for a double slit experiment, what is the smallest separation (in nm) between two slits that will produce a second-order maximum for 659 nm visible light? you need to round your answer to the nearest integer, do not include unit.

Answer:

So it's clear that Earth's hot iron core isn't what creates the magnetic field around our planet. ... On Earth, flowing of liquid metal in the outer core of the planet generates electric currents. The rotation of Earth on its axis causes these electric currents to form a magnetic field which extends around the planet

Explanation:

Answer:

F = 2(50 N) - (50 N) = 50 N

Explanation:

The direction of F is the direction in which the two students are pushing.

Answer:

this frequency is in the near UV range

Explanation:

The accelerated movement of a charge creates an electromagnetic wave, the speed of the wave is the speed of light

         c = λ f

the emitted frequency is f = 10⁶ 10⁹ Hz = 10¹⁵5 hz,

light of this frequency is in the near UV range

The block will slide approximately 3.18 meters along the ramp before coming momentarily to rest.

To find the distance along the ramp where the block comes momentarily to rest, we need to analyze the forces acting on the block.

Initially, when the block is sliding along the horizontal surface, there is no friction force acting on it. Therefore, the only force acting on the block is its weight, which can be split into two components: one parallel to the surface and one perpendicular to the surface.

The component of the weight parallel to the surface is given by:

F_parallel = m * g * sin(θ)

where m is the mass of the block (3.0 kg), g is the acceleration due to gravity (approximately 9.8 m/s^2), and θ is the angle of the ramp (40°).

F_parallel = 3.0 kg * 9.8 m/s^2 * sin(40°) ≈ 18.747 N

Since the surface is friction less, this force will not cause any change in the block's speed. Therefore, the block will continue to move with a constant speed of 7 m/s along the ramp until it comes to rest.

To determine the distance along the ramp where the block comes to rest, we can use the equation:

v^2 = u^2 + 2 * a * s

where v is the final velocity (0 m/s since it comes to rest), u is the initial velocity (7 m/s), a is the acceleration along the ramp, and s is the distance traveled along the ramp.

Rearranging the equation, we have:

2 * a * s = u^2

Since the block comes to rest, the final velocity is 0, so the equation becomes:

2 * a * s = 7^2

2 * a * s = 49

a * s = 24.5

Now, we need to find the acceleration (a) along the ramp. The component of the weight perpendicular to the ramp is responsible for the acceleration:

F_perpendicular = m * g * cos(θ)

F_perpendicular = 3.0 kg * 9.8 m/s^2 * cos(40°) ≈ 23.084 N

This force acts perpendicular to the ramp and provides the normal force to balance the weight of the block. Therefore, it is the force responsible for the acceleration along the ramp.

Using Newton's second law (F = m * a), we can determine the acceleration along the ramp:

23.084 N = 3.0 kg * a

a ≈ 7.695 m/s^2

Now, substituting the value of a into the equation a * s = 24.5, we can solve for s:

7.695 m/s^2 * s = 24.5

s ≈ 3.18 m

Therefore, the block will slide approximately 3.18 meters along the ramp before coming momentarily to rest.

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The cyclists displacement when he  rides a bicycle 4.0 km west, then 3.0 km north is 5km towards north-west.

Given the distance he travels towards west (d1) = 4km

The distance he travels towards north (d2) = 3km

An object's position changes if it moves with respect to a reference frame. Displacement describes this shift in location. The word "displacement" denotes the movement or displacement of an object. The displacement is the shortest distance covered in a certain direction. If we assume the distances he travelled as two sides of triangle then we the displacement which is the hypotenuse side.

So, displacement = √4^2+3^2 = 5km

The direction the cyclist travels is north-west and covers 5km.

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Answer:

1000 gigabytes is equal to 1 terabyte.

Answer:

499.73 m

Explanation:

We'll begin by calculating the change in the temperature. This can be obtained as follow:

Initial temperature (T₁) = 25 °C

Final temperature (T₂) = –20° C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = –20 – 25

ΔT = –45 °C

Finally, we shall determine the length on a cold day at –20° C. This can be obtained as follow:

Length at 25°C (L₁) = 500 m

Coefficient of linear expansion (α) = 12×10¯⁶ /°C

Change in temperature (ΔT) = –45 °C

Length at –20 °C (L₂) =?

α = L₂ – L₁ / L₁ΔT

12×10¯⁶ = L₂ – 500 / (500 × –45)

12×10¯⁶ = L₂ – 500 / –22500

Cross multiply

L₂ – 500 = 12×10¯⁶ × –22500

L₂ – 500 = –0.27

Collect like terms

L₂ = –0.27 + 500

L₂ = 499.73 m

Therefore, the length on a cold day at –20° C is 499.73 m.

Answer:

mm yummy

Explanation:

Answer:

30.5555556 m/s

You can write like "30.56 m/s".

Answer:

Below

Explanation:

You can convert km/h to m/s by dividing the value by 3.6

      110 km/h / 3.6 = 30.5556 m/s

*not sure if your teacher wants you to round to sig figs for this but here it is anyways. Because 110 has 2 sig figs it would be :

    31 m/s

Hope this helps! Best of luck <3

Answer:

2 to 4 hours

Explanation:

Given that,

Microbial food infections

We know that,

Food infection :

When we eat old food, uncooked, fermented food, more junk food and contaminated food then 2 to 4 hours after eating we started vomiting, headache then we affected by food infections.

So, we can say that microbial food infections are usually not seen until 2 to 4 hours after eating contaminated food.

Answer:

Im gonna say it is answer A:) Hope this helps!

Explanation:

The voltage generated by the 100W light bulb connected to the outlet is 120 volts.

To calculate the voltage generated by the 100W light bulb, we can use Ohm's law which states that voltage (V) is equal to the current (I) multiplied by the resistance (R).

The resistance of the light bulb can be calculated using the formula P=VI, where P is the power in watts, V is the voltage, and I is the current.

Since we know that the power of the light bulb is 100W, we can rearrange the formula to find the resistance (R) which is R=P/I^2. Substituting the values given, we get R=100/0.8333^2 which equals 144.

Now that we know the resistance of the light bulb, we can use Ohm's law to calculate the voltage. V=IR, substituting the values given, we get V=0.8333 x 144 which equals 120 volts.

Therefore, the voltage generated by the 100W light bulb connected to the outlet is 120 volts.

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The suitable dimensions for tied and spiral columns of Required loads, Stresses, Gross area, Area of steel are 1142.86 kN, 12.6 MPa, 90.89 m².

The required loads can be determined by dividing the factored load by the appropriate load factor. For this example, let's assume a load factor of 1.4. Required loads = Factored load / Load factor

= 1600 kN / 1.4

= 1142.86 kN

Determine the allowable stresses: a concrete compressive strength of fc' = 28 MPa, the allowable compressive stress (fa) can be calculated using the formula:

= 0.45 * 28 MPa

= 12.6 MPa

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Answer:

Below

Explanation:

FIND TOTAL NORTH DISPLACEMENT

   40 sin 35     + 50       + 10 sin 20   = 76.363 mi

FIND TOTAL E-W DISPLACEMENT  

  40 cos 35        -   10 cos 20 = 23.369 mi

Total resultant displacement ( using pythag theorem)

   sqrt ( 76.363^2 + 23.369^2 ) = 79.86  mi

    angle = arctan ( 79.23 / 23.37) = 73 °  North of East

Answer:

Explanation:

Yo creo que el no es correcto y que no es correcto es el diseño de la portada

Answer:

fdsbgdfshtrsnbfgsbnhgr

Explanation:

cdfrgresgtrshtrwhtrwhtwjhdgngdabfeahydrtgnb

Answer:

F = 11 N

Explanation:

Given,

Mass of a block, m = 5 kg

Acceleration of the block, a = 2.2 m/s²

We need to find the force on the person's hand. Let it is F. We know that force is given by the product of mass and acceleration as follows :

F = ma

F = 5 kg × 2.2 m/s²

F = 11 N

So, the force on a person's hand is 11 N.

We need to use two rays, such as one that is parallel to the principal axis and one that passes through the focal point, to locate the virtual image in a planar mirror or due to reflection at a flat surface.

To find a virtual image in a planar mirror or due to reflection at a flat surface, one needs to use at least two rays. The image is located where the light rays intersect.

Virtual imageVirtual images are images that are not real; instead, they are created by our eyes when light rays appear to come from a point behind a surface. Virtual images are formed when light rays appear to diverge from a point behind a mirror or lens, rather than converging to that point. If we hold a piece of paper against a mirror and move it around, we'll notice that we can see the image in various locations behind the mirror. As a result, virtual images have no physical existence and cannot be projected onto a screen.

For finding the virtual image in a planar mirror or due to reflection at a flat surface, one needs to use at least two rays. One of the most important concepts in geometric optics is that when light strikes a surface, it is reflected, refracted, or absorbed. Because of the law of reflection, it is simple to determine the location of the virtual image of an object reflected by a flat surface. We need to use two rays, such as one that is parallel to the principal axis and one that passes through the focal point, to locate the virtual image in a planar mirror or due to reflection at a flat surface.

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Answer:

I can msg it toyou

------->------>---->

Explanation:

It takes around 4 seconds for the camera ro fall 250 feet

use the quadratic formula where a=-16 b=0 and c=250

A. The period of vibration is the time it takes for one complete oscillation to occur. It is the reciprocal of the frequency. The period of vibration can be calculated using the formula:

Period = 1/Frequency

Given that the frequency of vibration is 5.0Hz, the period of vibration is:

Period = 1/5.0 s

Period = 0.2 s

B. If the cart's mass is doubled while the spring constant remains unchanged, the frequency of vibration will not change. This is because frequency is dependent on the spring constant and the mass of the cart and not on the amplitude of the oscillation.

C. If the spring constant doubles while the cart's mass remains the same, the frequency of vibration will also double. This is because frequency is directly proportional to the square root of the spring constant. Therefore, doubling the spring constant would lead to an increase in the frequency of vibration by a factor of square root of 2.

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Answer:

Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?

Liquid is the answer

Explanation:

Answer:

An element is a pure substance and is made of only one type of atom; it cannot be broken down into a simpler substance.

To compare the shapes of the velocity profiles, we need to plot each of the equations in MATLAB. The code to do this is as follows:

% Parameters

U = 1;

delta = 1;

% y values

y = linspace(0, delta, 100);

% Linear profile

linear_u = y/delta;

% Sinusoidal profile

sin_u = sin(pi/2*y/delta);

% Parabolic profile

para_u = 2*(y/delta) - (y/delta).^2;

% Plotting

plot(y/delta, linear_u/U, y/delta, sin_u/U, y/delta, para_u/U);

xlabel('y/\delta');

ylabel('u/U');

legend('Linear', 'Sinusoidal', 'Parabolic');

This code generates a plot that compares the three velocity profiles:

The linear velocity profile is a straight line, which means that the velocity increases linearly with distance from the wall. The sinusoidal profile has a maximum velocity at the wall, and decreases sinusoidally away from the wall. The parabolic profile has a maximum velocity at the centerline of the boundary layer, and decreases parabolically towards the wall and free stream.

Each of these velocity profiles is used to approximate the velocity profile in a laminar boundary layer, and the choice of which one to use depends on the specific problem at hand. For example, the linear profile is often used when the boundary layer is very thin compared to the length of the plate, while the parabolic profile is often used when the boundary layer is thicker. The sinusoidal profile is less commonly used, but may be appropriate for certain problems with complex flow geometries.

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Answer:

it is 59 degrees Fahrenheit

I'm pretty sure it's 59 °F

If the reflected ray on a mirror is rotated through an angle 22 degrees then the mirror itself is rotated at 68 degrees.

The angle through which the mirror is rotated is calculated by applying the laws of reflection as follows;

This law states that the angle between the incident ray and the mirror's surface is equal to the angle between the reflected ray and the mirror's surface.

So if the reflected ray on a mirror is rotated through an angle 22 degrees then the mirror itself is rotated at;

θ = 90⁰ - 22⁰

θ = 68⁰

Thus, if the reflected ray on a mirror is rotated through an angle 22 degrees then the mirror itself is rotated at 68 degrees.

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The complete question is below:

if the reflected ray on a mirror is rotated through an angle 22 degrees then the mirror itself is rotated at

(a) 36 degrees to each​

(b) 45  degrees to each​

(c) 68  degrees to each​

(d) 90  degrees to each​

The integral of the function of the force applied to the time of application

of the force gives the impulse of the force.

The speed with which the ball rebounds from the plate is approximately

34.23 m/s.

Reasons:

Force = Rate of change of momentum

F × t = m·(v₂ - v₁)

Where;

Speed of the ball, v₁ = 16 m/s

v₂ = The speed with which the ball rebounds from the plate

The impulse, I, of the force is given by the area under the curve.

The height of the triangular curve, h = 2,500 N

The base length of the triangular curve = 7 ms.

Area of a triangle = \(\frac{1}{2}\) × Base length × Height

Therefore, we have;

\(Area \ under \ the \ curve, \, I = \dfrac{0.007 \times 2500}{2} = 8.75\)

8.75 = 0.48 × (v₂ - 16)

v₂ ≈ 34.23 m/s

Therefore, the speed with which the ball rebounds, v₂ ≈ 34.23 m/s.

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Answer:

348.15K

Explanation:

75C+273.15=348.15K

With wavelengths of around 10-1000 m, radio waves used by cell phones to communicate with cell towers are far too big to be ionizing. In reality, WiFi runs at very specific frequencies, 2.4 GHz or 5 GHz, which correspond to wavelengths of 12 cm or 6 cm, respectively.

Since radiofrequency waves are electromagnetic fields rather than ionizing radiation like X-rays or gamma rays, they cannot ionize or destroy chemical bonds in living organisms.

The signal is transformed back into the data that was first sent by the transmitter when the radio waves reach a receiver. Your voice is sent through radio waves to the person you are contacting when you use a cell phone as a transmitter.

The primary means of communication between mobile phones and neighboring cell towers is through RF waves, an electromagnetic spectrum energy type.

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