explain how to use a graph of the function f(x)tk find f(3)

Answer:

21 pencils

Step-by-step explanation:

b 21 pencils

Answer:

$24

Step-by-step explanation:

First, find the cost to cover one pair of shoes.

Cost to cover one pair of shoes = surface area of the shoe box × cost per square inch

= 2(LW + LH + HW) × 0.02

L = 14 in.

W = 8 in.

H = 4 in.

Plug in the values

Cost to cover one pair of shoes = 2(14*8 + 14*4 + 4*8) × 0.02

= 2(112 + 56 + 32) × 0.02

= 2(200) × 0.02

= 400 × 0.02 = 8

Cost to cover one pair of shoes = $8

Cost to cover 3 pairs of shoes = 3*8 = $24

Answer:

a = 14, b = 3.5

Step-by-step explanation:

XZ = XY , then

2a + 3b = 11b ( subtract 3b from both sides )

2a = 8b ( divide both sides by 2 )

a = 4b

The perimeter is 91 , so

11b +2a + 3b + a = 91

14b + 3a = 91 ← substitute a = 4b

14b + 3(4b) = 91

14b + 12b = 91

26b = 91 ( divide both sides by 26 )

b = 3.5

and a = 4b = 4 × 3.5 = 14

Answer:

see below

Step-by-step explanation:

You will need the hypotenuse   12 ^2 + 9^2 = h^2   h = 15

In a right triangle:

S O H   C A H  T O A

sin s  =   S A H  = Opposite / Hypotenuse =   12/15

cos r = C A H  = Adjacent / Hypotenuse    = 12/ 15

Tan s = T O A =  12 / 9

cos (theta) = cos s  = 9 / 15

Tan r = 9/12

arc cos(theta) = theta = arccos(9/15) = 53.13 degrees

Answer:

D is the answer.

Step-by-step explanation:

On the X axis, the point lies at -1.75.
And on the Y axis the point is at 0.75.

Hope the explanation helps.

Answer:

d

Explanation:

The point (-1.75,0.75) is the location of 'point b'

Domain = the set of possible values along the x axis.

Domain = (-5 , 3 ]

Range = the set of possible values along the y axis.

Range = (-3 , 5 ]

Answer:

Option C

Step-by-step explanation: 3/4 x 8 will get 24 as the numerator and 32 as the denominator

The length of the measurements are;

EF = 7. 1 units

DE = 7. 0 units

Using the sine trigonometric identity, we have that;

sin θ = opposite/hypotenuse

Given that;

Opposite side = DE

Hypotenuse = DF

Substitute the values

sin 45 = DE/10

Find the value and substitute

DE = 0. 7071(10)

DE = 7. 0

Using the Pythagorean theorem;

EF² = 10² - 7²

find the square value

EF = √ 51

EF = 7.1

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Answer: Read the problem out loud to yourself.

Draw a Picture.

Think “What do I need to find?”

List what is given.

Find the key words.

Solve.

Check your work.

Step-by-step explanation: hope this helps :)

Answer:y=21°

x=8°

Step-by-step explanation:

3y+27=90

3y=63

y=21°

x+90°+8x+18°=180°

9x+108°=180°

9x=72°

x=8°

Answer:

the shape includes a curve

Answer:

\((x-5-\sqrt{19})(x-5+\sqrt{19})\)

Step-by-step explanation:

1) In general, given \(ax^2+bx+c\), the factored form is:

\(a(x-\frac{-b+\sqrt{b^2-4ac} }{2a} )(x-\frac{-b-\sqrt{b^2-4ac} }{2a})\)

2) In this case, \(a=1\), \(b= -10\) and \(c=6\).

\((x-\frac{10+\sqrt{(-10)^2-4\times6} }{2} )(x-\frac{10-\sqrt{(-10)^2-4\times6} }{2} )\)

3) Simplify.

\((x-\frac{10+2\sqrt{19} }{2} )(x-\frac{10-2\sqrt{19} }{2} )\)

4) Factor out the common term \(2\).

\((x-\frac{2(5+\sqrt{19)} }{2} )(x-\frac{10-2\sqrt{19} }{2} )\)

5) Cancel \(2\).

\((x-(5+\sqrt{19} ))(x-\frac{10-2\sqrt{19} }{2} )\)

6) Remove parentheses.

\((x-5-\sqrt{19} )(x-\frac{10-2\sqrt{19} }{2} )\)

7) Factor out the common term \(2\).

\((x-5-\sqrt{19} )(x-\frac{2(5-\sqrt{19}) }{2} )\)

8) Cancel \(2\).

\((x-5-\sqrt{19})(x-(5-\sqrt{19}))\)

9) Remove parentheses.

\((x-5-\sqrt{19})(x-5+\sqrt{19})\)

Thanks,
Eddie Echevarria

The values of p and ρˆ (p-hat) in the sample are

p = 0.48 and ρˆ (p-hat) = 0.44

From the question, we have the following parameters that can be used in our computation:

Proportion of male = 48%

Boys = 11

Girls = 14

The proportion of male represents the variable p

So, we have

p = Proportion of male = 48%

This gives

p = 48%

Express as decimal

p = 0.48

The variable ρˆ (p-hat) is then calculated as

ρˆ = x/n

In this case,

x = Boys = 11

n = Boys + Girls = 11 + 14 = 25

So, we have

ρˆ = 11/25

Evaluate

ρˆ = 0.44

Hence, the values are 0.48 and 0.44, respectively

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Answer: hi there is think that I can help you with your problem!

h = -16t^ 2 + 20t + 6     ....the ball will hit the ground when h  = 0

0 = -16t^2  + 20t   + 6      factor

0  = ( -8t  -  2 )  ( 2t  - 3)     set each  factor to 0

-8t  -  2  =  0                                 and                  2t  - 3   = 0

-8t   = 2                                                                 2t   =   3

t  = -2/8  = - 1/4  sec   [reject]                                t  = 3/2 sec  = 1.5 sec

Max ht  will be reached at [ -b / 2a ]    sec    =  -20 / [ 2(-16)]  =  20/32  =  5/8 sec

Step-by-step explanation:  

-16t^2+20t+6 = 0

will give you the times that the ball is on the ground. The negative root accounts for the fact that the ball is 6 feet above ground at t=0.

I get t=3/2 and t=-1/4

-2(2t -3) (4t +1) = 0

2t -3 = 0

2t-3 + 3 = 0 + 3

2t = 3

t = 3/2 second        

I hope that I helped you and have a nice day.

The derivative of \(y = 2^{(3x^5)}\) with respect to x is \(dy/dx = 2^{(3x^5)} * 15x^4 ln 2\). This gives us the rate of change of the function with respect to x.

To differentiate the function \(y = 2^{(3x^5)}\) with respect to x, we need to use the chain rule of differentiation.

First, we take the natural logarithm of both sides of the equation, which gives us:

\(ln y = ln 2^{(3x^5)}\)

Using the power rule of logarithms, we can simplify this to:

\(ln y = 3x^5 ln 2\)

Next, we differentiate both sides of the equation with respect to x, using the chain rule on the right-hand side:

\(1/y (dy/dx) = 15x^4 ln 2\)

Finally, we solve for dy/dx:

\(dy/dx = y * 15x^4 ln 2\)

Substituting \(y = 2^{(3x^5)}\), we get:

\(dy/dx = 2^{(3x^5)} * 15x^4 ln 2\)

Therefore, the derivative of \(y = 2^{(3x^5)}\) with respect to x is \(dy/dx = 2^{(3x^5)} * 15x^4 ln 2\).

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The rate of change between 1992 and 2006 is a decrease of 8.39%.

To find the annual rate of change between 1992 and 2006, we can use the formula:

r = \((V2/V1)^{1/n}\) - 1

where V1 is the initial value, V2 is the final value, and n is the number of years between the two values.

r = -0.0839

Therefore, the annual rate of change between 1992 and 2006 is -0.0839.

To express the rate of change in percentage form, we can multiply the result from part A by 100:

r = -0.0839 x 100

r = -8.39%

Therefore, the rate of change between 1992 and 2006 is a decrease of 8.39%.

To find the value of the car in the year 2009, we can assume that the value continues to drop at the same percentage rate as calculated in part A.

From 2006 to 2009, there are 3 years. So, using the formula for exponential decay, we have:

where V0 is the value in 2006, r is the rate of decrease, and n is the number of years between 2006 and 2009.

V = 11792.51

Therefore, the value of the car in the year 2009 would be approximately $11,800 (rounded to the nearest $50).

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The cost of each sandwich, given the number that was sold and the profit made was  $15.

Let S be the price of a sandwich and A be the price of a salad.

From the lunch sale, we know:

14 S + 14 A = $280

From the evening sale, we know:

42S + 154 A = $ 1400

Simplify the first equation by dividing through by 14:

S + A = $20

Solving this equation for S gives:

S = $20 - A

Substitute this equation into the second equation:

42 ( $20 - A ) + 154 A = $1400

$ 840 - 42 A + 154 A = $1400

112A = $560

A = $5

Substitute A = $5 into the first equation:

S + $5 = $20

S = $15

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Answer:

I exactly don't know the answer

Answer: b

Step-by-step explanation: a right triangle should have a right angle so you´d need atleast one right angle and two acute angles.

The number 4.4 is between \(4 \frac{1}{3}$\) and \(4 \frac{3}{5}$\) on the number line, so the answer is (D) 4.4.

To solve this problem, we need to convert the mixed numbers 4 1/3 and 4 3/5 to improper fractions and then find a number between them on the number line.

\(4 \frac{1}{3}$\) can be written as \(\frac{13}{3}$\) and \(4 \frac{3}{5}$\) can be written as \(\frac{23}{5}$\).

To find a number between \(\frac{13}{3}$\) and \(\frac{23}{5}$\), we need to find a common denominator. The least common multiple of 3 and 5 is 15, so we can rewrite the fractions with a denominator of 15:

\($\frac{13}{3} = \frac{65}{15}$\)

and

\($\frac{23}{5} = \frac{69}{15}$\)

Now we can see that the number \(\frac{67}{15}$\) is between \(\frac{65}{15}$\) and \(\frac{69}{15}$\), and we can convert it back to a mixed number:

\($\frac{67}{15} = 4 \frac{7}{15}$\)

Therefore, the number 4.4 is between \(4 \frac{1}{3}$\) and \(4 \frac{3}{5}$\) on the number line, so the answer is (D) 4.4.

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The mean of the test is 20.

To determine the mean of the test, we need to use the information provided about the scores falling above the mean in terms of standard deviations.

Let's denote the mean of the test as μ, and the standard deviation as σ.

We are given that a score of 29 falls three standard deviations above the mean, so we can write this as:

29 = μ + 3σ

Similarly, we are told that a score of 23 falls one standard deviation above the mean, which can be expressed as:

23 = μ + σ

Now we have a system of two equations with two variables (μ and σ). We can solve this system of equations to find the values of μ and σ.

From the second equation, we can isolate μ:

μ = 23 - σ

Substituting this value into the first equation, we have:

29 = (23 - σ) + 3σ

Simplifying the equation, we get:

29 = 23 + 2σ

2σ = 29 - 23

2σ = 6

σ = 3

Substituting the value of σ back into the second equation, we find:

μ = 23 - 3

μ = 20

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Answer:

yes it is

Step-by-step explanation:

hope this helps✨

This is how you do it.

Use the distance formula to find the distance from A to B, B to C, C to D and D to A. Then add up all 4 distances to find the perimeter.

Answer:

3=a(-3-(-2))^2+2

Step-by-step explanation:

Answer:

3=a(-3-(-2))^2+2

Step-by-step explanation:

Answer:

81/4

Step-by-step explanation:

From the given information; we are to use Lagrange multipliers to find the volume of the largest rectangular box

The coordinate planes and the vertex given in the plane is x + 9y + 4z = 27.

By applying Lagrange multipliers, we have;

\(fx = \lambda gx\)

where;

\(f: V = xyz\)

\(g : x + 9y + 4z = 27\)

From; \(fx = \lambda gx\)

\(yz = \lambda\)    --------- equation (1)

From; \(fy = \lambda gy\)

\(xz = 9 \lambda\)  --------- equation (2)

From; \(fz = \lambda gz\)

\(xy = 4 \lambda\) --------- equation (3)

Comparing and solving equation (1),(2) and (3);

\(\lambda x = 9 \lambda y = 4 \lambda z\)

divide through by \(\lambda\)

x = 9 y = 4z

3x = 27

x = 27/3

x = 9

From x = 9y

9 = 9 y

y = 9/9

y = 1

From

x = 4z

9 = 4 z

z = 9/4

Thus; the Volume of the largest rectangular box = 9 × 1  × 9/4

= 81/4

Answer:

L = 13

Step-by-step explanation:

perimeter is 2L + 2W = P

2L + 2(8) = 42

2L + 16 = 42

2L = 26(subtract 16 both sides)

L = 13(divide by 2)

Answer:

59,582π/375 (approximately 499.153) square centimeters

Step-by-step explanation:

Volume:

\( \frac{1}{3} \pi {(6.2)}^{2} (12.4)\)

\( \frac{1}{3} {( \frac{31}{5}) }^{2} ( \frac{62}{5} )\pi\)

\( \frac{59582\pi}{375} \)

Answer:

B

Explanation:

We want to identify the expression that have a quotient of 4/5;

Let us solve each of the expression to identify the correct one;

a. 5/2 ÷ 1/2

b.6/9 ÷ 5/6

c. 3/6 ÷ 2/5

d.7 1/2 ÷ 6

e.1 1/3 ÷ 1 2/3​

So, from the solution of each options, the only expression that gives 4/5 is B

b.6/9 ÷ 5/6

The given quadratic equation is:

We can solve the equation by equating it to zero and using the quadratic formula method method

The roots of the equation are:

p = 1.2385

q = 0.1615