Write the equation of a line perpendicular to and = 2 x – 5 that passes through the point (2,-5).

Answers

Answer 1

Answer:  y = -x/2 -4

Step-by-step explanation:

I hope you mean perpendicular to y= 2x - 5 and that passes through (2, -5)

Take the reciprocal of the original slope.  Reverse the slope to negative. Substitute the values of the given coordinates for x and y in the base equation y =-x/2 and solve for "b" the new y-intercept.

-5 = - (2)/2 +b

-5 = -1 +b

-5+1 = b

-4 = b


Related Questions

The rectangle below has the dimensions:
5.3 × 5.7

Create another rectangle that is scaled to 4
times the size of the current rectangle.

Answers

Answer:

A rectangle of 10.6 x 11.4 dimensions.

Step-by-step explanation:

(5.3*2)*(5.7*2)=5.3*4*5.7=10.6x11.4.

Solve the equation for N

Solve the equation for N

Answers

The value of N would be N = q/(9 + 4uz).

What is algebraic manipulation?

Algebraic manipulation is the process of rearranging mathematical expressions in order to solve equations or to make them easier to understand. It involves the use of mathematical operations and properties such as addition, subtraction, multiplication, division, and the commutative, associative, and distributive properties.

Given:

q - 4Nuz = 9N

To find the value of N, we can use algebraic manipulation.

9N + 4Nuz = q

N(9 + 4uz) = q

N = q/(9 + 4uz)

Hence, the value of N would be N = q/(9 + 4uz).

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MATCH THE CORRECT ONE PLEASE HELP

MATCH THE CORRECT ONE PLEASE HELP

Answers

Answer:

same side interior for 2 and 6 i think

YES WHAT THE OTHER PERSON SAID SORRY CAPS LOCK IS STUCK

I dont know how the answer

I dont know how the answer

Answers

The median from the histogram is 5

What is histogram?

A histogram is a graph used to represent the frequency distribution of a few data points of one variable.

The median is the value in the middle of a data set.

The total frequency of the distribution is

1+4+5+4+2+1+1+1+1

= 20

The median term will be on

20+1)/2

= 10.5th

Therefore form the graph the 10.5 th term falls in the class of 5

This means that the median class is 5.

Therefore the median from the histogram is 5

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Un profesor de Enseñanza Básica le indica a sus alumnos que escojan tres dígitos
diferentes del conjunto {1, 2, 3, 4, 5} y formen números mixtos colocando los dígitos
en el casillero . También les recuerda que la parte fraccionaria tiene que ser
menor que 1, por ejemplo
2
3
5
. ¿Cuál es la diferencia entre el mayor y el menor de los
números mixtos que se pueden formar?

Answers

Enseñanza Básica is the term used to describe the first level of education in the Chilean education system, which includes the first to eighth grades. A teacher of Enseñanza Básica asked his students to choose three-digit mixed numbers that can be formed.

A mixed number is a number that has both a whole number and a fraction component. To form three-digit mixed numbers, we need to have a whole number that is less than 100 and a proper fraction that has a denominator less than or equal to 99. Here are some examples:123 4/567 2/8109 1/2382 3/47There are a total of 900 three-digit numbers that can be formed using digits 1 to 9 without repetition. To find the number of three-digit mixed numbers that can be formed, we need to count the number of ways we can choose a proper fraction with a denominator less than or equal to 99. There are 99 possible denominators, and for each denominator, there are 98 possible numerators (excluding 0 and the denominator itself). Therefore, the total number of three-digit mixed numbers that can be formed is:900 x 99 x 98 = 8,334,600There are 8,334,600 three-digit mixed numbers that can be formed using digits 1 to 9 without repetition.

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The difference between the greatest and the least mixed numbers is 9.87 - 6.0789 ≈ 3.7911.

How to solve

The three digits different from {1, 2, 3, 4, 5} can be chosen from {0, 6, 7, 8, 9}.

