how could you check that when the calcium carbonate is reacting with hydrochloric acid the gas given off is carbon dioxide

Answer:

Explanation:

as we know in a face-centered unit each atom give1/2 a portion at the face

and fully atom involvement at center therefore  

1/2( total face of cube )+ 1(centre)

1/2 ×6 + 1

3+ 1

4 atoms per cell

The complication to the Schrodinger equation in multi-electron systems arises because electrons repel each other.

The Schrodinger equation is an equation that can be used to obtain the position of an electron in an atom. The position of the electro is obtained as the wavefunction. This wave function would yield four sets of values that we call the atomic orbital.

Thus the complication to the Schrodinger equation in multi-electron systems arises because electrons repel each other. This repulsion of the electrons have prevented the application of the equation to multi electron systems.

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Based on the given information, the true statement about the time indicated by the blue arrow is: (c) The rate of the forward reaction (N₂O₄ formation) is equal to the rate of the reverse reaction (NO₂ formation).

The graph shows the relative amounts of NO₂ and N₂O₄ over time, and the point indicated by the blue arrow represents a state of equilibrium. In an equilibrium state, the forward and reverse reactions occur at equal rates.

The concentrations of NO₂ and N₂O₄ reach a constant value, indicating that the conversion of NO₂ to N₂O₄ and the conversion of N₂O₄ to NO₂ are occurring at the same rate.

Option a suggests that NO₂ molecules are no longer reacting, which is incorrect as the reaction is still ongoing at equilibrium. Option b suggests that the reactant has been completely used up, which is not the case in an equilibrium state. Option d refers to the activation energy, which is unrelated to the equilibrium state. Therefore, option c is the correct choice.

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Answer:

freezing

Explanation:

because condensation is gas to liquid boiling is liquid to gas and sublimation is solid to gas

The volume of ideal gas will be decreased if the pressure increase while the temperature remain constant

To determine the effect of increasing pressure of ideal gas, we can use the equation available for ideal gas.

Ideal gas equation state as below:

PV=nRT ⇒ V = nRT/P
Where,
P = Pressure
V = Volume
n = mole
R = Ideal gas constant

T = Temperature

Based on above equation, we can conclude if the pressure increase and the temperature remain constant, the volume of the system will be decreased. Therefore, if the pressure decrease while the temperature remain constant, the volume will be increasing.

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Answer: it is a good conductor of electriciy tht is what wires are made of and it is a good conductor of heat so it will be able to handle the heat from the electricity

Explanation:

Answer:

Iron is a shiny, bright white metal that is soft, malleable, ductile and strong. Its surface is usually discolored by corrosion, since it combines readily with the oxygen of the air in the presence of moisture. In absolutely dry air, it does not rust

Explanation:

I hope it helps

Answer:

Heating the CuSO4. 5H2O crystals causes then to loose the water of crystallisation that is the 5H2O part. It becomes anhydrous copper sulphate. Its colour changes to white from blue.

Answer:

add sulfur trioxide

Explanation:

To produce benzenesulfonic acid from benzene, fuming sulfuric acid and sulfur trioxide are added. Fuming sulfuric acid, also refered to as oleum, is a concentrated solution of dissolved sulfur trioxide in sulfuric acid.

The least reactive metal is lead, since it reacted with none of the salt solutions.

Answer:

did you mean to add or attach a paper to this? We need more info to help

Explanation:

Answer:Mars, earth, Uranus and Jupiter

Explanation:

The pH of the solution after 25.0 mL of KOH has been added to the acid is  10.37.

HCOOH is a weak acid that reacts with KOH (a strong base) to form the HCOO⁻ ion and water:

HCOOH + KOH → HCOO⁻ + H₂O

The balanced chemical equation shows that the stoichiometric ratio of HCOOH to KOH is 1:1, so 25.0 mL of 0.20 M KOH corresponds to the same amount of moles of HCOOH. This means that 25.0 mL of the original 0.35 M HCOOH solution has reacted with the 25.0 mL of 0.20 M KOH solution.

moles of HCOOH remaining = moles of HCOOH initially - moles of KOH added

moles of HCOOH initially = 0.35 mol/L × 0.0250 L = 0.00875 mol

moles of KOH added = 0.20 mol/L × 0.0250 L = 0.00500 mol

moles of HCOOH remaining = 0.00875 mol - 0.00500 mol = 0.00375 mol

The concentration of the remaining HCOOH is:

[ HCOOH ] = moles of HCOOH remaining / volume of solution remaining

= 0.00375 mol / (25.0 mL + 25.0 mL)

= 0.075 M

Now we can use the expression for the dissociation constant of HCOOH to calculate the pH of the solution:

Ka = [ H⁺ ][ HCOO⁻ ] / [ HCOOH ]

We can assume that the HCOO⁻ ion behaves as a weak base and calculate its concentration using the equation:

[ HCOO⁻ ] = Ka / [ HCOOH ]

[ HCOO⁻ ] = (1.77 × 10⁻⁴) / 0.075 ≈ 2.36 × 10⁻³ M

Now we can use the equation for the ionization of water to calculate [ H⁺ ]:

Kw = [ H⁺ ][ OH⁻ ]

1.00 × 10⁻¹⁴ = [ H⁺ ][ 2.36 × 10⁻³ ]

[ H⁺ ] = 4.24 × 10⁻¹¹ M

Therefore, the pH of the solution is:

pH = -log[H⁺] ≈ 10.37

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Answer:

Three main processes control mountain height: lateral support of mountains from tectonic forces, which stops mountains from collapsing under their own weight or pushes them up against gravity; climate-controlled erosion; and isostasy, which keeps mountains afloat on the hot and soft mantle material.

Explanation:

A molecule refers to a basic unit of a substance that is composed of two or more atoms bonded together, while a compound refers to a substance made up of two or more different elements chemically combined in a fixed ratio.

A molecule is a basic unit of a chemical substance that consists of two or more atoms bonded together. It is the smallest particle of a substance that retains the chemical properties of the substance. A molecule can be composed of elements of the same type (such as O2, a molecule of oxygen), or elements of different types (such as H2O, a molecule of water).

A compound, on the other hand, is a substance made up of two or more different elements combined chemically in a fixed ratio. The elements in a compound are combined through chemical bonds, forming a new substance with unique properties that are different from those of the individual elements. In other words, a compound is a type of molecule that is composed of elements from two or more different types.

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Answer:

Measure so that the line you are reading is even with the center of the meniscus. For water and most liquids, this is the bottom of the meniscus. For mercury, take the measurement from the top of the meniscus. In either case, you are measuring based on the center of the meniscus.

Explanation:

By comparing the voltage values of the half-cell reaction of Sn with various metals, we can determine the relative reactivity of these metals. Here are the interactions listed along with their respective voltages:

- Sn + Ag: -1.018V

- Sn + Cu: -0.603V

- Sn + Fe: -0.082V

- Sn + unknown metal: 0.253V

Based on the given information, we can observe the following:

1. Sn + Ag: -1.018V

The voltage of -1.018V indicates that the reaction of Sn with Ag is spontaneous, with Sn acting as the reducing agent and Ag as the oxidizing agent. This suggests that Sn has a higher reactivity than Ag.

2. Sn + Cu: -0.603V

The voltage of -0.603V suggests that the reaction of Sn with Cu is also spontaneous, with Sn acting as the reducing agent and Cu as the oxidizing agent. This implies that Sn has a higher reactivity than Cu.

3. Sn + Fe: -0.082V

  The voltage of -0.082V indicates that the reaction of Sn with Fe is spontaneous, with Sn acting as the reducing agent and Fe as the oxidizing agent. This suggests that Sn has a higher reactivity than Fe.

4. Sn + unknown metal: 0.253V

  The voltage of 0.253V suggests that the reaction of Sn with the unknown metal is not spontaneous. The unknown metal is more reactive than Sn since it acts as the reducing agent, while Sn acts as the oxidizing agent.

In summary, Sn is more reactive than Ag, Cu, and Fe based on their respective voltage values. However, the unknown metal is more reactive than Sn.

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In this question, we have two compounds, ClF and LiCl. The first molecule is a covalent compound, since we will not have donation of electrons but instead the sharing of electrons, but in this case, the difference of the electronegativity will cause this molecule to have Polar covalent bond, which will cause partial charges to occur. LiCl is a molecule in which we have a greater difference in electronegativity, which makes this molecule be an ionic molecule, and not covalent. Since ionic compounds have real charges, the only possible answer will be ClF, since they have partial charges. Letter B

Answer:

Explanation:

The number of atoms of potassium can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.65 × 6.02 × 10²³

We have the final answer as

Hope this helps you

The molecular formula of a hydrocarbon that contains 8 carbon atoms, one ring, and two pi bonds can be determined using basic knowledge of hydrocarbons and molecular formulas.

Hydrocarbons are organic compounds that consist of only hydrogen and carbon atoms. The number of carbon atoms in a hydrocarbon determines the type of hydrocarbon, such as an alkane, alkene, or alkyne. In this case, the hydrocarbon contains 8 carbon atoms, a ring, and two pi bonds. A ring in a hydrocarbon is usually indicative of an aromatic compound, which contains alternating double bonds in a cyclic structure. The presence of two pi bonds suggests that the hydrocarbon is an alkyne. Therefore, the molecular formula for the hydrocarbon is C8H6, as it contains eight carbon atoms and six hydrogen atoms to satisfy the valence requirements of the atoms in the molecule.

The double bonds in the ring structure account for the two pi bonds in the molecule. This molecular formula represents an aromatic alkyne, which is a relatively rare type of hydrocarbon.

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The elements are the present in this mixture is the A and D. The correct option is 1.

The bright line spectrum that is produced by the four elements with the are in the below picture. The bright line spectrum is the spectrum when created is when the beam of the light passes through the sample that is analyte sample that is some of the wavelengths of the light that are absorbed through the atoms with the sample. Thus, the electrons in the atoms will get to the excited state.

Therefore, the bright line spectrum of the mixture formed by the two elements are A and the D. The option 1 is correct.

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On completing and balancing the half-reaction of chromium (iii) forming from dichromate the number of electrons are either produced or consumed  are option (b): Three electrons are produced.

To determine the number of electrons produced or consumed in the half-reaction of chromium(III) forming from dichromate, let's first write the balanced half-reaction. The dichromate ion (Cr2O7^2-) is reduced to chromium(III) ion (Cr^3+) in this reaction. We can represent the reduction half-reaction as follows:

Cr2O7^2- ⟶ Cr^3+

To balance the half-reaction, we need to equalize the number of chromium atoms and oxygen atoms on both sides. Since there are two chromium atoms on the left side and only one on the right side, we add a coefficient of 2 in front of the chromium ion:

2Cr2O7^2- ⟶ 2Cr^3+

Now, let's examine the changes in oxidation state for chromium in this reaction. In dichromate (Cr2O7^2-), chromium has an oxidation state of +6, while in chromium(III) (Cr^3+), it has an oxidation state of +3. Therefore, the oxidation state of chromium decreases by 3 in this reduction half-reaction.

Reduction involves a gain of electrons. Since the oxidation state of chromium decreases by 3, it means that three electrons are gained by each chromium ion. Therefore, the correct answer is option (b): Three electrons are produced.

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Answer:

c. Six electrons are consumed

Explanation:

The first step is to ensure that the chromium atoms are balanced by adjusting the coefficients if needed. Do so by giving the Cr3+ ion a coefficient of 2.

Cr2O2−7 ⟶ 2Cr3+ (aq)

Next, balance the oxygen atoms by adding H2O molecules. The half-reaction has seven O atoms on the left and none on the right, so add 7H2O (l) to the right side.

Cr2O2−7 ⟶ 2Cr3+ (aq) + 7H2O (l)

Next, balance the hydrogen atoms by adding H+ ions. The half-reaction has 14 H atoms on the right side and none on the left, so add 14H+(aq) to the left side.

Cr2O2−7 + 14H+ (aq) ⟶ 2Cr3+ (aq) + 7H2O (l)

At this point, the charge can be balanced by adding electrons (e−). To do so, find the total charge on each side of the reaction. The left side has a total charge of (−2) + 14 × (+1) = 12+. The right side has a total charge of 2 × (+3) = 6+. Adding 6e− to the left side brings the charge down to 6+ to match the right side.

Cr2O2−7 + 14H+ (aq) +6e− ⟶ 2Cr3+ (aq) + 7H2O (l)

This gives us the answer to the question, which is that six electrons are consumed, since they are on the left side of the equation. Note that it does not make a difference whether the reaction is assumed to be in an acidic or a basic solution. The extra step taken for a basic solution is to add the same number of OH− ions to both sides of the reaction, which does not affect the number of electrons needed to balance the charges.

Answer:

Valence electrons are electrons located in the outermost energy level (Responsible for bonding.)

Explanation:

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The maximum mass of sodium chloride that could be produced by the chemical reaction is 1.17 grams.

To determine the maximum mass of sodium chloride that could be produced, we need to find the limiting reactant. The limiting reactant is the reactant that will be completely consumed and determines the maximum amount of product that can be formed.

First, we need to calculate the number of moles for each reactant:

Hydrochloric acid (HCl): 0.73 g

Sodium hydroxide (NaOH): 1.54 g

Using the molar masses:

Molar mass of HCl = 36.46 g/mol

Molar mass of NaOH = 40.00 g/mol

Number of moles of HCl = mass / molar mass = 0.73 g / 36.46 g/mol = 0.020 moles

Number of moles of NaOH = mass / molar mass = 1.54 g / 40.00 g/mol = 0.039 moles

The balanced equation for the reaction is:

2HCl + NaOH → 2NaCl + H2O

From the balanced equation, we can see that the mole ratio between HCl and NaCl is 2:2 or 1:1.

Since we have 0.020 moles of HCl, the maximum amount of NaCl that can be produced is also 0.020 moles.

To calculate the maximum mass of NaCl, we can use the formula:

Mass = moles × molar mass

Mass of NaCl = 0.020 moles × 58.44 g/mol (molar mass of NaCl)

Mass of NaCl = 1.17 g

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The condition of the ideal gas law is that the gas molecules must move in a random fashion.

The condition of the ideal gas law is that the gas molecules must move in a random fashion. This means that the molecules move in a chaotic manner with no set pattern or direction, constantly colliding with each other and the walls of their container.

This assumption is based on the kinetic theory of gases, which assumes that gases are made up of small particles (molecules or atoms) that are in constant motion.

The ideal gas law is a mathematical relationship between the pressure, volume, temperature, and number of particles of a gas. It is based on several assumptions, including that the gas molecules are in constant motion, that they occupy no volume, and that they do not interact with each other except through elastic collisions.

Therefore, if the gas molecules do not move in a random fashion, this assumption would not hold, and the ideal gas law would not accurately describe the behavior of the gas.

The other options, such as the gas molecules interacting with each other or adhering to the container wall, are not conditions of the ideal gas law, but rather factors that can affect the behavior of real gases under certain conditions.

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Answer:

see image

Explanation:

let me know if you have any questions

Calculate [OH-] and pH with [H+] = 2.9 × 10^-10 M:

Using the equation Kw = [H+][OH-], where Kw is the ion product of water:

Kw = [H+][OH-]

1.0 × 10^-14 = (2.9 × 10^-10)[OH-]

[OH-] = (1.0 × 10^-14) / (2.9 × 10^-10)

[OH-] ≈ 3.45 × 10^-5 M

To calculate the pH, we can use the equation:

pH = -log[H+]

pH = -log(2.9 × 10^-10)

pH ≈ 9.54

THEREFORE, the [OH-] is approximately 3.45 × 10^-5 M, and the pH is approximately 9.54.

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The dissociation of a weak acid like benzoic acid in solution is described by the equilibrium expression: \(HA < - > H^+ + A^-\)

where HA represents the undissociated acid, H^+ represents the hydrogen ions, and \(A^-\) represents the conjugate base. The concentration of dissociated acid, [\(H^+\)], can be related to the percent dissociation, %d, as follows:

\(\%d = ( [H^+] / [HA] ) \times 100%\)

If we assume that the dissociation is a small fraction of the initial concentration, then we can assume that \([HA] = [HA]0\), the initial concentration of the acid. This allows us to simplify the expression for %d as follows:

\(\%d = [H^+] / [HA]0 \times 100%\)

We know that the concentration of the \(2.4 \times 10^{-2}\) M solution of benzoic acid is 5.0% dissociated.

To find the concentration of the \(2.4 x 10^{-3}\) M solution,

we can use the relationship between the concentration and the percent dissociation:

\(5.0\% = [H^+] / (2.4 x 10^{-2} \:M) \times 100\%\)

\([H^+] = 5.0\% \times (2.4 x 10^{-2} \:M) / 100\%\)

\([H^+] = 1.2 x 10^{-3} \:M\)

Finally, to find the percent dissociation of the \(2.4 \times 10^{-3}\) M

solution, we use the expression for %d with [HA]0 \(= 2.4 \times 10^{-3}\) M:

\(\%d = [H^+] / [HA]0 \times 100%\\\)

\(\%d = (1.2 \times 10^-3 M) / (2.4 x 10^{-3} \M) \times 100%\\\)

\(\%d = 50.0%\)

Therefore, in a \(2.4 \times 10^{-3}\) M solution of benzoic acid, the percent of dissociation would be 50.0%.

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Note: the correct question would be as bellow,

A 2.4 x 10^-2 solution of benzoic acid is 5.0% dissociated. in a 2.4 x 10^-3 solution the percent of dissociation would be?