Answer:
Debbie ran 0.875 miles in 7.5 minutes
Step-by-step explanation:
Order these numbers from least to greatest. The top number in your list should be the least, and the bottom number should be the greatest. A. 8/3, B. -√8, C. -3, D. √9
Answer:C, B, A, D
Step-by-step explanation:
Answer:
C, B, A, D
Step-by-step explanation:
A -- (8/3) = 2.666666667
B -- (-√8) = -2.828427125
C -- (-3) = -3
D -- (√9) = 3
Ans: (-3), (-√8), (8/3), (√9)
**Hope this helps!
determine whether the following procedure results in a binomial distribution or a distribution that can be treated as binomial (by applying the 5% guideline for cumbersome calculations). If it is not binomial and cannot be treated as binomial, identify at least one requirement that is not satisfied.
Treating 20 bald men with a special shampoo and recording how they say their scalp feels
Choose the correct answer below.
A. It is binomial or can be treated as binomial.
B. It is not binomial because the probability of success does not remain the same in all trials.
C. It is not binomial because there are more than two possible outcomes.
D. It is not binomial because there are more than two possible outcomes and the trials are not independent.
The given procedure results as not binomial and cannot be treated as binomial. It is not binomial because the probability of success does not remain the same in all trials. The correct answer is option B.
What is binomial distribution?Binomial distribution compiles the number of trials, or observations when each trial has the same probability of attaining one particular value. Binomial distribution controls the probability of observing a specified number of successful outcomes in a specified number of trials.
In a binomial distribution, the probability of getting a success have to remain the same for the trials we are investigating. For example, when tossing a coin, the probability of flipping a coin is half or 0.5 for every trial we conduct, because there are only two possible outcomes.
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2 345 000 000 in scientific notation
if you take away 25 from a number you will be left with two and halftimes 30. what is the number?
ASAP NEED NOW
Question 3 (Essay Worth 10 points)
(01.07 MC)
Show all work to multiply (6+√-64)(3-√-16).
Answer:
50
Step-by-step explanation:
(6+√-64)(3-√-16)
6(3-√-16) +√-64(3-√-16)
18 - 6√-16 + 3√-64 - √1024
18 - 6(4i) + 3(8i) - 32i²
i² = -1
18 - 24i + 24i - (-1) 32
18 + 24i - 24i + 32
18 + 32 = 50
I hope this helps!
A certain drug is eliminated from the bloodstream exponentially with a half-life of 12 hours. Suppose that apatient receives an initial dose of 25 milligrams of the drug at midnight. Estimate when the drugconcentration will reach 20% of its initial level. Round the answer to the nearest whole number.
Determine 20% of the initial level
20% → 0.2
\(25\text{ mg}\cdot0.2=5\text{ mg}\)Write the equation with half-life of 12 hours and initial dose of 25 mg.
\(y=25\cdot\Big(\frac{1}{2}\Big)^{\frac{t}{12}}\)Substitute y = 5, and solve for t
\(\begin{gathered} y=25\cdot\Big{(}\frac{1}{2}\Big{)}^{\frac{t}{12}} \\ 5=25\cdot\Big{(}\frac{1}{2}\Big{)}^{\frac{t}{12}} \\ \frac{5}{25}=\frac{\cancel{25}\cdot\Big{(}\frac{1}{2}\Big{)}^{\frac{t}{12}}}{\cancel{25}} \\ \frac{1}{5}=\Big{(}\frac{1}{2}\Big{)}^{\frac{t}{12}} \end{gathered}\)Get the natural logarithm of both sides
\(\begin{gathered} \ln \frac{1}{5}=\ln \Big{(}\frac{1}{2}\Big{)}^{\frac{t}{12}} \\ \ln \frac{1}{5}=\frac{t}{12}\cdot\ln \Big{(}\frac{1}{2}\Big{)}^{} \\ t=\frac{12\ln \frac{1}{5}}{\ln \frac{1}{2}} \\ t=27.86313714 \end{gathered}\)Rounding the answer to the nearest whole number, the time it takes for the initial dose to be reach 20% of its initial level is 28 hours.
Find the solution to the equation 3x +4-X= 5x-10-X
Add like terms:
\(\begin{gathered} 2x+4=4x-10 \\ \end{gathered}\)subtract 2x from both sides:
\(\begin{gathered} 2x+4-2x=4x-10-2x \\ 4=2x-10 \end{gathered}\)Add 10 to both sides:
\(\begin{gathered} 4+10=2x-10+10 \\ 14=2x \end{gathered}\)Divide both sides by 2:
\(\begin{gathered} \frac{2x}{2}=\frac{14}{2} \\ x=7 \end{gathered}\)Which would be appropriate compatible numbers to use to estimate ( 19 4 5 ) ( 4 6 ) ? Using this compatible number, what is the estimated product?
The appropriate compatible numbers to use to estimate would be 20(1/2)
estimated product is 10, took the quiz :)
Answer: 20 1/2
10
Step-by-step explanation:
Question 6 of 10
What is the solution to the system of equations graphed below?
y = -2x + 4
y=x-5
Answer:
the solution to the system of equations is (x, y) = (3, -2).
Step-by-step explanation:
y = -2x + 4 (Equation 1)
y = x - 5 (Equation 2)
To solve for x, we can equate the right sides of the equations:
-2x + 4 = x - 5
Now, we can solve for x:
-2x - x = -5 - 4
-3x = -9
x = (-9) / (-3)
x = 3
Substituting the value of x back into Equation 2, we can solve for y:
y = 3 - 5
y = -2
The following scatterplot shows two variables, x and y, along with a least-squares model.
Which of the following is a high leverage point with respect to the regression?
A (5,8)(5,8)
B (20,31)(20,31)
C (27,22)(27,22)
D (30,60)(30,60)
E (80,70)
Answer:
D(30,60)
Step-by-step explanation:
It was way outside the other points that are around the line.
The point (30,60) is a high leverage point on the regression plot.
What is High leverage points?High leverage points are those that are extreme but follow the regression equation's trend.
High leverage points are distinct from outliers, which deviate from the graph's or plot's pattern or trend.
Looking closely at the regression plot, the coordinate (30,60) follows the trend of the plot, however, it is farther from the majority of the points on the graph.
Hence, the point (30,60) is a high leverage point on the regression plot.
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can you please list all of the possible integers that could replace K in the expression \(6 {x }^{2} + kx - 8\)so that the expression can be factored using integers.
SOLUTION
We are given the expression
\(\begin{gathered} 6x^2+kx-8 \\ to\text{ list all the possible integers that could replace k so that the expression} \\ \text{can be factorized } \end{gathered}\)To do this, we say
\(\begin{gathered} 6x^2\text{ }\times\text{ }-8=-48x^2 \\ \text{now we list all the possible factors of }-48x^2\text{ and sum them to get k} \\ -48+\text{ 1 = -4}7 \\ -24\text{ + 2 = -22} \\ 48\text{ + (-1) = 47} \\ 24\text{ + (-2) = 22} \\ -16\text{ + 3 = -13} \\ 16\text{ + (-3) = 13} \\ -12\text{ + 4 = -8} \\ 12\text{ + (-4) = }8 \\ -\text{ 8 + 6 = -2} \\ 8+\text{ (-6) = 2} \end{gathered}\)Therefore the possible values of k are -47, 47, -22, 22, -13, 13, -8, 8, -2 and 2
Health care issues are receiving much attention in both academic and political arenas. A sociologist recently conducted a survey of citizens over 60 years of age whose net worth is too high to qualify for Medicaid. The ages of 25 senior citizens were as provided. Determine which of the statements below is true.
60 61 62 63 64 65 66 68 68 69 70 73 73 74 75 76 76 81 81 82 86 87 89 90 92
Required:
Identify the median age of the uninsured senior citizens.
Answer:
median value = 73 years
Step-by-step explanation:
The median age of the uninsured senior citizens can be determined by determining the middle position of the row of data given
median = [( n + 1 ) / 2 ] ^th
n = 25
median = (25 + 1 ) / 2 = 26 / 2 = 13
This means that the median value is located in the 13th position
The number in the 13th position = 73 years
The difference between the third and first quartiles in a data set, representing the middle half of
the data.
Answer:
Interquartile range
Step-by-step explanation:
The interquartile range gives the middle half of a dataset. It is obtained by subtractionng the value of the lower quartile (Q1) from the value of the upper quartile(3rd quartile).
Interquartile range (IQR) = Q3 - Q1
WHERE ;
Q3 = 3/4 * (n+1)th term and the first quartile (Q1) is given as ;
Q1 = 1/4 * (n+1)th term
n = size of data Given.
Write the equation of the line that is parallel to y = -2x + 4 and passes through (3, 1) in slope-intercept form.
Answer:
y = -2x + 7
Step-by-step explanation:
y = -2x + 4
Slope in above equation is -2. Parallel lines share the same slope so the new equation will also have a slope of -2.
y-intercept through point (3, 1):
y = mx + b
1 = -2(3) + b
1 = -6 + b
b = 7
Equation of line that is parallel to original:
y = mx + b
y = -2x + 7
ocupo encontrar la x con procedimiento
les regalare coronas!!!!
La variable x asociada al sistema geométrico con dos ángulos alternos externos es igual a 23.
¿Cómo determinar la variable asociada a dos ángulos alternos externos?
En esta pregunta tenemos un sistema geométrico conformado por dos líneas paralelas atravesadas por una tercera línea. Este conjunto incluye dos ángulos alternos externos, que guardan la siguiente relación según la geometría euclídea:
6 · x - 28 = 4 · x + 18
A continuación, despejamos la variable x:
6 · x - 4 · x = 28 + 18
2 · x = 46
x = 23
El valor de la variable x es 23.
ObservaciónNo existen preguntas en español sobre ángulos alternos externos, por lo que se añade una pregunta en inglés.
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Please see the attached.
Answer:
min: 56
lower quartile: 70
median: 74
upper quartile: 80
max: 86
John collected data to determine how many minutes his teammates spend practicing basketball each night. Identify the outlier in his data.
Question 1 options:
10 minutes
40 minutes
30 minutes
5 minutes
Answer:
Step-by-step explanation:
5 minutes is the outlier. It sticks out from the rest.
Proof that irrational numbers are uncountable
Answer:
If the set of all irrational numbers were countable, then R would be the union of two countable sets, hence countable. Thus the set of all irrational numbers is uncountable
The angles of a
quadrilateral, taken in order
are y, 5y, 4y
and
2y.
Find these angles
Answer:
30, 150, 120, and 60 degrees
Step-by-step explanation:
Since the sum of the interior angles in a quadrilateral is 360 degrees:
y+5y+4y+2y=360
12y=360
y=30
2y=60, 4y=120, 5y=150
Hope this helps!
Step-by-step explanation:
y+5y+ 4y + 2y=360°(sum of a Quadrilateral)
12y=360°
divide both sides by 12
y=30°
5y=(5×30)=150°
4y=(4×30)=120°
2y=(2×30)=60°
Brian set his compass equal to the radius of circle C and drew two circles centered at points A and B on circle C. He labeled the points of intersection of the two circles as shown.
Two circles are drawn by having another circle in the center. The center circle has points A, M, N, B, P, Q, and C. At C the two circles intersect, and at P the center circle and the top circle intersect.
To complete his construction, Brian only needs to use his straightedge to draw some chords of circle C.
Which figures could Brian be constructing?
equilateral triangle MNQ inscribed in circle C
equilateral triangle ANP inscribed in circle C
regular hexagon AMNBPQ inscribed in circle C
square MNPQ inscribed in circle C
square ANBQ inscribed in circle C
The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:
Equilateral triangle MNQ inscribed in circle C
Regular hexagon AMNBPQ inscribed in circle C
Brian is constructing figures inscribed in circle C.
Equilateral triangle MNQ inscribed in circle C:
This option is possible since the points M, N, and Q are labeled and they lie on circle C.
Equilateral triangle ANP inscribed in circle C:
This option is not possible. The points A and P are labeled, but the third vertex of the equilateral triangle is not specified.
Regular hexagon AMNBPQ inscribed in circle C:
This option is possible since the points A, M, N, B, P, and Q are labeled and they lie on circle C.
Square MNPQ inscribed in circle C:
This option is not possible based on the given information. The label points do not form a square.
Square ANBQ inscribed in circle C:
This option is not possible . The points A, N, B, and Q are labeled, but they do not form a square.
The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:
Equilateral triangle MNQ inscribed in circle C
Regular hexagon AMNBPQ inscribed in circle C
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The quotient of twenty and a number, decreased by 4, is equal to zero
The equation associated with the quotient of twenty and a number, decreased by 4, is equal to zero is 20/x - 4 = 0 and that number will be 5.
How to form an equation?Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.
In other words, an equation is a set of variables that are constrained through a situation or case.
Let's say that number is x,
Quotients of 20 and x will be given as 20/x
20/x - 4 = 0
20/x = 4
x = 20/4 = 5
Hence"The equation associated with the quotient of twenty and a number, decreased by 4, is equal to zero is 20/x - 4 = 0 and that number will be 5".
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Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 14 ft high?
Answer:
\(\frac{20}{49\pi }\) when the pile is at 14ft
Step-by-step explanation:
To get your height in inches alone from the way it's usually presented (e.g. 5' 7"), multiply the total number of feet by 12 and then add the remainder. For example, a 5' 7" person is (5 × 12) + 7 = 67" tall. To convert inches to centimeters (in to cm), simply multiply by 2.54.
How would you type in math symbols? When you ask for answer to algebra question.
Answer:
_+
Step-by-step explanation:
-3x is a example of symbols
find the value of x in the equation 2x²+3x+3=20
Step-by-step explanation:
we first of all move 20 behind the comma for it to become -20 +3 and we get -17.
then use the product =-34
sum = 3
factors then continue
Answer:
\(x= \frac{-3 - \sqrt{145} }{4} \ \ or\ \ x= \frac{-3 + \sqrt{145} }{4}\)
Step-by-step explanation:
2x² + 3x + 3 = 20
⇔ 2x² + 3x + 3 - 20 = 0
⇔ 2x² + 3x - 17 = 0
Using the Quadratic Formula to solve a Quadratic Equation :
\(x= \frac{-b \pm \sqrt{b^{2}-4ac} }{2a}\)
In the equation 2x² + 3x - 17 = 0
a = 2 , b = 3 and c = -17
Then
b² - 4ac = 3² - 4×2×(-17)
= 9 + 8 × 17
= 9 + 136
= 145
Then
b² - 4ac > 0
Then
\(x= \frac{-3 \pm \sqrt{145} }{2 \times 2}\)
Then
\(x= \frac{-3 \pm \sqrt{145} }{4}\)
I need help !!!!!In the figure shown
Answer: it is D
Step-by-step explanation:
what is the equation for the perpendicular bisector of the line segment whose endpoints are (-7, 2) and (-1,-6)
The equation of the perpendicular bisector of the line segment with endpoints (-7, 2) and (-1, -6) is y = (3/4)x + 1.
To find the equation of the perpendicular bisector of a line segment, we need to determine the midpoint of the line segment and the slope of the line segment. The perpendicular bisector will have a negative reciprocal slope compared to the line segment and will pass through the midpoint.
Given the endpoints (-7, 2) and (-1, -6), we can find the midpoint using the midpoint formula:
Midpoint = ((x1 + x2)/2, (y1 + y2)/2)
Midpoint = ((-7 + (-1))/2, (2 + (-6))/2)
= (-8/2, -4/2)
= (-4, -2)
The midpoint of the line segment is (-4, -2).
Next, we need to find the slope of the line segment using the slope formula:
Slope = (y2 - y1)/(x2 - x1)
Slope = (-6 - 2)/(-1 - (-7))
= (-6 - 2)/(-1 + 7)
= (-8)/(6)
= -4/3
The slope of the line segment is -4/3.
Since the perpendicular bisector has a negative reciprocal slope, the slope of the perpendicular bisector will be 3/4.
Now, we can use the midpoint (-4, -2) and the slope 3/4 in the point-slope form of a line to find the equation of the perpendicular bisector:
y - y1 = m(x - x1)
y - (-2) = (3/4)(x - (-4))
y + 2 = (3/4)(x + 4)
y + 2 = (3/4)x + 3
y = (3/4)x + 1.
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The perimeter of a pool is 150 m. the rectangle at the right is a scale drawing of the pool. The length of each square on the grid represents 1 cm. draw another scale drawing of the pool using the scale 25 m to 2 cm. Explain why your drawing is accurate.
The dimensions of the another rectangle is 2 cm and 4 cm.
According to the statement
We have to find that the perimeter of another rectangle.
So, For this purpose, we know that the
The perimeter of a shape is defined as the total length of its boundary.
From the given information:
The perimeter of a pool is 150 m. the rectangle at the right is a scale drawing of the pool. The length of each square on the grid represents 1 cm. draw another scale drawing of the pool using the scale 25 m to 2 cm.
Then
From the given rectangle,
Length of the rectangle = 5 cm
Width of the rectangle = 10 cm
Ratio of length : width = 1 : 2
Perimeter of the rectangle = 2(l + b)= 150 cm
l + b = 75 -----(1)
Since, l : b = 1 : 2
l/b = 1/2
b = 2l ------(2)
From equations (1) and (2),
l + 2l = 75
3l = 75
l = 25 m
Width 'b' = 2(25) = 50 m
Now we've to draw a rectangle with a scale = 25 : 2
Therefore, multiplier factor = 25/l = 25/2
l = 2 cm
Similarly,
50/w = 25/2
w = 4 cm
Now we are able to draw a rectangle with length = 2 cm and width = 4 cm.
So, The dimensions of the another rectangle is 2 cm and 4 cm.
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Help guyssssssssssssss
Answer:
1
Step-by-step explanation:
In a recent poll, 380 people were asked if they liked dogs, and 16% said they did. Find the margin of error of this poll, at the 95% confidence level.
The margin of error of this poll at the \(95\%\) confidence level is calculated to be \(0.035\).
We will use the following formula to calculate the margin of error at the \(95\%\) confidence level:
\(\[ \text{{Margin of Error}} = \text{{Critical Value}} \times \text{{Standard Error}} \]\)
The critical value for a 95% confidence level is 1.96 (approximately).
The standard error can be found out using the formula written below:
\(\[ \text{{Standard Error}} = \sqrt{\frac{{\text{{p}}(1 - \text{{p}})}}{{\text{{n}}}}} \]\)
In this formula, p is the proportion of people who like dogs (0.16) and n is the sample size (380).
As for the next step, we will substitute the values into the formulas:
\(\[ \text{{Margin of Error}} = 1.96 \times \sqrt{\frac{{0.16(1 - 0.16)}}{{380}}} \]\)
Evaluating this expression gives the margin of error at the 95% confidence level.
\(\[ \text{{Margin of Error}} = 1.96 \times \sqrt{\frac{{0.16(1 - 0.16)}}{{380}}} \approx 0.035 \]\)
Therefore, the margin of error of this poll at the 95% confidence level is approximately \(0.035\).
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A total of 27 students are in your class. There are nine more males than females.
How many females are in your class?