Evaluation Employees of a firm receive annual reviews. In a certain department, 4 employees received excellent ratings, 15 received good ratings, and 1 received a marginal rating. If 3 employees in this department are randomly selected to complete a form for an internal study of the firm, find the probability that
(a) all 3 selected were rated excellent.
(b) one from each category was selected.

The answer is 1) Not statistical, 2) Not statistical, 3) Not statistical, 4) statistical, 5) statistical, 6) statistical.

Statistical questions are questions that require collecting data from a group (a sample) in order to draw inferences about a larger group (a population). It involves numerical answers or data which can be analyzed and then interpreted using statistical methods. For example "the average height of the students in this classroom?" or " percentage of people in this city who own a car?"

Non-statistical are questions which do not require any collection of data or use of statistical methods. These questions are usually categorical answers or that do not contain any numeric values. For example "What color is the sky?" or "What is your favorite food?"

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Full Question:

Classify the questions as statistical or not statistical.

Answer:

To calculate the length and width of a rectangle first, calculate the value of width 'w' by using the area of rectangle formula that is, 'w = A/l'.

Step-by-step explanation:

x+(-2) >3

open the bracket

x-2>3

collect the like terms by taking 2 to the other side

x>3+2

x>6

Answer:

13

Step-by-step explanation:

If a = 4 and m = –3, evaluate a – 3m.

= Solution,

= a - 3m

= 4 - 3 ( - 3 )

= 4 + 9

= 13

Answer:

13 is the answer :)

Step-by-step explanation:

If,

a = 4 and m = -3

Then a - 3m ,

4 - 3(-3)

4+9

= 13

Answer:

2x² + \(\frac{3}{2}\) x - 5

Step-by-step explanation:

(f + g)(x) = f(x) + g(x), thus

f(x) + g(x)

= \(\frac{x}{2}\) - 2 + 2x² + x - 3 ← collect like terms

= 2x² + \(\frac{3}{2}\) x - 5

Answer:

24$

Step-by-step explanation:

Answer:

4:11:7

Step-by-step explanation:

Find the GCF, or greatest common factor of the 3 numbers. In this case it is 12. To simplify, divide each number by 12

Answer:

4:11:7

Step-by-step explanation:

please mark me as brainlest

Answer:

below

Step-by-step explanation:

Area of rectangle ( 3 x 4 )  minus the area of the circle (pi * 1^2) =

= shaded area = 8.86 cm^2

Answer: 9 × 6 = 54

Step-by-step explanation:

In the Product Game, we need to multiply the both number of factor markers.

Chris and Katie were playing The Product Game. Their factor markers were on 9  and 2.

Number = 9 × 2 = 18

Chris decided to move the marker from 2 to 6.

Now, one maker is on 9 and other is on 6. So,

Number = 9 × (2 + 4)

Number = 9 × 6 = 54

Therefore, 9 × 6 = 54 is a numerical expression  to represent his move.​

Answer:

P = 16

Step-by-step explanation:

Answer: 4°F

Step-by-step explanation:

8-4=4

Answer:

this is your answer 30,260,340

The probabilities as follows:

A. P(F2|F1) = 0.3 (30%)

B. P(F1|F2) = 0.25 (25%)

C. P(F1 or F2) = 0.19 (19%)

D. P(not F1 and not F2) = 0.81 (81%)

To solve this problem, we can use the concept of conditional probability and the principle of inclusion-exclusion.

Given:

P(F1) = 0.10 (Probability of failing at Check Point 1)

P(F2) = 0.12 (Probability of failing at Check Point 2)

P(F1 and F2) = 0.03 (Probability of failing at both Check Point 1 and Check Point 2)

A. To find the probability that an item failed at Check Point 1 and also failed at Check Point 2 (F2|F1), we use the formula for conditional probability:

P(F2|F1) = P(F1 and F2) / P(F1)

Substituting the given values:

P(F2|F1) = 0.03 / 0.10

P(F2|F1) = 0.3

Therefore, the probability that an item failed at Check Point 1 and also failed at Check Point 2 is 0.3 or 30%.

