From the following conjugate bases, \(NO^{-}_{2}\), \(PO_{4}^{3-}\), \(CH_{3}NH_{2}\), \(HSO^{-}_{4}\) are weak bases while \(CH^{-}_{3}\) is a strong base.
How to determine the strength of basicity of various conjugate bases?Conjugate bases are formed when an acid donates a proton (H+) in a chemical reaction. They are the species that result from the removal of a proton (H+) from an acid, which causes the acid to lose its acidic properties.
To determine whether each of the following conjugate bases is a strong base, a weak base, or a species with negligible basicity, we will analyze each of them:
1. \(HSO^{-}_{4}\) : \(HSO^{-}_{4}\) is a weak base. It is the conjugate base of \(H_{2}SO_{4}\), a strong acid, and its basicity is weaker compared to strong bases.
2. \(CH^{-}_{3}\): \(CH^{-}_{3}\) is a strong base. As a carbanion, it has a negative charge on the carbon atom, making it highly reactive and a strong base.
3. \(NO^{-}_{2}\) : \(NO^{-}_{2}\) is a weak base. It is the conjugate base of \(HNO_{2}\), a weak acid, and its basicity is weaker compared to strong bases.
4. \(PO_{4}^{3-}\): \(PO_{4}^{3-}\) is a weak base. It is the conjugate base of \(H_{3}PO_{4}\), a weak acid, and its basicity is weaker compared to strong bases.
5. \(CH_{3}NH_{2}\), : \(CH_{3}NH_{2}\) is a weak base. As a simple amine, it can accept a proton and act as a base, but its basicity is weaker compared to strong bases.
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compare and contrast a Covalent and an ionic bond
Which answer choice shows the location of a peptide bond in the peptide below?
mc014-1.jp
mc014-2.jp
mc014-3.jp
mc014-4.jp
mc014-5.jp
However, I can still explain the location of a peptide bond in a peptide in general terms. Peptide bonds are formed between the carboxyl group (-COOH) of one amino acid and the amino group (-NH2) of another amino acid. This bond formation occurs through a dehydration synthesis reaction, resulting in the elimination of a water molecule.
In a peptide chain, multiple amino acids are linked together through peptide bonds, forming a linear sequence. The location of a peptide bond can be identified by examining the specific amino acids involved in the bond. Generally, a peptide bond connects the carbonyl carbon (C=O) of one amino acid to the nitrogen (N-H) of the adjacent amino acid in the chain.
To pinpoint the exact location of a peptide bond within a specific peptide, a more detailed analysis of the peptide sequence or structural information is usually required.
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(GIVING BRAINLIEST)
Balance each of the following chemical equations below
Explanation:
A.
AgNO₃ + KCl → AgCl + KNO₃ (Already Balanced)
B.
H₂O + SO₃ → H₂SO₄ (Already balanced)
C.
2KI + Cl₂ → 2KCl + I₂
D.
2NaHCO₃ → Na₂CO₃ + H₂O + CO₂
E.
Zn + 2HCl → ZnCl₂ + H₂
F.
BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl
G.
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
H.
2Al + 3CuCl₂ → 2AlCl₃ + 3Cu
What is an appropriate stepwise synthesis for n-propylbutanamide that uses only 1-propanol and/or carbon dioxide as the only source(s) of carbon and any other reagents necessary
One possible stepwise synthesis of n-propylbutanamide using only 1-propanol and carbon dioxide as the sources of carbon is as follows:
Conversion of 1-propanol to propionic acid:1-propanol + O2 (oxidation) -> propionic acid.Conversion of propionic acid to propionyl chloride:Propionic acid + SOCl2 (thionyl chloride) -> propionyl chloride.Conversion of propionyl chloride to n-propyl butanamide:Propionyl chloride + NH2OH (ammonium hydroxide) -> n-propylbutanamide.Alternatively, the propionyl chloride can be prepared from propionic acid and carbon dioxide in a two-step process:
Conversion of propionic acid to a propionyl carbonate:Propionic acid + CO2 + (NH4)2CO3 (ammonium carbonate) -> propionyl carbonate.Conversion of propionyl carbonate to propionyl chloride:Propionyl carbonate + SOCl2 (thionyl chloride) -> propionyl chloride.Then, the propionyl chloride can be converted to n-propylbutanamide as described above.
Note: This is just one possible synthesis of n-propylbutanamide using 1-propanol and carbon dioxide as the only sources of carbon. There may be other synthesis routes that could also be used.
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List six properties of salts.
Heree some the properties of salts:
Soluble in water.In the molten state, salts can conduct the electricity.Hygroscopic.Salts can have different colors.Salts typically have a crystalline structure.Salts are generally denser than water.ExplanationSalts are typically soluble in polar solvents like water. This property is due to the ability of salts to form ionic bonds with water molecules through a process called hydration. Their solubility generally increases with temperature.In the molten (liquid) state, salts can conduct electricity because the ions are free to move and carry electric charge. Example:Learn more about salt on:
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chemical case?
Type of point mutation?
AAC-->ATC
Type of point mutation?
GTA-->TA
Chemical cause?
Type of point mutation?
CGG-->CTG
chemical cause?
Type of point mutation?
GTA → GTG, AAC → ATC, GTA → TA, and CGG → CTG are different types of point mutations that can occur in the genetic code. A point mutation is a type of genetic mutation that alters only one nucleotide base pair of a DNA molecule. It is also called a single nucleotide polymorphism (SNP).
The types of point mutations are substitution, deletion, and insertion.
GTA → GTG chemical case : This is a substitution mutation, which is a type of point mutation. The nucleotide guanine is replaced by thymine, resulting in a change from a purine to a pyrimidine. This kind of mutation is known as a transversion.
AAC → ATC chemical cause : This is a substitution mutation, which is a type of point mutation. The nucleotide adenine is replaced by thymine, resulting in a change from a purine to a pyrimidine. This kind of mutation is known as a transversion.
GTA → TA chemical cause : This is a substitution mutation, which is a type of point mutation. The nucleotide guanine is replaced by adenine, resulting in a purine-to-purine transition mutation.
CGG → CTG chemical cause : This is a substitution mutation, which is a type of point mutation. The nucleotide cytosine is replaced by thymine, resulting in a change from a pyrimidine to a purine. This kind of mutation is known as a transition mutation.
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Which is a chemical property that was used to separate your mixture
during the lab?
Solubility
Evaporation
Filtering
None of the above. Mixtures are separated through physical means.
None of the above.
Since none of the given option is a chemical property, rather all of them are physical method of separation and physical methods do not require a chemical change.
Solubility- It is a physical property because it is easily discernible through observation and does not alter the substance's chemical makeup. For instance, salt is still salt when it dissolves in water.
Evaporation - The chemical composition of a liquid does not change when it evaporates. The only alteration is a phase shift brought on by pressure and temperature. Evaporation, or the phase transition from liquid to gas, is a physical change as a result.
Filtration - Filtration is a physical separation procedure that uses a filter medium with a complicated structure that only allows fluid to pass through it to separate solid particles and liquid from a combination.
Therefore, neither new nor broken chemical bonds are created or broken during the separation. During the separation, bonds are severed or strengthened.
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I'm just looking for someone to check my answers on this and correct me if I'm wrong :)This is the question:You have three elements, A, B, and C, with the following electronegativity values:A = 0.9B = 3.0C = 3.5You react the elements to form the substances AB, AC, and BC. Answer the following questions:What type of substance is AB? What types of bonds are present? Explain your answer.What type of substance is AC? What types of bonds are present? Explain your answer.What type of substance is BC? What types of bonds are present? Explain your answer.If any of the substances are ionic compounds, which element is the cation and which is the anion? Explain your answer.And these are my answers:AB is a compound. It'd be an ionic compound because the electronegativity is different in each.AC is a compound. It'd be an ionic compound because the electronegativity is different in each.BC is a compound, but the bond between them is covalent.AB is an ionic compound. A is the cation and B is the anion because the element with lower electronegativity is the cation and the element with the higher electronegativity is the anion.
Answer:
Explanations:
Given the following electronegativity of three elements as:
Roy Kerr concluded that the grid of space is affected by the speed of rotation of a black hole, not its mass. True or False?
Answer:
False
Explanation:
Brainliest??
calculate dh8 for each of the following reactions, which occur in the atmosphere. a. c2h4 1g2 1 o3 1g2 hch3cho1g2 1 o2 1g2 b. o3 1g2 1 no1g2 hno2 1g2 1 o2 1g2 c. so3 1g2 1 h2o1l2 hh2so4 1aq2 d. 2no1g2 1 o2 1g2 h2no2 1g2
To calculate dh8 for each of the given reactions, we need to use Hess's Law, which states that the enthalpy change of a reaction is independent of the pathway taken to reach the products.
a. To find dh8 for this reaction, we need to look up the enthalpies of formation of the reactants and products. Then, we can use the formula dh8 = sum of products - sum of reactants.
dh8 = (dhf HCHO + dhf O2) - (dhf C2H4 + dhf O3)
b. Similarly, we can use the formula dh8 = sum of products - sum of reactants to find dh8 for this reaction.
dh8 = (dhf HNO2 + dhf O2) - (dhf O3 + dhf NO)
c. To calculate dh8 for this reaction, we need to first write out the balanced chemical equation and then use the formula dh8 = sum of products - sum of reactants.
dh8 = (dhf H2SO4) - (dhf SO3 + dhf H2O)
d. Finally, we can use the formula dh8 = sum of products - sum of reactants to find dh8 for this reaction.
dh8 = (dhf HNO2) - (2 x dhf NO + dhf O2)
Note that we need to use the enthalpies of formation for each compound, which can be found in a reference table.
To calculate ΔH° for each of the following reactions occurring in the atmosphere:
a. C2H4(g) + O3(g) → CH3CHO(g) + O2(g)
b. O3(g) + NO(g) → NO2(g) + O2(g)
c. SO3(g) + H2O(l) → H2SO4(aq)
d. 2NO(g) + O2(g) → 2NO2(g)
Follow these steps:
1. Determine the standard enthalpies of formation (ΔH°f) for each substance in the reaction. You can find these values in a thermodynamic data table or online.
2. Multiply the ΔH°f of each product by its stoichiometric coefficient and sum the values.
3. Multiply the ΔH°f of each reactant by its stoichiometric coefficient and sum the values.
4. Subtract the sum of reactants' ΔH°f from the sum of products' ΔH°f: ΔH° = Σ(ΔH°f products) - Σ(ΔH°f reactants).
By performing these calculations for each reaction, you will obtain the ΔH° for each reaction occurring in the atmosphere.
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pls help me with this cross word
Answer: Theft starts at c4 down
impression starts L14 left
investigator starts at m3
criminalistics starts at o1
pathologists starts at m14
toxicology b11
fingerprints c2
court n13
witness n8
microscope j13
edmond locard m1
expertise m4
murder j13
cant find other ones rn
Explanation:
A bond in which valence electrons are shared is called covalent. is the process of breaking large molecules into smaller ones by adding water. If energy is released when a molecule is broken apart, it is a(n) reaction. The process of building up large molecules from small components is a(n) process. A lipid with four sites lacking hydrogen saturation is a lipid.
Answer:
A bond in which valence electrons are shared is called COVALENT.
HYDROLYSIS is the process of breaking large molecules into smaller ones by adding water.
If energy is released when a molecule is broken apart, it is an EXERGONIC REACTION.
The process of building up large molecules from small components is an ANABOLIC process.
A lipid with four sites lacking hydrogen saturation is a POLYUNSATURATED lipid.
if u know that answer i will mark has brainliest
Answer:
The clear liquid is less dense than the black liquid, which is why it floats on top. If the volume were different, you would visually see more clear liquid than black and vice versa.
The clear liquid is less dense than the black liquid
Answer:
A. The clear liquid is less dense than the black liquid
Explanation:
Since the clear liquid since on top of the black one it's density is less. Whatever liquid has a higher density will sink to the bottom of the flask.
What function does a cell wall serve for a plant?
It provides the plant cell with structure and support, along with protection from bursting due to turgor pressure
Explanation:
9. Why do bees pollinate flowers?
A. They want to get to food in the flower.
B. They want to make seeds.
C. They want to help the flowers reproduce.
D. They want protection.
Explanation: B.
Bees pollinate in order to sweeten their seed
Answer:
A
Explanation:
Bees make excellent pollinators because most of their lives is spent collecting pollen which acts as a protein to feed their offspring
Gallium is a metal which forms compounds with a wide variety of uses. Some of the applications of gallium compounds include computer memory chips, light emitting diodes and lasers. Radioactive isotopes of gallium are used to image the human body and locate tumors. Naturally occurring gallium consists of two isotopes. One of those isotopes is 71ga with an isotopic mass of 70. 9247050 amu and an abundance of 39. 892%. What is the mass number of the other isotope?.
This problem is providing us with the isotopic mass of Ga-71 and its percent abundance, so the isotopic mass of the second isotope is required. At the end, the result turns out to be 68.92547 amu.
What is an isotope?In chemistry, isotopes are known as atoms of an element with different atomic masses (isotopic mass) but equal number of protons. In addition, they have a natural occurring abundance as a percentage.
Thus, this problem can be solved by writing the following weighted average for the atomic mass of Gallium:
\(m_{Ga}=m_{Ga-71}*\%ab_{Ga-71}+m_{Ga-?}*\%ab_{Ga-?}\)
Hence, since both percent abundances must sum 100 %, that of the second isotope will be 60.108 %. However, since its mass is unknown, one can use the average atomic mass of Gallium consigned in the periodic table in order to write the following, after plugging in what we have so far:
\(69.723=70. 9247050 amu *0.39892+m_{Ga-?}*0.60108\)
Hence, one can solve for the unknown as follows:
\(m_{Ga-?}=\frac{69.723amu-70. 9247050 amu *0.39892}{0.60108} \\\\m_{Ga-?}=68.92547amu\)
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what is the predominant intermolecular force in the liquid state of each of these compounds: ammonia ( nh3 ), carbon tetrabromide ( cbr4 ), and methyl chloride ( ch3cl )?
Part-A
In the liquid form of NH\(_{3}\), hydrogen bonding is the main force.
The main forces in the dispersion forces of CBr4
Dipole-dipole forces are the most common types of forces in CH\(_{3}\)CL.
Part B:
The compounds' boiling points are listed in decreasing order.
NaF > CH\(_{2}\)O > C\(_{2}\)H\(_{2}\) gas (less boiling point)
These are ionic chemicals :. (more boiling point)
A chemical compound is any material that consists of identical molecules having atoms from two or more different chemical elements.
Atoms from more than 100 different chemical elements, both in their pure forms and when mixed to form chemical compounds, make up all matter in the universe.
Only the atoms that are unique to that element are present in a pure element sample, and each element has its own unique atoms. For instance, the atoms that make up carbon differ from those that make up iron, which differ from those that make up gold. Every element has a distinctive symbol that is made up of one, two, or three letters that either come from the element's present name or from its original (typically Latin) name.
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Q) Part A:
What is the predominant intermolecular force in the liquid state of each of these compounds: ammonia (NH3 ), carbon tetrabromide (CBr4 ), and methyl chloride (CH3Cl )?? [options: dipole-dipole forces, hydrogen bonding, or dispersion forces]
Part B:
Rank the following compounds in order of decreasing boiling point: sodium fluoride (NaF ), acetylene (C2H2 ), and formaldehyde (CH2O )
A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place
over the next few minutes?
O Molecules in both the metal and the surrounding air will start moving at lower speeds.
O Molecules in both the metal and the surrounding air will start moving at higher speeds.
O The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up.
O The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Answer:
All of the above
Explanation:
If you wanted to mix pure methane with water and end up with 90 gallons of 60% methane, how many gallons of each should you use?
You should use ________ gallons of water and _________ gallons of methane
To determine the amount of water and methane needed, we can set up a system of equations based on the desired composition of the mixture. you should use 36 gallons of water and 54 gallons of methane to obtain a mixture of 90 gallons with a methane concentration of 60%.
Let's assume x represents the number of gallons of water and y represents the number of gallons of methane. We have the following information: The total volume of the mixture is 90 gallons: x + y = 90. The mixture should be 60% methane: (y / (x + y)) * 100 = 60. Simplifying the second equation: y / (x + y) = 0.6. Now we can solve the system of equations: From equation 1, we can express x in terms of y: x = 90 - y. Substituting this into equation 2: y / ((90 - y) + y) = 0.6. Simplifying further: y / 90 = 0.6. Solving for y: y = 0.6 * 90. y = 54. Now we can find x using equation 1: x = 90 - y. x = 90 - 54. x = 36. Therefore, you should use 36 gallons of water and 54 gallons of methane to obtain a mixture of 90 gallons with a methane concentration of 60%.
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Calculate the wavelength of the electromagnetic radiation whose frequency is 6. 94 x 10^12 Hz
The wavelength of the electromagnetic radiation whose frequency is
6.94 x 10¹² Hz is 4.32 x 10⁻⁵ meters.
The electromagnetic spectrum is a set of frequencies, wavelengths, and photon energies ranging from less than one hertz to more than ten thousand hertz, with wavelengths ranging from a few kilometres to a fraction of the size of an atomic nucleus. In general, electromagnetic waves tend to move at speeds similar to light in a vacuum. They do so, however, at a wide variety of wavelengths, frequencies, and photon intensities.
The electromagnetic spectrum is a range of all electromagnetic radiation that is further divided into multiple subranges known as parts. They are further subdivided into infrared radiation, visible light, and ultraviolet radiation.
Speed of light = c = 3x10⁸ m/s
Frequency = ν = 6. 94 x 10¹² Hz
so in electromagnetic wave,
c = λν
λ = c/ν
= 3 x 10⁸ / 6.94 x 10¹²
λ = 4.32 x 10⁻⁵ meters.
Therefore, wavelength is 4.32 x 10⁻⁵ meters.
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A swimming pool was sufficiently alkaline so that CO2 absorbed from the air produced in the pool a solution which was 2 x 10-4 M in CO32- M. If the pool water was originally 4 x 10-3 M in Mg2+, 6 x 10-4 M in Ca2+ and 8 x 10-7 M in Fe2+, then a precipitate should form of:
(a) only MgCO3
(b) only CaCO3
(c) only FeCO3
(d) only CaCO3 and FeCO3
(e) MgCO3, CaCO3 and FeCO3
(b)
only CaCO3
Explanation:
Given:
Alkaline solution= 2 x 10^-4 M in CO32-Pool water was originally 4 x 10^-3 M in Mg2+, 6 x 10^-4 M in Ca2+ and 8 x 10^-7 M in Fe2+
Precipitate should be of:
MgCO3, CaCO3 and FeCO3
We know that:
Mg2+ + CO32- → MgCO3Ca2+ + CO32- → CaCO3Fe2+ + CO32- → FeCO3Thus, for MgCO3 to form, [CO32-] should be 4 x 10^-3 M which is not possible in the given question.
For CaCO3 to form,[CO32-] should be 6 x 10^-4 M which is possible.
So, precipitate should be only CaCO3.
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Which of these scientist is know for his work in understanding climate change a : edwin hubble b : christian doppler c : warren washington d : charles kuen kao
Answer: just trust me its c
Explanation: i dont cap
Give short answer to the following questions. 18 ×5=40] An organic compound (A) is obtained by the treatment of calcium carbide with water and it is unsaturated hydrocarbon. a Convert compound (A) into butane. [2] b. What happens when compound (A) is passed through red hot copper tube at 400°C? [1] c. How can you prepare compound (A) from Kolbe's electrolysis? [2]
a) Compound (A) can be converted into butane through hydrogenation, undergoes decomposition at high temperatures through pyrolysis, b) and can be prepared from Kolbe's electrolysis by obtaining the alkene or alkyne as an intermediate product. c) The specific reaction conditions and mechanisms would depend on the particular structure and properties of compound (A).
a. To convert compound (A) into butane, we need to add two more carbon atoms to the unsaturated hydrocarbon.
This can be achieved through a process called hydrogenation, where compound (A) reacts with hydrogen gas (H2) in the presence of a suitable catalyst, such as palladium (Pd), to form butane. The reaction can be represented as follows:
Compound (A) + 2H2 -> Butane
b. When compound (A) is passed through a red-hot copper tube at 400°C, it undergoes a process called pyrolysis or thermal cracking. This process involves the breaking of chemical bonds within the compound due to the high temperature.
As a result, compound (A) decomposes into smaller fragments, including alkenes and alkynes, which are unsaturated hydrocarbons. The specific products obtained will depend on the structure of compound (A) and the conditions of the reaction.
c. Compound (A) can be prepared from Kolbe's electrolysis, which involves the electrolysis of a dilute solution of sodium or potassium salt of a carboxylic acid.
During the process, the carboxylic acid undergoes decarboxylation, where a carbon dioxide molecule is removed, resulting in the formation of an alkene or alkyne. These unsaturated hydrocarbons can be the starting material for the synthesis of compound (A) through subsequent reactions.
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What is the pressure of a gas of 0.0925 moles occupies 152 ml at 185 degrees celcius
In order to get the pressure of the gas, we will use the ideal gas equation expressed as:
\(PV=\text{nRT}\)• P is the ,pressure ,of the gas (in atm)
• V is the v,olume ,of the gas (in L)
• n is the ,number of moles, of gas (in moles)
• R is the ,gas constant
• T is the ,temperature, in kelvin
Given the following parameters:
\(\begin{gathered} n=0.0925\text{moles} \\ R=0.0821L\cdot atm/mole\cdot K \\ V=152mL=0.152L \\ T=185^0C=185+273=458K \end{gathered}\)Substitute the given parameters into the formula:
\(\begin{gathered} P=\frac{\text{nRT}}{V} \\ P=\frac{0.0925\cancel{\text{moles}}\times0.0821\frac{\cancel{L}\cdot atm}{\cancel{\text{mole}\cdot K}}\times458\cancel{K}}{0.152\cancel{L}} \\ P=\frac{0.0925\times0.0821atm\times458}{0.152} \\ P=\frac{3.4781665}{0.152}\text{atm} \\ P=22.88\text{atm} \end{gathered}\)Hence the pressure of the gas is 22.88atm
PLEASEEEE HELPP
If 359 mL of a gas were contracted to only 269 mL, what would be the initial temperature of it if it measured 422 K after the change?
I NEED IT FAST!!
Answer:
T₁ = 563.19 K
Explanation:
Given data:
Initial volume = 359 mL
Final volume = 269 mL
Final temperature = 422 K
Initial temperature = ?
Solution:
The given problem will be solve through the Charles Law.
Charles Law:
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₁ = V₁T₂ / V₂
T₁ = 359 mL × 422 K / 269 mL
T₁ = 151498 mL.K / 269 mL
T₁ = 563.19 K
Use the drop-down menus to complete the statements.
__________have a definite shape and volume.
__________do not have a definite volume or shape.
___________have a definite volume, but the shape may change.
Answer:
Solids, Gasses, Liquids
Explanation:
Solids are rigid structures that have a definite share and volume.
Gasses will continue to spread indefinitely until pressure prevents further spreading.
Liquids have a volume but take the shape of the container they are in.
secondary alcohols are oxidized to group of answer choices aldehydes. esters. ethers. carboxylic acids. ketones.
Secondary alcohols are oxidized to ketones. Option D
What are the secondary alcohols?
Due to the nature of the chemical processes involved in the oxidation process, secondary alcohols are converted to ketones.
The elimination of two hydrogen atoms during oxidation causes the alcohol functional group (-OH) to change into a carbonyl group (C=O). The carbon atom with the -OH group attached becomes a secondary carbon center when it is connected to two more carbon atoms in secondary alcohols.
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The salt pan in Death Valley is characterized by large polygonal (often six sided) cracks in evaporite deposits. These deposits:
The salt pan in Death Valley is characterized by large polygonal cracks in evaporite deposits.
These cracks form due to the contraction and expansion of the evaporite minerals, primarily salt, in response to temperature changes and water availability. The cracks often have a hexagonal shape, creating a unique and visually striking pattern on the surface of the salt pan.
Evaporite deposits are formed when water containing dissolved minerals evaporates, leaving behind solid mineral deposits. In Death Valley's salt pan, the main mineral responsible for these deposits is salt, specifically halite. As water evaporates from the salt pan, the concentration of salt increases, eventually reaching saturation. At this point, salt crystals start to precipitate out of the remaining brine, forming thick layers of evaporite deposits.
The contraction and expansion of these evaporite deposits occur as a result of temperature fluctuations. During hot and dry periods, the surface temperature of the salt pan rises, causing the salt to expand. Conversely, during cooler periods or when water is present, the salt contracts. This continuous cycle of expansion and contraction leads to the formation of the polygonal cracks, with six sides being a common occurrence.
Overall, the polygonal cracks in the evaporite deposits of Death Valley's salt pan are a fascinating geological feature resulting from the unique interplay between temperature changes and the presence of dissolved salt minerals in the area.
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what is the molarity of a solution that was prepared by dissolving 82.0 g of CaCl2 in enough water to make 812 mL of solution
The molarity of a solution that was prepared by dissolving 82.0 g of calcium chloride in enough water to make 812 mL of solution is 0.91M.
How to calculate molarity?Molarity is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution
The Molarity of a solution can be calculated using the following formula:
Molarity = no of moles ÷ volume
According to this question, a solution was prepared by dissolving 82.0 g of calcium chloride in enough water to make 812 mL of solution. The molarity can be calculated as follows:
no of moles of Calcium chloride = 82.0g ÷ 110.98 g/mol = 0.74 mol
Molarity = 0.74 ÷ 0.812 = 0.91M
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1. Consider NH3.If it dissolves in water(i) NH3 + H20 + NHẤ4+ H2O(ii)NH3 + H2O → NH+3 + OH-(iii) NH3 + H2O + NH+4+ OH-(iv) NH3 + H2O → NH+4+ OH-Which represents the dissolution of NH3 in water(a) i(b) ii (c) iii (d) iv (e) iii and iv2. HOA2+H20 . → H3O+ + OA-CIn this reaction:(i) OA c is the conjugate base of H2O(ii)OA-c is the conjugate base of HOAc (iii) H3O+ is theсconjugate base of HOA.(iv) H3O+ is the conjugate acid of H2O(a) i(b) ii (c) iii (d) iv (e) none3. Arrange the following according to increasing acid strength(i) Ka= 2.5 + 10-15(ii) Ka= 9.0 + 10-9(iii) pKa= 7.5(iv) % dissociation =100(a) iv, iii, ii, i2(b) ii, I, iii, iv(c) i, iii, iv, ii(d) i, ii, iii, iv(e) iii, iv, ii, i2
1. Ammonia is a colorless gas with a chemical formula of NH3, when it comes in contact with water, it will be transformed into Ammonium ion and it will produce one hydroxide ion, and this is why Ammonia will present a more basic (pH) behavior, the reaction that represents this behavior is:
NH3 + H2O -> NH4+ + OH-
Number 4 is the only one that represents it well
Number 3 has the same reaction but since there is a plus sign instead of an arrow, I consider it wrong.