The greatest mixed number is formed by placing the largest digit as the whole number and the remaining two digits as the fraction in descending order, i.e., 9 87/100 or 9.87.

The smallest mixed number is formed by placing the smallest non-zero digit as the whole number and the remaining two digits as the fraction in ascending order, i.e., 6 07/90 or 6.0789.

The difference between the greatest and the least mixed numbers is 9.87 - 6.0789 ≈ 3.7911.

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The Question in English

A Basic Education teacher tells his students to choose three digits

different from the set {1, 2, 3, 4, 5} and form mixed numbers by placing the digits

in the locker It also reminds them that the fractional part has to be

less than 1, for example

2

3

5

. What is the difference between the greatest and the least of the

mixed numbers that can be formed?

PLEASE HELP
Graph the following equation:
y=1/4x-2

Answers

Answer:

see explanation

Step-by-step explanation:

-2 is your y-intercept so one point on your plot is (0,-2)

your slope is 1/4, rise/run

so from the y-int go up 1 and right 4, so another point is (-1,4)

and you can keep going up 1 and right 4 for as many points as you need.

PLEEEEEASE HEEEEEELPPPP

PLEEEEEASE HEEEEEELPPPP

Answers

Answer:

x≤20

Step-by-step explanation:

x+5≤25

 -5.  -5

x≤20

Hopes this helps please mark brainliest

Answer:

The answer is B

Step-by-step explanation:

20+5=25 and x can be greater than or equal to 25

Twenty employees have applied for promotions. This year 7 promotions were awarded. If a random sample of 5 applications was selected.

a. What is the probability that at most 2 employees were promoted?
b. What is the probability that no employees were promoted?
c. Find the value of the expected value and the variance of this distribution.

Answers

Answer:

a)0.764

b)0.116

c)Expected value =1.75

Variance=1.1375

Step-by-step explanation:

Total Number of employees = 20

Number of promotions awarded = 7

Probability of success p =\(\frac{7}{20}\)

Probability of failure q = \(1-\frac{7}{20}=\frac{13}{20}\)

We randomly select 5 applications

a) What is the probability that at most 2 employees were promoted?

We will use binomial

\(P(X=x)=^nC_r p^r q ^{n-r}\\P(X\leq 2)=P(X=0)+P(X=1)+P(X=2)\\P(X\leq 2)=^{5}C_0 (\frac{7}{20})^0 (\frac{13}{20})^{5-0}+^{5}C_1 (\frac{7}{20})^1 (\frac{13}{20})^{5-1}+^{5}C_2 (\frac{7}{20})^2 (\frac{13}{20})^{5-2}\\P(X\leq 2)=\frac{5!}{0!(5-0)!} (\frac{7}{20})^0 (\frac{13}{20})^{5-0}+\frac{5!}{1!(5-1)!}(\frac{7}{20})^1 (\frac{13}{20})^{5-1}+\frac{5!}{2!(5-2)!} (\frac{7}{20})^2 (\frac{13}{20})^{5-2}\\P(X\leq 2)=0.764\)

b)What is the probability that no employees were promoted?

\(P(X=0)=^{5}C_0 (\frac{7}{20})^0 (\frac{13}{20})^{5-0}\\P(X=0)=\frac{5!}{0!(5-0)!} (\frac{7}{20})^0 (\frac{13}{20})^{5-0}\\P(X=0)=0.116\)

c)

\(E(X)=np=5 \times (\frac{7}{20})=1.75\\Var(X)=npq=5 \times (\frac{7}{20}) \times \frac{13}{20}=1.1375\)

A computer training institute has 625 students that are paying a course fee of $400. Their research shows that for every $20 reduction in the fee, they will attract another 50 students. Which equation could be used to represent this situation, where x is the course fee and R(x) is the total revenue?
R(x) = −2.5x2 + 1625x
R(x) = −3x2 + 1650x
R(x) = 3x2 − 1650x
R(x) = 2.5x2 − 1625x

Answers

The equation that could be used to represent this situation, where x is the course fee and R(x) is the total revenue, is: R(x) = 250000 + 375x - 2.5x²

What is an Equations?  

