The width (l) of a one-dimensional box for which the ground-state energy of an electron in the box equals the absolute value of the ground state of a hydrogen atom is l = sqrt((h^2) / (8 * m * 13.6 eV)).
Explanation:
To find the width (l) of a one-dimensional box for which the ground-state energy of an electron in the box equals the absolute value of the ground state of a hydrogen atom, follow these steps:
step1. Write down the expression for the ground-state energy of an electron in a one-dimensional box, which is given by:
E_box = (h^2 * n^2) / (8 * m * l^2), where h is the Planck's constant, n is the quantum number (n=1 for ground state), m is the electron mass, and l is the width of the box.
step2. Write down the expression for the absolute value of the ground state energy of a hydrogen atom, which is given by: E_hydrogen = 13.6 eV.
step3. Set the two energies equal to each other: E_box = E_hydrogen.
step4. Substitute the values of h, n, and m, and the given energy of the hydrogen atom into the equation: (h^2 * 1^2) / (8 * m * l^2) = 13.6 eV.
step5. Solve for l: l^2 = (h^2) / (8 * m * 13.6 eV).
step6. Take the square root of both sides to get the width (l): l = sqrt((h^2) / (8 * m * 13.6 eV)).
Now you have found the width (l) of a one-dimensional box for which the ground-state energy of an electron in the box equals the absolute value of the ground state of a hydrogen atom.
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The universe now contains a large variety of different elements. Describe how this happened
Answer: Because Allah made it
Explanation:
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if light photons are massless then why are they attracted by black holes?
Answer:
Photons have no mass, they do have energy, and the gravity of a black hole (or any other gravitating body) will attract them.
Explanation:
is that what you wanted?
Pluto has a mass of 1.30 1022 kg and a radius of 1.18 106 m.
(a) What is the acceleration due to gravity on Pluto? m/s2
(b) How much would a 5.68-kg person weigh on this planet?
a. The acceleration due to gravity on Pluto is approximately 0.620\(m/s^2.\)
b. A 5.68-kg person would weigh approximately 3.5296 N on Pluto.
(a) To calculate the acceleration due to gravity on Pluto, we can use the formula:
acceleration due to gravity (g) = G * (mass of Pluto) / \((radius of Pluto)^2\),
where G is the gravitational constant.
The gravitational constant is approximately 6.67430 ×\(10^{-11} m^3/(kg*s^2).\)
Substituting the given values:
g =\((6.67430 * 10^{-11 }m^3/(kg*s^2)) * (1.30 * 10^{22} kg) / (1.18 * 10^6 m)^2.\)
Calculating this expression:
g ≈ \(0.620 m/s^2.\)
(b) To calculate the weight of a person on Pluto, we can use the formula:
weight = mass * acceleration due to gravity.
Substituting the given values:
weight = 5.68 kg * 0.620 m/s^2.
Calculating this expression:
weight ≈ 3.5296 N.
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A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? Show all calculations and use SALT to describe the image.
Answer:
The height of the image of the candle is 20 cm.
Explanation:
Given that,
Size of the candle, h = 12 cm
Object distance from the candle, u = -6 cm
Focal length of converging lens, f = 15 cm
To find,
The height of the image of the candle.
Solution,
Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.
\(\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\)
v is image distance
\(\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm\)
If h' is the height of the image. Magnification is given by :
\(m=\dfrac{h'}{h}=\dfrac{v}{u}\)
\(h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm\)
So, the height of the image of the candle is 20 cm.
An object weighs 15 N in air and 13 N when submerged in mineral spirits, which has a density of 788 kg/m3. Determine the density of the object
The density of the object is 5911.94 kg/m³
An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.
