Answer:
Explanation:
To find the distance covered by the car after it applied brakes, we use 3rd equation of motion.
2as = Vf² - Vi²
s = (Vf² - Vi²)/2a
1.
We have:
Vi = Initial Velocity = 5 m/s
Vf = Final Velocity = 0 m/s (Since, car finally stops)
a = deceleration = - 2 m/s²
s = distance covered by the car = ?
Therefore,
s = [(0 m/s)² - (5 m/s)²]/2(- 2 m/s²)
s = 6.25 m
2.
We have:
Vi = Initial Velocity = 10 m/s
Vf = Final Velocity = 0 m/s (Since, car finally stops)
a = deceleration = - 2 m/s²
s = distance covered by the car = ?
Therefore,
s = [(0 m/s)² - (10 m/s)²]/2(- 2 m/s²)
s = 25 m
Hence, the distance traveled by the car is affected by the initial speed in accordance with a direct relationship.
1) Compute the x and y components of the following vectors, and state them in component form.
a) A 8.0 m South
b) B-15.0 m at 30-East of North
c) C = 12.0 m at 25-South of West -
d) D=10.0 m at 53-West of North-
a) A = 8.0 m South
Since the vector is directly along the South direction, there is no x component.
x component: 0 m
y component: -8.0 m (negative because it's southward)
Component form: A = (0, -8.0)
b) B = -15.0 m at 30° East of North
To find the components, we can use the following relationships:
x component: B_x = B * sin(θ)
y component: B_y = B * cos(θ)
B_x = -15.0 * sin(30°) = -15.0 * 0.5 = -7.5 m
B_y = -15.0 * cos(30°) = -15.0 * (sqrt(3)/2) ≈ -12.99 m
Component form: B ≈ (-7.5, -12.99)
c) C = 12.0 m at 25° South of West
x component: C_x = -C * cos(θ) (negative because it's westward)
y component: C_y = -C * sin(θ) (negative because it's southward)
C_x = -12.0 * cos(25°) ≈ -10.85 m
C_y = -12.0 * sin(25°) ≈ -5.16 m
Component form: C ≈ (-10.85, -5.16)
d) D = 10.0 m at 53° West of North
x component: D_x = -D * sin(θ) (negative because it's westward)
y component: D_y = D * cos(θ)
D_x = -10.0 * sin(53°) ≈ -8.0 m
D_y = 10.0 * cos(53°) ≈ 6.0 m
Component form: D ≈ (-8.0, 6.0)
Suppose that an object undergoes simple harmonic motion, and its displacement has an amplitude A = 15.0 cm and a frequency f = 11.0 cycles/s (Hz). What is the maximum speed ( v ) of the object?
A. 165 m/s
B. 1.65 m/s
C. 10.4 m/s
D. 1040 m/s
Answer:
Maximum speed ( v ) = 10.4 m/s (Approx)
Explanation:
Given:
Amplitude A = 15.0 cm = 0.15 m
Frequency f = 11.0 cycles/s (Hz)
Find:
Maximum speed ( v )
Computation:
Angular frequency = 2πf
Angular frequency = 2π(11)
Angular frequency = 69.14
Maximum speed ( v ) = WA
Maximum speed ( v ) = 69.14 x 0.15
Maximum speed ( v ) = 10.371
Maximum speed ( v ) = 10.4 m/s (Approx)
An object is dropped from a vertical height of 1.89 m above the balcony level. What is the object’s speed when it is 2.20 m below the balcony level if 10.0% energy is lost due to the air resistance? Does it matter when to apply 10% loss before V calculations or after?
[8.49m/s] [yes it does, 0.9Energy result in √0.9Velocity]
Can someone solve this problem?
The conservation of mechanical energy allows to find the results for the velocity of the body when it is under the balcony and has a loss of energy due to friction are:
The velocity is: v = 8.49 m / s The energy loss must be used in the definition of the final energy to have correct results.
Mechanical energy is defined as the sum of kinetic energy plus potential energies. One of the main principles of physics is that energy cannot be created or destroyed unless it is transformed.
A reference system is a coordinate system with respect to which measurements are made, indicating that the height of the body is y₁= 1.89m above the balcony and the end point is y₂ = 2.20 m below the balcony. Let's set a reference frame with zero at the lowest point of the movement, therefore the highest point has a height.
h = y₁ + y₂
h = 1.89 + 2.20
h = 4.09 m
Let's find the initial energy at the highest point where the velocity is zero.
Em₀ = U = m g h
They indicate that it loses 10% of energy due to air resistance, the final energy is
\(Em_f = Em_o - \frac{Emo}{10}\)
\(Em_f = 0.90 Em_o\)
Let's write the final mechanical energy for the lowest point, at this point the height is zero.
\(Em_f\) = K = ½ m v²
we substitute
½ m v² = 0.90 m g h
v = \(\sqrt{0.90 \ 2 \ g \ h }\)
Let's calculate
v = \(\sqrt{0.90 \ 2 \ 9.8 \ 4.09 }\)
v = 8.49 m / s
The energy loss must be used before calculating the speed since if it were used afterwards the speed should be multiplied by 0.9 which we can see is incorrect.
In conclusion using the conservation of mechanical energy we can find the result for the velocity of the body when it is under the balcony and has a loss of energy due to friction are:
The velocity is: v = 8.49 m / s The energy loss must be used in the definition of the final energy to have correct results.Learn more here: brainly.com/question/18645704
Question 1(Multiple Choice Worth 2 points)
(06.01 LC)
How can the luster of a mineral be described? by the way this is Science
A Bland
B Dim
C Dull
D Twinkle
earth energy budget is the relationship between how much energy the earth _______ and energy the earth _________
earth energy budget is the relationship between how much energy the earth receive from the sun and energy the earth radiates out.
What is energy?Energy is described as the quantitative property that is displaced to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
The term earth's energy budget is also described as the balance between of the amount of energy, that gets to the earth. from the Sun and the energy that leaves Earth and returns to the universe.
The earth's energy budget was mainly three types as shown:
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The graph depicts the motion of two objects. Which statement BEST describes the acceleration of the two objects?
Responses
A Acceleration 1 - no acceleration. Acceleration 2 - speeds up and slows down.Acceleration 1 - no acceleration. Acceleration 2 - speeds up and slows down.
B Acceleration 1 - no acceleration. Acceleration 2 - negative acceleration.Acceleration 1 - no acceleration. Acceleration 2 - negative acceleration.
C Acceleration 1 - positive acceleration. Acceleration 2 - negative acceleration.Acceleration 1 - positive acceleration. Acceleration 2 - negative acceleration.
D Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration.
Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration. The correct option is D.
What is acceleration?Acceleration of any object is defined as the variation in the speed of the object with the variation of time. Acceleration is a vector term and to define it we require both the magnitude and the direction. The unit of acceleration can be m / sec², miles / sec², etc.
In a velocity-time graph, the acceleration corresponds to the slope of the curve.
In fact, acceleration is defined as the ratio between the change in velocity and the time interval:
a = Δv / Δt
However, in a velocity-time graph, corresponds to the y-variable increment (), while corresponds to the x-variable increment (). (). As a result, acceleration can also be expressed as,
a = Δy / Δx
For object 1, the slope is constant: this means that the acceleration is constant.
For object 2, the slope varies: this means that the acceleration varies as well.
The missing graph is attached with the answer below.
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Define invariant transformations
Answer:
For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement qi, then the corresponding conjugate momentum, pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".
. Which of the statement below about the magnetic
properties of iron and steel is correct?
A. Both iron and steel are equally magnetized and
demagnetized
B. Iron is more easilymagnetized and demagnetized
than steel.
C. Steel is more easily magnetized and demagnetized
than iron
D. Iron is more easily magnetized than steel but steel is
more easily demagnetized than iron.
Answer:
D. Iron is more easily magnetized than steel but steel is more easily demagnetized than iron.
03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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3. Which object has more inertia?
A. A tractor trailer rig moving at 2 m/s
B. A pingpong ball rolling a 2 m/s
C. A bowling ball rolling at 1m/s
D. A car rolling at 5 m/s
Answer:
A. A tractor trailer rig moving at 2 m/s
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
In physics, Sir Isaac Newton's first law of motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
The inertia of an object such as a tractor trailer rig is greatly dependent or influenced by its mass; the higher quantity of matter in a tractor trailer rig, the greater will be its tendency to continuously remain at rest.
Hence, the object that has more inertia is a tractor trailer rig moving at 2 m/s because it has more mass than all the other objects in the category. Also, the mass of an object is directly proportional to its inertia.
i need help on a english book report
Answer:
I can help, but
Explanation:
Where is the question?