Equations are mathematical statements with two algebraic expressionsοn either sideοf an equals (=) sign. It illustrates the equality between the expressions writtenοn the left and right sides. To determine the valueοf a variable representing an unknown quantity, equations can be solved. A statement is not an equation if there is no "equal to" symbol in it. It will be regarded as an expression.

N(x) = 625 + 2.5x

The revenue R(x) will be the productοf the numberοf students enrolled and the fee charged per student. The fee charged per student will be (400 - x) dollars. So, the revenue function can be represented as:

R(x) = (625 + 2.5x)(400 - x)

Simplifying the expression, we get:

R(x) = 250000 + 375x - 2.5x²

Therefore, the equation that could be used to represent this situation, where x is the course fee and R(x) is the total revenue, is:

R(x) = 250000 + 375x - 2.5x²

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Given below are lease terms at the local dealership. What is the total cash
due at signing?
Terms:
• Length of lease = 36 months
• MSRP of the car = $27,500
• Purchase value of the car after lease = $17,500
• Down payment = $3400
• Monthly payment = $425
• $375 security deposit
• $500 acquisition fee

Answers

Answer:

4275$

Step-by-step explanation:

3400 down pmt + 375 sec dep + 500 fee

The total cash due at signing is, $15300

What is a numerical expression?

A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.

What is an equation?

An equation is written in the form of variables and constants separated by the operation of multiplication and division,

An equation states that terms in different forms on both sides of the equality sign are equal.

Multiplication and division do not separate the terms of an equation.

Given, The MSRP of the car is,  $27,500.

Now, The monthly payment = $425 and it is for 36 months,

Therefore, The total monthly downpayment is, 36×425 = $15300.

So, The total cash due at signing is, $15300 the monthly installments.

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an expression equivalent to 12+ 21 is

Answers

Answer:

33

Step-by-step explanation:

The answer is 1628. Because 16 x 21 = 28 x 12 = 336

Hope this helps

What is the value of this expression when m = 3 and n=−1?


−4(m−n)2


this is a fill in the blank question, please help me. Help me if you can, thank you

Answers

Answer:

−4( 3 − (−1) ) (2)

−4( 3 + 1 ) (2)

(−4) (4) (2)

(−16) (2)

−32

Arrange the following temperatures in ascending order and descending order.
a) 37°C, -15°C, 16°C, -12°C, 0°C, 96°C, -73°C
b) 20°C, -1°C -15°C 0°C, -7°C, 23°C, -36°C.​

Answers

Answer:

a) -73°C, -15°C, -12°C, 0°C, 16°C, 37°C, 96°C

a) 96°C, 37°C, 16°C, 0°C, -12°C, -15°C, -73°C

b) -36°C, -15°C, -7°C, -1°C, 0°C, 20°C, 23°C

b) 23°C, 20°C, 0°C, -1°C, -7°C, -15°C, -36°C

what is the probability that, in agiven year, the rainfall is between 28 and 36 inches?(Again, assume a normal distribution with mean 32 inches andstandard deviation 5 inches.)

Answers

ANSWER:

0.5762

STEP-BY-STEP EXPLANATION:

The first thing is to calculate the value of z, with the help of the following equation:

\(z=\frac{x-m}{sd}\)

In this case, we calculate for the values between 28 and 36 inches, like this:

\(\begin{gathered} P(28We calculate the probability with the help of the following table:

Replacing:

\(\begin{gathered} P=0.7881-0.2119 \\ P=0.5762 \end{gathered}\)

The probability is 0.5762

what is the probability that, in agiven year, the rainfall is between 28 and 36 inches?(Again, assume

Really easy math question!

Really easy math question!

Answers

Answer:
a. 146 ≤ 9c + 10

Explanation:
Step 1 - Find Out What Symbol We Will Be Using
Natalies budget is $146. This means she can spend less than or exactly $146 on yoga training. So, we will be using the less than or equal to symbol. It looks like this: ≤.

