find the slope please asap its due ina hour

Answer:

\( m\angle N = 32\degree \)

\( m\widehat {NQ}=106\degree \)

Step-by-step explanation:

By inscribed angle theorem:

\( m\angle N = \frac{1}{2} \times m\widehat {MP} \)

\( m\angle N = \frac{1}{2} \times 64\degree \)

\( m\angle N = 32\degree \)

Again by inscribed angle theorem:

\( m\angle P= \frac{1}{2} \times m\widehat {NQ} \)

\( 53\degree = \frac{1}{2} \times m\widehat {NQ} \)

\( 2\times 53\degree = m\widehat {NQ} \)

\( m\widehat {NQ}=106\degree \)

Answer:

2187

Step-by-step explanation:

This is the same as 3^7, which is 2187

Answer:

59049

Step-by-step explanation:

first calculate the ones inside the parentheses

(3^2)^5= (3*3)^5 = 9^5 = 9*9*9*9*9 = 81*9*9*9 = 729*9*9 = 6561*9 = 59049

Answer:

A

Step-by-step explanation:

A does not have a clear outlier.

A quarterback throws an incomplete pass. The height of the football at time t is modeled by the equation h(t) = –16t² + 40t + 7. Rounded to the nearest tenth, the solutions to the equation when h(t) = 0 feet are –0.2 s and 2.7 s.

the solution to be eliminated is -0.2s this is because time do not have negative values

ax² + bx + c = 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. a.

It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be real or complex.

Considering the given function, the answer is both real one is negative the other is positive.

The solution in this case represents time, and time of negative value do not apply in real life

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The function y = 7|x + 1| - 5 can be written as a Piecewise Function as follows,

               7x + 2                for x > -1

y   =

              -7x - 12               for x < -1

Given, a function y = 7|x + 1| - 5

Now, we have to write the given function as a piecewise function

|x + 1| = (x + 1) for x > -1 and

|x + 1| = - (x + 1) for x < -1

So, the given function can be written as a piecewise function

               7(x + 1) - 5                for x > -1

y   =

              -7(x + 1) - 5                for x < -1

On simplifying, we get

               7x + 2                for x > -1

y   =

              -7x - 12               for x < -1

Hence, the given function y = 7|x + 1| - 5 can be written as a Piecewise Function as follows,

               7x + 2                for x > -1

y   =

              -7x - 12               for x < -1

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A boat leaves port and follows a course of N72°E at 6 knots for 3 hours and 20 minutes. Then, it changes to a new course of S27°E at 12 knots for 5 hours. We need to determine the distance of the boat from the port.

To find the distance of the boat from the port, we can break down the boat's journey into two segments and calculate the distance traveled in each segment.

In the first segment, the boat travels at a speed of 6 knots for a duration of 3 hours and 20 minutes, which is equivalent to 3.33 hours. The course N72°E indicates that the boat is traveling 72° east of north. Using the formula d = v * t, where d represents the distance, v represents the velocity, and t represents the time, we can calculate the distance traveled in the first segment as 6 knots * 3.33 hours = 19.98 nautical miles.

In the second segment, the boat travels at a speed of 12 knots for a duration of 5 hours. The course S27°E indicates that the boat is traveling 27° east of south. Using the same formula, we calculate the distance traveled in the second segment as 12 knots * 5 hours = 60 nautical miles.

To find the total distance from the port, we can use vector addition. The boat's displacement in the north-south direction is 0 (since the boat changed from a northern course to a southern course), and the displacement in the east-west direction is the sum of the distances in each segment: 19.98 nautical miles + 60 nautical miles = 79.98 nautical miles.

Therefore, the boat is approximately 79.98 nautical miles from the port.

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The break-even points occur when the quantity produced, 'q' equals 11282.

The production level at which a product's expenses and revenues are equal is known as the breakeven point. When an asset's market price equals its initial cost, this is referred to as reaching the breakeven point in investment.

Consider the function,

From the data given, we can frame the expense function, which will be

E=3.60 q+44,000

Here, the value of the revenue function will be R=7.5q

In order to find the break-even point, we will equate the expense and revenue functions,

So, the value of E = value of R

=> 3.6q +44000 = 7.5 q

=>3.9q = 44000

=>q = 44000/3.9 = 11282.05 = 11282 (approximately)

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To find a recursive Nevill's method when interpolating a table using a polynomial at x = 4.1, we can use the following steps:

Step 1: Set up the given data in a table with two columns, one for f(x) and the other for x.

f(x)             x

36               1.16164956

3.80201036       4.0

0.30663842       4.2

0.35916618       -123926000.4

Step 2: Begin by finding the first-order differences in the f(x) column. Subtract each successive value from the previous value.

Δf(x)            x

-32.19798964     1.16164956

-3.49537194      4.0

-0.05247276      4.2

Step 3: Repeat the process of finding differences until we reach a single value in the Δf(x) column. Continue subtracting each successive value from the previous one.

Δ^2f(x)          x

29.7026177       1.16164956

3.44289918       4.0

Step 4: Repeat Step 3 until we obtain a single value.

Δ^3f(x)          x

-26.25971852     1.16164956

Step 5: Calculate the divided differences using the values obtained in the previous steps.

Divided Differences:

Df(x)             x

36                1.16164956

-32.19798964     4.0

29.7026177       4.2

-26.25971852     -123926000.4

Step 6: Apply the recursive Nevill's method to find the interpolated value at x = 4.1 using the divided differences.

f(4.1) = 36 + (-32.19798964)(4.1 - 1.16164956) + (29.7026177)(4.1 - 1.16164956)(4.1 - 4.0) + (-26.25971852)(4.1 - 1.16164956)(4.1 - 4.0)(4.1 - 4.2)

Solving the above expression will give the interpolated value at x = 4.1.

Q2: To construct an approximation polynomial using the Hermite method, we follow these steps:

Step 1: Set up the given data in a table with three columns: f(x), f'(x), and x.

f(x)             f'(x)              x

2.572152         7.615964          1.2

3.602102         13.97514          1.3

5.797884         34.61546          1.4

14.101442        199.500           1.5

Step 2: Calculate the divided differences for the f(x) and f'(x) columns separately.

Divided Differences for f(x):

Df(x)            \(D^2\)f(x)           \(D^3\)f(x)

2.572152         0.51595           0.25838

Divided Differences for f'(x):

Df'(x)           \(D^2\)f'(x)

7.615964         2.852176

Step 3: Apply the Hermite interpolation formula to construct the approximation polynomial.

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Answer:

$8 for 3 pounds

cost for p pounds: 3.50p - 2.50

Step-by-step explanation:

Cost of 3 pounds:

Original cost = Cost per pound x 3

= 3.50 x 3

= 10.50

Coupon = 2.50

Final cost = Original cost - Coupon

= 10.50 - 2.50

= $8

Cost of p pounds:

Original cost = Cost per pound x p

= 3.50 x p

= 3.50p

Coupon = 2.50

Final Cost = Original Cost - Coupon

= 3.50p - 2.50

Ai Mi has to pay $8 to buy 3 pounds of chicken.  An expression for the cost to buy p pounds of chicken would be; 3.50p - 2.50

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

The Cost of 3 pounds:

Thus Original cost = Cost per pound x 3

= 3.50 x 3

= 10.50

Also, we know that the Coupon cost is 2.50

The Final cost = Original cost - Coupon

= 10.50 - 2.50

= $8

Now Let the Cost of pounds is p

The Original cost = Cost per pound x p

= 3.50 x p

= 3.50p

Also the cost of the Coupon = 2.50

The Final Cost = Original Cost - Coupon

= 3.50p - 2.50

Hence, Ai Mi has to pay $8 to buy 3 pounds of chicken.  An expression for the cost to buy p pounds of chicken would be; 3.50p - 2.50

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Answer:

\( \frac{7}{4} \pi\)

or

\( \frac{3}{4} \pi\)

Step-by-step explanation:

See attached. I know (very haphazard). But the basic method is to inverse the trig function. This gives you the position of the terminal angle. -45 degrees means that you turned 45 degrees clockwise and are in quadrant 4. This corresponds to an angle of rotation of 315 degrees counter clockwise which is what we are looking for since the specified domain is betwern 0 and 360 degrees or 0 and 2 pi.

The next thing to remember is that Tan is also negative in Quadrant 2 (using the ASTC rule). This corresponds to an angle of rotation of 180 - 45 = 135 degrees.

Hope that helps.

Answer:

\( \frac{1}{4} - \frac{1}{12} \)

to make denominators same multiply 1/4 by 3 both up and down :

\( = \frac{1 \times 3}{4 \times 3} - \frac{1}{12} \\ = \frac{3}{12} - \frac{1}{12} \\ = \frac{2}{12} \\ = \frac{1}{6} \: (ans)\)

option B. $19.72 took the quiz and got 100%

Answer:

option B

Step-by-step explanation:

I took the test and got 100 on it

edge2020

Therefore , the solution of the given problem of truth table comes out to be 32 rows in the truth table.

An expression potential truth values can be mapped out and their results can be determined using a truth table. Each expression variable is represented by a column in the table, and each conceivable combo of truth variables is represented by a row. A column that displays the results of each value set is also included.

Here,

We must understand what a truth table is in order to determine how many rows there are in a truth table with five variables.

A truth table deconstructs a logic function by outlining all potential outcomes the function might achieve.

There are numerous rows and columns in the truth table.

The logical variables and combinations on the top row are shown in descending order of complexity from the final function.

The amount of fundamental statement letters that will be used in the set of formulas will decide how many rows are required for the truth table.

2n, where n is the total number of basic statement letters used, is the formula for calculating the number of rows.

There are  2ⁿ rows.

If a truth table has 5 variables, then there will be 25 rows.

2⁵ = 2×2× 2× 2× 2

= 32 .

Therefore , the solution of the given problem of truth table comes out to be 32 rows in the truth table.

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Add up the number of students within the random sample data:
32+26+28+22 = 108

We can then use proportional fractions / cross-multiply to answer the question.

In a sample size of 108 students, 32 of them preferred Movie A.
There are 900 students in total.

\(\frac{32}{108} =\frac{x}{900}\)

32*900 = 28800

108*x = 108x

108x = 28800

x = \(266\frac{2}{3}\) or \(\frac{800}{3}\)

In decimal form that is approximately 266.667 and round that to the nearest whole number, you get 267 students who would prefer Movie A.

Answer:

Option B, 8 / 6

Step-by-step explanation:

Tangent = Opposite / Adjacent

Tangent of ∠A = Opposite / Adjacent

Tan(A) = 8 / 6 which is the same as Option B

Hope this helps!

Answer:

6

Step-by-step explanation:

Took the test

Answer:

6

Step-by-step explanation:

Answer:

1. -4^3

-64

2. (-4)^3

-64

3. 4^3

64

Answer:

A

Step-by-step explanation:

Put the values of x and y into the expression, then multiply the values.

7 x 3 x 2 x 4 = 168

Answer:

B. 252

Step-by-step explanation:

\(7x^2y\)

Put x as 3 and y as 4.

\(7\left(3\right)^2\left(4\right)\)

Evaluate.

\(7(9)(4)\)

\(=252\)

Answer: 192 cubic inches

Step-by-step explanation:

The required statement "outlier in a data set can significantly affect the value of the mean but not the median" is true.

The average of a group of variables is referred to as the mean in mathematics and statistics. There are several methods for calculating the mean, including simple arithmetic means (adding the numbers together and dividing the result by the number of observations), geometric means, and harmonic means.

The average of a group of variables is referred to as the mean in mathematics and statistics.

There are several methods for calculating the mean, including simple arithmetic means (adding the numbers together and dividing the result by the number of observations), geometric means, and harmonic means.

Thus, given statement is true.

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Answer:

Task 1:

The roller coaster is modeled by a half-circle with the center at the origin and a highest point of 30 feet above the ground. The general equation of a circle with the center at the origin is x^2 + y^2 = r^2, where r is the radius of the circle. Since the roller coaster is a half-circle, the radius of the circle is 30 feet. Thus, the equation of the roller coaster is:

x^2 + y^2 = 30^2

x^2 + y^2 = 900

Task 2:

To solve for y, we isolate y and take the square root of both sides. Since we are only interested in the positive root, we get:

y = sqrt(900 - x^2)

Task 3:

The graph of the roller coaster is shown below:

Task 4:

To find the horizontal distance each beam is from the origin, we need to solve for x in the equation of the circle when y = 25. Substituting y = 25, we get:

x^2 + 25^2 = 900

x^2 = 400

x = ± 20

Since we are only interested in the positive value of x, the horizontal distance each beam is from the origin is 20 feet.

Task 5:

We need to place the two beams equidistant from the axis of symmetry of the roller coaster, which is the y-axis. Therefore, we place one beam at (20, 0) and the other beam at (-20, 0).

Task 6:

The cable is modeled by the equation y = -x + 30 and the strut is modeled by the equation y = -x/3. The graph of the cable and the strut on the model of the roller coaster is shown below:Task 7:

To find the point where the cable and the strut intersect, we need to solve the system of equations:

y = -x + 30

y = -x/3

Substituting the second equation into the first equation, we get:

-x/3 = -x + 30

2x/3 = 30

x = 45

Substituting x = 45 into the second equation, we get:

y = -x/3

y = -45/3

y = -15

Therefore, the cable and the strut intersect at the point (45, -15). This means that the cable and the strut intersect 15 feet below the ground level of the roller coaster at a horizontal distance of 45 feet from the origin.

Task 8:

The two struts are modeled by the equations y = 10x/3 and y = -10x/3. The graph of the two struts on the model of the roller coaster is shown below:

Task 9:

To find the x-value of where the beam should be placed, we need to find the intersection point of the two struts when they are 2 feet apart. We can set the two equations equal to each other and solve for x:

10x/3 = -10x/3 + 2

20x/3 = 2

x = 3/10

Therefore, the reinforcement beam should be placed at a horizontal distance of 3/10 feet from the origin.

Task 10:

We need to place the vertical reinforcement beam at a horizontal distance of

Step-by-step explanation:

x^2 + y^2 = 900

Solving for y:

y = sqrt(900 - x^2)

Equation to find the horizontal distance each beam is from the origin:

sqrt(x^2 + y^2) = d

where d is the distance from the origin to each beam.

Solving for d when y = 25:

sqrt(x^2 + 25^2) = d

d = sqrt(x^2 + 625)

Algebraically solving for x:

d = sqrt(x^2 + 625)

d^2 = x^2 + 625

x^2 = d^2 - 625

x = sqrt(d^2 - 625)

The two beams should be placed at x = ±sqrt(575).

To find the point of intersection, we need to solve the system of equations:

y = -0.2x + 30 (equation of the strut)

y = -0.5x + 30 (equation of the cable)

Setting the two equations equal to each other:

-0.2x + 30 = -0.5x + 30

0.3x = 0

x = 0

Substituting x = 0 into either equation to find y:

y = -0.2(0) + 30 = 30

The cable and strut intersect at the point (0, 30), which is the highest point of the roller coaster.

To find the x-value where the beam should be placed, we need to solve the equation:

sqrt(x^2 + 25^2) - sqrt((2 - x)^2 + 25^2) = 2

Squaring both sides:

x^2 + 625 - 2sqrt(x^2 + 625)((2 - x)^2 + 625) + (2 - x)^2 + 625 = 4

Expanding and simplifying:

-4x^3 + 16x^2 - 16x - 15 = 0

Using a graphing calculator or numerical methods, we find that the only real solution is x ≈ 2.5.

The beam should be placed at x = 2.5.

What is an equation?

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Given:

y = x³ + 2x +5

z = x² + 7x + 1

To find: Value of 2y + z in terms of x

Finding:

Now, 2y = 2 (x³ + 2x + 5) = 2x³ + 4x + 10

Then, 2y + z =  2x³ + 4x + 10 + x² + 7x + 1

=> 2y + z = 2x³ + x² + 11x + 11

Hence, Option C is the correct option.

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Answer:

y = -x + 6

Step-by-step explanation:

We can plug the given point and slope into the point-slope formula and solve for the y-intercept formula.

y - y = m(x - x)  <-- Point-Slope Formula

m = -1

(x,y) = (1, 5)

y - 5 = -1(x - 1)

y - 5 = -x + 1

y = -x + 6   <-- Y-intercept Formula

Answer:

We can use the standard normal distribution to solve this problem, by standardizing the salary value of $53,000 using the given mean and standard deviation:

z = (X - μ) / σ

where X is the salary value of $53,000, μ is the mean of $40,756, and σ is the standard deviation of $7500.

z = (53,000 - 40,756) / 7500 = 1.63547

Using a standard normal distribution table or calculator, we can find the proportion of employees who earn at most $53,000 by finding the area to the left of the standardized value of 1.63547:

P(Z ≤ 1.63547) = 0.9514

Therefore, approximately 95.14% of employees in entry-level positions at the company earn at most $53,000.

The probability of not drawing a blue marble in the first trial is given by the ratio of the number of yellow marbles to the total number of marbles: 8/10. After removing one yellow marble, the probability of not drawing a blue marble in the second trial becomes 7/9. Similarly, for the third trial, the probability is 6/8, and for the fourth trial, it is 5/7. To find the probability of not drawing a blue marble in all four trials, we multiply these individual probabilities together: (8/10) * (7/9) * (6/8) * (5/7) = 0.2.

To calculate the probability of not drawing a blue marble in the first four trials, we use the concept of conditional probability. We assume that each marble is drawn without replacement, meaning that once a marble is selected, it is not put back into the pocket. Since the marbles are drawn randomly, the probability of choosing a specific marble on any given trial depends on the composition of the remaining marbles. In this case, we multiply the probabilities of each trial together because we want to find the probability of multiple independent events occurring consecutively.

2. The probability of having exactly one blue marble within the first four trials can be calculated using a combination of probabilities. There are four possible positions for the blue marble within the four trials: first trial, second trial, third trial, or fourth trial. We can calculate the probability of having the blue marble in each of these positions and sum them up.

The probability of the blue marble being in the first trial is (2/10) * (8/9) * (7/8) * (6/7) = 0.1333.

The probability of the blue marble being in the second trial is (8/10) * (2/9) * (7/8) * (6/7) = 0.1333.

The probability of the blue marble being in the third trial is (8/10) * (7/9) * (2/8) * (6/7) = 0.1333.

The probability of the blue marble being in the fourth trial is (8/10) * (7/9) * (6/8) * (2/7) = 0.1333.

Adding these probabilities together gives a total probability of 0.1333 + 0.1333 + 0.1333 + 0.1333 = 0.5333.

We use the concept of conditional probability and calculate the individual probabilities for each position where the blue marble can be found. In each calculation, we multiply the probability of selecting a blue marble in the given position with the probabilities of selecting yellow marbles in the other positions. Then, we add up these individual probabilities to find the overall probability of having exactly one blue marble within the first four trials.

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Using BODMAS, the solutions of the expressions are: (1) 9, (2)-12, (3) 0.27, and (4) 0.24

We should know that BODMAS is a mathematical approach which means

In each of the expressions, we must follow the approach

1)    \(\frac{(6+3)^{2} }{3*9}\)

Simplifying this we have 9²/9=81/9

=9

2)  \(\frac{3^{2} -6*2}{(12-8)/2^{2} *10}\)

Using BODMAS we have

(9-12)/4/40

-3÷1/9

⇒-3*4

=-12

(3)   \(\frac{4.5+2*2.5^{2}-6 }{8*4+9}\)

Using BODMAS we have

(4.5+2*6.25-6)/32+9

⇒(4.5+12.5-6)/41

=11/41=0.27

4     (\(\frac{3.5+16-2.5^{2} }{10.5-6*11}\))

Using BODMAS we have  

(3.5+16-6.25)/10.5-66

Simplifying

(13.25)/-55.5

=0.24

Therefore, the values when simplified are  (1) 9, (2)-12, (3) 0.27, and (4) 0.24

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The correct statement which expresses the number correctly is "In 2,015 we had over 5,400 employees; today we have only 4,500."

Hence, the correct answer is option b.

Sentence B is the correct one as it uses the standard format for expressing large numbers, which is to use commas as the thousands separator. This format is widely accepted in English-speaking countries and is recommended by various style guides, including the Associated Press Stylebook and the Chicago Manual of Style.

Sentence A does not use any thousands separator, which can make the number harder to read and comprehend. Sentence C uses a period instead of a comma, which can cause confusion and is not a standard practice in English-speaking countries. Sentence D is not provided, so it cannot be evaluated for correctness.

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-- The given question is incomplete, the complete question is

"Which sentence expresses numbers correctly? a. In 2015 we had over 5400 employees; today we have only 4500. b. In 2,015 we had over 5,400 employees; today we have only 4,500. c. In 2015 we had over 5.400 employees: today we have only 4,500." --

In mathematics, "\(a^2\)" denotes the square of a number or variable "a." It is calculated by multiplying "a" by itself.

4For example, if "a" is 5, then a^2 would be 5*5, which equals 25. When "a" represents a positive number, its square is always positive.

If "a" is negative, its square is still positive since a negative multiplied by a negative results in a positive.

In geometrical terms, if "a" represents the length of the side of a square, then a^2 represents the area of that square. This notation is part of the general concept of exponentiation.

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The Question in English

What does a^2 mean in mathematics