 1.48 = (x - 105) / 6.30

=> x = 105 + 1.48 * 6.30 = 114.324.
Therefore, the raw score that falls at the 93rd percentile is 114.324.

C. Similar to part A, we can calculate the z-score from the percentile rank:

PR = 11

=> area to the left of z-score is 0.11.

Using the standard normal distribution table, the corresponding z-score is -1.23.

z = (x - μ) / σ

=> -1.23 = (x - 38.70) / 6.31

=> x = 38.70 - 1.23 * 6.31 = 30.93.
Therefore, the score that falls at the 11th percentile is 30.93.

D. We can calculate the z-score from the percentile rank:

PR = 29

=> area to the left of z-score is 0.29.

Using the standard normal distribution table, the corresponding z-score is -0.54.
z = (x - μ) / σ

=> -0.54 = (x - 90) / 20

=> x = 90 - 0.54 * 20 = 79.20.
Therefore, the raw score that would be equivalent to a percentile rank of 29 is 79.20.

E. Similar to part A and C, we can calculate the z-score from the percentile rank:

PR = 95

=> area to the left of z-score is 0.95.

Using the standard normal distribution table, the corresponding z-score is 1.65.

z = (x - μ) / σ

=> 1.65 = (x - 75) / 15

=> x = 75 + 1.65 * 15 = 99.75.

Therefore, the raw score that falls at the 95th percentile is 99.75.

F. T-score is calculated as:

T = 10z + 50, where z is the z-score corresponding to the raw score.

26 = 10z + 50 => z = (26 - 50) / 10 = -2.4.

z = (x - μ) / σ => -2.4 = (x - 110) / 14.93 => x = 110 - 2.4 * 14.93 = 74.17.

Therefore, the value of the equivalent raw score is 74.17.

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Answer:

28-4x

Step-by-step explanation:

Step 1: Open most inner bracket and simplify

=18-2(x+x-5)

=18-2(2x-5)

Step 2: Expand brackets by multiplying 2 in and simplify

=18-2(2x)-2(-5)

=18-4x+10

=28-4x

Therefore the answer is 28-4x

Answer:

GREATEST COMMON FACTOR IS 9XZ

Answer:

3xy^3z

Step-by-step explanation:

The complete statement is -

"Even though the triangles are all different sizes, the decimal values for each ratio are same."

A triangle is a two - dimensional figure with three sides and three angles.

The sum of the angles of the triangle is equal to 180 degrees.

∠A + ∠B + ∠C = 180°

Given is that -

"Even though the triangles are all different sizes, the decimal values for each ratio are ​_____."

We can write the complete statement as -

"Even though the triangles are all different sizes, the decimal values for each ratio are same."

Therefore, the complete statement is -

"Even though the triangles are all different sizes, the decimal values for each ratio are same."

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The value of b (real number) can be anything greater than zero so we cannot be determined with the given information so option (C) will be correct.

There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.

Given the absolute equation,

|x| = b for b >0

b is a set of all positive real numbers and we know that real number goes 0 to infinite means,

b could be 1,2,3... anything.

It means the corresponding solution will also be 1,2,3... anything.

Therefore we cannot determine the solution.

Hence "We cannot predict the number of solutions of the given mode function  |x| = b, such that b>0 without more information".

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The true proportion of the side lengths of the quadrilaterals is A'B'/AB

From the question, we have the following parameters that can be used in our computation:

Quadrilaterals ABCD and A'B'C'D

These quadrilaterals are similar

So, it means that the corresponding side lengths are proportional

So. we have

Side length = AB

Corresponding side length = A'B'

The true proportion is then represented as

k = Corresponding side length/Side length

Substitute the known values in the above equation, so, we have the following representation

k = A'B'/AB

Hence, the proportion is A'B'/AB

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Step-by-step explanation:

may be it is answer.......

Answer:

=

Step-by-step explanation:

The two fractions are equal because if you simplify the first (-38/40), dividing the numerator and denominator by 2, it will become -19/20

Answer:

7/8 if you divide you will get your answer

The value of x , y and z in the parallel line is 50 degrees.

When parallel lines are crossed by a transversal line, angle relationships are formed such as vertically opposite angles, alternate interior angles, alternate exterior angles, adjacent angles, corresponding angles etc.

Therefore, let's use the angle relationships to find the angle, x, y and z as follows:

Therefore,

x = 360 - 310(sum of angles in a point)

x = 50 degrees

Therefore,

x = y(alternate interior angles)

Alternate interior angles are congruent.

Hence,

y = 50 degrees

Therefore,

x = z(alternate interior angles)

z = 50 degrees.

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Answer:

Midpoint = (-1, 5)

Step-by-step explanation:

                     x₁  +  x₂         y₁   +   y₂

Midpoint = (--------------- , -----------------)

                          2                   2

                     -4  +  2         5  +   5

Midpoint = (--------------- , -----------------)

                          2                   2

                         -2                  10

Midpoint = (--------------- , -----------------)

                          2                   2

Midpoint = (-1, 5)

I hope this helps!

The point (9, -7) is the only solution to the system of linear inequalities given.

To determine which point would be a solution to the system of linear inequalities, let's substitute the given points into the inequalities and see which point satisfies both inequalities.

The system of linear inequalities is:

y > -4x + 6

y > (1/3)x - 7

Let's test each given point:

For the point (9, -7):

Substituting the values into the inequalities:

-7 > -4(9) + 6

-7 > -36 + 6

-7 > -30 (True)

-7 > (1/3)(9) - 7

-7 > 3 - 7

-7 > -4 (True)

Since both inequalities are true for the point (9, -7), it is a solution to the system of linear inequalities.

For the point (-12, -2):

Substituting the values into the inequalities:

-2 > -4(-12) + 6

-2 > 48 + 6

-2 > 54 (False)

-2 > (1/3)(-12) - 7

-2 > -4 - 7

-2 > -11 (False)

Since both inequalities are false for the point (-12, -2), it is not a solution to the system of linear inequalities.

For the point (12, 1):

Substituting the values into the inequalities:

1 > -4(12) + 6

1 > -48 + 6

1 > -42 (True)

1 > (1/3)(12) - 7

1 > 4 - 7

1 > -3 (True)

Since both inequalities are true for the point (12, 1), it is a solution to the system of linear inequalities.

For the point (-12, -7):

Substituting the values into the inequalities:

-7 > -4(-12) + 6

-7 > 48 + 6

-7 > 54 (False)

-7 > (1/3)(-12) - 7

-7 > -4 - 7

-7 > -11 (True)

Since one inequality is true and the other is false for the point (-12, -7), it is not a solution to the system of linear inequalities.

In conclusion, the point (9, -7) is the only solution to the system of linear inequalities given.

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The written form of 20 to 5 as a ratio in lowest terms as required is; 4 : 1.

It follows from the task content that 20 to 1 is required to be written as a ratio using lowest terms.

To write a representation such as 20 to 5 as a ratio; we have that;

20 : 5

However, to express the ratio in it's simplest form; we must divide both ratio terms by their greatest common factor which is 5.

Therefore, we have; 20/5 : 5/5

Ultimately, the required ratio on simplest terms is; 4 : 1.

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