HELP ASAP PLS
mystery element a has 3 valence electrons located in the 5th electron orbital. what do you know about this electron?
a) it belongs to group V and is in period 3
b) it belongs to group iii and is in period 5
c) it has 5 protons and 5 electrons
d) it has 3 protons and 5 electrons

Mercury, Venus, and Mars are all rocky planets. None are more or less different than Earth. Earth is the largest and the only planet with extensive regions of liquid water.

Explanation:

Answer:

En nuestro sistema solar, hay cuatro planetas terrestres, que también son los cuatro más cercanos al sol: Mercurio, Venus, Tierra y Marte. Durante la formación del sistema solar, probablemente hubo más planetoides terrestres, pero se fusionaron entre sí o fueron destruidos.

The number of moles of carbon monoxide (CO) produced when 0.65 mol of oxygen reacts with excess carbon is 0.7 moles.

To determine the number of moles of carbon monoxide (CO) produced when 0.65 mol of oxygen reacts with excess carbon, we need to use the stoichiometry of the balanced chemical equation.

From the balanced equation:

C + \(O_{2}\) → CO

We can see that one mole of carbon reacts with one mole of oxygen to produce one mole of carbon monoxide.

To find the number of moles of carbon monoxide produced, we can directly equate it to the number of moles of oxygen in this case, since the reaction occurs with excess carbon. Therefore, 0.65 mol of oxygen will produce 0.65 mol of carbon monoxide.

Since there is a 1:1 molar ratio between oxygen and carbon monoxide according to the balanced equation, the number of moles of carbon monoxide produced is equal to the number of moles of oxygen used in the reaction. Hence, 0.65 moles of carbon monoxide are produced when 0.65 moles of oxygen react with excess carbon.

Stoichiometry calculations involve the use of balanced chemical equations to determine the molar ratios between reactants and products. In this case, the stoichiometry allows us to establish a direct relationship between the number of moles of oxygen and the number of moles of carbon monoxide produced. Rounding the answer to the nearest tenth gives us 0.7 moles of carbon monoxide as the result.

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Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

The change in entropy in J/K for:

A. the vaporization of 50.0 g of benzene (C₆H₆) at its boiling point of 80°C. ∆\(H_v_a_p\) = 31.0 kJ/mol is 138.34 J/K.

B. the melting of 50.0 g of benzene (C₆H₆) at its freezing point of 5.5°C. ∆\(H_f_u_s\) = 9.92 kJ/mol is 56.39 J/K.

C. A 555 g sample of acetone (CH₃COCH₃) is 150 J/K. If the acetone starts at 10.0°C the final temperature is 11.1°C.

To calculate the change in entropy (∆S) in J/K for the given processes, we can use the equations:

∆S = ∆H / T

where ∆H is the change in enthalpy and T is the temperature in Kelvin.

A. Vaporization of 50.0 g of benzene (C₆H₆) at its boiling point of 80°C (∆\(H_v_a_p\) = 31.0 kJ/mol)

First, we need to calculate the moles of benzene (C₆H₆) using its molar mass:

Molar mass of benzene (C₆H₆) = 78.11 g/mol

Moles of benzene = 50.0 g / 78.11 g/mol = 0.640 mol

Now, we can calculate the change in entropy:

∆S = ∆\(H_v_a_p\) / T

T = 80°C + 273.15 = 353.15 K

∆S = (31.0 kJ/mol) / (0.640 mol) / (353.15 K)

= 138.34 J/K

Therefore, the change in entropy for the vaporization of 50.0 g of benzene is 138.34 J/K.

B. Melting of 50.0 g of benzene (C₆H₆) at its freezing point of 5.5°C (∆\(H_f_u_s\) = 9.92 kJ/mol)

Similarly, we calculate the moles of benzene:

Moles of benzene = 50.0 g / 78.11 g/mol = 0.640 mol

∆S = ∆\(H_f_u_s\) / T

T = 5.5°C + 273.15 = 278.65 K

∆S = (9.92 kJ/mol) / (0.640 mol) / (278.65 K)

= 56.39 J/K

Therefore, the change in entropy for the melting of 50.0 g of benzene is 56.39 J/K.

C. For the 555 g sample of acetone (CH₃COCH₃) with a specific heat capacity of 141.5 J/mol*K.

∆S = \(C_p\) * ∆T

∆T = final temperature - initial temperature

∆S = (141.5 J/mol*K) * (final temperature - 10.0°C)

555 g = 0.555 kg

∆S = (141.5 J/mol*K) * (∆T) = 150 J/K

Solving for ∆T:

∆T = 150 J/K / (141.5 J/mol*K) = 1.059 K

Final temperature = 10.0°C + 1.059 K = 11.059°C

Therefore, the final temperature of the acetone sample is approximately 11.1°C.

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The two ways in which the physical state of matter can be changed are melting and freezing.

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The gaseous form of matter has the lowest intermolecular forces of attraction.

The particles in a gas have a large amount of space between them and a high kinetic energy. A gas lacks a fixed volume or shape. A gas will expand to fill its container if contained; if unconfined, its particles will disperse indefinitely.

According to NASA's Glenn Research Center, putting a gas under pressure by lowering the capacity of the container reduces the distance between particles and compresses the gas.

The simplest state of matter is the gaseous state, however only 11 of the elements in the periodic table behave as gases at standard temperature and pressure (STP, or 1 atm and 273 K). These are Hydrogen, Nitrogen, Oxygen, Fluorine, Neon, Argon, Krypton, Xenon, Radon.

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Answer:

Approximately \(1.24 \times 10^{2}\; \rm g\), assuming that all sulfur in that coal was converted to \(\rm SO_2\).

Explanation:

Look up the relative atomic mass of \(\rm S\) and \(\rm O\) on a modern periodic table:

Convert the unit of the mass of coal to grams:

\(\begin{aligned} & m(\text{coal})= 1\; \rm kg \times \frac{10^{3}\; \rm g}{1\; \rm kg} = 1000\; \rm g\end{aligned}\).

Mass of sulfur in that much coal:

\(m(\text{sulfur}) = 1000\; \rm g \times 6.23\% = 62.3\; \rm g\).

The relative atomic mass of sulfur is \(32.06\). Therefore, the mass of each mole of sulfur atoms would be \(32.06\; \rm g\). Calculate the number of moles of atoms in that \(62.3\; \rm g\) of sulfur:

\(\begin{aligned}& n(\text{S})\\&= \frac{m(\mathrm{S})}{M(\mathrm{S})}\\ &= \frac{62.3\; \rm g}{32.06\; \rm g \cdot mol^{-1}} \approx 1.94323\; \rm mol\end{aligned}\).

Each \(\rm SO_2\!\) molecule contains one sulfur atom. Therefore, assuming that all those (approximately) \(1.94323\; \rm mol\!\) of sulfur atoms were converted to \(\rm SO_2\) molecules through the reaction with \(\rm O_2\), (approximately) \(1.94323\; \rm mol\) of \(\!\rm SO_2\) molecules would be produced.

Calculate the mass of one mole of \(\rm SO_2\) molecules:

\(\begin{aligned}& M(\mathrm{SO_2})\\ &= 32.06 + 2\times 15.999 \\ &= 64.058\; \rm g \cdot mol^{-1}\end{aligned}\).

The mass of that \(1.94323\; \rm mol\) of \(\rm SO_2\) molecules would be:

\(\begin{aligned}& m(\mathrm{SO_2}) \\ &= n(\mathrm{SO_2}) \cdot M(\mathrm{SO_2}) \\ &\approx 19.4323\; \rm mol \\ &\quad \times 64.058\; \rm g \cdot mol^{-1} \\ &\approx 1.24\times 10^{2}\; \rm g\end{aligned}\).

The amount of calories that you will obtain by eating the energy bar is: 149 calories

Calories are a unit of energy measurement that expresses the amount of energy that a food can provide to the body when the food is digested and absorbed.

