consider the sequence 11; 5; -1; -7;.... determine the sequence of the nth term of the sequence! PLSSSS HELP​

The probability of obtaining exactly two 6's in four rolls of a fair die is approximately 0.1608, or about 16.08%.

In probability theory, an outcome is the result of a random experiment, such as rolling a die, flipping a coin, or drawing a card from a deck. An outcome can be a single event, such as rolling a 3 on a die, or a combination of events, such as rolling a 1 and then a 4 on two consecutive rolls of a die.

The probability of an outcome is a number between 0 and 1 that measures the likelihood of that outcome occurring. A probability of 0 means that the outcome is impossible, while a probability of 1 means that the outcome is certain. For example, the probability of rolling a 7 on a single roll of a standard die is 0, because there is no face on the die with a 7. The probability of rolling a 1, 2, 3, 4, 5, or 6 is 1/6 each, because each face on the die has an equal chance of showing up.

The probability of obtaining a 6 on a single roll of a fair die is 1/6. The probability of not obtaining a 6 on a single roll is 5/6.

To obtain exactly two 6's in four rolls, we can use the following approach:

So the probability of obtaining exactly two 6's in four rolls of a fair die is approximately 0.1608, or about 16.08%.

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Out of the 400 surveyed students, 327 were either seniors or commuters.

To find the number of students who were either seniors or commuters out of the 400 surveyed students, we need to add the number of seniors and the number of commuters while avoiding double-counting those who fall into both categories.

According to the information given:

There were 262 seniors.

There were 215 commuters.

150 of the seniors were also commuters.

To avoid double-counting, we need to subtract the number of seniors who were also commuters from the total count of seniors and commuters.

Seniors or commuters = Total seniors + Total commuters - Seniors who are also commuters

= 262 + 215 - 150

= 327

Therefore, out of the 400 surveyed students, 327 were either seniors or commuters.

It's important to note that in this calculation, we accounted for the overlap between seniors and commuters (150 students who were both seniors and commuters) to avoid counting them twice.

This ensures an accurate count of the students who fall into either category.

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Answer: 92.50%

From the given problem, we can say that the total volume of the concentration is:

The initial volume of the solution is 555 mL. After the evaporation, the 50% sucrose solution lost 255 mL.

To find the concentration of the remaining 300 mL, we will use the following formula:

Where:

C₁ = initial concentration

C₂ = final concentration

V₁ = initial volume

V₂ = final volume

From the given, we know that:

C₁ = 50% = 0.50

C₂ = ?

V₁ = 555 mL

V₂ = 300 mL

Substitute these to the formula and we will get:

Therefore, we can say that the sucrose concentration in the remaining 300mL is 92.50%

Answer:

The answer is C, 3/4.

Since it is parallel to y=3/4 x+2, 3/4 is the slope for both equations.

The solution of the given expression will be 9/16.

Expressions in maths are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

Given an expression, [-3*(10+(-7))]²÷[(3-(-9)]²

= [-3*(10+(-7))]²÷[(3-(-9)]² = (-9)²/12²

= 9/16

Hence, The solution of the given expression will be 9/16.

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3.1.1 The basic property of operations used is the commutative property of multiplication.

3.1.2 The basic property of operations used is the additive inverse property.

3.1.3 The basic property of operations used is the associative property of addition.

3.1.1 The basic property of operations used in this calculation is the commutative property of multiplication. It states that the order of the factors in a multiplication problem can be rearranged without changing the product. In this case, the numbers 25 and 4 were swapped, resulting in the same product of 100.

3.1.2 The basic property of operations used in this calculation is the additive inverse property. It states that for any number, there exists an additive inverse such that when the number and its additive inverse are added together, the result is zero. In this case, adding 412 and its additive inverse (-412) results in zero.

3.1.3 The basic property of operations used in this calculation is the associative property of addition. It states that the grouping of numbers being added does not affect the sum. In this case, the numbers 25, 37, 20, 5, 30, and 7 were regrouped to facilitate easier mental addition. By grouping 25 and 37, and then grouping 20, 5, 30, and 7, the final sum of 62 is obtained, which is the same as adding all the numbers together in the original order.

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Answer: A. That order is taken into account​ (consider rearrangements of the same items to be different​ sequences).

Step-by-step explanation:

The combination is usually given by the formula below:

C n,x = n! / x! (n-x)!

We should note that the requirements for a combination rule include:

• That r of the n items are selected​ (without replacement).

• That there be n different items available.

• That order is not taken into account​ (consider rearrangements of the same items to be the​ same).

Therefore, the option that is not a requirement of the Combinations​ Rule, ​, for the items that are all​ different will then be option A"That order is taken into account​ (consider rearrangements of the same items to be different​ sequences).

Answer:

156.4 ÷ 23 = 6.8

Step-by-step explanation:

hope this helps

We need to know about quadratic equation to solve the problem. The year when the number of cases will be 50,000 is 2017.

Quadratic equation is an equation that has a maximum degree of two. Quadratic equations always have two roots, it can be solved by factorization method. In this question we have been given a function that we can simplify to get a quadratic equation. We need to find the year when the identity theft cases reach 50,000, we need to equate the equation to 50,000 and then solve the quadratic equation to get x.

f(x)=0.058x+2.175x+340.2\(x^{2}\)-1500x+20000 =340.2\(x^{2}\)-1497.767x+20000

50000=340.2\(x^{2}\)-1497.767x+20000

340.2\(x^{2}\)-1497.767-30000=0

Using Sridharacharya's method,

x=1497.767±\(\sqrt{2243305.99+40824000}\)/680.4=1497.767±6562.56855/680.4

x=11.85 or x=-7.44

Here x cannot be negative, so the right value of x is approximately 12,

year when cases is 50000= 2005+12=2017

Therefore the year when identity theft cases reach 50000 is 2017.

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Answer:

B; There is only one (x,y) solution and y is negative

Step-by-step explanation:

First, I graphed the two equations. Attached is an image of the equations graphed. Next, I looked for overlapping points. Wherever the two points overlap, there is a solution. When looking at the graph, we can see the lines overlap at only one point, (0,-1). Since y is negative, the answer must be B; there is only one (x,y) solution and y is negative.

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Answer:

\(27 \div 6 = 4.50\)

\(18.00 \div 4.50 = 4\)

Each hot dog costs $4.50

You can but 4 hot dogs with $18

Answer:

As a whole, the piece first measured 38 inches. No matter how many times you cut it, all of the pieces will still add up to 38 inches. You know that 19 inches is the length of one of the two pieces, so all you need to find is the other unknown piece. Add the two together, with m being the unknown length.

19+m=38

If you want to solve the equation, just subtract 19 from both sides.

19+m=38

m=19

The correct option is the second one, the interval in which the function is decreasing is [-5, 0]

To identify in which intervals the function is decreasing, we need to find when the function is (when reading from left to right) going downwards.

And trivially, the function is increasing if it goes upwards (again, when reading from left to right).

Here we can see that the intervals in which the function is decreasing are:

[-5, 0] and [2, 4]

The only of thes that appears in the options is the first one, so that is the correct option.

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Answer:

Step-by-step explanation:

y<7<-21

let me know if im right

if not let me know in the comments so i can fix the problem

and help u further

Answer:

Allowance for doubtful account Dr 4850 , To Account receivable Cr 4850

Step-by-step explanation:

Journal Entry                                    Debit    Credit

Allowance for doubtful account    $4850  

To Account receivable                                   $4850

A debit to the allowance for doubtful accounts is to reduce the allowance balance that was previously established and a credit to the accounts receivable is to remove the amount that will not be collected.

For the integral ∫asin(x)dx, use integration by parts ∫udv=uv−∫vdu.

Let u=asin(x) and dv=dx.

Then du=(asin(x))′dx=\(\rm \dfrac{dx}{ \sqrt{1 - {x}^{2} } } \) and v=∫1dx=x

So,

\( \rm{\int{\operatorname{asin}{\left(x \right)} d x}}=\color{h}{\left(\operatorname{asin}{\left(x \right)} \cdot x-\int{x \cdot \frac{1}{\sqrt{1 - x^{2}}} d x}\right)}=\color{h}{\left(x \operatorname{asin}{\left(x \right)} - \int{\frac{x}{\sqrt{1 - x^{2}}} d x}\right)} \\ \)

Let u=1−x2.

Then du=(1−x2)′dx=−2xdx and we have that xdx=−du/2.

The integral can be rewritten as

\( \rm x \operatorname{asin}{\left(x \right)} - \color{g}{\int{\frac{x}{\sqrt{1 - x^{2}}} d x}} = x \operatorname{asin}{\left(x \right)} - \color{j}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}} \\ \)

Apply the constant multiple rule ∫cf(u)du=c∫f(u)du with c=-1/2 and f(u)=\( \frac{1}{ \sqrt{u} } \)

\( \rm x \operatorname{asin}{\left(x \right)} - \color{h}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}} = x \operatorname{asin}{\left(x \right)} - \color{h}{\left(- \frac{\int{\frac{1}{\sqrt{u}} d u}}{2}\right)} \\ \)

Apply the power rule

\( \rm\int u^{n}\, du = \frac{u^{n + 1}}{n + 1} \\ \)

with n=−1/2

\( \rm x \operatorname{asin}{\left(x \right)} + \frac{\color{h}{\int{\frac{1}{\sqrt{u}} d u}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\int{u^{- \frac{1}{2}} d u}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\frac{u^{- \frac{1}{2} + 1}}{- \frac{1}{2} + 1}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\left(2 u^{\frac{1}{2}}\right)}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{h}{\left(2 \sqrt{u}\right)}}{2} \\ \)

\( \rm Recall \: that  \: u=1− {x}^{2} \)

\( \rm x \operatorname{asin}{\left(x \right)} + \sqrt{\color{re}{u}} = x \operatorname{asin}{\left(x \right)} + \sqrt{\color{rd}{\left(1 - x^{2}\right)}} \\ \)

Therefore,

\( \rm\int{\operatorname{asin}{\left(x \right)} d x} = x \operatorname{asin}{\left(x \right)} + \sqrt{1 - x^{2}}+C \\ \)

Answer:14

Step-by-step explanation: both angels are the same aka 41 then solve the equation 2x+13=41. First subtract 13 off both sides of the equations. You’re left with 2x=28 then divide by 2 to find x on its own and get 14.

Answer:

1. x = 14

2. x = 25

3. x = 15

Step-by-step explanation:

Answer:

that would be 3/4

Step-by-step explanation:

Answer:

3/4

Step-by-step explanation:

In the Equation y = mx + b, m represents the constant rate when graphed.

Answer:

I do not have access to Annexure A and Annexure B, so I cannot collect the data, draw the frequency table or pie chart, or answer the last question. However, I can provide a general explanation of how to calculate the mean, mode, median, and range from a set of data.

To find the mean (average) of a set of data, add up all the values in the set and divide by the number of values. For example, if the maximum temperatures of the 30 days are:

25, 28, 29, 27, 26, 30, 31, 32, 29, 27, 26, 24, 23, 25, 28, 30, 32, 33, 34, 31, 29, 28, 27, 26, 25, 24, 23, 21, 20, 22

The sum of the values is:

25 + 28 + 29 + 27 + 26 + 30 + 31 + 32 + 29 + 27 + 26 + 24 + 23 + 25 + 28 + 30 + 32 + 33 + 34 + 31 + 29 + 28 + 27 + 26 + 25 + 24 + 23 + 21 + 20 + 22 = 813

Dividing by the number of values (30), we get:

Mean = 813/30 = 27.1

To find the mode of a set of data, identify the value that occurs most frequently. In this example, there are two values that occur most frequently, 27 and 29, so the data has two modes.

To find the median of a set of data, arrange the values in order from smallest to largest and find the middle value. If there are an even number of values, take the mean of the two middle values. In this example, the values in ascending order are:

20, 21, 22, 23, 23, 24, 24, 25, 25, 26, 26, 27, 27, 27, 28, 28, 29, 29, 29, 30, 30, 31, 31, 32, 32, 33, 34

There are 30 values, so the median is the 15th value, which is 28.

To find the range of a set of data, subtract the smallest value from the largest value. In this example, the smallest value is 20 and the largest value is 34, so the range is:

Range = 34 - 20 = 14

To create a frequency table for the maximum temperature data, we need to group the data into intervals and count the number of values that fall into each interval. For example, we could use the following intervals:

20-24, 25-29, 30-34

The frequency table would look like this:

Interval | Frequency

20-24 | 4

25-29 | 18

30-34 | 8

To calculate the size of the angles for the pie chart, we need to find the total frequency (30) and divide 360° by the total frequency to get the proportion of each interval in degrees. For example, for the interval 25-29:

Proportion = Frequency/Total frequency = 18/30 = 0.6

Angle = Proportion * 360° = 0.6 * 360° = 216°

We can repeat this calculation for each interval to obtain the angles for the pie chart.

In terms of the last question, it is not clear what is meant by "which data collection best describe the maximum and why?". If you could provide more context or clarification, I would be happy to try to help.

If x denotes the width (in feet) of the billboard, find a function in the variable x giving the area of the printed region of the billboard as a function of x is (150/x - 10)(x - 4).

A billboard designer has decided that a sign should have 5-ft margins at the top and bottom and 2-ft margins on the left and right sides.

x = width of the billboard designer

Total Area including margin = 150 ft^2

Height of the billboard = Area/width

Height of the billboard = 150/x

Before the height of the billboard = (150/x - 5 × 2)

Before the height of the billboard = (150/x - 10) ft

The width of the printed region billboard = (x - 2 × 2)

The width of the printed region billboard = (x - 4) ft

The area of the printed region of the billboard = The width of the printed region billboard × The height of the printed region billboard

The area of the printed region of the billboard = (150/x - 10)(x - 4)

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The complete question is:

A billboard designer has decided that a sign should have 5-ft margins at the top and bottom and 2-ft margins on the left and right sides. Furthermore, the billboard should have a total area of 150 ft^2 (including the margins).

If x denotes the width (in feet) of the billboard, find a function in the variable x giving the area of the printed region of the billboard.

Area as a function of x =

De acuerdo con la información podemos inferir que la población se refiere a los habitantes de la ciudad y la muestra es 40,000 personas.

Para identificar la información faltante debemos tener en cuenta la información del enunciado. En este caso nos dicen que quieren implementar una revista en una ciudad determinada y para identificar los temas de la revista debemos hacer una encuesta.

En este caso, la entrevista se realiza a 40,000 personas por lo que esta sería la muestra debido a que no podríamos realizar la encuesta a cada una de las personas que es habitante de la ciudad.

Nota: Esta pregunta está incompleta. Aquí está la información completa:

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Answer: -2 and 4

Step-by-step explanation:

\(f(x) = \frac{-2x+2}{2x+4}\)            g(x) = -2x+8

Question asks what the domain is if we had f(x) ÷ g(x)

\(\frac{f(x)}{g(x)} = \frac{-2x+2}{2x+4}\)  ÷                  >When dividing fractions, keep the first

                                                      Change the sign, flip the second fraction

\(\frac{f(x)}{g(x)} = \frac{-2x+2}{2x+4} * \frac{1}{-2x+8}\)        

\(\frac{f(x)}{g(x)} = \frac{-2x+2}{(2x+4)(-2x+8)}\)          

> you can never get a 0 on the bottom of division so that is where the exception of what x cannot be.

2x+4 = 0

2x= -4

x =  -2

and

-2x+8 = =

-2x = -8

x = 4

So x cannot be -2 and 4

As per the angle sum property, the interior angles that form the triangle is option

B. 60, 60, 60°

C. 40.50,90°

D. 30.60.90*

Angle sum property

Angle sum property states that the sum of all the interior angles of the triangle is equal to 180 degrees.

Given,

Here we have the list of interior angles

A. 45, 45, 45*

B. 60, 60, 60°

C. 40.50,90°

D. 30.60.90*

E. 90,90°, 45°

F. 90, 90, 90°

Now, we have to find in which for these angle will form the tringle.

As per the definition of the angle sum property, the sum of all the interior angle of the triangle is 180°.

Based on these we have to verify each of the given interior angles,

A) 45 + 45 + 45 = 135

B. 60 + 60 + 60 = 180

C. 40 + 50 + 90 = 180

D. 30 + 60 + 90 = 180

E. 90 + 90 + 45 = 225

F. 90 + 90 + 90 = 270

Therefore, based on these values we have identified that the options (B), (C), and (D) forms the triangle.

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Descartes must be thinking of the number 0.

Now, Let's call the number Descartes is thinking of "x".

Hence, According to the problem, if Descartes multiplies "x" by 9, he gets "x" back. In other words, 9 times "x" is equal to "x".

So we can write this as an equation:

⇒ 9x = x

Now we need to solve for "x". We can start by subtracting "x" from both sides of the equation:

⇒ 9x - x = 0

⇒ 8x = 0

divide both sides by 8 to get:

⇒ x = 0

Thus,  Descartes must be thinking of the number 0.

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Answer:

3rd one.

Step-by-step explanation:

Answer:

4th one

Step-by-step explanation: