Determine the molality of a solution prepared by dissolving 0. 500 moles of caf2 in 11. 5 moles h2o.

For the net charge to be +3,the mystery charge should be is -2 and net force is towards left.

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Answer:

Explanation:

True

Answer:

time for sulphur dioxide to diffuse is 221.05 secs

The time for sulphur dioxide to diffuse is 108 sec.

Sulfur dioxide has a molecular weight of sixty-four and as a result, the square root is 8. since its inversely proportional, on the way to diffuse two times as fast, the rectangular root of the molecular weight should be 4, and subsequently the molecular weight might be 16. So the solution is methane (CH4).

The charge of diffusion for a gas is inversely proportional to the rectangular root of its molecular mass (Graham's law). The gasoline with the lowest molecular weight will effuse the fastest. The lightest, and consequently fastest, fuel is helium.

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Answer:

moles SO42- = 0.0500 L x 0.20 M=0.010

moles Ba2+ = 0.0500 L x 0.10 M = 0.0050

Ba2+ + SO42- = BaSO4 (s)

moles SO42- in excess = 0.010 - 0.0050=0.0050

total volume = 100 mL = 0.100 L

[SO42-]= 0.0050/0.100= 0.050 M

[Na2SO4] = 2 /2 = 1 M

moles Na2SO4 = 2 M x 0.500 L = 0.500

mass Na2SO4 = 0.500 x 142 g/mol=71.0 g

moles MgBr2 = 46 /184 =0.25

moles Br- = 0.25 x 2 = 0.50

[Br-]= 0.50 / 0.50 L = 1 M

The activation of the serine/threonine protein kinase akt requires phosphoinositide 3-kinase (pi 3-kinase) to create phosphorylated lipids that serve as docking sites that localize Akt to the plasma membrane.

Ak strain changing is the meaning of the word Akt. The term "Akt" first appeared in 1928, when J. Furth conducted research on mice that spontaneously generated thymic lymphomas.

An essential enzyme in the signaling pathway that controls how cells react to insulin as well as other growth stimuli is called phosphoinositide 3-kinase (PI3K). To create phosphatidyl-inositol-3,4,5-trisphosphate (PIP3) at the plasma membrane, one such enzyme phosphorylates phosphatidylinositol-4,5-bisphosphate in the third carbon in the molecule.

Therefore, The activation of the serine/threonine protein kinase akt requires phosphoinositide 3-kinase (pi 3-kinase) to create phosphorylated lipids that serve as docking sites that localize Akt to the plasma membrane.

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Explanation:

You want 45 out of the 50's ....or  45 / 50ths of the 85 L

     45/50 * 85 = 76.5 L

sound waves travel faster in solids than in liquids, and faster in liquids than in gasses. While the density of a medium also affects the speed of sound, the elastic properties have a greater influence on the wave speed.

hope this helped

Answer:

the answer is D

Explanation:

but hope this helps

Answer:

Yo, wassup I think its D.

The volume of unreacted Oxygen = 1.25 L = 1.25 dm³ = 1250 cm³

Given

Combustion of propane

3.6 L CO2

7.25 L O2

Required

The volume of unreacted oxygen

Solution

Reaction

C₃H₈ + 5O₂ ⇒ 3CO₂ + 4H₂O

Avogadro's :  

In the same T,P and V, the gas contains the same number of molecules  

So the ratio of gas volume will be equal to the ratio of gas moles  

Vol O₂ = 5/3 x vol CO2 = 5/3 x 3.6 = 6 L

The unreacted : 7.25 - 6 = 1.25 L

When ethanedioic acid (HOOC-COOH) reacts with two 1,2-ethanediol molecules (HOCH₂CH₂OH), it forms a trimmer polymer.

Polymer is a material composed of long chain molecules, or macromolecules, which are made up of many repeating smaller units, known as monomers. Polymer molecules can be natural, such as cellulose, or synthetic, such as plastics and rubbers. Polymers are used to produce a wide range of materials with different characteristics and properties.

The HOOC group of the ethanedioic acid molecule reacts with the two hydroxyl groups of the two 1,2-ethanediol molecules to form the ester linkages. This produces a trimmer polymer, with three monomers connected via two ester linkages.

O

 |

HOOC-COO-O-CH₂CH₂-O-CH₂CH₂-OH

 |

 O

 H

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Answer: I think you're supposed to add the protons and neutrons and then that's your answer. Sorry if I'm wrong :/

Explanation:

Answer: there are 12 electrons 12 protons and 12 neutrons.

i hope this helps.

a. The equilibrium constant for the reaction at 25 °C from the reaction A(aq) ⥫⥬  enzyme B (aq) and the Δ° of the reaction is -5.540 kJ·mol⁻¹ is 2.98 × 10³.

b. The Δ for the reaction at body temperature (37.0 °C) if the concentration of A is 1.5 M and the concentration of B is 0.60 M is  -8.020 kJ·mol⁻¹.

To calculate the equilibrium constant (K'eq) for the reaction at 25°C, we have the relation:

Δ° = -RT ln K'eq

Where R is the universal gas constant, T is the temperature in Kelvin, and ln is the natural logarithm.

Therefore, K'eq = e-Δ°′/RT

Substituting the given values, we have:

K'eq = e-(-5540 J/mol)/(8.314 J/mol K × 298 K)

= 2.98 × 10³

The Δ for the reaction at body temperature (37.0 °C) is given by the relation:

Δ = Δ° + RT ln(Q)

where Q is the reaction quotient at the given concentration of reactants and products.

Q = [B] / [A] = 0.60 / 1.5 = 0.4

Substituting the given values, we have:

Δ = -5540 J/mol + (8.314 J/mol K × 310 K) ln (0.4)

= -8020 J/mol

Therefore, the Δ for the reaction at body temperature is -8.020 kJ·mol⁻¹.

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element is made up of only one type of atoms.

it is pure form of matter

example hydrogen, oxygen, carbon etc

Answer:

An element is a substance that is made up of only one kind of atom and cannot be broken down into simpler forms by any ordinary chemical means

The correct order of increasing size is in each set is:  Li⁺ < Na⁺ < K⁺, Br⁻ < Se²⁻ < Rb⁺, and  N³⁻ < O²⁻ < F⁻.

a. In order of increasing size, the ions in set a are: Li, Na, K. This is because they all have the same charge (+1), but as you move down the periodic table, the atomic radius increases.

b. In order of increasing size, the ions in set b are: Br-, Se2-, Rb. This is because Br- and Se2- have the same charge (-1), but as you move down the periodic table, the atomic radius increases. Rb has a larger atomic radius than Se, which gives it a larger ionic radius.

c. In order of increasing size, the ions in set c are: N3-, O2-, F-. This is because they all have the same charge (-1), but as you move across the periodic table, the atomic radius decreases. F- has the smallest atomic radius, which gives it the smallest ionic radius.

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Answer:

almost everything

Explanation:

Explanation:

37x - 1 + 23x + 1 = 180 ° { being co-interior angles }

60x = 180°

x = 180°/ 60

x = 3 °

Now

< T = 37x - 1° = 37 * 3° - 1 = 110°

Hope it will help :)

Answer:

When the gaseous phase of water reaches a metal lid it condenses to form water.

Explanation:

The gaseous phase of water is at a higher temperature than the temperature of a metal lid. Thus when it comes in contact with the cold lid it loses heat and gets converted to the liquid phase.

When water vapor loses temperature, it undergoes a process called condensation, which results in its conversion to a liquid state. This process is essentially the opposite of vaporization. Typically, condensation occurs when a vapor is compressed or cooled to its saturation limit, causing the molecular density within the gas phase to reach its maximum threshold.

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The number of moles of nitrogen gas in the cylinder is calculated by dividing the product of pressure, volume, and temperature by the ideal gas constant.

To determine the number of moles of nitrogen gas in the cylinder, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure in atmospheres

V = volume in liters

n = number of moles

R = ideal gas constant (0.0821 L·atm/(mol·K))

T = temperature in Kelvin

First, we need to convert the given pressure from inches of mercury (inHg) to atmospheres (atm). Using the conversion factor 1 inHg = 0.0334211 atm, we find:

P = 93.0 inHg * 0.0334211 atm/inHg = 3.10877 atm

Next, we need to convert the given temperature from Celsius to Kelvin. Adding 273.15 to the Celsius temperature, we have:

T = 15.00°C + 273.15 = 288.15 K

Now we can rearrange the ideal gas law equation to solve for the number of moles (n):

n = PV / RT

n = (3.10877 atm) * (9.400 L) / (0.0821 L·atm/(mol·K) * 288.15 K)

Calculating this expression will give us the number of moles of nitrogen gas in the cylinder.

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Answer:

SO4²

Explanation:

Formula and structure: The sulfate ion formula is SO42- and the molar mass is 96.06 g mol-1. This salt is formed by one sulfate center to which 4 atoms of oxygen are attached, 2 of these atoms are forming S=O.

Answer:

\(so _{4} ^{2 - } \)

Explanation:

sulfate is consisting of sulfur element with 4 oxygen as the structure in the pic given and this group is 2- charged

B2O3 (s)  + 6HF (l)  ---------> 2BF3 (g)  + 3 H2O (l) is the balanced equation.

A chemical equation is a graphical representation of the a chemical reaction using symbols but also chemical formulas. The reactant enterprises are on the left, and the product entities are on the right, with a plus sign between both the entities both the reactants and products, as well as an arrow pointing towards the products to indicate the reaction's direction.

Given reaction is  

                          B2O3 (s)  + HF (l)  ---------> BF3 (g)  +  H2O (l)

On left side 2 B atoms.  To equalize B atoms , put coefficient 2 for BF3.

                          B2O3 (s)  + HF (l)  ---------> 2BF3 (g)  +  H2O (l)

Now on right side 6 F atoms.  To equalize F atoms , put coefficient 6 for HF.

                          B2O3 (s)  + 6HF (l)  ---------> 2BF3 (g)  +  H2O (l)

Now on right side 6 H atoms.  To equalize H atoms , put coefficient 3 for H2O.

                           B2O3 (s)  + 6HF (l)  ---------> 2BF3 (g)  + 3 H2O (l)

Now all atoms are balanced.

Therefore, balanced equation is B2O3 (s)  + 6HF (l)  ---------> 2BF3 (g)  + 3 H2O (l)

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There are approximately 0.00495 moles of sodium hydroxide present in the 50.00 mL solution.

To find the moles of sodium hydroxide (NaOH) in a 50.00 mL solution with a concentration of 0.09899 M, you can use the formula:

moles = volume (L) × concentration (M)

First, convert the volume from mL to L:

50.00 mL = 0.05000 L

Now, multiply the volume in liters by the concentration:

moles = 0.05000 L × 0.09899 M

moles ≈ 0.00495 mol

Therefore, there are approximately 0.00495 moles of sodium hydroxide present in the 50.00 mL solution.

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Answer:

C. Glass

Explanation:

Amorphous solids have a non-crystalline structure and no order. In that case, Diamonds, Graphite, and Iron all have a crystalline structure and order. You are left with C as your answer.

Answer:

A link is a fastening unit that attaches two parts of an object together

Different types of links have different characteristics

Answer:

Linking is the process of combining all the component object files. The linker determines where the code will reside in memory and how control will transfer between the components.

Answer: 3.33

Explanation:

The molecular formula of the given composition is C₃H₆O₃.

Molecular formula is defined as a compound's chemical formula, which counts the total number of each element present in a molecule of the compound as discrete molecules. The arrangement of atoms in a molecule in three dimensions is known as molecular geometry, commonly referred to as the molecular structure.

The percentage composition is

C = 40.00 %

H = 6.72 %

O = 53.29 %

Mole = 100 g

Mass of C = 40 / 100 x 100 = 40 g

mass of H = 6.72 / 100 x 100 = 6.72 g

Mass of O = 53.29 / 100 x 100 = 53.29 g

Dividing the mass with moles

C = 40 / 12 = 3.3

H = 6.72 / 1 = 6.72

O = 53.29 / 16 = 3.3

Formula = C₃H₆O₃

Thus, the molecular formula of the given composition is C₃H₆O₃.  

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Answer:

the mass of a tree is primary carbon

Explanation:

the the carbon comes from carbon dioxide during photosynthesis

Answer:

Plants get all the carbon, hydrogen, and oxygen they need from carbon dioxide and water, which they use to build carbohydrates during photosynthesis. To build other kinds of molecules they also need elements like nitrogen, phosphorous, and sulfur. Plants get these as well as other elements from the soil.

Explanation:

Answer:

Aluminum + Nickel(Ii) Nitrate = Nickel + Aluminum Nitrate

Explanation:

In the allyl cation, all the bond lengths are equal and the positive charge is delocalized over all the three carbon atoms.

The allyl cation has the formula C2H5+. In the allyl cation, the positive charge is delocalized over the three carbon atoms as shown in the image attached. Hence, relevant resonance structures can be proposed for the allyl cation.

The bond lengths in the allyl cation are intermediate between the bond lengths of double bonds and single bonds. All the bond lengths are equal.

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