To solve this problem we must perform the following algebraic operations with the given information

Information about the problem:

Calculating how many calories are in 26 g carbohydrates we have:

Calories (26 g carbohydrates)= 26 * 4 calories

Calories (26 g carbohydrates)= 104 calories

Calculating how many calories are in 5 g fat we have:

Calories (5 g fat)= 5 * 9 calories

Calories (5 g fat)= 45 calories

Calculating how many calories are in the energy bar we have:

Calories (energy bar)= 104 calories + 45 calories

Calories (energy bar)= 149 calories

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Answer: Plants and animals share many characteristics, but they are different in some respects hope that helps-

Explanation:

The wavelength in nm of a wave that has a frequency of 2.22 x 10¹⁴ Hz is 1.35 × 10-⁶ m.

Wavelength is the length of a single cycle of a wave, as measured by the distance between one peak or trough of a wave and the next.

Wavelength is denoted by λ, and corresponds to the velocity of the wave divided by its frequency i.e. λ = v/f

According to this question, the frequency of a wave is given as 2.22 x 10¹⁴ Hz. The wavelength can be calculated as follows:

λ = 3 × 10⁸ ÷ 2.22 x 10¹⁴

λ = 1.35 × 10-⁶ m

Therefore, 1.35 × 10-⁶ m is the wavelength of the wave.

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Answer:

0.02L

Explanation:

Using the formula V1/T1 = V2/T2

Given

V1 = 0.5L

T1 = 25 degrees

T2 = 1 degree

V2 =?

Substitute

0.5/25 = V2/1

Cross multiply

25V2 = 0.5

V2 = 0.5/25

V2 = 0.02L

Hence the new volume will be 0.02L

Three is no change in the blue litmus but the red litmus change color. This is because the ammonia turns red litmus blue due to ammonia.

When ammonium chloride and sodium hydroxide are mixed, they undergo a neutralization reaction to form ammonium hydroxide and sodium chloride. The chemical equation for this reaction is:

NH4Cl + NaOH → NH4OH + NaCl

In this equation, NH4Cl represents ammonium chloride, NaOH represents sodium hydroxide, NH4OH represents ammonium hydroxide, and NaCl represents sodium chloride.

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Bromine is more reactive than krypton because of its electronic configuration. Bromine is a member of the halogen family, meaning it has seven valence electrons in its outermost shell. This makes bromine more reactive than krypton, which has eight valence electrons in its outermost shell.

Bromine has a higher reactivity because it is more willing to accept electrons, which allows it to form bonds with other elements more easily.

This is due to the fact that bromine has the ability to form a stable octet of electrons in its outermost shell by gaining one more electron as its valence shell has 4s²4p⁵.

On the other hand, krypton has a full outer shell of eight electrons 4s²4p⁶, and it is not as willing to accept additional electrons, making it less reactive. Therefore, bromine is more reactive than krypton in the periodic table.

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Answer:

B

Explanation:

Molarity measures the strength of a solution. Remember, a solution is made up of two parts: the solvent (which does the dissolving) and the solute (the substance that is dissolved). The more solute there is, the higher the concentrate and therefore the higher the molarity of the solution. Thus B is the answer

Answer:Aluminum metal in silver nitrate ….

You might be expecting silver metal, Ag, and aluminum nitrate, Al(NO3)3, as products. But instead all you will end up with is wet aluminum. The passivating layer of Al2O3 will prevent aluminum from reducing silver ions.

Explanation: Al(s) + AgNO3(aq) → No reaction

The two things we might do to the mixture to disrupt the Al2O3 surface will cause the Ag+ ions to react. Often a source of chloride ion is used because AlCl4^- will form, exposing the aluminum surface. But that will cause AgCl(s) to precipitate. You can also make the solution basic with NaOH and form Al(OH)4^-, but that will cause Ag2O(s) to form. (You will get Ag2O instead of AgOH.)

Concentrated acids will oxidize any aluminum metal that might be exposed if you were to add concentrated HNO3. That would simply enhance the

If excess ammonium sulfate reacts with 20.0g of calcium hydroxide then liters of ammonia are produced at STP 0.081L

Ammonium sulphate is the organic solvent and the primary use of ammonium sulphate is as a fertilizer for alkaline soils

Here given reaction is

(NH₄)₂SO₄ + Ca(OH)₂ → CaSO₄ + NH₃ + H₂O

Here given data is

Calcium hydroxide  = 20.0g

We have to find liters of ammonia are produced at STP =?

20.0g of (NH₄)₂SO₄ STP = ?

Then 20.0g of (NH₄)₂SO₄×1 mol/132g×0.54L/1 mol = 0.081L

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Answer:

27

Explanation:

Answer:

Map scale refers to the relationship (or ratio) between distance on a map and the corresponding distance on the ground.

Explanation:

For example, on a 1:100000 scale map, 1cm on the map equals 1km on the ground.

Crystallization of sugar in a syrup can be avoided by adding inverted sugar. Invert sugar is a mixture of glucose and fructose, produced from sucrose. It is produced by hydrolysis of sucrose by heating with water and an acid such as lemon juice, vinegar or cream of tartar.

By adding invert sugar to a syrup, it reduces the amount of sucrose present in the solution and promotes the formation of glucose and fructose. This causes the solution to become more saturated and the syrup less likely to crystallize. Invert sugar is often used in the production of confectionery, ice cream, and other sweets.Inverted sugar can also be used to improve the texture and quality of baked goods. It is often used in cake recipes to enhance the flavor and increase the shelf life. It can also be used as a substitute for honey or corn syrup in recipes that require a liquid sweetener.In conclusion, the addition of invert sugar helps to prevent crystallization of sugar in syrup. Invert sugar is a mixture of glucose and fructose produced from sucrose by hydrolysis.

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Answer:

last one

Explanation:

Answer:

full moon

hope this helps

The energy in the ground state of the electron confined in a 10 nm box is approximately 10.89 eV, and the energy in the first excited state is approximately 43.56 eV.

To calculate the energy of an electron confined in a 10 nm box, we can use the formula for the energy levels of a particle in a one-dimensional infinite potential well:

E_n = (n^2 * h^2) / (8 * m * L^2)

where:

E_n is the energy of the nth energy level,

n is the quantum number of the energy level (n = 1 for the ground state),

h is the Planck's constant (6.626 x 10^-34 J·s),

m is the mass of the electron (9.10938356 x 10^-31 kg),

L is the length of the box (10 nm = 10 x 10^-9 m).

Let's calculate the energy in the ground state (n = 1) and the first excited state (n = 2):

For the ground state (n = 1):

E_1 = (1^2 * h^2) / (8 * m * L^2)

Substituting the values:

E_1 = (1^2 * (6.626 x 10^-34 J·s)^2) / (8 * (9.10938356 x 10^-31 kg) * (10 x 10^-9 m)^2)

Calculating this expression will give us the energy in the ground state.

For the first excited state (n = 2):

E_2 = (2^2 * h^2) / (8 * m * L^2)

Substituting the values:

E_2 = (2^2 * (6.626 x 10^-34 J·s)^2) / (8 * (9.10938356 x 10^-31 kg) * (10 x 10^-9 m)^2)

Calculating this expression will give us the energy in the first excited state.

Please note that the energies calculated will be in joules (J). If you prefer electron volts (eV), you can convert the results by dividing by the electron volt value (1 eV = 1.602 x 10^-19 J).

Performing the calculations:

For the ground state:

E_1 = (1^2 * (6.626 x 10^-34 J·s)^2) / (8 * (9.10938356 x 10^-31 kg) * (10 x 10^-9 m)^2) ≈ 1.747 x 10^-18 J

For the first excited state:

E_2 = (2^2 * (6.626 x 10^-34 J·s)^2) / (8 * (9.10938356 x 10^-31 kg) * (10 x 10^-9 m)^2) ≈ 6.987 x 10^-18 J

Converting the energies to electron volts (eV):

E_1 ≈ 10.89 eV (rounded to two decimal places)

E_2 ≈ 43.56 eV (rounded to two decimal places)

Therefore, the energy in the ground state of the electron confined in a 10 nm box is approximately 10.89 eV, and the energy in the first excited state is approximately 43.56 eV.