B. To find the probability that an item failed at Check Point 2 given that it failed at Check Point 1 (F1|F2), we use the same formula:

P(F1|F2) = P(F1 and F2) / P(F2)

Substituting the given values:

P(F1|F2) = 0.03 / 0.12

P(F1|F2) = 0.25

Therefore, the probability that an item failed at Check Point 2 and also failed at Check Point 1 is 0.25 or 25%.

C. To find the probability that an item failed at either Check Point 1 or Check Point 2 (F1 or F2), we can use the principle of inclusion-exclusion:

P(F1 or F2) = P(F1) + P(F2) - P(F1 and F2)

Substituting the given values:

P(F1 or F2) =\(0.10 + 0.12 - 0.03\)

P(F1 or F2) = 0.19

Therefore, the probability that an item failed at either Check Point 1 or Check Point 2 is 0.19 or 19%.

D. To find the probability that an item failed at neither of the check points (not F1 and not F2), we can subtract the probability of failing from 1:

P(not F1 and not F2) = 1 - P(F1 or F2)

Substituting the previously calculated value:

P(not F1 and not F2) = 1 - 0.19

P(not F1 and not F2) = 0.81

Therefore, the probability that an item failed at neither Check Point 1 nor Check Point 2 is 0.81 or 81%.

In conclusion, we have calculated the probabilities as follows:

A. P(F2|F1) = 0.3 (30%)

B. P(F1|F2) = 0.25 (25%)

C. P(F1 or F2) = 0.19 (19%)

D. P(not F1 and not F2) = 0.81 (81%)

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Answer:

-2 < x<4

Step-by-step explanation:

We have open circles and -2 and 4 so we don't include those numbers

The line is in between so the x is in between

-2 < x<4

The range, in interval notation, is then $[80, 280].

What is the linear equation?

A linear equation is an equation that represents a straight line when graphed on a coordinate plane. A linear equation has the form y = mx + b, where m is the slope and b is the y-intercept.

The cost of renting tools is given by the linear equation $C = 50 + 30x$, where $x$ is the number of hours and $C$ is the cost in dollars.

The minimum cost is $50 + 30(1) = 80$, which occurs when $x = 1$.

The maximum cost is $50 + 30(10) = 280$, which occurs when $x = 10$.

The range, in interval notation, is then $[80, 280].

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The following is an assembly program that calculates the value of the given polynomial, assuming signed integers x and y are stored in register r2 and r3, respectively.

\(```.LIST.ALIGN 4    .GLOBAL _start_start:    PUSH {R4, R5, LR}\)
   \(MOV R4, R2        // R4 < - x    MOV R5, #2        // R5 < - 2\)\(MUL R4, R4, R4    // R4 < - x^2    MUL R4, R4, R5    // R4 < - 2x^2    MOV R5, #3        // R5 < - 3\)
  \(ADD R4, R4, R5, LSL #16    // R4 < - 2x^2 + 3x^2    MOV R5, #5        // R5 < - 5    MUL R5, R5, R2    // R5 < - 5x\)
  \(SUB R4, R4, R5, LSL #16    // R4 < - 2x^2 + 3x^2 - 5x    MOV R5, #11       // R5 < - 11    SUB R4, R4, R5, LSL #16    // R4 < - 2x^2 + 3x^2 - 5x - 11\)
  \(MOV R3, R4        // R3 < - y    POP {R4, R5, PC}.END```\)

Explanation: The polynomial is given as

\(`y = 2x^4 + 3x^2 - 5x - 11`.\)

To calculate this polynomial in assembly language, we need to perform the following steps:

Load the value of `x` into a register. We assume that `x` is stored in register `r2`.

Calculate \(`2x^2`\) and add \(`3x^2`\) to it. We first square the value of `x` by multiplying it with itself and then multiply it with `2`. We then add \(`3x^2`\) to this result. We store this result in register `r4`.

Calculate `5x` and subtract it from the result of step 2. We first multiply the value of `x` with `5` and then subtract it from the result of step 2. We store this result in register `r4`.

Subtract `11` from the result of step 3. We subtract `11` from the result of step 3 and store this result in register `r4`.

Load the value of `y` into a register. We assume that `y` is stored in register `r3`.

Return from the subroutine. We pop the registers from the stack and return from the subroutine.

The assembly program that is used to calculate the value of a given polynomial assuming signed integers x and y are stored in registers r2 and r3, respectively. The polynomial given is\(y = 2x4 + 3x² - 5x - 11\). In this assembly program, we load the value of x into a register, calculate 2x^2, add 3x^2 to it, subtract 5x from the result, and subtract 11 from the final result. The value of y is then stored in a register, and we return from the subroutine.

This assembly program is designed for 32-bit ARM architecture, and it can be run on any ARM processor. The program is written in ARM assembly language, which is a low-level programming language used to write programs that run on ARM processors. It is a complex language that requires a deep understanding of the processor architecture and instruction set.

In conclusion, the assembly program presented here can be used to calculate the value of a given polynomial using signed integers x and y stored in registers r2 and r3, respectively. This program can be adapted to calculate other polynomials or perform other arithmetic operations on ARM processors. It is a powerful tool for low-level programming and optimization, but it requires a significant amount of expertise to write and debug.

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Answer:

\(\frac{100}{a}\)

Step-by-step explanation:

Hello!

a% is the same as \(\frac a{100}\).

a% of a can be found by multiplying them both, giving us \(\frac {a^2}{100}\)

The value of the expression is \(\frac{100}{a}\)

Answer:

6 2/3

Step-by-step explanation:

10* 2/3

20/3

which is 6 2/3

Mia can create a scale drawing of a football field using a scale of 1:1,000. The scale drawing will provide a Visual representation of the field, allowing for easier analysis and planning.

To create a scale drawing of a football field using a scale of 1:1,000, Mia can follow these steps:

1. Determine the dimensions: The football field's dimensions are given as 120 yards by 53 1/3 yards. Convert the fractional measurement to a decimal for simplicity. In this case, 1/3 yard is approximately 0.333 yards.

2. Decide on the units: Since the scale is 1:1,000, Mia needs to determine the unit of measurement she will use in her scale drawing. For consistency, she can choose to use feet as the unit.

3. Calculate the scaled dimensions: To create the scale drawing, Mia needs to scale down the dimensions of the football field. Since the scale is 1:1,000, she can divide the actual dimensions by 1,000 to obtain the scaled dimensions. The scaled dimensions would be 120 yards / 1,000 = 0.12 yards (or 0.36 feet) for the length and 53.333 yards / 1,000 = 0.053333 yards (or 0.16 feet) for the width.

4. Draw the scaled football field: Using a ruler and a grid paper, Mia can draw a rectangle with dimensions of 0.12 feet by 0.053333 feet (or inches, depending on the size of the grid paper). She can label the sides of the rectangle with the corresponding measurements in feet.

5. Add additional markings: Mia can add other markings to the scale drawing, such as the goal posts, yard markers, and any other important features of the football field. She can refer to the actual measurements and proportions of these elements to ensure accuracy.

By following these steps, Mia can create a scale drawing of a football field using a scale of 1:1,000. The scale drawing will provide a visual representation of the field, allowing for easier analysis and planning.

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Answer:

WZ = 30

Step-by-step explanation:

set up equation based on WZ = W'Z'

3/4[6x + 10] = 13x - 35

multiply each side of equation by 4 to eliminate fractions:

18x + 30 = 52x - 140

-34x = -170

x = 5

substitute 5 for 'x' in either expression:

13(5) - 35

65 - 35 = 30

Answer:

\( \frac{3}{4} (6x + 10) = 13x - 35 \\ \)

Just find the value x

The new tableau becomes:X1X2X3S1S2S3Z101/3 0 −2/3 1/3 0 −1/3 22/3 0 2/3 8/3 0 1/3 80 1 4/3 1 0 −1/3 70X1 = 10, X2 = 0, X3 = 14/3, S1 = 0, S2 = 0, S3 = 0, and Z = 70.


Juan tells himself that it is his own fault that he did not study more for his test.Using the given initial tableau, we need to circle the pivot and write the new tableau on a separate sheet of paper.
Continue to circle each pivot and write each tableau until the indicators are all non-negative. The given initial tableau is:X1X2X3S1S2S3Z420100220122501002802210045−3−2−400001From the given initial tableau, we need to find the pivot element for which we can perform the row operations. We choose the element 2 in row 1 and column 2 as the pivot and perform row operations to make all the indicators non-negative.
The new tableau becomes:X1X2X3S1S2S3Z23/2−1/2 0 1 0 −1/2 0 11/2 3/2 0 5/2 0 1/2 0 14−1/2 0 0 0 1/2 1 9/2We choose the element 1 in row 1 and column 1 as the pivot and perform row operations to make all the indicators non-negative.

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Answer:

\( \bf \longrightarrow \: 2 {x}^{3} + 4 {x}^{2} + x\)

Taking x common

\( \sf \longrightarrow \: x \bigg(2 {x}^{2} + 4x + 1 \bigg)\)

Therefore,

Answer:

A. x (2x*2 + 4x + 1)

Step-by-step explanation:

Answer:

They have completed 50% of the race

Step-by-step explanation:

13 is half of 26. So when putting it in fraction form 13/26 can be equal to 50/100/

Now we can see that our fraction is 50/100, which means that 13/26 as a percentage is 50%.

Answer:

Step-by-step explanation:

Answer:

A is the steepest Because

A = 1.66666666667

B=-1.5

C= is just 0

Step-by-step explanation:

Step-by-step explanation:

1) 5a+4b-3a-7b+4a

Add terms having 'a' and 'b' separately

=6a-3b

Now subtitute values of a and b :

=6(-3)-3(4)

=-18-12

=-30

2)c(6-b)-c²

=6c-bc-c²

Subtitute values of b and c:

= 6(-2)-(5)(-2)-(-2)²

=-12+10-4

=-6

3)5x²-2xy+3y

Subtitute values of x and y:

=5(-5)²-2(-5)(-2)+3(-2)

=5(25)-20-6

=125-20-6

=99

4)-k²-(7k-4m)

Subtitute values of m and k:

=-(-2)²-{7(-2)-4(4)}

=-4-(-14-16)

=-4-(-30)

=-4+30

=26

5)3(6x+5y)-2y

Subtitute values of x and y:

=3{6(3)+5(-3)}-2(-2)

=3(18-15)+4

=3(3)+4

=9+4

=13

6)5(3m-n)-4(2m-n)

Subtitue values of m and n:

=5{5(-8)-(-11)}-4{2(-8)-(-11)}

=5(-40+11)-4(-16+11)

=5(-29)-4(-5)

=-145+20

=-125

Note:If you have any question about it you can friendly ask.Thanks

There are 3 balanced strings in set T.

To count the number of balanced strings in the set T={0, 1, 2}, we can establish a bijection between the set of balanced strings and T itself. A balanced string is defined as a string in which the sum of its digits is a multiple of 3.

We can define a function f: T" -> T that maps each string in T" to T by preserving the balanced property. If a string in T" is already balanced, f returns the string itself. If the string is not balanced, f replaces the last digit with digit that makes the sum a multiple of 3.

By showing that this function is both injective (one-to-one) and surjective (onto), we establish a bijection. The bijection rule states that if two sets have a bijection between them, they have the same cardinality. Therefore, the number of balanced strings is equal to the number of elements in T, which is 3.

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The monthly payment on a 30-year, $205,000 loan with a 5.0% interest rate would be $1,073.51, with $926.23 of that being interest.

To calculate the monthly payment on a 30-year, $205,000 loan with a 5.0% interest rate, you first need to calculate the monthly interest rate. This can be done by dividing the annual interest rate (5.0%) by 12: 5.0% / 12 = 0.416%.

Next, you need to calculate the monthly payment by using this formula: Monthly Payment = \(Loan Amount x [Interest Rate / (1 – (1 + Interest Rate)^-N)]\)

In this example, the loan amount is $205,000, the interest rate is 0.416%, and N is 360 (the number of payments over 30 years). Plugging this into the formula gives us:

\(Monthly Payment = $205,000 x [0.416% / (1 – (1 + 0.416%)^-360)]]\)]

This gives a monthly payment of $1,073.51. To calculate the interest portion of the payment, multiply the loan amount by the monthly interest rate (0.416%): $205,000 x 0.416% = $926.23. Thus, the interest portion of the monthly payment is $926.23.

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Answer:

x2 - 4 = 0

4x2 = 16

Step-by-step explanation: