homonuclear dianions contain atoms of the same element and an overall charge of . some dianions are stable enough to exist in compounds, while others are unstable and have only been detected in the gas phase. the bond order of the molecular ion b2 2- is

Answer:

D

Explanation:

tissues are used to make organs and depending on the organ certain types of tissue can be used

Using Cahn-Ingold-prelog rules, the substituents that would have the highest priority is a) i

According to the Cahn Ingold Prelog system, priorities are assigned as  1,2,3, or 4 to the atoms directly bonded to the stereo genic center in decreasing order of atomic number. The atom of highest atomic number has the highest priority 1.

A substituent with higher atomic number takes over a substituent with a lower atomic number. Hydrogen is the lowest priority substituent, as it has the lowest atomic number. But for isotopes, the atom with the higher atomic mass gets higher priority.

For assigning the priority, multiple bonds are seen as if each bond of the multiple bond is bonded to an unique atom.

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The pressure of \(N_{2}\) will rise under the given conditions. And, Yes, it is possible to reverse this tendency by adding \(H_{2}\). The minimum pressure of H2 required to reverse the tendency is 0.01 atm.

The reaction involved is: \(N_{2}\)(g) + 3\(H_{2}\)(g) ⇌ 2\(NH_{3}\)(g)  Hence, when \(H_{2}\) is added to the above system, the \(N_{2}\) and  \(H_{2}\)  will react to produce \(NH_{3}\). This reaction will reduce the amount of \(N_{2}\) present in the system, causing the pressure of \(N_{2}\) to decrease. Therefore, by adding \(H_{2}\)  , we can change the tendency of \(N_{2}\) pressure from rise to fall.To calculate the minimum pressure of  \(H_{2}\)  required to reverse the tendency, we have to use the equilibrium constant, Kp. The expression for Kp for the above reaction is: Kp =( \(NH_{3}\)) / p(\(N_{2}\)) p3( \(H_{2}\) )

At equilibrium, Kp = 1.7 × 104 at 1126 °C.Now, we will solve for the minimum pressure of \(H_{2}\)   needed to reverse the tendency. Let's assume that the pressure of \(N_{2}\) has increased by x atm. Therefore, the new pressure of \(N_{2}\) will be (0.0406 + x) atm. At equilibrium, we have:

p2(\(NH_{3}\) ) / p(\(N_{2}\)) p3( \(H_{2}\) ) = 1.7 × 104

On substituting the given values and simplifying, we get:

p2(\(NH_{3}\)) / p(N2) = 6.39 × 10-5

Now, p2(\(NH_{3}\)) = 5.97 atm, and p(\(N_{2}\)) = (0.0406 + x) atm.

On substituting these values, we get:5.97 / (0.0406 + x) = 6.39 × 10-5

Solving for x, we get:x = 0.00579 atm ≈ 0.01 atm (rounded to 2 significant digits)Therefore, the minimum pressure of \(H_{2}\)   required to reverse the tendency is 0.01 atm.

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The statements that correctly describes the graphic representation of the cooling process are ;  ( A, B, C,  D )

As the gas is cooled over time there will be certain reactions observed as the gas begins to cool down and an example of such observation will be the presence of droplets of the gas on the sides of the sealed container at certain temperatures.

As the gas is cooled the kinetic energy of the molecules will continue to decrease causing the intermolecular attraction of the molecules to increase

Hence we can conclude that the statements that correctly describes the graphic representation of the cooling process are the freezing point of the gas is 100°C,  It will take 140 minutes for the gas to completely solidify. Droplets of the gas will begin to condense on the sides of the container at 125°C

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No, spoiling milk is not a chemical change. Spoiling milk is a physical change, which is a change in the state or appearance of a substance without changing its chemical composition.

When milk spoils, it is still composed of the same molecules, but its physical properties (such as taste, smell, and texture) have changed. Spoiling milk is caused by the growth of microorganisms, such as bacteria, which break down milk proteins and fats, causing changes in the milk's appearance, taste, and smell.  In the case of milk, spoiling is the result of the growth of bacteria, which is a physical change.  A physical change is a change in the physical state or appearance of a substance without any change in the chemical composition or identity of the substance.

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The volume of gas in the tank is determined as 1.78 L.

The volume of gas in the tank is calculated by applying idle gas law as follows;

PV = nRT

where;

n = reacting mass / molar mass

n = (300 g) / (3 x 16 g)

n = (300 g) / (48 g/mol)

n = 6.25 moles

The volume of the gas is calculated as follows;

V = nRT/P

V = (6.25 x 8.314 x 214.25)/(6250)

V = 1.78 L

Thus, the volume of ideal gas increases with increase in temperature.

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The total of the oxidation numbers of the one hydrogen and four oxygen atoms in HClO₄ is -7.

Oxidation numbers are numbers assigned to atoms in a chemical compound to be able to determine the atom's charge. All atoms in their elemental form are assigned an oxidation number of zero.

Determine the oxidation number of chlorine (Cl). In molecules, the overall charge on the molecule is zero, so we can use this fact to help us determine the oxidation number of chlorine. HClO₄ is an acidic molecule, which has a -1 charge overall. So we know that the oxidation number of the Cl must be +7 in order for the overall charge to be -1.

Determine the oxidation number of hydrogen (H). Hydrogen typically has an oxidation number of +1. We can double check this by adding up all the oxidation numbers in the molecule and making sure they equal the overall charge of -1.

Determine the oxidation number of oxygen (O). Oxygen typically has an oxidation number of -2. We can double check this by adding up all the oxidation numbers in the molecule and making sure they equal the overall charge of -1.

Therefore, the total of the oxidation numbers of the one hydrogen and four oxygen atoms in HClO₄ is: 1 + (-2 × 4) = -7.

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Part-A

In the liquid form of NH\(_{3}\), hydrogen bonding is the main force.

The main forces in the dispersion forces of CBr4

Dipole-dipole forces are the most common types of forces in CH\(_{3}\)CL.

Part B:

The compounds' boiling points are listed in decreasing order.

NaF > CH\(_{2}\)O > C\(_{2}\)H\(_{2}\) gas (less boiling point)

These are ionic chemicals :. (more boiling point)

A chemical compound is any material that consists of identical molecules having atoms from two or more different chemical elements.

Atoms from more than 100 different chemical elements, both in their pure forms and when mixed to form chemical compounds, make up all matter in the universe.

Only the atoms that are unique to that element are present in a pure element sample, and each element has its own unique atoms. For instance, the atoms that make up carbon differ from those that make up iron, which differ from those that make up gold. Every element has a distinctive symbol that is made up of one, two, or three letters that either come from the element's present name or from its original (typically Latin) name.

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Q) Part A:

What is the predominant intermolecular force in the liquid state of each of these compounds: ammonia (NH3 ), carbon tetrabromide (CBr4 ), and methyl chloride (CH3Cl )?? [options: dipole-dipole forces, hydrogen bonding, or dispersion forces]

Part B:

Rank the following compounds in order of decreasing boiling point: sodium fluoride (NaF ), acetylene (C2H2 ), and formaldehyde (CH2O )

The correct order of the four compounds in increasing Rf values on the TLC plate is: A. chlorobenzene, 1-chloro-4-nitrobenzene, 1-chloro-2,4-dinitrobenzene, 1-chloro-2,6-dinitrobenzene

In thin-layer chromatography (TLC), the Rf value (retention factor) is used to compare the migration of compounds on the plate. The Rf value is influenced by the polarity of the compound and the polarity of the solvent mixture. More polar compounds will have lower Rf values, while less polar compounds will have higher Rf values.

The solvent mixture used in this question is 8:1 hexanes/ethyl acetate, which is relatively non-polar.

1. Chlorobenzene is the least polar compound, as it only has a chlorine atom attached to the benzene ring.
2. 1-chloro-4-nitrobenzene has one nitro group, which increases its polarity compared to chlorobenzene.
3. 1-chloro-2,4-dinitrobenzene has two nitro groups, making it more polar than 1-chloro-4-nitrobenzene.
4. 1-chloro-2,6-dinitrobenzene also has two nitro groups, but the presence of the two nitro groups at the 2,6 positions makes it more polar than 1-chloro-2,4-dinitrobenzene.

As the Rf values increase with decreasing polarity, the correct order is A. chlorobenzene, 1-chloro-4-nitrobenzene, 1-chloro-2,4-dinitrobenzene, 1-chloro-2,6-dinitrobenzene.

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Answer:

1.35 m

Explanation:

We can solve this problem by using the freezing point depression formula:

Where:

We input the data:

And solve for m:

The following solutions has an osmolarity of 4.0 is given as: 2.0 M KBr .

osmolarity = molarity × n ( number of dissociate particles)

a) 0.3 M NaCl

NaCl ----->   Na   + Cl

osmolarity = 0.3 × 2

                  = 0.2 osmol

b) 2.0 M KBr

KBr --->  K  +   Br

osmolarity = 2 × 2

                  = 4 osmol

c) 1.0 M Fe₂O₃

Fe₂O₃   ----->   2Fe³⁺    +    3O²⁻

osmolarity = 1 × 5

                  = 5 osmol

d) 1 M MgCl₂

MgCl₂   ----->   Mg²⁺    +   2Cl⁻

osmolarity = 1 × 3

                  = 3 osmol

e) 1.5  M AlCl₃

AlCl₃    ---->    Al³⁺   +  3Cl⁻

osmolarity = 1.5 × 4

                  = 6

Thus, The following solutions has an osmolarity of 4.0 is as: 2.0 M KBr .

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The textual evidence indicates that the above mission is important because it is relevant and crucial to the exploration of Mars. From the information given, we know that:

Textual evidence is concerned with written facts and the methods employed to determine whether or not the information is true. When an author provides a perspective or thesis and employs evidence to support the assertions, textual evidence is used.

Textual evidence is evidence that has been obtained from the original source or other texts to support an argument or thesis. Such evidence can be obtained in the form of a quotation, paraphrased material, or textual descriptions.

The four types of textual evidence are:

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Answer:

Bones

Explanation:

The name and chemical symbol of the given element whose electronic configurations are shown is:

a. Germanium and its symbol is Ge.

b. Niobium and its symbol is Nb.

The chemical symbol of an element is the symbol that is used to represent the atom of the element usually based on the name o the element.

The name and chemical symbol of the given element whose electronic configurations are shown is determined as follows:

a.) [Ar]4s¹3d¹⁰4p²5p¹

The atomic number of the element is 32

The element whose atomic number is 32 is Germanium and its symbol is Ge.

b.) [Kr]5s²4d²5p¹

The atomic number of the element is 41

The element whose atomic number is 32 is Niobium and its symbol is Nb.

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Answer:

Carbon dioxide molecule

Answer:a , d ,e

Explanation:

jusy took quiz

O-linked oligosaccharides are commonly attached to the —oh group of amino acids.

Glycosylation is a post-translational modification of proteins in which glyco-linked oligosaccharides are added to proteins. This process is found in eukaryotes, primarily in the endoplasmic reticulum and Golgi apparatus, and involves the enzymatic attachment of sugar units to specific sites on a protein molecule.

These short chains of saccharide sugar residues, called glycosyl sidechains, are examples of glycoconjugates which are covalently attached to hydroxyl groups on the protein.

The most common types of glycosylation sites are the N-linked glycosylation sites, which have an attached sugar group, often an N-acetylglucosamine or N-acetylmannosamine connected to an asparagine sidechain, and the O-linked glycosylation sites, which have a sugar group, usually a galactose or mannose sugar, attached to a hydroxyl group on serine, threonine or hydroxylysine residues.

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Answer:

Ionic Compound

Explanation:

1) NaBr

2) CaCl2

3) MgS

4) AlO

5) Li3P

6) Cs3N

7) KI

8) BaF2

9) RbNO2

10) BaO

11) Potassium oxide

12) Magnesium iodide

13) Aluminum chloride

14) Calcium bromide

15) Sodium nitride

16) Lithium fluoride

17) Barium phosphide

18) Dicesium sulfide

19) Strontium fluoride

20) Sodium chloride

Hope this helps!!

Answer:

B

Explanation:

In semiconductors, the band gap is small, allowing some electrons to be promoted at ordinary temperatures, resulting in conductivity of those materials.

In certain materials, such as semiconductors, the band gap is small, enabling some electrons to be promoted from the valence band to the conduction band even at ordinary temperatures. This phenomenon leads to conductivity and various electrical properties of the material.

The band gap refers to the energy difference between the valence band (the highest energy level occupied by electrons in the material's ground state) and the conduction band (the energy level above the valence band where electrons can freely move and conduct electricity). In materials with a small band gap, the energy required to excite electrons from the valence band to the conduction band is relatively low.

At ordinary temperatures, thermal energy is present in the form of heat, causing atoms and electrons to vibrate and gain energy. In materials with a small band gap, this thermal energy can be sufficient to promote some electrons across the band gap and into the conduction band. These promoted electrons become mobile, contributing to the material's conductivity.

This behavior is significant in semiconductor devices, where the ability to control the flow of electrons is essential. By carefully selecting materials with small band gaps, semiconductor devices can exhibit desired electrical characteristics, such as enhanced conductivity, the ability to amplify signals, and the generation of light in light-emitting diodes (LEDs).

In summary, materials with small band gaps allow electrons to be easily promoted to the conduction band at ordinary temperatures, leading to their electrical conductivity and enabling various applications in semiconductor technology.

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Answer:

add a substace devider

Explanation:

i forgot what it was called but there is a chemical that allows the substances to seperste and than you can test the substaces ph and what it is

Explanation and Answer:

When trying to find the mass of a substance from the mass of another substance using a chemical equation we have to follow some steps.

Before starting solving the problem we have to make sure that we have a balanced equation of the reaction. The steps are:

1. Make sure that we are working with a balanced chemical equation.

2. Convert the mass of the given compound to moles using its molar mass.

3. Convert the moles of the given compound into moles of the target compound using their molar ratio. Their molar ratio will be given by the relationship of their coefficients in the equation of the reaction.

4. Convert the moles of the target compound into grams using its molar mass.

Answer:

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Explanation:

Answer:

The question specified 2 moles of potassium chloride. Clearly, there are 2 moles of chloride ions. How many moles of chloride ions in 95.2 g

Explanation:

Protons, Neutrons and Electrons are the three primary subatomic particles that form an atom.

Protons and Neutrons are large particles and are densely compacted into the nucleus of the atom. Protons are electrochemically positive in charge and the Neutrons are electrochemically neutral in charge.

Together the protons and Neutrons make up the mass of the atom.

Electrons are electrochemically negatively charged particles that move random around the nucleus. They have a relatively small mass compared to Protons and Neutrons. They are found in electron clouds that surround the nucleus and their movement and properties provide for the bonding characteristics of each atom.

Answer:

b

Explanation:

Answer: A

Explanation:

Answer:

I think it would be b

Explanation:

pls correct me if im wrong!

The enthalpy change of the reaction of decane would be -6582.3 kJ/mol of decane.

The enthalpy change of a reaction can be calculated using the following equation:

ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)

We are given the standard molar enthalpy of formation of n-decane, C10H22, which is -249.4 kJ/mol.

Using the balanced chemical equation, we can identify the stoichiometric coefficients of the reactants and products:

C10H22(I) + 12.5O2(g) --> 10CO2(g) + 11H2O(g)

Reactants:

n(C10H22) = 1

n(O2) = 12.5

Products:

n(CO2) = 10

n(H2O) = 11

Now we can calculate the enthalpy change of the reaction:

ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)

ΔH = [10(-393.5 kJ/mol) + 11(-241.8 kJ/mol)] - [1(-249.4 kJ/mol) + 12.5(0 kJ/mol)]

ΔH = -6582.3 kJ/mol

The enthalpy change of the reaction is -6582.3 kJ/mol of decane.

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Answer:

You need a balanced equation.

2Fe(s) + 3S(s) ==> Fe2S3(s) ... balanced equation

Reactants are solid iron and solid sulfur

Product is iron(III) sulfide

A. 1.42 moles Fe x 3 moles S/2 moles Fe = 2.13 moles sulfur

B. 2.75 moles S x 2 moles Fe/3 moles S = 1.83 moles iron

Option A: if D was removed, the equilibrium would have shifted towards the product as D lies on the product side of the equation.

An equilibrium may be stressed in a number of ways. One method is to change the reactant or product of a chemical process when it reaches equilibrium. To lessen the stress, adding more product causes the equilibrium to switch to reactants. If a reactant or product is taken away, the equilibrium changes to produce more of the taken away reactant or product, respectively.

The chemical process is no longer at equilibrium when we stress it, and it begins to move back towards equilibrium in a way that reduces the stress. The formal formulation is termed Le Chatelier's principle: If an equilibrium is stressed, then the reaction moves to decrease the stress.

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Correct question is:

For the following reaction, determine which way the equilibrium would shift, toward the products or toward the reactants, given the proposed change. Assume the reaction is endothermic.

A + B → C + D

Part A: If D was removed

Part B: If more B was added to the reaction

Part C: If the reaction was heated