given how the quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is

Answer:

The field strength needed to produce a 24.0 V peak emf is 0.5913 T

Explanation:

From the formula for maximum emf of a generator,

\(emf_{max}= NAB\omega\)

∴ \(B = \frac{emf_{max} }{NA\omega}\)

Where N is the number of loops

A is cross section of loops

B is magnetic field strength

ω is the angular frequency of loops

From the question, \(emf_{max} = 24.0V\)

N = 300 turns

A = l × b ( since it is a rectangular coil)

A = 6.46 cm × 5.00 cm

A = 0.0646 m × 0.05 m

A = 0.00323 m²

ω = 400 rpm = (400/60)×2π rad/s

ω = 41.8879 rad/s

Putting all the parameters into the formula

\(B = \frac{emf_{max} }{NA\omega}\)

\(B = \frac{24.0}{300\times0.00323\times41.8879}\)

\(B = 0.5913T\)

Hence, the field strength needed to produce a 24.0 V peak emf is 0.5913 T

Answer:

10g to kg=0.01

20×0.01=0.2

Force of 0.2N

The nuclear fusion reaction, which occurs in the star's core, is responsible for this. In stars that are more massive than the Sun, heavier elements such as iron and nickel are formed and ejected into the interstellar medium through supernova explosions. However, in the case of a 1-M star, the fusion process only produces helium, carbon, and nitrogen.

The answer is Hydrogen. Explanation: In terms of chemical elements, a single 1-M star will eventually eject significant amounts of hydrogen into the interstellar medium. Once the helium in the core has been exhausted, the outer layers of the star begin to expand and cool. It becomes a red giant as a result of this process. The star's outer layers eventually expand so far that they are lost, forming a planetary nebula. The core of the star, which is now exposed, emits ultraviolet radiation that ionizes the planetary nebula's gases, causing it to glow brightly. The core is now known as a white dwarf, which gradually cools and dims over time.

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A single 1-M star will eventually eject significant amounts of hydrogen, iron, nickel, and other chemical elements into the interstellar medium.

A 1-M star, also known as a solar-mass star, goes through several stages of stellar evolution. Initially, it burns hydrogen in its core, producing helium through nuclear fusion. As the star evolves, it undergoes a series of nuclear reactions, leading to the synthesis of heavier elements. During the red giant phase, the star expands and loses its outer layers, which results in the ejection of significant amounts of hydrogen and other light elements into the interstellar medium.

Additionally, during the late stages of a 1-M star's life, it undergoes a supernova explosion, which releases enormous amounts of energy and leads to the synthesis of even heavier elements like iron and nickel. These elements are synthesized through nuclear reactions occurring during the explosive event. The explosion disperses these newly formed elements into space, enriching the interstellar medium with iron, nickel, and other elements.

Therefore, a single 1-M star will indeed eject significant amounts of hydrogen, iron, nickel, and various other chemical elements into the interstellar medium throughout its evolution and, particularly, during the supernova explosion at the end of it.

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The speed of the car after 5 seconds, given that the car has a uniform acceleration of 2 m/s² is 10 m/s

The following data were obtained from the question:

The final speed of the car can be obtained as demonstrated below:

v = u + at

Inputting the various parameters, we have

v = 0 + (2 × 5)

Clear bracket

v = 0 + 10

v = 10 m/s

Thus, from the above calculation, we conclude that the speed after 5 seconds is 10 m/s

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Clear question:

A car starts at rest and has a uniform acceleration of 2 m/s² .Find the speed of the car the car after 5 seconds.

dP/dt = (0.831 - 0.2P) / 100, where P represents pressure (in kilopascals).

This equation represents the rate at which the pressure is changing with the given conditions of temperature and volume.

To find the rate at which the pressure is changing, we need to use partial derivatives. Given the equation PV = 8.31T, we can differentiate both sides of the equation with respect to time t.

Differentiating both sides with respect to time t, we get:

P(dV/dt) + V(dP/dt) = 8.31(dT/dt)

Now, let's substitute the given values:

dT/dt = 0.1 K/s (rate of temperature change)

dV/dt = 0.2 L/s (rate of volume change)

T = 300 K (temperature)

V = 100 L (volume)

Plugging in the values into the equation:

P(0.2) + 100(dP/dt) = 8.31(0.1)

0.2P + 100(dP/dt) = 0.831

Now, we can solve for dP/dt:

100(dP/dt) = 0.831 - 0.2P

dP/dt = (0.831 - 0.2P) / 100

Therefore, the rate at which the pressure is changing when the temperature is 300 K and increasing at a rate of 0.1 K/s, and the volume is 100 L and increasing at a rate of 0.2 L/s is given by:

dP/dt = (0.831 - 0.2P) / 100

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The presence of a polar covalent bond show that the electronegativities of the two atoms are not equal.

What does polar covalent bond means?

A polar covalent bond is a type of chemical bond between two atoms in which the electrons are unequally shared between the two atoms, resulting in a molecule with an electric dipole moment. The atoms in a polar covalent bond have different electronegativities and the electron cloud is distorted, creating a partial positive charge on one atom and a partial negative charge on the other.

The presence of a polar covalent bond indicates that the two atoms have different electronegativities. One atom will have a higher electronegativity than the other, meaning that the electron pair is pulled more towards it and forms a slightly negative charge. The other atom will have a lower electronegativity, resulting in a slightly positive charge.

Therefore, it show that the electronegativities of the two atoms are not equal.

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Given data:

* The mass on the frictionless table is,

* The mass hangs freely from the string is,

* The hanging mass falls a distance is,

Solution:

(1). The normal force of mass on the frictionless table is,

As the displacement of the mass m_1 on the frictionless table is in the hroizontal direction.

Thus, the work done by teh normal force is,

As both the normal force and displacement are perpendicuular to each other.

Thus, the work done by the nromal force on the mass m_1 is,

Thus, the work done by the normal force on m_1 is zero.

Given:

Someone is lying on the bed.

To find:

A) the internal forces on the mattress

B) The external forces on the mattress

Explanation:

A) The internal forces acting on the mattress are:

1. When someone lies on the mattress, there is tension inside the mattress.

2. There is compression on the mattress.

3. Also there are torsion and shear

B) The external force:

The external forces are the

1. The force of gravity or the weight of the person on the mattress

2. The normal reaction on the mattress

3. The friction between the mattress and the person

The volume of the 400g bag of flour is 666.67 cm^3.

This question asks for the calculation of the volume of a 400g bag of flour with a density of 0.6 g/cm^3. The density of a material is defined as its mass per unit volume, and can be expressed mathematically as:

density = mass/volume.

Rearranging the equation to solve for volume, we get:

volume = mass/density.

Substituting the given values, we get:

Volume = 400 g / 0.6 g/cm^3

Solving for the volume, we get:

Volume = 666.67 cm^3
Volume = 400g / 0.6 g/cm^3, which simplifies to 666.67 cm^3.
Therefore, the volume of the 400g bag of flour is 666.67 cm^3.

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--The complete Question is, If a 400g bag of flour has a density of 0.6 g/cm^3, what is its volume in cm^3? --

Answer:

\(R\$37,96\)

Explanation:

1) Olá, vamos calcular primeiramente o Volume da Piscina. Ela é uma piscina com uma forma tradicional, retangular. Temos a largura, o comprimento e a profundidade.

\(Volume=a.b.c\\\\Volume=largura*comprimento*altura\\Volume= 10*15*1,5\\Volume=225m^{3}\)

2) Precisamos fazer uma correlação entre a medida de capacidade (litro) e de volume, já que o custo é por litro d'água.

\(1 litro = 1dm^3\\1 m^{3}=1000 \:dm^{3}=1000 \:litros\\225\:m^{3}=225000\: litros\)

3) Observe que Francisco gasta 0,005 g de \(NaClO\) por semana.

Considerando que o mês tenha 4,5 semanas. E que quanto mais se trata a piscina mais se gasta Hipoclorito de Sódio. Temos uma relação diretamente proporcional.

Finalmente,

3.1) Rendimento do hipoclorito de produto em gramas por semana:

\(1 semana \rightarrow 0,005g\\4,5 semanas \rightarrow 0,0225g\)

3.2) Consumo mensal (y), considerando 4,5 semanas:

\(0,005g\rightarrow1 litro\\y\rightarrow225000\\y=1125 gramas \: para\: 225000 litros.\\\\1125gramas \:por\:litro\rightarrow 1 semana\\q \rightarrow 4,5\\q=5062,5 \:gramas=\:5,0625 Kg \:de \:NaClO\\\\\)

3.3)  O custo da manutenção, já que 18 kg de \(NaClO\)  custa R$ 135 e são grandezas diretamente proporcionais:

\(18 kg\rightarrow \$135\\5,0625 \:kg \:de \:NaOCl\rightarrow p\\p=\frac{5,0625*135}{18}=\frac{683.4375}{18} \therefore p=R\$37,96\)

Answer:

f=1.5MHz or f=1500Hz

Explanation:

f=v/λ

3×10⁸/2×10-⁵

f=1500Hz

f=1.5MHz

Answer:

Explanation:

Given:

P = 12 W

R = 270 Ω

t = 2.5 s

____________

Q - ?

Power:

P = I²·R

Current strength:

I = √ (P / R) = √ (12 / 270) ≈ 0.21 A

Charge:

Q = I·t = 0.21·2.5 = 0,525 C

Answer:

A. 2 kg

Explanation:

\(Force = 10N\\Acceleration = 5.0m/s^2\\Mass = ? = x\\Force = mass\times acceleration \\10 = x \times 5\\10 = 5x \\\frac{10}{5} =\frac{5x}{5} \\2=x\\\\Mass= 2kg\)

Answer:

240 Joules

Explanation:

work = f x d

16 newtons is the force

15 meters is the distance

15*16= 240

The two subatomic particles that contribute to the net charge of an ion are electrons and protons.

Atom is the smallest possible amount of matter which still retains its identity as a chemical element, now known to consist of a nucleus surrounded by electrons.

The atom is made up of three components called subatomic particles as follows;

The proton is the positively charged subatomic particle forming part of the nucleus of an atomwhile the electron is the subatomic particle having a negative charge and orbiting the nucleus.

This suggests that the two subatomic particles that contribute to the net charge of an ion are electrons and protons. That is;

Net charge = protons - electrons

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To determine the number of moles of F2 remaining after 3 mol of S have reacted, we need to consider the balanced chemical equation for the reaction between F2 and S. However, as the equation is not provided, we cannot provide an exact answer.

Assuming a simple stoichiometric ratio, let's consider the balanced equation:

F2 + S -> SF2

Based on this equation, for every 1 mol of S, 1 mol of F2 is required to react. Therefore, if 3 mol of S have reacted, we would expect 3 mol of F2 to have also reacted, assuming the reaction has gone to completion.

Since the initial mixture contained 9 mol of F2, and 3 mol of F2 have reacted along with the 3 mol of S, the remaining number of moles of F2 would be 9 - 3 = 6 mol.

Again, it's important to note that this is a simplified assumption based on a stoichiometric ratio, and the actual balanced equation may differ, which would affect the final result.

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Answer:

The  value  is  \(C =  21.07 ppm\)

Explanation:

From the question we are told that

 The volume of the first  aliquot is \(V_a1  =  25.0 \  mL\)

 The  volume after dilution is  \(V_A =  50.0mL\)

 The  Absorbance of the first solution  is  \(A_1 =  0.656\)

 The  wavelength at which the absorbance occurred is   \(\lambda _1 =  348 nm  =  348*10^{-9} \  m\)

    The  length of the cell \(l  = 2.50 \  cm\)

    The volume the second  aliquot is \(V_{a2}  =  25.0 \  mL\)

     The  volume of the solution it was mixed with is  \(V_s  =  10.00mL\)

     The  concentration of quinine in the 10 mL solution  \(Z =  25.7ppm\)

    The volume of the second solution after dilution is \(V_d = 50.0 mL\)

      The  absorbance of the second solution is \(A_2 =  0.976\)

Generally the concentration of quinine is mathematically represented as

         \(C =  \frac{A_1 *Z *  V_s  }{(A_2 -A_1) V_{a2}}\)

=>    \(C =  \frac{ 0.656  *  25.7 *  10.0}{ (0.976 -  0.656) *  25}\)

=>   \(C =  21.07 ppm\)

The total number of \(Al^{+3}\) ions (aluminum cations) needed to b transferred in the current is 72917 using principles of electrochemistry.

Total charge transferred is given to be \(0.035\\\) \(pC\).

Since, \(1 p C = 1\) × \(10^{-12}\) \(C\\\)

Total Charge (\(Q\)) = \(0.035\) × \(10^{-12}\)  \(C\)

Charge on each aluminum cation \(Al^{+3}\)  = Total charge of extra protons contained in each aluminum cation.

Charge on a single proton = \(1.6\) × \(10^{-19}\) \(C\)

Extra protons on each aluminum cation (\(Al^{+3}\)) = \(3\)

Thus charge on each aluminum cation (\(Al^{+3}\)) = \(3\) × \(1.6\) × \(10^{-19}\)

Now let the total number of aluminum cations (\(Al^{+3}\)) be \(n\).

Thus according to principles of electrochemistry:

\(n\) × \(3\) × \(1.6\) × \(10^{-19}\) = \(0.035\) × \(10^{-12}\)

Solving the equation for \(n\), we get \(n\) = \(72917\)

Thus, in total 72917 ions of \(Al^{+3}\) are needed to be transferred in the current.

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The correct question should be:

If 0.035pC of charge is transferred via the movement of Al3+ ions, how's many of these must be transferred in total?

Answer:

Workdone = 1250Nm

Explanation:

Given the following data;

Force, F = 500N

Distance, d = 2.5m

Workdone is given by the formula;

\( Workdone = force * distance\)

Substituting into the equation, we have

\( Workdone = 500 * 2.5 \)  

Workdone = 1250Nm

Therefore, the actual work done by the worker is 1250 Newton-meter.

The actual work done by the worker is 1250 J.

Work can be defined as the product of force and distance. The s.i unit of work is Joules

The formula of work is

W = Fd....................... Equation 1

Where W = work done by the worker, F = Force, d = distance.

From the question,

Given: F = 500 N, d =  2.5 m

Substitute these values into equation 1

W = 500×2.5

W = 1250 J

Hence, the actual work done by the worker is 1250 J

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a tendency of a body to do nothing or to remain unchanged.

Answer:

a tendency to do nothing or to remain unchanged.

Explanation:

Answer:

Waves come in two kinds, longitudinal and transverse. Transverse waves are like those on water, with the surface going up and down, and longitudinal waves are like of those of sound, consisting of alternating compressions and rarefactions in a medium.

I'm not quiet sure what exactly this question is asking but some examples of vectors include displacement, velocity, position, force, and torque.

The inclination angle of an object is related to the frictional force in that as the angle increases, the frictional force required to prevent sliding also increases.

The inclination angle of an object refers to the angle at which it is tilted or inclined relative to a horizontal surface. The relationship between inclination angle and frictional force can be understood using a free body diagram.

Consider an object on an inclined plane. The force of gravity acting vertically downward can be broken down into two components: one parallel to the incline and one perpendicular to it. The component parallel to the incline is responsible for the object's tendency to slide down the plane. This force is known as the gravitational force component along the incline.

Frictional force acts opposite to the gravitational force component along the incline. It acts parallel to the incline and prevents the object from sliding down. The magnitude of the frictional force depends on the coefficient of friction and the normal force acting perpendicular to the incline.

As the inclination angle increases, the gravitational force component along the incline increases. Therefore, the frictional force needed to balance it also increases. This means that the frictional force is directly related to the inclination angle.

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The magnitude and the direction the boat go, relative to the straight line

across it is 15.81 m/s and 18⁰ respectively.

= √ ( 15² + 5² )

= √ ( 225  + 25 )

= √250

= 15.81 m/s

If boat makes angle θ with direction of flow of river

Tanθ = 15/5 = 3

θ = 72⁰ approx.

Angle with straight line across it = 90 - 72 = 18⁰

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Answer:

55.84 look at periodic table

so 55.84*3= 167.52gFe

The correct options for the factors that contribute to the Earth's magnetic field, which protects us from solar wind, are option b. the liquid outer core and option f. the Earth's rotation.

The Earth's magnetic field is generated by the motion of molten iron and nickel in the liquid outer core of the Earth (Option b). This motion, known as convection, generates electric currents that produce the magnetic field.

The Earth's rotation (Option f) also plays a significant role. The rotation of the Earth causes the convection currents in the liquid outer core to circulate and amplify the magnetic field, creating a dynamo effect.

The Earth's revolution (Option a) around the Sun and its tilt on its axis (Option c) are not directly responsible for the generation of the Earth's magnetic field. They are factors that influence climate and seasons on Earth but do not contribute to the magnetic field.

The seasons (Option d) are related to the Earth's axial tilt and its orbit around the Sun but are not directly connected to the generation of the magnetic field.

The solid inner core (Option e) is not involved in generating the Earth's magnetic field. It is mainly composed of solid iron and nickel and does not have the fluid motion required for the generation of a magnetic field.

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Answer:

Velocity = 94.85m/s

Explanation:

Given the following data ;

Height = 1200m

Vertical distance = 1050m

To find the time, we would use the second equation of motion;

\( S = ut + \frac {1}{2}at^{2}\)

Substituting into the equation, we have;

\( 1200 = 0(t) + \frac {1}{2}*9.8*t^{2}\)

\( 1200 = 0 + 4.9*t^{2} \)

\( 1200 = 4.9*t^{2} \)

\( t^{2} = \frac {1200}{4.9} \)

\( t = \sqrt{122.45}\)

t = 11.07 secs

To find the velocity;

Mathematically, velocity is given by the equation;

\(Velocity = \frac{distance}{time}\)

Substituting into the above equation;

\(Velocity = \frac{1050}{11.07}\)

Velocity = 94.85m/s

Therefore, the velocity of the water above 1050 m over the sea level is 94.85m/s.