Can somebody please help me with this?

Answer:

See explanation

Explanation:

The phase changes of carbon dioxide is quite interesting. It is even more interesting that its phase change from gas to solid is dependent on pressure and temperature.

The triple point of CO2 is -56°C at 5.11 atm pressure. This implies that below 5.11 atm, liquid CO2 can not exist. In fact, at -78°C and 1 atm, CO2 is a solid.

Hence, when pressure increases from 1 atm to 10 atm at -40C, CO2 changes from liquid to gas.

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As we know,

\( \sf \:currrent = \dfrac{charge}{time} \)

where,

Let's use the given formula ~

\(\qquad \sf  \dashrightarrow \: 2.5 = \dfrac{2000}{t} \)

\(\qquad \sf  \dashrightarrow \: t= \dfrac{2000}{2.5} \)

\(\qquad \sf  \dashrightarrow \: t = \dfrac{2000 \times 2}{2.5 \times 2} \)

\(\qquad \sf  \dashrightarrow \: t = \dfrac{4000 }{5 } \)

\(\qquad \sf  \dashrightarrow \: t = 800\)

So, the Total time taken by the Charge to flow through a motor is 800 seconds

Or it can be converted into minutes as :

Answer:

Observational

Explanation:

This is the answer because researchers or scientist observe the effect of a  diagnostic test, treatment or other intervention without trying to change anything.

The hydrosphere include glaciers, groundwater, and polar ice. That is option A, B and C.

Hydrosphere is defined as the part of the earth that is made up of water which includes the surface of the planet, underground, and in the air.

The water found in the hydrosphere of earth moves in cycles in such a way that non is lost.

The components of the hydrosphere include the following:

The polar ice is part of the hydrosphere because it is the frozen part of the earth's hydrosphere.

The lava is not part of the hydrosphere but part of lithosphere and it's released when volcanic eruptions occurs.

Therefore is can be concluded that glaciers, groundwater, and polar ice are parts of the hydrosphere while the lava is not part of the hydrosphere.

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Answer:

Manipulated (independent) Variable and Responding (Dependent) Variable

Answer:

c.all atoms have the same arrangement for electrons

Answer:

C because the number of protons and neutrons add up to make the number of electrons.

Answer:

A) 1 & 2 only

Explanation:

Seeing that the chemicals present are in question one I take it you are asking about that question.

Decreasing the concentration causes a decrease in reaction process and also the total amount of product you would get out of the given reaction

Decreasing the temperature causes the molecules in this reaction to become less excited or reactive, thus causing the reaction to slow down

Answer:

10.5 dm3 O2

0.94 moles de MgO

Explanation:

La pregunta dice explícitamente que el magnesio es puro en un 90%.

Por lo tanto, masa de magnesio puro = 90/100 * 25G = 22,5 g

Número de moles de Mg = 22,5g / 24g/mol = 0,94 moles de Mg

La ecuación de reacción es;

2Mg (s) + O2 (g) ------> 2MgO (s)

Si 2 moles de Mg reaccionan con 1 moles de O2

0.94 moles de Mg reacciona con 0.94 * 1/2 = 0.47 moles de O2

Si 1 mol de O2 ocupa 22,4 dm3

0.47 moles de O2 ocupan 0.47 * 22.4 / 1 = 10.5 dm3

También;

2 moles de Mg producen 2 moles de MgO

Entonces, 0.94 moles de Mg producen 0.94 moles de MgO

Answer:

Yup, I believe so.

Explanation:

Answer: Two, Wobble, Eclipsing.

Explanation:

A binary star system is made of two stars, one of which is brighter than the other. Astronomers are able to detect the dimmer star because its gravity causes the bright star to wobble. Astronomers can also spot the dimmer star by observing a phenomenon called an eclipsing binary.

Answer:

Two, Wobble, Eclipsing.

Explanation:

Answer:

Static Electricity

Explanation:

Answer:

static electricity

Explanation:

The 8.33 grams of calcium carbonate are required to provide the RDA of calcium.

The RDA (Recommended Daily Allowance) of calcium is 1.0 g for men and women from 19-50 years of age. Calcium carbonate CaCO3 contains 12.0% calcium by mass. To determine the number of grams of calcium carbonate required to provide the RDA of calcium, the following steps need to be followed:Step 1: Calculate the mass of calcium that is required to meet the RDA for calcium. 1.0 g is the recommended daily allowance (RDA) for calcium. Therefore, we require 1.0 g of calcium. Step 2: Calculate the mass of calcium carbonate that will yield 1.0 g of calcium. Calcium carbonate contains 12.0% calcium by mass.

This implies that 100 g of calcium carbonate contains 12 g of calcium. Then, (12 g of calcium / 100 g of CaCO3) = (1 g of calcium / x)Where x is the mass of CaCO3 required to obtain 1.0 g of calcium. Therefore, solving for x gives: x = (100 g of CaCO3 × 1 g of calcium) / 12 g of calciumx = 8.33 gThus, 8.33 g of calcium carbonate are needed to provide the RDA of calcium. Answer: 8.33 grams of calcium carbonate are required to provide the RDA of calcium.

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Answer:

pure substance

Explanation:

3.00 ×10² g of HF.

A Thermochemical Equation is a balanced stoichiometric chemical equation that includes the enthalpy change, ΔH. In variable form, a thermochemical equation would look like this:

A + B → C. ΔH = (±) #

The thermochemical reaction is of two types:

Endothermic Reaction Those thermochemical reactions in which heat is absorbed. Change in enthalpy for this reaction is positive.

Exothermic Reaction Exothermic reactions are the reaction in which the heat or the energy is evolved during the reaction.

SiO2 + 4 HF(g)  →  SiF4(g) + 2 H20(l)    ΔH®rxn=-184 kJ

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The mass of water needed to increase its temperature by 24.7°C and produce a heat energy of 24,183 J is 230.7 grams.

To calculate the mass of water required to increase its temperature by 24.7°C and produce a heat energy of 24,183 J, we can use the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
Using this information, we can calculate the mass of water needed as follows:
Heat energy = mass x specific heat capacity x change in temperature
Substituting the values given in the question, we get:
24,183 J = mass x 4.18 J/g°C x 24.7°C
Simplifying this equation, we get:
mass = 24,183 J / (4.18 J/g°C x 24.7°C)
mass = 230.7 g
Therefore, the mass of water needed to increase its temperature by 24.7°C and produce a heat energy of 24,183 J is 230.7 grams.

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The molarity of a solution is calculated by dividing the number of moles of a substance by the volume of the solution.

Here, correct answer will be

To determine the molarity of a 120.9132 g of MgO in 3 L of solution, we need to first convert the grams of MgO to moles. This can be done by dividing the mass of the MgO (120.9132 g) by its molar mass (24.305 g/mol for magnesium and 15.9994 g/mol for oxygen).

This gives us a total of 5.04 moles of MgO. We then divide this number by the volume of the solution (3 L) to get the molarity. Therefore, the molarity of 120.9132 g of MgO in 3 L of solution is 1.0 M MgO.

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The exercises refer to hydrocarbons. Depending on the type of bond, it will be the termination of the name of the molecule.

For a single bond: End with the suffix -ane

For double bond: Ends in -ene

For triple bond: Ends in -yne

Let's look at each particular case

a) Heptene

Hept- means 7 carbons, so we have a compound with 7 carbons and one double bond. The formula will be:

c)Hexane

6 carbons with a simple bond

d)Pentane

5 carbons with a simple bond

e)Propyne

3 carbons with a triple bond

The original volume of HBr that was titrated can be calculated as the ratio of the moles of HBr to its concentration.

To determine the original volume of HBr that was titrated, we can use the concept of stoichiometry and the equation balanced for the neutralization reaction between HBr and KOH.

The balanced equation is:

HBr + KOH → KBr + H₂O

From the balanced equation, we can see that the stoichiometric ratio between HBr and KOH is 1:1. This means that for every mole of HBr, we need an equal number of moles of KOH to complete neutralization.

First, let's determine the moles of KOH used in the titration:

Moles of KOH = 0.500 M × 0.075 L = 0.0375 mol

Since the stoichiometric ratio is 1:1, this also represents the number of moles of HBr that were neutralized.

Now, we can calculate the original volume of HBr using the concentration of the unknown solution:

Moles of HBr = 0.0375 mol

Concentration of HBr = unknown (let's assume it is C mol/L)

Volume of HBr = Moles of HBr / Concentration of HBr = 0.0375 mol / C mol/L

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Answer:

electronic configuration of Lead at the ground state is [ Xe ] 6 s 2 4 f 14 5 d 10 6 p 2 .

A first order process' rate constant, k, can be computed using the formula: k = 0.693/half-life.

A equation is a scientific statement indicating that two sums or values are equal, such as 6 x 4 = 12 x 2. When two or more components must be taken into account collectively in order to comprehend or describe the overall situation, this is known as an equation.

The meaning of an equation in algebra is a scientific statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.

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Answer:

Explanation:

Density of a substance can be found by using the formula

From the question

Density = 11.35 g/cm³

mass of iron = 1.1 g

To find the volume substitute the values into the above formula and solve for the volume

That's

Making volume the subject we have

So we have

= 0.096916

We have the final answer as

Hope this helps you

The attractive forces associated with the solid NaCl salt is the Dipole-dipole force and the ionic bonding.

The NaCl is the sodium chloride , the NaCl is formed by the ionic bond and called as the ionic compound. The ionic bond is the attractive force that is formed in between the positively charged atom and the negatively charge atom. The ionic bond is formed between the atom by the complete transfer of the electrons.

The NaCl compound is the polar in nature because of  the difference in the electronegativity between the sodium and the chlorine atoms, create  a permanent dipole. Therefore, the dipole dipole interaction is present in the sodium chloride.

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Answer:

Avogadro's number, 6.022×1023 6.022 × 10 23 , gives us the amount of substances or particles contained in one mole. For example, there are 6.022×1023 6.022 × 10 23 atoms in one mole of Ba, the symbol for the element barium.

To find the number of atoms in 274.66 g of barium, you need to know the atomic weight of barium and convert the weight to moles. The atomic weight of barium is 137.327 g/mol. Using the formula:

mol = weight/atomic weight

we find that 274.66 g of barium is equivalent to 2.00 mol of barium. Since there are Avogadro's number of atoms per mole, the number of atoms of barium in 274.66 g is equal to 2.00 mol * 6.022 x 10^23 atoms/mol = 1.20 x 10^24 atoms.

The ratio of atoms determines the empirical formula of adipic acid. As a result, C₂H₂O is the empirical formula for adipic acid.

To determine the empirical formula of adipic acid based on the given percentages of carbon (C), oxygen (O), and hydrogen (H) by mass, we need to convert these percentages into moles and then find the simplest whole number ratio.

Assume we have 100 grams of adipic acid. This assumption allows us to directly convert the percentages into grams.

Mass of C = 49.32 g

Mass of O = 43.84 g

Mass of H = 6.85 g

Convert the masses of each element into moles by dividing by their respective molar masses:

Molar mass of C = 12.01 g/mol

Molar mass of O = 16.00 g/mol

Molar mass of H = 1.01 g/mol

\(\text{Moles of C} = \frac{{49.32 \, \text{g}}}{{12.01 \, \text{g/mol}}} \approx 4.107 \, \text{mol}\)

\(\text{Moles of O} = \frac{{43.84 \, \text{g}}}{{16.00 \, \text{g/mol}}} \approx 2.740 \, \text{mol}\)

\(\text{Moles of H} = \frac{{6.85 \, \text{g}}}{{1.01 \, \text{g/mol}}} \approx 6.792 \, \text{mol}\)

Determine the simplest whole number ratio of the moles by dividing each mole value by the smallest mole value:

\(\text{Moles of C} = \frac{{49.32 \, \text{g}}}{{12.01 \, \text{g/mol}}} \approx 4.107 \, \text{mol}\)

\(\text{Moles of O} = \frac{{43.84 \, \text{g}}}{{16.00 \, \text{g/mol}}} \approx 2.740 \, \text{mol}\)

\(\text{Moles of H} = \frac{{6.85 \, \text{g}}}{{1.01 \, \text{g/mol}}} \approx 6.792 \, \text{mol}\)

Round the mole ratios to the nearest whole number:

Moles of C ≈ 2

Moles of O ≈ 1

Moles of H ≈ 2

The empirical formula of adipic acid is determined by the ratio of atoms. Therefore, the empirical formula of adipic acid is C₂H₂O.

Note: The molecular formula of adipic acid may be a multiple of the empirical formula, indicating a higher number of atoms in the actual molecule.

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Total, 42.37 millimeters of the 0.266 M Lithium nitrate solution are required to make 150 mL of the 0.075 M LiNO₃ solution.

To determine the volume of a 0.266 M LiNO₃ solution required to make 150 mL of a 0.075 M LiNO₃ solution, we can use the equation:

C₁V₁ = C₂V₂

Where;

C₁ = initial concentration of the LiNO₃ solution (0.266 M)

V₁ = volume of the LiNO₃ solution to be measured in millimeters (mm)

C₂ = final concentration of the LiNO₃ solution (0.075 M)

V₂ = final volume of the LiNO₃ solution (150 mL)

Rearranging the equation, we have;

V₁ = (C₂V₂) / C₁

Substituting the given values;

V₁ = (0.075 M) × (150 mL) / (0.266 M)

Converting mL to mm (1 mL = 1 mm), we get:

V₁ = (0.075 M) × (150 mm) / (0.266 M)

Calculating the result;

V₁ ≈ 42.37 mm

Therefore, approximately 42.37 millimeters of the 0.266 M LiNO₃ solution are required to make 150 mL of the 0.075 M  LiNO₃ solution.

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Answer:

hi

Explanation:

The final composition of the resulting solution of 10^-2 M NH4Cl and NaHS will have a pH of 9.36.

We are given the concentration of NH4Cl and NaHS as 10^-2 M.The ammonium ion (NH4+) will undergo hydrolysis in water and form NH3 and H+.NH4+ + H2O ⇌ NH3 + H+ (acid-base reaction)The reaction shows that the ammonium ion is an acid and will produce hydrogen ions in an aqueous solution.On the other hand, sodium hydrogen sulfide (NaHS) is a weak base and undergoes hydrolysis in an aqueous solution.NaHS + H2O ⇌ NaOH + H2SThe equation shows that hydrogen sulfide (HS-) is a weak acid and will produce hydroxide ions in an aqueous solution.The hydrolysis reactions of the two salts lead to an increase in hydroxide ions (OH-) in the solution, leading to a basic solution.

We can calculate the pH of the solution using the Kb values of NaHS and the Ka value of NH4+.NH4+ + H2O ⇌ NH3 + H+Ka = [NH3][H+]/[NH4+]Kb = [HS-][OH-]/[NaHS]We can assume the concentrations of NH3 and HS- to be the same, let's assume it is x, then the equilibrium constant can be expressed as:Kw = Ka × Kb[H+][OH-] = Ka × Kb[H+][OH-] = (1.8 × 10^-5) × (1.2 × 10^-13) = 2.16 × 10^-18pH + pOH = 14pH + pOH = 14pH = 14 - pOHpOH = -log[OH-] = -log(1.47 × 10^-8) = 7.83pH = 14 - 7.83 = 6.17We can conclude that the pH of the resulting solution will be 9.36 and the final composition of the resulting solution of 10^-2 M NH4Cl and NaHS will be basic.

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Answer:

V2= 531.4 ml

Explanation:

T1= 273+45 °C= 318 Kelvin

T2= 273+65 °C= 338 Kelvin

V1= 500ml *( 0.001L/1ml)= 0.5 Liters

V2= \(\frac{V1 * T2}{T1}\)= \(\frac{0.5 L * 338K}{318K}\) = 0.5314465409 Liters* (1 ml/0.001 L)= 531.4 ml