Answer:
Explanation:
1.wrap bar magnet in a plastic baggie and remove the iron filings from the mixture by using a bar magnet. Place a small piece of scrap paper on the scale and “tare” the scale. Then place filings on the scrap paper and record (e) the mass of the iron filings. Don't throw out the iron–save it to be recollected.
2.When sand is added to water it either hangs in the water or forms a layer at the bottom of the container. Sand therefore does not dissolve in water and is insoluble. It is easy to separate sand and water by filtering the mixture. Salt can be separated from a solution through evaporation.
3.Sand (mostly silicon dioxide) is not.
Pour the salt and sand mixture into a pan.
Add water. ...
Heat the water until the salt dissolves. ...
Remove the pan from heat and allow it to cool until it's safe to handle.
Pour the salt water into a separate container.
Now collect the sand.
Pour the salt water back into the empty pan.
Heat the salt water until the water boils. Continue boiling it until the water is gone and you're left with the salt.
Another way you can separate the salt water and sand is to stir up the sand/salt water and pour it through a coffee filter to capture the sand.
Answer:
1. Separating iron from mixture
Provided a magnetmoved the magnet close to the mixtureseparated the magneted iron from the magnet.2. Separating sand from mixture
poured the mixture in a separation funnelfiltered off the sand from the mixture.3. Separating Salt mixture
boild the mixturecontinued heating to drynessthe remimants left behind is the saltFor cardiovascular exercise, it is important to exercise in your:
1. Resting Heart Rate
2. Target Heart Rate
3. Maximum Heart Rate
4. All of the Above
Answer:
4 target heart rate. is the answer
Explanation:
hope its right
The 3.00-cm-long second hand on a watch rotates smoothly.
1.) What is its angular speed?
2.) What is the speed of the tip of the hand?
1.) Its angular speed is 6.28 rad/s.
2.) The speed of the tip of the hand 9.42 cm every second.
The angular speed of the second hand on a watch is calculated as the ratio of the circumference of the circle the hand follows to the total time taken to complete one rotation, typically measured in radians per second. The radius of the circle the second hand moves on is 1.5 cm. So, the circumference of the circle is 2π ×1.5 cm, which gives us 9.42 cm. Thus, the angular speed of the second hand is 6.28 rad/s.
The speed of the tip of the second hand can be calculated as the product of the radius of the circle it moves on and its angular speed. Thus, the speed of the tip of the second hand is equal to 9.42 cm/6.28s or 1.51 cm/s.
To express the answer in Angular Velocity, we would say the tip of the second hand has a rotational speed of 1.51 cm/s at an angular velocity of 6.28 rad/s. This means that the tip of the second hand spins around six times each second and covers a distance of 9.42 cm every second.
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The sum of the relative frequencies for all classes will always equal:
a. 1
b. the number of elements in a data set
c. the number of classes
d. a value between 0 to 1
The total of all classes' relative frequencies will always equal: (a) 1
What is frequencies ?A frequency is a measurement of how frequently a certain value, occurrence, or feature takes place. It is employed in a wide range of disciplines, including science, engineering, mathematics, and statistics. Frequency is often expressed as a number, percentage, or ratio. For example, a frequency chart might show the number of times a particular product was purchased over a certain time period. Frequency can also refer to the number of times a particular wave pattern occurs in a given time period. In physics and engineering, frequency is used to measure the number of cycles per second of a wave or periodic phenomenon. For example, a wave with a frequency of 440 hertz (Hz) has 440 complete cycles per second.
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A car travelling at 3.50 m/s [w] speeds up to 14.8 m/s [w] in 3.17 s. determine the acceleration of the car.
The acceleration of the car is 3.56 m/s².
What is acceleration?Rate of change of velocity with time, both in terms of speed and direction. A point or object going straight ahead is accelerated when it accelerates or decelerates.
Some characteristics of acceleration are-
Acceleration is a vector quantity since it has a both magnitude and a direction. A vector quantity is also velocity. The velocity vector change during a time interval divided by that of the time interval is the definition of acceleration. The limit of both the ratio of the change in speed throughout a given interval of time approaches zero determines the instantaneous acceleration (at the specific time and location) ( Instantaneous rates of change). For instance, acceleration will be stated as metres per second if velocity is represented in meters per second.The formula for acceleration is;
\(\bar{a}=\frac{v-v_{0}}{t}=\frac{\Delta v}{\Delta t}\)
\(\begin{aligned}&\bar{a}=\text { average acceleration } \\&v=\text { final velocity } \\&v_{0}=\text { starting velocity } \\&t=\text { elapsed time }\end{aligned}\)
The starting velocity is 3.50 m/s
The final velocity is 14.8 m/s.
The elapsed time is 3.17 s.
Substitute all the values in the formula of acceleration;
\(\bar{a}=\frac{14.8-3.50}{3.17}\\\bar{a}=3.56\)
Therefore, the acceleration of the car is 3.56 m/s².
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Questions
What is the effect of the following variables on the strength of an electromagnet in terms of:
1. lightness of the wire coiled around the nail?
2. Number of coils of wire around the nail?
3. Number of dry cells used?
4. Size of nail?
Answer:
1. The tightness of the wire has no effect on the strength of the electromagnet
2. The strength increases with the number of coils
3. The strength of the electromagnet increases with the number of dry cells used
4. The strength of the electromagnet increases with the wideness of the nail but not the length of the nail
Explanation:
The strength of an electromagnet is given by the following relation;
\(B = \dfrac{\mu_0 \cdot K \cdot N \cdot I}{L}\)
Where;
B = The magnetic field strength at the center
μ₀ = The magnetic permeability of free space = 4·π × 10⁻⁷ N·A⁻²
N = The number of loops formed by the conductor around the core
I = The current flowing through wire coiled around the nail
K = The magnetic permeability of the nail
L = The length of the coil
Therefore, we have;
1. From the above equation, the tightness of the wire coil around the nail (or the radius, 'R', of the wire) does not does not affect the magnetic field strength
2. The number of coils, 'N', is directly related to the magnetic field strength, 'B', and therefore, increasing the number of turns or coils around the nail, increases the magnetic field strength
3. The current in the circuit is directly related to the magnetic field strength and the number of dry cell used increases the current in the circuit and therefore, can increase the magnetic field strength
4. The size of the nail used in a solenoid and the magnetic field strength are directly related. The wider the nail, the stronger the magnetic field
Suppose a 50.0 g block of silver (specific heat = 0.2350 J/g·°C) at 100.°C is placed in contact with a 50.0 g block of iron (specific heat = 0.4494 J/g·°C) at 0.00°C, and the two blocks are insulated from the rest of the universe. The final temperature of the two blocks will be:
Answer:
34.34 °C
Explanation:
From the question,
Heat lost by the silver block = heat gained by the iron block.
cm(x-y) = c'm'(y-z)................... Equation 1
Where c = specific heat capacity of the silver block, m = mass of the silver block, c' = specific heat capacity of the iron, m' = mass of the iron. x = initial temperature of the silver block, z = initial temperature of the iron, y = final temperature of the mixture.
make y the subject of the equation
y = (cmx+c'm'z)/(cm+c'm')............... Equation 2
Given: c = 50 g, c = 0.2350 J/g·°C, x = 100°C, m' = 50 g, c' = 0.4494 J/g.°C, z = 0°C
Substitute these values into equation 2
y = [(50×0.2350×100)+(50×0.4494×0)]/[(50×0.2350)+(50+0.4494)]
y = 1175/(11.75+22.47)
y = 1175/34.22
y = 34.34 °C
how does metallic bonding result in useful properties of metals
Metallic bonding contributes to characteristic properties such as conductivity, malleability, ductility and others of metal due to their presence.
Metallic bonding is characteristic of metals where electrons and postive charges in metal participate in bonding. It has multiple significance such as it provides electrically conductive nature to the metal. The free delocalized electrons move under the influence of applied voltage giving the property of conductivity.
They are also responsible for thermal conductivity. The metallic bonding can also be attributed to malleability, ductility, strength, toughness and metallic luster.
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A man pulls a refrigerator using 48 N of force. The refrigerator accelerates 0.35 m/s<2. What is the mass of the refrigerator
Answer: 137.14 kg
Explanation: F=ma (Force = mass x acceleration)
So, 48N (newtons) = m×0.35m/s²
N = kg (m/s²)
(48 kg m/s²)÷0.35m/s² = m
137.14 kg
note: answer is to the nearest hundredth because of the .035 m/s²
When you're super tired and you lose energy, what energy are you actually losing?
I said Physics class, but it's really for Science class.
Answer:
it is chemical energy
Explanation:
that is the energy used by our body, so it is the one that we will loose. and the energy that we gain is also chemical energy
a 0.11-kg tin can is resting on top of a 1.7-m high fence post. a 0.0020-kg bullet is fired horizontally at the can. it strikes the can with a speed of 900.0 m/s, passes through it, and emerges with a speed of 720 m/s. when the can hits the ground, how far is it from the fencepost? disregard friction while the can is in contact with the post.
It is 1.93 metres away from the post.
for vertical motion
\(S= u t + \frac{1}{2} g t^{2}\)
S = 0 + \(\frac{1}{2} g t^{2}\)
1.7 = \(\frac{1}{2} 9.8 t^{2}\)
t = 0.589 sec
using law of conservation of momentum, on the horizontal motion
\(m_{bullet} \ v_{bullet i} = m_{bullet} \ v_{bullet f} + m_{tin} \ v_{tin}\)
\(0.0020 = 0.0020 \ 3 \ 720 + 0.11 \ v_{tin}\)
\(v_{tin}\) = 3.273 m/s
S = \(v_{tin} \ t\)
= 3.273 m/s * 0.589 s
= 1.93 m
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You are gardening in the peak of summer, it hasn't rained in a week, and your plants are looking rough. You decide to water the plants for an hour. The next day you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. With what you know from class, please try and explain what is happening to your plants.
In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.
However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.
It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.
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Suppose, in a physics lab experiment, you try to move a box of 5 kg by tying a rope around it across a flat table and pulling the rope at an angle of 30 degree above the horizontal as shown in the figure;
i. If the box is moving at constant speed of 2m/s and the coefficient of friction is 0.40, What is the magnitude of F?
ii If the box is speeding up with constant acceleration of 0.5 m/s2 ,What will be the magnitude of F?
i. The magnitude of F, given that the box is moving at constant speed of 2 m/s is 24.5 N
ii. The magnitude of F, given that the box is moving at constant acceleration of 0.5 m/s² is 2.5 N
i. How do i determine the magnitude of F?We can obtain the magnitude of F when the box is moving at constant speed of 2 m/s can be obtain as follow:
Mass of box (m) = 5 KgAngle (θ) = 30 degreesAcceleration due to gravity (g) = 9.8 m/s² Magnitude of F =?F = mgSineθ
F = 5 × 9.8 × Sine 30
F = 5 × 9.8 × 0.5
Magnitude of F = 24.5 N
ii. How do i determine the magnitude of F?We can obtain the magnitude of F when the box is moving at constant acceleration of 0.5 m/s² can be obtain as follow:
Mass of box (m) = 5 KgAcceleration (a) = 0.5 m/s² Magnitude of F =?F = ma
F = 5 × 0.5
Magnitude of F = 2.5 N
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Can someone help me with this please!!!
Answer:
B. 10 m
Explanation:
f = v/λ = (20 m/s)λ / (5 m) = 4 Hz original frequency
1/2(4 Hz) = 2 Hz half the original frequency
(20 m/s) / λ = 2 Hz
λ = (20 m/s) / (2 Hz) = 10 m
The second wavelength would increase to 10 m
Ratio of dimension of k.e and power
The proportion of kinetic energy to power in dimensions is [T].
The following determines the object's kinetic energy:
E = ½mv²
The mass formula in dimensions is [m] = [M].
The dimensional velocity formula is [v] = [LT-1].
Kinetic energy's dimensional formula is [K] = [ML2T-2].
Power is the amount of work completed each second. It comes from:
P = W / t
[W] = [ML2T-2] is the dimensional formula for work done.
The time dimension formula is [t] = [T].
The dimensionless power equation is [P] = [ML2T-3].
The kinetic energy to power ratio is [K]/[P] = [ML2T-2] / [ML2T-3].
[K] / [P] [T]
Therefore, [T] is the ratio of the dimensions of kinetic energy to power. This is the necessary remedy as a result.
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If the mass of the body is tripled and its velocity becomes doubled, then the linear momentum of the body will
Answer:
don't know I is not am studnt
Here, we are required to determine how the linear momentum of the body changes if the mass of the body is tripled and its velocity becomes doubled.
The linear momentum of the body would increase by a factor of 6.
The linear momentum of a body is the product of its mass and it's linear velocity.
As such, when the mass of the body is trippled i.e ×3
And it's velocity is doubled i.e x2
Consequently, it's linear momentum is increased by a factor of 6 resulting from the multiplication of 3 by 2.
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For both waves on strings and sound waves in tubes,
A. The mode number is independent of the wavelength.
B. A higher mode number means a shorter wavelength.
C. A higher mode number means a longer wavelength.
The correct statement is B.
A higher mode number means a shorter wavelength.
What is Wavelength?
Wavelength is an important characteristic of all types of waves, including electromagnetic waves (such as light and radio waves) and mechanical waves (such as sound waves and water waves). In general, the wavelength of a wave is determined by the source of the wave, the medium through which it travels, and the frequency of the wave.
The correct statement is B. A higher mode number means a shorter wavelength.
In both cases, the mode number refers to the number of segments, or nodes, into which the wave can be divided. The wavelength, on the other hand, refers to the distance between two adjacent peaks or troughs of the wave.
When the mode number increases, the number of segments or nodes in the wave increases, which means that the wavelength must decrease in order to maintain the same frequency of the wave. This is because the total length of the string or tube remains the same, and so the length of each segment must decrease as the number of segments increases. Therefore, a higher mode number corresponds to a shorter wavelength.
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What is main source of solar energy? Write it's reaction. Why is tremendous amount of energy is released from sun?
The main source of solar energy is nuclear fusion.
The equation of the nuclear fusion reaction in the sun is :
H + H → D + β + + ν, where β + represents a positron and ν stands for a neutrino.
There is a tremendous amount of energy released from the sun because nuclear fusion reaction reactions produce a large amount of energy due to a mass defect.
What is nuclear fusion?The Sun and other stars undergo nuclear fusion, which is the merging of two atomic nuclei to create a single, larger nucleus.
Both reactions produce significant quantities of energy, but nuclear fusion produces significantly less radioactive waste and has a much higher energy yield.
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A sample of neon gas (Ne, molar mass M = 20.2 g/mol) at a temperature of 13.0∘C is put into a steel container of mass 47.2 g that’s at a temperature of −40.0∘C. The final temperature is −28.0∘C. (No heat is exchanged with the surroundings, and you can neglect any change in the volume of the container.) What is the mass of the sample of neon?
The mass of the sample of neon gas is equal to the mass of the container, which is 47.2 g.
To solve this problem, we can use the principle of conservation of energy, assuming that no heat is exchanged with the surroundings.
We'll use the equation:
Q_neon + Q_container = 0,
where Q_neon represents the heat gained or lost by the neon gas and Q_container represents the heat gained or lost by the container.
The heat gained or lost by a substance can be calculated using the equation:
Q = mcΔT,
where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Let's calculate the heat gained or lost by the neon gas:
Q_neon = m_neon × c_neon × ΔT_neon,
where m_neon is the mass of the neon gas and c_neon is its specific heat capacity.
We need to assume that the specific heat capacity of neon gas at constant volume is approximately equal to its specific heat capacity at constant pressure.For monatomic gases like neon, the molar specific heat capacity at constant volume (Cv) is (3/2)R, where R is the molar gas constant. The molar specific heat capacity at constant pressure (Cp) is (5/2)R.
Since we have the molar mass of neon, we can calculate the molar gas constant (R) as follows:
R = 8.314 J/(mol·K).
The mass of neon gas can be determined using its molar mass (M) and the number of moles (n):
m_neon = n × M.
The number of moles can be obtained from the ideal gas law:
PV = nRT,
where P is the pressure, V is the volume, T is the temperature, and R is the molar gas constant.
In this case, we are assuming no change in the volume of the container, so the volume factor cancels out. Therefore, we don't need to consider the volume in our calculations.
Now let's calculate the heat gained or lost by the container:
Q_container = m_container × c_container × ΔT_container,
where m_container is the mass of the container and c_container is its specific heat capacity.
Since the final temperature is the same as the initial temperature of the container, ΔT_container is zero, and there is no heat gained or lost by the container.
Returning to the conservation of energy equation:
Q_neon + Q_container = 0,
we have:
Q_neon + 0 = 0,
Q_neon = 0.
Since Q_neon is zero, it means that no heat is gained or lost by the neon gas. This implies that the initial and final temperatures of the neon gas are the same, 13.0°C.
Now, let's calculate the mass of the neon gas:
m_neon = n × M,
where n is the number of moles.
To find the number of moles, we can use the ideal gas law:
PV = nRT,
where P is the pressure and R is the molar gas constant.
Given that no pressure is specified in the problem, we assume that the pressure remains constant. Therefore, the number of moles (n) and the mass of the neon gas (m_neon) remain the same.
In conclusion, the mass of the sample of neon gas is equal to the mass of the container, which is 47.2 g.
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which kind of energy transformation occurs in a gasoline-powered car?
F. Chemical energy is converted into mechanical energy.
G. Mechanical energy is converted into light energy.
H. Light energy is converted into sound energy.
J. sound energy is converted into chemical energy.
Answer:
Chemical energy is converted into mechanical energy
Explanation:
Chemical energy stored in the bonds of hydrocarbons is released as heat which drives the piston in a car to produce circular motion that propels the car.
Which types of changes observe the law of conservation of mass?
A.only changes of state
B.only physical changes
C.only chemical changes
D.physical changes and chemical changes
Answer:
I think it might be umm... b
The correct answer is actually D
Explanation: i got it right on my district assignment! :)
A blackbody has a
surface area of 2.00 m^2.
Find the energy emitted
per minute from this
area if the temperature
is 398 K. Express the
answer in joules. The
Stefan-Boltzmann
constant is 5.67 × 10^-8 W/m^2•K^4
The energy emitted per minute by the blackbody at the given area is 170,724.8 J/min.
Energy emitted per minute
The energy emitted per minute at the given area is calculated as follows;
P = σAT⁴
P = (5.67 x 10⁻⁸) x (2) (398)⁴
P = 2845.41 W = 2845.41 J/s
Convert energy emitted per second to per minutes
P = 2845.41 J/s x (60 s / min) = 170,724.8 J/min
Thus, the energy emitted per minute by the blackbody at the given area is 170,724.8 J/min.
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A baseball is thrown at a 22.5° angle and an initial velocity of 65 m/s. What will be its horizontal
and vertical velocity?
Guys pls someone answer my question I have an exam and this question has 5 marks
Answer:
Horizontal component = 60.05 m/s
vertical component = 22.96 m/s
Explanation:
cosine(angle) = adjacent / hypotenuse or horizontal / angled velocity
angled velocity * cosine (angle) = horizontal velocity
65 m/s * cosine(22.5) = 60.05 m/s
sine(angle) = adjacent/ hypotenuse or vertical/ angled velocity
angled velocity * sine (angle) = vertical velocity
65m/s sine(22.5) = 22.96 m/s
Find the work done by the force field on a particle that moves along the parabola from to.
The work done by the force field on a particle that moves along the parabola is 7/3 + (e²-e)/2
What is work done?The work done is defined as the magnitude of the displacement d multiplied by the force component acting in the direction of the displacement.
Work done = \(\int\limits^0_C {F} \, dr\)
dr = dxi + dyj
Given,
F(x,y) = x²i + yeˣj
Work done = \(\int\limits^0_C\)(x²i + yeˣj)×(dxi + dyj)
= \(\int\limits^0_C\)x²dx + yeˣdy
As, C: x = y² + 1
y = \(\sqrt{x-1}\)
dy = \(\frac{dx}{2\sqrt{x-1} }\)
Now substitute the values of y and dy:
Work done = \(\int\limits^0_C\)x²dx + \(\sqrt{x-1e^{x} }\) × \(\frac{dx}{2\sqrt{x-1} }\)
= \(\int\limits^0_C\)x² + ¹/₂ eˣ dx
Now, work done = \(\int\limits^1_2 {x^{2} }\) + ¹/₂ eˣ dx
= [x³/3 + ¹/₂ eˣ]²₁
= [2³/3 + ¹/₂ e²] - [1³/3 + ¹/₂ e¹]
= 8/3 + ¹/₂ e² - 1/3 + e/2
= 7/3 + (e²-e)/2
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Complete question is as follows:
Find the work done by the force field F(x,y) = x²i + yeˣj on a particle that moves along the parabola x=y²+1 from (1, 0) to (2, 1)
What is the cause of change in properties of matter
Answer:
Chemical changes cause a substance to change into an entirely substance with a new chemical formula.
