HELP PLS MARKING BRANLIST 100 Pts TAKING TEST RN


A shopping cart is going 2.0 m/s and comes to a complete stop after 4 seconds. What was the cart's acceleration?

8 m/s2

-0.5 m/s2

0.5 m/s2

-8 m/s2

Answer:

it's friction

Explanation:

100% sure about that

Answer:

c: long and thin resistor.

Explanation:

The resistance of a resistor is given by:

R = ρ*L/A

where:

R = resistance

ρ = resistivity (depends on the material)

L =  length of the material

A = cross-sectional area of the material

We can see that the length is on the numerator, which means that if we increase the length, then the resistance is increased.

We also can see that the cross-sectional area is on the denominator, then if we increase the area (for example, with a ticker resistor) the resistance decreases.

Then if we want to maximize the resistance, we need to have a long and thin resistor, so the correct answer is c.

1. The height of the image is 0.287 m.

2. The wavelength of the light is 563 nm.

1. The image distance, denoted as `i`, is determined by the lens formula: `1/f = 1/o + 1/i`, where `f` represents the focal length, `o` is the object distance, and `i` represents the image distance. Given `f = 28.3 cm` and `o = 1.78 m`, we need to convert the object distance from meters to centimeters: `o = 1.78 m = 178 cm`. Therefore, the image distance is calculated as follows:

i = (1/f - 1/o)^-1 = (1/28.3 - 1/178)^-1 = 24.53 cm.

The image height, denoted as `h'`, can be determined using the object height `h` and the magnification `m` relationship: `h' = m * h`. The magnification `m` is given by `m = -i/o`, where the negative sign indicates an inverted image. Thus,

m = -i/o = -(24.53 cm)/(178 cm) = -0.138.

The image height `h'` is obtained by multiplying `h` by `m`: `h' = m * h`, where `h = 2.08 m`. Therefore,

h' = (-0.138) * 2.08 = -0.287 m.

The negative sign signifies an inverted image. Hence, the height of the image is determined as `0.287 m`, and it is inverted.

2. Bright fringes are observed at angles `theta` satisfying the condition `d sin theta = m lambda`, where `d` represents the spacing between two slits, `m` is an integer indicating the fringe order, and `lambda` denotes the wavelength of light. In this case, given `d = 1/20 mm` and `m = 1`, the angle `theta` corresponding to the first bright fringe is given by `tan theta = x/L`, where `x` represents the separation between two fringes, and `L` is the distance from the grating to the screen. With `x = 27.2 mm` and `L = 2.41 m`, we can calculate:

tan theta = (27.2 mm)/(2.41 m) = 0.01126.

Therefore, `sin theta = tan theta = 0.01126`.

Consequently, the wavelength `lambda` is determined using the formula `lambda = d sin theta / m`, where `d = 1/20 x 10^-3 m`, `sin theta = 0.01126`, and `m = 1`:

lambda = (1/20 x 10^-3 m) x 0.01126 / 1 = 5.63 x 10^-7 m = 563 nm.

In summary:

1. The height of the image is 0.287 m.

2. The wavelength of the light is 563 nm.

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Answer:

the distance is 0.6 km

Explanation:

The computation of the distance is shown below:

As we know that

Distance = Speed × time

where

Speed = 72 km/h

And, the time is 30 seconds

So, the distance is

= 72 × 30

= 0.6 km

Hence, the distance is 0.6 km

Answer:

balanced forces external forces

Explanation:

A body that is under a network of balanced external forces will experience no resultant force at all, since all the forces cancel themselves out. A body that is moving with this type of force will  experience no acceleration, since there is no force acting on them. This lack of acceleration means that the body maintains a constant velocity if it is already in motion, or zero when the body is at rest.

Answer:

B. 2.45 Newtons

Explanation:

This is a tension force problem with only tension and the weight force acting on the object. Using Newton's second law F=ma, and there being no acceleration in the system, T-w=0. Using this, T=w. w=mg, therefore (.250kg)(9.8m/s^2) = 2.45 Newtons

Answer:

See image

Explanation:

Plato

Answer:

C

Explanation:

C should be the right answer

Answer: In the Newton's ring experiment, the diameter of the 4th dark ring is 0.30 cm and the diameter of the 10th dark ring is 0.62 cm. We can use this information to find the diameter of the 15th dark ring and calculate the wavelength of the light.

Explanation:

In the Newton's ring experiment, the diameter of the 4th dark ring is 0.30 cm and the diameter of the 10th dark ring is 0.62 cm. We can use this information to find the diameter of the 15th dark ring and calculate the wavelength of the light.

a) To find the diameter of the 15th dark ring, we can use the formula for the diameter of the nth dark ring:

d_n = sqrt(n * λ * R)

where d_n is the diameter of the nth dark ring, n is the order of the ring, λ is the wavelength of the light, and R is the radius of curvature of the lens.

Since we want to find the diameter of the 15th dark ring, we can substitute n = 15 into the formula and solve for d_15:

d_15 = sqrt(15 * λ * R)

b) To calculate the wavelength of the light, we can use the formula:

λ = (\(d_10^2 - d_4^2\)) / (\(10^2 - 4^2\))

where d_10 is the diameter of the 10th dark ring and d_4 is the diameter of the 4th dark ring.

Substituting the given values, we have:

λ = (\(0.62^2 - 0.30^2\)) / (\(10^2 - 4^2\))

Simplifying this expression will give us the value of the wavelength of the light used in the experiment.

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The reason why you can't measure the focal length of a diverging lens directly is that the diverging lens spreads out the light rays that pass through it, causing them to diverge away from each other. This means that the light does not converge to a single point after passing through the lens, as it would with a converging lens. Therefore, it is difficult to determine the exact point at which the light rays converge, which is necessary to measure the focal length directly.

However, you can use a converging lens to measure the focal length of a diverging lens. By placing the diverging lens a certain distance away from the converging lens, you can form an image of a distant object. By measuring the distance between the lenses and the position of the image, you can calculate the focal length of the diverging lens using the thin lens equation.

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Answer:

\(\displaystyle 2\, \pi\, \sqrt{\frac{R^{3}}{G\m M}}\), where \(R\) is the orbital radius, \(M\) is the mass of the Moon, and \(G\) is the gravitational constant.

Explanation:

Let \(m\) denote the mass of the satellite. Let \(R\) denote the orbital radius, let \(M\) denote the mass of the Moon, and let \(G\) denote the gravitational constant.

The Moon would exert the following gravitational attraction on the satellite:

\(\displaystyle \frac{G\, M\, m}{R^{2}}\).

Let \(\omega\) denote the angular velocity of the satellite. For the satellite to stay in this orbit of radius \(R\), the net force on the satellite needs to be:

\(m\, \omega^{2}\, R\).

Since the gravitational force is the only force on this satellite, the net force on the satellite would be equal to the gravitational force:

\(\displaystyle m\, \omega^{2}\, R = \frac{G\, M\, m}{R^{2}}\).

Rearrange this equation to find the angular velocity:

\(\displaystyle \omega^{2} = \frac{G\, M}{R^{3}}\).

\(\displaystyle \omega = \sqrt{\frac{G\, M}{R^{3}}}\).

Note that with the Moon as the center, a full revolution around the Moon would take an angular distance of \(2\, \pi\). Divide the angular distance by the angular velocity to find the time required for this revolution:

\(\begin{aligned}T &= \frac{2\, \pi }{\omega} && \genfrac{}{}{0}{}{\text{angular displacement}}{\text{angular velocity}} \\ &= 2\, \pi \, \sqrt{\frac{R^{3}}{G\, M}}\end{aligned}\).

The electric field strength of the microwave signal received back at the airport, 200 μs later, can be calculated using the radar equation. Given the transmitted power, the cross-section of the airplane, and the distance, we can determine the received power and then calculate the electric field strength using the appropriate formula.

The radar equation relates the transmitted power, the cross-section of the target, the distance, and the received power. The received power can be calculated as the product of the transmitted power and the radar cross-section divided by the distance squared. In this case, the transmitted power is 150 kW, the cross-section of the airplane is 30 m², and the distance is 30 km (converted to 30,000 m). By substituting these values into the radar equation, we can determine the received power. Next, we can calculate the electric field strength using the formula E = sqrt(2 * P / (c * ε₀ * A)), where P is the received power, c is the speed of light, ε₀ is the vacuum permittivity, and A is the effective aperture of the receiving antenna. Given the time delay of 200 μs, we can convert the electric field strength to the desired unit of μV/m.

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Answer:

you are going 1 mile per hour depending on how fast

Explanation:

The average force on the puck by the stick is 448 N

To find the average force on the hockey puck, we can use the impulse-momentum theorem:

Impulse = Change in momentum

The impulse on the puck can be calculated as:

Impulse = mass x change in velocity
Impulse = 0.16 kg x (9 m/s - (-5 m/s))
Impulse = 0.16 kg x 14 m/s
Impulse = 2.24 N*s

The change in velocity is negative because the puck is moving in the opposite direction after the impact.

The impulse on the puck is equal to the average force multiplied by the time of contact:

Impulse = average force x time
2.24 N*s = average force x 0.005 s
average force = 2.24 N*s / 0.005 s
average force = 448 N

Therefore, the average force is 448 N.

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The resistivity of a wire does not change when its diameter and length are split in half, as long as the material and temperature remain constant

The resistivity of a material, denoted by the symbol rho (ρ), is an intrinsic property of the material that describes how well it resists the flow of electric current. It is defined as the ratio of the electric field applied to a material to the resulting current density.

The resistivity of a material is not affected by its size or shape, but it can be affected by its temperature, impurities, and other factors. Therefore, if we split the diameter and length of a wire in half, but keep the material and temperature constant, the resistivity will remain the same.

This can be understood by considering the formula for the resistance of a wire:

R = (ρ * L) / A

where R is the resistance, ρ is the resistivity, L is the length of the wire, and A is the cross-sectional area of the wire.

If we split the diameter and length of the wire in half, the cross-sectional area A is reduced by a factor of 4, and the length L is reduced by a factor of 2. Therefore, the resistance will be halved as well, but the resistivity will remain the same.

.

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The resistance of a circuit that contains two 50.0 Ω resistors connected in series with a 12.0 V battery is 100 Ω. The resistance of the circuit is equal to the sum of the individual resistors when they are connected in series.

In this case, two 50.0 Ω resistors are connected in series, resulting in a total resistance of 100 Ω. Resistance can be defined as the obstruction that electricity faces when it travels through a conductor. The greater the resistance, the less current is allowed to flow through the circuit. The following equation is used to calculate resistance: R = V / IWhere R is resistance, V is voltage, and I is current.

Resistance can also be calculated using Ohm's Law if we know the values of voltage and current. When resistors are connected in series, the total resistance of the circuit is equal to the sum of the individual resistors. This is expressed by the following equation:RT = R1 + R2 + ... + RNWhere RT is the total resistance of the circuit, and R1, R2, and RN are the individual resistors. In this case, the circuit contains two 50.0 Ω resistors connected in series.

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Answer:

A lightbulb has 25 W stamped on it. What does this mean?:

These labels mean that each lightbulb has Its respective power delivered to It when It Is connected to a constant

Explanation:

Arousal theories can be thought of as outlining the homeostatic equilibrium of a person's alertness (or stimulus) level, such as increasing workload in response to a decline in arousal level.

The core notion of drive reduction theory is homeostasis. In other words, people are drawn to actions which can assist them in achieving a state of balance in their bodies and minds. The fundamental tenet is that your biological requirements drive your motivation.

The drive hypothesis of motivation postulates that disruptions of homeostasis lead to the emergence of physiological wants. These demands produce physiological drive states that influence behavior to fulfill the need and ultimately restore equilibrium to the system.

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Answer: 0.28 A

Explanation:

Answer:

-322.64 J

Explanation:

75 N  * cos 125     *    7.5   =  -322.64 J

The correct tight asymptotic bound for T(n) in 1, 2, 3 where T(1)=c is Θ(n log n).

To find the tight asymptotic bound of T(n), we will use the Master Theorem. So, let's take a look at each recurrence relation:

1. T(n) = 10T(n/10)+100nApplying the Master Theorem: a = 10, b = 10, f(n) = 100nlogb a = log10 10 = 1 Since f(n) = Θ(n) = Θ(n1), Case 2 of the Master Theorem applies. The solution, therefore, is Θ(n log n).

2. T(n) = T(n/10)+100n Here, a = 1, b = 10, f(n) = 100nlogb a = log10 1 = 0 Since f(n) = Θ(n0) = Θ(1), Case 1 of the Master Theorem applies. The solution, therefore, is Θ(n).

3. T(n) = T(n/10)+100 Here, a = 1, b = 10, f(n) = 100logb a = log10 1 = 0 Since f(n) = Θ(1) = Θ(n0), Case 2 of the Master Theorem applies. The solution, therefore, is Θ(log n).Therefore, the correct tight asymptotic bound for T(n) in 1, 2, 3 where T(1)=c is Θ(n log n).

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Let's use the Master Theorem to find the asymptotic tight bound for each of the three recurrence relations given in the problem statement.

1. T(n) = 10T(n/10) + 100n Here, a = 10, b = 10, and f(n) = 100n. We can calculate the value of logb a as follows: log10 10 = 1 Since f(n) = Θ(n1), we can apply Case 2 of the Master Theorem and get: T(n) = Θ(n log n)Therefore, the correct tight asymptotic bound for T(n) in the first case is Θ(n log n).

2. T(n) = T(n/10) + 100n Here, a = 1, b = 10, and f(n) = 100n. We can calculate the value of logb a as follows: log10 1 = 0 Since f(n) = Θ(n1), we can apply Case 1 of the Master Theorem and get: T(n) = Θ(n)Therefore, the correct tight asymptotic bound for T(n) in the second case is Θ(n).

3. T(n) = T(n/10) + 100 Here, a = 1, b = 10, and f(n) = 100. We can calculate the value of logb a as follows: log10 1 = 0 Since f(n) = Θ(1), we can apply Case 2 of the Master Theorem and get: T(n) = Θ(log n) Therefore, the correct tight asymptotic bound for T(n) in the third case is Θ(log n). Hence, the three asymptotic tight bounds for T(n) are Θ(n log n), Θ(n), and Θ(log n), respectively.

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more than mg

Explanation:

the pressure

The speed of your friend during the circular distance is 2 times greater than your speed.

The distance you travelled and the distance travelled by your friend during one rotation is calculated as follows;

your circular distance = 2πr

where;

your distance = 2π(4 m) = 8π m

your friend's circular distance = 2πd

where;

your friends distance = 2π(8 m) = 16π m

The speed of each person at equal time is calculated as;

v = distance / time

your speed = 8π/t

your friend's speed = 16π/t = 2(8π/t)

Thus, your friend's speed = 2 times your speed.

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The chief purpose of the ceramic material is to insulate the metal button from the other contact point. The correct answer is option d).

The ceramic material surrounding the metallic button in a flashlight bulb serves as an electrical insulator to prevent the metallic button from making contact with the other contact point of the bulb.

The metallic button at one end of the bulb serves as one of the two electrical contacts required to complete the electrical circuit and illuminate the bulb. The other electrical contact is typically a metallic ring or spring located at the base of the bulb.

If the ceramic material were not present, the metallic button would make contact with the other contact point and the bulb would not work properly. Therefore, the ceramic material is essential to the proper functioning of the flashlight bulb.

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The wavelength of the initial note is 2.34m

The distance between two successive crests or troughs of a wave is known as its wavelength. It is measured in the wave's direction. The distance a wave travels between its crests or troughs is known as its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave). The wave's crest is its highest point, while its dip is its lowest. Because a wavelength represents a distance or length, it is expressed in length units like meters, centimeters, millimeters, nanometers, etc. Light's wavelength changes with color, or it differs for each hue. While violet has the shortest wavelength, red has the longest.

wavelength = v/f

Given:

Initial frequency, \(f_{initial} = 146.8 Hz\)

Final frequency, \(f_{final} = 880\;Hz\)

Sound Level, \(\beta = 79\;dB\)

We know that,

Speed of the sound, \(v=343\;m/s\)

Density of air, \(\rho=1.2\;kg/m^{3}\)

Wavelength, \(\lambda = \frac{v}{f}\)

Wavelength of initial note is,

\(\lambda = \frac{v}{f_{initial} }\)

Substitute the known values in the above equation,

\(\lambda = \frac{343}{146.8}\)

\(\lambda = 2.34\;m\)

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Answer:

Explanation:

You know, I never really thought about this very much. I've always just thought of it as M * V. But when you look at a dictionary definition, it says it is the motion of a body.

That means that speed can be a momentum. Speed is independent of direction. So the colloquial definition does not take into account a change in direction as being very relevant.

The answer then is direction. When physics uses v, it is also counting direction.

Answer:

if the switch is open the bulbs will be on

when one light burns out the rest stay on

parallel circuit allow the bulbs to maintain the brightness of a since cricuit

When one light burns out the rest stay on in parallel circuit.

Parallel circuits allow the bulbs to maintain the brightness of a single circuit.

Hence, option (d) and (F) are correct answer.

It is referred to as a series combination when two or more resistors are connected end to end in a row. Any number of resistances connected in series have a combined resistance that is equal to the sum of the individual resistances.

It is referred to as a parallel combination when two or more resistances are coupled between the same two sites. The sum of the reciprocals of all the individual resistances is equal to the reciprocal of the combined resistance of a number of resistances connected in parallel.

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I think it's the yellow one

Answer:

Dalton's ideas proved foundational to modern atomic theory. However, one of his underlying assumptions was later shown to be incorrect. Dalton thought that atoms were the smallest units of matter-−minustiny, hard spheres that could not be broken down any further. This assumption persisted until experiments in physics showed that the atom was composed of even smaller particles. In this article, we will discuss some of the key experiments that led to the discovery of the electron and the nucleus.

J.J. Thomson and the discovery of the electron

In the late 19^{\text{th}}19  

th

19, start superscript, start text, t, h, end text, end superscript century, physicist J.J. Thomson began experimenting with cathode ray tubes. Cathode ray tubes are sealed glass tubes from which most of the air has been evacuated. A high voltage is applied across two electrodes at one end of the tube, which causes a beam of particles to flow from the cathode (the negatively-charged electrode) to the anode (the positively-charged electrode). The tubes are called cathode ray tubes because the particle beam or "cathode ray" originates at the cathode. The ray can be detected by painting a material known as phosphors onto the far end of the tube beyond the anode. The phosphors spark, or emit light, when impacted by the cathode ray.

A diagram of a cathode ray tube.

A diagram of a cathode ray tube.

A diagram of J.J. Thomson's cathode ray tube. The ray originates at the cathode and passes through a slit in the anode. The cathode ray is deflected away from the negatively-charged electric plate, and towards the positively-charged electric plate. The amount by which the ray was deflected by a magnetic field helped Thomson determine the mass-to-charge ratio of the particles. Image from Openstax, CC BY 4.0.

To test the properties of the particles, Thomson placed two oppositely-charged electric plates around the cathode ray. The cathode ray was deflected away from the negatively-charged electric plate and towards the positively-charged plate. This indicated that the cathode ray was composed of negatively-charged particles.

Thomson also placed two magnets on either side of the tube, and obser

Explanation:

One of the brightest nebulae in the night sky, the Orion Nebula may be seen with the unaided eye. The Trapezium is a young open cluster of four main stars in this magnitude 4 interstellar cloud of ionized atomic hydrogen.

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