A rover vehicle weighs 37 N on Mars. How much would the rover weigh on Earth?
The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N
How do determine the weight of the vehicle on earth?We'll begin by obtaining the mass of the rover vehicle. This is shown below:
Weight (W) = 37 NAcceleration due to gravity on Mars (g) = 3.72 m/sMass of rover vehicle =?Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
Divide both sides by g
m = W /g
m = 37 / 3.72
m = 9.95 Kg
Now, we shall determin the weight of the rover vehicle on Earth. Details below:
Mass (m) = 9.95 KgAcceleration due to gravity on Earth (g) = 10 m/s² Weight (W) = ?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 9.95 × 10
Weight = 99.5 N
Thus, we can conclude that the weight on Erath is 99.5 N
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A wave that has smaller amplitude than another carries less _______
Answer:
A wave that has smaller amplitude than another carries less what
Waves that have smaller amplitude have less energy. the particles of the waves. rarefactions are far amplitude waves. Wavelength is the distance from one crest to the next crest or from one trough to the next trough.
Explanation:
90 V
R₁
60
R2
30
R3
30
Based on the circuit above, what would be the current through the R3 resistor?
In the parallel combination, the current through R3 is 3 A. In the series combination, the current through R3 is 0.75 A.
To determine the current through resistor R3 in both the parallel and series combinations, we need to apply Ohm's Law and the appropriate formulas for calculating total resistance and current in each configuration.
First, let's consider the parallel combination:
In a parallel combination, the voltage across each resistor is the same. Therefore, the voltage across R3 is also 90 V.
Using Ohm's Law (V = I × R), we can calculate the current flowing through R3 in the parallel combination:
I_parallel = V / R3
= 90 V / 30 Ω
= 3 A
So, in the parallel combination, the current through R3 is 3 A.
Now, let's consider the series combination:
In a series combination, the total resistance is the sum of the individual resistances:
R_total = R1 + R2 + R3
= 60 Ω + 30 Ω + 30 Ω
= 120 Ω
To find the current through the series combination, we can use Ohm's Law:
I_series = V / R_total
= 90 V / 120 Ω
= 0.75 A
Therefore, in the series combination, the current through R3 is 0.75 A.
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Note the complete questions is User
90 V R₁=60 R2= 30, R3 = 30
Based on the circuit above, what would be the current through the R3 resistor in parallel and in series combinantion.
you are driving at 18m/s down Lyndale avenue. A car backs out a driveway 25 meters in front of you. You continue at that speed while your brain processes the danger which takes 0.25 seconds. You then slam on the brakes and your car has an acceleration of -5.4m/s^2. Do you stop before reaching the driveway(and hitting the car)? Show your work. This is a two-part problem with constant speed and braking.
Hello!
For this, first let's calculate time of stop:
t = (V - Vi) / a
Replacing:
t = (0 m/s - 18 m/s) / -5,4 m/s^2
Resolving:
t = -18 m/s / -5,4 m/s^2
t = 3,33 s + 0,25 s = 3,58 s
Now lets calculate distance traveled, with formula:
d = Vi*t + (a*t^2)/2
Replacing:
d = 18 m/s * 3,58 s + (-5,4 m/s^2 * (3,58 s)^2) /2
Resolving:
d = 64,44 m + (-34,604 m)
d = 29,83 m
Then, the vehicle will CRASH
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Two planets, Dean and Sam, orbit the Sun. They each have with circular orbits, but orbit at different distances from the Sun. Dean orbits at a greater average distance than Sam. According to Kepler's Third Law, which planet will have a longer orbital period? Group of answer choices Dean Sam Since they both have circular orbits, they will have the same orbital periods. There isn't enough information to tell.
Answer:
The correct answer is Dean has a period greater than San
Explanation:
Kepler's third law is an application of Newton's second law where the force is the universal force of attraction for circular orbits, where it is obtained.
T² = (4π² / G M) r³
When applying this equation to our case, the planet with a greater orbit must have a greater period.
Consequently Dean must have a period greater than San which has the smallest orbit
The correct answer is Dean has a period greater than San
Answer:
According to the law of universal gravitation, any two objects are attracted to each other. The strength of the gravitational force depends on the masses of the objects and their distance from each other.
Many stars have planets around them. If there were no gravity attracting a planet to its star, the planet's motion would carry it away from the star. However, when this motion is balanced by the gravitational attraction to the star, the planet orbits the star.
Two solar systems each have a planet the same distance from the star. The planets have the same mass, but Planet A orbits a more massive star than Planet B.
Which of the following statements is true about the planets?
A.
Planet B will keep orbiting its star longer than Planet A.
B.
Planet A has a longer year than Planet B.
C.
Planet A orbits its star faster than Planet B.
D.
Planet B is more attracted to its star than Planet A.
Explanation:
You fly your 15 m spaceship, parallel to the ship's length with a speed of c/3 relative to your friend. How long is your spaceship as observed by your friend?
We are asked to determine the length of a ship whose length is 15 meters. To determine the relative length we will use the following formula:
\(L=L_0\sqrt{1-\frac{v^2}{c^2}}\)Where:
\(\begin{gathered} L=\text{ relative length} \\ L_0=\text{ original length} \\ v=\text{ velocity of the object} \\ C=\text{ speed of light} \end{gathered}\)Now, we substitute the value of the speed as a function of the speed of light:
\(v=\frac{c}{3}\)Substituting we get:
\(L=L_0\sqrt{1-\frac{(\frac{c}{3})^2}{c^2}}\)Now, we distribute the exponent and simplify:
\(L=15m\sqrt{1-\frac{1}{9}}\)Solving the operations:
\(L=14.14m\)Therefore, the length of the spaceship observed by the friend is 14.14 meters.
10. A boy of mass 55kg runs at 12m/s and hops on a 15kg skateboard that was at rest. What is thevelocity of the boy on the skateboard afterwards?
M = mass of the boy = 55kg
V = initial velocity of the boy = 12 m/s
m= mass of stationary skateboard = 15kg
v= velocity os stationary sketeboard= 0 m/s
V' = velocity of the boy on the skateboard after collision
Conservation of momentum:
MV + mv = (M + m) V'
Replacing:
55 kg * 12 m/s + 15 kg *0 = (55 kg+ 15 ) V'
Solve for V´'
660 = 70 V´'
660/70 = V'
V'= 9.42 m/s
the temperature at which the velocity of sound in air is twice its velocity at 15°C
With the use of below formula, at 879 °C, velocity will be double the velocity at 15 °C.
What is the relationship between Velocity and sound ?The velocity of sound waves in air is proportional to the square root of Thermodynamic temperature. That is, V = K\(\sqrt{T}\)
Given that the temperature at which the velocity of sound in air is twice its velocity at 15°C, Let us make use of the formula;
(v2/v1) = √(T2 / T1)
Where
v2 = final velocityv1 = initial velocityT2 = final absolute temperatureT1 = initial temperature.Recall that absolute temperature = °C + 273.
If v2 = 2 × v1 and temperature in degree Celsius = 15°C, then,
Temperature in Kelvin K = 15 + 273 = 288
Substitute all the parameters into the formula
(2 × v1)/v1 = √(T2/288)
2 = √ (T2 /288)
Square both sides
4 = (T2/288)
T2 = 4 × 288
T2 = 1152K
Temperature in degrees Celsius = 1152 - 273 = 879 °C.
Therefore, at 879 °C, velocity will be double the velocity at 15 °C.
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People who do very detailed work close up, such as jewellers, often can see objects clearly at much closer distance than the normal 25 cm. a. What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 8.5 cm
This question is incomplete, the complete question is;
People who do very detailed work close up, such as jewelers, often can see objects clearly at much closer distance than the normal 25 cm.
a) What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 8.50 cm? (Assume the lens-to-retina distance is 2.00 cm.)
b) What is the size in mm of an image of a 8.00 mm object, such as lettering inside a ring, held at this distance? (Include the sign of the value in your answer.) __ mm
Answer:
1) the power in D of the eyes of a woman is 61.7647 D
2) the size in mm of an image of a 8.00 mm object is -1.882 mm
Explanation:
Given the data in the question;
a) power in D of the eyes of woman who can see an object clearly at a distance of only 8.5 cm and the lens-to-retina distance is 2.00 cm,
so
u = 8.5 cm = ( 8.5 / 100 )m = 0.085 m
v = 2.00 cm = ( 2 / 100 )m = 0.02 m
Now, we know that power of lens p = 1 / u + 1 / v
so we substitute
p = ( 1 / 0.085 ) + ( 1 / 0.02 )
p = 11.7647 + 50
p = 61.7647 D
Therefore, the power in D of the eyes of a woman is 61.7647 D
b) What is the size in mm of an image of a 8.00 mm object, such as lettering inside a ring, held at this distance? (Include the sign of the value in your answer.)
we know that;
m = -v / u
we substitute
m = -0.02 / 0.085
m = -0.2353
since H₀ = 8.0 mm
H\(_i\) = m × H₀
H\(_i\) = -0.2353 × 8.0
H\(_i\) = -1.882 mm
the size in mm of an image of a 8.00 mm object is -1.882 mm
Which statement about technology is true?
Technology improves a scientist’s ability to make observations.
Technology does not have any effect on a scientist’s work.
Technology is necessary for scientists to perform experiments.
Technology only helps scientists analyze data and write reports.
Answer:
Technology improves a scientist’s ability to make observation
hope this helps
:D
Answer:
Technology improves a scientist’s ability to make observations.
Explanation:
Which of the following are ways radiation is used?Check all that apply.A.For medical testsB.As ink in a penC.To generate electricityD.To determine the age of a buried animal skull
We will have the following:
The ways radiation is used are:
* For medical tests.
* To generate electricity.
*To determine the age of a buried animal skull.
Pot holder should have high insulation and low _____.
Potholder should have high insulation and low conductivity, therefore the correct answer is the option B
What is insulation?Insulation is a type of material used to create barriers to the transmission of the form of energy which either is in form of heat or electricity.
For outdoor trips in cold weather, several thin layers act as better insulating barriers for heat transfer.
The ability of an electric charge or heat to pass through a material is measured by its conductivity. A material is considered a conductor if it offers very little resistance to the flow of thermal or electric energy.
Thus, Potholders should be highly insulated and have low conductivity, therefore the correct answer is the option B
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your question seems incomplete, the complete question is
To be effective, a pot holder should have low _____. viscosity conductivity malleability density
For the simple harmonic oscillation where k = 19.6
N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v =
(0.808 m/s) sin 8.08t, determine (a) the total energy, (b)
the kinetic and potential energies as a function of time,
(c) the velocity when the mass is 0.050 m from
equilibrium, (d) the kinetic and potential energies at
half amplitude (x = A/2).
a. Total energy is 0.098 J
b. Potential and Kinetic Energies is 0.032 sin^2(8.08t) J
c. Velocity at x is -0.808 sin(8.08t) m/s
d. Potential and Kinetic Energies at x is 0.016 sin^2(8.08t) J
Step by step explanationWe can use the following formulas for the energy, velocity, and potential and kinetic energies of a simple harmonic oscillator:
Total Energy: E = 1/2 k A^2Velocity: v = -ωA sin(ωt)Potential Energy: U = 1/2 k x^2Kinetic Energy: K = 1/2 m v^2where ω = √(k/m) is the angular frequency.
Given that k = 19.6 N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v = (0.808 m/s) sin 8.08t, we can find the values of E, U, and K as follows:
(a) Total Energy:
E = 1/2 k A^2 = 1/2 * 19.6 * 0.1^2 = 0.098 J
(b) Potential and Kinetic Energies:
U = 1/2 k x^2 = 1/2 * 19.6 * (-0.1 cos(8.08t))^2 = 0.098 cos^2(8.08t) J
K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.032 sin^2(8.08t) J
(c) Velocity at x = 0.050 m:
When x = 0.050 m, cos(8.08t) = -0.5, so we have:
v = -ωA sin(ωt) = -ω(0.1) sin(8.08t) = -0.808 sin(8.08t) m/s
(d) Potential and Kinetic Energies at x = A/2:
When x = A/2 = 0.050 m, cos(8.08t) = -0.5, so we have:
U = 1/2 k x^2 = 1/2 * 19.6 * (0.050)^2 = 0.0245 J
K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.016 sin^2(8.08t) J
Note that the sum of potential and kinetic energies at any point in time is equal to the total energy, which is constant.
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What is the approximate value of k when 30 = e^5k?
Answer:
Explanation:
30 = e^5k
ln30 = lne^5k
ln30 = 5k
k = ln30/5
k = 0.68023947...
round to your heart's content.
A model rocket has a mass of 0.2 kg, with a motor that can provide a force of 200 N. A second model rocket is being built with the same motor, but it is being designed to accelerate one-fourth as much as the first rocket.What kind of change can be made in the design to achieve this objective?
brainliest! for a full explanation
We can achieve this design by adding weight to the second rocket, such as by adding a heavier nose cone, fins, or other components.
What kind of change can be made in the design?The first model rocket has a mass of 0.2 kg and is powered by a motor that can provide a force of 200 N.
Using Newton's second law of motion, we can calculate the acceleration of the rocket:
F = ma
where;
F is the force applied to the rocket, m is the mass of the rocket, and a is the acceleration of the rocket.Rearranging the equation, we can solve for the acceleration:
a = F/m
Plugging in the values, we get:
a = 200 N / 0.2 kg
a = 1000 m/s^2
So the first model rocket accelerates at 1000 m/s².
The second model rocket is being designed to accelerate one-fourth as much as the first rocket. This means that its acceleration will be:
a' = 1/4 * a
a' = 1/4 * 1000 m/s²
a' = 250 m/s²
So we need to design the second rocket so that it accelerates at 250 m/s².
We can use the same motor, so the force applied to the rocket will still be 200 N. Therefore, we need to change the mass of the rocket to achieve the desired acceleration.
Using the equation for acceleration, we can solve for the mass needed to achieve an acceleration of 250 m/s²:
a' = F/m'
250 m/s² = 200 N / m'
m' = 200 N / 250 m/s^2
m' = 0.8 kg
So the mass of the second rocket needs to be 0.8 kg in order to achieve an acceleration of 250 m/s² with the same motor.
Thus, we can achieve this by adding weight to the second rocket, such as by adding a heavier nose cone, fins, or other components. Alternatively, we could also increase the size of the second rocket while keeping the same mass, which would decrease its acceleration but also increase its overall speed and altitude.
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Amanda runs a business in a market where all firms are price takers. Bob suggests that she lower her price to attract even more customers. Should Amanda follow Bob's suggestion? Should she consider raising her price?
Amanda should carefully consider the elasticity of demand, cost of production, and competition before deciding whether to lower or raise prices. The ultimate goal is to find the right balance between attracting customers and maintaining profitability.
In a market where all firms are price takers, lowering the price may attract more customers, but it may also lead to lower profit margins. It is essential to weigh the potential benefits and costs of lowering the price before making a decision.
Amanda should consider several factors before deciding whether to follow Bob's suggestion or raise her price. These factors may include the elasticity of demand for her products, the cost of production, the pricing strategy of her competitors, and the level of competition in the market.
If the demand for Amanda's products is elastic, meaning that customers are very sensitive to price changes, lowering the price may increase the quantity sold but may not lead to higher revenues. In this case, Amanda may need to consider other strategies to increase revenue, such as expanding her product line or improving the quality of her products.
If the demand for Amanda's products is inelastic, meaning that customers are less sensitive to price changes, lowering the price may lead to increased revenue. However, Amanda should still consider the cost of production and ensure that the lower price still results in a profit.
Raising the price may be a viable option if Amanda has a unique product or a competitive advantage over her competitors. A higher price may signal higher quality or exclusivity, which can attract customers who are willing to pay a premium for the product. However, Amanda should ensure that the price increase does not lead to a significant decline in the quantity sold.
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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when you charge a balloon by rubbing it on your hair this is an example of what method of charging; what happens when you bring the balloon near your hair after rubbing it; static electricity; balloons and static electricity answers; what happens when you touch a metal doorknob after rubbing your shoes on the carpet?; balloon and paper experiment explanation; if you rub a glass rod with a piece of silk, the rod becomes positively charged this means that; why does the balloon stick to the wall
The balloon sticks to wall due to electrostatic force
What is electrostatic force?
Electrostatic forces are attractive or repulsive forces between particles that are caused by their electric charges. This force is also called the Coulomb force or Coulomb interaction and is so named for French physicist Charles-Augustin de Coulomb, who described the force in 1785.
The electrostatic force acts over a distance of about one-tenth the diameter of an atomic nucleus or 10-16 m. Like charges repel one another, while unlike charges attract one another. For example, two positively charged protons repel each other as do two cations, two negatively charged electrons, or two anions. Protons and electrons are attracted to each other and so are cation and anions
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