h0 = 176 kj·mol-1 and i:!.g0 = 91.2 kj·mol-1 at 298 k. what is the value of i:!.g at 1000 k?

The phase transition which occurs when a substance increases temperature at constant pressure is solid to liquid. The correct option is A.

It can be seen in the attached diagram that when the substance is at 120 degrees C and 925 mmHg, it is in the solid phase. Then, if we increase the temperature while keeping the pressure as constant, it will change to the liquid phase.

The lines represent the combinations of pressures and temperatures where two phases can exist in equilibrium. In another words, these lines show phase change points. The line divides the solid and gas phases, defines sublimation (solid to gas) and deposition (gas to solid).

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Although part of your question is missing, you might be referring to this full question: Consider the phase diagram shown here. A sample of the substance in the phase diagram is initially at 120 degrees C and 925 mmHg. What phase transition occurs when a substance increases temperature at constant pressure?

a) solid to liquid

b) liquid to gas

c) solid to gas

d) liquid to solid

Based on the given information, the concentration of the titrant, NaOH, is 1.00 M. The burette contains 0.0 mL of NaOH, and the flask contains 100 mL of H₂SO4 of unknown concentration.

The goal is to determine the concentration of H₂SO4 using a titration method with NaOH and Bromothymol blue as an indicator.

During the titration process, NaOH is slowly added to the H₂SO4 solution until the solution reaches the equivalence point, where the moles of NaOH added are equal to the moles of H₂SO4 present in the solution. At this point, the pH of the solution should be 7.5, and the volume of NaOH added is recorded in the “mL NaOH” box.

Using the balanced chemical equation, H₂SO4 + 2NaOH → Na₂SO4 + 2H₂O, the moles of H₂SO4 present in the solution can be determined based on the volume of NaOH used and the known concentration of NaOH. The moles of H₂SO4 are then divided by the volume of H₂SO4 used, which is recorded in the “mL H₂SO4” box, to obtain the concentration of H₂SO4.

In summary, the concentration of the titrant, NaOH, is 1.00 M. The volume of NaOH used during the titration is recorded in the “mL NaOH” box, while the volume of H₂SO4 used is recorded in the “mL H₂SO4” box. The concentration of H₂SO4 can be calculated using the known concentration of NaOH, the volume of NaOH used, and the balanced chemical equation.

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Based on the given information, the concentration of the titrant, NaOH, is 1.00 M. The burette contains 0.0 mL of NaOH, and the flask contains 100 mL of H₂SO4 of unknown concentration.

The goal is to determine the concentration of H₂SO4 using a titration method with NaOH and Bromothymol blue as an indicator.

During the titration process, NaOH is slowly added to the H₂SO4 solution until the solution reaches the equivalence point, where the moles of NaOH added are equal to the moles of H₂SO4 present in the solution. At this point, the pH of the solution should be 7.5, and the volume of NaOH added is recorded in the “mL NaOH” box.

Using the balanced chemical equation, H₂SO4 + 2NaOH → Na₂SO4 + 2H₂O, the moles of H₂SO4 present in the solution can be determined based on the volume of NaOH used and the known concentration of NaOH. The moles of H₂SO4 are then divided by the volume of H₂SO4 used, which is recorded in the “mL H₂SO4” box, to obtain the concentration of H₂SO4.

In summary, the concentration of the titrant, NaOH, is 1.00 M. The volume of NaOH used during the titration is recorded in the “mL NaOH” box, while the volume of H₂SO4 used is recorded in the “mL H₂SO4” box. The concentration of H₂SO4 can be calculated using the known concentration of NaOH, the volume of NaOH used, and the balanced chemical equation.

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Answer:

personally I think it's a but it could also be D.

But yeah personally I would say A

The polarity of a molecule can be expressed in terms of its moment, denoted by the symbol μ. This moment is defined as the product of the partial charges in the molecule and the distance between their centers.

A molecule is said to be polar if it has a non-zero dipole moment, which means that the partial charges are not evenly distributed across the molecule.
The polarity of a molecule has important implications for its chemical and physical properties. For example, polar molecules are more likely to dissolve in polar solvents, while non-polar molecules are more likely to dissolve in non-polar solvents. Additionally, the polarity of a molecule can affect its reactivity and its ability to participate in various chemical reactions.
The dipole moment of a molecule can be calculated using various methods, including experimental measurements and theoretical calculations. In general, molecules with polar bonds will have a non-zero dipole moment, while molecules with non-polar bonds will have a zero dipole moment. However, there are exceptions to this rule, and the overall polarity of a molecule is determined by the combination of its individual bond polarities.
In summary, the dipole moment of a molecule is a measure of its polarity, and it is determined by the partial charges in the molecule and the distance between them. Understanding the polarity of a molecule is important for understanding its properties and behavior in various chemical and physical environments.

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Answer:

See below

Explanation:

See the attached diagram which will answer a lot of your posted questions

Answer:

Ionic

Explanation:

Ionic compounds generally form between elements that are metals and elements that are nonmetals. For example, the metal calcium (Ca) and the nonmetal chlorine (Cl) form the ionic compound calcium chloride (CaCl2).

B is the correct answer

Answer:

3.5 meters

Explanation:

Answer:

A Punnet Square...the second I am not sure.

Explanation:

Unfortunately the second could be many things. You'd have to have more background information.

Answer:

PUNNETT....,MAKE SURE U HAVE 2 T,s

Explanation:

punnett and cross

The addition of HCl to the reaction mixture would alter the chemical equilibrium and shift the reaction towards the formation of aluminum hydroxide.

If HCl (hydrochloric acid) is added to the reaction mixture from the previous question, it would react with the NaAl(OH)4 (sodium tetrahydroxoaluminate) present in the mixture. The balanced chemical equation for this reaction would be:

HCl(aq) + NaAl(OH)4(aq) → Al(OH)3(s) + NaCl(aq) + H2O(l)

Here, the HCl would donate a proton to the NaAl(OH)4, resulting in the formation of Al(OH)3 (aluminum hydroxide), NaCl (sodium chloride), and H2O (water). This would be an acid-base reaction where HCl acts as an acid and NaAl(OH)4 acts as a base.

Since aluminum hydroxide is an insoluble solid, it would precipitate out of the solution as a white solid. This would be observed as a white cloudy appearance in the reaction mixture. Additionally, the solution would become more acidic due to the addition of HCl.

The presence of excess HCl in the solution could also lead to the dissolution of some of the aluminum hydroxide precipitate, resulting in a clearer solution.

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The molality of the solution is approximately 1.55 m. Therefore, the correct answer is A) 1.55 m.

To find the molality (m) of the solution, we need to determine the number of moles of the solute (propyl alcohol) and the mass of the solvent (water).

Given:

Mass of propyl alcohol (solute) = 35.0 g

Mass of water (solvent) = 200 g

Step 1: Convert the mass of propyl alcohol to moles.

First, we need to calculate the molar mass of propyl alcohol (C3H7OH):

C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol

Molar mass of propyl alcohol = (3 * 12.01 g/mol) + (8 * 1.008 g/mol) + 16.00 g/mol = 60.12 g/mol

Now, we can calculate the number of moles of propyl alcohol:

Number of moles of propyl alcohol = Mass of propyl alcohol / Molar mass of propyl alcohol

= 35.0 g / 60.12 g/mol

Step 2: Calculate the molality.

Molality (m) is defined as the number of moles of solute per kilogram of solvent.

Mass of water (in kg) = Mass of water (g) / 1000

Now we can calculate the molality:

Molality (m) = Number of moles of propyl alcohol / Mass of water (in kg)

= (35.0 g / 60.12 g/mol) / (200 g / 1000)

Simplifying the expression, we get:

Molality (m) = (35.0 g * 1000) / (60.12 g/mol * 200 g)

= 1.55 m (rounded to two decimal places)

Option A

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Answer:

30 I guess

Explanation:

The new pressure will be : 25 atm

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

\(\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}\)

P₁=15 atm

V₁=5 L

V₂= 3 L

\(\tt P_2=\dfrac{P_1.V_1}{V_2}\\\\P_1=\dfrac{15~atm\times 5~L}{3~L}\\\\P_1=\boxed{\bold{25~atm}}\)

Answer:

Final pressure of the air inside is 0.83atm

Explanation:

Boyle's law is the gas law that relates the change in volume when pressure change at constant temperature and vice versa. The equation is:

P₁V₁ = P₂V₂

Where P is pressure and V is volume of 1, initial state and 2, final state of the gas

Replacing:

P₁ = 0.5atm

V₁ = 2.5L

P₂ = ?

V₂ = 1.5L

P₁V₁ = P₂V₂

0.5atm*2.5L = P₂*1.5L

0.83atm = P₂

The empirical formula of the compound, given it contains 19.3% Na, 26.9% S, and 53.8% O is NaSO₄

The following paameters were obtained from the question:

The empirical formula of the compound can be obtained as follow:

Divide by their molar mass

Na = 19.3 / 23 = 0.839

S = 26.9 / 32 = 0.840

O = 53.8 / 16 = 3.3625

Divide by the smallest

Na = 0.839 / 0.839 = 1

S = 0.840 / 0.839 = 1

O = 3.3625 / 0.839 = 4

Thus, the empirical formula of the compound is NaSO₄

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Complete question:

A compound is 19.3% Na, 26.9% S, and 53.8% O. Its formula mass is 238 g/mol. What is the empirical formula? Show your work in a neat and logical manner.

The shape of PbCl2 molecule is linear because there are only two atoms (Pb and Cl) bonded to the central atom (Pb) with no lone pairs. The bond angle is 180 degrees, which is the ideal angle for a linear molecule.

For the molecule PbCl2, the molecular shape and bond angle are as follows:
Shape: Linear
Bond Angle: 180 degrees
In PbCl2, the central atom is lead (Pb) with two chlorine (Cl) atoms bonded to it. The molecule has a linear shape, resulting in a bond angle of 180 degrees, which is also the ideal angle for this molecular geometry.

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Answer:

True.

Explanation:

The higher the 'Mol Concentration', the stronger the acid or base the substance is. For example...

1 Mol of HCl is less concentrated than 6 Mol HCl.

This is the same with bases:

1 Mol of NaOH is less concentrated than 6 Mol NaOH.

Yes!

Explanation:

If density is greater, the object sinks. Saturn is mainly composed of the lightest two gases known, hydrogen and helium. It is the only planet in our solar system whose density is less than water.

Svante Arrhenius, as a doctoral candidate, proposed the acid-base theory, which initially faced skepticism from his professors who thought his ideas were unfounded. However, within a decade, the Arrhenius theory was widely accepted and praised in the scientific world. In his theory, Arrhenius defined acids as compounds having ionizable hydrogen, and bases as compounds with ionizable hydroxide ions (OH-).

Arrhenius proposed his theory of acids and bases in 1884 as part of his doctoral thesis. At the time, his ideas were met with skepticism and criticism from his professors and peers, who were more accustomed to the older, classical theories of acids and bases.

However, Arrhenius's theory was eventually accepted and became widely praised within the scientific community. This was in part due to the experimental evidence that supported his theory and the way that it could be used to explain a wide range of chemical phenomena.

In Arrhenius's theory, an acid is a substance that dissociates in water to produce hydrogen ions (H+), while a base is a substance that dissociates in water to produce hydroxide ions (OH-). This theory provided a new and more comprehensive understanding of the behavior of acids and bases and laid the foundation for further research in this area.

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Answer:

thats alot and makes no since

Answer:

Explanation:

The required volume flow rate of liquid ethyl alcohol to supply at a rate of 2000 kJ/s is approximately 164.9 L/min.

To determine the required volume flow rate of liquid ethyl alcohol, we need to calculate the fuel flow rate first. Then, we can convert it to volume flow rate.

Given:

Rate of energy release (Q) = 2000 kJ/s

Excess air = 40% (or 0.4)

First, let's calculate the fuel flow rate (m f):

Q = m f × Lower Heating Value (LHV)

The Lower Heating Value (LHV) for ethyl alcohol can be calculated using the enthalpy of vaporization:

LHV = enthalpy of vaporization / molecular weight of fuel

LHV = 42,340 kJ/k mol / 46.07 kg/k mol = 920.11 kJ/kg

Now, we can calculate the fuel flow rate:

m f = Q / LHV

m f = 2000 kJ/s / 920.11 kJ/kg ≈ 2.173 kg/s

Next, let's convert the fuel flow rate to volume flow rate:

Volume flow rate (V f) = m f / density

V f = 2.173 kg/s / 790 kg/m³ = 0.002749 m³/s

Finally, we can convert the volume flow rate to L/min:

V f = 0.002749 m³/s × (1000 L/1 m³) × (60 s/1 min) ≈ 164.9 L/min

Therefore, the required volume flow rate of liquid ethyl alcohol to supply at a rate of 2000 kJ/s is approximately 164.9 L/min.

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Answer:

have g8igcicg9ccgco

Explanation:

gcohogxzrxog floor. gi gi gi gi. r. uvgi7rz. g yde6ifkg. gg g goog oh g of ifz8fd8dti

Answer:

By using an electronegativity table (a periodic table with electronegativity values), you can find the difference between the two elements of the molecule and then determine its polarity based on the following criteria:

Nonpolar Covalent Bond: < 0.4

Polar Covalent Bond: between 0.4 and 1.8

Ionic Bond: > 1.8

Example:

Let's we are given the diatomic molecule, HCl.

Electronegativity of H: 2.1

Electronegativity of Cl: 3.0

Find the difference by subtracting the smaller value from the bigger one:

3.0 - 2.1 = 0.9

0.9 is between 0.4 and 1.8; thus it is a polar covalent bond.

The aqueous solutions can be arranged in increasing boiling point order as follows: 0.050m Al(ClO4)3 < 0.110m K2CO3 < 0.300m C6H12O6.

The boiling point of a solution is influenced by the concentration of solute particles in the solution. The greater the concentration of solute particles, the higher the boiling point. In this case, we are comparing the boiling points of three different aqueous solutions.

The solution with the lowest boiling point is 0.050m Al(ClO4)3. This is because Al(ClO4)3 is an ionic compound that dissociates into multiple ions in water, thereby increasing the number of solute particles. Higher concentration of solute particles raises the boiling point.

The solution with the next higher boiling point is 0.110m K2CO3. K2CO3 is also an ionic compound and dissociates into two ions in water. Although the concentration is higher compared to Al(ClO4)3, it is lower than that of C6H12O6.

The solution with the highest boiling point is 0.300m C6H12O6. C6H12O6, which is glucose, is a molecular compound and does not dissociate into ions in water. Therefore, it has the lowest concentration of solute particles among the given solutions, resulting in the lowest boiling point.

Hence, the correct order of increasing boiling points is 0.050m Al(ClO4)3 < 0.110m K2CO3 < 0.300m C6H12O6.

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When we have a chemical reaction, the speed of the reaction will depend on different factors such as concentration, temperature, or pressure.

If we assume that the temperature and pressure remain constant, it will be the concentration that will determine the rate of reaction for a non-zero order reaction.

If the concentration of the reactants decreases, the reaction rate also decreases, therefore, if the reactants are depleted, the reaction rate decreases.

Answer: D. The rate of the reaction slows down.

Explanation

Given:

ΔG° = 13.8 kJ/mol = (13.8 x 1000) J/mol = 13800 J/mol

Temperature, T = 25.0°C. = 25.0°C + 273 = 298.0 K

What to find:

the value of the equilibrium constant, K for the reaction at 25.0°C.

Step-by-step solution:

Both K and ΔG° can be used to predict the ratio of products to reactants at equilibrium for a given reaction.

ΔG° is related to K by the equation ΔG°= −RTlnK.

R is the molar gas constant, ( R = 8.3144598 J/K/mol)

If ΔG° < 0, then K > 1, and products are favored over reactants at equilibrium.

The next step is to substitute the values of ΔG° and T into the equation to get K.

ΔG°= −RTlnK

13800 J/mol = -(8.3144598 J/K/mol x 298 K x lnK)

13800 J/mol = -(2477.70902 J/mol x lnK)

Divide both sides by 2477.70902 J/mol