can someone please help i will name brainliest

The angular displacement of the baseball as it travels from the pitcher to the catcher is 13.2π radians.

To determine the angular displacement of the curveball as it travels from the pitcher to the catcher, we need to consider the given angular velocity and time.

1. First, we need to convert the angular velocity from revolutions per minute (rev/min) to radians per second (rad/s):
Angular velocity (ω) = 330 rev/min ×(2π rad/rev) × (1 min/60 s) = 22π rad/s

2. Now, we can find the angular displacement (θ) using the formula:
θ = ω × t
where t is the time it takes for the ball to reach the catcher.

3. Plug in the given values:
θ = (22π rad/s) × (0.60 s) = 13.2π rad

The angular displacement of the baseball as it travels from the pitcher to the catcher is 13.2π radians.

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Question 1

T=2*pi*sqrt(m/k) 

dimension of T=sec

dimension of 2*pi=nil(dimensionless)

dimension of m=kg

equation dimension

sec=sqrt(kg/k)

sec^2=kg/k

k=kg/sec^2

so dimension of k will be 

MT^(-2) 

dimension of N/m=kgms^(-2)/m=kgs^(-2) so it is same 

Question 2

F=Gm1*m2/r^2

Dimension of F=MLT^(-2)

MLT^(-2)=G*M*M/L^2

G=ML^3T^(-2)/M^2=M^(-1)L^(3)T^(-2)

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The magnitude of the velocity of the canoe relative to the river that is flowing 0.60 m/s east relative to the earth is 0.71 m/s.

The mаgnitude of the velocity of the cаnoe relаtive to the river cаn be found using the Pythаgoreаn theorem. The Pythаgoreаn theorem stаtes thаt for а right triаngle, the squаre of the hypotenuse is equаl to the sum of the squаres of the other two sides. In this cаse, the hypotenuse is the velocity of the cаnoe relаtive to the river, аnd the other two sides аre the velocity of the cаnoe relаtive to the eаrth аnd the velocity of the river relаtive to the eаrth.

Using the Pythаgoreаn theorem, we cаn find the mаgnitude of the velocity of the cаnoe relаtive to the river аs follows:

\(V_{cr}\) = √(\(V_{ce} ^{2}\) + \(V_{re} ^{2}\))

where \(V_{cr}\) is the velocity of the canoe relative to the river, \(V_{ce} ^{2}\) is the velocity of the canoe relative to the earth, and \(V_{re} ^{2}\) is the velocity of the river relative to the earth.

Plugging in the given values, we get:

\(V_{cr}\) = √((0.38 m/s)² + (0.60 m/s)²)

\(V_{cr}\) = √(0.1444 m2/s² + 0.36 m2/s²)

\(V_{cr}\) = √(0.5044 m²/s²)

\(V_{cr}\) = 0.71 m/s

Therefore, the magnitude of the velocity of the canoe relative to the river is 0.71 m/s.

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Answer:

temperature inside the balloon so it is warmer than the surrounding air

Explanation:

For the balloon to get an uplift , it should be lighter than air . That means the density of the gas inside should be less than the density of air outside . only then ,  weight of the balloon plus the weight of the air inside balloon  will become less than the weight of displaced air outside . This can be achieved by warming up the air inside. Its temperature must exceed that of outside air.

The option that best explain how the pilot can make the balloon rise is option D. The pilot can increase the temperature inside the balloon so it is warmer than the surrounding air

An object will float in air when the density of the object is lower than the density of the air.

Increase in temperature of a gas decreases the density of the gas.

For the pilot to make the balloon rise, he must find a way to make the balloon more lighter than air. To do this, he has to increase the temperature of the balloon.

In this question, the pilot can increase the temperature inside the balloon so it is warmer than the surrounding air in order for the balloon to quickly rise several feet higher above some trees in distance.

Therefore, option D best explain how the pilot can make the balloon rise.

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The correct response would be: "She should place a positively charged rod near the left sphere."

What is Charges?

In physics, charges refer to the fundamental property of matter that gives rise to electric interactions. Charges can be positive or negative, and they are responsible for the phenomenon of electric force, which is the force that acts between charged objects.

By bringing a positively charged rod near the left sphere, it will induce a redistribution of charges in the conductive sphere. The positive charges in the left sphere will repel the positive charges in the rod, causing the electrons in the left sphere to move away from the rod and distribute themselves more evenly across the surface of the sphere, leaving the side facing the rod with a net positive charge.

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The new time it takes for a wave pulse to travel between the ends of the spring is 2.0 s.

The question has to do with period of a stretched spring.

The frequency of a stretched spring is given by f = 1/2L√(T/μ) where

We then find the period

The period of a stretched spring T = 1/f

T = 2L√(μ/T)

We know that the time it takes the wave pulse to travel is the period, T = 1/f

So, T = 2L√(μ/T)

Since T and μ are constant, we have that

T ∝ L

So, T₂/T₁ = L₂/L₁ where

Making T₂ subject of the formula, we have

T₂ = (L₂/L₁)T₁

Substituting the values of the variables into the equation, we have

T₂ = (L₂/L₁)T₁

T₂ = (20 m/10 m)1.0 s

T₂ = (2)1.0 s

T₂ = 2.0 s

So, the new time it takes for a wave pulse to travel between the ends of the spring is 2.0 s.

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To double the rate at which energy is transported by a transverse wave traveling along a string, you should increase the amplitude of the wave by a factor of the square root of 2 (√2).

we'll consider the relationship between the energy transported by a transverse wave traveling along a string and its amplitude. The power (rate of energy transport) of a wave is proportional to the square of its amplitude. Given that you want to double the rate (r) at which the energy is transported, you can use the following steps:
1. Set up the proportionality equation: New Power (2r) = k * (New Amplitude)^{2} where k is the proportionality constant.
2. Since the power is doubled (2r), we can rewrite the equation as: 2r = k * (New Amplitude)^2.
3. Divide both sides by k and r to find the ratio of the new amplitude squared to the original amplitude squared: \frac{(New Amplitude)^{2 }{ (Original Amplitude)^{2}} = 2.
4. To find the factor by which the amplitude should be increased, take the square root of both sides:\frac{ New Amplitude }{Original Amplitude }= √2.

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complete question:

a transverse wave traveling along a string transports energy at a rate r. if we want to double this rate, we could group of answer choices

A. increase the amplitude by a factor of square root of (8)

B. increase the amplitude of the wave by a factor of 8

C .increase the amplitude by a factor of square root of (2).

D. increase the amplitude of the wave by a factor of 2.

E. increase the amplitude of the wave by a factor of 4.

Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alone a horizontal roadway. Therefore,

(a) Cable work: 6,750,000 J horizontally.

(b) Cable work: 6,308,250 J at 35.0° above horizontal.

(c) No work by gravity.

To calculate the work done by the cable in each scenario, we need to consider the angle between the direction of the force applied and the displacement.

(a) If the cable pulls horizontally (0° above the horizontal):

In this case, the angle between the force and the displacement is 0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(0°)

Work = 1350 N * 5000 m * 1

Work = 6,750,000 J

The cable does 6,750,000 Joules of work on the car when it pulls horizontally.

(b) If the cable pulls at 35.0 degrees above the horizontal:

In this case, the angle between the force and the displacement is 35.0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(35.0°)

Work = 1350 N * 5000 m * 0.819

Work = 6,308,250 J

The cable does approximately 6,308,250 Joules of work on the car when it pulls at 35.0 degrees above the horizontal.

(c) The work done by gravity on the car is zero because gravity acts vertically downward, perpendicular to the displacement along the horizontal roadway. Therefore, the gravitational force does not contribute to the work done on the car in this scenario.

In both cases (a) and (b), the cable does the same amount of work on the tow truck as on the car since they are connected by the cable. So the work done by the cable on the tow truck would be equal to the values calculated above: 6,750,000 J in case (a) and 6,308,250 J in case (b).

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Answer:

60 Ns

Explanation:

change in momentum = Fxt

6*10

60 Ns

A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

change in momentum = force . time

change in momentum = 6 . 10 = 60

A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.

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"If the darts are thrown at the same speed then (B) Projectile that travels along trajectory B was projected earlier and (C) Second dart must be projected at angle, such that 0 + 0,8 = 90° is correct."

Initial speed of dart A = u'

Angle of dart A = θ'

Initial speed of dart B = u''

Angle of dart B = θ''

Both darts start out at the same speed,

Thus, u' = u'' = u

The darts are launched one at a time from the same location A, but not simultaneously. However, they cover the same horizontal distance and arrive at B simultaneously.

Since both darts' horizontal ranges are equal,

= [ u²sin(2θ') / g ] =  [ u²sin(2θ'') / g ]

= sin(2θ') = sin(2θ'')

Although θ' is not equal to θ", we can infer that θ" >θ' from the figure.

Since both are acute angles,

= sinθ'' > sinθ'

Multiplying both sides by 2u/g, we get,

= [ 2u X sinθ'' / g ] > [ 2u X sinθ' / g ]

so that the two darts' respective trajectories are as follows:

= T'' > T'.

Thus, statement B and C are correct options.

The given question is incomplete. The complete question is '(A) Projectile that travels along trajectory A was projected earlier (B) Projectile that travels along trajectory B was projected earlier. (C) Second dart must be projected at angle e, such that 0 + 0,8 = 90° (D) Second dart must be projected at angle , >, STA​.'

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The incandescent lamp was a major innovation in the field of lighting, allowing for brighter and more controllable light than previous lighting technologies.

The lamp worked by passing an electric current through a filament, which heated up and emitted light.

Thomas Edison's invention of the incandescent lamp in 1879 was a major breakthrough in lighting technology and had a significant impact on many industries, including theatre, film, and photography.

The incandescent lamp also had a profound effect on society, improving quality of life by enabling longer work hours and increased leisure time and spurring further technological advances in lighting and electricity.

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Answer:

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

Explanation:

Given:

Blue light of wavelength λ1 = 435 nm

n2 in diamond = 2.42

Find:

Wavelength of light in  diamond λ2

Computation:

Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.

So,

n1λ1 = n2λ2

(1)(435) = (2.42)λ2

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

Answer:

180

Explanation:

got it right on acellus

Answer:

Elephant and the eath because Fg is determined by Mass of an object.. So elephant has greater mass therefore, it's Fg is higher

According the universal  law of gravitation, the gravitational force is directly proportional to the mass of an object.  An elephant weighs so much than a man and thus it will experience larger gravitational force from earth.

Gravitational force is a resistive force by which an object attracts other objects towards its centre of mass. The force exerted by the object depends on the mass and the force experienced by the other object depends on its mass and distance between the two objects.

According to universal law of gravitation, the gravitational force is directly proportional to the mass of the object and distance from the ground. The expression for the law is written as:

\(\rm g = G \frac{M_{1} M_{2}}{r^{2}}\)

Where, G is the universal gravitational constant and M1 and M2 be the masses of two objects which and r be the distance between them. As per this relation gravity decreases with increase in distance and increase with an increase in mass.

Therefore, a massive body such as an elephant will experience greater gravitational force from the earth.

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The number of electrons leaving the battery per minute is approximately 1.13 × 10^20.

To determine the number of electrons leaving the battery per minute, we can use the equation:

I = V / R

The current, represented by I, is determined by the voltage, denoted as V, divided by the resistance, symbolized by R.

V = 9.0 V

R = 3.0 Ω

Substituting the values into the equation:

I = 9.0 V / 3.0 Ω = 3.0 A

The current represents the rate of flow of charge, and each electron carries a charge of 1.6 × 10^-19 C. Therefore, the number of electrons leaving the battery per minute can be calculated using the equation:

Number of electrons = I * (1 C / (1.6 × 10^-19 C)) * (60 s / 1 min)

Substituting the values:

Number of electrons = 3.0 A * (1 C / (1.6 × 10^-19 C)) * (60 s / 1 min) ≈ 1.13 × 10^20 electrons

Hence, the number of electrons leaving the battery per minute is approximately 1.13 × 10^20.

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Answer:

true

Explanation:

Answer:

yes

Explanation:

you don't learn it until high school

Answer:

i dont knolw though i am just answeeibg myself this usmy account but i am trsasndfering pout to myself

Explanation:

mkjbjb

The concentration of lithium ions in 0.350 M of Li₃PO₄ is .0245 M for the given molarity .

A solution's molarity (M) is the number of moles of solute dissolved in one litre of solution. To determine a solution's molarity, divide the moles of solute by the volume of the solution in litres: Molarity (M) = moles of soluteliters of solution (molL).Chemists require solution concentrations to be represented in a form that accounts for the amount of particles that react according to a specific chemical equation. Because percentage measurements are either based on mass or volume, they are often ineffective for chemical processes. It is recommended to use a concentration unit based on moles. A solution's molarity (M) is the number of moles of solute dissolved in one litre of solution.

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A circuit that includes lights and batteries has two energy sources: the battery and the light bulb. The batteries provide the energy necessary to operate the light bulbs and make the circuit work. When you connect a light bulb to a battery, an electrical current flows through the circuit, allowing the bulb to light up.

In general, a circuit with lights and batteries works as follows:

When the circuit is closed, the battery's positive and negative terminals are connected by the wires. The current travels through the wires to the light bulb. When the current reaches the light bulb, it encounters the filament, causing it to heat up. The heat makes the filament glow, emitting light as a result. The circuit continues to function as long as the battery has enough energy to keep the filament glowing.

In conclusion, the presence of a battery and a light bulb in a circuit allows it to produce light. The battery provides the energy necessary to keep the filament glowing, resulting in the bulb's illumination.

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The maximum force that the tires can exert on the road before slipping is 16200 N.

From the information in the question;

The coefficient of static friction =  0.9

The mass of the car = 1800 kg

Using the formula;

μ = F/R

μ  = coefficient of static friction

F = force on the tires

R = the reaction force

But recall that the reaction is equal in magnitude to the weight of the car.

W=R

Hence; R = 1800 kg × 10 ms-2 = 18000 N

Making F the subject of the formula;

F = μR

Substituting values;

F =  18000 N × 0.9

F = 16200 N

Hence, the maximum force that the tires can exert on the road before slipping is 16200 N.

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Option a, b, c affects rate of diffusion. The rate of diffusion of a substance is influenced by several factors, including the presence of other solutes, temperature, and concentration gradient.

The presence of other solutes can impede the diffusion of a substance by creating a crowded environment, making it difficult for the substance to move through the medium. T

emperature can also affect the rate of diffusion, as higher temperatures increase the kinetic energy of molecules, making them move faster and facilitating diffusion. Additionally, the concentration gradient plays a crucial role in diffusion as the greater the concentration gradient, the faster the rate of diffusion.

However, the direct supply of metabolic energy (ATP) does not affect the rate of diffusion as diffusion is a passive process that occurs spontaneously down the concentration gradient. The factors affecting the rate of diffusion of a substance include the presence of other solutes (a), temperature (b), and concentration gradient (c).

The presence of other solutes may alter the rate due to interactions or competition for space. Temperature affects the kinetic energy of particles, with higher temperatures leading to increased movement and faster diffusion. The concentration gradient drives diffusion, as substances move from areas of high concentration to areas of low concentration. Direct supply of metabolic energy (d) does not typically impact passive diffusion, but may affect active transport processes in cells.

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If F = 37 N, the static frictional force between the block and the table and the minimum force required to move it must be equal.

It is the force that regulates itself. The value of static friction varies from zero to the smallest force required to initiate motion. The formula for determining static friction is as follows: Normal Force divided by the static friction coefficient is static friction.