Explanation:
Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the end results are called products.
describe two forces you experience/observer everday
Answer:
Static friction: Keeps objects from sliding
Kinetic energy: Simply walking
Explanation:
Answer:
Friction and Inertia
Explanation:
Friction - Friction causes a force on a surface which is in the opposite direction to its motion. Example: applying the brakes in a car.
Inertia - An object will stay in motion and an object at rest will stay at rest unless acted upon by an outside force. Example: Why your book stays still on the table if you don't touch it, or why you shoot forward when brakes are applied in a car.
an object with mass m is suspended at rest from a spring with a spring constant of 200 n/m. the length of the spring is 5 cm longer than its unstretched length l, as shown above. a person then exerts a force on the object and stretches the spring an additional 5 cm. what is the total energy stored in the spring at the new stretched length?
The total energy stored in the spring at the new stretched length can be calculated using the formula for the potential energy of a spring, which is 1/2*k*x^2, where k is the spring constant and x is the displacement from the equilibrium position.
In this case, the displacement is 5 cm + 5 cm = 10 cm and the spring constant is 200 N/m. Converting the displacement to meters, we get x = 0.1 m. Therefore, the total energy stored in the spring is 1/2*(200 N/m)*(0.1 m)^2 = 1 J.
Here's the step-by-step explanation:
1. The object is suspended at rest from a spring, causing it to stretch 5 cm longer than its unstretched length. Using Hooke's Law, we can find the force exerted by the spring: F = kx, where F is the force, k is the spring constant (200 N/m), and x is the stretch (5 cm = 0.05 m). So, F = 200 × 0.05 = 10 N.
2. The person exerts an additional force, stretching the spring another 5 cm (0.05 m). The total stretch now is 10 cm (0.1 m).
3. To find the total energy stored in the spring, we can use the formula for the potential energy of a spring: U = (1/2)kx^2. Using the total stretch, x = 0.1 m, and the spring constant, k = 200 N/m, we can calculate the total energy stored: U = (1/2) × 200 × (0.1)^2 = 1 Joule.
The main answer is: The total energy stored in the spring at the new stretched length is 1 Joule.
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On which object will Earth's gravity act with the greatest magnitude? *
An apple
A cereal bowl
A watermelon
A TV remote
Answer: The watermelon
Explanation: The watermelon has a larger mass than the rest of the three.
A car starts with velocity of 3m/s and moves in a straight line with a constant acceleration if the velocity at the end of 5sec is 5.5 m/s find the uniform acceleration and the distance travelled in 10sec
Answer:
\huge{\underline{\underline{.........Answer.........}}}
.........Answer.........
Given:-
u = 0.3 m/s
v = 5.5 m/s
t = 5 seconds
Explanation:-
Case-1
Acceleration = ?
From the first law of motion.
v = u + atv=u+at
a = \frac{v - u}{t}a=
t
v−u
a = \frac{5.5 - 0.3}{5}a=
5
5.5−0.3
a = \frac{5.2}{5}a=
5
5.2
a = 1.04a=1.04
\boxed{\boxed{a = 1.04 m/s^2}}
a=1.04m/s
2
So,the acceleration produced is 1.04 m/s^2.
Case-2
Distance travelled = ?.
From second equation of motion.
s = ut + \frac{1}{2} a {t}^{2}s=ut+
2
1
at
2
s = 0.3 \times 10 + \frac{1}{2} \times1.04 \times 100s=0.3×10+
2
1
×1.04×100
s = 3 + \frac{1}{2} \times 104s=3+
2
1
×104
s = 3 + 52s=3+52
s = 55 \: meterss=55meters
\boxed{\boxed{s = 55 meters}}
s=55meters
So,the distance travelled is 55 meters.
Explanation:
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Answer:i think it’s D
Explanation:
What is the orbital velocity on Venus?