ch4+202==>c02+302 what type of chemical reaction

The photon that carries more energy is the blue photon, and it carries around 50% more energy than the average orange photon (590-620 nm). The law used to solve the previous problem suggests that energy is proportional to the frequency of an electromagnetic wave. Thus, the higher the frequency, the higher the energy. The correct option is C.

In electromagnetic radiation, the energy carried by each photon is directly proportional to the frequency and inversely proportional to the wavelength. Thus, higher frequency photons carry more energy than lower frequency photons.

A photon's energy is directly proportional to its frequency and inversely proportional to its wavelength. Thus, higher frequency photons, such as blue photons, carry more energy than lower frequency photons, such as orange photons. The energy of a photon is given by the equation: E = hf

Where E is energy, h is Planck's constant (6.63 x 10⁻³⁴ J s), and f is frequency.

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Nasser and Buti are liable for the debts and other financial obligations of their company under the Commercial Companies Law of UAE.

Article 73 states that a partner in a partnership company is jointly liable with the company for the company's obligations. Hence, both the partners are responsible for the debts and obligations of the company.

2. No, the appointment of Ahmad, a non-partner, as a manager of the company was not in accordance with the law. Article 154(1) states that a manager must be a partner in the limited liability company or a shareholder in a public joint-stock company. As Ahmad is not a partner, his appointment as a manager is not valid.

3. Victor's liability for debts and other financial obligations of the company is limited as he is a shareholder of the company and not a partner. Article 72 states that the liability of a shareholder is limited to the value of the shares that he holds. Therefore, Victor's liability is limited to the value of his shares.

4. Yes, Viktor has acted in contravention of the law by performing managerial duties and entering deals on behalf of the company. Article 154(2) states that a manager must not perform any activities that are not related to the company's business or have the potential to cause harm to the company. By performing managerial duties and entering deals on behalf of the company, Viktor has violated this provision.

5. Yes, Ahmad violated the law by withdrawing the 50,000 AED from the company's account. Article 172(1) states that a manager must not withdraw any amount from the company's account without the approval of the general assembly. As Ahmad withdrew the amount without the approval of the general assembly, he violated the law.

6. Yes, Ahmad's dismissal was lawful and in accordance with the law. Article 159 states that a manager can be dismissed by a resolution of the general assembly. As Ahmad was dismissed by a resolution of the general assembly, his dismissal was lawful.

7. Global Domination LLC has joined the company as a shareholder. The transfer of shares is considered effective as per Article 83, which states that the transfer of shares is effective from the date of registration in the commercial register.

Incomplete question :

Answer the following questions with specific reference to relevant Articles of the Commercial Companies Law: 1. What is the liability of Nasser and Buti for the debts and other financial obligations of their company? (2 points)

2. Was the appointment of Ahmad, a non-partner, as a manager of the company in accordance with the law? (1 point)

3. What is Victor's liability for debts and other financial obligations of the company? ( 2 points)

4. Has Viktor acted in contravention of the law by performing managerial duties and entering deals on behalf of the company? (1 point)

5. Did Ahmad violate any rules by withdrawing the 50,000 AED from the company's account? (1 point)

6. Was Ahmad's dismissal lawful and in accordance with the law? (1 point)

7. In what capacity has Global Domination LLC joined the company? Is the transfer of shares considered effective? (2 points)

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Answer:

an ideal gas does not exist except as a conceptual notion, an ideal. Physicists and chemists idealized the behaviour of real gases so that they could explain these phenomena. Under conditions of low pressure and high temperature, all gases behave like real gases, even gases such as UF6 .

Answer:

True

Explanation:

Answer:

London dispersion forces

Explanation:

The London dispersion force is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.

Answer:

The Greeks called these particles atomos, meaning indivisible, and the modern word “atom” is derived from this term. Democritus proposed that different types and combinations of these particles were responsible for the various forms of matter.

Explanation:

hope it helps

The idea of indivisibility of the atom upheld by Dalton was largely derived from early Greek philosophers.

John Dalton was the first scientist to begin an empirical study of atomic theory. Before this time, all that was known about the atom were largely based on the speculation of Greek philosophers.

However, one recurring theme among Greek philosophers is that atoms are indivisible. This idea that atoms are indivisible became a very strong pivot of the Dalton's theory of the atom.

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Answer:

Organic chemistry

Explanation:

Organic chemistry is part of the chemistry that studies carbon compounds, which also use organic compounds, which have characteristics.

Answer: the mole

Explanation:

The mole is the unit of amount in Chemistry.

It provides a bridge between the atom and the macroscopic amounts of material that we work with in the laboratory.

The volume of CO₂ generated under condition of STP in the reaction :

CaCO₃   +  2HCl   ----->   CaCl₂   +   H₂O   +   CO₂ is  12.5 mL.

The reaction is given as :

CaCO₃   +  2HCl   ----->   CaCl₂   +   H₂O   +   CO₂
mass of CaCO₃  = 750 mg = 0.75 g

molarity of HCl = 0.100 M

volume of HCl = 25 mL = 0.025 L

moles of CaCO₃  = 0.75 / 100

                            = 0.0075 mol

moles of HCl = 0.100 × 0.025

                       = 0.0025 mol

here HCl is limiting reagent , formation of CO₂ depends on HCl

2 moles of HCl = 1 mole of CO₂

0.0025 mol of HCl = 0.0025 / 2

                               = 0.00125 mol

volume of CO₂ = moles / molarity

                          = 0.00125 / 0.100

                         = 0.0125 L = 12.5 mL

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A battery is a device that converts chemical energy into electrical energy through a process known as an electrochemical reaction.

When a battery is connected to a circuit, the electrochemical reaction causes a flow of electrons from the anode to the cathode, generating an electric current that can power a device.

The metal chosen for the anode must be capable of losing electrons easily, while the metal chosen for the cathode must be capable of accepting electrons. The choice of metals can also affect the voltage and capacity of the battery, as well as its overall efficiency.

In general, the metals used in a battery should have a large difference in their electronegativity values, which determines how easily an atom can attract electrons. Common metals used in batteries include zinc, lithium, nickel, and cadmium.

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The entropy change of the universe is zero, which is consistent with the second law of thermodynamics. Therefore, the entropy of the universe remains constant or the change in entropy is zero.

Answer:AScoffee = -1.71 J/K, ASroom = 1.71 J/K, ASuniverse = 0.

According to the second law of thermodynamics, entropy of an isolated system always increases. In the given question, we need to calculate the entropy change of coffee, room, and universe. Let's solve this problem.

Given: Mass of coffee = 170 g (density of water = 1 g/cm³)

Specific heat of coffee = specific heat of water = 4.18 J/(g·°C)

Temperature of coffee = 88°C

Temperature of room = 20°C

The initial temperature of coffee = 88°C

The final temperature of coffee = 20°C

Change in temperature of coffee (ΔT) = final temperature - initial temperature = 20°C - 88°C = -68°C

Let's calculate the entropy change of coffee. Entropy change of coffee:

AScoffee = -[170 g/(1000 g/1 kg)](4.18 J/(g·°C))ln[(20°C + 273 K)/(88°C + 273 K)]

AScoffee = -[0.17 kg](4.18 J/(g·°C))ln(293 K/361 K)

AScoffee = -1.71 J/K

Now, let's calculate the entropy change of the room. The change in entropy of the room would be equal and opposite to the change in entropy of coffee (based on the principle of energy conservation).

ASroom = -AScoffeeASroom = 1.71 J/K

The entropy change of the universe would be the sum of entropy change of coffee and entropy change of the room.

ASuniverse = AScoffee + ASroomASuniverse = -1.71 J/K + 1.71 J/KA

Suniverse = 0

The entropy change of the universe is zero, which is consistent with the second law of thermodynamics. Therefore, the entropy of the universe remains constant or the change in entropy is zero.

Answer:AScoffee = -1.71 J/K, ASroom = 1.71 J/K, ASuniverse = 0.

