Determine the amount of torque
applied by a 1.0 m long pry bar with
250 N of force acting on it. Assume
that the angle is 90°.

Answer:

Meteoroids are objects in space that range in size from dust grains to small asteroids. Think of them as “space rocks." When meteoroids enter Earth's atmosphere (or that of another planet, like Mars) at high speed and burn up, the fireballs or “shooting stars” are called meteors.

Explanation:

thx to the internet

Answer:

C. The distance traveled by an object at a certain velocity.

Explanation:

YW!

Answer:

third option is the most accurate

A mirror receives a light beam at a 45 degree angle. The light beam takes the form of a straight line. As a result, choice (C) is accurate.

When a beam of light strikes a mirror at an angle, the reflected beam follows the law of reflection, which states that the angle of reflection is equal to the angle of incidence, and both angles are measured with respect to the normal (a line perpendicular to the surface of the mirror) at the point of incidence.

In this case, since the beam of light strikes the mirror at an angle of 45 degrees, the angle of reflection is also 45 degrees, as shown in the diagram below:-

       /|

     /  |

   /    |

 /      |

/________|  <--- Mirror surface

|       /

|     /

|   /

| /

As a result of the law of reflection, the reflected beam of light will form a symmetrical angle with the incident beam, as shown in the diagram below:-

     /|

   /  |

 /    |

/      |

|     /

|   /

| /

|/

This reflected beam will continue to travel in a straight line away from the mirror, and will not change shape. Therefore, the correct answer is option C: "A straight line".

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Answer:

momentum(M in Kgm/s)=mass(m in Kg) *velocity(v in m/s)

a) M=m*v. m=75kg,v=16 m/s

M =75*16

M=1200Kgm/s

b)M=135*16.2

M=2187Kgm/s

c)M = 0.8*6.5

M=5.2Kgm/s

Hope it is helpful?

The momentum of an object having mass

a) 75kg speed skater moving forward at 16m/s is 1200 kg.m/s

b) 135kg ostrich running north at 16.2m/s is 2187 kg.m/s

c) 0.8 kg kitten running to the left at 6.5 m/s is 5.2 kg.m/s

Momentum is defined as mass times velocity of body. it is denoted by p and its SI unit is Kg.m/s. It has both magnitude and direction. it is a vector quantity.

i.e. p = mv

a) Given,

mass m = 75Kg

velocity v = 16m/s

momentum p = 75× 16 = 1200 kg.m/s

b) Given,

mass m = 135Kg

velocity v = 16.2m/s

momentum p = 135×16.2 = 2187 kg.m/s

c) Given,

mass m = 0.8Kg

velocity v = 6.5m/s

momentum p = 0.8×6.5 =5.2 kg.m/s

Hence momentums of a), b) and c) are 1200 , 2187 and 5.2 kg.m/s respectively.

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Answer:

b

Explanation:

i know

Answer:

b one will not accelerate

Answer:

If two magnetic south poles or two magnetic north poles are brought near each other, the magnetic force is repulsive and the magnets will push against each other in opposite directions. If opposite poles are brought near, it is attractive. But the fundamental origin of the magnetic field is moving charge.

At  1.29 T/s rate must the magnitude of B change in order to induce a current of 0.392 A in the windings of the coil.

Using Faraday's Law, we can relate the induced EMF (voltage) to the rate of change of magnetic flux through the coil:

\(EMF = -N(dΦ/dt)\)

where N is the number of turns in the coil, and Φ is the magnetic flux through the coil. The negative sign indicates that the induced EMF opposes the change in flux.

We can also relate the EMF to the current and resistance:

EMF = IR

Combining these equations, we can solve for the rate of change of magnetic flux:

\((dΦ/dt) = -EMF/N = (-IR)/N\)

Plugging in the given values, we get:

\((dΦ/dt) = (-0.392 A x 12.7 Ω) / 147 = -0.0337 Wb/s\)

Since the magnetic field is perpendicular to the plane of the coil, the magnetic flux through the coil is given by: \(Φ = BAN\)

where A is the area of the coil (5 cm x 8 cm = 0.04 m^2). Solving for the rate of change of magnetic field:

\((dB/dt) = (dΦ/dt) / AN = (-0.0337 Wb/s) / (0.04 m^2 x 147) = -1.29 T/s\)

Therefore, the magnitude of the magnetic field must decrease at a rate of 1.29 T/s in order to induce a current of 0.392 A in the coil.

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Answer:

The most significant difference between the static and current electricity is that in static electricity the charges are at rest and they are accumulating on the surface of the insulator. Whereas in current electricity the electrons are moving inside the conductor.

Rainbows are not usually seen as complete circles because the ground is usually in the way and rainbows are actually arched shaped. Option a is correct answer.

The primary reason why rainbows are not usually seen as complete circles is that the ground obstructs the view. When we observe a rainbow, we see a portion of it above the horizon, forming an arc shape. The lower part of the rainbow, which would complete the circle, is hidden by the ground. Therefore, our perspective limits our ability to see the full circle of the rainbow.

Rainbows are created by the refraction, reflection, and dispersion of sunlight through water droplets in the atmosphere. The spherical shape of raindrops causes the light to be refracted and reflected at different angles, resulting in the formation of a circular arc of colors. However, due to the positioning of the observer on the ground, only a portion of the arc is visible, creating the familiar semi-circular shape of a rainbow.

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B. Vesicle does NOT describe a structural feature of a volcano.

A vent, fissure, and magma chamber are all structural features, while a vesicle refers to a small cavity in volcanic rock, formed by trapped gas bubbles during the solidification of lava. A vent is an opening in the Earth's surface that allows volcanic material to escape. A fissure is a large crack in the Earth's surface that allows lava to flow. A magma chamber is a large underground reservoir containing molten rock. A vesicle is an air pocket inside rocks formed by the expansion of gases during volcanic eruptions.

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The given amplifier circuit is a common-source amplifier. The equivalent circuit diagram of the amplifier includes a MOSFET N5486 transistor. We can determine the drain current (ID) and drain-source voltage (VDS) using the following equations:

1. Voltage at the source terminal (VS) is calculated using Ohm's law: VS = IS x RS.2. The drain current (ID) can be calculated using the equation ID = IS (1 + GVin), where Vin is the input voltage, G is the voltage gain, and IS is the current flowing through RD.Let's calculate the values of ID and VDS:

Given:- IS = VDD / RD = 10V / 10Ω = 1A- Vin = -1V / (1.5 x 10^6Ω + 0.47μF) = -0.6666667μA (using voltage divider rule)- G = -RD / RS = -10Ω / 3kΩ = -0.003333 Calculating ID:ID = 1A (1 - 0.003333 x 0.6666667 x 10^6)≈ 0.997A = 997mACalculating VDS:VDS = VDD - IDRD= 10V - 997mA x 10Ω≈ 10V - 9.97V≈ 0.03VTherefore, the values of ID and VDS are approximately ID = 997mA and VDS ≈ 0.03V, respectively.

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a) Peak voltage: Given, Voltage setting = 0.5 V/division Peak to peak voltage, Vpp = 8 cm = 4 divisions Peak voltage, Vp = Vpp / 2 = 4 cm = 2 divisions∴ Peak voltage = 2 × 0.5 = 1 VB) RMS voltage: Given, Voltage setting = 0.5 V/division Peak to peak voltage, Vpp = 8 cm = 4 divisions RMS voltage, Vrms= Vp/√2= 1/√2=0.707 V∴ RMS voltage = 0.707 Vc).

The frequency observed on the screen: The time period for 1 Hz = Time period (T) = 1/fThe distance traveled by the wave during the time period T will be equal to the horizontal length of one division. Therefore, the length of one division = 10 ms = 0.01 s Time period for one division, t = 0.01 s/ division. We know that the frequency, f = 1/T= 1/t * no. of divisions. Therefore, f = 1/0.01 x 1 = 100 Hz Thus, the frequency observed on the screen is 100 Hz.2) The frequency of a sine wave is measured using a CRO (by comparison method) by a spot wheel type of measurement.

If the signal source has a frequency of 50 Hz and the number of spots counted in 1 minute was 30, calculate the frequency of the unknown signal. The frequency of the unknown signal is 1500 Hz. How? Given, The frequency of the signal source = 50 Hz. The number of spots counted in 1 minute = 30The time for 1 spot (Ts) = 1 minute / 30 spots = 2 sec. Spot wheel frequency (fs) = 1/Ts = 0.5 Hz (since Ts = 2 sec)We know that f = ns / Np Where,f = frequency of the unknown signal Np = number of spots on the spot wheel ns = number of spots counted in the given time period Thus, frequency of the unknown signal, f = ns / Np * fs = 30/50*0.5=1500 Hz. Therefore, the frequency of the unknown signal is 1500 Hz.

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Answer:

Ff = 7.35*10^5 N

Explanation:

To find the maximum transverse pulling force you use the following formula, for the friction force:

\(F_f=\mu N=\mu Mg\) (1)

μ: friction coefficient = 0.15

N: normal force, which is equal to the weight over the wheel

M: mass of th train = 500 ton = 500 000 kg

g: gravitational acceleration = 9.8 m/s^2

You replace the values of the variables in the equation (1):

\(F_f=(0.15)(500000kg)(9.8m/s^2)=735000 N=7.35*10^5N\)

hence, the maximum transverse pulling force is 7.35*10^5 N

Answer:

Explanation:

The direction of the vector implies only its angle, not its magnitude. The direction of the vector is found in

\(tan^{-1}(\frac{y}{x})\) so

\(tan^{-1}(\frac{11.1}{-43.0})=-14.5\) but since we are in QII (where x is negative and y is positive) we have to add 180 to this number to get a direction of 165.5 degrees

Answer:

I hope it helped you...please mark as brainliest.....thanks!!!!!!!

Explanation:

Inches of mercury is ideal for vacuum lifting with vacuum cups, as the amount of vacuum required is rarely high. Typical vacuum handling utilizes anything between 15″Hg and 25″Hg. Therefore, “Hg is suitable as a measurement of system performance in this type of operation

The column of mercury employed in a mercury barometer, the height of which (inches of mercury) is used as a measure of atmospheric pressure.

At some point, all water vapour that is found in a vacuum system came from the atmosphere. Consider that air at 25° C and 50% relative humidity contains 12 torrs of water vapour. ... Additionally, any surface will adsorb a certain number of monolayers of water molecules.

Credits:

Vacuum Measurement: A Basic Guide - Fluid Power Journal

Sources of Water Vapor in Vacuum Systems | Normandale ...

Answer:

Explanation:

Given:

E = 4500 J

h = 2.45 m

____________

F - ?

W = F·h

F = W / h = 4 500 / 2.45 ≈ 1 840 N

Answer:

P = 33.6 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

\(F = 14*6\\F = 84 [N]\)

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

\(W = F*d\)

where:

W = work [J]

F = force = 84 [N]

d = displaciment = 40 [m]

\(W = 84*40\\W = 3360 [J]\)

Finally, the power can be calculated by the relationship between the work performed in a given time interval.

\(P=W/t\\\)

where:

P = power [W]

W = work = 3360 [J]

t = time = 100 [s]

Now replacing:

\(P=3360/100\\P=33.6[W]\)

The power is given in watts

The rock sitting on the cliff that is 25 m high has the gratest gravitational potential energy.

Potential energy is defined as the energy of an object by virtue of it's location. Mathematically, it is written as:

PE = mgh

Where

To determine the rock with the grater potential energy, we shall determine the potential energy of both rock assuming they have the same mass. Details below:

For rock sitting at 25 m high:

PE = mgh

PE = 10 × 9.8 × 25

PE = 2450 J

For rock sitting at 12 m high:

PE = mgh

PE = 10 × 9.8 × 12

PE = 1176 J

From the above calculation, we have:

Thus, we can conclude that the rock sitting at 25 m high, has the gratest potential energy.

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The Department of Energy regulations require solidification of high-level radioactive wastes within 10 years of their production.

Therefore the answer is c) 10 years.

High-level radioactive wastes are generated from the production of nuclear power and the reprocessing of spent nuclear fuel. These wastes contain a significant amount of radioactive material and pose a potential hazard to human health and the environment if not managed properly.

The Department of Energy (DOE) is responsible for managing high-level radioactive wastes generated by its facilities and has established regulations to ensure their safe handling and disposal. One of these regulations requires that high-level radioactive wastes be solidified within 10 years of their production.

Solidification involves mixing the liquid wastes with materials such as cement or glass to form a solid, stable form that can be safely stored or disposed of. By solidifying the wastes, the risk of accidental spills or leaks is reduced, and the wastes can be more easily transported and stored.

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This is a time dilation exercise. The time taken for the CD to last as measured by a clock on earth is given as: 67.08 minutes.

Under the theory of special relativity, time dilation is the "slowing down" of a clock as determined by an observer in relative motion with respect to that clock.

Recall that the equation for time dilation is given as:

t = t₀/√(1- (v²/c²)

Where:

t₀ is the observer in the space craft

t  is the observer on earth

v is the speed of the space craft which is given as 2 x 10⁸m/sec

c is the speed of light which is given as 3 x 10⁸m/sec

Hence

v/c = 2 x 10⁸/ 3 x 10⁸

= 2/3

Thus,

t = 5/√(1-(4/9)

= 50 √(9/5)

= 150/√5

= 150 /2.2361

= 67.08 min

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Answer: \(3920\ J\)

Explanation:

Given

mass of ball m=10 kg

It is placed at a height of 150 m

It is dropped from the height and allowed to free fall for 40 m

Velocity acquired by the ball during this fall is given by \(v^2-u^2=2as\)

Insert u=0, a=g

\(\Rightarrow v^2-0=2\times 9.8\times 40\\\Rightarrow v=\sqrt{784}\\\Rightarrow v=28\ m/s\)

Kinetic energy at this instant

\(K.E.=\dfrac{1}{2}\times 10\times 28^2\\\\\Rightarrow K.E.=3920\ J\)

Answer:

The answer is time-delay circuit breaker.

An intentional delay between the time when the fault or overload is sensed and the time when the circuit breaker (CB) operates is present in time delay circuit breakers.

What is a circuit breaker?

A circuit breaker is an electrical safety device that is designed to protect an electrical circuit from damage caused by overload, short circuit, or ground fault. A circuit breaker will trip or disconnect the circuit from the power supply when it detects a fault. After resolving the problem, the circuit can be reconnected. The circuit breaker is a critical element of the electrical system. It protects electrical equipment, facilities, and human lives from electrical incidents. It acts as a switch that can be turned off if an electrical fault or damage is detected.

What is a time-delay circuit breaker?

A time-delay circuit breaker is a circuit breaker with an intentional delay between the time when the fault or overload is sensed and the time when the CB operates. It provides time-delay protection against short circuits and overloads. It is used when a motor or other inductive loads are present. In the absence of a time-delay circuit breaker, the breaker may trip immediately due to the high inrush current when an inductive load is switched on. This high current is much greater than the normal full-load current. A time-delay circuit breaker will delay the trip so that the inrush current has time to diminish to normal full-load current levels.

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False. The voltage reaches its maximum value 1/4 of a period after the current reaches its maximum value is false.

Bogus. In an air conditioner circuit, the voltage and current are out of stage with one another because of the presence of receptive components like capacitors or inductors. How much time shift between the voltage and current waveforms relies upon the recurrence of the air conditioner signal and the upsides of the circuit components. While the voltage waveform might lead or slack the ongoing waveform, the time contrast between their greatest qualities isn't really 1/4 of a period. It relies upon the particular circuit and the stage point between the voltage and current waveforms. Subsequently, the explanation that the voltage arrives at its most extreme worth 1/4 of a period after the ongoing arrives at its greatest worth isn't by and large obvious.

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The given statement "scientists are concerned about the decrease in ozone is allowing more ultraviolet" is true because ozone is a molecule made up of three oxygen atoms that exist in the Earth's atmosphere. It's a form of oxygen that absorbs almost all of the Sun's harmful ultraviolet light.

Ultraviolet rays are very harmful to humans, causing skin cancer, immune system breakdowns, and cataracts in the eyes. When the ozone layer is damaged or thinned, it can allow more ultraviolet rays to penetrate the atmosphere, which is why scientists are so concerned about ozone depletion.What are the impacts of ozone depletion?It is estimated that a 1% reduction in the ozone layer increases the incidence of non-melanoma skin cancer by 2%.A decrease of 10% in the ozone layer may result in a 20% increase in the incidence of skin cancer.The thinning of the ozone layer may result in a decrease in plant production, which may result in food supply shortages.A decrease in ozone may have an impact on phytoplankton, which play a crucial role in ocean food webs. These tiny creatures consume carbon dioxide and produce half of the world's oxygen. As phytoplankton numbers decline, ocean ecosystems may change, affecting everything from fish populations to weather patterns.

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The bat should fly about 0.8065 m/s in order to hear a beat frequency of 8 Hz.

The shift in a wave's frequency caused by an observer moving away from the wave source is known as the Doppler effect or Doppler shift. The equation for this is given by,

\(f=\frac{v \pm v_0}{v\mp v_s}f_s\)

where f is the observed frequency, v is the speed or velocity of the sound waves, v₀ is observer velocity ("+" if it's towards and "-" if it's away from the source), vs is source velocity("-" if it's towards and "+" if it's away from the observer), and fs is the actual frequency of the sound waves.

The velocity of sound waves in the air is 344 m/s, v₀ is zero for the incident, v is the source velocity towards the wall, and fs is 1700 Hz.

Then, the incident frequency is given by,

\(f_{incidence}=\frac{344-0}{344-v}\times f_s\)

The wall is stationary, therefore, f(incidence)=f(reflected). Then, the new frequency the bat hears is,

\(\begin{aligned}f_{new}&=\frac{344+v}{344}\times f_{reflected}\\&=\frac{344+v}{344}\times \frac{344-0}{344-v}\times f_s\\&=\frac{344+v}{344-v} \times f_s\end{aligned}\)

To hear a beat frequency of 8 Hz, the velocity of the bat should be,

\(\begin{aligned}f_{new}-f_s&=8\\\left(\frac{344+v}{344-v} \right)f_s-f_s&=8\\\frac{344+v}{344-v}-1&=\frac{8}{f_s}\\\frac{344+v-344+v}{344-v}&=\frac{8}{1700}\\2v&=0.0047(344-v)\\2v&=1.6168-0.0047v\\2.0047v&=1.6168\\v&=\mathrm{0.8065\;m/s}\end{aligned}\)

The answer is 0.8065 m/s.

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