g An object experiences a gravitational force of 38 Newtons. What force is needed to make the object remain still

Answers

Answer 1

The object is under the influence of two forces: weight (the gravitational force) and the applied force. Therefore, to make the object remain still, an applied force equal in magnitude and opposite in direction to the gravitational force of 38 Newtons is needed.

What is gravitational force?

Gravitational force is a force that attracts two objects with mass to one another. The equation of gravitational force is:

F = G (m₁m₂ / r²)

where,

F = gravitational force,

G = gravitational constant,

m₁ and m₂ = mass of the two objects,

r = distance between them.

What is force?

A force is any interaction that changes or tends to change the motion of an object. Force is a vector quantity with both magnitude and direction, represented by an arrow. The net force is the sum of all the forces acting on an object, which determines the object's motion according to Newton's laws of motion. The units of force are newtons (N).

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Related Questions

a computer's power supply converts mains ac to low-voltage regulated dc power for the internal components of a computer. you are building a new computer. you are deciding which type of power supply to install. which of the following definitions best describes a valid type of power supply?

Answers

In order to prevent overloading of any circuit, dual rail electrical supply includes independent tracks and P C B traces that are used to offset voltage sags between various circuits.

Using conductive paths, tracks, or signal traces etched from copper sheets laminated onto a non-conductive substrate, a printed circuit board, or PCB, is used to mechanically support and electrically link electronic components.

Semiconductors are used by practically all inverters to generate a controlled power output. An input voltage is rectified if the source has an ac input.

It is, therefore, the proper response.

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(PLSSS HELP)An object's velocity time graph can have (postivite,no,negative) change because the objects velocity is the(differnt,same) The same object can have a position time graph with a (negative, Positive, no) change because the object is moving away from the (initial , final) position.

Answers

Answer:

no, same, positive, initial

Explanation:

Suppose a spectral line of hydrogen, normally at 500 nm when measured in a lab on Earth, is observed in the spectrum of a star to be at 500.3 nm. This is called a red shift because the wavelength is longer (and red is on the long-wavelength side of the visible spectrum). How fast is the star moving away from Earth? Give your answer in m/s. Hint: follow example 5.6. Compare in particular to the "Check your learning" calculation, and note that larger Δλ means larger speed.

Answers

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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With what speed would a rock of mass 115g
have to be thrown if it were to have a
wavelength of 2.03 × 10−34 m?
Planck’s constant is 6.63 × 10−34 J · s.
Answer in units of m/s.

Answers

The speed of the rock is 56.8 m/s.

Wavelength, λ = 2.03 x 10⁻³⁴m

Mass of the rock, m = 115 x 10⁻³kg

So, the kinetic energy,

1/2 mv² = hc/λ

v = √(2hc/mλ)

v = √(2 x 6.63 x 10⁻³⁴/115 x 10⁻³x2.03 x 10⁻³⁴)

v = 56.8 m/s

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When a pole vaulter reaches the top of her vault, how does her potential energy compare to her kinetic energy?.

Answers

80% of the kinetic energy is converted into potential energy, since the pole is only 80% effective.

What is potential and kinetic energy?

Potential energy is the energy that is stored in any object or system as a result of its position.

∵ P.E = m×g×h

The energy of a moving object or system is known as Kinetic energy.

∵ K.E = 1/2×mv²

The kinetic energy(KE) is changed into gravitational potential energy(PEG) when a pole vaulter reaches the top of her vault.

He ran, converting his kinetic energy to gravitational potential energy.

  ∴ PEG = 0.8×KE.

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If force is made to act on a smaller area, then the pressure will be ______________

Answers

Pressure=force/area therefore pressure is inversely proportional to the area if the force is constant. As a result the pressure will be greater.

if 22.0 kg of ice at 0.00 °c is combined with 4.80 kg of water vapor at 100.0 °c, what will be the final equilibrium temperature (in °c) of the system

Answers

The final equilibrium temperature (in °C) of the system when ice and water vapor are combined can be calculated using the principle of energy conservation and the specific heat capacities of ice and water.

To determine the final temperature, we can apply the equation:

(m₁ * c₁ * ΔT₁) + (m₂ * c₂ * ΔT₂) = 0

Where:

- m₁ is the mass of ice (22.0 kg)

- c₁ is the specific heat capacity of ice (2.09 J/g·°C)

- ΔT₁ is the change in temperature of ice (final temperature - 0.00 °C)

- m₂ is the mass of water vapor (4.80 kg)

- c₂ is the specific heat capacity of water (4.18 J/g·°C)

- ΔT₂ is the change in temperature of water (final temperature - 100.0 °C)

Solving for the final temperature, we find:

(22.0 kg * 2.09 J/g·°C * ΔT₁) + (4.80 kg * 4.18 J/g·°C * ΔT₂) = 0

Substituting the given values, we can solve for ΔT₁ and ΔT₂. Once we have those values, we can find the final temperature by adding ΔT₁ to 0.00 °C.

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A large tank contains 100 gallons of pure water. Brine (a salt/water mixture) containing 4 pounds of salt per gallon flows into the tank at a rate of 5 gallons per hour. The well-mixed tank is drained at 3 gallons per hour. Let y(t) be the amount of salt (in pounds) in the tank at t≥0 hours since the mixing began. Set up an Initial Value Problem (IVP) for y(t) that models this situation. You DO NOT need to solve the IVP. Please put your final answer in the box.

Answers

The Initial Value Problem (IVP) for y(t) is given by the differential equation: dy/dt = 20 - (3/V(t)) * y(t), with the initial condition y(0) = 0.

To set up an Initial Value Problem (IVP) for the amount of salt in the tank, let's analyze the given information and formulate the differential equation.

Let:

- V(t) be the volume of water in the tank at time t (in gallons).

- y(t) be the amount of salt in the tank at time t (in pounds).

Given:

- The initial volume of water is V(0) = 100 gallons.

- Brine flows into the tank at a rate of 5 gallons per hour, so the rate of change of volume is dV/dt = 5.

- The concentration of salt in the brine is 4 pounds per gallon.

- The tank is well-mixed, so the salt is evenly distributed throughout the tank.

- The tank is drained at a rate of 3 gallons per hour, so the rate of change of volume is dV/dt = -3.

Based on the given information, we can establish the following relationships:

1. The rate of change of salt in the tank is equal to the rate of salt inflow minus the rate of salt outflow:

  dy/dt = (4 pounds/gallon) * (5 gallons/hour) - (y(t)/V(t)) * (3 gallons/hour).

2. The volume of water in the tank is decreasing due to drainage:

  dV/dt = -3 gallons/hour.

Therefore, the Initial Value Problem (IVP) for y(t) is given by the differential equation:

dy/dt = 20 - (3/V(t)) * y(t), with the initial condition y(0) = 0.

In this IVP, the rate of change of salt in the tank depends on the concentration of salt in the incoming brine, the rate of inflow, the rate of outflow, and the current amount of salt in the tank.

By solving this IVP, one can determine the function y(t) that represents the amount of salt in the tank as a function of time, considering the given conditions.

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How to complete ??? Thankssss

How to complete ??? Thankssss

Answers

1 - Incident ray

2 - Refracted ray

3 - Angle of incidence

4 - Angle of refraction

Describe refraction.

The bending of light as it travels through a medium with a varied refractive index is known as refraction. The speed of light changes as it moves from one medium, like air, to another, like water or glass. This causes the light to bend or change direction.

The angle at which the light strikes the interface between the two media and the disparity in refractive indices between the two media determine how much bending takes place. Total internal reflection is a phenomena where all of the light is completely reflected back into the original medium if the angle of incidence is large enough.

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what is the value of coefficient of friction force​

Answers

Answer:

There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force.There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S KThere is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S KMetal on leather 0.6 0.5There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S KMetal on leather 0.6 0.5Wood on leather 0.5 0.4There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S KMetal on leather 0.6 0.5Wood on leather 0.5 0.4Rubber on concrete, dry 0.9 0.7There is a frictional force between two objects that are not in relative motion. Such a force is called the static friction force....Friction coefficients.MATERIAL S KMetal on leather 0.6 0.5Wood on leather 0.5 0.4Rubber on concrete, dry 0.9 0.7wet 0.7 0.57

Explanation:

Greetings, I'm from my beloved Mexico
The coefficient of friction depends on the objects that are causing friction. The value is usually between 0 and 1 but can be greater than 1. A value of 0 means there is no friction at all between the objects; such is possible with Superfluidity.

Saair rushes to her car in order to hurry home and dressed for work . Failing to realize the dangers to driving under slick and icy conditions, she collides her 976.0 kg Mazda Miata into the rear of a 3178.p kg pick up truck which was at rest at the light on Lake Avenue . Ima's per-collision speed was 12.0 m/s . Determine the collision speed of the two entangled cars as they slide across the ice

Answers

The post collision speed of the Mazda Miata and the  pick up truck  as they slide across the ice are respectively 6.36 m/s and 5.64 m/s.

What is elastic collision?

An elastic collision is one in which the system does not experience a net loss of kinetic energy as a result of the collision.

Given that masses of the  Mazda Miata and the pick-up truck are respectively 976.0 kg  and 3178.0 kg.

Pre-collision speed of Ima = 12.0 m/s.

As the collision is elastic in nature,

The post collision speed of the Mazda Miata =

{(976.0 - 3178.0)/(976.0 - 3178.0)} × 12.0 m/s

= - 6.36 m/s.

The post collision speed of the pick up truck =

{(2×976.0)/(976.0 - 3178.0)} × 12.0 m/s

=5.64 m/s.

Hence, the post collision speed of  the two entangled cars  as they slide across the ice are respectively 6.36 m/s and 5.64 m/s.

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14. Determine the kinetic energy of a 1000-kg roller coaster car that is moving with a speed of
40.0 m/s.

Answers

Answer:

200,000 J

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 1000 \times {40}^{2} \\ = 500 \times 400\)

We have the final answer as

200,000 J

Hope this helps you

Hello!!

Sorry to contradict the before answer, but he's wrong.

The formula is correct:

k = 1/2 * mv²

If we replace it with our data:

k = 1/2 * (1000 kg) (40 m/s)²

Here is the problem, 40^2 is = 1600, so the result is wrong:

k = 500 Kg * 1600 m²/s²

And if we resolve it:

k = 800 000 Joules

Then the kinetic energy of the roller coaster car is 800 000 Joules.

acontainer is filled whith mercury to alevel of 10m whit water to alevel of 8m and whit oil to alevel of 5m the densities oil ,water and mercury are 0.8g/cm³,1g/cm³ and 13.6g/cm³ calculate the total pressure exerted by the liquids at the base​

Answers

Answer:

1450.4 KN\(m^{2}\)

Explanation:

Pressure = ρhg

where: ρ is the density of the liquid, h is the height and g the force of gravity.

Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury

So that,

i. Pressure of oil = ρhg

(ρ = 0.8 g/cm³ = 800 kg/m³)

                        = 800 x 5 x 9.8

                        = 39200

Pressure of oil = 39200 N\(m^{2}\)

ii. Pressure of water = ρhg

(ρ = 1 g/cm³ = 1000 kg/m³)

                                      = 1000 x 8 x 9.8

                                     = 78400

Pressure of water = 78400 N\(m^{2}\)

ii. Pressure of mercury = ρhg

(ρ = 13.6 g/cm³ = 13600 kg/m³)

                      = 13600 x 10 x 9.8

                      = 1332800

Pressure of mercury = 1332800 N\(m^{2}\)

So that,

Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800

                                               = 1450400

                                               = 1450.4 KN\(m^{2}\)

Total pressure exerted by the liquids at the base is 1450.4 KN\(m^{2}\).

Compile and share a list of "highly applicable tips" (8-10
points) related to organizational behavior and leadership. To
format your points properly, position yourself as a management
consultant who i

Answers

Each organization is unique, so tailor these tips to fit your specific context and needs. As a management consultant, I recommend assessing your organization's current state and identifying areas for improvement to implement these tips effectively.

As a management consultant, here is a compiled list of highly applicable tips related to organizational behavior and leadership:

1. Foster a positive organizational culture: Create a work environment that values collaboration, open communication, and employee well-being. Encourage a culture of respect, trust, and support.

2. Lead by example: As a leader, set a positive example through your actions and behaviors. Demonstrate the values and behaviors you expect from your team members.

3. Effective communication: Communication is crucial for building strong relationships and ensuring clarity. Practice active listening, provide constructive feedback, and encourage open and honest communication channels within the organization.

4. Empower and delegate: Trust your team members and empower them to take ownership of their work. Delegate tasks effectively, matching responsibilities with individuals' strengths and skills.

5. Encourage innovation and creativity: Foster an environment that encourages new ideas, creativity, and innovation. Provide opportunities for employees to contribute their ideas and reward innovative thinking.

6. Develop and support talent: Invest in employee development and provide opportunities for growth and learning. Offer training programs, mentorship, and coaching to help employees reach their full potential.

7. Build strong teams: Focus on building cohesive and high-performing teams. Foster collaboration, encourage diversity of thought, and promote teamwork to achieve collective goals.

8. Embrace change and adaptability: Organizational success often relies on the ability to adapt to changing circumstances. Encourage a mindset of flexibility, adaptability, and continuous improvement.

9. Practice ethical leadership: Uphold high ethical standards and lead with integrity. Make ethical decisions, promote fairness, and hold yourself and others accountable for ethical conduct.

10. Recognize and appreciate employees: Acknowledge and appreciate the contributions of your team members. Celebrate achievements, provide recognition, and offer rewards and incentives to motivate and retain talent.

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Write down 2 differences between electrical conductors and electrical insulators.

Answers

Answer:

electrical conductors help electric current to pass through it

electrical conductors are usually made of any metal

electrical insulator don't help electric current to pass through it

electrical insulators are made of non metals

hope it helped you

Explanation:

conductors allows free flow of electrons from one atom to another.

insulators restrict free flow of electrons

conductors allow electrical energy to pass through them

insulators do not allow electrical energy to pass through them

89) Two identical objects are placed in a room with a temperature of 20°C. Object A has a temperature of 50°C, while object B has a temperature of 90°C. What is the ratio of the net power emitted by object B to the power emitted by object A?
A) 1.7
B) 2.8
C) 81
D) 17
E) 21

Answers

The ratio of the net power emitted by object B to the power emitted by object A is 2.8

What is net power?

Net power is the difference between the power output of a device or system and the power input required to operate it. It is calculated by subtracting the power input from the power output. Net power is the measure of the efficiency of a system, and is calculated by dividing the net power output by the power input.

The net power emitted by an object is given by the Stefan-Boltzmann law, which states that the net power emitted per unit area is proportional to the fourth power of temperature. Thus, the ratio of the net power emitted by object B to the power emitted by object A is given by:
\(P_B/P_A = (T_B/T_A)^4\)
= (90/50)⁴
= 2.8

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What is the kinetic energy of a 5kg ball that is rolling 3m/s?

Answers

Answer:

22.5

Explanation:

As the mass is 5 kg,velocity is 3m/s so the derivation use for kinetic energy is 1÷2 mv*2 . By this derivation we will find out the kinetic energy

Two students are playing catch with a 0.20 kg baseball. The first student throws the ball at 25 m/s. How much work is done by the second student in stopping the ball?

Answers

Answer:

W = 62.5 J

Explanation:

Given that,

Mass of a baseball, m = 0.2 kg

Initial speed of first student, u = 25 m/s

Finally, the ball stops, v = 0

We need to find the work done by the second student in stopping the ball. We know that, work done is equal to the change in kinetic energy. It can be given by :

\(W=\dfrac{1}{2}m(v^2-u^2)\\\\W=-\dfrac{1}{2}mu^2\\\\W=-\dfrac{1}{2}\times 0.2\times(25)^2\\\\W=-62.5\ J\)

So, the required work done is 62.5 J.

Sally is riding her skateboard at 12.0 ft/s and passes under an apple tree. As she
moves past, she grabs a 2.0 kg branch with five apples right off the tree. Sally's mass
is 34 kg. What is her speed after grabbing the branch and apples?

Answers

Answer:

11.3

Explanation:

if the moon is highest in the sky in the morning at 6:00am, what phase will the moon be after one week?

Answers

If the moon is highest in the sky in the morning at 6:00am, it means that it is in its waning phase. This is because the moon rises later and later each day during its waning phase, eventually reaching its highest point in the morning.

After one week, the moon will have gone through approximately half of its cycle and will be in its third quarter phase. This is when the moon appears as a half-circle in the sky, with the right half illuminated. During this phase, the moon rises around midnight and sets around noon, making it visible during the morning hours. As the moon continues to wane, it will appear smaller and smaller in the sky until it reaches its new moon phase, which marks the beginning of a new lunar cycle. Understanding the phases of the moon is important for astronomers and anyone who wants to track the moon's position and movements in the sky.

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Imagine that you have an isotropic magnetized plasma with T ∥0

=T ⊥0

=T 0

. Double the magnetic field slowly compared to a gyroperiod, but fast compared to the energy transfer time between T ∥

and T ⊥

. What are the new values of T ∥

and T ⊥

(call them T ∥1

and T ⊥1

) ? Now let the plasma sit long enough for T ∥1

and T ⊥1

to mix by collisions and come to an isotropic temperature T 1

, but not long enough for the plasma to exchange energy with the outside world. What is T 1

? Reduce the magnetic field back down to its original value slowly compared to a gyroperiod, but fast compared to the energy transfer time between T ∥

and T ⊥

. What are T ∥2

and T ⊥2

? And after the plasma becomes isotropic, what is T 2

? This process is called 'magnetic pumping'.

Answers

The new values of T∥1 and T⊥1 will be equal to the original isotropic temperature T0.

When the magnetic field is doubled slowly compared to a gyroperiod but fast compared to the energy transfer time between T∥ and T⊥, the plasma remains magnetized, but the magnetic field becomes stronger. Since the energy transfer time between T∥ and T⊥ is much longer than the timescale of magnetic field doubling, the temperature anisotropy is not affected during this process. Therefore, T∥1 and T⊥1 remain equal to T0.

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a car of mass 2000 kg is driven by a force of 40 KN for 5 seconds. how much does its speed change

Answers

Based on the given information, we can calculate the change in velocity of the car using the following formula:

Change in velocity = (Force x Time) / Mass

Substituting the given values, we get:Change in velocity = (40,000 N x 5 s) / 2000 kg

Change in velocity = 100 m/s

Therefore, the speed of the car changes by 100 m/s.

What was not a positive benefit of Spanish exploration in Oklahoma?
A.
Future interactions between the Spanish and French would have a buffer zone.
B.
Historians gained a written account of Oklahoma in the 15th and 16th centuries.
C.
Geographers gained new knowledge about the continent of North America.
D.
The Spanish and American Indian tribes enjoyed exclusively friendly relations.

Answers

the answer is:

d. the spanish and american indian tribes enjoyed exclusively friendly relations.

Answer:

b. the spanish and american indian tribes enjoyed exclusively friendly relations.

Explanation:

Consider light falling on a single slit, of width 1.2 μm, that produces its first minimum at an angle of 32.3°.Randomized Variablesθ = 32.3°w = 1.2 μmCalculate the wavelength of the light in nanometers.

Answers

The wavelength of the light is approximately 650 nanometers.

To find the wavelength of light in this scenario, we can use the single-slit diffraction formula:

sinθ = mλ / w

where θ is the angle of the first minimum (32.3°), m is the order of the minimum (m = 1 for the first minimum), λ is the wavelength, and w is the width of the slit (1.2 μm).

Rearranging the formula to find the wavelength:

λ = w * sinθ / m

Now, plug in the given values:

λ = (1.2 μm) * sin(32.3°) / 1

λ ≈ 0.65 μm

Since 1 μm = 1000 nm, we convert the wavelength to nanometers:

λ ≈ 0.65 * 1000 nm

λ ≈ 650 nm

The wavelength of light is approximately 650 nanometers.

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all circuit conductors between the service equipment, the source of a separately derived system or other power supply source, and the final branch-circuit overcurrent device defines a(n) ? . a. branch circuit b. feeder c. outside branch circuit d. all of the above nec reference

Answers

The correct answer is b. feeder.

In the context of electrical circuits, a feeder is a set of conductors that connect the service equipment, the source of a separately derived system, or other power supply source to the final branch-circuit overcurrent device. The feeder conductors supply power to multiple branch circuits and are protected by an overcurrent device located at the point where the feeder connects to the branch circuits.

On the other hand, a branch circuit is a set of conductors that originates at the final overcurrent device protecting the circuit and supplies power to outlets, lighting fixtures, or appliances. An outside branch circuit is a branch circuit that extends beyond the walls of a building or structure.

The National Electrical Code (NEC) defines the terms "feeder" and "branch circuit" and specifies the requirements for their installation, protection, and use. It is important to distinguish between feeders and branch circuits to ensure compliance with the NEC and to maintain a safe and reliable electrical system.

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Please do a complete derivation from first principles
1. Wave equation A. Show that the conservation of momentum equation can be written in terms of the velocity potential as po (VO₁ + 1 VIV$1²) + Vp = 0, where ₁ = 4: B. Using the adiabatic equation

Answers

Wave Equation: The wave equation describes the propagation of waves, such as sound or water waves. It can be derived from the conservation of momentum equation and the adiabatic equation for an ideal fluid.

A. Conservation of Momentum:

Starting with the conservation of momentum equation, we have:

∂(ρu)/∂t + ∇⋅(ρu⊗u) = -∇p

Where:

- ρ is the density of the fluid.

- u is the velocity vector.

- t is time.

- ∇ is the gradient operator.

- ⊗ represents the tensor product.

- p is the pressure.

Now, let's assume that the fluid is incompressible (constant density), and the flow is irrotational (curl of velocity is zero). Under these assumptions, the equation simplifies to:

∂u/∂t + (u⋅∇)u = -∇p/ρ

B. Velocity Potential:

In irrotational flow, we can define a scalar field called the velocity potential, denoted by φ, such that the velocity vector u is the gradient of the velocity potential:

u = ∇φ

Using this relationship, we can express the time derivative of velocity as:

∂u/∂t = ∇(∂φ/∂t)

Substituting this into the conservation of momentum equation and dividing by the density ρ, we get:

∇(∂φ/∂t) + (∇φ⋅∇)∇φ = -∇(p/ρ)

Simplifying further, we have:

∇(∂φ/∂t) + (∇φ⋅∇φ) = -∇(p/ρ)

C. Adiabatic Equation:

The adiabatic equation relates pressure changes to changes in density for an adiabatic process in an ideal fluid. It can be expressed as:

p = κρ^γ

Where:

- κ is the adiabatic constant.

- γ is the heat capacity ratio.

D. Final Wave Equation:

Substituting the adiabatic equation into the simplified conservation of momentum equation, we get:

∇(∂φ/∂t) + (∇φ⋅∇φ) = -∇(κρ^(γ-1))

Dividing through by κ, rearranging terms, and using the fact that γ - 1 = 1/4, we obtain:

(1/κ)∇(∂φ/∂t) + (∇φ⋅∇φ) = -(ρ^(\(^{3/4}\))(1/κ)∇ρ

Now, since κ = 4, we can simplify further to:

(1/4)∇(∂φ/∂t) + (∇φ⋅∇φ) = -(ρ^\(^{3/4}\)))(1/4)∇ρ

And rounding to decimal places, we arrive at:

(1/4)∇(∂φ/∂t) + (∇φ⋅∇φ) = -0.25(ρ^\(^{3/4}\))∇ρ

This equation represents the wave equation in terms of the velocity potential.

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If a car is traveling 35 m/s for 200 seconds, how far will the car travel?

Answers

Hey I’m just setting up my profile so I’ll say fast

What happens to distance and velocity if the time to fall increases or decreases?

Answers

In free-fall motion the velocity is given by the following equation of motion:

\(v=v_0-gt\)

Where:

\(\begin{gathered} v=\text{ velocity} \\ g=\text{ acceleration of gravity} \\ t=\text{ time} \end{gathered}\)

Therefore, the velocity increases linearly with time. This happens if the object encounters no air resistance. In the case that there is air resistance the object will reach a terminal velocity.

In the case of distance, this is given by the following equation:

\(s=v_0t-\frac{1}{2}gt^2_{}\)

This means that the distance increases with time following a parabolic function.

help me to answer this please ​

help me to answer this please

Answers

Answer:

ok

Explanation:

A student is using a 68 ohm resistor to build a circuit with a voltage source. If the student
needs 0.72 amperes of current to flow through the resistor, what voltage should be used?

Answers

Answer:

48.96V

Explanation:

Given parameters:

Resistance  = 68Ω

Current  = 0.72A

Unknown:

Voltage  = ?

Solution:

According to ohm's law;

           V = IR

V is the voltage

I is the current

R is the resistance

  Now insert the parameters and solve;

      V  = 68 x 0.72 = 48.96V

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