HELP NEEDED ASAP I'M GIVING BRAINLIEST

1) Select the best answer from the choices below. Light has many properties of waves, but sometimes it also behaves like:


a

A photon

b

Polarized light

c

Ultraviolet rays

d

A stream of particles


2) What type of waves transmit signals in satellite communication?

a
Microwaves
b
X-rays
c
Gamma Rays
d
Radio Waves

3) Cell phones use digital signals to send and receive information. These digital signals travel as what kind of wave?

a
Gamma rays
b
X-rays
c
Microwaves
d
Radio waves

The magnitude of the acceleration due to gravity on planet p is 5 meters per seconds squared.

From the Second Equation of Motion;

s = ut + (1/2)gt²

Where v is final velocity, u is initial velocity, g is acceleration due to gravity and t is time elapsed.

Given the data in the question;

Plug the given data in the above formula and solve for g.

s = ut + (1/2)gt²

40m = (0 × 4s) + ( (1/2) × g × (4s)²

40m =  (1/2) × g × 16s²

Multiply both sides by 2

2 × 40m = 2 × (1/2) × g × 16s²

80m = g × 16s²

g × 16s² = 80m

g = 80m / 16s²

g = 5m/s²

Therefore, the acceleration due to gravity is 5m/s².

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Answer:

Yes

Explanation:

I think our memories can be altered by emotions. If someone tells you something over and over and over again with strong emotion you will start to remember that more than the memory.

Emotions are very powerful and if you feel a certain emotion connected with a different memory I think that is stronger and can trick your brain into thinking that is the memory because of the strong emotion, even though the true memory was right, since it might not have as strong of mental emotion your brain will think that is the false memory because whatever is more memorable your brain will remember.

If that makes any sense,

The equation that states the law of conservation of energy is:

ΔE = q + w

Hence, the correct option is C.

In this equation, ΔE represents the change in energy of a system, q represents the heat transferred to or from the system, and w represents the work done on or by the system.

According to the law of conservation of energy, the total energy of a closed system remains constant; it can neither be created nor destroyed, only transferred or transformed from one form to another.

This equation expresses that the change in energy of a system is equal to the heat added or removed from the system plus the work done on or by the system.

Therefore, The equation that states the law of conservation of energy is:

ΔE = q + w

Hence, the correct option is C.

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Given:

Mass, m = 3.5 kg

Initial temperature, T1 = 20°C

Final temperature, T2 = Boiling point of water = 100° C

Part (a).

Let's find the amount of energy needed.

Apply the specific heat capacity formula:

Where:

c is the specific heat capacity of water = 4.187 kJ/g °C

Thus, we have:

Where:

1 kJ = 0.239 kCal

1172.36 kJ = 1172.36 x 0.239 = 280.19 kCal

Therefore, the heat needed is 280.19 kCal.

Part B.

Given:

Cost = 13¢ per kWh

Where:

1 kCal = 0.00116 kWh

280.19 x 0.00116 = 0.327 kWh

Since the charge for is 13 ¢ per kWh, we have:

13 x 0.327 = 4.251 ¢.

Therefore, the cost, if electrical energy were used, will be 4.251 ¢

ANSWER:

• (a). 280.19 kCal

• (b)., ,4.251 ¢.

When taking the basic vehicle control skills test, failing to exit your vehicle properly during any exercise will result in Automatic failure of the basic vehicle control skills test.

Option C is the correct answer.

The basic vehicle control abilities exam might be automatically failed if you don't properly lock the car or get out of it. It might be possible for you to safely stop and get out of your car in order to verify the outside position of your car. You must accomplish this by putting the car in neutral and applying the parking brake. Option C is the correct answer.

During the basic vehicle control abilities exam, you must face the car and keep three points of contact throughout the times when getting out. You must keep your hand on the railing if the testing vehicle is a bus. The basic control abilities exam might be automatically failed if you exit the car improperly.

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The complete question is, "When taking the basic vehicle control skills test, failing to exit your vehicle properly during any exercise will result in:

A. Failure of only that exercise.

B. An extra point against your final score.

C. Automatic failure of the basic vehicle control skills test."

This question is incomplete; here is the complete question:

Marco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32.4 cm. If he measures the frequency as 3 hertz, which statement about the wave is accurate?

A. The wave has traveled 32.4 cm in 3 seconds.

B. The wave has traveled 32.4 cm in 9 seconds.

C. The wave has traveled 97.2 cm in 3 seconds.

D. The wave has traveled 97.2 cm in 1 second.

The answer to this question is D. The wave has traveled 97.2 cm in 1 second.

Explanation:

The frequency of a wave, which is in this case 3 hertz, represents the number of waves that go through a point during 1 second. According to this, if the frequency of the wave is 3 hertz this means in 1 second there were 3 waves. Moreover, if you multiply the wavelength (32.4cm) by the frequency (3) you will know the distance the wave traveled in 1 second: 32.4 x 3 =  97.2 cm. This makes option D the correct one as the distance in 1 second was 97.2 cm.

Answer:Is D!

Explanation:TEAT(Sorry) -_-*

The phase change in which hydrogen bonds are formed is freezing. That is option B.

Phase change is defined as the process that matter passes through in which there is change in state of matter from one form to another.

The different phase changes of matter include the following:

Freezing is defined as the phase change through which a liquid medium changes to a solid medium leading to the formation of ice.

Ice contains more hydrogen bonds than water. That is to say that freezing is the phase change in which hydrogen bonds are formed most.

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Answer:

1. condensation

2. heat of vaporization

3. freezing

4. 68.8J

Explanation:

States of Matter Quick Check

This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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Answer:

A

Explanation:

Trust me I just took it !

To find the range of values required for the capacitor (C) in the tuning circuit of an AM radio, we can use the formula for the resonance frequency of an LC circuit:f = 1 / (2π√(LC))

Given:
Inductance (L) = 0.250 mH
Minimum frequency (f_min) = 550 kHz
Maximum frequency (f_max) = 1650 kHz
We need to find the range of capacitance (C) values that allow the circuit to resonate within this frequency range.
For the minimum frequency:
550 kHz = 1 / (2π√(0.250 mH * C_min))
√(0.250 mH * C_min) = 1 / (2π * 550 kHz)
0.250 mH * C_min = (2π * 550 kHz)^(-2)
C_min = (2π * 550 kHz)^(-2) / 0.250 mH
Similarly, for the maximum frequency:
1650 kHz = 1 / (2π√(0.250 mH * C_max))
√(0.250 mH * C_max) = 1 / (2π * 1650 kHz)
0.250 mH * C_max = (2π * 1650 kHz)^(-2)
C_max = (2π * 1650 kHz)^(-2) / 0.250 mH
Calculating these values will give us the range of capacitance required for the tuning circuit.
Please note that I'm providing the general approach to calculate the range of capacitance based on the given parameters. You can substitute the values into the formulas and perform the calculations to obtain the specific range.

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The heat lost by water is equal to the heat gained by ice here. The heat lost from water for a temperature change of 25 to 10 degree Celsius is 12300 J.

Calorimetry is an analytical technique used to determine the heat energy absorbed or evolved by a system. The calorimetric equation relating the heat energy q with the mass m, specific heat c and the temperature difference ΔT is :

q = m c ΔT

Here, the heat energy gained by the dry ice is equal to the heat lost from water.

temperature difference for water = 25- 10 °C = 15°C

thus, 15°C is lost from water.

mass of water = 200 g

q =200 g × 4.12 J/°C g × 10°C = 12300 J

Therefore, the heat energy lost from water is 12300 J.

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Answer:

Work done = 838470 Joules.

Explanation:

Given the following data;

Power = 19 hp

Time = 1 minute to seconds = 60 seconds.

Next, we would convert the unit of power in "hp" to "Watt."

1 Watt = 0.00135962 horsepower

x Watt = 19 horsepower

Cross-multiplying, we have;

19 = 0.00135962x

x = 19/0.00135962

x = 13974.5 Watts.

Now, to find the work done in moving the mower;

Work done = power * time

Substituting into the formula, we have;

Work done = 13974.5 * 60

Work done = 838470 Joules.

Answer:

140km/h

Explanation:

Average speed= Distance/Time

= 210/1.5

= 140 I'm/h

The spring has 3.7 J energy when a force of 37. N act on it.

Energy is the ability or the capacity to perform work.

To calculate the energy of the spring, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the spring has 3.7 J energy.

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Magnitude of the car's acceleration is 3.5 m/s²

Given:

Mass of car = 1,000 kg

Net force applied by car = 3,500 N

How to find the acceleration of the car?

Formula:

Net force = Mass × Acceleration

So,

3,500 = 1,000 × Acceleration

Acceleration = 3,500 / 1,000

Acceleration = 3.5 m/s²

Therefore, the acceleration found from the formula is 3.5 m/s².

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Answer:

C. Acceleration due to gravity

Explanation:

which is 9.8 m/s2 on Earth. The formula for calculating weight is F = m × 9.8 m/s2.

Answer:

A. 2 Cu + O2 → 2 CuO illustrates conservation of mass, as the total mass of the reactants (copper and oxygen) equals the total mass of the products (copper oxide). This is because in a chemical reaction, the total mass of the reactants must be equal to the total mass of the products.

A, B, and C all illustrate conservation of mass because the number of atoms of each element is the same on both sides of the chemical equation, which means that the total mass of the reactants equals the total mass of the products. Therefore, the correct answer is all of the above.

Answer:

The first four resonance frequency in the string are;

1) 50·√50 Hz

2) 100·√50 Hz

3)150·√50 Hz

4) 200·√50 Hz

Explanation:

The given parameters of the string are;

The density of the string, ρ = 0.01 kg/m

The tension force on the string, T = 5 N

The length of the string, l = 0.1 m

Therefore the mass of the string, m = Length of string × Density of the string

∴ m = 0.01 kg/m × 0.1 m = 0.001 kg

The formula for the fundamental frequency, f₁, is given as follows;

\(f_1 = \dfrac{\sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{\sqrt{\dfrac{T}{\rho} } }{2 \cdot L}\)

Where;

f₁ = The fundamental frequency in the string

T = The tension in the string = 5 N

m = The mass of the string = 0.001 kg

L = The length of the string = 0.1 m

ρ = The density of the string = 0.01 kg/m

By plugging in the values of the variables, we have;

\(f_1 = \dfrac{\sqrt{\dfrac{5}{0.01} } }{2 \times 0.1} = 50 \cdot \sqrt{5}\)

The first four harmonics are;

f₁, 2·f₁, 3·f₁, 4·f₁

Therefore, we have the first four resonance frequency of the string are as follows;

1 × 50·√50 Hz = 50·√50 Hz

2 × 50·√50 Hz = 100·√50 Hz

3 × 50·√50 Hz = 150·√50 Hz

4 × 50·√50 Hz  = 200·√50 Hz

The human eye can detect objects that are 30 centimeters apart at a distance of 1 kilometer owing to its approximately 1 arcminute angular resolution.

The human eye has a maximum angular resolution of 28 arc seconds, or 0.47 arc minutes. As a result, at a distance of 1 kilometer, we are unable to resolve things smaller than 30 cm. The closer the object is placed; more distinguishable it appears to the eyes.

Angle resolution is one of the limits to which your eyes can see. Light rays that are reflected off or produced by things are visible to your eye. These light rays enter your pupil and are focused on your retina by your eye's lens. Depending on the angle at which the corresponding light beams from two items interact, your pupil size—which is comparable to the aperture of a camera—determines how well you can distinguish between two objects.

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Complete question:

the human eye has an angular resolution of roughly 1 arcminute. which of the following objects are we not able to resolve, and uses the unit of arcminute correctly?

Objects closer than 1 km

Objects away from the vision

Objects at a distance of 2 km

Objects just near to eyes

The given problem can be solved using the following free-body diagram:

The diagram is the free-body diagram for the pulley that is holding the weight. Where:

Now we add the forces in the vertical direction:

Adding like terms:

Now, since the velocity is constant this means that the acceleration is zero and therefore the sum of forces is zero:

Now we solve for "T" by adding "mg" from both sides:

Now we divide both sides by 2:

Now we substitute the values and we get:

Solving the operations:

Now we use the free body diagram for the second pulley:

Now we add the forces in the vertical direction:

The forces add up to zero because the velocity is constant and the acceleration is zero:

Solving for the force:

Therefore, the pulling force is equal to the tension we determined previously and therefore is:

The rate of water level rising when the water is 30 cm deep will be 1/30 m/min.

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

The complete question is;

"A water trough is 10m long and has a cross-section which is the shape of an isosceles trapezoid

that is 30cm wide at the bottom, 80cm wide at the top, and has a height of 50cm. If the trough is being filled with water at the rate of 0.2 m3/min, how fast is the water level rising when the water is 30cm deep?"

b1 is the width of the water at a height at the bottom

b2 is the width of the water at the height at the top

The length of the trapezoid is L

The volume of the trapezoid is found as;

\(\rm V = 0.5(b_1 + b_2)hL\)

The breadth rises by 1 as the height does, therefore which implies

\(\rm \frac{dh}{dt} =\frac{dw}{dt}\)

The water's breadth at the combined height is [0.3 + h]

\(\rm V = 5h(0.3 +(0.3 + h))\\\\ V = 3h + 5h^2\)

After differentiation we get;

\(\rm \frac{dv }{dt} =3 \frac{dh}{dt} +10 h \frac{dh}{dt} \\\\\ \frac{ \frac{dv }{dt}}{3+10h}=\frac{dh}{dt} \\\\\ \frac{dv }{dt}= 0.2 \\\\\ h = 0.3 \\\\ \frac{dh}{dt} = \frac{1}{30} m/min\)

Hence the rate of water level rising when the water is 30 cm deep will be 1/30 m/min.

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Answer:

180N

Explanation:

the gravity on Earth is six times the one on the moon

Answer:

I think 180N

Explanation:

the gravity of the surface of the earth is 6Times

more than the moon

Answer:

elastic potential energy

Explanation:

The situation above shows an example of an "elastic potential energy." This type of potential energy depends on the force being applied to the elastic object.

In the situation above, the elastic object is the rubber band. The resultant energy is then being stored until such time that this object will be freed. Once this happens, the elastic object will revert to its original form and the rock will soar (be released).

The amount of energy that is being stored largely depends on the distance of the "stretch" being applied to the object. It is said that the greater the force, the greater the stretch and the greater the distance covered by the rock (and vice-versa).

No, law of conservation of energy is not applicable to open systems.

Law of conservation of energy states that energy present anywhere can neither be created nor be destroyed by any means, it can only be converted from one form of energy to other form of energy. It means total energy of an isolated system remains same.

An open system is a system that can exchange energy and matter from the surroundings. The flow of energy takes places in an open system. Therefore, the law of conservation does not apply to an open system as it can lose or gain energy, hence its total energy will not be constant and will violate law of conservation of energy.

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The question asks us to determine the time it takes for the current to equal 100 mA after the switch in the circuit has been closed.

Let's break down the problem into smaller steps to find the answer:

A milliseconds is a unit of time in the International System of Units which is equal to one thousandth of a second and 1000 microseconds. The units of 10 milliseconds may be called a centimeter, and one in 100 milliseconds is a decisecond, but these names are rarely used. Below are the order of numbers for the smaller units of time below the second. Starting from milliseconds, microseconds, nanoseconds, picoseconds, femtoseconds, attoseconds, zeptoseconds and each value is based on a reference for seconds. The researchers managed to measure the fastest unit of time, zeptosecond, which is faster than seconds and milliseconds. The size of a zeptosecond is 0.000000000000000000001 (zero point septillion or zero point billion trillion) seconds.

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To answer these questions, we can use the Bernoulli equation, which relates the pressure, velocity, and height of a fluid in a system to the pressure, velocity, and height of a reference point. For an ideal fluid flowing through a tube with a varying cross-sectional area, the Bernoulli equation is given by:

P + (1/2)ρv^2 + ρgh = constant

where P is the pressure, ρ is the density of the fluid, v is the velocity of the fluid, g is the acceleration due to gravity, and h is the height above a reference point.

In this case, we are given the pressure difference between points 1 and 2, and we are asked to find the velocity of the glycerin at each point. We can use the Bernoulli equation to solve for the velocity at each point by setting the constant equal to the pressure at one of the points and solving for the velocity at the other point.

(a) To find the velocity at point 1, we can set the constant equal to the pressure at point 1 and solve for the velocity:

P1 + (1/2)ρv1^2 + ρgh1 = P2 + (1/2)ρv2^2 + ρgh2

P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2

(1/2)ρv1^2 = (1/2)ρv2^2

v1 = v2

Since we don't know the values of the other variables, we can't solve for the velocity directly. However, we know that the velocities at points 1 and 2 are equal, so we can use this relationship to solve for the velocity at one point in terms of the other.

(b) To find the velocity at point 2, we can set the constant equal to the pressure at point 2 and solve for the velocity:

P1 + (1/2)ρv1^2 + ρgh1 = P2 + (1/2)ρv2^2 + ρgh2

P1 - P2 = (1/2)ρv2^2 - (1/2)ρv1^2

P1 - P2 = (1/2)ρ(v2^2 - v1^2)

(P1 - P2)/(1/2)ρ = v2^2 - v1^2

(9.45 kPa)/(1/2)ρ = v2^2 - v1^2

(9.45 kPa)/(1/2)ρ = v2^2 - v1^2

(9.45 kPa)/(1/2)ρ = v2^2 - v1^2

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Answer:

Geologists use seismic waves to locate the center of an earthquake.

Explanation:

Answer: they collect data from seismographs

Explanation: on the quiz on edge 2020, it’s correct

The final velocity of the car 120.93 m/sec.

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.

Given in the question, a car travelling with an initial velocity of 15.0 m/s, accelerates at 2.40 m/s² over a distance of 180 m

Using equation of motion,

v² = u² + 2as

v² = 15² + 2*40*180

v =  120.93 m/sec

The final velocity of the car 120.93 m/sec.

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