How do you calculate the theoretical yield?

Answer:

your answer is

A spot of the mixture is placed near the bottom of a piece of chromatography paper. The paper is then placed upright in a suitable solvent , such as water. As the solvent soaks up the paper, it carries the mixtures with it. Different components of the mixture will move at different rates.

Hope it’s helps you Buddy

Explanation:

Tribasic Potassium Phosphate + Calcium Nitrate = Tuite + Potassium Nitrate

2 moles of aqueous Tribasic Potassium Phosphate react with 3 moles of aqueous Calcium Nitrate to form 1 mole of solid Tuite and 6 moles of aqueous Potassium Nitrate

Reaction Type

Double Displacement (Metathesis)

Net Ionic Equation

2K3PO4 + 3Ca(NO3)2 = Ca3(PO4)2 + 6KNO3 might be an ionic equation. Calculate the net ionic equation for 2K3PO4(aq) + 3Ca(NO3)2(aq) = Ca3(PO4)2(s) + 6KNO3(aq).

Redox (Oxidation-Reduction) Reaction

K3PO4 + Ca(NO3)2 = Ca3(PO4)2 + KNO3 might be a redox reaction.

Reactants

Tribasic Potassium Phosphate - K3PO4

E340Iii E340(Iii) Potassium Phosphate Tripotassium Phosphate K3PO4 Molar Mass K3PO4 Oxidation Number

Calcium Nitrate - Ca(NO3)2

Saltpeter Lime Nitrate Lime Saltpeter Norge Saltpeter Norway Saltpeter Calcium Saltpeter Norwegian Saltpeter Anhydrous Calcium Nitrate Ca(NO3)2 Molar Mass Ca(NO3)2 Oxidation Number

Answer:

Be,Mg,Ca,Sr,Ba.Ra[down the group electronegativity is decreasing]

Explanation:

The following elements in order of decreasing electronegativity are:

Beryllium > Magnesium > Calcium > Strontium > Barium > Radium.

Electronegativities decrease from top to bottom within a group of elements. The order of decreasing electronegativities F > Cl > Br > I is another sequence that we will use to interpret the chemical and physical properties of organic compounds.

In the periodic table, atomic radii decrease from left to right across a row and increase from top to bottom down a column. Because of these two trends, the largest atoms are found in the lower-left corner of the periodic table, and the smallest are found in the upper right corner.

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The diagram best shows the field lines around two particles with opposite charges is the third diagram. Therefore, option C is correct.

A graphic tool for viewing vector fields is a field line. It is made up of a fictitious directed line that is perpendicular to the field vector over its whole length.

Among many other sorts, they are employed to display magnetic, electric, and gravitational fields. In the study of fluid mechanics, streamlines are field lines that display the velocity field of a fluid flow.

The field lines are parallel to the charge's surface. Both the size of the charge and the quantity of field lines are proportional. The positive charge is where the field lines begin, and the negative charge is where they come to a conclusion.

Thus, option C is correct.

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Answer: its C

Explanation: I took the test

M = mol/L

To solve for the number of atoms in a certain amount of moles, we must multiply the number of moles by Avogadro's number (\(N_A\)): \(6.02*10^{23}\), and multiply the product by the number of atoms in the compound.

We're given:

First, we must find the number of moles. We can do this by first converting 800.0 mL to L and multiplying it by 0.10 M.

800.0 mL ÷ 1000 = 0.8 L

⇒ Now, multiply 0.8 L by 0.10 M:

0.8 L × 0.10 M = 0.08 mol

Now, we must find the number of molecules in this sample. Multiply 0.08 mol by Avogadro's number:

\(0.08*6.02*10^{23}\\=0.4816*10^{23}\\=4.816*10^{22}\)

Finally, to find the number of atoms in the sample, multiply the number of molecules by the number of atoms in the compound.

We can begin by finding the number of atoms in sucrose:

\(C_{12}H_{22}O_{11}\)

12 + 22 + 11 = 45 atoms

⇒ Multiply 45 atoms by \(4.816*10^{22}\) mol:

\(45*4.816*10^{22}\\=216.72*10^{22}\\=2.1672*10^{24}\)

Convert to the correct number of significant figures (2):

\(=2.17*10^{24}\)

\(2.17*10^{24}\) atoms

Answer:

A.) Thermal

Explanation:

I got it correct on founders edtell

Answer:

Explanation:

So chemical changes require a change on a molecular level that cannot be reversed because they form some new substance. Souring milk is not something you can reverse, and the process of it souring produces new molecules.

0.361 moles of N₂ were required to produce 12.3 g of NH₃, using the balanced chemical equation N₂ + 3H₂ → 2NH₃.

The balanced chemical equation for the reaction is N₂ + 3H₂ → 2NH₃. We can use the balanced equation and the molar mass of NH₃ to calculate the number of moles of N₂ required to produce 12.3 g of NH₃,

1 mol NH₃ = 2 mol N₂ (from the balanced equation)

molar mass of NH₃ = 17.03 g/mol

moles of NH₃ = 12.3 g / 17.03 g/mol

moles of NH₃ = 0.722 mol

moles of N₂ = (0.722 mol NH₃) / 2

moles of N₂ = 0.361 mol

Therefore, 0.361 moles of N₂ were needed to produce 12.3 grams of NH₃.

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Complete question - For the reaction, N₂ + 3H₂ → 2NH₃. Given 12.3 grams of NH3, how many moles of N₂ were needed?​

KCl → k+ + Cl. The ensuing aggregate of ions is identical in each pre-and publish-blend unit of compounds. both comprise Na+, Cl-, okay+, and Br- ions, and no insoluble compounds can result from any mixture of those ions.

The three rules for writing net ionic equations are simply pretty trustworthy. only do not forget to break apart the (aq) substances. best split strong electrolytes.

Delete any ions that seem on both sides of the equation. when an aqueous solution of potassium chloride KCl, while combined with silver nitrate AgNO3 answers insoluble AgCl forms as a white substance. this is an example of a double displacement reaction. due to the fact potassium ion and silver ions displace collectively in the product formation.

The net ionic equation is a chemical equation for a response that lists best those species collaborating inside the reaction. The internet ionic equation is generally utilized in acid-base neutralization reactions, double displacement reactions, and redox reactions.

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An oxygen gas has a volume of 225 mL at 75.0° C and 175 mmHg the volume of the oxygen gas at the new conditions is 12 mL.

We can use the combined gas law to solve for the volume of the oxygen gas at the second set of conditions:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.

Converting the initial conditions to SI units:

V1 = 225 mL = 0.225 L

T1 = 75.0 + 273.15 = 348.15 K

P1 = 175 mmHg = 0.23 atm

Converting the final conditions to SI units:

T2 = 20.0 + 273.15 = 293.15 K

P2 = 11000 mmHg = 14.47 atm

Now we can solve for V2:

V2 = (P1 * V1 * T2) / (T1 * P2)

V2 = (0.23 * 0.225 * 293.15) / (348.15 * 14.47)

V2 = 0.012 L = 12 mL

Therefore, the volume of the oxygen gas at the new conditions is 12 mL.

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This means that the average kinetic energy of the particles in the first sample (at 600 K) is three times greater than the average kinetic energy of the particles in the second sample (at -73°C or 200 K).

According to the kinetic theory of gases, the average kinetic energy of gas particles is directly proportional to the temperature of the gas. The equation that relates the average kinetic energy (KE) and temperature (T) of a gas is

KE ∝ T

the average kinetic energy of gas particles increases with an increase in temperature and decreases with a decrease in temperature.

Given that one sample is at 600 K and the other sample is at -73°C, one need to convert -73°C to Kelvin by adding 273 (Kelvin = Celsius + 273).

The temperature in Kelvin for the second sample is: T₂ = -73°C + 273 = 200 K

Now one can compare the average kinetic energies of the two samples.

KE₁ / KE₂ = T₁ / T₂

Substituting the given temperatures: KE₁ / KE₂ = 600 K / 200 K

Simplifying the equation: KE₁ / KE₂ = 3, the average kinetic energy of the particles in the first sample (at 600 K) is three times greater than the average kinetic energy of the particles in the second sample (at -73°C or 200 K).

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Answer:

D

Explanation:

No energy is lost during transforming into another because energy cannot be reated or destroyed

Answer:

i think is d

Explanation:

I'm not sure wait for a few more answers

The empirical formula of the compound with 14.3% Nitrogen, 4.1% Hydrogen, and 81.6% Bromine would be \(NH_4Br\).

The compound contains 3 atoms of different elements according to the following percentage:

Let's find the mole equivalent of each percentage:

Divide by the smallest mole:

Thus, the empirical formula of the compound is \(NH_4Br\).

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Answer:

Color : Colorless.

Phase : Gas. ...

Odor : Oxygen is an odorless gas.

Taste : A tasteless gas.

Conductivity : A poor conductor of heat and electricity.

Solubility : Slightly soluble in water, alcohol and some other common liquids.

Density : It is denser than air.

Explanation:

Answer:

Sn is the oxidation agent and h2 is the reducing agent

Explanation:

Because oxidation agent means reduction which means the lose of oxygen and Sn lose oxygen.

While reduction agent means oxidation which also means the gain of oxygen and h2 gain oxygen.

I hope you understand my explanation if you need any help in chemistry I'm always here

The number of moles of the sodium chlroide from the calculation is 0.11 moles.

We can connect a substance's mass to its particle count using the concept of a mole. A material's molar mass, which is measured in grams per mole, is the mass of one mole of that substance. One mole of carbon-12 atoms, for instance, weighs 12 grams according to its molar mass of 12 grams/mol.

We have that;

Number of moles = Mass/molar mass

mass = 6.37 grams

Molar mass =  58.5 g/mol

Number of moles = 6.37 g/58.5 g/mol

= 0.11 moles

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The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

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sana maka tulong ❣️

Answer:

203 grams

Explanation:

The no. of moles of (6.3 x 10²⁴ molecules--Avagadros number) of NH₃ = (1.0 mol)(7.2 x 10²⁴ molecules)/(6.022 x 10²³ molecules) = 11.96 mol.

The no. of grams of NH₃ present = no. of moles x molar mass = (11.96 mol)(17.0 g/mol) = 203.3 g ≅ 203.0 g.

The answer is the mass of a sample of NH3 containing 7.20 x 1024 molecules of NH3 is 203 grams.

A molecule is a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.

6.02214076 × 10²³  molecules constitutes 1 mole of NH₃

7.20 x 10²⁴ molecules constitutes of

\(\rm\dfrac{7.20 \times 10^{24}}{6.02\times 10^{23}}\\\)

=11.19 moles

1 mole of NH₃ = 17 gm

11.19 mole will be = 17 * 11.19

= 203 grams

Therefore the mass of a sample of NH3 containing 7.20 x 1024 molecules of NH3 is  203 grams.

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Answer:

It's harder to melt sodium chloride because of its density and stability.

Explanation:

The bond between Na+ and Cl- is an ionic bond, meaning its an ionic compound. Ionic compounds have more inter molecular forces(forces involving multiple molecules). Chlorine has much less of these forces than NaCl and isn't as dense.

Answer:

It's harder to melt sodium chloride because of its density

Explanation:

To calculate the pressure inside the canister, we can use the ideal gas law equation:

PV = nRT

Therefore, the pressure inside the canister at a campfire temperature of 1500 °C is approximately 136.39 atmospheres.

To calculate the pressure inside the canister, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure (in atmospheres)

V = volume (in liters)

n = number of moles of gas

R = ideal gas constant (0.0821 L·atm/(mol·K))

T = temperature (in Kelvin)

First, we need to convert the volume from milliliters to liters:

1500 milliliters = 1500/1000 = 1.5 liters

Next, we need to convert the temperature from Celsius to Kelvin:

1500 °C + 273.15 = 1773.15 K

Now, we can substitute the values into the ideal gas law equation:

P * 1.5 = 3 * 0.0821 * 1773.15

Simplifying the equation:

P = (3 * 0.0821 * 1773.15) / 1.5

Calculating the value:

P ≈ 136.39 atm

Therefore, the pressure inside the canister at a campfire temperature of 1500 °C is approximately 136.39 atmospheres.

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Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Answer:

Increase

Decrease

Explanation:While in solution, ionic substances produce ions. The ions in solution determine the conductivity of the solution.

The ionic strength of a solution shows the concentration of ions in a given solution. The more the number of ions in the solution, the greater the ionic strength of the solution and vice versa.

When HNO3 is added to a solution of KOH, the number of ions in the solution increases and so does the ionic strength of the solution.

When KOH is added to a solution of CaCl2 then Ca(OH)2 is formed. The formation of a solid precipitate decreases the concentration of ions in solution as well as the ionic strength of the solution.

Answer:

The number of Bromine combining magnesium

Explanation:

The subscript gives the number of atom/s combining to form a compound. For this problem, 1 atom of Mg combines with 2 atoms of Br.

To form the ionic combine, Mg will lose two electrons. A bromine atom requires just one electron to have a complete octet. So, two bromine atoms will be needed to complete the bonding process.

Therefore, Mg loses two electrons to two Br atoms and the electrostatic attraction from the charges created forms the ionic bond.

The number 2 represents the number of bromine atoms.

Magnesium bromide is formed by the combination of magnesium (metal) and bromine (non-metal).

The valency of magnesium is 2 while that of bromine is 1. To form a neutral compound 2 moles of bromine ion combines with 1 mole of magesium ion.

Thus, the number 2 represents the number of bromine atoms.

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\(\\ \sf\longmapsto PV=nRT\)

\(\\ \sf\longmapsto 4.67(2)=0.66(8.314)T\)

\(\\ \sf\longmapsto 9.34=5.48T\)

\(\\ \sf\longmapsto T=1.7°C\)

Key words

Answer:

Was is a hydrocarbon therefore when heated some co2 escapes but later solidifies

Explanation:

Hope it helps

Answer:

0.052 M

0.059 m

Explanation:

There is some missing info. I think this is the complete question.

A student dissolves 4.6 g of glucose in 500 mL of a solvent with a density of 0.87 g/mL. The student notices that the volume of the solvent does not change when the glucose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.

Step 1: Calculate the moles of glucose (solute)

The molar mass of glucose is 180.16 g/mol.

4.6 g × 1 mol/180.16 g = 0.026 mol

Step 2: Calculate the molarity of the solution

0.026 moles of glucose are dissolved in 500 mL (0.500 L) of solution. We will use the definition of molarity.

M = moles of solute / liters of solution

M = 0.026 mol / 0.500 L = 0.052 M

Step 3: Calculate the mass corresponding to 500 mL of the solvent

The solvent has a density of 0.87 g/mL.

500 mL × 0.87 g/mL = 435 g = 0.44 kg

Step 4: Calculate the molality of the solution

We will use the definition of molality.

m = moles of solute / kilograms of solvent

m = 0.026 mol / 0.44 kg = 0.059 m