Step 2 - Eliminate Incorrect Options
Now that we know the symbol will look like ≤, we can eliminate options d and b.

Step 3 - Find Out Which Is The Dependent Variable
Natalie is going to buy a yoga mat which only costs $10. She is also going to join yoga classes which costs $9 per class. Since, the total cost of yoga classes depends on how many classes she takes, this is the dependent variable.

Step 4 - Write The Equation Using The Information Gathered
146 ≤ 9c + 10

the answer is A: 146 ≤ 9c + 10

write a equation of the line that passes through each pair of points (1,0) (5,-1)

Answers

Answer:

Slope : -1/4

Equation: y = -x + 1/4

Step-by-step explanation:

You start by finding the slope using the slope formula. Then after finding the slope you use one of the pairs to substitute in the equation y = mx+b then after doing that you solve for your b since it will be the only missing variable. Then you have your equation.

the chess club meets every two weeks and the student council meets every three weeks, how many weeks will it be before both clubs meet again on the same week

Answers

Answer:

6 weeks

Step-by-step explanation:

We need to find the common multiple of 3 and 2. The multiple of 2 and 3 is 6.

So on the 6th week.

I hope I could help!

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

The clubs meet on the 6th week.

The number of weeks before the clubs meet again on the same week is 5.

What is an expression?

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

The chess club meets every two weeks and the student council meets every three weeks.

This means,

The least common multiple of 2 and 3 is 6.

The club meets on the 6th week.

Thus,

The clubs meet on the 6th week.

The number of weeks before the clubs meet again on the same week is 5.

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Subtract.

7 1/5−(−3/5)

Enter your answer in the box as mixed number in simplest form.

Answers

7 4/5

Cause I’m smort

Answer:

7 4/5

Step-by-step explanation:

when you subtract, keep the first value then change subtract to addition and, finally, change the sign of the second value

this problem, 7 1/5 -(-3/5) is the same as this addition problem:

7 1/5 + 3/5

this equals 7 4/5

Find 5 1/2 x 1/3 in simplest form

Answers

Answer:

5 1/2 x 1/3 = 11x/6

Of twice a number and another number is five the sum of two numbers is 19 find the numbers

Answers

the two numbers are -7 and 26.



Let's call the first number "x" and the second number "y".

We're given that "twice a number and another number is five", which can be translated as:

2x + y = 5

We're also given that "the sum of two numbers is 19", which can be translated as:

x + y = 19

We now have two equations with two variables. We can solve for one variable in terms of the other, and then substitute that expression into the other equation to solve for the remaining variable.

Let's solve the second equation for "x":

x + y = 19

x = 19 - y

Now we can substitute this expression for "x" into the first equation:

2x + y = 5

2(19 - y) + y = 5

38 - 2y + y = 5

38 - y = 5

y = 33

Now we can use either equation to solve for "x":

x + y = 19

x + 33 = 19

x = -14

Therefore, the two numbers are -14 and 33.

Answer: the two numbers are -7 and 26.

Step-by-step explanation:

The running back for the Bulldogs football team carried the ball 7 times for a total loss of 12 1/4 yards. Find the average change in field position on each run. Enter the average change as a simplified mixed number.

Answers

The average change as a simplified mixed number would be,

⇒ 1 3/4

A fraction is a part of whole number, and a way to split up a number into equal parts. Or, A number which is expressed as a quotient is called fraction. It can be written as the form of p : q, which is equivalent to p / q.

We have to given that;

The running back for the Bulldogs football team carried the ball 7 times for a total loss of 12 1/4 yards.