Although the maximum static friction will rise, the frictional force will always be the same as the weight in mg because friction cannot accelerate an object. Because FrN can take any value less than N to balance the weight, this is the case.

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The balloon carries approximately 3.23 x 10^13 excess electrons.

To determine the number of excess electrons on the balloon, we need to use the elemental charge and the charge on the balloon.

The elementary charge, denoted e, is the charge carried by a single electron and has a magnitude of approximately 1.6 x 10^-19 coulombs.

The charge on the balloon is given as -5.16 nC (a negative charge indicates an excess of electrons).

To calculate the number of excess electrons, we can divide the charge on the balloon by the elementary charge:

Number of excess electrons = (balloon charge) / (elemental charge)

Number of excess electrons = (-5.16 nC) / (1.6 x 10^-19 C)

Calculation of this distribution:

Number of excess electrons ≈ -3.23 x 10^13 electrons

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Answer:

ok, I have taken that class my 8th-grade year I might be able to help what is the question tho kinda confused about that?

Explanation:

sorry ?

Answer:

Principal, Teacher, Curator, Writer

Explanation:

The minimum duration of the pulse is approximately 3.3 × \(10^{-14\) s.

E = hc/λ

where c is the speed of light. Thus, we can write:

ΔE = hcΔν/λ

We are given that the minimum uncertainty in the energy is 1.0%. Therefore, we can write:

ΔE = 0.01E

where E is the energy of a photon. Substituting the expression for E and rearranging, we get:

Δν = (0.01λ)/(hc)

Now, the duration of an ultrashort pulse is related to its bandwidth (Δν) by the equation:

Δt = 1/(2πΔν)

Substituting the expression for Δν, we get:

Δt = (2πhc)/(0.01λ)

Plugging in the given wavelength of 610 nm, we get:

Δt = (2π × 6.626 × \(10^{-34\) J s × 3.00 ×\(10^8\) m/s)/(0.01 × 610 × \(10^{-9\) m) ≈ 3.3 × \(10^{-14\) s

A pulse refers to a single disturbance that travels through a medium, such as a wave. It is characterized by a localized, brief change in a physical quantity, such as pressure, temperature, or displacement, that propagates through space and time.

For example, when a stone is thrown into a still pond, it creates a pulse that travels through the water as a circular wave. The pulse causes the water molecules to vibrate back and forth, creating a ripple effect. Similarly, when a sound is produced, it creates a pulse of pressure waves that propagate through the air and stimulate the eardrum, enabling us to hear the sound.

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The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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To calculate the strength of the magnetic field at point P in the given figure, we can use Ampere's Law. Ampere's Law states that the line integral of the magnetic field around a closed loop is equal to the product of the permeability of free space (μ₀) and the current enclosed by the loop.

In this case, the loop can be chosen as a circle centered at point P with a radius equal to r2. The current enclosed by the loop is I.

Using Ampere's Law, we have:

∮ B · dl = μ₀ * I_enclosed

Since the magnetic field is assumed to be constant along the circular path, we can simplify the equation to:

B * 2πr2 = μ₀ * I

Solving for B, we get:

B = (μ₀ * I) / (2πr2)

Plugging in the given values:

B = (4π × 10^-7 T·m/A) * (5.6 A) / (2π × 0.028 m)

B ≈ 0.04 T

Therefore, the strength of the magnetic field at point P is approximately 0.04 Tesla.

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An elevated feature near the heel or flanks or a position upwind of the fire affords a good sight line and there is advantage of it as long as there is zero possibility that the fire will go there, which is true statement.

Elevated feature helps to protect the space besides there is a fire present. Elevated feature is the safest and nearest place to not get effected by the fire present in the other side of the elevated feature.

This feature is also created in case of emergency situations to immediately reduce the effect of the fire. This could a technique to reduce the effect of the hazards in the disaster management.

While considering the effect of hazards reduction, there are parameters on which these depends, are shape of elevated feature, elevation of the elevated feature and steepness of the elevated feature.

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