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In the aforementioned reaction, hydrogen is required for 50.0 g ion nitrogen to completely react, hence 10.80 g of hydrogen are required. This indicates that 0.5 moles or barium chloride and 1 mole or silver chloride will combine to generate 1 mole ion silver chloride.

The mole ratio based just on stoichiometric coefficients can be used to calculate how much hydrogen gas will totally react with nitrogen after we have the chemical equation that is balanced. In order for hydrogen and nitrogen to totally react, 7.8 moles are required.

A double displacing reaction occurs when silver nitrate and barium chloride are combined. They swap ionic components in this process. The end results would then be barium nitrate and silver chloride.

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Answer:

Explanation:

because they want to make us aliens

The difference in binding energy per nucleon between 23/11 Na and 23/12 Mg can be calculated by finding the total binding energy for each isobar and dividing it by the respective number of nucleons.

To calculate the difference in binding energy per nucleon between the isobars 23/11 Na and 23/12 Mg, we need to find the total binding energy for each isobar and then divide it by the respective number of nucleons.

The atomic mass of 23/11 Na is 23, which means it has 23 nucleons (protons and neutrons). The atomic number is 11, indicating it has 11 protons.

The atomic mass of 23/12 Mg is also 23, so it has 23 nucleons. However, the atomic number is 12, indicating it has 12 protons.

We can use the equation:

Binding Energy per Nucleon = (Total Binding Energy) / (Number of Nucleons)

To find the total binding energy, we can consult a table or use an approximate average value. Let's assume the average binding energy per nucleon for both elements is 8.5 MeV (million electron volts).

For 23/11 Na:

Binding Energy per Nucleon = (Total Binding Energy of Na) / (Number of Nucleons)

                         = (8.5 MeV) / (23 nucleons)

For 23/12 Mg:

Binding Energy per Nucleon = (Total Binding Energy of Mg) / (Number of Nucleons)

                         = (8.5 MeV) / (23 nucleons)

The difference in binding energy per nucleon can then be calculated by subtracting the value for Na from the value for Mg.

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The best statements that describe the effect of concentration on the rate of a reaction are:

1. Higher concentrations result in more collisions, therefore increasing the rate of a reaction.
2. Higher concentrations result in more effective collisions, therefore increasing the rate of a reaction.

These two statements explain that as the concentration of reactants increases, the number and effectiveness of collisions between particles increase, leading to a higher reaction rate. Increasing the concentration of reactants in a chemical reaction can affect the rate of the reaction. This is because higher concentrations of reactants increase the frequency of collisions between particles, leading to more chances of successful collisions and thus increasing the rate of the reaction.

Statement 1 is correct because higher concentrations result in more collisions among reactant particles, increasing the chances of successful collisions and thus increasing the rate of the reaction.

Statement 2 is also correct because higher concentrations lead to more effective collisions, meaning that a higher proportion of the collisions have enough energy and proper orientation to result in a reaction. This increases the rate of the reaction.

Statement 3 is not correct. Higher concentrations actually result in more effective collisions, not less effective collisions, as explained above.

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Answer:

Explanation:

They play a very important part. The geometry is not a straight line. It is an angle over 90 which means that the molecule has the same general shape as a boomerang. The two hydrogens and the 2 lone electron pairs try to get away as far as possible from each other. The actual shape results in a tetrahedron shape. But the two hydrogens and 1 oxygen actually look like the aforementioned boomerang.

Answer:

hii

needed points

Elodea leaf was the subject of a test by Ms. Sanchez. Using a light source and oxygen gas, she conducted an experiment in which she counted the number of bubbles emitted by an elodea leaf.

Elodea plants transfer the created oxygen from leaves to stem during photosynthesis. A small amount of oxygen escapes from the leaves to generate oxygen bubbles in the water, but the majority of oxygen leaves the stem because the intracellular air spaces in the stem are greater.

The oxygen that surges up from an underwater plant's leaves. Plants create food and oxygen from carbon dioxide and water through a process known as photosynthesis.

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