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Explanation:

to see how a change in a reactant concentration would affect the speed of the chemical reaction

Answer:

D: Chlorine( I may be wrong my chemistry year was a nightmare)

The awnser is chlorine (Cl) trust me

Answer:

Here is ur answer...

Explanation:

2) Half-filled d orbital increases the stability of the element.

Answer:

3, 4 ,1

Explanation:

Answer: The energy changes that occur during a chemical reaction can be shown in a diagram called a potential energy diagram, or sometimes called a reaction progress curve. A potential energy diagram shows the change in potential energy of a system as reactants are converted into products.

Explanation:

Answer:

It shows whether the reaction is exothermic or endothermic.

Explanation:

Answer:

A-L

Explanation:

Since before the change, the substance is described as having atoms "close together" and "cannot slide past one another", one can assume this is a solid, since in both liquids and gases, the atoms can move around more or less freely.

Then, it explains that the new substance "can fill a container", which is a property of both a liquid and a gas.

Thus, the answer would be either P, solid to liquid, or L, solid to gas.

Since P is not an option you can choose, by process of elimination, that leaves L, or option A.

Have a nice day! ^-^

Answer:

A-L

Explanation:

i took the test

hope this helps

First 30

Hydrogen

Helium

Lithium

Beryllium

Boron

Carbon

Nitrogen

Oxygen

Fluorine

Neon

Sodium

Magnesium

Aluminum

Silicon

Phosphorus

Sulfur

Chlorine

Argon

Potassium

Calcium

Scandium

Titanium

Vanadium

Chromium

Manganese

Iron              

Cobalt

Nickel

Copper

Zinc  

75

Answer:

The rest after that first 30.

Explanation:

Gallium

Germanium

Arsenic

Selenium

Bromine

Krypton

Rubidium

Strontium

Yttrium

Niobium

Molybdenum

Technetium

Ruthenium

Rhodium

Palladium

Silver

Cadmium

Indium

Tin

Antimony

Tellurium

Iodine

Xenon

Cesium

Barium

Lanthanum

Cerium

Praseodymium

Neodymium

Promethium

Samarium

Europium

Gadolinium

Terbium

Dysprosium

Holmium

Erbium

Thulium

Ytterbium

Lutetium

Hafnium

Tantalum

Tungsten

Rhenium

Osmium

Iridium

Platinum

Gold

Mercury

Thallium

Lead

Bismuth

Polonium

Astatine

Radon

Francium

Radium

Actinium

Thorium

Protactinium

Uranium

Neptunium

Plutonium

Americium

Curium

Berkelium

Californium

Einsteinium

Fermium

Mendelevium

Nobelium

Lawrencium

Rutherfordium

Dubnium

Seaborgium

Bohrium

Hassium

Meitnerium

Darmstadtium

Roentgenium

Copernicium

Nihonium

Flerovium

Moscovium

Livermorium

Tennessine

Oganesson

(e) (i) Number average (Mn) = 6,900g/mol

(ii) Mn will remain the same in this case as it does not depend on weight.= 6,900g/mol

(iii) The degree of polymerization (DP) is 4492.

(i) Number average (Mn)

The number average molecular weight (Mn) is the sum of the molecular weights of all polymer chains divided by the total number of polymer chains.

Weight average (Mw)

The weight average molecular weight (Mw) is the sum of the product of the molecular weight and the fraction of the total polymer chains that have that molecular weight.

Using the given formula, let's first calculate the Mn:

(2100 + 6600 + 12000) / 3 = 6,900g/mol

Let's now calculate the Mw:

[(2100 x 2100) + (6600 x 6600) + (12000 x 12000)] / (2100 + 6600 + 12000)= 9966.67g/mol

(ii) Equal weights of chains

Mn will remain the same in this case as it does not depend on weight.

Mw, on the other hand, will change.

The following formula will be used:

2100 x (1/3) + 6600 x (1/3) + 12000 x (1/3) = 6,900g/mol

(iii) The degree of polymerization (DP)

DP refers to the number of repeating units in the polymer chain.

We can calculate the DP using the following formula:

DP = (Mn / M) * NA where M is the molar mass of the repeating unit, and NA is Avogadro's number.

Using the Mn value from part (i) and the given molecular weights for the repeating units, we can calculate the DP:

DP = (6,900 / ((126 + 324 + 300) / 3)) * 6.02 × 1023= 4492.45 (approximately 4492)

Therefore, the degree of polymerization is 4492.

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The weight average molecular weight (Mw) of the polymer will be \($$M_w=\frac{1\times2100^2+1\times6600^2+1\times12000^2{1\times2100+1\times6600+1\times12000}=8,580\;g/mol$$\).

Weight average molecular weight (Mw) of the polymer will be \($$M_w=\frac{1.0587\times2100^2+1.0587\times6600^2+1.0587\times12000^2{1.0587\times2100+1.0587\times6600+1.0587\times12000}=8,825\;g/mol$$\).

The degree of polymerization of the polymer in the first question is 25.01.

Number average (Mn) and weight average (Mw) molecular weights of a polymer are calculated using the following formula:

\($$M_n = \frac{\sum N_iM_i}{\sum N_i}$$\)

and

\($$M_w = \frac{\sum N_iM_i^2}{\sum N_iM_i}$$\)

where Ni is the number of chains with molecular weight Mi.

(i) When the number of chains with molecular weights of 2100, 6600, and 12000 are mixed together:

Molecular weight (M) Number of chains (N) 2100 1 6600 1 12000 1

Total 3

The number average molecular weight (Mn) of the polymer will be:

\($$M_n=\frac{1\times2100+1\times6600+1\times12000}{1+1+1}= 6,900\;g/mol$$\)

The weight average molecular weight (Mw) of the polymer will be:

\($$M_w=\frac{1\times2100^2+1\times6600^2+1\times12000^2}{1\times2100+1\times6600+1\times12000}=8,580\;g/mol$$\)

(ii) When the equal weights of chains are mixed together:

The total weight of the chains is:

2100 + 6600 + 12000 = 20,700 g

Number of chains with molecular weight 2100 = 2100 x n1

Number of chains with molecular weight 6600 = 6600 x n2

Number of chains with molecular weight 12000 = 12000 x n3

So, the total weight of each group of chains will be

n1M1 + n2M2 + n3M3.

Now, we can calculate the values of n1, n2, and n3 as follows:

n1 = 6600 x n2n2 = 12000 x n3M1 + M2 + M3 = 2100 + 6600 + 12000 = 20700n1M1 + n2M2 + n3M3 = 20700

Equating the value of n1 in terms of n2 and n3 and substituting it in the equation above:

n1 = 6600 x n2

\($$\frac{6600}{n1}=n2$$\)

\($$\frac{12000}{n2}=n3$$\)

\($$n1=\frac{20700}{2100+6600+12000}=0.1739$$\)

n2 = 0.0208, n3 = 0.0052

Therefore, the number of chains with molecular weight 2100 = 0.1739 x 2100 / 6600 x 0.1739 x 6600 = 0.0208 x 12000 / 6600 x 0.0208 x 6600 = 0.0052 x 2100 / 6600 x 0.0052 x 12000 ≈ 1.0587

Number average molecular weight (Mn) will be:

\($$M_n=\frac{1.0587\times2100+1.0587\times6600+1.0587\times12000}{1.0587+1.0587+1.0587}= 7,170\;g/mol$$\)

Weight average molecular weight (Mw) of the polymer will be:

\($$M_w=\frac{1.0587\times2100^2+1.0587\times6600^2+1.0587\times12000^2}{1.0587\times2100+1.0587\times6600+1.0587\times12000}=8,825\;g/mol$$\)

(iii) The degree of polymerization (DP) of the polymer in the first question will be:

Number of chains with molecular weight 2100 = 1

Number of chains with molecular weight 6600 = 1

Number of chains with molecular weight 12000 = 1

The molecular weight of the repeating units of the three different chains have molecular weights of 126, 324, and 300 respectively.

Therefore, the degree of polymerization (DP) of the polymer in the first question will be:For 2100 chain,

\($$n_1=\frac{2100}{126}=16.67$$\)

For 6600 chain,

\($$n_2=\frac{6600}{324}=20.37$$\)

For 12000 chain,

\($$n_3=\frac{12000}{300}=40.00$$\)

So, the average degree of polymerization (DP) is:

\($$DP=\frac{1\times16.67+1\times20.37+1\times40.00}{1+1+1}=25.01$$\)

Therefore, the degree of polymerization of the polymer in the first question is 25.01.

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Answer:

I think its a and c

Explanation:

im smrt

The absence of a positive indication signifies that the system's compressor was functional. As a result, the compressor's work is 15.0 Kcal.

The system loses energy when the corresponding PV work has a negative sign. The work performed by the system is negative if the volume grows at constant pressure (V > 0), which shows that the system has expended energy by working on its surroundings.

The heat extracted from the freezer less the heat discharged via the condenser is the work done by the compressor:

work = heat removed - heat released

= 40.0 Kcal - 55.0 Kcal

= -15.0 Kcal.

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Answer:

C

Explanation:

Water freezes from the TOP DOWN. An example can be when you take the ice thingy container and when you pour water into it to form an ice cube for your drink leave it for a couple of minutes, it’ll freeze from the top and it can be easily break when u compress on it by your finger.

A is possible. But, it’s wrong.

In addition, the density of water is more than ice. Which allows the ice float ontop of the water.

Option B is incorrect.

When liquid water is cooled, it contracts like one would expect until a temperature of approximately 4 degrees Celsius is reached. After that, it expands slightly until it reaches the freezing point, and then when it freezes it expands. (When water reaches 0 °C it turns into an ice cube so, the ice cube has a higher volume than water)

C is possible, too.

D is wrong.

Answer: isopropyl alcohol

Density approximately 6.5 lb / gal. Used in making cosmetics, skin and hair preparations, pharmaceuticals, perfumes, lacquer formulations, dye solutions, antifreezes, soaps, window cleaners. Sold in 70% aqueous solution as rubbing alcohol.

Explanation:

Answer:The addition of OH- to the solution would shift the equilibrium to the left, resulting in a decrease in [NH4+] and [OH-]. Therefore, option B is correct.

Answer:

THE NEW VOLUME OF THE GAS SAMPLE IS 40 L AT 1 atm AND 400 K

Explanation:

Using general gas equation which combines Boyle's and Charles' law, the volume of the gas sample at the new pressure and temperature can be obtained.

P1V1/T1 = P2V2/T2

P1 = Initial pressure = 2 atm

V1 = Initial volume = 15 L

T1 = Initial temperature = 300 K

P2 = Final pressure = 1 atm

T2 = Final temperature = 400 K

V2 = Final volume = unknown

Substituting the values into the equation, we have;

V2 = P1V1T2 / P2 T1

V2 = 2 * 15 * 400 / 1 * 300

V2 = 12 000/ 300

V2 = 40 L

The new volume after the pressure was reduced to 1 atm and the temperature increased to 400 K is 40 L.

Answer:

The volume will also decrease.

Explanation:

This illustration clearly indicates Boyle's law.

Boyle's law states that the volume of a fixed mass of gas is directly proportional to the absolute temperature, provided the pressure remains constant. Mathematically, it is represented as:

V & T

V = KT

K = V/T

V1/T1 = V2/T2 =... = Vn/Tn

Where:

T1 and T2 are the initial and final temperature respectively, measured in Kelvin.

V1 and V2 are the initial and final volume of the gas respectively.

From the illustration above, the volume is directly proportional to the temperature. This implies that as the temperature increases, the volume will also increase and as the temperature decreases, the volume also will decrease.

Answer:

https://socratic.org/answers/220339

this is the answer , my grandpa create this page

Explanation:

Answer: yes but usally to Doujinshi

Explanation:cause it’s better then Real stuff I guess

Answer:

boy noooooo

Explanation: