can you answer one of the questions

Answer:

Hawaii is my best guess! I'm not 100% sure tho, but I'm pretty sure its Hawaii (And i think i spelled it wrong lol) :) Hope this helps!

Explanation:

Underwater is the answer to the question

so hawii ima guess. i looks

The maximum angle due to angular momentum measured from vertical, does the rod (with the attached ball of clay) rotate is 57°.

Given that,

Mass of the rod, \(\small M= 80\;g=0.08\; kg\)

Mass of the clay ball, \(\small m=11\;g=0.011\;g\)

Length of the rod, \small\(L=35\;cm=0.35\;m\)

Initial speed of the ball, \(\small v_{i}=2.3\;m/s\)

From law of conservation of angular momentum, Total initial angular momentum of the system = total final angular momentum of the system\(\small mv_{i}\frac{L}{2}=\frac{1}{2}(I_{rod}+I_{ball})\omega_{f}\small mv_{i}L=(I_{rod}+I_{ball})\frac{V_{f}}{(L/2)}\).

\(\small mv_{i}L=\left (\frac{1}{12}ML^{2}+m\left (\frac{L}{2} \right )^{2} \right )\frac{V_{f}}{(L/2)}\)

Now, From law of conservation of energy, Initial rotational kinetic energy = final potential energy:

\(\small \frac{1}{2}(I_{rod}+I_{ball})\left (\frac{V_{f}}{(L/2)} \right )^{2}=m(L/2)g(1-\cos\theta)\)

\(\small \frac{1}{2}\left (\frac{1}{12}ML^{2}+m\left (\frac{L}{2} \right )^{2} \right )\left (\frac{V_{f}}{(L/2)} \right )^{2}=m(L/2)g(1-\cos\theta)\)

\(\small \left (\frac{1}{12}M+m\left (\frac{1}{2} \right )^{2} \right )\left (\frac{V_{f}}{(1/2)} \right )^{2}=mLg(1-\cos\theta)\)

\(\small \therefore \theta=\cos^{-1}\left (0.5496 \right )\small \boldsymbol{\therefore \theta=56.66^{o}}\)

ROUNDING TO 2 SIGNIFICANT FIGURES

\(\small \boldsymbol{\therefore \theta=57^{o}}\)

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Answer:

necessary for the growth, development and repair of all body tissues. it's involved in many body functions, including formation of collagen, absorption of iron, the proper functioning of the immune system, wound healing, and the maintenance of cartilage, bones, and teeth.

Explanation:

Answer:

Vitamin C act as antioxidant which protect our cell from damaging caused by radicals.

Therefore, the velocity of the ball just before it hits the ground is approximately 22.1 m/s. Therefore, the closest value to this option is 21.0 m/s.

When a ball of mass 0.25 kg falls from a height of 50 m, we can calculate its velocity using the principle of conservation of energy. According to this principle, the sum of the potential and kinetic energy of an object remains constant.

Therefore, we can equate the potential energy at the initial height to the kinetic energy at the final velocity.Let's calculate the potential energy of the ball at the initial height

:Eg = mghEg = 0.25 kg × 9.81 m/s² × 50 m

Eg = 122.625 J

This is the energy that the ball has due to its position. As it falls, this energy is transformed into kinetic energy. At the moment the ball reaches the ground, all the potential energy has been transformed into kinetic energy

.Ek = 1/2mv²Ek = Egv² = 2Ek/mv = √(2Ek/m)

Let's plug in the values we obtained:Eg = 122.625 Jm = 0.25 kgv = √(2Ek/m)

We obtain:v = √(2 × 122.625 J / 0.25 kg)v = √(245.25 J/kg)v = 22.116 m/s

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Using lens equation:

Answer:

1.21 cm

Answer:

P.E = 25.48 Joule

Explanation:

Here,

mass (m) = 2kg

height (h) = 1.3m

g = 9.8m/s^2

P.E = mgh

= (2) (9.8) (1.3)

P.E = 25.48 Joule

Thus, the potential energy of a 2kg plant that is on a windowsill 1.3m high is 25.48 Joule

-TheUnknownScientist

False

Sound actually travels faster through warm, less dense air compared to cold, denser air. In general, sound waves propagate faster in mediums with higher temperatures because the molecules in warmer air are more energetic and have higher velocities.

This increased molecular motion allows sound waves to travel more quickly. Conversely, in colder air, the slower molecular motion results in a slower speed of sound propagation.

Certainly! The speed of sound is influenced by the properties of the medium through which it travels, such as temperature, density, and elasticity. When it comes to air, temperature has a significant impact on the speed of sound.

In warmer air, the molecules have higher kinetic energy, which means they move more quickly and collide with each other more frequently. This increased molecular motion results in a faster speed of sound propagation.

The higher temperature leads to increased molecular velocities, allowing sound waves to travel faster.

On the other hand, in colder air, the molecules have lower kinetic energy, resulting in slower molecular motion and fewer collisions. The reduced molecular velocity in colder air leads to a slower speed of sound propagation.

Density also plays a role in the speed of sound, but its effect is secondary to temperature. In general, sound travels faster in less dense mediums. Cold air tends to be denser than warm air due to the increased molecular packing caused by lower temperatures.

However, the impact of density on sound speed is relatively small compared to the influence of temperature.

Sound actually travels faster through warm, less dense air because the higher temperature results in greater molecular velocities, promoting faster sound wave propagation.

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Asteroids are made up of metals and rocky material, while comets are made up of ice, dust and rocky material. Both asteroids and comets were formed early in the history of the solar system about 4.5 billion years ago.

Answer: Traveling wave

Explanation:

The proper use of the friction zone enhances control and maneuverability in various riding situations, including starting on a hill, searching ahead, making quick stops, and changing lane positions through curves.

The proper use of the friction zone refers to the skillful manipulation of the clutch on a motorcycle to control the engagement and disengagement of power to the rear wheel. By understanding and effectively utilizing the friction zone, riders can enhance their control over the motorcycle's acceleration, deceleration, and overall maneuverability.

Among the options provided, the use of the friction zone is particularly beneficial in situations where precise control and smooth transitions are necessary. Let's examine each option in detail:

a. Start out on a hill: When starting out on an uphill slope, the friction zone allows riders to gradually engage the power while releasing the clutch, preventing the motorcycle from rolling back. By carefully managing the clutch and throttle, riders can find the optimal balance between power delivery and clutch engagement, ensuring a smooth and controlled start.

b. Search ahead: The friction zone enables riders to maintain a moderate level of power while keeping the clutch partially engaged. This allows them to better scan the road ahead, assess potential hazards, and react promptly. By controlling the power delivery through the friction zone, riders can maintain a comfortable speed and stay prepared for any necessary maneuvers.

c. Make a quick stop: When approaching a sudden stop, skilled riders can use the friction zone to disengage the clutch smoothly, preventing the motorcycle from lurching forward or stalling. By modulating the clutch and gradually applying the brakes, riders can come to a controlled stop without sacrificing stability.

d. Change lane position when riding through a curve: In a curve, the friction zone allows riders to adjust their speed and control their line by manipulating the power delivery. By slightly engaging or disengaging the clutch, riders can fine-tune their acceleration or deceleration within the curve, enabling them to position themselves optimally for the desired line and navigate the curve smoothly.

In summary, it provides riders with the ability to manage power delivery and clutch engagement, leading to smoother transitions, improved stability, and overall safer riding experiences.

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The friction zone in a manual vehicle's operation refers to the point where the clutch is partially engaged, aiding in certain maneuvers. In the referenced question, the use of the friction zone can particularly ease the process of starting out on a hill.

The friction zone is a term often used in the context of operating a manual transmission vehicle or motorcycle. It is the gray area wherein the clutch is partially engaged, enabling a connect between the engine and the transmission. This control of power makes certain maneuvers easier.

In the context of this multiple choice question, the proper use of the friction zone makes it easier to: start out on a hill. When on a hill, the friction zone provides the necessary control to prevent the vehicle from rolling backward, making the process of starting smoother and easier.

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The correct option is D. the volume of the ventricle when it is most full.

The volume of the ventricle when it is most full is the most correct description of end-diastolic volume.

It can be defined as the amount of blood in the ventricle immediately before a cardiac contraction or systole occurs. End-diastolic volume is the volume of blood in the ventricles at the end of diastole, after filling with blood from the atria, before the ventricles contract to begin systole.

ventricles are hollow chambers or cavities found in the heart and brain. In the heart, there are two ventricles responsible for pumping blood, while in the brain, there are four interconnected ventricles that produce and circulate cerebrospinal fluid.

Therefore, the correct option is D. the volume of the ventricle when it is most full.

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Answer:

Matter? Atoms? Oxygen Molecules?

Answer:

Recycled answer from jaskhanna07343

Explanation:

Water does not wet waxed surfaces because the cohesive forces within the drops are stronger than the adhesive forces between the drops and the wax. Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water

There are several possible hypotheses for changing the pitch of sound:

Changing the frequency of the sound wave: The pitch of a sound wave is directly proportional to its frequency. Therefore, changing the frequency of the sound wave will change its pitch.

Changing the length of the vibrating object: The length of the vibrating object has an effect on the pitch of the sound wave it produces. If the length is shortened, the pitch of the sound will increase. Conversely, if the length is lengthened, the pitch of the sound will decrease.

Changing the tension in the vibrating object: The tension in the vibrating object affects the pitch of the sound wave it produces. Increasing the tension will raise the pitch of the sound, while decreasing the tension will lower the pitch.

