The transformation of f(x) to g(x) involves a horizontal shift and a reflection. The function g(x) is a transformed version of f(x) obtained by translating f(x) to the left by 2 units along the x-axis.
Specifically, to obtain g(x) from f(x), we first shift f(x) two units to the left, and then we take the absolute value of the result.
This means that the graph of g(x) will be the same as the graph of f(x) for all values of x greater than or equal to -2, but will be reflected across the y-axis for all values of x less than -2.
In other words, the transformation of f(x) to g(x) involves a horizontal shift and a reflection.
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I need help, its due trm please ASAP!!!
From the situation described in the problem, we have that:
a) The sinusoidal function that models the depth of the water is given by: D(t) = 2sin(π/6x) + 3.
b) After 4 hours, the depth is of 4.732 meters.
How is the sine function defined?The sine function is defined as follows:
g(x) = a sin(bx+c)+d.
The coefficients are defined as follows:
a: amplitude.b: The period is of 2π/B.c: phase shift.d: vertical shift.For this problem, the minimum value is of 1 and the maximum value is of 5, having a difference of 4, hence the amplitude is found as follows:
2a = 4 -> a = 2.
A standard sine function with an amplitude of 2 varies between -2 and 2, while this varies between 1 and 5, meaning that it had a vertical shift up 3 units, and d = 3.
The period is of 12 hours, hence:
2π/B = 12
12B = 2π
B = π/6.
The function has no phase shift, hence c = 0 and the function is given by:
D(t) = 2sin(π/6x) + 3.
From point (4, 4.732) on the graph of the function, after 4 hours, the depth is of 4.732 meters.
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Solve for v.
28-3v=4v
Simplify your answer as much as possible
V =
Which graph represents y=x?
Answer:
the first one is correct
Step-by-step explanation:
The feet S and T of two verticL poles SR and TP are in line with a point Q on the same level ground. SR and TP are 5m and 9m respectively. S lies between Q and T and is 25m from Q. The angle of elevation of P from R is 30°. Calculate: the angle of elevation of P from Q correct to one decimal place
The angle of elevation from P to Q is 14.8°
How to calculate the angle of elevationThe angle of elevation of point P from point Q can be discovered by using the concept of similar triangles. Let's consider the right triangles QSR and QTP.
In triangle QSR, we have:
QS = 25m (given)
SR = 5m (given)
Utilizing the Pythagorean hypothesis, able to discover QR:
QR = sqrt(QS^2 + SR^2) = sqrt(25^2 + 5^2) = sqrt(650) ≈ 25.5m
Presently, in triangle QTP, we have:
QT = QR + RT = 25.5m + 9m = 34.5m (since SR and TP are in line)
We are given that the angle of elevation of P from R is 30°. This implies that point PRT is 30°.
Utilizing trigonometry in triangle QTP, able to discover the angle of elevation of P from Q:
tan(angle PQT) = TP / QT
tan(angle PQT) = 9m / 34.5m
point PQT = arctan(9m / 34.5m) ≈ 14.8°
Hence, the angle of elevation of P from Q is 14.8°, redress to one decimal place.
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d²v dt² v=2t² +7t+11 Find
The second derivative of v with respect to t, denoted as d²v/dt², is equal to 4
The second derivative of v with respect to t, we will differentiate v twice.
v = 2t² + 7t + 11
First, let's find the first derivative of v with respect to t (dv/dt):
dv/dt = d/dt (2t² + 7t + 11)
Using the power rule of differentiation, we differentiate each term separately:
dv/dt = 2(2t) + 7(1) + 0
dv/dt = 4t + 7
Now, let's find the second derivative of v with respect to t (d²v/dt²):
d²v/dt² = d/dt (4t + 7)
Again, using the power rule of differentiation, we differentiate each term separately:
d²v/dt² = 4(1) + 0
d²v/dt² = 4
Therefore, the second derivative of v with respect to t, denoted as d²v/dt², is equal to 4.
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The point ( ¯ 2 , 6 ) is plotted on a coordinate plane. Which statements are true? Select the two statements that are true. A. The reflection point across the y-axis is ( 2 , 6 ) . B. The reflection point across the y-axis is ( 2 , ¯ 6 ) . C. The reflection point across the y-axis is ( ¯ 2 , ¯ 6 ) . D. The reflection point across the x-axis is ( 2 , 6 ) . E. The reflection point across the x-axis is ( 2 , ¯ 6 ) . F. The reflection point across the x-axis is ( ¯ 2 , ¯ 6 ) .
Answer:The two true statements are:
A. The reflection point across the y-axis is (2, 6).
D. The reflection point across the x-axis is (¯2, ¯6).
Step-by-step explanation:
Answer:
The two true statements are:
A. The reflection point across the y-axis is (2, 6).
D. The reflection point across the x-axis is (¯2, ¯6).
Step-by-step explanation:
How do I find the value of x that make lines u and v parallel
=======================================================
Explanation:
The square marker in the top left corner tells us we have a 90 degree angle. The 8x+10 must also be 90 degrees for lines u and v to be parallel. Refer to the alternate exterior angle theorem. Ignore the diagonal lines. Your teacher likely put them there as a distraction.
8x+10 = 90
8x = 90-10
8x = 80
x = 80/8
x = 10
1. Samira wants to analyze the effect of drinking alcohol on the functioning capacity of the
liver. Her two research associates will conduct two separate studies about the same
topic. Ricochet will use an experiment approach. Tituba will use an observational study
approach. Determine what will be the difference between both studies.
A spherical balloon is being inflated. Its radius in centimeters after t minutes is given by r(t) = 3^3 square root of t +6, where 0
1. 6.2403
2. 0.7889
3. 4.3267
4. 0.2311
The correct answer is option 2. The radius of the balloon after 9 minutes is approximately 0.7889 centimeters.
To find the radius of the balloon after 9 minutes, we substitute t = 9 into the equation r(t) = 3√t + 6:
r(9) = 3√9 + 6
r(9) = 3 * 3 + 6
r(9) = 9 + 6
r(9) = 15
Therefore, the radius of the balloon after 9 minutes is 15 centimeters.
However, none of the given options match the value of 15 centimeters. It is possible that there was an error in the options provided or in the calculations. If we assume that option 2 corresponds to the radius after 9 minutes, the value of 0.7889 centimeters does not align with the equation r(9) = 15. Therefore, there may be a discrepancy in the options or in the calculations provided.
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Express the answers to the following operations with the proper number of significant figures. (a) 8.370×1.3 ×10 (b) 4.265/2.0 (c) (1.2588×10 ^3)×(1.06×10 ^−2) (d) (1.11) ^1/2
The answers, rounded to the appropriate number of significant figures, are as follows:
(a) 1.088 ×\(10^2\)
(b) 2.132
(c) 1.3331 ×\(10^1\) and
(d) 1.05.
Let's calculate the answers to the given operations using the appropriate number of significant figures.
(a) 8.370×1.3×10
To perform this multiplication, we multiply the decimal numbers and add the exponents of 10:
8.370 × 1.3 × 10 = 10.881 × 10 = 1.0881 × \(10^2\)
Since the original numbers have four significant figures, we round the final answer to four significant figures:
1.088 × \(10^2\)
(b) 4.265/2.0
For division, we divide the decimal numbers:
4.265 ÷ 2.0 = 2.1325
Since both numbers have four significant figures, the answer should be rounded to four significant figures:
2.132
(c) (1.2588×\(10^3\))×(1.06×\(10^-^2\))
To multiply these numbers, we multiply the decimal numbers and add the exponents:
(1.2588 × \(10^3\)) × (1.06 × \(10^-^2\)) = 1.333128 × \(10^1\)
Since the original numbers have five significant figures, we round the final answer to five significant figures:
1.3331 × \(10^1\)
(d) \((1.11)^(^1^/^2^)\)
To calculate the square root, we raise the number to the power of 1/2:
\((1.11)^(^1^/^2^)\)= 1.0524
Since the original number has three significant figures, the answer should be rounded to three significant figures:
1.05
It's important to note that the significant figures in a result are determined by the original data and the operations performed. The final answers provided above reflect the appropriate number of significant figures based on the given information and the rules for significant figures.
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Determine the x cornponent of velocity when the particle is at y=8ft. Express your answer in feet per second to three significant figures. A particle moves along the curve y=e
2x
such that its velocity has a constant magnitude of v=5ft/s. Part B Determine the y component of velocity when the particle is at y=8ft Express your answer in feet per second to three significant figures.
Given that the particle moves along the curve y=e^(2x) and the magnitude of its velocity is v=5ft/s.A particle moving along a curve is given by:y = e^(2x)Taking the derivative of this function with respect to time t will give the velocity function as follows;dy/dt = 2e^(2x) dx/dt ............................... (1)We know that the magnitude of velocity is constant v = 5ft/s.
Therefore, we can use the velocity function to solve for dx/dt and dy/dt as shown below;dx/dt = v/√(4e^(4x)) = v/(2e^(2x)) ................ (2)Substituting equation (2) into (1), we get;dy/dt = 2e^(2x) dx/dt = 2e^(2x) * v/(2e^(2x))=v = 5 ft/sHence, the y-component of velocity when the particle is at y = 8 ft is 5 ft/s.
Therefore, we can use the slope of the curve at point y = 8 ft to find the angle of the slope, then use trigonometry to solve for the x-component of velocity.
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Partitioning- finding the endpoint
Values of x and y will be 12 and 5 respectively.
It's given in the question,
Three points Q, R and S are collinear.Coordinates of Q → (2, 0)Coordinates of R → (8, 3)Coordinates of S → (x, y)QR : RS = 3 : 2Since, expression for the coordinates of a point (h, k) which divides the segment joining points \((x_1,y_1)\) and \((x_2,y_2)\) in the ratio of m : n is given by,
h = \(\frac{mx_2+nx_1}{m+n}\)
k = \(\frac{my_2+my_1}{m+n}\)
Since, R is a point on segment QS dividing in the ratio of 3 : 2, coordinates of R will be,
\(8=\frac{3x+2\times 2}{3+2}\)
\(8=\frac{3x+4}{5}\)
\(3x+4=40\)
\(3x=36\)
\(x=12\)
Similarly, \(3=\frac{3y+2\times 0}{3+2}\)
\(3=\frac{3y}{5}\)
\(3y=15\)
\(y=5\)
Therefore, values of x and y will be 12 and 5 respectively.
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6. In a study with a 4 x 2 x 3 factorial design, a. There are _______ independent variables. b. There are _______ possible main effects. c. There are ______ different conditions. d. There are _______ possible interactions.
a. There are three independent variables in a 4 x 2 x 3 factorial design.
b. There are four possible main effects in a 4 x 2 x 3 factorial design, one for each independent variable.
c. There are 24 different conditions in a 4 x 2 x 3 factorial design, which is the product of the levels of each independent variable (4 x 2 x 3 = 24).
d. There are several possible interactions in a 4 x 2 x 3 factorial design, including two-way and three-way interactions between the independent variables.
a) How many independent variables are there in a 4 x 2 x 3 factorial design ?a). In a factorial design, the independent variables are systematically manipulated in all possible combinations. In a 4 x 2 x 3 factorial design, there are three independent variables, each with a different number of levels.
The first independent variable has four levels, the second independent variable has two levels, and the third independent variable has three levels.
Therefore, there are three independent variables in this design.
b) What is a main effect in a factorial design ?b). A main effect is the effect of a single independent variable on the dependent variable, averaged across all levels of the other independent variables.
In a 4 x 2 x 3 factorial design, there are three independent variables, each of which can have a main effect. Therefore, there are three possible main effects in this design.
Additionally, there can be two-way and three-way interactions between the independent variables, which can also affect the dependent variable. However, a main effect is distinct from an interaction effect and is not dependent on any other independent variables.
c) How is the total number of different conditions calculated in a 4 x 2 x 3 factorial design ?c).The number of different conditions in a 4 x 2 x 3 factorial design is calculated by multiplying the number of levels for each independent variable.
In this case, the first independent variable has four levels, the second independent variable has two levels, and the third independent variable has three levels.
Therefore, the total number of different conditions is obtained by multiplying these three numbers (4 x 2 x 3 = 24). Each condition represents a unique combination of the levels of the three independent variables.
d) How do interactions occur in factorial designs ?d). Interactions in factorial designs occur when the effect of one independent variable on the dependent variable depends on the level of another independent variable. In a 4 x 2 x 3 factorial design, there are several possible interactions between the independent variables.
For example, there may be a two-way interaction between the first and second independent variables, meaning that the effect of the first independent variable on the dependent variable depends on the level of the second independent variable.
Similarly, there may be a two-way interaction between the second and third independent variables, or between the first and third independent variables.
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Angie runs 7 mph for the first half of a marathon, 13.1
miles, but twists her knee and must walk 2 mph for the
second half. What was her average speed? Round to 2
decimal places.
Answer:
Step-by-step explanation:
For the first half of the Marathon, we need to find the time.
t = d/r
r = 7 mph
d = 13.1
t = 13.1 / 7
t = 1.87 hours.
For the second half of the Marathon we need the time as well.
t = d/r
r = 2 mph
d = 13.1
t = 13.1 / 2
t = 6.55 hours.
Now to find the average speed, you will need the total time and the total distance
Total distance = 13.1 + 13.1 = 26.2 miles
Total time = t1 + t2
Total time = 1.87 hours + 6.55 hours.
Total time = 8.42
average speed = Total Distance / total time
average speed = 26.2 / 8.42 = 3.11 miles per hour
Most accounts use the simple interest formula to calculate the interest .
True
False
Answer:
False
Step-by-step explanation:
Please mark me as brainliest
Answer:
false
Step-by-step explanation:
just took test
After conducting a one-sample Z test, you arrived at a value of 5.7 for the z value. What is your conclusion? Reject the null hypothesis Accept the null hypothesis None of the above The result is too close to call
The conclusion after conducting one sample z-test for z value 5.7 is not possible the correct answer is option c. None of the above.
To determine the conclusion of a one-sample Z test based on the Z-value,
We need to compare the Z-value with the critical value of Z at the chosen level of significance (alpha) and with the corresponding p-value.
If the Z-value is greater than the critical value of Z or if the p-value is less than the chosen level of significance (alpha).
Then we reject the null hypothesis.
Otherwise, we fail to reject the null hypothesis.
Without knowing the level of significance and the corresponding critical value.
We cannot determine the conclusion of the test based solely on the Z-value of 5.7.
However, if we assume a standard significance level of 0.05.
We can use a Z-table or statistical software to find the corresponding critical value of Z, which is 1.96 for a two-tailed test.
If the Z-value of 5.7 is greater than the critical value of Z of 1.96, then we reject the null hypothesis.
Otherwise, we fail to reject the null hypothesis.
Therefore, for the one-sample Z test with given information it is not possible to conclude the correct answer is option c. none of the above.
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An underwater observation tower is being built with circular viewing portholes enabling visitors to see underwater life. Each vertically oriented porthole is to have a 3 ft diameter whose center is to be located 50 ft underwater. Find the total fluid force exerted on each porthole. Also, compute the fluid force on a horizontally oriented porthole that is under 50 ft of water.
The total fluid force exerted on each vertically oriented porthole with a 3 ft diameter and a center located 50 ft underwater is approximately 28,274 pounds. The fluid force on a horizontally oriented porthole under 50 ft of water is also approximately 28,274 pounds.
The pressure at a given depth in a fluid is given by the equation P = ρgh, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth.
In this case, the depth of the vertically oriented porthole is 50 ft. We assume the density of water to be approximately 62.4 pounds per cubic foot, and the acceleration due to gravity is approximately 32.2 ft/s². Plugging these values into the equation, we can calculate the pressure at the depth of the porthole:
P = (62.4 lb/ft³) * (32.2 ft/s²) * (50 ft) = 100,080 lb/ft²
To find the fluid force exerted on the porthole, we need to multiply the pressure by the area of the porthole. The area of circle is given by the formula A = πr², where r is the radius of the circle. In this case, the radius is half the diameter, which is 1.5 ft. Thus, the area of the porthole is:
A = π * (1.5 ft)² = 7.07 ft²
Now, we can calculate the fluid force:
Fluid Force = Pressure * Area = 100,080 lb/ft² * 7.07 ft² ≈ 28,274 lb
Therefore, the total fluid force exerted on each vertically oriented porthole is approximately 28,274 pounds.
For the horizontally oriented porthole under 50 ft of water, the fluid force would be the same as the vertically oriented porthole. Hence, the fluid force on the horizontally oriented porthole is also approximately 28,274 pounds.
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ABC is the image of ABC under a rotation about point B
A'B'C' is the image of triangle ABC under rotation about 120° CCW about point Q. This is true.
How to illustrate the triangle?It should be noted that triangle A'B'C' appears to be congruent to triangle ABC and about the same distance from point Q.
Here, the angle of rotation from ABC to A'B'C' appears to be about 120° counterclockwise when measured using a geometry program.
Therefore, triangle A'B'C' is the image of triangle ABC under rotation about 120° CCW about point Q.
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A card is drawn from a well-shuffled deck of 52 cards. What is the probability of getting a red 10?
A. 1/2
B. 1/26
C. 1/13
D. 1/4
Answer:
1/13
Step-by-step explanation:
Knowing that:
In a deck of card half of the deck of card are red: 1/2
Also means 52/2 = 26
There are 2 red 10 in a deck of card.
Solve:
Since there are 2 red 10 in a deck of card and half of the deck of 52 card are red also known as 26.
Thus, the probability of getting a red 10 is 2/26. As you can see that not a answer choice. That because 2/26 is a even number as well as it means that it can be simplify.
GCD (or HCF) of 2 and 26 is 2.
Therefore, divide both by 2.
2/2 = 1
26/2 = 13
Hence, we can see that the simplify form is 1/13.
As a result, the probability of getting a red 10 is 1/13.
~lenvy~
CC has the following beginning balances in its stockholders' equity accounts on January 1, 2012: Common Stock, $100,000; Additional Paid-in Capital, $4,100,000; and Retained Earnings, $3,000,000. Net income for the year ended December 31, 2012, is $800,000. Court Casuals has the following transactions affecting stockholders' equity in 2012:
May 18 Issues 25,000 additional shares of $1 par value common stock for $40 per share.
May 31 Repurchases 5,000 shares of treasury stock for $45 per share.
July 1 Declares a cash dividend of $1 per share to all stockholders of record on July 15. Hint: Dividends are not paid on treasury stock.
July 31 Pays the cash dividend declared on July 1.
August 10 Reissues 2,500 shares of treasury stock purchased on May 31 for $48 per share.
Taking into consideration all the entries described above, prepare the statement of stockholders' equity for the year ended December 31, 2012.
Total stockholders’ equity 7,800,000
Statement of stockholders’ equity for CC for the year ended December 31, 2012:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000
Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
Total stockholders’ equity 7,800,000
Explanation:The given information is as follows:Common Stock on January 1, 2012 = $100,000Additional Paid-in Capital on January 1, 2012 = $4,100,000
Retained Earnings on January 1, 2012 = $3,000,000Net Income for the year ended December 31, 2012 = $800,000Cash Dividend Declared on July 1 and paid on July 31 = $200,000
To prepare the statement of stockholders’ equity for the year ended December 31, 2012, we will begin by preparing the opening balances of each of the equity accounts. We will then add the net income to the retained earnings account.
The closing balance for retained earnings is then computed by subtracting the cash dividend declared and paid from the total retained earnings. Finally, the total stockholders' equity is calculated by adding the balances of all the equity accounts.
Calculations:Opening balance of common stock = $100,000
Opening balance of additional paid-in capital = $4,100,000
Opening balance of retained earnings = $3,000,000
Net Income for the year ended December 31, 2012 = $800,000
Retained earnings (Opening Balance) = $3,000,000
Add: Net Income for the year ended December 31, 2012 = $800,000
Total retained earnings = $3,800,000Less: Cash Dividend Declared on July 1 and paid on July 31 = $200,000Retained earnings (Closing balance) = $3,600,000
Total stockholders’ equity = Common Stock + Additional Paid-in Capital + Retained Earnings (Closing balance) = $100,000 + $4,100,000 + $3,600,000 = $7,800,000
Therefore, the statement of stockholders’ equity for CC for the year ended December 31, 2012, is as follows:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000
Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
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could anyone help me???? I WILL GIVE THE BRAINLIEST!!!!!!! PLEASE PLEASE PLEASE!!!! or could anyone tutor me on how to do it?????? 27 points!!!!!!!!
Answer:
see attached
Step-by-step explanation:
The attachment is my effort to complete the proof. It appears to me the idea is to show that B=3+1 and that 1=3+C. Then you substitute (3+C) for 1 and you've got the proof you want.
_____
The given statements and reasons are intended to give you enough clues that you can figure out the logic that is being used. Once you have done that, you fill in the missing details.
Match the correct translation with the given transformation.
Answer:
1. a-b
2. a-d
3. c-e
4. g-f
5. a-h
6. e-j
Hilbert axioms changed Euclids geometry by
Hilbert axioms changed Euclid's theorem by identifying and explaining the concept of undefined terms
What was Hilbert's Axiom?These were the sets of axioms that were proposed by the man David Hilbert in the 1899. They are a set of 20 assumptions that he made. He made these assumptions as a treatment to the geometry of Euclid.
These helped to create a form of formalistic foundation in the field of mathematics. They are regarded as his axiom of completeness.
Hilbert’s axioms are divided into 5 distinct groups. He named the first two of his axioms to be the axioms of incidence and the axioms of completeness. His third axiom is what he called the axiom of congruence for line segments. The forth and the fifth are the axioms of congruence for angles respectively.
Hence we can conclude by saying that Hilbert axioms changed Euclid's theorem by identifying and explaining the concept of undefined terms.
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complete question
Hilbert’s axiom’s changed Euclid’s geometry by _____.
1 disproving Euclid’s postulates
2 utilizing 3-dimensional geometry instead of 2-dimensional geometry
3 describing the relationships of shapes
4 identifying and explaining the concept of undefined terms
someone please help...
Answer:
2 1/3
1 4/3
2.333...
233.3...%
Step-by-step explanation:
the humane society reports that of 428 animals at their local animal shelter, 376 are household pets and the remaining 52 are wildlife animals. over the weekend, 29 of the household pets were adopted and 10 of the wildlife animals were released back into the wild. is there sufficient evidence to indicate a difference in the number of animals leaving the shelter over the weekend for the two types (household pets and wildlife animals)? use the p-value approach at the 1% level of significance.
There is sufficient evidence to believe that the number of household pets leaving the shelter over the weekend is different from the proportion of wildlife animals leaving the shelter over the weekend.
How to prove it there's sufficient evidenceTo determine if there's sufficient evidence,
Let us define the null and alternative hypotheses for this test as follows:
Null hypothesis (H0): The proportion of household pets leaving the shelter over the weekend is the same as the proportion of wildlife animals leaving the shelter over the weekend.
Alternative hypothesis (Ha): The proportion of household pets leaving the shelter over the weekend is different from the proportion of wildlife animals leaving the shelter over the weekend.
The test statistic for two sample test is given by:
z = (p1 - p2) / sqrt(p * (1 - p) * (1/n1 + 1/n2))
where
p1 and p2 are the proportions of household pets and wildlife animals leaving the shelter over the weekend, respectively,
p is the pooled proportion,
n1 and n2 are the sample sizes for household pets and wildlife animals, respectively.
Pooled proportion is
p = (x1 + x2) / (n1 + n2)
where x1 and x2 are the number of household pets and wildlife animals leaving the shelter over the weekend, respectively.
Given
-n1 = 376, n2 = 52, x1 = 29, x2 = 10
p = (29 + 10) / (376 + 52) = 0.091
The observed proportions are:
p1 = x1 / n1 = 29 / 376 = 0.0771
p2 = x2 / n2 = 10 / 52 = 0.1923
The test statistic value
z = (0.0771 - 0.1923) / sqrt(0.091 * (1 - 0.091) * (1/376 + 1/52)) = -3.04
By using a standard normal distribution table,
The p-value is 0.00238.
Since the p-value (0.00238) is less than the level of significance (0.01), we reject the null hypothesis and conclude that there is sufficient evidence to indicate a difference in the number of animals leaving the shelter over the weekend for household pets and wildlife animals.
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1. arva teachers were discussing how many pull-ups they can do. mr. leppold claims he can do 3 more pull-ups than mr. will. mrs. crump says she can do 5 more than mr. leppold.
a. write an equation for how many pull-ups each teacher can do, using variables (l for mr. leppold, w for mr. will, c for mrs. crump):
l =
c =
w =
b. make an equation for the number of pull-ups for mr. will using the variable c: w =
c. if mr. leppold can do 18 pull-ups, mr. brennan can do ____ pull-ups and mrs. crump can do ___ pull-ups.
By using the variable Mr. Leppold can do 18 pull-ups, Mr. Will can do 15 pull-ups, and Mrs. Crump can do 23 pull-ups. Mr. Leppold can do 3 more pull-ups than Mr. Will and Mrs. Crump can do 5 more than Mr. Leppold.
To solve this problem, we need to set up equations using the given information. Mr. Leppold claims he can do 3 more pull-ups than Mr. Will, so we can express that as l = w + 3. Mrs. Crump says she can do 5 more than Mr. Leppold, so we can write c = l + 5. We can then substitute l = w + 3 into c = l + 5 to get c = w + 8. This gives us the equations l = w + 3, c = l + 5, and c = w + 8. We can then substitute in a number for l (18) to solve for the other two variables. When l = 18, we get w = 15 and c = 23. Therefore, Mr. Leppold can do 18 pull-ups, Mr. Will can do 15 pull-ups, and Mrs. Crump can do 23 pull-ups.
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Please help me solve this algebraic expression
Answer:
m^3 + 3m, I simplified.
Secants ⎯⎯⎯⎯⎯⎯⎯⎯⎯ and ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯ intersect in the exterior of a circle. DJH measures 191° and EG measures 53°. Determine the measure of ∠ EFG.
Answer:
\( m\angle EFG =69\degree \)
Step-by-step explanation:
\( m\angle EFG =\frac{1}{2}(191- 53)\degree \)
\( m\angle EFG =\frac{1}{2}\times 138\degree \)
\( m\angle EFG =69\degree \)
this is worth 40 points so pls help! I need this ASAP.
I also need COMPLETE solution
Answer:
Shown below.
Step-by-step explanation:
Test Marks Tally Frequency Percentage
1 8 8/60 = 0.133
2 6 6/60 = 0.100
3 5 5/60 = 0.083
4 5 5/60 = 0.083
5 5 5/60 = 0.083
6 8 8/60 = 0.133
7 6 6/60 = 0.100
8 7 7/60 = 0.116
9 4 4/60 = 0.066
10 5 5/60 = 0.083
Total 59 59/60 = 0.983
For the Tally section, I believe you just fill in tally marks corresponding to the frequency. One of the observations in the table is 0, which is not a column in the frequency table.
why is an unbiased staitistc generally preferred overan a biased statistic for estimating a population
An "unbiased-statistic" is preferred over "biased-statistic" for estimating population because it provides more accurate estimate of true population parameter.
A "biased-statistic" systematically overestimates or underestimates the population parameter, which leads to incorrect conclusions about the population. Biases can arise in many ways, such as through sampling methods or measurement errors.
Whereas, an "unbiased-statistic" is not systematically too high or too low, but rather it is an estimate that is equal on average to the true population parameter.
The "Unbiased-estimates" have a smaller "sampling-error" and are more accurate and more reliable for making inferences about the population.
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