how do we get rid of oil droplets formed while hydrolyzing anhydride

Hope the picture help u understand I did it in steps so it would be easier to understand:)

Answer:

A catalyst

Catalysts speed up the rate of reaction without being changed or used up in the reaction.

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Answer:

Chemical Compound

Explanation:

I'm not sure why but I know it's chemical. Hope this helps!

Weathering of rocks by chemicals called  the breaking down or dissolving of rocks and minerals on Earths surface.

What is meant by rocks?

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Quick Sort is the sorting algorithm that has the following time complexity profile i.e., best case: o(n log n).

A Divide and Conquer method is Quick Sort. It chooses an element to act as a fulcrum and divides the supplied array around it. There are numerous variations of Quick Sort that select pivot in various methods.

1)As a rule, choose the first component as the center.

2)Always choose the final component as the center 

3)Choose a random number as a pivot element.

4)Decide on median as your center.

Partitioning is Quick Sort's primary operation. The partition procedure works best when it always chooses the middle element as the pivot. 

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The energy of the green light emitted per photon is 5.173e-19 Joule. The result is obtained by multiplying the frequency by the Planck's constant.

Photon energy is the energy radiated or absorbed by a single photon. The formula of photon energy is:

E = hν = hc/λ

Where

A mercury lamp emits the energy of the green light per photon an in joules with a frequency of 780715225001500.40 Hz.

The photon energy emitted is

E = hν

E = 6.626 × 10⁻³⁴ × 780715225001500.40

E = 5.173e-19 Joule

Hence, the energy of the green light per photon emitted by the mercury lamp is 5.173e-19 Joule.

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Therefore, the average rate of formation of Br2 during the first two minutes is 1.238×10⁻⁴ M/s.

To find the average rate of formation of Br2 during the first two minutes, we can use the stoichiometric ratio between Br2 and Br-. From the balanced equation, we can see that the ratio is 3:5.

Given that the average rate of consumption of Br- is 2.06×10⁻⁴ M/s, we can calculate the average rate of formation of Br2 using the stoichiometric ratio:

Average rate of formation of Br2 = (3/5) * (2.06×10⁻⁴M/s)

= 1.238×10⁻⁴ M/s

Therefore, the average rate of formation of Br2 during the first two minutes is 1.238×10⁻⁴ M/s.

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Answer:

5.77% Error.

Explanation:

Given an experimental value of 275 g , and a theoretical value of 260 g, the percent error can be found using the equation:

\(\% \: error \: = \frac{ |theoretical \: value \: - \: experimental \: value | }{theoretical \: value} \times 100\)

% Error = ( | 260 - 275 | / 260 ) × 100 = ( | - 15 | / 260 ) × 100 = ( 15 / 260 ) × 100 = 1500/260 = 300 / 52 = 5.769230769230.. ≈ 5.77%

The concentration of Hg₂²⁺ in 0.10 M KI saturated with Hg₂I₂ is 8.5x10⁻⁹ M.

To find the concentration of Hg₂²⁺ in 0.10 M KI saturated with Hg₂I₂, we first need to write the solubility product expression for Hg₂I₂.

Hg₂I₂(s) ↔ 2Hg₂²⁺(aq) + 2I⁻(aq).

The solubility product expression for this reaction is Ksp = [Hgₓ₂²+]²[I⁻]². In order to account for activity coefficients, we need to use the Debye-Hückel equation.

At 25°C, the activity coefficient of KI is 0.76 and that of Hg₂I₂ is 0.41.

Using these values, we can calculate the concentration of Hg₂²⁺ as follows: Ksp = [Hg₂²+]²[I⁻]² = (0.41*[Hg₂²⁺])²*(0.76*0.10)².

Solving for [Hg₂²⁺] gives us a concentration of approximately 8.5x10⁻⁹ M.

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Phenolphthalein in highly acidic solutions, it may exhibit a slightly pink color, and in highly basic solutions, it may appear colorless again.

In acidic solutions (pH < 7), phenolphthalein is colorless. This is because, in an acidic environment, the concentration of hydrogen ions is high. Phenolphthalein is a weak acid that undergoes deprotonation in the presence of excess H⁺ ions, forming its colorless form. The equilibrium between the acidic and deprotonated forms of phenolphthalein is shifted towards the colorless form in acidic conditions.

In basic solutions (pH > 7), phenolphthalein exhibits a pink or magenta color. In a basic environment, the concentration of hydroxide ions (OH⁻) is high. Phenolphthalein in its deprotonated form is a negatively charged ion (anion) and is stabilized by the presence of the excess OH⁻ ions. The deprotonated form has a pink or magenta color, leading to the color change.

The transition range of phenolphthalein, where it changes from colorless to pink/magenta, occurs around pH 8.2 to 10.0. Below pH 8.2, it remains colorless, and above pH 10.0, it becomes a deep pink/magenta.

Phenolphthalein is not suitable for use in strongly acidic or strongly basic solutions as the color change is not as clear. In highly acidic solutions (pH < 3), it may exhibit a slightly pink color, and in highly basic solutions (pH > 12), it may appear colorless again.

So, phenolphthalein is a useful pH indicator due to its clear and distinct color change in the pH range of approximately 8.2 to 10.0, making it suitable for determining the endpoint in acid-base titrations or pH determination in that range.

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The defined value of the principal quantum number (n) associated with 5d is 5.

The principal quantum number (n) is an integer that represents the energy level or shell of an electron in an atom. It determines the overall size and energy of an orbital. In the case of the 5d orbital, the principal quantum number is 5, indicating that the electron occupies the fifth energy level or shell.

The principal quantum number can have any positive integer value starting from 1. As the value of n increases, the energy level and distance from the nucleus also increase. Therefore, the 5d orbital corresponds to the fifth energy level or shell, with a higher energy and larger size compared to lower energy levels like 1s, 2p, or 3d.

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During the formation of a water molecule, we focus on the oxygen atom. In hybridization of H2O, the oxygen atom is sp3hybridized.

The percent yield of a reaction is the percentage of the theoretical yield that is actually obtained in the experiment which is 59.9%.

To calculate the percent yield of the reaction between titanium metal and chlorine gas to form titanium(IV) chloride, the following calculation must be made:

Actual yield / Theoretical yield x 100

The actual yield in this reaction is 9.1 g of titanium(IV) chloride, and the theoretical yield can be calculated from the balanced chemical equation:

3.71 g Ti + 7.42 g Cl2 → TiCl4 + 3 g Cl2

The theoretical yield is calculated by multiplying the moles of titanium metal by the molar mass of titanium(IV) chloride:

3.71 g Ti / (47.90 g/mol) = 0.0777 mol Ti × (193.86 g/mol) = 15.2 g TiCl4

The percent yield of the reaction is then:

9.1 g TiCl4 / 15.2 g TiCl4 ×100 = 59.9% yield

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The intermolecular forces at play that allow the sodium sulfate to dry the product are hydrogen bonding and van der Waals forces.

When anhydrous sodium sulfate is added to a solution, it readily absorbs water molecules by forming hydrogen bonds with them. This removal of water molecules results in a reduction in the number of water molecules present in the mixture and thus, the product is dried.

Additionally, van der Waals forces also play a role in the drying process. Van der Waals forces are weak, non-covalent forces that arise due to the fluctuation of electron density in a molecule. They are responsible for the interaction between molecules, including the attraction between sodium sulfate and water molecules.

The combined effect of hydrogen bonding and van der Waals forces results in the absorption of water by the anhydrous sodium sulfate, leading to the drying of the product.

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To make a 60 ml of 2% Minoxidil solution, 120 tablets of 10 mg Minoxidil are required.

To make a 2% solution of Minoxidil, we need 2 grams of Minoxidil in 100 ml of solution.

First, we need to convert 60 ml to grams. Since 1 ml of water weighs 1 gram, we can assume that 60 ml of solution weighs 60 grams.

To make a 2% solution, we need 2 grams of Minoxidil in 100 ml of solution. This means that for 60 ml of solution, we need:

(2 grams / 100 ml) x 60 ml = 1.2 grams

Each Minoxidil tablet has a weight of 10 mg, which is equivalent to 0.01 grams. Therefore, the number of tablets needed is:

1.2 grams ÷ 0.01 grams per tablet = 120 tablets

So the answer is A) 120 tablets.

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Answer:

The correct statement is;

(B) Only II

Explanation:

I) The atomic mass unit or amu which is also known as daltons which is defined as 1/12 × the mass of a carbon-12 atom, which is therefore, 1.660538921 × ⁻²⁴ grams

Therefore, the mass of 1 atom of carbon-12 = 12 amu

II) The mass of one mole of oxygen-16 is 16 grams while the mass of one mole of carbon-12 is 12 grams

The mass of 4 atoms of carbon 12 = 4 × 12 amu = 48 amu

The mass of 1 atom of oxygen-16 = 15.99491461956 amu

Therefore, the mass of 3 atoms of oxygen-16 = 3 × 15.99491461956 = 47.9847438587 amu ≈ 48 amu

Therefore only II is correct.

a) The concentration of N_2O_4 in the container after one half-life of the reaction is 1.4 moll L.

b) The concentration after 60 seconds is option B 0.60 M.

What are the 3 types of concentration?

The three types of concentration commonly used in chemistry are:

Molarity (M): This is the most commonly used type of concentration, and it is defined as the number of moles of solute per liter of solution. Molarity is represented by the symbol "M".

Molality (m): This is a concentration unit that measures the number of moles of solute per kilogram of solvent. Molality is represented by the symbol "m".

Mass Percent (%m/m): This is a concentration unit that measures the mass of solute per 100 grams of solution. It is also called weight percent. Mass percent is represented by the symbol "%m/m".

The explanation of the answer is given below.

Therefore, The concentration of N_2O_4 in the container after one half-life is 1.4 moll L and concentration after 60 seconds is 0.60 M.

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Answer:

The answer is A. a wave of vibrating electric and magnetic energy.

Answer: Decomposition is the answer

Explanation: why because aluminium hydroxide would decomposes in the presence of heat and would form an oxide which is aluminium oxide and would also form water as a product.

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Only possible with alkaline earth metals

Let's see an example

\(\\ \sf\longmapsto X(OH)_2\)

The elements are

Option C is correct

\(\rule{300pt}{1000000pt}\)

Answer:

D. The number of protons.

The molecular formula of the compound CH2 with molar mass = 42.0 g/mol is C₃H₆. Therefore, option D is correct.

The term molar mass is defined as the mass in grams of one mole of a substance. The units of molar mass are grams per mole, abbreviated as g/mol.

First, let's find the molar mass of CH₂.

The molar mass CH₂= 12.0 + (2 x 1.01)

= 14.02 g/mol

Now to determine the molecular formula, we need to find the ratio based in the molar masses.

42 / 14.02

= 2.99

≅ 3

Therefore, the ratio is 3, the molecular formula is C₃H₆.

Thus, option D is correct.

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Answer:

c. side chain

Explanation:

c. side chain. The variable part of an amino acid, which is the unique chemical structure that distinguishes one amino acid from another, is the side chain (also known as R-group).

The side chain, commonly referred to as the R-group, is the variable component of an amino acid and the particular chemical structure that sets one amino acid apart from the others. Each amino acid shares the same fundamental structure, which consists of a core alpha carbon atom bound to a hydrogen atom, an amino group (NH₂), an acid group (COOH), and an amino group (NH₂). The particular collection of atoms connected to the core carbon is known as the side chain, and it differs amongst various amino acids. The amino acid's distinct characteristics and roles in protein synthesis and biological processes are determined by the side chain's make-up and structure.

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Calcium carbonate, CaCO3, decomposes to form calcium oxide, CaO, and carbon dioxide, CO2. The balanced chemical equation for this decomposition reaction is:

CaCO3 -> CaO + CO2

To determine the number of moles of calcium carbonate that react, you need to know the molar mass of calcium carbonate. The molar mass of calcium carbonate is 100.09 g/mol.

Now, you can use the molar mass of calcium carbonate to calculate the number of moles of calcium carbonate that react. To do this, divide the mass of calcium carbonate by its molar mass:

24.5 g CaCO3 / 100.09 g/mol = 0.2447 moles CaCO3

Therefore, 0.2447 moles of calcium carbonate react when 24.5 g of calcium carbonate decompose.

If we had used 4 grams of NaOH instead of 2 grams, the heat gained by the solution would have been higher.

The term enthalpy has to do with the heat that could be emitted or evolved in a given reaction. We know that in a neutralization reaction, there is an evolution of heat and as such the reaction  vessel would feel warm at the end of the reaction.

Also, the enthalpy would depend on the amount of the limiting reactant. In this case, the limiting reactant would be the sodium hydroxide and as such the enthalpy would affected by a change in the amount of the sodium hydroxide.

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The equation that reflects combustion is the equation in Option B.

We know that a combustion reaction has to do with a kind of reaction that involves the burning of a substance in oxygen. As such, when the substance is burnt we have carbon dioxide and water produced.

In this case, we have to look at the equations as they have been written and then try to know which of them has to do with the burning of a substance in oxygen and this would be the  Option B. It is the burning of an organic compound.

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Answer:

Experiment plays many roles in science. One of its important roles is to test theories and to provide the basis for scientific knowledge. It can also call for a new theory, either by showing that an accepted theory is incorrect, or by exhibiting a new phenomenon that is in need of explanation.

Explanation:

Answer:

Explanation:

One of its important roles is to test theories and to provide the basis for scientific knowledge that we need to know. How are we supposed to know the answer to our question if we don't perform the experiment to test our question.

The given reference, "stavrinidou, e. et al. direct measurement of ion mobility in a conducting polymer. adv. mater. 25, 4488–4493 (2013)" is a citation for a scientific paper published in the journal Advanced Materials.

This paper, written by Stavrinidou et al. in 2013, focuses on the direct measurement of ion mobility in a conducting polymer.

Ion mobility refers to the ability of ions (charged particles) to move within a material. In the context of conducting polymers, ion mobility is an important property as it determines the material's ability to conduct electricity. Understanding and measuring ion mobility can provide insights into the electrical behavior of conducting polymers.

The paper by Stavrinidou et al. describes a method for directly measuring ion mobility in a conducting polymer. They likely conducted experiments using specialized equipment and techniques to determine the speed at which ions move within the material.

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