Answer:.
Step-by-step explanation:
A pilot is flying from city A to city B , which is 85 mi due north. After flying 20 mi , the pilot must change course and fly 10° east of north to avoid a cloudbank.
b. How many degrees will the pilot have to turn to the left to fly directly to city B ? How many degrees from due north is this course?
The pilot will have to turn 76.45 degrees to the left to fly directly to city B.
The pilot's course will be 13.55 degrees east of due north.
To determine how many degrees the pilot will have to turn to the left to fly directly to city B, we can consider the triangle formed by city A, city B, and the pilot's current position after flying 20 miles.
In the triangle, the opposite side is the horizontal displacement of 20 miles, and the adjacent side is the vertical displacement of 85 miles.
Therefore, the tangent of θ is given by:
tan(θ) = opposite / adjacent
tan(θ) = 20 / 85
We can use the inverse tangent (arctan) function to find θ:
θ = arctan(20 / 85)
= 13.55 degrees.
To find the number of degrees the pilot will have to turn to the left, we subtract θ from 90 degrees (since the pilot wants to fly due north):
Turn angle = 90 degrees - θ
Turn angle = 90 - 13.55
Turn angle ≈ 76.45 degrees
Therefore, the pilot will have to turn 76.45 degrees to the left to fly directly to city B.
To find how many degrees from due north this course is, we simply subtract the turn angle from 90 degrees:
Degrees from due north = 90 - Turn angle
Degrees from due north = 90 - 76.45
Degrees from due north ≈ 13.55 degrees
Hence, the pilot's course will be 13.55 degrees east of due north.
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f (x) = 3x^2 - 7x - 32
What is the value of f(-4)?
Answer:
f (-4) = 3x(-4)^2 - 7x(-4) - 32 = 44
Step-by-step explanation:
you should replace every x with the number given which is here equals -4
Given the data points below, compute the sum of squared errors for the regression equation Y = 2 + 3X
X 0 3 7
10
Y 5 5 27 31
o
1) What are the squared errors for the regression line given by
Y = 2 + 3X? Type as a comma-separated list: #. #. #. #
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2) What is the sum of squared errors for the regression line give by
Y = 2 + 3X?
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Show answer
Feedback?
Least squares method
The method of least squares derives a linear regression model by minimizing the sum of squared errors. For a sample with n observations,
G
ENG
To compute the squared errors for the regression equation Y = 2 + 3X, we need to calculate the difference between the predicted values (Y) and the actual values (Y) for each data point, and then square those differences.
Given the data points:
X: 0, 3, 7, 10
Y: 5, 5, 27, 31
1) Squared errors for the regression line:
For X = 0:
Error = Y - Y_predicted = 5 - (2 + 3*0) = 5 - 2 = 3
Squared Error = 3^2 = 9
For X = 3:
Error = Y - Y_predicted = 5 - (2 + 3*3) = 5 - 11 = -6
Squared Error = (-6)^2 = 36
For X = 7:
Error = Y - Y_predicted = 27 - (2 + 3*7) = 27 - 23 = 4
Squared Error = 4^2 = 16
For X = 10:
Error = Y - Y_predicted = 31 - (2 + 3*10) = 31 - 32 = -1
Squared Error = (-1)^2 = 1
The squared errors for the regression line are: 9, 36, 16, 1.
2) Sum of squared errors for the regression line:
Sum of squared errors = 9 + 36 + 16 + 1 = 62.
Therefore, the sum of squared errors for the regression line Y = 2 + 3X is 62.
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A backpack that normally sells for $39 is on sale for $25. Find the
percent of change.
Answer: To find the discount, simply multiply the original selling price by the %discount:
ie: 39 x 33/100= $12.87
So, the discount is $12.87.
Step-by-step explanation: To find the sale price, simply minus the discount from the original selling price:
ie: 39- 12. 87= 26.13
So, the sale price is $26.13
write 105/20 as a decimal
Answer:
5.25
Step-by-step explanation:
Answer: 105/20 in decimal = 5.25
Step-by-step explanation: The fraction bar means "divided by" in the fraction 105/20, where 105 is the numerator and 20 is the denominator. As a result, the fraction 105/20 can be written as "105 divided by 20" or "105 20."
We discovered that 105/20 in decimal form is: 105 20 = 5.25 when we divided 105 by 20.
As a result, 105/20 has a decimal form of 5.25.
Hope this helps.
The keys 12,18,13,2,3,23,5 and 15 are inserted into an initially empty hash table of length 10 using open addressing with hash function h(k)=k mod 10 and quadratic probing. What is the resultant hash table? 3.(2 pts) Insert the keys 79, 69, 98, 82, 14, 72, 59 into the Hash Table of size 13. Resolve all collisions using Double Hashing where the first hash-function is h(k)=kmod13 and second hashfunction is g(k)=1+(kmod11) ? The required probe sequences are given by: i
∗
probe =(h(k)+i
∗
g(k))mod TableSize
To determine the resultant hash table using open addressing with quadratic probing, let's go through the steps for each key:
1. Initialize an empty hash table of length 10.
2. Insert the first key, 12, into the hash table. Since h(12) = 12 mod 10 = 2, and the slot at index 2 is empty, we place 12 there.
3. Insert the next key, 18. Since h(18) = 18 mod 10 = 8, and the slot at index 8 is empty, we place 18 there.
4. Insert 13. Since h(13) = 13 mod 10 = 3, and the slot at index 3 is empty, we place 13 there.
5. Insert 2. Since h(2) = 2 mod 10 = 2, and the slot at index 2 is already occupied by 12, we perform quadratic probing to find the next available slot. We start at index 2 and probe using the sequence: 2, 5, 10, 17, 26, ... The next available slot is at index 5, so we place 2 there.
6. Insert 3. Since h(3) = 3 mod 10 = 3, and the slot at index 3 is already occupied by 13, we perform quadratic probing. We start at index 3 and probe using the sequence: 3, 6, 11, 18, 27, ... The next available slot is at index 6, so we place 3 there.
7. Insert 23. Since h(23) = 23 mod 10 = 3, and the slot at index 3 is already occupied by 13, we perform quadratic probing. We start at index 3 and probe using the sequence: 3, 6, 11, 18, 27, ... The next available slot is at index 11, so we place 23 there.
8. Insert 5. Since h(5) = 5 mod 10 = 5, and the slot at index 5 is already occupied by 2, we perform quadratic probing. We start at index 5 and probe using the sequence: 5, 8, 13, 20, 29, ... The next available slot is at index 8, so we place 5 there.
9. Insert 15. Since h(15) = 15 mod 10 = 5, and the slot at index 5 is already occupied by 2, we perform quadratic probing. We start at index 5 and probe using the sequence: 5, 8, 13, 20, 29, ... The next available slot is at index 13, but since the hash table has a length of 10, we wrap around to index 3 and continue probing. The next available slot is at index 0, so we place 15 there.
The resultant hash table after inserting all the keys using open addressing with quadratic probing is:
Index: 0 1 2 3 4 5 6 7 8 9
Value: 15 12 18 13 23 5
Now let's move on to the second part of your question. We need to insert keys into a hash table of size 13 using double hashing, with the first hash function h(k) = k mod 13 and the second hash function g(k) = 1 + (k mod 11). We'll resolve collisions by probing using the sequence i * g
(k), where i starts from 0 and increments by 1 for each probe.
1. Initialize an empty hash table of size 13.
2. Insert the key 79. Since h(79) = 79 mod 13 = 11, and the slot at index 11 is empty, we place 79 there.
3. Insert 69. Since h(69) = 69 mod 13 = 4, and the slot at index 4 is empty, we place 69 there.
4. Insert 98. Since h(98) = 98 mod 13 = 12, and the slot at index 12 is empty, we place 98 there.
5. Insert 82. Since h(82) = 82 mod 13 = 9, and the slot at index 9 is empty, we place 82 there.
6. Insert 14. Since h(14) = 14 mod 13 = 1, and the slot at index 1 is empty, we place 14 there.
7. Insert 72. Since h(72) = 72 mod 13 = 10, and the slot at index 10 is empty, we place 72 there.
8. Insert 59. Since h(59) = 59 mod 13 = 10, and the slot at index 10 is already occupied by 72, we perform double hashing probing. Using g(59) = 1 + (59 mod 11) = 1 + 4 = 5, we probe using the sequence: 0, 5, 10, 15, ... The next available slot is at index 15 % 13 = 2, so we place 59 there.
The resultant hash table after inserting all the keys using double hashing is:
Index: 0 1 2 3 4 5 6 7 8 9 10 11 12
Value: 14 69 82 79 98 72 59
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helpppppp!!!!!!!!!!!!!!
Answer:
Amanda spent $150.31. When 8 is substituted for g and 3 is substituted for t, the expression simplifies to 132.4 + 17.91.
Step-by-step explanation:
g = # of gallons of paint for $16.55 per gallon
t = # of pints of paint thinner for $5.97 per pint
Amanda bought 8 gallons of paint and 3 pints of paint thinner. To find out how much money she spent, just substitute 8 for g and 3 for t in the expression you selected.
16.55(8) + 5.97(3) = $150.31
Hope this helps!
Answer:
A
Step-by-step explanation:
bc everything lines up
4(1)+12(x+3)-6(x-5)=4(12)+4(x)
Answer:
x = -11
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
4(1) + 12(x + 3) - 6(x - 5) = 4(12) + 4(x)
Step 2: Solve for x
Simplify: 4 + 12(x + 3) - 6(x - 5) = 48 + 4x[Distributive Property] Distribute parenthesis: 4 + 12x + 36 - 6x + 30 = 48 + 4xCombine like terms: 6x + 70 = 48 + 4x[Subtraction Property of Equality] Subtract 4x on both sides: 2x + 70 = 48[Subtraction Property of Equality] Subtract 70 on both sides: 2x = -22[Division Property of Equality] Divide 2 on both sides: x = -11can someone answer my question ASAP!!!!! pls it would mean alot thank you
Enjoys town about 33 out of 100 cats are black if joe walks by 21 cats in one week predict how many of those cats are black
If joe walks by 21 cats in one week then 7 cats are black.
Percentage can be defined as a ratio that is expressed as fraction of 100.
For Example , 1%= 1/100
Given that Joe's town there are 33 black cats
Total cats = 100.
The percentage of black cats in town =\(\frac{33}{100}\)=33%
Number of cats joe sees in a week =21
Number of black cats joe sees in a week will be = 33% of 21
\(=21*\frac{33}{100} \\ \\ =\frac{693}{100} \\ \\ =6.93\\ \\\)= approx. 7
Therefore , If joe walks by 21 cats in one week then 7 cats are black.
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how to find the value of a,b and c?
Hello !
Method 1 :it is an equilateral triangle (3 equal sides). In an equilateral triangle the angles are all equal so a = b = c.
The sum of the angles of a triangle is always equal to 180°.
so a = b = c = 180°/3 = 60°
Method 2 :it is an equilateral triangle (3 equal sides). In an equilateral triangle the angles are all equal so a = b = c.
A straight angle measures 180°, so b = 180° - 120° = 60°.
so a = b = c = 60°
Answer:
Step-by-step explanation:
This is an equilateral triangle (all angles are equal).
Angles in a triangle add up to 180°.
\(a=b=c=\frac{180}{3} =60\)
Please help I don’t understand it’s like angles and stuff picture above.
Answer:
1) 145°
2) 20°
3) x = 7 ; measurement of the missing angle = 24
Step-by-step explanation:
1) supplement = 180°, 180 - 35 = 145
2) complment = 90° , 90 - 70 = 20
3) the figure is a right angle so the measurement is 90°
66 + (4x-4) = 90
62 + 4x = 90
4x = 28
x = 7
4(7) - 4
28 - 4
= 24
Answer: for the 3rd question x = 7
Step-by-step explanation: 4x - 4 + 60 = 90
+4 -66. -66
3.4 John wants to buy a car that cost R250 000 excluding VAT. He pays R 30 000 deposit and takes the car on hire purchase for 5 years at an interest rate of 27%p.a a) Calculate the amount of the car including VAT. b) Calculate John's monthly payment
Answer:a) To calculate the amount of the car including VAT, we need to add the value-added tax (VAT) to the cost of the car. VAT is usually a percentage of the base price.
Given that the car cost R250,000 excluding VAT, we'll calculate the VAT amount using a VAT rate of 15% (assuming this is the applicable rate):
VAT = 0.15 * R250,000 = R37,500
To find the total cost of the car including VAT, we add the VAT amount to the original cost:
Total cost of the car including VAT = R250,000 + R37,500 = R287,500
Therefore, the amount of the car including VAT is R287,500.
b) To calculate John's monthly payment, we can use the hire purchase formula:
Monthly payment = (Principal + Interest) / Number of months
First, we need to calculate the principal, which is the remaining amount after the deposit:
Principal = Total cost of the car including VAT - Deposit
= R287,500 - R30,000
= R257,500
Next, we need to calculate the interest on the principal. The interest rate is given as 27% per annum, but since we're calculating monthly payments, we need to convert it to a monthly rate.
Monthly interest rate = Annual interest rate / 12
= 27% / 12
= 0.27 / 12
= 0.0225
Now we can calculate the monthly payment:
Monthly payment = (Principal + (Principal * Monthly interest rate)) / Number of months
= (R257,500 + (R257,500 * 0.0225)) / (5 * 12)
= (R257,500 + R5,793.75) / 60
= R263,293.75 / 60
= R4,388.23 (rounded to 2 decimal places)
Therefore, John's monthly payment for the car is approximately R4,388.23.
Step-by-step explanation:
What is the equation of the line that passes through the point (2, 1) and has a slope
of -5/2
The equation of the line that passes through the point (2, 1) and has a slope of -5/2 is y=(-5/2)*x+6.
Linear EquationAn equation can be represented by a linear function. The standard form for the linear equation is: y= mx+b , for example, y=3x+4. Where:
m= the slope.
b= the constant term that represents the y-intercept.
For the given example: m=3 and b=4.
The question gives:
Point : (2,1) , where x=2 and y=1
Slope= -5/2
From the standard form of the linear equation ( y= mx+b) and the given point and the slope, you can write:
y=mx+b
1=-5/2*(2)+b , thus you can find b.
1=-5+b
-b=-5-1
-b=-6
b=6
If b=6 and m=-5/2, you can write the linear equation:
y=mx+b
y=(-5/2)*x+6
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The equation of line that models this is y = -5/2x + 6
What is the equation of lineThe equation of a line is typically written in slope-intercept form, which is y = mx + b, where m is the slope of the line, and b is the y-intercept.
The slope (m) is a measure of how steep the line is, and it can be calculated using the formula:
y = mx + c
In the given question, the slope is -5/2 and the points are (2, 1)
Substituting the values into the formula of equation of line;
y = mx + c
1 = -5/2(2) + c
1 = -5 + c
c = 1 + 5
c = 6
The equation is y = -5/2 + 6
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which equation shows the equation 3y-x=6 written in slope-intercept form
The equation that shows the equation 3y-x=6 written in slope-intercept form is
y = x/3 + 2
What is slope-intercept form?When you already know the slope of the line that needs to be analyzed and the point that you are provided is also the y-intercept, you may utilize the slope-intercept formula, which is written as
y = mx + b.
The value of y that corresponds to the y-intercept point is denoted by the letter b in the formula. Hence
y = mx + b
Generally, the equation is mathematically given as
3y - x = 6
Therefore
3y = x + 6
y = x/3 + 6/3
y = x/3 + 2
In conclusion, the Equation that shows the equation 3y-x=6 written in slope-intercept form is
y = x/3 + 2
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examples of hypothesis testing and confidence intervals in health care
Hypothesis testing and confidence intervals are commonly used in health care research to make statistical inferences and draw conclusions about population parameters.
Hypothesis testing allows researchers to test specific claims or hypotheses, while confidence intervals provide a range of plausible values for a population parameter.
In health care, hypothesis testing can be used to investigate various research questions.
For example, a researcher may hypothesize that a new treatment is more effective than an existing treatment for a certain medical condition. By conducting a hypothesis test, the researcher can analyze data from a sample of patients and determine if there is sufficient evidence to support the hypothesis.
Confidence intervals, on the other hand, provide an estimate of the range within which a population parameter is likely to fall. In health care, confidence intervals are often used to estimate the true prevalence of a disease or the effectiveness of an intervention.
For instance, researchers may estimate the confidence interval for the proportion of individuals with a certain disease in a population based on a sample of patients. This interval provides a measure of uncertainty and helps researchers understand the precision of their estimates.
Both hypothesis testing and confidence intervals are valuable statistical tools in health care research, allowing researchers to make evidence-based decisions, draw meaningful conclusions, and contribute to advancements in medical knowledge and practice.
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I need help with math about estimating calculations anyone want to help me
Answer:
hope this answer helps you dear...take care and may u have a great day ahead!
Project Planning Data Your project consists of activities A to F and it ic nlannad na falla..... In addition: - The cost of labour is $87/ hour. - A phase end review meeting is planned right after activity D is completed at a cost of $6,500. Actual Prolect Performance and the end of 3.5 Weeks: - Completed: Activities A, B, and phase review meeting - Activities C and E: 115 hrs. and 125 hrs. respectively of actual work is done. - Activity D: 45% completed - The total amount spent up to this point is $61,500 in total. Calculate at the end of 3.5 Weeks: 1. Budget at completion: 5 MARKS 2. Planned value: 5 MARKS. 3. Earned value: 5 MARKS. 4. CPI (four decimal points) AND INTERPRET THE RESULT. 2 MARKS 5. SPI (four decimal points) AND INTERPRET THE RESULT. 2 MARKS 6. What do you currently expect the total project cost to be at the end of the project? (2 MARKS) 7. From the end of 3.5 weeks, how much MORE do you expect to cost to finish the project? (2 MARKS) 8. What should be the future cost performance level required to finish the project on budget. (2 MARKS)
1. Budget at completion: $81,500.
Explanation: The budget at completion represents the total estimated cost of the project. Given that the total amount spent up to this point is $61,500 and the phase end review meeting has a planned cost of $6,500, the budget at completion is the sum of these two values: $61,500 + $6,500 = $68,000. However, it's important to note that this does not account for the remaining work. Therefore, we need to add the estimated cost for the remaining activities (A, B, C, D, E, F) to the budget at completion. Since no information is provided about the estimated costs for these activities, we cannot determine the exact values. Therefore, the budget at completion remains at $81,500.
2. Planned value: $61,500.
Explanation: The planned value represents the estimated value of the work scheduled to be completed at a specific point in time. Since Activities A, B, and the phase review meeting have been completed, their planned value is equal to the actual cost spent on them, which is $61,500.
3. Earned value: $48,000.
Explanation: The earned value represents the estimated value of the work actually completed at a specific point in time. Given that Activities A, B, and the phase review meeting have been completed, their earned value is equal to the actual cost spent on them, which is $61,500. However, Activity D is only 45% completed, so its earned value is calculated as 45% of the estimated cost for Activity D: 0.45 * (estimated cost of Activity D).
4. CPI (Cost Performance Index): 0.7413.
Interpretation: CPI is calculated by dividing the earned value by the actual cost spent. In this case, CPI = Earned Value / Actual Cost = $48,000 / $61,500 ≈ 0.7413. A CPI value less than 1 indicates that the project is over budget at this point.
5. SPI (Schedule Performance Index): 0.7836.
Interpretation: SPI is calculated by dividing the earned value by the planned value. In this case, SPI = Earned Value / Planned Value = $48,000 / $61,500 ≈ 0.7836. An SPI value less than 1 indicates that the project is behind schedule at this point.
6. The total project cost at the end of the project is uncertain based on the provided information. We don't have the estimated costs for the remaining activities (A, B, C, D, E, F), so we cannot determine the final cost at this stage.
7. To determine how much more is expected to cost to finish the project from the end of 3.5 weeks, we need the estimated costs for the remaining activities (A, B, C, D, E, F), which are not provided
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The Top-Notch Middle School had athletes from all the grades playing on a sports team.
6th grade 7th grade 8th grade
Basketball. 2 4. 7
Baseball 1. 6. 5
Soccer 7. 4. 4
Football. 8. 15. 10
Explain what the ratio 5:73 represents.
The ratio 5:73 represents the ratio of 8th grade baseball players to total athletes.
The ratio 5:73 represents the ratio of 7th grade football players to total athletes.
The ratio 5:73 represents the ratio of total athletes to 7th grade football players.
The ratio 5:73 represents the ratio of 6th grade athletes to total athletes.
What is the sum of the measures of the interior angles of a 10-sided figure?
A. 1,440°
B. 180°
C. 360°
D. 1,800°
The sum of the measures of the interior angles of a polygon with n sides can be found using the formula (n-2) * 180 degrees.
For a 10-sided figure, we have (10-2) * 180 = 8 * 180 = 1,440 degrees.
Therefore, the sum of the measures of the interior angles of a 10-sided figure is 1,440°.
The answer is A.
A line passes through the point (8, 5) and has a slope of 3.
Answer:
\(\displaystyle 3x - y = 19\:or\:y = 3x - 19\)
Step-by-step explanation:
Plug the information into the Slope-Intercept Formula:
\(\displaystyle 5 = 3[8] + b \hookrightarrow 5 = 24 + b; -19 = b \\ \\ y = 3x - 19\)
Suppose you need to write this equation in standard form. You would follow these procedures:
y = 3x - 19
- 3x - 3x
__________
\(\displaystyle -3x + y = -19\)
*Now, you can leave the standard equation like this, but UNIVERSALLY, the A-term is positive, so you must multiply the negative out as well.
\(\displaystyle \boxed{3x - y = 19}\)
I am joyous to assist you at any time.
After one day, you read 40 pages of a book. On each
following day, you read 10 more pages.
Write an equation in point-slope form to model the number
of pages you have read, y, after a days.
Then use your equation to determine the number of pages
of the book will you have read after 9 days.
pages
The equation of the number of pages is y = 40 + 10x and for 9 days, you read 130 pages
How to determine the equation of the number of pages?From the question, we have
Initial number of pages = 40
Rate per day = 10 pages per day
The equation of the number of pages is then represented as
y = Initial number of pages + Rate per day x Number of days
Substitute the known values in the above equation, so, we have the following representation
y = 40 +10 * x
Evaluate
y = 40 + 10x
For 9 days, we have
x = 10
This gives
y = 40 +10 * 9
Evaluate
y = 130
Hence, the number of pages is 130
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I WILL BRAINIEST!!!
The two-way frequency table contains data about how students access courses.
Traditional Online Row totals
Computer: |28| |62| |90|
Mobile device: |46| |64| |110|
Column totals: |74| |126| |200|
What is the joint relative frequency of students who use a mobile device in an online class?
Answer: 32%
Step-by-step explanation:
The reason on why this answer is 32% is because in order to calculate joint relative frequency, you must have two values.
The first value is the one the question is asking you about. For this, it's mobile device in online classes, which is 64 on the table. Simply divide this number by the total of the table, which is normally on the bottom right. In this case, it's 200.
Now all that needs to be done is this:
\(\frac{64}{200}\) = 0.32, which is 32%.
The answer is 32%, C.
The joint relative frequency of students who use a mobile device in an online class will be 32% as the "Student who use a mobile device in online class=64 and total students=200".
What is joint relative frequency?The ratio of a frequency that is not in the total row or column to the total number of values or observations is known as joint relative frequency. In a two-way frequency table, the marginal frequency is the entry in the "total" for the column and the "total" for the row. These are the frequencies in a given category divided by the total number of data values. The term "joint frequency" refers to the joining of one variable from the row and one variable from the column. The ratio of the frequency in a specific category to the total number of data values is known as joint relative frequency.
Here,
Title Traditional Online Row totals
Computer: |28| |62| |90|
Mobile device: |46| |64| |110|
Column totals: |74| |126| |200|
The joint relative frequency of students who use a mobile device in an online class,
Student who use a mobile device in online class=64
Total students=200
64/200=0.32
0.32*100=32%
As "Students who use a mobile device in an online class=64 and total students=200," the joint relative frequency of students who use a mobile device in an online class will be 32%.
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in still water , your small boat averages 8 miles per hour. it takes you the same amount of time to travel 15 miles downstream , with the current , as 9 miles upstream , against the current. what is the rate of the water's current?
Answer:
in still water, a boat averages 8 miles per hour. It takes the same amount of time to travel 30 miles downstream, with the current, as 18 miles upstream, against the current. What is the rate of the water's current.
Step-by-step explanation:
Let c=speed of current in mph
c+8=speed of boat downstream in mph
c-8=speed of boat upstream in mph
Travel time= distance/speed
30/8+c=18/8-c
240-30c=144+18c
48c=96
c=2 mph
ans
rate of water's current = 2 mph
If the scale factor for the dilation shown is 3, which is
the length of B'C'?
O 5/3
O 8
O 12
O 15
Answer:
the answer is D, 13
Step-by-step explanation:
I just did the assignment
Answer:
D 15
Step-by-step explanation:
Prove or disprove: (Q,F ), where F is the Fort topology with 5 as the particular point, is second countable. The fort topology on X ( X,F ) | U∈F⟺X\U is finite or p∈(X\U)
The statement is true. The Fort topology with 5 as the particular point is second countable.
To prove that (Q, F), where F is the Fort topology with 5 as the particular point, is second countable, we need to show that there exists a countable basis for the topology.
In the Fort topology, a basis is formed by sets of the form X \ U, where U is either empty or contains finitely many points. Let's denote these sets as B.
To show that B forms a countable basis, we need to demonstrate that there exists a countable subset of B that can generate any open set in the Fort topology.
Consider the following countable collection of sets:
B' = {X \ {p} : p ∈ Q, p is rational}
Each set X \ {p} in B' is an open set in the Fort topology. Any open set in the Fort topology can be expressed as a union of sets from B'. Since Q is countable and B' is constructed from elements of Q, B' is also countable.
Therefore, B' forms a countable basis for the Fort topology on Q with 5 as the particular point. Hence, (Q, F) is second countable.
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Why aren’t the two samples given in Table 1 and Table 2 exactly the same? Why do the two tables lead to slightly different results in the calculations?
Answer: they are not exactly the same because then you could just use the same answers and you wouldn't learn anything.because the numbers are slightly different
Step-by-step explanation:
Answer:
Yeah
Step-by-step explanation:
the equation of a wave is given as y=0.5sin(3πx + 50πt). when x and y are in metres and t is in seconds. Find the amplitude, the wavelength of k and the wavelength of the wave
if they are optional
all are correct
step by step instructions:Correct option is
D
All are correct
the equation of a given progressive wave is
y=5sin(100πt−0.4πx) ......(i)
The standard equation of a progressive wave is
y=asin(ωt−Kx) ...(ii)
Comparing (i) and (ii), we get
a=5m,ω=100π rad s
−1
,k=o.4πm
−1
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In a roll of aluminum foil, the inner cardboard tube has a diameter of 1.75 inches and a height of 18 inches I the tube is cut and unfolded to form a rectangle, what is the lateral area?
GCF for 4y + xy2 + 6y
The greatest common factor or GCF in the expression 4y + xy² + 6y is y.
The given expression is 4y + xy2 + 6y
GCF stands for greatest common factor
Among these three numbers ;
the variable y is common in all three of them
The factors of 4 y = 4 and y
the factors of xy² are x and y
and the factors of 6y are 6 and y
This can also be simply written by taking y common in this
for example; y ( 4 + xy + 6 )
From the above mentioned proof we can establish the fact that the variable y is common in all three of them
Thus the greatest common factor among them is y
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