Changing the density of the medium: The density of the medium through which the sound wave travels can also affect the pitch of the sound. If the medium is denser, the pitch of the sound will be higher, and if the medium is less dense, the pitch of the sound will be lower.

Modifying the sound wave through electronic means: The pitch of sound can be changed electronically by using devices such as equalizers, filters, and pitch shifters. These devices modify the frequency of the sound wave, which changes its pitch.

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Answer:

Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.

In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.

Answer:

7 seconds

Explanation:

please see paper!

vf² = vo²+2ad

vf=vo+at

vf²=3.5²+2.2.75

vf²=312.25

vf=17.67 m/s

vf=vo+at

17.67 = 3.5 +2t

t=7.085 s

Answer:

0.900

Explanation:

joules" (and any subsequent words) was ignored because we limit queries to 32 words.

Answer:

See image

Explanation:

Plato

Option (B) many

According to the lesson, it can be said that many adults have some of the same problems with sleep that Bailey does.

Sleeplessness is one of the most common issues, every second adult or a teenager is facing now a days. Due to a lot of responsibilities, we end up having little time for sleep and this in turn affects our body functions.

Good sleep hygiene is often recommended to improve sleep quality, which  also helps in alleviating anxiety due to work load and responsibilities.

Answer is Option (B) many

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Explanation:

F net of sled = Tension force by rope - Kinetic friction between ground.

F normal of sled = mg = (67kg)(9.81kg/m^2) = 657.27N.

Kinetic friction = 0.18 (I cannot see the value) * Normal force of sled = 0.18 * 657.27N = 118.31N

So F net of sled = 800N - 118.31N = 681.69N.

(I cannot see what the question is asking for, please check on your own!)

the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5

Work done by a force is equal to the scalar product of the force applied and displacement. If d displacement happens on applying a force F, then work done, W by the force is

W = F. d

given:

mass, m = 25 kg

height, d = 1.50 m

work has to be done against the weight of the book, F = mg

work done W = F. d

W = mgd

W = (25) ×(9.8)×(1.50)

W = 367.5 J

This work is stored as the potential energy of the book.

Therefore, the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5J

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Answer: 40.2m/sec

Work: v=p/m= 5.83kg/0.145k=40.2cm/sec

Explanation:

According to newtons first law of motion " A body is at a state of rest or uniform motion unless acted upon by a force (external)" which will either

1. change the direction

2. change the acceleration

3. change the velocity(moves or stop the body from moving)

4. change the shape or size

Answer:

c

Explanation:

The position vs. time graph of an object with constant acceleration is a parabolic curve. The curvature is upward for positive acceleration and downward for negative accelerations.

Answer:

C

Explanation:

The relationship between distance and acceleration is dependent of the square of the time the unit is accelerating:  (1/2)*a*t^2, where a is the acceleration and t is the time.  Since the time is squared, and it falls on the x axis, each increse in time produces a squared impact on distance.

Answer:

23 cm from the mirror

Explanation:

Answer:

A) 75m

Explanation:

distance = speed x time taken

Here given:

speed: 15 m/s

time: 5 second

So, distance covered:

15 x 5

75 m

Distance

Answer:

A. 1.71 m

B. 2.66 m

Explanation:

A. Determination of the height of the pier.

We'll begin by calculating the time taken for the ball to get to the water

This can be obtained as follow:

Horizontal velocity (u) = 1.27 m/s,

Horizontal distance (s) = 0.75 m

Time (t) =?

s = ut

0.75 = 1.27 × t

Divide both side by 1.27

t = 0.75 / 1.27

t = 0.59 s

Finally, we shall determine the height of the pier as follow:

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 0.59 s

Height of pier (h) =?

h = ½gt²

h = ½ × 9.8 × 0.59²

h = 4.9 × 0.3481

h = 1.71 m

Thus, the height of the pier is 1.71 m

B. Determination of the horizontal distance.

Horizontal velocity (u) = 4.50 m/s

Time (t) = 0.59 s

Horizontal distance (s) =?

s = ut

s = 4.5 × 0.59

s = 2.66 m

Thus, if the ball moved at a velocity of 4.50 m/s off the pier, it will land at a distance of 2.66 m from the end of the pier.

The frequency of the third harmonic of a string is three times the frequency of the fundamental frequency.

The frequency of the third harmonic of a string is three times the frequency of the fundamental frequency.

The third harmonic is the third standing wave pattern that can be produced on a string. It is produced when a string vibrates at a frequency that is three times the fundamental frequency.

This is also known as the third overtone.

A fundamental frequency is the lowest frequency at which a string vibrates. It is also known as the first harmonic.

When the string vibrates at a higher frequency, it produces higher harmonics or overtones.

The frequency of the second harmonic is twice that of the fundamental frequency, and the frequency of the third harmonic is three times the frequency of the fundamental frequency.

Therefore, the frequency of the third harmonic of a string is three times the frequency of the fundamental frequency.

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Explanation: