During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ± 0.001) kg with a speed of (3.2 ± 0.01) ms-1. The second trolley is moving away with a distance of (2.5 ± 0.01) ms-1.

What is the absolute uncertainty of the ratio of momentum of the two trolleys X/Y?

Answer:

pretty sure its A

Explanation:

please give brainliest if i'm correct

Answer:

A.

Explanation:

I have done this and that was correct

hope this helps

The angle to the horizontal the ball was launched at can be determined using trigonometry. Once you have the initial horizontal and vertical velocities, you can use the tangent function to calculate the launch angle.

Velocity is a physical quantity that describes the rate at which an object changes its position. It is a vector quantity, which means it has both magnitude and direction. The magnitude of velocity is the speed of the object, while its direction is the direction of motion.

Time is a concept that refers to the sequence of events that occur in a continuous progression, from the past, through the present, and into the future. It is a way to measure the duration or the length of events or periods, and it is a fundamental aspect of our experience and understanding of the world.

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Answer:

so true though

Explanation:

The image is formed 8cm in front of the lens and is a real image.

We would have to remind ourselves that if we are looking at the lens then we have to be looking at any reflecting surface that we know. There are two kinds of lens that we have, we have the concave and the convex lens.

We know that the focal length of the convex lens is positive thus we have;

1/f = 1/u + 1/v

f = focal length

u = object distance

v = image distance

Thus;

1/8 = 1/4 - 1/v

1/v = 1/4 - 1/8

v = (0.25 - 0.125)^-1

v = 8 cm

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a.i) The work done when the body is displaced from s=0 to s = 0.4 m is 0.8 J.

(a.ii) The work done when the body is displaced from s=0 to s = 0.8 m is 1.2 J.

(b.i) The final velocity of the body when the displacement is 0.4 m is 3.46 m/s.

(b.ii) The final velocity of the body when the displacement is 0.8 m is 4 m/s.

The work done on an object is the product of force and displacement of the object.

The work done between 0 to 0.4 m is determined from the area of the triangle formed.

W = ¹/₂(0.4 m - 0 m) x ( 4 N )

W = ¹/₂(0.4 m) x ( 4 N )

W = 0.8 J

The work done from s=0 to s =0.8 m,

W = ( Area of 0 to 0.4 m) + ( Area of 0.4 m to 0.8 m)

W =  0.8 J  +   ¹/₂(0.8 m - 0.4 m) x ( 2 N )

W = 0.8J  +  ¹/₂(0.4 m) x ( 2 N )

W = 0.8J + 0.4 J

W = 1.2 J

The final velocity of the body is calculated by applying work energy principle.

change in kinetic energy of the body = work done by the body

¹/₂m(v₂² - v₁²) = W

Where;

when, s = 0.4 m, the final velocity is calculated as;

¹/₂m(v₂² - v₁²) = 0.8 J

¹/₂(0.2)(v₂² - 2²) = 0.8

0.1(v₂² - 2²) = 0.8

v₂² - 2² =  0.8 / 0.1

v₂² - 2² = 8

v₂² = 8 + 4

v₂² = 12

v₂ = √12

v₂ = 3.46 m/s

when s = 0.8 m, the final velocity is calculated as;

¹/₂(0.2)(v₂² - 2²) = 1.2 J

0.1(v₂² - 2²) = 1.2

v₂² - 2² =  1.2 / 0.1

v₂² - 2² = 12

v₂² = 12 + 4

v₂² = 16

v₂ = √16

v₂ = 4 m/s

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Answer:

42.1%

Explanation:

Applying,

E(%) = (M.A/V.R)×100............. Equation 1

Where E(%) = Percentage efficiency, M.A = mechanical advantage, V.R = Velocity ratio.

But,

M.A = L/E............... Equation 2

Where L = Load, E = Effort.

From the question,

Given: L = 150 N, E = 200 N

Substitute these values into equation 2

M.A = 200/150

M.A = 1.33

Also,

V.R for Inclined plane = 1/sin∅ =

V.R = 1/sin∅............... Equation 2

Where ∅ = angle of the inclined plane.

Where,

tan∅ = 4/12

∅ = tan⁻¹(4/12)

∅ = 18.43°

Therefore,

V.R = 1/sin18.43

V.R = 3.16.

Substituting the value of M.A and V.R into equation 1

E(%) = (1.33/3.16)×100

E(%) = 42.1%

Answer:

g ±Δg = (9.8 ± 0.2) m / s²

Explanation:

For the calculation of the acceleration of gravity they indicate the equation of the simple pendulum to use

          T = \(2\pi \sqrt{ \frac{L}{g} }\)

          T² =  \(4\pi ^2 \frac{L}{g}\)4pi2 L / g

          g = \(4\pi ^2 \frac{L}{T^2}\)

They indicate the average time of 20 measurements 1,823 s, each with an oscillation

let's calculate the magnitude

           g = \(4\pi ^2 \frac{0.823}{1.823^2}\)4 pi2 0.823 / 1.823 2

            g = 9.7766 m / s²

now let's look for the uncertainty of gravity, as it was obtained from an equation we can use the following error propagation

for the period

             T = t / n

             ΔT = \(\frac{dT}{dt}\) Δt + \(\frac{dT}{dn}\) ΔDn

In general, the number of oscillations is small, so we can assume that there are no errors, in this case the number of oscillations of n = 1, consequently

              ΔT = Δt / n

              ΔT = Δt

now let's look for the uncertainty of g

             Δg = \(\frac{dg}{dL}\) ΔL + \(\frac{dg}{dT}\)  ΔT

             Δg = \(4\pi ^2 \frac{1}{T2}\)   ΔL + 4π²L  (-2  T⁻³) ΔT

a more manageable way is with the relative error

             \(\frac{\Delta g}{g} = \frac{\Delta L }{L} + \frac{1}{2} \frac{\Delta T}{T}\)

we substitute

              Δg = g ( \frac{\Delta L }{L} + \frac{1}{2}  \frac{\Delta T}{T}DL / L + ½ Dt / T)

the error in time give us the stanndard deviation  

let's calculate

               Δg = 9.7766 (\(\frac{0.001}{0.823} + \frac{1}{2} \ \frac{0.671}{1.823}\))

               Δg = 9.7766 (0.001215 + 0.0184)

               Δg = 0.19 m / s²

the absolute uncertainty must be true to a significant figure

                Δg = 0.2 m / s2

therefore the correct result is

               g ±Δg = (9.8 ± 0.2) m / s²

The approximate value of the magnitude of the displacement vector 2D - E is roughly  16.88.

In order to find out the magnitude of the displacement vector 2D - E, you can use these steps:

multiplying  D by 2. this would result to

12i + 6j - 2k

subtracting  E from 2D. this would result to

8i + 11j - 10k

The calculation of Step three entails computing the magnitude of 2D - E where   |V| = sqrt(Vi^2 + Vj^2 + Vk^2)

|2D - E| = sqrt((8^2) + (11^2) + (-10^2))

|2D - E| = sqrt(64 + 121 + 100)

|2D - E| = sqrt(285),

|2D - E| = 16.88 when rounded off to two decimal places.

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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The energy difference is directly proportional to the frequency of emitted light."

The correct option is A.

The relationship between the energy differences in energy levels in an atom and the light emitted by the atom is described by the Planck-Einstein equation, which relates the energy of a photon of light to its frequency:

E = hν,

where E is energy, h is Planck's constant, and ν is frequency.

When an electron in an atom drops from a higher energy level to a lower energy level, it emits a photon of light with a frequency proportional to the energy difference between the two levels. Therefore, the energy difference between the energy levels is directly proportional to the frequency of the emitted light.

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Answer:

A. Gamma decay

Explanation:

A form of nuclear decay in which the atomic number is unchanged is a gamma decay.

The atom has undergone a gamma decay.

In a gamma decay, no changes occur to the mass and atomic number of the substance.

The methods to determine the specific charge of an electron are The J. J. Thomson Method and The Millikan Oil Drop Method.

The J. J. Thomson Method

In this method, an electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen. When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force, which is given by the formula: $F= evB$ $F= evB$

When a magnetic field is applied at right angles to an electron beam, it bends the path of the beam into a circular path. The radius of the path of an electron beam in a magnetic field is determined by the relationship:r = mv/eB. As a result, the specific charge of an electron may be calculated from the expression: $e/m = 2V / B^2r^2$

The Millikan Oil Drop Method

This is another technique for determining the specific charge of an electron. The oil drop experiment was first done by Robert A. Millikan in 1909. He did this experiment by suspending charged droplets of oil in a uniform electric field between two parallel plates.

The fall of the oil droplets in the absence of an electric field was also noted. The fall velocity of the oil droplet was determined by measuring the time taken by the oil droplet to pass through a fixed distance between the plates in the absence of an electric field. By measuring the electric field strength, the voltage applied to the plates, and the fall velocity of the oil droplet, the specific charge of the electron was determined.

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The methods to determine the specific charge of an electron are :

In the J. J. Thomson Method, an  electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen.

When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force.

The Millikan Oil Drop Method is an experiment by which is created by suspending charged droplets of oil in a uniform electric field between two parallel plates.

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Explanation:

Thanx for the figure;
The force component of F   UP the ramp that  moves the crate must equal the force of the crate DOWN the ramp

75 kg = mg Newtons = 735.8 Newtons

    Downplane force is   735.8 sin 34°  = 411.4 Newtons

   Fn =The horizontal force will be found by   cos 34 = 411.4/ F                                                                       F = 411.4/cos (34) = 496 N

Normal Force =  735.8 cos 34°  = 610 N   This part is due to the mass of the crate....there is additional normal force from the force pushing the crate up the hill  (from below)

   = F sin34   =  496 sin 34 = 277.4 N

            SUM of normal forces = 610 + 277.4 = 887.4 N

Answer:

  a.  |F| ≈ 496 N

  b.  normal force ≈ 887 N

Explanation:

You want the magnitude of the horizontal force F that moves a crate up a 34° ramp at constant speed, and you want the magnitude of the normal force on the crate.

The constant speed of the crate tells you the net force up the ramp is zero. This is the sum of the component of force F in that direction and the force due to gravity in the opposite direction:

  F·cos(34°) - m·g·sin(34°) = 0

  F = mg·tan(34°) = (75 kg)(9.8 m/s²)tan(34°) ≈ 496 N

The magnitude of force F is about 496 N.

The normal force on the crate will be the sum of the component of F in that direction and the force due to gravity in the same direction:

  F·sin(34°) +m·g·cos(34°) ≈ 887 N

The magnitude of the normal force is about 887 N.

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

87

Explanation:

Answer:the answer is 3

Explanation:

Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

Answer:

Explanation:

1. Place a cup of hot tea on a flat surface.

2. Place a thermometer in the tea and record the temperature.

3. Place a fan in front of the cup of tea and turn it on.

4. Place the thermometer in the tea again and record the temperature.

5. Compare the two temperatures and observe the difference.

6. The difference in temperature is an indication of the thermal energy that has been dissipated from the cup of hot tea.

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Answer:

(a) The angular frequency ($\omega$) of a spring/mass system with a force constant ($k$) and a mass ($m$) can be found using the formula:

\omega = \sqrt{\frac{k}{m}}

Plugging in the values given, we get:

\omega = \sqrt{\frac{90 N/m}{8.15 kg}} \approx 3.18 \text{ rad/s}

Therefore, the angular frequency of the spring/mass system is approximately 3.18 rad/s.

(b) The period ($T$) of a spring/mass system can be found using the formula:

T = \frac{2\pi}{\omega}

Plugging in the value of $\omega$ we found in part (a), we get:

T = \frac{2\pi}{3.18\text{ rad/s}} \approx 1.98 \text{ s}

Therefore, the period of the spring/mass system is approximately 1.98 s.

Answer:

object would move but it could be difficult to slow down or stop.

The overall displacement of the object in a given direction over the course of a unit of time is its velocity.

A vector quantity is velocity. This implies that it has a predetermined course. The rate at which an object moves over time is referred to as its velocity.

This motion has zero velocity because the definition of velocity is the rate of displacement. A person must maximize his or her displacement from the starting position if they want to maximize their velocity.

Since velocity is a vector quantity, we must consider direction when evaluating it. The primary distinction between speed and velocity is that speed is a scalar quantity that depends on distance whereas velocity does not.

Therefore, The overall displacement of the object in a given direction over the course of a unit of time is its velocity.

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Answer:I think Fossils show that some animals are extinct

Explanation:

Please mark as brainliest for me.Thanks

Answer:

The answer is below

Explanation:

We are to check if the statement is true of false. If it is false, we correct the statement.

Solution:

Acceleration is the time rate of change of velocity. It is the ratio of the change in velocity to the change in time. The acceleration can be gotten from a velocity time graph by finding the slope of the graph.

The x coordinate represent the time and the y coordinate velocity.

5) Graph A passes through the point (0, 0) and (4, 24). Therefore the acceleration (slope) is:

Acceleration = \(\frac{24-0}{4-0}=6\ m/s^2\)

This is correct.

6) Graph B is a straight line of 12 m/s. It passes through (0, 12) and (4, 12). Hence:

Acceleration = \(\frac{12-12}{4-0}=0\ m/s^2\)

This is false.

Therefore the acceleration of graph B is 0 m/s².