Now, The average change as a simplified mixed number would be,

⇒ (12 1/4) / 7

⇒ (49/4) / 7

⇒ (49 / 4×7)

⇒ 7/4

⇒ 1 3/4

Therefore, The average change is,

⇒ 1 3/4

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Explain the meaning of the term floor plan in this context​

Answers

floor plan => It is the scale drawing that show the relationship between rooms, spaces, and physical features viewed from the above

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Explain the meaning of the term floor plan in this context

4. Consider the function g(x) = 2x^2 - 4x+3 on the interval [-1, 2]
A.) Does Rolle's Theorem apply to g(x) on the given interval? If so, find all numbers, s,
guaranteed to exist by Rolle's Theorem. If not, explain why not. (2 pts.)
b.) Does the Mean Value Theorem apply to g(x) on the given interval? If so, find all
numbers, a guaranteed to exist by the Mean Value Theorem. If not, explain why not.
(4 pts.)

Answers

Hi there!

A.) Begin by verifying that both endpoints have the same y-value:

g(-1) = 2(-1)² - 4(-1) + 3

Simplify:

g(-1) = 2 + 4 + 3 = 9

g(2) = 2(2)² - 4(2) + 3 = 8 - 8 + 3 = 3

Since the endpoints are not the same, Rolle's theorem does NOT apply.

B.)

Begin by ensuring that the function is continuous.

The function is a polynomial, so it satisfies the conditions of the function being BOTH continuous and differentiable on the given interval (All x-values do as well in this instance). We can proceed to find the values that satisfy the MVT:

\(f'(c) = \frac{f(a)-f(b)}{a-b}\)

Begin by finding the average rate of change over the interval:

\(\frac{g(2) - g(-1)}{2-(-1)} = \frac{3 - 9 }{2-(-1)} = \frac{-6}{3} = -2\)

Now, Find the derivative of the function:

g(x) = 2x² - 4x + 3

Apply power rule:

g'(x) = 4x - 4

Find the x value in which the derivative equals the AROC:

4x - 4 = -2

Add 4 to both sides:

4x = 2

Divide both sides by 4:

x = 1/2

what is 999.09344471 rounded to the nearest square kilometer?

Answers

The nearest kilometers to 999.09344471 km is 1000 km.

Given value is 999.09344471 Km.

We have to calculate the round off value to the nearest kilometers. we know that after the decimal if the value of tenth place is 5 or bigger than 5 then we add 1 to the tens place digit, this is the fundamental rule of rounding off.

Now on following this rule from the very right hand side up to the tenth place digit we come to the conclusion that only  the value after the decimal (934) is to be rounded off which is (900).

So 999.09344471 km is finally becomes 999.900 km after rounding of to nearest hundredth value.

Again rounding off 999.900 km to nearest km so it becomes 1000 km.

The nearest kilometers to 999.09344471 km is 1000 km.

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An evergreen nursery usually sells certain shrub after 6 years of growth and shaping: The growth rate during those 6 years is approximated by dh/dt = 1.2t + 2, where t is the time in years and h is the height in centimeters. The seedlings are 15 centimeters tall when planted (t = 0). (a) Find the height after years h(t) (b) How tall are the shrubs when they are sold? cm

Answers

(a) After t years, the height is 18t² + 3t + 10

(b) The shrubs are847 cm tall when they are sold.

Given growth rate

dh/dt = 1.8t + 3

dh = (18t + 3)dt

Integrating this, we have

h = 18t² + 3t + C

When t = 0, h = 10cm

Then

10 = C

So

(a) h = 18t² + 3t + 10

(b) Because they are sold after every 9 years, then at t = 9

h = 18(9)² + 3(9) + 10

= 810 + 27 + 10

= 847 cm

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Which angle relationships are correct? Check all that apply.

∠1 and ∠8 are alternate exterior angles.
∠4 and ∠6 are same side interior angles.
∠5 and ∠7 are vertical angles.
∠2 and ∠8 are corresponding angles.
∠3 and ∠6 are alternate interior angles.

Answers

The angle relationships which are correct are:

∠4 and ∠6 are same side interior angles.

∠3 and ∠6 are alternate interior angles.

Side interior angles

Two angles that are on the same side of the transversal and written the same side of the transversal when two lines are intersected by a third line are called side angles.

Alternate interior angles

Alternate interior angles are the angles formed on the opposite sides of the transversal.

Hence the correct relationship are ∠4 and ∠6 are same side interior angles and ∠3 and ∠6 are alternate interior angles.

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HELP MEEEEEE



|| Part A
Which sets of measurements could be the interior angle measures of a a triangle?
(a)
Select each correct answer
A 10°, 10°, 160°
B15°,75°, 90°
20°, 80°, 100°
D 35°, 35°, 105°
E 60°, 60°, 60°
Part B
Which sets of measurements could be the side lengths of a triangle?
Select each correct answer.
A3 cm, 3 cm, 3 cm
84 cm, 8 cm, 13 cm
c5 cm, 9 cm, 14 cm
D 6 cm. 7 cm. 8 cm.
(b)

Answers

Answer:

Part a) a b and e

Part b) a and d

Step-by-step explanation:

Part A)

The sum of the angles is a triangle is always 180 degrees.

So that means that of the answer choices, the ones with angle measures that add up to 180 degrees form a triangle. 0

a) 10 + 10 + 160 = 180

b) 15 + 75 + 90 = 180

c) 20 + 80 + 100 = 200

d) 35 + 35 + 105 = 175

e) 60 + 60 + 60 = 180

a , b and e all have angle measures that would add up to 180 degrees therefore a b and e would form triangles

Part B)

In order for side lengths to form a triangle, the sum of the two shorter sides must be greater than the longest side.

a) all side lengths are 3 which would form an equilateral triangle ( triangle with all equal sides ). For more clarification we could say 3 + 3 = 6 > 3 ( sum of sides are greater than other side length )

b) 8 + 13 = 21 > 83

c) 5 + 9 = 14 > 14

d) 6 + 7 = 13 > 8

The only true outcomes are a and d so a and d would form triangles

A sixth-grade class must raise at least $447 to go on a field trip. The amount of money, m, that each of the 30 students must raise can be found using the inequality below. If all the students contribute an equal amount, how much will each student need to raise for the class to go on the field trip? 1. Summarize the given situation in your own words. (What do you notice?)

Answers

Answer:

Each student must raise $14.90

Step-by-step explanation:

This is actually fairly easy to figure out (at least this part) all you do is 447/30 and then you get your 14.9 (14.90)

m = 14.90

30m = 447

The half‑life of sodium‑ 22 is 2.6 years. If there are initially 70 grams of sodium‑ 22, find a formula that gives the amount , in grams, remaining after t years.

Answers

A formula that gives the amount is

N(t) = 70 (0.5)^t/2.6

How to find a formula that gives the amount

The half life of the element is calculated from the formula

N(t) = N'(1/2)^(t/t')

where

N(t) = quantity of the substance remaining

N' = initial quantity of the substance

t = time elapsed

t' = half life of the substance

Plugging the values from the problem

N(t) = ?

N' = 70 grams

t = t

t' = 2.6 years

N(t) = 70 (0.5)^t/2.6

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18. The florist charges $31.75 for eight roses and five carnations. For one rose and three
carnations, if costs $5.75. What is the cost for a carnation? (Solving systems of equations applications)

Answers

Answer: Let's use the variables "r" and "c" to represent the cost of one rose and one carnation, respectively.

From the first sentence, we know that 8 roses and 5 carnations cost $31.75. So we can write the equation:

8r + 5c = 31.75

From the second sentence, we know that 1 rose and 3 carnations cost $5.75. So we can write the equation:

r + 3c = 5.75

Now we have two equations with two variables. We can use substitution or elimination to solve for "c". Let's use substitution:

r = 5.75 - 3c (from the second equation)

Substitute this expression for "r" into the first equation:

8(5.75 - 3c) + 5c = 31.75

Simplify and solve for "c":

46 - 24c + 5c = 31.75

-19c = -14.25

c = 0.75

Therefore, the cost for a carnation is $0.75.

Step-by-step explanation:

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