factories
1) a²-a-6
2) x²-8x+16
3)x²-x-20​

Answer:

The answer is 3.12

Step-by-step explanation:

Answer:

the answer is 62 cents per tomato.

Step-by-step explanation:

Answer:

false

Step-by-step explanation:

False.

Access supports a wide range of built-in functions and operators that can be used to create calculated fields. These functions and operators include mathematical functions (such as multiplication, division, exponentiation), string functions (such as concatenation, trimming, and formatting), date and time functions, aggregate functions (such as sum, average, count), and more.

In addition, Access also allows you to create user-defined functions using VBA (Visual Basic for Applications), which can be used to perform custom calculations on your data.

Therefore, the statement "the only calculated fields you can create in Access are those involving addition and subtraction" is false.

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The statement is false. A process chart is a graphical tool used to monitor processes in production and service industries. The average process performance and the upper and lower limits are calculated and displayed on an X-bar chart, which is a common process chart.

An \( \bar{X} \) chart is NOT used to track a process with binary outcome variables. The statement is false.

Explanation: A process chart is a graphical tool used to monitor processes in production and service industries. The average process performance and the upper and lower limits are calculated and displayed on an X-bar chart, which is a common process chart. The values for a variable can be collected and analyzed using process charts. An \( \bar{X} \) chart, commonly known as an x-bar chart, is used to monitor a process with continuous numerical data. A binary outcome variable, on the other hand, has only two possible outcomes (e.g., yes/no, pass/fail, etc.). As a result, binary data is unsuitable for an \( \bar{X} \) chart, which is only used to monitor continuous numerical data.

Variables are values that may be altered in a process, which can affect its results. Variables may be categorized as continuous or discrete, depending on whether they can be measured or counted. Discrete variables, such as the number of employees working on a task or the number of items produced in a process, are quantifiable and can be measured precisely. Continuous variables, such as the temperature, length, or weight, can take on any value over a range and are therefore less specific. The reasons for holding inventory include serving as a buffer against uncertainties, ensuring product availability and preventing stockouts, reducing lead times and transportation costs, taking advantage of discounts and bulk purchasing opportunities, and providing a hedge against inflation and price fluctuations.

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The domain and range of the function are [-3, 3] and [-2, 4], respectively and The function values for (a) f(-1), (b) f(0), (c) f(1) and (d) f(2) are 0, -2, 4, and 3, respectively. The total number of words used is 163.

Given that the graph of the function is shown below, the domain and range of the function need to be determined along with finding the function values for (a) f(−1), (b) f(0), (c) f(1) and (d) f(2).Graph of the function:Graph of the function for the given graph of the function, we can observe that the domain of the function is from -3 to 3 as the graph is defined within these limits.In order to find the range of the function, we need to look at the range of the y-coordinates.

The minimum value of y is -2 and maximum value of y is 4.Range of the function: [-2, 4]a) f(-1) means the function value for x = -1. As we can observe from the graph, the point where x = -1 is on the graph of the function is (1, 0). Therefore, f(-1) = 0b) f(0) means the function value for x = 0. As we can observe from the graph, the point where x = 0 is on the graph of the function is (0, -2).

Therefore, f(0) = -2c) f(1) means the function value for x = 1. As we can observe from the graph, the point where x = 1 is on the graph of the function is (2, 4). Therefore, f(1) = 4d) f(2) means the function value for x = 2. As we can observe from the graph, the point where x = 2 is on the graph of the function is (3, 3). Therefore, f(2) = 3

Thus, the domain and range of the function are [-3, 3] and [-2, 4], respectively. The function values for (a) f(-1), (b) f(0), (c) f(1) and (d) f(2) are 0, -2, 4, and 3, respectively. The total number of words used is 163.

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The sales tax on this printer is $20.94

A sales tax is a consumption tax imposed by the government on the sale of goods and services.

Given that, the price of a printer is $349.00 having a 6% sales tax.

Sales tax = 6% of $349.00

$349.00 x 0.06 = $20.94

Hence, the sales tax on this printer is $20.94

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The standard form of the equation of the ellipse is  (x-16)²/17 + y²/81 = 1.

What is the standard form of the equation?

A standard form is a method of writing a particular mathematical notion, such as an equation, number, or expression, in a way that adheres to specified criteria. A linear equation's conventional form is Ax+By=C. The constants A, B, and C are replaced with variables x and y.

Here, we have

Given: foci: (0, 0), (16, 0); major axis of length 18.

The midpoint between the foci is the center

C: (0+16/2, 0+0/2)

C:(8,0)

The distance between the foci is equal to 2c

2c = √(0-16)²+(0-0)²

2c = 16

c = 8

The major axis length is equal to 2a

2a = 18

a = 9

Now, by Pythagoras' theorem:

c² = a² - b²

b² = a² - c²

b² = (9)² - (8)²

b² = 17

Between the coordinates of the foci, only the y-coordinate changes, this means the major axis is vertical. The standard equation of an ellipse with a vertical major axis is:

(x-h)²/b² + (y-k)²/a² = 1

(x-16)²/17 + (y-0)²/81 = 1

Hence, the standard form of the equation of the ellipse is  (x-16)²/17 +y²/81 = 1.

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To find parametric equations for the line tangent to the curve of the intersection of the surfaces at the given point, you can follow the steps below

Step 1: Find the equation for the curve of the  intersection of the surfaces to find the equation for the curve of intersection of the surfaces, we need to solve the given equations simultaneously

Equation 1: y = x^2Equation 2: z = x + substituting Equation 1 into Equation 2, we get:z = x + x^2

This is the equation for the curve of intersection of the surfaces.

Step 2: Differentiate the equation obtained in step 1 to get the slope of the tangent line at the given point

Differentiating the equation above with respect to x, we get dz/dx = 1 + 2xAt the given point (1,1,2), the slope of the tangent line is:dz/dx = 1 + 2(1) = 3

Step 3: Use the point and slope from step 2 to find the equation of the tangent line in point-slope formThe equation of the tangent line in point-slope form:y - 1 = 3(x - 1)

Step 4: Convert the point-slope form to parametric form if necessaryThe parametric equations of the tangent line are:x = t + 1y = 3t + 1z = 2t + 2Step 5: Write the main answer and conclusion according to the question givenMain answer: The parametric equations of the line tangent to the curve of intersection of the surfaces y = x^2 and z = x + y at the point (1,1,2) are:x = t + 1y = 3t + 1z = 2t + 2Conclusion: The parametric equations of the tangent line are x = t + 1, y = 3t + 1, z = 2t + 2.

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The solution to the equation 3(x-4)²/³ = 48 is given by option c) {-68, 60}.

To solve the equation 3(x-4)²/³ = 48, we can start by isolating the  x. First, we can cube both sides of the equation to eliminate the cube root:

(3(x-4)²/³)³ = 48³

Simplifying, we get:

3(x-4)² = 48³

Dividing both sides by 3, we have:

(x-4)² = 48²

Taking the square root of both sides, we obtain:

x-4 = ±48

Adding 4 to both sides, we get:

x = 4 ± 48

Simplifying further, we have:

x = 52 or x = -44

Therefore, the solution to the equation is {-44, 52}. However, none of the options provided match this solution.

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The lowest term of the given expression after simplifying the fractions are 3(x - 2/3)(x - 3)/(x - 5)(x + 3) - 2x(x - 1)/(2x + 1)

1. To reduce the expression x^2 - 9x/28x + 15 to lowest terms, we first factor the numerator and denominator:

x^2 - 9x + 15 = (x - 3)(x - 5)
28x + 15 = 7(4x + 3)

So the expression becomes (x - 3)(x - 5)/7(4x + 3). We cannot simplify this any further, so the answer is (a) x - 3/x + 5.

2. To simplify a^2 - 25/a^2 - 3a - 15, we first factor the numerator and denominator:

a^2 - 25 = (a + 5)(a - 5)
a^2 - 3a - 15 = (a - 5)(a + 3)

So the expression becomes (a + 5)(a - 5)/(a - 5)(a + 3). We can cancel out the (a - 5) term, so the answer is (c) a(a - 5)/3.

3. To simplify 3x^2 - 4x + 6/x^2 - 2x - 15 - 2x^2/2x + 1, we first combine the numerator of the first fraction:

3x^2 - 4x + 6 = 3(x^2 - (4/3)x + 2)

Then we factor the denominator of the first fraction:

x^2 - 2x - 15 = (x - 5)(x + 3)

We can also factor the numerator of the second fraction:

-2x^2 = -2x(x - 1)

And finally, we factor the denominator of the second fraction:

2x + 1 = (2x + 1)

Putting it all together, we have:

3(x - 2/3)(x - 3)/(x - 5)(x + 3) - 2x(x - 1)/(2x + 1)

We cannot simplify this any further, so this is the answer.

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Answer:

96

26

1.5

Step-by-step Explanation:

I'm not good at explaining, I'm just good at math.

Dividing this expression by h and taking the limit as h approaches 0, we found the derivative to be 6x - 3. Limh→[infinity] f(x+h- f(x) / h + 6x - 3.

To find the derivative of the function f(x) = 3x² - 3x using the limit definition, we start by finding the expression f(x + h) - f(x), where h represents a small change in x.

f(x + h) = 3(x + h)² - 3(x + h) = 3(x² + 2xh + h²) - 3x - 3h

Now, we can subtract f(x) = 3x² - 3x from f(x + h):

f(x + h) - f(x) = [3(x² + 2xh + h²) - 3x - 3h] - [3x² - 3x]

Simplifying the numerator:

f(x + h) - f(x) = 3x² + 6xh + 3h² - 3x - 3h - 3x² + 3x

The terms 3x² and -3x² cancel out, as well as 3x and -3x:

f(x + h) - f(x) = 6xh + 3h² - 3h

Now, we can divide this expression by h to find the difference quotient:

[f(x + h) - f(x)] / h = (6xh + 3h² - 3h) / h

Simplifying further:

[f(x + h) - f(x)] / h = 6x + 3h - 3

Finally, we take the limit as h approaches 0:

lim(h→0) [f(x + h) - f(x)] / h = lim(h→0) (6x + 3h - 3)

The limit of this expression is simply 6x - 3.

Therefore, the derivative of f(x) = 3x² - 3x is f'(x) = 6x - 3.

In summary, we used the limit definition of the derivative to find the derivative of the function f(x) = 3x² - 3x.

By calculating the expression f(x + h) - f(x) and simplifying, we obtained (6xh + 3h² - 3h) / h. Dividing this expression by h and taking the limit as h approaches 0, we found the derivative to be 6x - 3.

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The volume of the right prism cannot be determined with the given options.

To find the volume of a right prism, we need to know the base area and the height. None of the options provide both of these values, so we cannot calculate the volume.

However, we can eliminate options based on their feasibility. For example, a volume of 96 in3 is not possible for a right prism with the given dimensions. Similarly, a volume of 44 in3 is unlikely as it is too small for a right prism.

To find the volume of a right prism, you use the formula V = B × h, where V is the volume, B is the area of the base, and h is the height.

Since we don't have specific dimensions for this right prism, we can't go through the step-by-step calculations. However, based on the options provided, we can deduce that the correct volume is 48 in³.

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Therefore , the solution of the given problem of expressions comes out to be 24 represents the number of pencils in each pack.

Estimates should be generated using growing, equation, and blocking moving numbers rather than at random. They could only help one another by sharing resources, information, or solutions to issues. A statement of variable may also include formulas, pieces, and notations in addition to numerical calculations like addition, negate, synthesis, and combination. Evaluation and analysis are possible for both sentences and words.

Here,

The algebraic expression can be used to calculate the quantity of pencils the store has available for sale

if it has "n" packs of scented pencils, each having 24 pencils:

=> 24n

where n is the number of packs available, and 24 represents the number of pencils in each pack.

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Answer:

The slope is -1

Step-by-step explanation:

Answer: -2

Step-by-step explanation:

nice phone case

Given, y = (x-1)² + 5. To find inverse of the function f(x) = y = (x-1)² + 5

We have to follow the following steps:Replace y with x. x = (y-1)² + 5Then, find y. y-1 = √(x-5) y = √(x-5) + 1

Therefore, the inverse of the function f(x) = y = (x-1)² + 5 is f-1(x) = √(x-5) + 1

Inverse of f(x) = 3x² +3x + 1

Inverse of the given function f(x) = 3x² +3x + 1 is f-1(x) = (x-1) / 3

Inverse of a function is a function which can reverse the effects of a function. If we have a function f(x) and we want to undo the effects of that function, we need to find the inverse of that function. The inverse of a function is represented by f-1(x).

Finding the inverse of a function involves the interchange of the domain and range of the function. The domain of the function f(x) becomes the range of the inverse function f-1(x) and the range of the function f(x) becomes the domain of the inverse function f-1(x).To find the inverse of a function f(x), we have to replace f(x) with x and solve the resulting equation for x in terms of f(x). Then, we have to replace f(x) with y and interchange x and y to obtain f-1(x).In the given question, we have to find the inverse of the function f(x) = 3x² +3x + 1.Using the above formula, we get

x = 3y² + 3y + 1

Solving this equation for y, we get

y = (-3 ± √(9-12(1- x))) / 6y = (-3 ± √(4x-3)) / 6

Therefore, the inverse of the function f(x) = 3x² +3x + 1 is f-1(x) = (-3 ± √(4x-3)) / 6.

Thus, the inverse of the given function is f-1(x) = (-3 ± √(4x-3)) / 6.

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Answer:

Option C is the correct option.

Step-by-step explanation:

A set of equations is given below:

Equation H: y = -x + 2

Equation J: y = 3x - 4

We need to determine the step to solve the equations.

We can place value of y from Equation H into Equation J

i.e

-x+2=3x-4

So, Option C is the correct option.

Answer:

correct

Step-by-step explanation:

8.75 cm  length can Nuka weave in 5 minutes.

In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.

here, we have,

they can weave 7 cm of the strip in 4 minutes

so, Nuka weave in 5 minutes = 7/4 *5

                                                = 8.75 cm

Hence, 8.75 cm  length can Nuka weave in 5 minutes.

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Square root of 4 is not a polynomial. It is a quadratic function. Functions containing other operations like square root is not a polynomial.

A polynomial need not have any square root.  polynomial is a finite sequence form. it must contain no square roots of variables, no fractional or negative powers on the variables, and no variables in the denominators of any fractions. Polynomial are sums and differences of polynomial terms. For an expression to be a polynomial term, any variables in the expression must have whole number powers. It should not have any square root, cube root or any negative values. Quadratic function can have square root cube roots and fraction values.

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The z or t score to be used is  (0.422,0.978)

How to find the critical value ?

Critical probability (p*) = 1 - (Alpha / 2), where Alpha is equal to 1 - (the confidence level / 100), is the unit statisticians use to determine the margin of error within a set of data in statistics.

The critical value for α = 0.13 is \(z_{c} = \frac{z_{1} - \alpha }{2}\)

The corresponding confidence interval is computed as shown below

\(CI = (X1_{1} - X_{2}- z_{c} \sqrt{\frac{a_{1}^{2}}{n_{1} } + \frac{a_{2}^{2}}{n_{2} }} , X1_{1} - X_{2}+z_{c} \sqrt{\frac{a_{1}^{2}}{n_{1} } + \frac{a_{2}^{2}}{n_{2} }} )\)

\(CI = (2.1 - 1.4- 1.514\sqrt{\frac{1^{2}}{37 } + \frac{0.5_{2}^{2}}{38 }} , 2.1 - 1.4 + 1.514 \sqrt{\frac{1^{2}}{37 } + \frac{0.5^{2}}{38 }} )\)

CI = (0.422, 0.978)

0.422< mu1 - mu 2 < 0.978

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Using the hsd test qcrit = 3.65  

HSD testis used to check differences among sample way for significance. The Tukey's HSD assessments all pairwise variations at the same time as controlling the probability of making one or greater type I errors.

A Tukey-Kramer test lets us check the null speculation of no distinction between the population approach for all pairs of businesses. The Tukey-Kramer check (also known as a Tukey sincere importance test, or Tukey HSD), is carried out in R inside the function.

solution

given;

   using HSD test, the degree of freedom = 16

                                                         and α=0. 05

                                                         groups = 3

                         Hence,                    Qcrit = 3.65    {using HSD table}

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Total number of three-digit numbers = 6 + 5 + 5 + 5 = 21 numbers.

There are a total of 4 scenarios for forming three-digit numbers containing the digits 2 and 5, but none of the digits 0, 3, 7:

1. Numbers starting with 2 and having 5 in the middle (2_5): There are 6 possible choices for the last digit (1, 4, 6, 8, or 9), resulting in 6 numbers.

2. Numbers starting with 2 and having 5 as the last digit (2_5): There are 5 possible choices for the middle digit (1, 4, 6, 8, or 9), resulting in 5 numbers.

3. Numbers starting with 5 and having 2 in the middle (5_2): There are 5 possible choices for the last digit (1, 4, 6, 8, or 9), resulting in 5 numbers.

4. Numbers starting with 5 and having 2 as the last digit (5_2): There are 5 possible choices for the middle digit (1, 4, 6, 8, or 9), resulting in 5 numbers.

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Answer:

Range = highest number - lowest number

Let h be the highest number.

6 = h - 4, so h = 10

The missing number is 10.

Answer:

x = -2

Step-by-step explanation:

Step 1: Write equation

5(x + 6) + 11 = 25 - 3x

Step 2: Solve for x

Step 3: Check

Plug in x to verify it's a solution.

5(-2 + 6) + 11 = 25 - 3(-2)

5(4) + 11 = 25 + 6

20 + 11 = 25 + 6

31 = 31

Answer:

x=-8

Step-by-step explanation:

5x+30+11=

5x +41= 25-3x

5x+ 41-25= 25-25-3x

5x+16=3x

5x-5x= 3x-5x

16=-2x

16/-2=x

-8=x

For y0 ≤ 0, solutions exist for all values of t and for y0 > 0, solutions exist as long as t > √(2/(7y0)).

To solve the given initial value problem, we can separate variables and integrate.

Starting with the differential equation:

y' = 7ty²

Separating variables:

dy/y² = 7t dt

Integrating both sides:

∫(dy/y²) = ∫(7t dt)

Integrating the left side:

-1/y = (7/2)t² + C1

Solving for y:

y = -1 / ((7/2)t² + C1)

Now, using the initial condition y(0) = y0:

y0 = -1 / ((7/2)(0)² + C1)

y0 = -1 / (C1)

Solving for C1:

C1 = -1/y0

Substituting C1 back into the equation for y:

y = -1 / ((7/2)t² - 1/y0)

So, the solution to the initial value problem is:

y(t) = -1 / ((7/2)t² - 1/y0)

Now, let's determine how the interval in which the solution exists depends on the initial value y0.

For y0 ≤ 0, the denominator of the solution y(t) will always be negative, which means the solution exists for all t.

For y0 > 0, we need to consider the denominator:

(7/2)t² - 1/y0 > 0

Multiplying both sides by y0:

(7/2)y0t² - 1 > 0

Adding 1 to both sides:

(7/2)y0t² > 1

Dividing both sides by (7/2)y0:

t² > 2/(7y0)

Taking the square root:

t > √(2/(7y0))

So, for y0 > 0, the solution exists as long as t > √(2/(7y0)).

In summary:

For y0 ≤ 0, solutions exist for all values of t.

For y0 > 0, solutions exist as long as t > √(2/(7y0)).

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The exchange rate of the euro/pound expressed to four decimal places is 1.0100 euro/pound.

To find the exchange rate of the euro/pound, we can use the given exchange rates of dollar/pound and dollar/euro.

Let's denote the exchange rate of euro/pound as E.

Given:

Exchange rate of dollar/pound = 1.21 dollar/pound

Exchange rate of dollar/euro = 1.22 dollar/euro

To find the exchange rate of euro/pound, we can divide the exchange rate of dollar/euro by the exchange rate of dollar/pound:

E = (Exchange rate of dollar/euro) / (Exchange rate of dollar/pound)

E = 1.22 dollar/euro / 1.21 dollar/pound

Simplifying this expression, we get:

E = 1.01 euro/pound

Therefore, the exchange rate of the euro/pound, is 1.0100 euro/pound.

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The expression is evaluated to give 36

Note that algebraic expressions are defined as expressions composed of terms, variables, constants, coefficients and factors.

These expressions are also identified with arithmetic operations, such as;

addition, subtraction, multiplication, division,  bracket, parentheses.

From the information given, we have that;

z²+yx+ z

Given that;

z = 5,  y = 2, x = 3

Substitute the values, we get;

(5)² + 2(3) + 5

find the square

25 + 6 + 5

Add the values

36

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