The buoyancy = weight of the object - weight in water
= 15 N - 13N
= 2 N
The buoyancy force can also be determined by using the expressed:
\(\mathbf{F_B = Volume (V) \times density ( \rho) \times g}\)
\(\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }\)
\(\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}\)
volume (v) = 2.589 × 10⁻⁴m³
Recall that:
The mass of an object can be estimated by using the formula:
Weight = mass × gravity
mass = Weight / gravity
mass = 15/9.8
mass = 1.5306 kg
The density of the object can now be calculated using the relation
Density = mass/volume
Density = 1.5306 kg / 2.589 × 10⁻⁴m³
Density = 5911.94 kg/m³
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how is a school like a system what parts of a school can relate to parts of the system
Answer:
school can relate to parts of the system are:-
1. Education systems components
2. Teaching and learning
3. Financial resources
4. early learning and students success
5. human and organizational capital
6. Additional areas
hope it will help you
Kyle and Jenny both have pet rabbits. They wanted to see who had the fastest rabbit, so they each recorded data at their homes and brought it's the results. Kyle rabbit went a total of 40 m in a time of one minute and 20 seconds. Jenny's rabbit went 30 m in one minute and 30 seconds. What was the velocity of Kyle's rabbit? What was the velocity of jennies rabbit? Whose rabbit was the fastest?
Answer:
v_kyle = 0.5 m/s
v_jennies = 0.333 m/s
Kyle's Rabbit was the fastest
Explanation:
For the velocity of Kyle's Rabbit:
d = distance covered = 40 m
t = time taken = (1 min)(60s/1 min) + 20 s = 80 s
\(v_{kyle} = \frac{d}{t} = \frac{40\ m}{80\ s}\)
v_kyle = 0.5 m/s
For the velocity of Jennies Rabbit:
d = distance covered = 30 m
t = time taken = (1 min)(60s/1 min) + 30 s = 90 s
\(v_{jennies} = \frac{d}{t} = \frac{30\ m}{90\ s}\)
v_jennies = 0.333 m/s
It is clear from the results that:
Kyle's Rabbit was the fastest
Which of the following will cause the degeneracy pressure within an object to increase?
A. raising its temperature
B. shining a light on it, which adds radiative energy
C. lowering its temperature
D. letting it expand to lower density
E. compressing it to higher density
Option E. Compressing it to a higher density will cause the degeneracy pressure within an object to increase.
Degeneracy pressure is the pressure exerted by the fermions (such as electrons or neutrons) in an object when they are forced into a small volume due to quantum mechanical effects. This pressure arises due to the Pauli Exclusion Principle, which states that no two fermions can occupy the same quantum state simultaneously.
As a result, the fermions in the object will occupy higher and higher energy levels as they are compressed into a smaller volume, creating an outward pressure that resists further compression. Therefore, compressing an object to a higher density will cause the fermions within it to occupy higher energy levels, leading to an increase in degeneracy pressure.
Letting the object expand to lower density, will actually decrease the degeneracy pressure since the fermions will have more room to spread out and occupy lower energy levels. Overall, the degeneracy pressure is an important factor in determining the structure and stability of objects such as white dwarfs, neutron stars, and even atomic nuclei. Therefore, the correct answer is option E.
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I NEED THIS ANSWER QUICK!
About how much precipitation in the water cycle occurs over the ocean?
A) 15 percent
B) 50 percent
C) 78 percent
D) 100 percent
Answer:
Hello, I'm here to help you.
↬ 78%
Explanation:
↬ Think that about 70% of the area of the earth is covered by the ocean.
↬ So the precipitation that falls on it is a smiliar percentage.
which one is deposition plz help
1. Your wet hair dries after a few minutes
2. The mirror gets fogged up when you breathe on it
3. Liquid glass cools and hardens
Deposition is when a gaseous state changes to solid state by escaping liquid state. So I think it is 3. Liquid glass cools and hardens
alana drew a diagram to compare the life cycles of low-mass and high-mass stars. a venn diagram with 2 intersecting circles. the left circle is labeled low-mass stars and the right circle is labeled high-mass stars. there is an x in the low-mass stars circle, z in high-mass stars circle and y in the intersecting areas. which labels belong in the areas marked x, y, and z?
Low mass stars vary in that they have longer life cycles and develop into white dwarfs. Supernova explosions occur in high mass stars, which also have shorter life cycles.
What should be said about a Venn diagram?Circles are used in a Venn diagram to depict the relationships between individual items or small groups of things. Circles that overlap have certain qualities, but circles that do not overlap do not. Venn diagrams help you to more easily see the relationships and differences between two ideas.
What should be said about a Venn diagram?Circles are used in a Venn diagram to depict the relationships between individual items or small groups of things. Circles that overlap have something in common, but circles that don't share nothing.
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A boat is traveling upstream at 14 km/h with respect to the water of a river. The water itself is flowing at 9 km/h with respect to the ground. What is the velocity of the boat with respect to the ground
Answer:
16.64 km/h
Explanation:
Think of the x and y components as the a and b sides of a triangle and simply do the Pythagorean Theorem:
\(a^2+b^2=c^2\)
\(14^2+9^2=c^2\)
\(\sqrt{196+81}=c\)
\(\sqrt{277}=c\)
\(16.64 km/h\)
What branch of science is the system-
atic study of God's physical creation
and how it works?
Answer:
Physical science
Explanation:
Which example illustrates Newton's first law? O A. The force of a wheelbarrow on the ground is equal to the force of the ground on the wheelbarrow. B. More mass is added to a wheelbarrow, and a larger force is required to move it. C. A person pushes a wheelbarrow, causing it to move forward. D. The force of a wheelbarrow on the ground is in the opposite direction of the force of the ground on the wheelbarrow.
A person pushing a wheelbarrow, causing it to move forward, is the example that illustrates Newton's first law. The correct option is C.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
According to Newton's first law, a body tries to maintain its motion until or unless the external force is not applied to it.
If a body is at rest, try to rest if the body is in motion, try to be in motion until or unless an external force is not applied to it.
The wheelbarrow being propelled forward by a human is an illustration of Newton's first law.
Hence, the correct option is C.
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A current I starts at z = -~ and flows up the z-axis as a linear filament until its hits an origin-centered sphere of radius R. The current spreads out uniformly over the surface of the sphere and flows up lines of longitude from the south pole to the north pole. The recombined current flows thereafter as a linear filament up the z-axis to z = +0. (a) Find the current density on the sphere. (b) Use explicitly stated symmetry arguments and Ampère's law in integral form to find the magnetic field at every point in space. (c) Check that your solution satisfies the magnetic field matching conditions at the surface of the sphere.
J = I / (4πR²),
The magnetic field inside the sphere isB(r) = μ0 I / (2πr),
The magnetic field Outside the sphere isB(r) = μ0 I r² / (2 R³),
The magnetic field is continuous across the surface of the sphere.How to find magnetic field on spherical surface using Ampère's law?(a) The current density on the sphere can be found by dividing the total current by the surface area of the sphere.
The total current is equal to the current flowing through the linear filament, which is given by I. The surface area of the sphere is given by 4πR². Therefore, the current density on the sphere is:J = I / (4πR²)
(b) Due to the symmetry of the problem, the magnetic field will have no φ-component, and will only depend on the radial distance r and the polar angle θ.
By Ampère's law,
The magnetic field at a point P inside the sphere of radius R can be found by integrating the current density J over a circular path C around the z-axis passing through P:
∮C B · dl = μ0 Ienc
where,
B is the magnetic field, dl is the infinitesimal element of path length along C, μ0 is the permeability of free space, and Ienc is the current passing through any surface bounded by C.Since the current is distributed uniformly over the surface of the sphere, we can take a surface S with the same circular path C as its boundary.
Then, Ienc is equal to the total current passing through the sphere, which is equal to I.
By symmetry,
The magnetic field will be perpendicular to the circular path C at every point, and its magnitude will only depend on the distance r from the z-axis. Therefore, we can writeB = B(r) ẑ,
where,
ẑ is the unit vector in the z-direction. The integral can be evaluated as:B(r) ∫C dl = B(r) 2πr = μ0 I
Solving for B(r), we obtain:B(r) = μ0 I / (2πr)
This is the magnetic field at every point in space inside the sphere.(c) At the surface of the sphere, the magnetic field must be continuous across the boundary.
Therefore, we need to evaluate the magnetic field both inside and outside the sphere and make sure they match at r = R.
For r < R, we have:
B(r) = μ0 I / (2πr)
For r > R, the magnetic field is due to the current flowing on the surface of the sphere.
By Ampère's law,
we can take a circular path C of radius r centered on the z-axis, passing through the point P outside the sphere, and evaluate the magnetic field due to the current passing through the surface bounded by C. Since the current is flowing up lines of longitude, the current passing through the surface bounded by C is equal to the current passing through a circular disk of radius r on the surface of the sphere. The current density on the disk is:J = I / (4πR²),
The current passing through the disk is:Ienc = J π r²
Therefore, we have:B(r) ∫C dl = B(r) 2πr = μ0 Ienc
Solving for B(r), we obtain:B(r) = μ0 I r² / (2 R³)
At r = R, the magnetic field is:B(R) = μ0 I / (2πR) = μ0 I R / (2πR²) = μ0 J R
which is the same as the magnetic field due to the current density on the surface of the sphere.
Therefore, the magnetic field is continuous across the surface of the sphere, and our solution satisfies the magnetic field matching conditions.
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Two dimensions. In Figure 13-34, three point particles are fixed in place in an xy plane. Particle A has mass mA = 3 g, particle B has mass 2.00mA, and particle C has mass 3.00mA. A fourth particle D, with mass 4.00mA, is to be placed near the other three particles. What (a) x coordinate and (b) y coordinate should particle D be placed so that the net gravitational force on particle A from particles B, C, and D is zero (d = 22 cm)?
To make the net gravitational force on particle A from particles B, C, and D zero, particle D should be placed at the x coordinate of -11 cm and the y coordinate of 0 cm.
The net gravitational force on particle A from particles B, C, and D can be calculated using the formula for gravitational force:
F = G * (m₁ * m₂) / r²
Where F is the gravitational force, G is the gravitational constant, m₁ and m₂ are the masses of the two particles, and r is the distance between them.
Since the net gravitational force on particle A should be zero, we can set up an equation:
FAB + FAC + FAD = 0
Using the given information that the distance d is 22 cm and the masses of particles B, C, and D are known in terms of mA, we can calculate the x and y coordinates for particle D.
By applying the principle of superposition, we can calculate the net gravitational force on particle A from particles B, C, and D at the x coordinate and y coordinate of particle D. By adjusting the position of particle D, we can find the coordinates that result in a net gravitational force of zero on particle A.
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A proton and an antiproton are moving toward each other in a head-on collision. If each has a speed of
0.764c
with respect to the collision point, how fast are they moving (in terms of c) with respect to each other? (Enter your answer to at least three decimal places.)
The two particles' relative speed in terms of c is 3.583. Hence, they are moving at a speed of 3.583c with respect to each other.
The term used to describe the speed of light in a vacuum is "c." According to the special theory of relativity, the faster an object travels, the more its mass increases. Particles, for example, can travel at high speeds, and as they approach the speed of light, their mass grows to such a degree that it becomes infinite.
The Lorentz factor, which depends on an object's velocity, is used to quantify these relativistic effects. It's defined as follows:
γ = 1 / √(1 - v²/c²)
Where γ is the Lorentz factor, v is the speed of the object, and c is the speed of light.
When two particles collide head-on, they have equal and opposite momenta, and the total energy is converted into particle mass. This is also true when an antiparticle collides with a particle. When a particle and an antiparticle collide, the total energy is transformed into mass. When a proton and an antiproton collide, they annihilate each other, releasing enormous amounts of energy.
The speed of the two particles in terms of c with respect to the collision point is 0.764. So, we can find their relative speed by using the Lorentz transformation:
γ = 1 / √(1 - (0.764c)²/c²)
γ₁ = 1 / √(1 - 0.764²)
γ₁ = 1 / √(0.426)
γ₁ = 1.3904
The relative velocity between two particles is given by:
v = (v₁ - v₂) / (1 - (v₁v₂/c²))
v₁ = 0.764c
v₂ = -0.764c
v = (0.764c + 0.764c) / (1 - (0.764c)(-0.764c)/c²)
v = 1.528c / (1 - 0.764²)
v = 1.528c / 0.426
v = 3.583c
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A layer of liquid metallic hydrogen is found deep inside Jupiter (and Saturn). The hydrogen is called metallic because it ___.
Jupiter and Saturn have a layer of liquid metallic hydrogen deep inside. This layer of hydrogen is referred to as "metallic" hydrogen because it behaves as an electrical conductor and is electrically conductive.
Metallic hydrogen is a state of hydrogen in which, under extremely high pressure, it behaves as an electrical conductor. Hydrogen is a non-metallic element that is normally an insulator. Metallic hydrogen, on the other hand, has been hypothesized to be a superconductor at room temperature.
The gravitational compression inside Jupiter produces pressure and temperature conditions that are ideal for the formation of metallic hydrogen. As a result, this is where the majority of the planet's magnetic field comes from. Metallic hydrogen's electrical conductivity produces magnetic fields that extend beyond the planet's surface and form the planet's magnetosphere as it spins.
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What is specific heat capacity
Answer:
Heat capacity or thermal capacity is a physical property of matter, defined as the amount of heat to be supplied to a given mass of a material to produce a unit change in its temperature. The SI unit of heat capacity is joule per kelvin. Heat capacity is an extensive property
Why the car floated before it started to sink? Explain.
it takes the elevator in a skyscraper 4.0 s to reach its cruising speed of loms. a bu kg passenger gets aboard on the eround floor. what is the passenger's weight a. before the elevator startsm o v i n g ! b. while the elevator is speeding up? c. after the elevator reaches itscruising speed?
The passenger's weight remains the same throughout the elevator's motion. The weight is determined by the gravitational force acting on the passenger, which is unaffected by the elevator's motion.
let's consider the three scenarios:
a. Before the elevator starts moving: The passenger's weight is determined by the gravitational force acting on them. Therefore, the weight of the passenger is the same as their mass multiplied by the acceleration due to gravity (9.8 m/s^2).
b. While the elevator is speeding up: During this phase, the passenger experiences an additional acceleration due to the elevator's upward motion. The passenger's apparent weight increases, resulting from the combination of the gravitational force and the upward acceleration of the elevator. The total force acting on the passenger is the sum of their actual weight (mg) and the upward force due to acceleration (ma), where m is the mass of the passenger and a is the elevator's acceleration.
c. After the elevator reaches its cruising speed: Once the elevator reaches its cruising speed, it travels at a constant velocity, and the passenger experiences a steady state without any acceleration. At this point, the passenger's weight returns to their actual weight, determined solely by the gravitational force.
Therefore, the passenger's weight is the same before the elevator starts moving (a) and after it reaches its cruising speed (c), while it increases during the period when the elevator is speeding up (b) due to the combined effects of gravitational force and upward acceleration.
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8. Do you need to show your work on ANY problem that requires a calculation to receive full credit?
Yes
No
Answer:
Yes
Explanation:
Think about this hypothetical (not real) situation: Scientist discovered 2 new planets- Planet 11 and Planet Will. Both planets have the exact same diameter. However, Planet 11 has a MUCH stronger force of gravity. What can you infer about the relative MASS of each planet? Explain your answer.
Please answer in a full paragraph! :)
Based on the information provided, if Planet 11 has a much stronger force of gravity than Planet Will, we can infer that Planet 11 has a greater mass than Planet Will. This is because the force of gravity is directly proportional to the mass of an object. A planet with a greater mass will exert a stronger gravitational force on objects within its vicinity than a planet with a lower mass, assuming the two planets have the same diameter.
This relationship can be explained by the law of universal gravitation, which states that the force of gravity between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. Therefore, if Planet 11 has a stronger gravitational force than Planet Will, it must have a greater mass, assuming that the distance between the two planets is the same.
In summary, the stronger force of gravity on Planet 11 compared to Planet Will implies that Planet 11 has a greater mass than Planet Will.
2. Which best represents a physical property of a
substance?
A. Acids act as a corrosive to metal.
B. Gold has a density of 19.3 g/cm3.
C. Sodium combines with chlorine to create
sodium chloride.
D. Hydrochloric acid reacts with zinc metal,
creating hydrogen gas.
If the current coming out a battery in a series circuit is 2 A, the current going into
the battery on the other side must be
Answer:
2 A
Explanation:
Kirchhoff Laws to the circuit consisting more than two batteries, the current leaving the battery is as same as entering the battery
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A reaction has a standard free‑energy change of −12.50 kJ mol−1(−2.988 kcal mol−1). Calculate the equilibrium constant for the reaction at 25 °C.
Keeq=
The equilibrium constant (Keeq) for a reaction at 25 °C can be calculated using the equation Keeq = e^(−ΔG°/RT)
How can the equilibrium constant (Keeq) be calculated from the standard free-energy change (ΔG°)?The equilibrium constant (Keeq) for a chemical reaction can be calculated using the equation Keeq = e^(−ΔG°/RT), where ΔG° represents the standard free-energy change, R is the gas constant, and T is the temperature in Kelvin.
In this case, the given standard free-energy change is −12.50 kJ mol−1 (−2.988 kcal mol−1). To calculate the equilibrium constant at 25 °C, we need to convert the temperature to Kelvin by adding 273.15 (25 °C + 273.15 = 298.15 K). Then, we substitute the values into the equation to find the equilibrium constant.
Keeq = e^(−12.50 kJ mol−1 / (8.314 J K−1 mol−1 × 298.15 K))
By evaluating the expression, we can determine the equilibrium constant (Keeq) for the given reaction at 25 °C.
The relationship between standard free-energy change and equilibrium constant in chemical reactions to understand the thermodynamic aspects of chemical equilibria
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What speed would such a block have if pushed horizontally 106 m along a frictionless track by such a laser?
Speed would such a block have if pushed horizontally 106 m along a frictionless track by such a laser is 0.127 m / s
First, it is necessary to find the radiation pressure on the surface. You will find it using the following formula:
P = P / (πr ^ 2) c
where P is the pressure and c is the speed of light in vacuum
P = 27 * 10 ^ 6 / π (0.2 / 2) ^ 2 * (3 * 10 ^ 8)
= 286.62×\(10^{-2}\) = 2866N / m ^ 2.
Then you must calculate the force (F) and the acceleration (a). This is done through the formulas:
F = P * (πr ^ 2)
F = 2866 * π * (0.2 / 2) ^ 2 = 0.089N
As, a = F / m
a = 0.089 / 104 = 0.00085m / s ^ 2
You can now calculate the speed.
V = √2ad
V = √2 *0.00085 * 106
V = 0.127 m / s
The complete question is: You've recently read about a chemical laser that generates a 20.0-cm-diameter, 27.0 MW laser beam. One day, after physics class, you start to wonder if you could use the radiation pressure from this laser beam to launch small payloads into orbit. To see if this might be feasible, you do a quick calculation of the acceleration of a 20.0-cm-diameter, 104 kg, perfectly absorbing block. What speed would such a block have if pushed horizontally 106 m along a frictionless track by such a laser? Express your answer with the appropriate units.
Someone please help me
Grandma has written up a new apple pie recipe with her crazy units again that you are trying to make. The recipe
calls for 6.25 x 10 cups of cinnamon How many teaspoons do you need?
Answer:
300x480 teaspoons
Explanation:
when converting cups to teaspoons just multiply by 48
Answer:
The answer should be 3tsp
Explanation:
3tsp
The distance of east-west highway is 1.030 x 10^6m. How much is the value of mantissa in this number?
(a) 1.030
(b) 0.030
(d) 6
(c) 10
The mantissa distance, which is referred to as the decimal portion of a logarithm, has a value of 0.030 in this number.
Is the decimal portion of a number's logarithmic value referred to as the mantissa?A common logarithm's integral portion is known as the characteristic, and its non-negative decimal portion is known as the mantissa. If log 39.2 equals 1.5933, then 1 is the characteristic and 5933 is the logarithm's mantissa.
What is the number's logarithmic mantissa?The base-10 logarithm's mantissa, which represents the digits of the provided integer but not its magnitude, is a common logarithm's fractional component. For instance, both ㏒10201.3010 and ㏒102002.3010 have a mantissa of 0.3010.
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where is a hard-rubber or nonflammable comb positioned when curling the hair for a thermal design?
When curling the hair for a thermal design, a hard-rubber or nonflammable comb should be positioned near the base of the hair section.
This is because the heat from the curling iron or other thermal tool can cause the comb to melt or become damaged if it is too close to the heated area. Placing the comb near the base of the hair section also helps to create a smooth and even curl.
Additionally, using a nonflammable comb helps to prevent any potential fire hazards that could occur if a plastic comb were to come into contact with the heat source. Overall, positioning the comb properly and using the right type of comb are important factors in achieving a safe and effective thermal design.
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