CAN SOMEONE HELP ME PLEASE ASAP!?

Step-by-step explanation:

i am not sure but i guess u could do

4+7= 11

11+x=11x

2+17=19

19+x=19x

gcf = 209 sooo umm..

209 fits into eleven 19 times

209 fits into 19 eleven times

ig thats ur answer

Answer:

16 unidades preparan simultáneamente 1200 empanadas por día.

Step-by-step explanation:

Si cada fuente tiene una capacidad de 75 empanadas por horneada y que la mayor cantidad posible ocurre cuando el volumen de producción se cocina simultáneamente, entonces el total de fuentes es la cantidad total de producción dividida por la capacidad de empanadas por fuente. Es decir:

\(x = \frac{1200\,emp}{75\,\frac{emp}{und} }\)

\(x = 16\,unidades\)

16 unidades preparan simultáneamente 1200 empanadas por día.

Answer:

228

Explain your answer:

Answer:

A = 228 ft²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \(\frac{1}{2}\) h (b₁ + b₂ )

where h is the height and b₁, b₂ the parallel bases

here h = 12 and b₁ = 14, b₂ = 24 , then

A = \(\frac{1}{2}\) × 12 × (14 + 24) = 6 × 38 = 228 ft²

Let's prove the following equality [rv(q^(rp))]=r^(pv¬q) using a series of logical equivalences.

Step 1: \([rv(q^{(rp)})]=r^{(pv¬q)\) (given)

Step 2: \([r v (q ^{ (rp))}] = [r v (q ^{ p}) ^{ (q {^ ¬q}) v (r ^ {p}) ^{ (r ^{ ¬q})} ]\) (distributive law)

Step 3: \([r v (q ^ {p}) ^ {(q ^ {¬q) }v (r{ ^ p}) ^{ (r{ ^ ¬q}})] }= [r v (q ^{ p}) ^ {(F) v (r ^ {p}) ^ {(F)}}}]\)(negation law)

Step 4: \([r v (q ^{ p}) ^{ (F) }v (r ^{ p}) ^ {(F)}] = r v (q ^{ p}) ^{ (r ^ {p})}\) (identity law)

Step 5:\(r v (q ^{ p}) ^{ (r ^{ p{}) = r ^ {(q ^{ p v (r ^{ p})}}})\) (DeMorgan's law)

Step 6:\(r ^ {(q ^ {p }v (r ^{ p})) = r ^{ (p v q)}\) (commutative law)

Step 7: Therefore, \([rv(q^{(rp)})]=r^{(pv¬q)\)is proved.

Answer: By using a series of logical equivalences, \([rv(q^{(rp)})]=r^{(pv¬q)\)is proved.

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The given equation is proved using a series of logical equivalences as follows:

\([rv (q^ {(rp)})] = r^ {(pv¬q)} = ¬[(r V q) ^{ r}] ^ {¬(p V q)} = (r ^{ p})^{¬q\)

Given equation is:

[rv (q^ (rp))] = r^ (pv ¬q)

Let's prove this equation using a series of logical equivalences.

Step 1: Apply Commutative Law.

We know that\(P ^ Q\)≡ \(Q ^ P\) and P V Q ≡ Q V P.

\([rv (q^ {(rp)})] = [(rp) ^ {q}]Vr (1\)\)

So, the equation becomes \([(rp) ^ {q}] V r = r ^ {(pV ¬q)\)

Step 2: Apply Distributive Law.

We know that \(P ^ {(Q V R)\) ≡ \((P ^ Q)\)V\((P ^ R)\) and

P V \((Q ^ R)\)≡\((P V Q) ^ {(P V R)\).\([(rp) ^ q]\)V r = (\(r ^ p\)) V \((r ^ ¬q})\) (2)

Step 3: Apply De Morgan's Law.

We know that ¬\((P ^ Q)\) ≡ ¬P V ¬Q and

¬(P V Q) ≡ \(¬P ^ {¬Q\).(¬r V ¬p\() ^ ¬q\) V r = (\(r ^ p\)) V \((r ^ ¬q})\) (3)

Step 4: Apply Distributive Law on both sides.

\((¬r ^ {¬q} V r) V (¬p ^ {¬q} V r) = (r ^ {p}) V (r ^ {¬q}) (4)\)

Step 5: Apply De Morgan's Law on both sides.

¬(r V \(q ^ r\)) V (\(¬p ^ ¬q\\\) V r) = (\(r ^ p\)) V (\(r ^ ¬q\)) (5)

Step 6: Apply Distributive Law on the left-hand side and get the right-hand side in conjunction.

¬[\((r V q) ^ r\)] V (\(¬p ^ ¬q\)V r) = (\(r ^ p\)) ^ (\(r ^ ¬q\)) (6)

Step 7: Apply Commutative Law. (r V q\() ^ r\) ≡\(r ^ {(r V q)\) by Commutative Law.

\([¬r ^ {¬q V r}] V (¬p ^ {¬q V r}) = (r ^ p) ^ (r ^ ¬q})\) (7)

Step 8: Apply Distributive Law on the right-hand side.

\([¬r ^ {¬q V r}] V (¬p ^ {¬q V r}) = r ^{ (p ^ {¬q})\)(8)

Step 9: Apply De Morgan's Law on both sides. \(¬[(r V q) ^ {r}] ^ {¬(p V q)} = r ^ {(p ^ {¬q})\) (9)

Step 10: Apply Commutative Law.\(r ^ {(p ^ {¬q})} ≡ (r ^ {p}) ^{ ¬q\) by Commutative Law.

\(¬[(r V q) ^ {r}] ^ {¬(p V q)} = (r ^ {p}) ^ ¬q\)(10)

Thus, the given equation is proved using a series of logical equivalences as follows.

\([rv (q^ {(rp)})] = r^ {(pv¬q)} = ¬[(r V q) ^{ r}] ^ {¬(p V q)} = (r ^{ p})^{¬q\)

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Plug the second equation (the one already solved for y) into the first equation

2x - (2x + 3) = 7

2x - 2x - 3 = 7

-3 = 7

Since the 2x's canceled out and left a false statement, this system of equations has no solution.

Hope this helps!

Answer:

Choice B is incorrect

Step-by-step explanation:

Because quadrilateral has a 360-degree sum of all angles, not 180.

The solutions to the system of equations in this problem are given as follows:

We want to obtain the graphic solution for the system of equations, hence we obtain the point of intersection of the two equations.

The equations for this problem are given as follows:

From the graph, we have the intersection points, hence the solutions are given as follows:

The image used for this problem is the graph of the functions given.

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Answer:

e. WWI » 1914

b. Sykes-Picot agreement » 1916

d. Balfour Declaration » 1917

a. WWII » 1945

c. Israel becomes a state » 1948

Step-by-step explanation:

\(.\)

Answer:

I really don't know i need the answer as well

Step-by-step explanation:

Answer:13/16

Step-by-step explanation:trust me bro

Answer:

13/16

Step-by-step explanation:

So what we want to do here is find the smallest common denominator. I personally find 160 the easiest to work with.

7x16=112(numerator for 7/10)

10x16=160(denominator)

This gives us the fraction 112/160.

13x10=130

16x10=160

This gives us the fraction

130/160

Therefore 13/16 is bigger.

Please mark brainliest!

The amount you could save per month would be 25% of your discretionary money.

Discretionary income is the money you have left over after paying taxes and necessary cost-of-living expenses.

The formula for discretionary money is: Discretionary money = Realized income - Fixed expenses. Inputting data, we have: Discretionary money = $3,543.22 - Fixed expenses

Amount to be saved = 25% of discretionary money

Amount to be saved = 0.25 * (Realized income - Fixed expenses)

Therefore, the amount savable is calculated as 0.25 times the difference between your realized income and fixed expenses.

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Answer:

45

Step-by-step explanation:

15 x 3 is 45

Answer:

45 minutes

Step-by-step explanation:

We will use ratios for this question:

\(\frac{15}{2} =\frac{x}{6} \\\\2x=90\\x=45\)

Answer:

324 \(cm^{2}\)

Step-by-step explanation:

Area is the length multiplied by width. In the case of a square, both sides are the same so it would simply be 18 x 18 or \(18^{2}\) which equals 324, but make sure to adds units, \(cm^{2}\). Hope this helps

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Answer:

(a) To the nearest tenth:

π = 3.1, √3 = 1.7, 2√3 = 3.4, √5 = 2.2

(b) √3, √5, π, 2√3

\(F=\dfrac{GMm}{r^2}\\\\Fr^2=GMm\\\\m=\dfrac{Fr^2}{GM}\)

Answer:

A correlation coefficient shows where one variable changes in results to the other. A line of best fit is the best fit line that passes through or near the graphed data. It is used to describe data and predict where new data will appear on the graph. These two methods help to find correlation between variables as they are used to predict how and where variable are and will go in correlation to one another.

Step-by-step explanation:

Answer:

\(\dfrac{1}3\)

Step-by-step explanation:

When rolling a die successively, the probability of rolling a certain number(s) does not change because the die stays the same.

In this problem, we need to find the probability that a die roll will produce a number less than 3. First, we can list out those numbers:

all numbers:

numbers less than 3:

We can see that there are 6 total numbers and 2 numbers less than 3.

Therefore, we can represent the probability of rolling a number less than 3 as:

\(\dfrac{2}{6}\)

\(\boxed{=\dfrac{1}3}\)

First, we'll find the probability that a die is rolled only once.

There are 2 numbers that are less than 3, which are 1 and 2.

This makes the fraction 2/6, or simplified to 1/3.

The probability is 1/3.

Answer:1733.28

square inches I think

Answer:

1733.28 in^2.

Step-by-step explanation:

The radius r = 1/2 the diameter = 1/2 *12 = 6 inches.

SA = 2*3.14*6^2 + 2*3.14*6*40

= 1733.28 in^2.

Answer:

The domain of y = f(x) is [0,8]

Step-by-step explanation:

Since the straight line with negative slope begins on the y-axis at (0. 9) and exits the plane at (8, 1), we get is domain from the minimum and maximum values of x for which the function is valid.

So, the minimum value of x at which the function is valid is x = 0 and the function is y = f(0) = 9.The maximum value of x at which the function is valid is x = 8 and the function is y = f(8) = 1.

So, the domain of the function y = f(x) is [0,8]

Answer:

y = f(x) is [0,8]

Step-by-step explanation:

The length of the guy wire, using similar triangles, is of:

43 feet.

Similar triangles are triangles that share these two features listed as follows:

The height h of the tower can be found using similar triangles, as the two right triangles are similar.

The equivalent measures are given as follows:

Hence the proportional relationship is:

h/7 = 17/3

Applying cross multiplication:

3h = 17 x 7

h = 17 x 7/3

h = 39.67 ft.

Then, applying the Pythagorean Theorem, the length of the guy wire is of:

l² = 39.67² + 17²

l = sqrt(39.67² + 17²)

l = 43 feet. (rounded down).

(the pythagorean theorem is applied as the length of the guy wire is the hypotenuse of the right triangle).

The problem is given by the image at the end of the answer.

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Answer: 4 and -9

Step-by-step explanation:

x(x+5)

The probability that the team won a game if it played at lincoln park is 7/10

Here we have been given that the match is held in 2 locations- Daryl Fields and Lincoln Park

We see that there are a total of 20 matches played out of which 10 are played in Daryl Fields and 10 in Lincoln Park.

We need to find the probability that the team won a game if it played at lincoln park

Let A be the event that the team wins

Let B be the event that the game is played in Lincoln Park

Hence we need to find P(A/B)

Now according to the rule of conditional probability

P(X/Y) = P(X ∩ Y) / P(Y)

Hence P(A/B) = P(A ∩ B) / P(B)

Now P(A ∩ B) implies the number of matches the team won in Lincoln Park

= 7/20

P(B) is the probability of matches played in Lincoln Park = 10/20

Hence P(A/B) = 7/10

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The value of the probability of choosing a green lollipop and a purple lollipop is, 8 / 45

We have to given that;

One bag contains 3 red lollipops and 2 green lollipops.

And, The other bag contains four purple lollipops and five blue lollipops.

Hence, The probability of choosing a green lollipop is,

P₁ = 2 / 5

And, The probability of choosing a purple lollipop is,

P₂ = 4 / 9

Thus, The value of the probability of choosing a green lollipop and a purple lollipop is,

P = P₁ ×  P₂

P = 2/5 × 4/9

P = 8/45

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Answer:

38

Step-by-step explanation:

4x+y2y−x

=4*2+4*2*4-2

=8+32-2

=40-2

=38

Given half-cup of milk. if we find how many  milliliters are there in this cup we get it approximately equal to 120 milliliters.

In cooking and baking, cup measurements are commonly used. However, it's important to note that cup measurements can vary slightly depending on the country or region. In the United States, a standard cup measurement is equal to 240 milliliters.

A half-cup is exactly half of this measurement, which means it would be approximately equal to 240/2 = 120 milliliters. Therefore, option C, 120, is the closest approximation to the number of milliliters contained in a half-cup of milk. It's worth noting that for more precise measurements, it's always advisable to use a kitchen scale or measuring cup with milliliter markings.

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The probability that she is taking a night class = 0.437

According to the information given in the question,

We will be using the concept of Conditional Probability,

According to conditional probability, any event A is determined and derived keeping in mind that the second event B has already occurred.

Seeing the data given in the question,

Now if we see that the total number of sections per day is 7 we could derive that,

⇒ The sections were taken by part-time faculty = Total sections held in a day x % part-time faculty + sections in night class x % part-time faculty.

The sections were taken by part-time faculty = (5 x 40%) + (2 x 60%)

= 2 + 1.2

= 3.2

⇒ Now to calculate the probability of sections taken by the part-time faculty,

P = \(\frac{Number\ of\ sections \ by\ part-time \ faculty}{Total \ number\ of sections\ in\ a\ day }\)

P = \(\frac{3.2}{7}\)

P = 0.457

⇒ The probability that the sections are taken at night and by the part-time faculty = Probability of night section x % of sections taken by part-time faculty.

= \(\frac{2}{6} * 60\) %

= 0.20

⇒ Now the Probability that the class is taken part-time.

=  \(\frac{Probability\ that\ the\ sections\ are\ taken\ at\ night\ and\ by\ the\ part-time\ faculty}{ Probability\ that\ the\ night\ classes\ are\ taken\ by\ part-time\ faculty}\)

= \(\frac{0.20}{0.457}\)

= 0.437

Therefore, the probability that she is taking a night class = 0.437

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