For an experiment with 3 groups of 10 participants in each group. fcrit for alpha 0.05 =

Answer:

true

Explanation:

PLS MAKE ME AS BRAINLIST

Answer: below what? you cant see what we are supposed to answer

Explanation:

This case, 80 bytes get allocated.Assuming a 32-bit architecture, the size of a pointer is typically 4 bytes. In the given code snippet, the variable "ptr" is being allocated memory using the "malloc" function. The "malloc" function takes in the number of bytes to be allocated as an argument and returns a pointer to the first byte of the allocated memory block.

In this case, "ptr" is being allocated memory for an array of 20 pointers to integers. Each pointer is of size 4 bytes (assuming a 32-bit architecture), so the total size of memory being allocated is 20 * 4 = 80 bytes.
Therefore, the line "ptr = (int**)malloc(20 * sizeof(int*));" is allocating 80 bytes of memory and assigning the pointer to the first byte of that memory block to the variable "ptr".

When using a 32-bit architecture, the allocation statement `ptr = (int**)malloc(20 * sizeof(int*));` will allocate memory for an array of 20 integer pointers. Since the size of a pointer on a 32-bit architecture is 4 bytes, the total bytes allocated will be:
20 (number of pointers) * 4 (bytes per pointer) = 80 bytes

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F = k x, often known as the spring constant or stiffness constant, calculates the force produced by the action of a spring.

Hooke's Law states that the extension of a spring is proportional to the load applied to it. The spring constant is measured in N/m. A variety of materials will follow this rule as long as the load does not exceed the elastic limit of the material. The spring constant, or k, is used to calculate spring stiffness. The stiffer the spring is and the harder it is to stretch, the larger the spring constant.

k*x - m*g = mv^2/L

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The average speed of the given car is 2.22 s and 3.13 s for 0.25 m and 0.50 m distance respectively.

The average speed can be calculated by adding the speed of each trial divided by the number of trials,

For 0.25 m the average speed will be:

\(S_{avg} = \dfrac{2.24 + 2.21 + 2.23}{ 3}\\\\S_{avg} = 2.22\)

For the 0.50 m, the average speed will:

\(S_{avg} = \dfrac {3.16 + 3.08 + 3.15} {3 }\\\\S_{avg} = 3.13\rm \ s\)

Therefore, the average speed of the given car is 2.22 s and 3.13 s for 0.25 m and 0.50 m distance respectively.

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After the elastic collision, cart 1 will have a final velocity of (3/4)v₀ in the positive x-direction, and cart 2 will have a final velocity of (1/4)v₀ in the positive x-direction.

During an elastic collision, both momentum and kinetic energy are conserved. In this scenario, cart 1 of mass m is initially moving with a velocity v₀ in the positive x-direction, while cart 2 of mass 3m is at rest.

Using the conservation of momentum, we can set up the equation:

(m)(v₀) + (3m)(0) = (m)(v₁) + (3m)(v₂),

where v₁ and v₂ are the final velocities of cart 1 and cart 2, respectively.

Since cart 2 is initially at rest, its momentum is zero. Simplifying the equation:

m(v₀) = m(v₁) + 3m(v₂).

Since the masses cancel out, we can further simplify:

v₀ = v₁ + 3v₂.

Next, we can apply the conservation of kinetic energy. The kinetic energy of a moving object is given by (1/2)mv². Before the collision, only cart 1 has kinetic energy, while after the collision, both carts have kinetic energy. Therefore, we can write:

(1/2)m(v₀)² = (1/2)m(v₁)² + (1/2)(3m)(v₂)².

Simplifying this equation:

(1/2)(m)(v₀)² = (1/2)(m)(v₁)² + (1/2)(3m)(v₂)².

Dividing both sides by (1/2)m:

(v₀)² = (v₁)² + 3(v₂)².

Combining this equation with the earlier equation from momentum conservation (v₀ = v₁ + 3v₂), we can solve for the final velocities:

(v₁ + 3v₂)² = (v₁)² + 3(v₂)².

Expanding and simplifying:

v₁² + 6v₁v₂ + 9v₂² = v₁² + 3v₂².

Canceling out the common terms:

6v₁v₂ = -6v₂².

Dividing both sides by 6v₂:

v₁ = -v₂.

Therefore, the final velocities are:

v₁ = -(1/4)v₀,

v₂ = (1/4)v₀.

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Answer:

Resource disposal or waste disposal is a crucial aspect of resource management.

Businesses in the manufacturing sector must develop a model of operations that allows an endless loop of internal recycling of waste and or processing waste resources into commercial resources.

A good example would be when an abattoir processes the internal organs of cows and goats with some waste gotten from rice mill into can food for dogs and canines. Waste from this secondary process can either be converted into organic manure to be sold to farmers or processed further for consumption at carnivorous fish farms.

Cheers

Safety symbols, danger symbols, or safety labels are graphical symbols that warn of or indicate hazards linked with an area or object. Images, pictograms, forms, words, phrases, sentences, or statements placed on walls, boards, buildings, doors, entrances, machinery, equipment, tools, transportation, roadways, or any other visible location are examples of safety symbols. The symbol alerts people to the presence of hazardous products or substances, as well as a hazardous environment, and warns them on how to stay safe or the potential repercussions if not avoided.

The given symbol means hammer.

A hammer is a hand tool that consists of a weighted "head" attached to a long handle and swung to produce an impact to a limited region of an item. This may be used to drive nails into wood, shape metal, or crush rock.

While all of these hammers have a round head for driving nails, the claw end may be used for prying, splitting wood, ripping drywall, and other minor demolition chores. A claw hammer's claw is curved, whereas a framing hammer's claw is straight. These hammers are ideal for the following tasks: woodworking

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The gauge pressure required to lift a car with a mass of 1200 kg using a hydraulic automobile lift with a piston diameter of 0.30 m is approximately 3.97 × 10⁵ Pa.

To calculate the gauge pressure, we can use the equation:

P = F/A,

where P is the pressure, F is the force exerted on the piston, and A is the area of the piston.

The force required to lift the car can be calculated using Newton's second law:

F = m × g,

where m is the mass of the car and g is the acceleration due to gravity.

Plugging in the given values, we have:

F = 1200 kg × 9.8 m/s² = 11760 N.

The area of the piston can be calculated using the formula for the area of a circle:

A = π × r²,

where r is the radius of the piston.

Given the diameter of the piston as 0.30 m, we find the radius to be 0.15 m.

Plugging in the values, we have:

A = π × (0.15 m)² ≈ 0.0707 m².

Finally, substituting the values into the pressure equation, we find:

P = (11760 N) / (0.0707 m²) ≈ 3.97 × 10⁵ Pa.

Therefore, the gauge pressure required to lift the car is approximately 3.97 × 10⁵ Pa.

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The angle in radians between two vectors can be found using the dot product formula:

\(θ = cos^-1 ((a • b) / (||a|| ||b||))\)

Where:
- θ is the angle between the vectors in radians
- a and b are the two vectors
- a • b is the dot product of the vectors
- ||a|| and ||b|| are the magnitudes of the vectors

To find the angle between the vectors, first calculate the dot product of the vectors by multiplying the corresponding components of the vectors and adding the results. Then, find the magnitudes of the vectors by taking the square root of the sum of the squares of the components. Finally, plug the dot product and magnitudes into the formula and use the inverse cosine function to find the angle in radians.

For example, if the vectors are a = (1, 2, 3) and b = (4, 5, 6), the angle between them would be:

\(θ = cos^-1 (((1)(4) + (2)(5) + (3)(6)) / (sqrt((1)^2 + (2)^2 + (3)^2) * sqrt((4)^2 + (5)^2 + (6)^2)))\)

\(θ = cos^-1 ((4 + 10 + 18) / (sqrt(14) * sqrt(77)))θ = cos^-1 (32 / (sqrt(14) * sqrt(77)))θ = 0.225 radians\)
So the angle between the vectors is 0.225 radians.

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The correct statements are: [1] If the absorbance band of an interferent can be blocked by the slit while still passing the absorbance band of the analyte, [3] If narrowing the slit causes the light band passed to go from polychromatic to monochromatic light, [4] If the bandwidth of the light passed by the slit includes some of the baseline.

By adjusting the slit width on a monochromator, it is possible to selectively block certain absorbance bands while allowing others to pass through. This can be useful in eliminating interference from other substances in the sample.

Narrowing the slit width reduces the range of wavelengths that can pass through, resulting in a more monochromatic light. This can enhance the sensitivity of absorbance measurements by reducing background noise.

If the bandwidth of the light passed by the slit includes some of the baseline, it can lead to inaccuracies in absorbance measurements. Narrowing the slit width helps to minimize the inclusion of baseline noise, improving the sensitivity of the measurement.

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Answer: 78m/s  =A

u=0 ,a=3m/sec^2 ,t=25sec

v=u+at

=0+25×3

=75m/s

after 1sec

v=u+at+75

=0+3×1+75

=78m/s

Explanation:

u=0 ,a=3m/sec^2 ,t=25sec

v=u+at

=0+25×3

=75m/s

after 1sec

v=u+at+75

=0+3×1+75

=78m/s

The number of significant figures in the calculation for the perimeter should match the least number of significant figures among the measurements, which is 2. Therefore, the calculation for the perimeter should be reported with 2 significant figures.

When performing calculations, it is important to consider the rules of significant figures. The rule states that the result of a calculation should be rounded to match the least number of significant figures in the given measurements.

In the given measurements, the least number of significant figures is 2, which is found in Side 3 (2.000 m). Therefore, when calculating the perimeter of the seven-sided figure, the result should be rounded to 2 significant figures.

For example, if the calculated perimeter is 41.756 meters, it should be rounded to 42 meters since 2 is the least number of significant figures. This ensures that the result aligns with the precision of the measurements provided.

By adhering to the rules of significant figures, we can maintain consistency and accuracy in our calculations and ensure that the level of precision is appropriate for the given data.

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Answer:

The internal energy of a substance is equal to the total amount of potential energy and kinetic energy of ALL the particles in the substance.

For example, when the temperature increases (more temperature means more energy), the kinetic energy of the particles in the substance increases.

And when we reach a point near a change of phase (like near fusion point) there is energy used to break the bonds between the particles, then we have an increase in potential energy.

Then we could write the internal energy as:

U = ∑(KEₙ) + ∑(PEₙ)

Where ∑(KEₙ) and ∑(PEₙ) are the sums of the kinetic energy and potential energy of all the particles in the substance.

The equation that best summarizes the internal energy (U) of a substance that has both kinetic and potential energy is U = ∑(KEₙ) + ∑(PEₙ).

Therefore, equation that best summarizes the internal energy (U) of a substance that has both kinetic and potential energy is U = ∑(KEₙ) + ∑(PEₙ).

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For the auto now no longer to strike the deer, the minimal deceleration ought to be eight m / (s ^ 2) with a blended immediately drivers response took at the distance of 15 metres.

The given parameters are;

The distance farfar from the deer the auto turned into while the motive force notices the deer = 25 m

The velocity of the auto = 20m / s

Therefore, for the auto now no longer to strike the deer, the minimal deceleration of the auto ought to be from 20 ^ 2 / (2 * 25) = eight m/s² for a direct motive force response time

For a motive force response time of 0.five seconds, we have

Distance moved with the aid of using car = 0.five * 20 = 10 metersDistance moved with the aid of using car = 0.five * 20 = 10 meters

Minimum deceleration of the auto required = 20 ^ 2 / (2 * 15) =13. overline three m/s^ 2

Distance of the auto from the deer on the begin of deceleration = 25 - 10 = 15 meters.

Therefore, climate the deer is struck with the aid of using the auto relies upon at the drivers response time and deceleration of the auto.

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When a tire travels over a surface, it must deliver three forces to ensure proper movement. These three forces are the longitudinal force, the lateral force, and the vertical force. These forces are essential for a tire to maintain good traction and control while traveling on the surface.

The Longitudinal force refers to the force that is delivered parallel to the direction of the vehicle's movement. The amount of longitudinal force that a tire can deliver will determine the amount of torque that is transferred from the vehicle to the surface beneath it.

This force is required to ensure that the vehicle moves forward or backward in the desired direction. The Lateral force refers to the force that is delivered perpendicular to the direction of the vehicle's movement. This force is required to ensure that the vehicle can maintain its course on the road or surface on which it's traveling. The lateral force must be controlled to ensure the vehicle stays on its desired path.

The vertical force refers to the force that is delivered downward on the surface. This force is required to maintain the tire's contact with the road or surface beneath it. The amount of vertical force delivered must be sufficient to support the vehicle's weight. This force is critical in preventing the tire from losing grip while moving over an obstacle or when the vehicle is taking turns.

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The speed of the car is 55.2 m/s.

We can define speed as the ratio of distance to time. We know that the question states the car is one lap behind the lead race car when the lead car has 52 laps to go in a race.

If 1 lap =  1.34km or 1340 m

Distance covered =   1340 m * 52 = 69680 m

Time = 69680 m/ 56.3 m/s

= 1237.7 s

Given that the second car is one lap behind;

51 *  1340 m = 68340 m

Speed =  68340 m/1237.7 s

= 55.2 m/s

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Explanation:

acceleration is the Changing of throut per unit time ....

and in uniform motion .....

in that the speed of an object is uniform means same

The kind of stretching they should do before they are warmed up is dynamic stretching.

A dynamic stretch is a movement-based type of stretch. It uses the muscle itself to induce stretching. It differs from traditional "static" stretches because the stretch position is not preserved.

Extend your left foot backward, bend your right foot forward and bend it, and rotate left and right to raise your arms to the sky. Or why not stand and add another kind of gentle twist.

Dynamic stretches are based on movement, while static stretches move the joints as much as possible and hold them for a period of time (usually 30-90 seconds).

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When, a 10 kg box will accelerates forward at a rate of 12 m/s². Then, the  force acting on the box is 120 Newtons.

Force is the physical quantity which describes the interaction between two objects, which tends to cause a change in the motion of an object.

We can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration;

F = m × a

where F will be the net force, m will be the mass of the object, and a will be the acceleration.

Substituting the given values, we get:

F = 10 kg × 12 m/s²

Simplifying, we get;

F = 120 N

Therefore, the force acting on the box is 120 Newtons.

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Answer:

t = 8.55 years

Explanation:

The formula for power is given as:

Power = Work/Time

but, the work here is equal to the increase in potential energy of the water. Therefore,

Power = P.E/Time

P = mgh/t

t = mgh/P

where,

t = time required = ?

P = Power of pump = 2.21 KW = 2210 W

m = mass of water = 3.2 x 10⁷ kg

h = height = 1.9 km = 1900 m

g = 9.8 m/s²

Therefore,

t = (3.2 x 10⁷ kg)(9.8 m/s²)(1900 m)/(2210 W)

t = (2.69 x 10⁸ s)(1 h/3600 s)(1 day/24 h)(1 year/365 days)

t = 8.55 years

For a planar surface, the direction of dip is always perpendicular (90 degrees) to the direction of strike.

In geology, the strike and dip are measurements used to describe the orientation of a planar rock surface, such as a bedding plane or fault. The strike represents the horizontal direction of the line formed by the intersection of the rock surface with a horizontal plane. The dip, on the other hand, represents the angle of inclination of the rock surface from the horizontal plane. In a planar surface, the dip is always perpendicular to the strike. This means that if the strike is in a particular direction, the dip will be at a right angle (90 degrees) to that direction.

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Answer: 0.0528

Explanation:

acellus

Human roles in energy transition are:

By taking these steps, you can actively contribute to the energy transition and be a part of the movement toward a more sustainable and clean energy future.

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The activity of the source in Becquerel is 333.3Bq

The number of nuclei that disintegrate or decay per unit time is known as Activity.

Given that a sample of radioactive material emits 400000 particles over a period of 20 minutes.

Activity A = dN/dt

A = 400000 / 1200

A = 333.3 particles / s

A = 333.3 Bq

Therefore,

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Answer:

A. Rock cycle

Explanation:

Because it really is the change of a rock from another, like ingenuous, sedimentary rock..

The takeoff speed of the long jumper is approximately 9.90 m/s.

To find the takeoff speed of the long jumper, we can use the principles of projectile motion.

The horizontal distance traveled by the jumper (8.84 m) can be used to determine the time of flight. The horizontal distance is equal to the horizontal component of velocity multiplied by the time of flight:

d = Vx * t

where d is the horizontal distance, Vx is the horizontal component of velocity, and t is the time of flight.

Horizontal distance, d = 8.84 m

We need to find the takeoff speed, which is the magnitude of the initial velocity of the jumper. The initial velocity can be represented as:

V0 = √(Vx^2 + Vy^2)

where V0 is the initial velocity, Vx is the horizontal component of velocity, and Vy is the vertical component of velocity.

We can determine the vertical component of velocity using the angle of takeoff (24.0°). The vertical component can be calculated as:

Vy = V0 * sin(θ)

where θ is the angle of takeoff.

Since we know the horizontal distance, we can also determine the time of flight using the horizontal velocity:

t = d / Vx

Now, we can substitute the equations to find the takeoff speed:

V0 = √(Vx^2 + Vy^2)

= √((V0 * cos(θ))^2 + (V0 * sin(θ))^2)

= V0 * √(cos^2(θ) + sin^2(θ))

= V0 * √(1)

= V0

We can simplify the equation to:

V0 = d / t

Substituting the given values into the equation, we have:

V0 = 8.84 m / t

Now, we need to calculate the time of flight. The time of flight can be found using the vertical component of velocity:

t = Vy / g

where g is the acceleration due to gravity.

Substituting the values, we have:

t = (V0 * sin(θ)) / g

Substituting this equation into the equation for V0, we get:

V0 = 8.84 m / ((V0 * sin(θ)) / g)

Simplifying further, we have:

V0 = 8.84 m * g / (V0 * sin(θ))

Solving for V0, we have:

V0 = √(8.84 m * g / sin(θ))

Now, we can substitute the known values:

Acceleration due to gravity, g ≈ 9.8 m/s²

Angle of takeoff, θ = 24.0°

V0 = √(8.84 m * 9.8 m/s² / sin(24.0°))

Evaluating this expression, we find:

V0 ≈ 9.90 m/s

Therefore, the takeoff speed of the long jumper is approximately 9.90 m/s.

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Answer:

the answer to this would be D.

Answer: Its D but it might swap to another letter so keep your eye out bud pass this test good luck

Explanation: