How do I graph y-7=-3(x-1)

(a) To find the

constant

A, we need to integrate the given pdf from 0 to 1 and set it equal to 1, since the total

probability

of all possible outcomes must be 1:

∫[0,1] A(1/x) dx = 1

Using the fact that ln(1/x) is the antiderivative of 1/x, we get:

A[ln(x)]|[0,1] = 1

A[ln(1) - ln(0)] = 1

A(0 - (-∞)) = 1

A = 1

Therefore, the constant A is 1.

(b) The expected capacity of the storage tank is the expected value of the random variable, which is given by:

E(X) = ∫[0,1] x f(x) dx

Using the given pdf, we get:

E(X) = ∫[0,1] x (1/x) dx = ∫[0,1] dx = 1

Therefore, the expected capacity of the storage tank is 1 thousand gallons.

(c) Let C be the capacity of the tank in thousands of gallons. Then, the probability that the supply is exhausted in a given week is the probability that the weekly sales exceed C, which is given by:

P(X > C) = ∫[C,1] f(x) dx

Using the given pdf, we get:

P(X > C) = ∫[C,1] (1/x) dx = ln(1/C)

We want P(X > C) = 0.01, so we solve the equation ln(1/C) = 0.01 for C:

ln(1/C) = 0.01

1/C = e^0.01

C = 1/e^0.01

Rounding this to 3 decimal places, we get:

C ≈ 0.990

Therefore, the capacity of the tank must be at least 0.990 thousand gallons to ensure that the probability of the supply being exhausted in a given week is no more than

0.01

.

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Answer: Meiosis

Step-by-step explanation: Meiosis is the type of cell division that creates egg and sperm cells.

Answer: meiosis

Step-by-step explanation:

To know how much each chocolate bar costs, knowing that ten chocolate bars cost 3 pesos, we only have to divide the total cost of the 10 chocolate bars by the total number of chocolate bars.

So that:

Tenth that; the cost of each bar is 0.3 pesos.

We can reject the null hypothesis at the 0.05 level and accept the alternative hypothesis.

A one-sided test will test using the full alpha to test whether the result is far enough in one direction. A two-sided test will split the alpha in half to test whether the result is too big or too small.

The null hypothesis is:

\(\mathit{H}_{0}: \mu= 2.5\)

The alternative hypothesis is:

\(\mathit{H}_{1}: \mu > 2.5\)

The z-score for a mean of 3 is:

\(z = (x- \mu)/ (\sigma/ \sqrt{n})) \\ = (3-2.5)/(1.8/\sqrt{n})) \\ = (.5)/(1.8/6)) \\ = (.5)/(.3)) \\ = 1.666666667\)

The z-score for the 0.05 significance level is 1.645, which is less than the mean of 3 z score of 1.67.

Hence, we can go ahead and reject the null hypothesis

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95.54% of the chocolate bars at the factory weigh less than 8. 17 ounces

An equation is an expression showing the relationship between two or more numbers and variables. An equation can either be linear, quadratic, cubic and so on depending on the degree.

z score shows by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean)/standard deviation

Given that mean = 8, standard deviation = 0.1

For x < 8.17 ounces:

z = (8.17 - 8) / 0.1 = 1.7

From the normal distribution table:

P(z < 1.7) = 0.9554 = 95.54%

The probability that the chocolate bars weigh less than 8. 17 ounces is 95.54%

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The volume of the Illustrated cone used as an example is 51.3cm³.

Volume is a measurement of three-dimensional space that is occupied. It is frequently expressed numerically using SI-derived units, as well as different imperial or US-standard units. Volume and the definition of length are related.

A cone is a recognizable three-dimensional geometric shape with a flat and curved surface that is pointed upward. The formula for the volume of a cone is V=1/3hπr²

Let's say the radius is 7cm. The volume will be:

= 1/3 × 3.14 × 7²

= 51.3cm³

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To complete the indirect proof, also known as proof by contradiction, we assume the opposite of the desired conclusion and derive a contradiction from it. In this case, we assume ~(~S V ~U) and aim to derive a contradiction.

Assume ~(~S V ~U). Using De Morgan's law, we can rewrite this as (S & U). From the premises, we have:

1. S ⊃ D (TV ~U)

2. U ⊃ D (~T V R)

3. (S & U) ⊃ ~R  (given, not ~R)

We will now derive a contradiction:

4. ~R                       (modus ponens: 3, S & U)

5. ~T V R                 (modus ponens: 2, U)

6. ~T                      (disjunctive syllogism: 4, 5)

7. TV ~U                  (modus ponens: 1, S)

8. U                        (simplification: S & U)

9. ~U                      (disjunctive syllogism: 4, 8)

From step 8 and step 9, we have both U and ~U, which is a contradiction.

Since we derived a contradiction from the assumption ~(~S V ~U), our initial assumption must be false. Therefore, the conclusion ~S V ~U must be true.

Hence, the indirect proof demonstrates that ~S V ~U is true.

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Answers:

x= -10 and y= 16

3y = -6x - 12

3y = -6(-2y+22) -12

3y = 12y - 144

3y + -12y = 12y -144 + -12y

-9y = -144

divide -9 on both sides

y= 16

x= -2y+22

x= -2y+22

x= (-2)(16)+22

x= -10

Answer:

99   (cm^2)

Step-by-step explanation:

Perpendicular to the AB segment at points D and C, the graph is divided into two triangles and a rectangle.

The area of the middle rectangle is equal to 8*9=72. The hypotenuse of the right triangle is 10cm, and one of the right sides is 9cm, so the other side is SQRT (10^2-9^2) = SQRT (19).

One side of the left triangle is 9cm long and the other side is 14-8-sqRT (19) = 6-sqRT (19) cm.

Then, add the area of the three parts.

72+9*sqrt（19）/2+9*（6-sqrt（19））/2=99    (cm^2)

a. The corresponding parts (angles and sides) of the image and preimage of triangle ABC are congruent after two rigid transformations. b. The congruence of the corresponding parts is true because rigid transformations preserve the shape and size of geometric figures.

a. When comparing all corresponding parts (angles and sides) of the image and preimage of triangle ABC after two rigid transformations, we observe that they are congruent. This means that the corresponding angles and sides of the transformed triangle match exactly with the corresponding angles and sides of the original triangle.

b. The results are true because rigid transformations (such as translations, rotations, and reflections) preserve the shape and size of geometric figures. In other words, these transformations do not alter the angles and lengths of the original triangle. As a result, the transformed triangle remains congruent to the original triangle.

To prove that two triangles are congruent without using rigid transformations:

a. You can use other methods of congruence, such as side-angle-side (SAS), angle-side-angle (ASA), or side-side-side (SSS) congruence. These methods involve comparing specific combinations of angles and sides between the triangles.

b. No, it is not necessary to show that all parts of one triangle are congruent to all parts of the other triangle to prove their congruence. Depending on the given information, you can use the appropriate congruence criteria (such as SAS, ASA, or SSS) to establish the congruence of the triangles based on the specific combinations of angles and sides that are known or given.

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Answer:

ufoufoydiyd8yf86fiyxitdkydyofiyd8yfoyfoycoycoycoycoyfiyfiyfyocyiciycigxitc8txitditxt8xtix8tx8td8yd8yc8yyc8yf58d8txt7x85d85duts7td8txits

Step-by-step explanation:

yfid8yydyofoyf0

Answer:

the area of the shape is 7.14

Step-by-step explanation:

First, find the area of the square:

2 in x 2 in = 4 in

then to find the area of the semi- circles add them together to make a circle

To find the area of the circle, use:

pi x radius^2  

Since the diameter is 2 divide the diameter by 2 to get radius  

3.14 x 1^2 = 3.14

The circle is 3.14 plus 4 ( the square ) = 7.14

Answer:

They are zeroes when y=0

Step-by-step explanation:

For a function \(f(x)\), if \(f(x)=0\), the values of x that make the function true are known as roots, or x-intercepts, or zeroes.

Step-by-step explanation:

Today, we are going to be talking about the three-way principle of mathematics. Basically, there are three ways to solve a problem in math: verbally, graphically, or by example. In this lesson, we will discuss each of these principles by solving sample problems using each type.

Answer:

x and y both equal 24

The domain is all real numbers and the Range is y ≥ 3.The correct answer is option A.

To determine the domain and range of the quadratic function based on the given table, let's analyze the values.

Domain represents the set of possible input values (x-values) for the function.

Range represents the set of possible output values (y-values) for the function.

From the given data:

x = -1, 0, 1, 4

y = 5, 3, 3, 5, 35

Looking at the x-values, we can see that the function has values for all real numbers. Therefore, the domain of the function is "all real numbers."

Now, let's consider the y-values. The minimum value of y is 3, and there are no y-values less than 3.

Additionally, the maximum value of y is 35. Based on this information, we can conclude that the range of the function is "y ≥ 3" since all y-values are greater than or equal to 3.

Therefore, the correct answer is:A. Domain: all real numbers

Range: y ≥ 3

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The probable question may be:

The table below represents a quadratic function. Use the data in the table to determine the domain and range of the function.

x= -1,0,1,4

y= 5,3,3,5,35

A. Domain: all real numbers Range: y ≥3

B. Domain: all real numbers

Range: x≥0

c. Domain: all real numbers

Range: y ≥0

D. Domain: all real numbers

Range: y ≤3

Answer:

d. 8 over 15 = 136 over 15 this is the right answer okay

Answer:

Thats the answer from american school

Step-by-step explanation:

The value of the common length BD would be 8 units aprroximately.

Trigonometric identities are the functions that include trigonometric functions such as sine, cosine, tangents, secant, and, cot.

Given information;

1. Considering line BD as a side of ABD, express its length in terms of variables representing side lengths and angle measures in ABD.

So, We know that

Sin A = BD / AB

Sin A = BD / c

c Sin A = BD

Substitute;

(10) Sin (53.13) = BD

BD = 10 ( 0.79)

BD = 7.99

Therefore, the value of the common length BD would be 8 units aprroximately.

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The height of the quarter is given by the polynomial -16t^2 + 250 feet and the height of the dime is given by the polynomial -16t^2 - 10t + 100 feet.

To compare the height of the quarter and dime at any time t, we need to find the difference between their heights.

Let's first find the height of the dime when the quarter is released, which is at t=0:

Height of the quarter at t=0: 16(0)^2 + 250 = 250 feet

Height of the dime at t=0: -16(0)^2 - 10(0) + 100 = 100 feet

So, the initial height difference between the quarter and dime is 250 - 100 = 150 feet.

Now, let's find the height difference between the quarter and dime at any time t:

Height of the quarter at time t: 16t^2 + 250

Height of the dime at time t: -16t^2 - 10t + 100

So, the height difference at time t is:

(16t^2 + 250) - (-16t^2 - 10t + 100) = 32t^2 + 10t + 150

Therefore, the height difference between the quarter and dime at any time t is given by the polynomial 32t^2 + 10t + 150.

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Answer:2.5cm

Step-by-step explanation:1cm =0.01 m

Answer:

17

Step-by-step explanation:

You would make the 10.01 a 10 and the 7.07 a 7.

Answer:-8\5

Step-by-step explanation down 8 to the left 5

a. uniformly distributed.  When the probability is proportional to the length of the interval in which the random variable can assume a value, the random variable is said to be uniformly distributed.

In a uniform distribution, the probability density function is constant within the interval, meaning that all values within the interval have an equal chance of occurring.

The uniform distribution is characterized by a rectangular-shaped probability density function, where the height of the rectangle represents the probability and the width of the rectangle represents the interval. This distribution is often used when there is no specific bias or preference for any particular value within the interval.

On the other hand, the normal distribution (b) follows a bell-shaped curve, the exponential distribution (c) describes the time between events in a Poisson process, and the Poisson distribution (d) is used to model the number of rare events occurring in a fixed interval of time or space.

Therefore, the random variable is uniformly distributed (a) when the probability is proportional to the length of the interval.

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it is seen that if the number of people in the group is n = 23, the probability that at least two people will have the same birthday is at least 1/2.

Let P(A) be the probability that in a randomly selected group of n people, at least two people have the same birthday.

If we assume that the year has 365 days, then the number of ways to select n people with different birthdays is n x (n-1) x (n-2) x ... x (n-364).

the probability of selecting n people with different birthdays is P(A') = n(n - 1)(n - 2)...(n - 364)/365nThen, the probability that at least two people in a group of n have the same birthday is given by P(A) = 1 - P(A').

We need to find the smallest value of n such that P(A) ≥ 1/2.Let's solve for this.Let us find n such that P(A) ≥ 1/2.

By using the complement rule, 1-P(A') = P(A).Then:1 - n(n - 1)(n - 2)...(n - 364)/365n ≥ 1/2n(n - 1)(n - 2)...(n - 364)/365n ≤ 1/2(2)n(n - 1)(n - 2)...(n - 364) ≤ 365n/2Now, take the natural logarithm of both sides and simplify as follows:ln[n(n - 1)(n - 2)...(n - 364)] ≤ ln[365n/2]nln(n) - ln[(n - 1)!] - ln[(n - 2)!] - ... - ln[2!] - ln[1!] ≤ ln[365n/2]

Therefore, we need at least 23 people in the group for the probability of two or more people having the same birthday to be at least 1/2.

This is because n = 23 is the smallest number for which the inequality holds, and therefore, it is the smallest number of people required to ensure that the probability of two or more people having the same birthday is at least 1/2.

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The probability that 6 lands face up at least once in the five rolls of a fair die is 0.4643 or 46.43%.

First of all, let's find out the total number of outcomes possible when a fair die is rolled 5 times.

The number of possible outcomes for a single roll of a die is 6.

Thus, the total number of outcomes possible for 5 rolls of a die will be \(6^5 = 7776.\)

Next, let's find out the number of outcomes in which no 6 lands face up.

The probability of not getting a 6 in a single roll is 5/6 (since there are 5 faces other than 6 on the die).

Thus, the probability of not getting a 6 in any of the 5 rolls is\((5/6)^5\).

So, the number of outcomes in which no 6 lands face up will be: \(7776 x (5/6)^5 = 4165.08\)

Now, let's find out the number of outcomes in which at least one 6 lands face up.

This will be the total number of outcomes minus the number of outcomes in which no 6 lands face up.

So, the number of outcomes in which at least one 6 lands face up will be:

7776 - 4165.08 = 3610.92.

Thus, the probability of getting at least one 6 in 5 rolls of a die will be:

3610.92/7776 = 0.4643 (rounded to 4 decimal places).

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Answer:

22

Step-by-step explanation:

You use the order of operations: PEMDAS.

Sooo...

4*6-8/4=

24-8/4=

24-2=

22

The plot of y(t) will show how the mass oscillates with time, starting from the equilibrium position and gradually coming to rest due to the damping effect of the friction.

The given equation represents the motion of a mass connected to a spring with viscous friction. To plot the displacement, y(t), we need to solve the differential equation. With initial conditions y(0) = 0, we can find the solution using the Laplace transform. After solving the equation, we can plot y(t) for t < 0 and t ≥ 0 separately. For t < 0, the applied force, f(t), is zero, so the mass will not experience any external force and will remain at rest. For t ≥ 0, the applied force is 10, and the mass will respond to this force and undergo oscillatory motion around the equilibrium position.

To solve the given differential equation, we can start by finding the characteristic equation by setting the coefficients of y, its derivative, and its second derivative to zero:

s^2 + 18s + 102 = 0.

Solving this quadratic equation gives us the roots s1 = -3 + 3i and s2 = -3 - 3i. These complex roots indicate that the mass will undergo damped oscillations.

Using the Laplace transform, we can solve the differential equation and obtain the expression for Y(s), the Laplace transform of y(t):

(s^2 + 18s + 102)Y(s) = F(s),

where F(s) is the Laplace transform of f(t). Since f(t) = 10 for t ≥ 0, its Laplace transform is F(s) = 10/s.

Solving for Y(s) gives us:

Y(s) = 10 / [(s^2 + 18s + 102)].

To find y(t), we need to inverse Laplace transform Y(s). Using partial fraction decomposition, we can express Y(s) as:

Y(s) = A / (s - s1) + B / (s - s2),

where A and B are constants to be determined. After finding A and B, we can inverse Laplace transform Y(s) to obtain y(t).

With the given initial condition y(0) = 0, we can solve for A and B by setting up equations using the initial value theorem:

A / (s1 - s1) + B / (s1 - s2) = 0,

A / (s2 - s1) + B / (s2 - s2) = 0.

Solving these equations will give us the values of A and B. Finally, we can substitute these values back into the inverse Laplace transform of Y(s) to obtain y(t).

For t < 0, since the applied force f(t) is zero, the mass will not experience any external force. Therefore, y(t) will remain at its initial position, y(0) = 0.

For t ≥ 0, the applied force f(t) is 10, and the mass will respond to this force and undergo oscillatory motion around the equilibrium position. The displacement, y(t), will depend on the properties of the mass, the spring, and the viscous friction. The plot of y(t) will show how the mass oscillates with time, starting from the equilibrium position and gradually coming to rest due to the damping effect of the friction.

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Answer:

Each child will receive eight fifths of the cupcakes.

5x=8 ; x represents how many cupcakes each child receives.

\(\frac{8}{5}\)

Step-by-step explanation:

There are 8 cupcakes in total.

5 children.

Divide 8 by 5. \(\frac{8}{5}\)

I hope this helps!

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Answer:

6/25

Step-by-step explanation:

.24 = 24/100 = 6/25

Answer:

6/25

Step-by-step explanation:

step 1 The decimal number = 0.24

step 2 Write it as a fraction

0.24/1

step 3 Multiply 100 to both numerator & denominator

(0.24 x 100)/(1 x 100) = 24/100

It can be written as 24% = 24/100 or 24/100

step 4 To simplify 24/100 to its lowest terms, find LCM (Least Common Multiple) for 24 & 100.

4 is the LCM for 24 & 100

step 5 divide numerator & denominator by 4

24/100 = (24 / 4) / (100 / 4)

= 6/25

6/25 is a simplest fraction for the decimal point number 0.24

answer:

tell us why the other gardens are needed