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Unit 6: Balancing Equations and Simple Stoichiometry
6.06: Stoichiometry Practice Worksheet
This worksheet is worth 10 points. For problems 5-7 make sure to show your work using the factor-label method (Please circle or highlight your answers). Also, please round answers to the correct number of significant figures.
Answers
Answer:
Q5. 16.3g
Q6. 18.9g
Q7. 43.3g
Explanation:
Knowledge required to answer the questions:
1. The mass in 1 mole of a chemical substance in grams is equal to the formula mass of the substance
2. The equation: m = n × Mr, where m = mass (in g), n = number of moles (in mol) and Mr = formula mass (i.e. the sum of the atomic mass of all the atoms in the chemical substance)
3. The ratio of moles of each chemical substance in a reaction is according to the balanced equation
Question 5:
HBr + KHCO₃ → H₂O + KBr + CO₂
According to principle 2, find the number of moles of HBr using the given mass and the calculable Mr;
The Mr will be the sum of the atomic mass of each atom in the chemical compound, these atomic masses can be found on the periodic table:
HBr Mr = 1 + 79.9
HBr Mr = 80.9
If m = n × Mr, then n = m/Mr;
n = 30/(80.9)
n = 0.370828183
According to principle 3, and the balanced reaction equation, we can see the ratio of HBr to the CO₂ is 1:1;
In other words, 1 mol of HBr will react with 1 mol of KHCO₃ to produce 1 mol of H₂O, 1 mol of KBr and 1 mol of CO₂;
So, if you start with 30g or 0.37... moles of HBr, this will react with 0.37... moles of KHCO₃ to produce 0.37... moles of H₂O, 0.37... moles of KBr and 0.37... moles of CO₂;
Now, we simply have to use the equation from principle 2 to get the mass;
CO₂ Mr = 12 + 2(16)
Notice how you need to add (2 × 16) since CO₂ has two oxygen atoms
CO₂ Mr = 44
m = 0.37... × 44+
m = 16.3164401 ⇒ 16.3g
If the number of moles of reagents does not match up with the ratio illustrated in the balanced equation, then one will be the limiting reagent and the other or others would be in excess;
Using this principle and the method used previously, you could solve the questions 6 and 7;
I won't explain in full these questions, but will give the answers:
Question 6:
2 NaOH + H₂SO₄ → 2 H₂O + Na₂SO₄
NaOH m = 150
NaOH Mr = 23 + 16 + 1 = 40
m = n * Mr
n = 40/150 = 0.2666..
NaOH : Na₂SO₄
2 : 1
Na₂SO₄ n = 0.26.../2 = 0.1333...
Na₂SO₄ Mr = 2(23) + 32.1 + 4(16) = 142.1
m = 0.1333... * 142.1 = 18.946... ⇒ 18.9g
Question 7:
Pb(SO₄)₂ + 4 LiNO₃ → Pb(NO₃)₄ + 2 Li₂SO₄
Li₂SO₄ m = 350
Li₂SO₄ Mr = 2(6.9) + 32.1 + 4(16) = 109.9
Li₂SO₄ n = 109.9/350 = 0.314
Li₂SO₄ : LiNO₃
2 : 4 simplifies to:
1 : 2
LiNO₃ n = 0.314 × 2 = 0.628
LiNO₃ Mr = 6.9 + 14 + 3(16) = 68.9
LiNO₃ m = 0.628 × 68.9 = 43.2692 ⇒ 43.3g
Related Questions
Express this measurement in scientific notation to 3sf:
0.009543 g
Group of answer choices
.954 x 10^-2 g
9.54 x 10^-3
9.54 x 10^-3 g
9.54 x 10^3 g
Answers
When you have a small number and you are making it bigger, the exponent will be a negative number. You'll need to move the decimal point between the first two numbers after the 0's so in this case, the decimal point will go between the 9 and the 5.
The final answer after rounding will be \(9.54\) × \(10^{-3}\).
which substance can be broken down by a chemical change ?
1) magnesium
2) manganese
3) mercury
4) methanol
Answers
Answer:
Methanol
Explanation:
Methanol is a compound and compounds are pure substances formed by the combination of elements; they can be decomposed by ordinary chemical means. The other answers are incorrect because they are elements and elements consists of only one kind of atom and they cannot be broken down into a simpler type of matter by either physical or chemical means.
if your acetic acid buret was still wet inside with deionized water when you filled it with acetic acid?
Answers
Answer:
The water would act as a base and would produce an undesired product of ethanol (CH3OH) through a dissociation reaction. If doing a titration reaction, it will likely yield inaccurate results.
The degree of contrast between two opposing forces is called______?
Answers
Answer:
polarity
Explanation:
The irreversible isomerization A
B was carried out in a batch reactor and the following concentration time data were obtained:
Time vs Concentration data in a Batch reactor
t 0 3 5 8 10 12 15 7.5
mol/h 4 2.89 2.25 1.45 1.0 0.65 0.25 0.07
Determine the reaction order,
, and the specific reaction a rate constant, k, using any method of your choice.
Answers
The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.
The term "kinetics" refers to the study of reaction rates, which are determined by measuring the concentration of reactants and products as a function of time.Kinetics experiments can be used to determine the reaction rate and order of reaction. A chemical reaction's rate is defined as the change in the concentration of a reactant or product per unit time. The order of a reaction refers to the number of molecules that must react to produce a product. The order of reaction can be determined by measuring the initial rate of the reaction as a function of concentration.Methods for determining the reaction rate order include the initial rate method, the half-life method, and the integrated rate method. The initial rate method determines the reaction order by measuring the initial rate of the reaction at different reactant concentrations. The half-life method determines the reaction order by measuring the time it takes for the reactant concentration to decrease by half.The integrated rate method determines the reaction order by measuring the concentration of the reactant or product at different times.The specific rate constant can be determined by using the Arrhenius equation, which relates the rate constant to the activation energy, temperature, and frequency factor. The frequency factor can be determined by measuring the rate constant at different temperatures.For such more question on polymerization
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Becca is a forensic technician analyzing the fragments of a window. She sees that there is a hole in the window, and that the outside hole is smaller than the inside hole. What might she deduce from this information?
Answers
The observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.
From the observation that the hole in the window is smaller on the outside than on the inside, Becca, as a forensic technician, might deduce the following:
The hole was caused by an impact from the outside: The smaller outside hole suggests that the force that created the hole originated from the outside and exerted more pressure on the window surface facing inward.
The object causing the hole was larger on the inside: The discrepancy in hole sizes implies that the object that struck the window had a larger size or diameter on the inside, and as it penetrated the glass, it compressed or fragmented the glass, resulting in a larger hole on the inside.
The object may have passed through the window: The difference in hole sizes indicates that the object may have penetrated the window, potentially passing through to the inside. This could suggest a break-in or an incident involving the window being struck from the outside.
Overall, the observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.
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Explain why the electron configuration of 2-3-1 represents an atom in an excited state.
Answers
Answer:
The excited state electron configuration of an atom indicates the promotion of a valence electron to a higher energy state.
Can somebody please help me understand this? I don't understand what I need to do to solve any of the parts.
Answers
This technique has been used to identify the presence of gases such as oxygen, methane, and carbon dioxide in the atmospheres of exoplanets.
i) To estimate the frequency of the violet (leftmost) emission, we can use the equation v = c/λ, where v is frequency, c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the emission in meters. The wavelength of the violet emission is 400 nm or 400 x 10^-9 m, so the frequency can be calculated as v = (3.00 x 10^8 m/s) / (400 x 10^-9 m) = 7.50 x 10^14 Hz.
ii) To estimate the energy of the violet emission, we can use the equation E = hv, where E is energy, h is Planck's constant (6.63 x 10^-34 Js), and v is frequency in Hz. Substituting the frequency calculated in part (i), we get E = (6.63 x 10^-34 Js) x (7.50 x 10^14 Hz) = 4.97 x 10^-19 J.
b. The spectral lines are produced by the electrons within the atoms of this element, which can absorb or emit specific amounts of energy to move between different energy levels. These energy transitions result in the emission or absorption of photons with specific wavelengths and frequencies, giving rise to the observed emission spectrum.
c. The violet emission line represents the photon with the most energy since it has the shortest wavelength (400 nm) and highest frequency (7.50 x 10^14 Hz) among the lines shown. This highest energy does not necessarily represent the energy of the valence electrons, but rather corresponds to the specific energy transitions occurring within the atoms of the element.
d. Emission spectra can be used to determine the gases present in the atmosphere of a far-away planet by analyzing the specific wavelengths of the emitted or absorbed light from the planet. Each gas has a unique emission or absorption spectrum, allowing scientists to identify the gases present in the planet's atmosphere.
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class material don't interact please
Answers
A 0.00143 M concentration of MnO4^- is not a reasonable solution .
Number of moles of carbonateThe ions left in solution are Na^+ and NO3^-
Number of moles of calcium nitrate = 100/1000 L × 1 = 0.1 moles
Since;
1 mole of sodium carbonate reacts with 1 mole of calcium nitrate then 0.1 moles of sodium carbonate were used.
Conductivity of filtrateThe claim of the student that the concentration of sodium carbonate is too low is wrong because the value was calculated from concentration and volume of calcium nitrate and not using the precipitate. If the filtrate is tested for conductivity, it will be found to conduct electricity because it contains sodium and NO3 ions.
2) In the reaction as shown, the MnO4^- ion was reduced.
The initial volume is 3.4 mL while the final volume is 29.6 mL.
Number of moles of MnO4^- ion = (29.6 mL - 3.4 mL)/1000 × 0.0235 M = 0.0006157 moles
The calculations are performed as followsIf 2 moles of MnO4^- reacted with 5 moles of acid0.0006157 moles of MnO4^- reacted with 0.0006157 moles × 5 moles/ 2 moles
= 0.0015 moles
In this case, number of moles of acid = 0.139 g/90 g/mol = 0.0015 molesNumber of moles of MnO4^- = 0.00143 M × (29.6 mL - 3.4 mL)/1000
= 0.000037 moles
If 2 moles of MnO4^- reacts with 5 moles of acid0.000037 moles of MnO4^- reacts with 0.000037 moles × 5 moles/ 2 moles
= 0.000093 moles
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select two correct answers
Answers
Answer:
D and E
Explanation:
The other answers don't support steel, they support iron or are supporting both, and the question is why steel alloys are more often used
C supports both
B supports how iron's strength
A supports iron being easily shaped and bent
hope this helps
Which is one way that spring tides are different from regular tides?
Answers
Answer:
high tides are a little higher and low tides are a little lower than average
Explanation:
A spring tide is the highest tide (when the greatest difference between the high and low tides). This happens during the new and full moon.
Answer: It's worth noting that low tides can sometimes be lower than usual, which is referred to as spring tides. Despite its name, this phenomenon isn't related to spring and has a different historical origin.
How far will you travel in 180 seconds running at a rate of 6 m/s?
Answers
Answer:
1080 meters.
Explanation:
I need help figuring it out the answers were wrong I put in
Answers
PLZZZ HELP
Which property of an object can change depending on the object’s location in the solar system?
O mass
O weight
O electricity
O density
Answers
Answer: (give brainliest)
( )weight
Explanation:
You would have the same mass on Mars or Jupiter as you do here on Earth. Your weight is different on other planets due to gravity. However, your mass is the same everywhere!
Answer:
Density
Explanation:
C. In what orbital is an electron located that has quantum numbers of: n = 5, 1= 0, m₁ = 0, ms=-1? (1
point)
Answers
The electron is in the 5s orbital.
What is an orbital?The term orbital is the region in space where there is a high probability of finding an electron. There are four quantum numbers that define an orbital and these are;
Principal quantum number
Orbital quantum number
Spin quantum number
Magnetic quantum number
Let us now look at the sets of quantum numbers as given, a look at the principal and the orbital quantum numbers (m and l) tell us that the electron is in the 5s orbital.
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true/false. label the functional groups in the molecule. you are currently in a labeling module. turn off browse mode or quick nav, tab to items, space or enter to pick up, tab to move, space or enter to drop.a molecule is composed of several functional groups.
Answers
The statement is true that a molecule is composed of several functional groups.
What is molecules?A molecule is a group of two or more atoms held together by chemical bonds. Atoms can form chemical bonds by sharing electrons with other atoms, leading to the formation of stable molecules with unique chemical and physical properties. Molecules can be made up of atoms of the same element or different elements, and they can vary widely in size and complexity. In biology, many important molecules are made up of carbon, hydrogen, oxygen, nitrogen, and other elements, and they play critical roles in biological processes such as metabolism, cellular signaling, and genetic information storage and transmission. Examples of important biological molecules include DNA, RNA, proteins, carbohydrates, lipids, and many others. These molecules are responsible for carrying out the various functions of cells and organisms and are critical for life as we know it.
Here,
Many molecules in biology are composed of several functional groups, which are specific atoms or groups of atoms within the molecule that give it its chemical properties and reactivity. Examples of common functional groups in biological molecules include amino (-NH2), carboxyl (-COOH), hydroxyl (-OH), phosphate (-PO4), and methyl (-CH3) groups, among others. The presence of these functional groups can determine how a molecule interacts with other molecules in the cell and can influence its function and activity.
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What is the freezing point, in °C,
of a 0.520 m aqueous
solution of NaCl?
Answers
Answer: The freezing point of a solution is the temperature at which the solution becomes a solid. The freezing point of a solution is lower than the freezing point of the pure solvent because the solute particles interfere with the movement of the solvent molecules, which slows down the freezing process.
To determine the freezing point of a solution, we can use the freezing point depression equation:
ΔTf = Kf x molality
where ΔTf is the change in freezing point, Kf is the freezing point depression constant for the solvent, and molality is the concentration of the solute in the solution expressed in moles of solute per kilogram of solvent.
To find the freezing point of a 0.520 m aqueous solution of NaCl (sodium chloride), we need to know the freezing point depression constant for water, which is 1.86 °C/m. We can then use the equation above to calculate the change in freezing point:
ΔTf = 1.86 °C/m x 0.520 m = 0.97 °C
To find the freezing point of the solution, we need to subtract the change in freezing point from the freezing point of the pure solvent. The freezing point of pure water is 0 °C, so the freezing point of the 0.520 m aqueous solution of NaCl is:
0 °C - 0.97 °C = -0.97 °C
Answer:
-1.934
Explanation:
0 - {(0.520) x (1.86) x (2)}
7. A human's appendix, wisdom teeth, and a dew claw are
examples of a(n)
A. Analogous Structures
B. Homologous Structures
C. Vestigial Structures
D. Fossils
Answers
Answer:
Vestigial Structures
Explanation:
Structures that were needed for an organism's ancestor, but no longer required for survival for the current organism. We needed our wisdom teeth and appendix in order to eat tougher foods, but now we do not need those to survive. But, we still have them.
100.0 g CO2 reacts with 100.0 g H2O according to the equation below.
6CO2 + 6H2O -> 6O2 + C6H12O6
How many grams of glucose, C6H12O6 form from the 100.0 g H2O
[ ? ] g C6H12O
Answers
The mass of glucose produced from 100.0 g H2O is 166.8 g C6H12O6.
Given:100.0 g CO2 reacts with 100.0 g H2O according to the equation below.
6CO2 + 6H2O → 6O2 + C6H12O6
How many grams of glucose, C6H12O6 form from the 100.0 g H2O
According to the reaction, 6 moles of water react with 6 moles of carbon dioxide to produce one mole of glucose and 6 moles of oxygen.
Balanced Chemical Equation:
6CO2 + 6H2O → 6O2 + C6H12O6
We have given the mass of H2O, so first, we will calculate the number of moles of H2O.
Number of moles of H2O:
Mass of H2O = 100.0 g
Molar mass of H2O = 18 g/mol
Number of moles of H2O = Mass/Molar mass
= 100.0 g/18 g/mol
= 5.56 moles
Now, we know that 6 moles of water react with 1 mole of glucose.
So, the number of moles of glucose produced:Number of moles of glucose:
6 moles H2O → 1 mole glucose5.56 moles H2O → (1/6) x 5.56 = 0.9267 moles glucose
Now we will calculate the mass of glucose from the number of moles of glucose.
Mass of glucose:Number of moles of glucose = 0.9267 moles
Molar mass of glucose = 180.2 g/mol (C6H12O6)
Mass of glucose = number of moles x Molar mass
= 0.9267 moles x 180.2 g/mol
= 166.8 g
Therefore, the mass of glucose produced from 100.0 g H2O is 166.8 g C6H12O6.
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A non polar covalent bond (pure covalent) would form in which of the following pairs of atoms?
A.) H-Cl
B.) Se-Br
C.) Na-Cl
D.) Br-Br
Answers
Which atom has the larger atomic radius Ga or B
Answers
Answer:
Ga
Explanation:
wich statement describes one way that RNA differs from DNA?
Answers
Answer:
They contain different five-carbon sugars and a different nitrogenous base.
What happens to the sun's energy as it travels to Earth's atmosphere?
A. Some of it is destroyed in Earth's atmosphere.
B. It is completely trapped by Earth's surface.
C. It is all reflected back into space.
D. Some of it reaches Earth's surface.
Answers
Explanation:
Some of it is destroyed in Earth's atmosphere.
B. It is completely trapped by Earth's surface.
C. It is all reflected back into space.
Answer: A
When the sun gives out light, some of the light can be destroyed in the atmosphere, by turning into ozone. The answer is A.
What type of reaction is this?
Answers
Cu + O2 ---> CuO2 -The first reaction is a combustion reaction
2 HCl + Mg → H2 + MgCl2- The second reaction is a Single replacement reaction
What is a combustion reaction?A combustion reaction is a type of chemical reaction that occurs between a fuel and an oxidizer in the presence of heat or light, resulting in the release of energy in the form of heat and light.
In other words, it is a reaction in which a substance reacts with oxygen to produce heat and light.
Combustion reactions are important in many aspects of daily life, including the burning of fossil fuels for energy production, the combustion of wood or other materials for heating or cooking, and the combustion of fuels in internal combustion engines.
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How did modern scientists experiment with Van Goghs paints to determine their chemical reactions?
Answers
Answer:
the would test random expirements
When an aqueous solution of Barium chloride (BaCl2) reacts with an aqueous solution of silver nitrate (AgNO3), a white precipitate of silver chloride and an aqueous solution of barium nitrate is formed. Write the molecular, complete ionic and net ionic equations for this reaction.
Answers
Answer:
1. Molecular equation
BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)
2. Complete Ionic equation
Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)
3. Net ionic equation
Cl¯(aq) + Ag⁺(aq) —> AgCl(s)
Explanation:
1. Molecular equation:
BaCl2(aq) + AgNO3(aq) –> AgCl(s) + Ba(NO3)2 (aq)
The above equation can be balance as follow:
There are 2 atoms of Cl on the left side and 1 atom on the right side. It can be balance by putting 2 in front of AgCl as shown below:
BaCl2(aq) + AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)
There are 2 atoms of Ag on the right side and 1 atom on the left side. It can be balance by putting 2 in front of AgNO3 as shown below:
BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)
Now, the equation is balanced
2. Complete ionic equation
In solution, BaCl2 and AgNO3 will dissociate as follow:
BaCl2(aq) —> Ba²⁺(aq) + 2Cl¯(aq)
AgNO3(aq) —> Ag⁺(aq) + NO3¯ (aq)
BaCl2(aq) + AgNO3(aq) –>
Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯
3. Net ionic equation
Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)
Cancel out the spectator ions i.e ions that appears on both side of the equation in order to get the net ionic equation. This is illustrated below:
2Cl¯(aq) + 2Ag⁺(aq) —> 2AgCl(s)
Cl¯(aq) + Ag⁺(aq) —> AgCl(s)
1. Molecular equation: \(BaCl_2(aq) + 2 AgNO_3(aq) \rightarrow 2 AgCl(s) + Ba(NO_3)_2(aq)\)
2. Complete Ionic equation:\(Ba^{2+} (aq)+ 2Cl^- (aq) + 2 Ag^+ (aq) + 2NO_3^-(aq) \rightarrow2AgCl(s) + Ba^{2+}(aq) + 2 NO_3^-(aq)\)3. Net ionic equation: \(Cl^- (aq) + Ag^+ (aq) \rightarrow AgCl(s)\)
1. Molecular equation:
\(BaCl_2(aq) + AgNO_3(aq) \rightarrow AgCl(s) + Ba(NO_3)_2(aq)\)
There are two Cl atoms on the left side and one on the right. Balance can be achieved by adding 2 in front of AgCl, as seen below:
\(BaCl_2(aq) + 2AgNO_3(aq) \rightarrow AgCl(s) + Ba(NO_3)_2(aq)\)
There are two Ag atoms on the right side and one on the left. It is possible to achieve equilibrium by adding 2 in front of \(AgNO_3\), as demonstrated below:
\(BaCl_2(aq) + 2 AgNO_3(aq) \rightarrow 2 AgCl(s) + Ba(NO_3)_2(aq)\)
2. Complete ionic equation
\(BaCl_2\) and \(AgNO_3\) will dissociate in solution as follows:
\(BaCl_2(aq) \rightarrow Ba^{2+}(aq) + 2Cl^-(aq)\)
\(AgNO_3(aq) \rightarrow Ag^+ (aq) + NO_3^-(aq)\)
\(Ba^{2+} (aq)+ 2Cl^- (aq) + 2 Ag^+ (aq) + 2NO_3^-(aq) \rightarrow2AgCl(s) + Ba^{2+}(aq) + 2 NO_3^-(aq)\)
3. Net ionic equation
To obtain the net ionic equation, cancel out the spectator ions, which are ions that appear on both sides of the equation. As an example, consider the following:
\(2Cl^-(aq) + 2Ag^+(aq) \rightarrow 2AgCl(s)\)
\(Cl^-(aq) + Ag^+(aq) \rightarrow AgCl(s)\)
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At STP, how many moles are in the given
volumes of the following gases?
a. 67.2 L SO₂
b. 0.880 L He
c. 1.00 x 103 L C₂H6
Answers
Answer:
a. Using the Ideal Gas Law, PV = nRT, we can rearrange it to get n = PV/RT. At STP, T = 273 K and P = 1 atm. The molar volume of any gas at STP is 22.4 L/mol. Therefore, for SO₂:
n = (1 atm)(67.2 L)/(0.0821 L·atm/mol·K)(273 K)
n = 2.60 mol
b. Again using the Ideal Gas Law, we get:
n = (1 atm)(0.880 L)/(0.0821 L·atm/mol·K)(273 K)
n = 0.0355 mol
c. Following the same procedure:
n = (1 atm)(1.00 x 10³ L)/(0.0821 L·atm/mol·K)(273 K)
n = 40.9 mol
For the decomposition of ammonia on a platinum surface at 856 °C
2 NH3(g)N2(g) + 3 H2(g)
the average rate of disappearance of NH3 over the time period from t = 0 s to t = 5.48×103 s is found to be 1.50×10-6 M s-1.
What is the average rate of appearance of H2 over the same time period?
M s-1.
Answers
\(\\ \tt\leadsto \dfrac{d[NH_3]}{dt}=1.50\times 10^{-6}\)
dt remains same for reaction\(\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}\dfrac{d[NH_3]}{dt}\)
\(\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}(1.5\times 10^{-6})\)
\(\\ \tt\leadsto \dfrac{d[H_2]}{dt}=2.25\times 10^{-6}Ms^{-1}\)
M is molarity here not metre
The average rate of appearance of H2 over the time period from t = 0 s to \(\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}\) M/s.
To find the average rate of appearance of \(\rm H_2\), we can use the stoichiometry of the reaction to relate it to the rate of disappearance of \(\rm NH_3\).
From the balanced equation: \(\rm 2NH_3(g) - > N_2(g) + 3 H_2(g)\)
We can see that for every 2 moles of \(\rm NH_3\) that disappear, 3 moles of \(\rm H_2\) appear.
Given that the average rate of disappearance of \(\rm NH_3\ is\ 1.50\times10^{-6} M/s\), we can calculate the average rate of appearance of \(\rm H_2\) as follows:
Average rate of appearance of \(\rm H_2\) = (3/2) x (Average rate of disappearance of \(\rm NH_3\))
Average rate of appearance of \(\rm H_2\) = (3/2) x \(\rm (1.50\times10^{-6} M/s)\)
Average rate of appearance of \(\rm H_2\) = \(\rm 2.25\times10^{-6} M/s\)
Therefore, the average rate of appearance of \(\rm H_2\) over the time period from t = 0 s to \(\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}\) M/s.
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7. What is the volume of the
composite
solid?
4 in.
3 in.
3 in.
Answers
Answer:
The volume of Component 1 is 36 cubic inches.
Explanation:
To calculate the volume of a composite solid, we need to determine the individual volumes of the different components and then add them together.
In this case, the composite solid consists of multiple components with the following dimensions:
Component 1:
Length: 4 inches
Width: 3 inches
Height: 3 inches
To find the volume of Component 1, we multiply the length, width, and height together:
Volume of Component 1 = Length x Width x Height = 4 in x 3 in x 3 in = 36 cubic inches
Therefore, the volume of Component 1 is 36 cubic inches.
Please provide the dimensions of the remaining components of the composite solid, and I will calculate the total volume by summing up the individual volumes.
What type of bonding would be expected in argon?
Answers
Answer:
Argon is a member of the noble gas family of elements. This means that it already has eight valence electrons in its outermost shell. Because of this, Ar rarely bonds with other atoms to form compounds
Explanation: