Answer:
a = 0.5 [m/s²]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces is equal to the product of mass by acceleration.
ΣF = m*a
F = force = 200 [N]
m = mass = 400 [kg]
a = acceleration [m/s²]
Now replacing:
200 = 400*a
a = 0.5 [m/s²]
Please help me ASAP!!
Answer:
the ball lose kentic energy and gains potential energy rolling upward
Answer:
c
Explanation:
when a ball is rolling down it loses potential and gains kinetic, but in this case since the ball is going upwards it is losing kinetic energy and gaining potentail like a roller coaser
Using this formula Q = mcAt. A 1kg block of aluminum is increased in temperature by 75°C. how much heat energy was required? a 67,7250 b 67.728 C 65.7253 d 66.7253 Check it
Answer:
67500 J
Explanation:
Q = mcΔt.................... Equation 1
Where Q = Amount of heat, m = mass of aluminum, c = specific heat capacity of aluminium, Δt = change or increase in temperature.
From the question,
Given: m = 1 kg, Δt = 75 °C
Constant: c = 900 J/kg.K
Substitute these values into equation 1
Q = 1×900×75
Q = 67500 J
Hence the heat energy required is 67500 J
An airplane starts from rest and accelerates at a constant 3.00 m/s^2 It’s final displacement is 600m. What is the time value?
Answer:
20 Seconds
Explanation:
Data
x=600m, initial velocity (u) =0, a=3m/s
x=ut+1/2 a (t squared )
600m=0+(1/2)*3 txt
t=
\( \sqrt{400} \)
t=20 seconds
A cows mass is 401 kg and a trucks mass is 832 kg. What is the difference between their weights . Answer please!!!
Answer:
403 kg is the diffrence
Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?
Question 12 options:
Put it in the fridge where it is cold
Cover it with a blanket so it's dark
Warm it up on the stove
There is nothing you can do to change the speed of the reaction
In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.
Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct
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Alexis is studying how lenses work. She looks through a magnifying glass and through the peephole of a door.
Which best describes a difference between the lenses used in these two devices?
The lens in the magnifying glass can produce both real and virtual images, but the lens in the peephole can produce only real images.
The lens in the magnifying glass can produce only real images, but the lens in the peephole can produce both real and virtual images.
The lens in the magnifying glass can produce both upright and inverted images, but the lens in the peephole can produce only upright images.
The lens in the magnifying glass can produce only inverted images, but the lens in the peephole can produce inverted and upright images.
Answer:
The lens in the magnifying glass can produce both upright and inverted images, but the lens in the peephole can produce only upright images.
Explanation:
Answer: C
Explanation:
A normal atom is electronically ** (positive/negative/neutral) because the number of ** (protons/neutrons/electrons), each with a positive charge, equals the number of ** (protons/neutrons/electrons), each with a negative charge.
The answers to multiple choice questions are in parentheses
Answer:
(neutral)
(protons)
(electrons)
Explanation:
Electrons have a negative charge (-) while protons have a positive (+) charge.
Atoms will usually be neutral, which means that there will be no charge.
For an atom to have a neutral charge, protons and electrons must "cancel" each other out. For this to happen, you need to have the same amount of each.
Positive will "cancel" out the negative.
find the pressure exerted by a force of 8000 newtons on an area of 25m square..give your answer in Newtown/m2
Answer:
Pressure = 320 N/m²
Explanation:
Given the following data;
Force = 8000 Newton
Area = 25 m²
To find the pressure, we would use the following formula;
Pressure = force/area
Substituting into the formula, we have;
Pressure = 8000/25
Pressure = 320 N/m²
if the mass of the object is tripled and the speed is doubled then the kinetic energy will change by a factor of
Answer:
New kinetic energy = 12 times of the initial kinetic energy.
Explanation:
The kinetic energy of an object is given by :
\(K=\dfrac{1}{2}mv^2\)
Where
m is mass of the object
v is speed of the object
ATQ,
If the mass of the object is tripled, m' = 3m
Speed is doubled, v' = 2v
New kinetic energy will be:
\(K'=\dfrac{1}{2}m'v'^2\\\\K'=\dfrac{1}{2}\times 3m\times (2v)^2\\\\=\dfrac{1}{2}\times 3m\times 4v^2\\\\=12\times \dfrac{1}{2}mv^2\\\\K'=12\times K\)
So, the new kinetic energy will become 12 times of the initial kinetic energy.
The image shows mountains in Alaska.
Which describes the main feature of the circled area of these mountains?
A syncline is visible.
An anticline is visible.
These mountains show no evidence of folding.
These mountains likely formed from normal faults
Answer:
A syncline is visible.
Explanation:
A syncline is visible.
Answer:
These mountains show no evidence of folding.
If you, a physics student, weigh about 70 kg, are standing on the surface of 1
the Moon, who's mass is 7.34 x 10^22 kg what is the force of gravity acting
on the Moon and yourself? The radius of the Moon is 1.71 x 10^6 m.
25 units
400 units
117 N
200 N
Answer:
it's answer is 117 N
F = Gm1m2/r^2
F = 6.67 * 10 ^-11 * 70 * 7.34 * 10 ^22/(1.71 * 10 ^6)^2
F = 117 N
hope it helps you
(b) What are the dimensions of a and b in the relation F = a*x^0.5+ bt^2 where F is force, x is distance and t is
time.
Answer:
It is 5F
Explanation:
Consider two carts, of masses m and 2m, at rest on an air track. If you push first one cart for 3 s and then the other for the same length of time, exerting equal force on each, the momentum of the light cart is ________ the momentum of the heavy cart.a) four timesb) twicec) equal tod) one-halfe) one-quarter
The value of the momentum on the second cart is p₂ = v₂m₂ = 2vm.
What is momentum?Momentum is defined in Newtonian mechanics as the product of an object's mass and velocity. It is a vector quantity with magnitude and direction. If an object's mass is m and its velocity is v,
Given that consider two carts, of masses m and 2m, at rest on an air track. if you first push one cart for 3 s and then the other for the same length of time, exerting equal force on each.
The momentum on the second cart will be calculated as,
F = m₁ a₁ = m₂ a₂
if m₁ = m and m₂ = 2m :
F = ma₁ = 2m a₂ ⇒ a₁ = 2 a₂
Since v = at + v₀ with t = 3, v₀ = 0 ⇒ v = 3a:
v₁ = 2 v₂
Since p = vm with v₁ = 2v and v₂ = v :
p₂ = v₂m₂ = 2vm
Therefore, the value of the momentum on the second cart is p₂ = v₂m₂ = 2vm.
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IBangkok, Thailand, and Lima, Peru, are located at opposite positions of Earth's surface. When a rock is dropped in both cities, observers would describe the motion of either rock with a word that means "down."
Where are the two rocks moving?
Responses
They are moving away from each other.
.
One rock is moving due east and the other is moving due west.
They are moving down, which is the same direction in both cities.
They are moving toward each other.
Answer :dawg you got snaids thats the answer awww man
Explanation:
answer is that of an answer
Find the marginal cost functions for each of the following average cost functions. a) AC= 1.5Q + 4 + 460 b) AC = 160 +5+3Q+2Q²
(a) The marginal cost function is MC = 3Q + 464.
(b) The marginal cost function is MC = 160 + 5 + 6Q + 6Q^2.
What is the marginal cost function?The marginal cost (MC) of a product is the change in the total cost of producing an additional unit of the product.
(a) AC = 1.5Q + 4 + 460
The total cost (TC) of producing Q units is given by:
TC = AC * Q
TC = (1.5Q + 4 + 460) * Q
TC = 1.5Q^2 + 4Q + 460Q
TC = 1.5Q^2 + 464Q + 460
The marginal cost function is given by the derivative of the total cost function with respect to Q:
MC = dTC/dQ
MC = d/dQ (1.5Q^2 + 464Q + 460)
MC = 3Q + 464
b) AC = 160 + 5 + 3Q + 2Q²
The total cost of producing Q units is given by:
TC = AC * Q
TC = (160 + 5 + 3Q + 2Q^2) * Q
TC = 160Q + 5Q + 3Q^2 + 2Q^3
The marginal cost function is given by the derivative of the total cost function with respect to Q:
MC = dTC/dQ
MC = d/dQ (160Q + 5Q + 3Q^2 + 2Q^3)
MC = 160 + 5 + 6Q + 6Q^2.
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Is it possible that the physical velocity is constant but the magnitude of the velocity is variable?give an example
Answer:
yes it is possible
Explanation:
if the body is travelling with uniform speed in a circular track its speed remains the same but the velocity is non-uniform as the direction of the body is changing every time.
eg: a body in uniform circular motion has constant speed but its velocity changes at every point during the course of motion. Whenever, the direction changes, velcoity changes.
A pool ball moving 1.83 m/s
strikes an identical ball at rest.
Afterward, the first ball moves
1.15 m/s at a 23.3° angle. What is
the x-component of the velocity of
the second ball?
Answer:n to the right to the right
Explanation:
What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.
Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.
To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.
The energy required to melt 1 kg of ice is 3.33×105 J/kg.
Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.
To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.
Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.
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Some bat species have auditory systems that work best over a narrow range of frequencies. To account for this, the bats adjust the sound frequencies they emit so that the returning, Doppler-shifted sound pulse is in the correct frequency range. As a bat increases its forward speed, should it increase or decrease the frequency of the emitted pulses to compensate?
Answer:
As a bat increases its forward speed, it should decrease the frequency of the emitted pulses to compensate.
decrease
Explanation:
Decreasing the frequency of the emitted pulse will help the bat reduce its frequency caused by its forward motion. The forward motion shifts the bat's auditory frequency to a higher frequency; consequently, the bat should adjust downwards the frequency of the emitted pulse so the reflected pulse will be in the correct frequency range.
Which of the following statements describes meta-analysis
Meta-analysis includes all of these such as systematic inclusion and exclusion criteria for studies, multiple, systematic searches to identify studies which answer a focused question, only quantitative studies are included in this. Thus, the correct option is B.
What is Meta-analysis?A meta-analysis is a statistical analysis which combines the results of multiple scientific studies. Meta-analyses of anything can be performed when there are multiple scientific studies available which are addressing the same question, with each of the individual study reporting measurements which are expected to have some degree of error in it.
The subjects from all the studies were pooled and statistically analyzed to determine the effect of the one thing such as relationship between wearing sunscreen and melanoma. This meta-analysis has been found to show a 50% reduction in the melanoma diagnosis among the sunscreen-wearers.
Therefore, the correct option is B.
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Your question is incomplete, most probably the complete question is:
Which of the following describe meta-analysis?
A. Systematic inclusion and exclusion criteria for studies
B. All of these
C. Multiple, systematic searches to identify studies that answer a focused question
D. Only quantitative studies are included
E. None of these
Kindly please tell me the answer to this question...
Following are the answers:
Pressure = \(force/area = 1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 PaDensity = Pressure/ (acceleration due to gravity x height) =\(9.79 N/m^2 / (9.8 m/s^2 x 0.92 m)\) = 1060 kg/m^3.What is the pressure and density?1. To calculate the pressure exerted by the water column on the surface of the mercury, we can use the formula:
Pressure = force/area
The force is the weight of the water column and the area is the cross-sectional area of the container.
The weight of the water column is given by the mass of the water times the acceleration due to gravity:
mass = density x volume
volume = area x height
So, mass = density x area x height = 1000 kg/m^3 x pi x (0.025 m)^2 x 0.25 m = 0.196 kg
Weight = mass x acceleration due to gravity =\(0.196 kg * 9.8 m/s^2\) = 1.92 N
The cross-sectional area of the container is pi x (0.025 m)^2 =\(0.196 m^2.\)
So, Pressure = force/area = \(1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 Pa
2. To calculate the density of the oil, we can use the formula:
density = mass/volume
Since the height of the oil column is 0.92 m and the cross-sectional area of the container is 0.196 m^2, the volume of the oil column is 0.196 m^2 x 0.92 m = 0.18012 m^3.
We do not know the mass of the oil, but we can calculate it using the pressure exerted by the oil column on the surface of the mercury:
Pressure = force/area = density x acceleration due to gravity x height
So, density = Pressure/ (acceleration due to gravity x height) = 9.79 N/m^2 / (9.8 m/s^2 x 0.92 m) = 1060 kg/m^3.
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Suppose 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter. The final temperature of the water and copper calorimeter is 18.0C.
1) What was the initial common temperature of the water and copper? (Express your answer to three significant figures.)
The initial common temperature of the water and copper is approximately 2.68°C.
To find the hidden typical temperature of the water and copper, we need to use the norm of protection of energy, which communicates that energy can't be made or obliterated, recently moved or changed beginning with one design then onto the following.
The force lost by the ice as it breaks up is identical to the power obtained by the water and the calorimeter. We can impart this using the recipe:
Q_ice = Q_water + Q_calorimeter
where Q_ice is the force lost by the ice, Q_water is the power procured by the water, and Q_calorimeter is the force gained by the calorimeter.
We can determine the power lost by the ice using the recipe:
Q_ice = m_ice * L_f
where m_ice is the mass of the ice and L_f is the force of blend of water, which is 333 J/g.
Q_ice = (10.0 g) * (333 J/g) = 3330 J
We can sort out the force obtained by the water using the condition:
Q_water = m_water * c * (T_f - T_i)
where m_water is the mass of the water, c is the specific power breaking point of water, which is 4.184 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.
Q_water = (300.0 g) * (4.184 J/g°C) * (18.0°C - T_i)
We can figure the force obtained by the calorimeter using the recipe:
Q_calorimeter = m_calorimeter * c_calorimeter * (T_f - T_i)
where m_calorimeter is the mass of the calorimeter, which is 200.0 g, c_calorimeter is the specific force breaking point of copper, which is 0.385 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.
Q_calorimeter = (200.0 g) * (0.385 J/g°C) * (18.0°C - T_i)
Subbing these circumstances into the norm of conservation of energy, we get:
m_ice * L_f = m_water * c * (T_f - T_i) + m_calorimeter * c_calorimeter * (T_f - T_i)
Tending to for T_i, we get:
T_i = T_f - [(m_ice * L_f)/(m_water * c + m_calorimeter * c_calorimeter)]
T_i = 18.0°C - [(10.0 g) * (333 J/g)/(300.0 g * 4.184 J/g°C + 200.0 g * 0.385 J/g°C)]
T_i = 2.68°C
As needs be, the basic ordinary temperature of the water and copper was 2.68°C (conveyed to three immense figures).
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A large piston in a hydraulic lift has an area of 100 cm2. The force needed to a small piston with an area of 15 cm2 to lift a 1800 kg car is _ kg
The force needed to lift the 1800 kg car with the small piston is 2,649 N or approximately 270 kg (since 1 kg is equal to 9.81 N).
The hydraulic lift works based on Pascal's principle, which states that the pressure applied to a confined fluid is transmitted equally in all directions throughout the fluid.
Assuming there is no loss of energy due to friction or other factors, the force exerted on the small piston will be equal to the force exerted on the large piston. This can be expressed as:
F1/A1 = F2/A2
where F1 is the force exerted on the large piston, A1 is the area of the large piston, F2 is the force exerted on the small piston (which we want to find), and A2 is the area of the small piston.
We can rearrange this equation to solve for F2:
F2 = (F1/A1) x A2
Given that the area of the large piston is 100 cm², we can calculate the force exerted on the large piston by using the weight of the car and the gravitational acceleration:
F1 = m x g = 1800 kg x 9.81 m/s² = 17,658 N
Substituting the values into the equation, we get:
F2 = (17,658 N / 100 cm2) x 15 cm² = 2,649 N
Therefore, the force needed to lift the 1800 kg car with the small piston is 2,649 N or approximately 270 kg (since 1 kg is equal to 9.81 N).
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write down the value of
920 kg in g
Answer:
920000
Explanation:
Each kg contains 1,000 grams
What is the real reason the skies blue
Answer:
Rayleigh scattering
Explanation:
The blue color of the sky is due to a phenomenon called Rayleigh scattering. When sunlight enters the Earth's atmosphere, the shorter blue wavelengths of light are scattered more than the other colors by the tiny molecules of nitrogen and oxygen in the air. This causes the blue light to be redirected in many different directions, making the sky appear blue to our eyes. The other colors of light are scattered as well, but to a lesser extent, which is why the sky appears blue instead of a mixture of all colors. This effect is also the reason why the sun appears more yellow, orange or red during sunrise or sunset, when its light has to travel through more of the Earth's atmosphere before reaching our eyes, causing the shorter blue wavelengths to be scattered even more, leaving behind the longer wavelengths of light.
What types of physical education program modifications need to be made for individuals with Down syndrome who have atlantoaxial instability?
Answer:
Excuse me wot? That is so confoosing
Explanation:
How is the acceleration of a falling object calculated
Answer:
F=w=ma OR by using equations of motions vf=vi-at : a=vf-vi/t eq 1 s=vit+1/2at squre eq 2 2as=vf squre - vi squre eq 3
Explanation:
where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.
A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
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how many taste buds do humans have 100,000, 100, 10,000 1,000
The approximate number of taste buds that humans have is 10,000 (option C).
What are taste buds?Tastebuds are any of the small organs on the tongue used for tasting.
Taste buds are cells on the tongue that allow one to perceive tastes, including sweet, salty, sour, bitter and umami.
Taste buds regenerate approximately every 10 days, which means injured taste buds usually repair on their own. The average adult human has between 2000 and 8000 tastebuds.
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In an experiment, a group of students will determine the dielectric constant of paper. They have the following materials available, as well as other materials traditionally available in a high school physics lab. _____ Aluminum foil _____ Sheets of paper _____ Sheets of plastic _____ Multimeters with the ability to measure capacitance(a) Outline an effective experimental procedure to gather the necessary data that can be used to determine the dielectric constant of paper. Place a check mark next to each item above that the students should use. Draw a labeled diagram to represent the setup used for this procedure.The table below shows data from a different experiment in which students measure the capacitance of different setups as they vary the distance between the two plates of the capacitor, the area of the plates, and the material inserted between the plates.Trial Capacitor Dielectric Distance Between the Plates ( m ) Area of the Plates ( m2 ) Capacitance ( F )1 paper 1.00×10−4 0.04 8.1×10−92 paper 1.00×10−4 0.09 18.3×10−93 paper 1.00×10−4 0.16 32.6×10−94 paper 1.00×10−4 0.25 49.8×10−95 paper 2.00×10−4 0.25 23.1×10−96 paper 3.00×10−4 0.25 18.9×10−97 paper 4.00×10−4 0.25 14.9×10−98 paper 5.00×10−4 0.25 9.2×10−99 plastic 1.10×10−4 0.04 11.3×10−910 plastic 1.10×10−4 0.09 25.3×10−911 plastic 1.10×10−4 0.16 45.1×10−912 plastic 1.10×10−4 0.25 70.4×10−913 plastic 2.20×10−4 0.25 35.2×10−914 plastic 3.30×10−4 0.25 23.5×10−915 plastic 4.40×10−4 0.25 17.6×10−916 plastic 5.50×10−4 0.25 14.1×10−9(b)i. What subset of the experimental trials would be most useful in creating a graph to determine the dielectric constant of paper? Explain why the selected trials are most useful.ii. Indicate below which quantities should be graphed to yield a straight line whose slope could be used to calculate a numerical value for the dielectric constant κ of paper.Vertical axis: Horizontal axis:(c) Plot the data points for the quantities indicated in part (b)(ii) on the graph below. Clearly scale and label all axes including units, if appropriate. Draw a straight line that best represents the data.(d) Use the data to determine a value for κ of paper.(e) On the axes below, sketch the Capacitance C as functions of plate separation d, plate area A, and dielectric constant κ.
(a) The students should use aluminum foil, sheets of paper, sheets of plastic, and multimeters with the ability to measure capacitance for the experiment.
What is dielectric constant?Dielectric constant, also known as relative permittivity, is a measure of a material's ability to store electrical energy in an electric field. It is defined as the ratio of the electric flux density produced by an applied electric field to the electric flux density that would be produced by the same electric field in a vacuum.
An effective experimental procedure to determine the dielectric constant of paper could involve the following steps:
Cut two pieces of aluminum foil and attach them to opposite sides of a sheet of paper using tape, leaving a small area of the foil exposed.
Measure the area of the exposed foil using a ruler and calculate the capacitance of the capacitor using a multimeter with the ability to measure capacitance.
Repeat step 2 for different distances between the plates of the capacitor by adjusting the distance between the foil pieces and measuring the capacitance at each distance.
Plot the capacitance versus distance data on a graph and determine the slope of the best-fit line.
Calculate the dielectric constant of paper using the slope of the best-fit line and the equation C = κεA/d, where C is the capacitance, A is the area of the plates, d is the distance between the plates, ε is the permittivity of free space, and κ is the dielectric constant of paper.
(b)
i. The trials with paper inserted between the plates and varying distances between the plates would be most useful in creating a graph to determine the dielectric constant of paper. Specifically, trials 1-5 would be most useful, as they all use paper as the dielectric material and vary the distance between the plates.
ii. The capacitance C should be graphed on the vertical axis, and the reciprocal of the distance between the plates (1/d) should be graphed on the horizontal axis to yield a straight line whose slope could be used to calculate the dielectric constant κ of paper.
(d) Using the data from trials 1-5 and the graph in part (c), the slope of the best-fit line is 3.77 x 10^-9 F/m. Using the equation C = κεA/d and the measured values of A and d, and ε (permittivity of free space), we can solve for the dielectric constant κ of paper as:
κ = Cd/εA = (3.77 x 10^-9 F/m) / [(8.85 x 10^-12 F/m) x (0.04 m^2)] = 10.7
Therefore, the dielectric constant of paper is approximately 10.7.
(e) See attached image for sketches of Capacitance C as a function of plate separation d, plate area A, and dielectric constant κ. The capacitance rises as the space between the plates gets closer. With a rise in plate area, the capacitance also grows. Last but not least, the capacitance increases as the dielectric constant increases at a certain plate gap and area.
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