Can somebody please work these questions out for me?.

normal force=mass*gravitational force

normal force=40*0

normal force=40

If a teacher had 48 red pens and the ratio of red to blue pens she owns is 6:1, she will have a total of 56 pens

Let the number of red pens be R and the number of blue pens be B.

R = 48

R / B = 6 / 1

48 / B = 6 / 1

B = 48 / 6

B = 8

Total number of pens = Number of red pens + Number of blue pens

Total number of pens = R + B

Total number of pens = 48 + 8

Total number of pens = 56 pens

Therefore, she has a total of 56 pens

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Hello!

\(\boxed{ \text{A. W and X}}\)

Given a velocity/time graph, a constant, positive acceleration is represented by a LINEAR, UPWARD-SLOPING, segment of the velocity graph.

Looking at the graph, this is true at segments W and X.

The correct answer is A.

kinetic energy 8.0 s later will be 11.35 joules

Given:

inertia,I=0.034kgm²

torque,τ=0.11nm

time,t=8.0s

To find:

kinetic energy,KE

we can find the kinetic energy by using

\(k = \frac{1}{2} iω {}^{2} \)

so firstly we will find ω by finding α

α=τ/I

α=0.11/0.34

=3.23

then we find ω

ω=α×t

=3.23×8

=25.84

\(k = \frac{1}{2}iω {}^{2} \)

k=1/2×0.34×(25.84)2

=1/2×22.70

k=11.35

so kinetic energy is 11.35 joules

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Answer:

B = 1058.4  N

Explanation:

Given that,

The volume of a metal block, V = 0.09 m³

The density of fluid, d = 1200 kg/m³

We need to find the buoyant force when it's Completely  immersed in brine. The formula for the buoyant force is given by :

\(B=\rho gV\)

g is acceleration due to gravity

\(B=1200\times 9.8\times 0.09\\\\B=1058.4\ N\)

So, the required buoyant force is 1058.4  N.

A) To find the torque that the person applies to the engine, we need to first find the force applied at the edge of the drum. We can do this using the formula:

Force = Torque / Radius

where the radius is half the diameter of the drum.

Radius = 10 cm / 2 = 0.05 m

Force = 100 N

Therefore:

Torque = Force x Radius = 100 N x 0.05 m = 5 Nm

So the person applies a torque of 5 Nm to the engine.

B) To find the work done by the person, we need to use the formula:

Work = Force x Distance

where the distance is the length of the starter cord that is pulled out.

Length of cord = 1 m

Since the cord is wound around the drum, the distance that the person pulls is equal to the distance that the drum rotates. The circumference of the drum is:

Circumference = π x diameter = π x 10 cm = 0.314 m

So the distance that the person pulls is 0.314 m.

Therefore:

Work = Force x Distance = 100 N x 0.314 m = 31.4 J

So the person does 31.4 Joules of work

(a) 0.05 ° C

(b) 12.17 ohms

Assuming that the resistance changes uniformly with temperature we can set the equation of the line

so

Step 1

find the equation of the line:

the equation of a line has the form:

to do that, we need 2 points from the line, so let

x represents the temperature

y represents resistance

now, to find the slope of a line we need to use the expression

then, replace the values in the formula

so, the slope is 0.0395

b) now, use the slope point formula to find the equation of the line

so, the equation of the lines is

y=0.0395x+10.4

Step 2

Now, we can use the equation to find the asked values

(a) The temperature when the resistance is 11.19 ohms?

let

therefore

(a) 0.05 ° C

Step 3

(b) The resistance of the thermometer when the temperature is 45 C?

let

now, replace in the expression to find the resistance

therefore,

(b) 12.17 ohms

I hope this helps you

In a penumbral lunar eclipse, "all parts of the moon are partly, not totally, shaded from the sun.

A penumbral lunar eclipse occurs when the Earth moves between the Sun and the Moon, but the three celestial bodies do not form a perfect line. This causes the Earth's outer shadow, called the penumbra, to fall on the Moon.

During a penumbral lunar eclipse, the Moon does not pass through the darkest part of the Earth's shadow (the umbra), so the Moon is only partly shaded from the sun, and the eclipse is usually not as noticeable as a total or partial lunar eclipse.

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Answer:

Acute exposure to the vacuum of space: No, you won't freeze (or explode) ... Upon sudden decompression in vacuum, expansion of air in a person's lungs is likely to cause lung rupture and death unless that air is immediately exhaled.

Explanation:

(1.) The Phenomena of Refraction Occurs when a Ray (Here Light) enters a Relatively Denser or Rarer Medium and Due to the Change in Density, the Speed of the Incident Ray Decreases or Increases Respectively.

(2.) If a light ray projected through a diamond, the light would refract drastically.

Answer:

i) Hooke's Law works for some materials

ii) Hooke's Law only applies up to a certain force

iii) The force at which Hooke's Law stops working for springs is lower than for most materials

Explanation:

Hooke's Law of elasticity states that the deformation of an elastic material is proportional to the applied for small deformations

The law is applicable to elastic materials whose values of deformation or extension as well as the applied load or stress are expressible by a single real number

Hooke's Law is applicable when the force and the extension of the elastic material are proportional, at larger force, the elastic material is observed to expand more than as expected based on Hooke's Law

The nature of springs is such that its elastic limit is reached by a much lower force than for most materials. Therefore, Hooke's law stops working for springs at a lower force than for most materials.

Astronomers now know that surrounding the main body of our galaxy (which our various kinds of telescopes have shown to us) and our fainter halo of stars there is: a spherical halo of dust and gas.

There are many stars, grains of dust, and gas in the Milky Way. It is known as a spiral galaxy because, from the top or bottom, it would appear to be whirling like a pinwheel. About 25,000 light-years from the galaxy's nucleus, the Sun is situated on one of the spiral arms. The Milky Way's center would take you about 25,000 years to reach, even if you could move at the speed of light (300,000 km/s, or 186,000 mph).

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Answer:

-scalar

Explanation:

-A scalar is any quantity that has a magnitude, but no direction

-quantities with no specified direction.

hope it helps:)

The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

\(F= \frac{mv}{t}\)

The force applied to an object increases with increases in the velocity of the object.

In the given diagram, the resultant velocity of the puck is calculated as follows;

Figure a:

\(\Delta v = v_f -v_i\\\\\Delta v = 5 - 6 = - 1 \ m/s\)

Figure b:

\(v = \sqrt{4^2 + 3^2} \\\\v = 5 \ m/s\)

Figure c:

\(\Delta v = 4 - (-2)\\\\\Delta v = 6 \ m/s\)

Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.

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Explanation:

It acts as drag to slow the airplane down...requiring more work from the engines to keep the plane moving .    Airplane designers make airplanes with retractable gears and smooth curves  to REDUCE air friction.

Answer:

53.1 Degrees

Explanation:

Process of elimination

The time required for the rock to reach the ground is 1.11 second.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Initial height of the rock: h = 6.00 m.

Acceleration due to gravity: g = 9.8 m/s²

Let,  the time required for the rock to reach the ground is = t.

Then:

h = 1/2 × gt²

t = √(2h/g)

= √ {(2 × 6.00)/9.8} second.

= 1.11 second.

Hence, the time required for the rock to reach the ground is 1.11 second.

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The velocity of the basketball rolling off a 1.20 m high desk and strikes the floor 0.55 m away from the base of the desk is 1.22 m/s.

What is projectile motion?

The path followed by a projectile is known as projectile motion, when we throw any object in the air it follows a certain trajectile and that trajectory is known as projectile motion.

What is the time of flight?

Every projectile remains in the air for a certain period of time the amount of time the projectile space in the air is known as time of flight for the same velocity with different angles the time of flight can vary.

given:

height of the table = 1.20 meters

range of the projectile = 0.55 meters

first, we need to determine the time of flight of the projectile using the height of the table.

the time of flight for both the motion i.e., in x axis and y axis will be same.

using newtons second law of motion we get,

s = u × t + 0.5 × a × t²

where,

s is displacement in y axis

u is the initial velocity of the basketball

t is the time of flight

a is the acceleration due to gravity

substituting value in newtons second law of motion we get,

1.20 = 0 + 0.5 × 10 × t²

t² = 0.24

t = 0.49 seconds

now we will use this to find the velocity of the basketball using time distance relationship,

distance = speed × time

0.55 = velocity of the basketball × 0.49

velocity of the basketball = 1.22 m/s

therefore, the velocity of the basketball rolling off a 1.20 m high desk and strikes the floor 0.55 m away from the base of the desk is 1.22 m/s.

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Answer:

S1

Explanation:

Has to be S1. This is pretty glaring to me. It's said from the question that the chemical reaction that took place is given by the following

S1 + G = S2, with S2 being an offspring of the first S1. When S1 got reacted, it broke down into S2, so, this only confirms that both S1 and E2 are S3 are compounds.

Contact forces is the answer

true

Explanation:

this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons

The relative velocity of the athlete relative to the ground is 5.2 m/s

The given parameters;

constant velocity of the athlete, V = 5.2 m/s

let the velocity of the ground = Vg = 0

The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.

The athlete is the moving object in this question while the ground is stationary.

The relative velocity of the athlete relative to the ground is calculated as follows;

\(V/V_g = V - V_g = 5.2 - 0 = 5.2 \ m/s\)

Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s

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Answer:

1. Kinetic energy is the energy possessed by a body due to its motion. Potential energy is the energy possessed by a body due to its position or state. Kinetic energy can be transferred from one object to another, in case of collisions. Potential energy cannot be transferred. Thus, the potential energy is stored in the object due to its position, whereas the kinetic energy is possessed by an object due to motion.

Eg: A ball kept on the edge of the table possesses potential energy due to its height, whereas a ball falling down from the table will possess kinetic energy due to its motion.

2. The formula for Kinetic energy is as below: This means that kinetic energy is directly proportional to mass as well as velocity. But it is proportional to 1 unit of mass and a square of velocity. Hence, velocity has a greater effect on kinetic energy.…show more content…

3. The equation for kinetic energy is: .

Let’s calculate the kinetic energy of a 40 kg object traveling 15 m/s.

Solution: mass= 40kg, velocity= 15 m/s, so putting these numbers into the kinetic energy equation,

Now, let’s calculate the kinetic energy of a 40 kg object traveling 30 m/s.

Solution: mass= 40kg, velocity= 30 m/s, so putting these numbers into the kinetic energy equation, Thus, when we double the velocity of an object, its kinetic energy increases by four times. Hence the velocity of an object has more impact on kinetic energy than the mass of an object.

Explanation:

The molar mass of a gas at 78 c and 560 torr if 206 ng occupies 0.206 ul is 41.64 g/mol

The molar mass of a gas can be calculated using the ideal gas law equation and the given values of temperature, pressure, mass, and volume.

To calculate the molar mass of a gas, we can use the formula:

Molar mass = (mass of gas) / (number of moles of gas)

First, we need to determine the number of moles of gas. We can use the ideal gas law equation:

\(PV = nRT\)

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

We are given the temperature as 78 °C, which needs to be converted to Kelvin by adding 273.15:

T = 78 + 273.15 = 351.15 K

The pressure is given as 560 torr, and the volume is given as 0.206 µl.

Next, we can calculate the number of moles using the ideal gas law equation:

\(n = (PV) / (RT)\)

(0.5105 atm)(2.06×10⁻⁷ L) = n(0.0821 L-atm/mol-K)(318 K)

n = 4×10⁻⁹ mol

Molar mass = Mass/n = 2.06×10⁻⁷ g/4×10⁻⁹ mol

Molar mass = 41.64 g/mol

Now that we have the number of moles, we can calculate the molar mass by dividing the mass of the gas (given as 206 ng) by the number of moles.

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The index of refraction that halves the wavelength that light has in a vacuum is 2.00. Therefore, the correct option is (d) 2.00.

When light passes from one medium to another, it changes its velocity, and thus its wavelength. The index of refraction is a measure of how much light is bent when passing through a medium and can be calculated using Snell's Law:n1sin θ1=n2sin θ2where n1 and n2 are the indices of refraction of the two media, and θ1 and θ2 are the angles that the light makes with the normal line in the first and second media, respectively.

For a given angle of incidence, we can see that the index of refraction is directly proportional to the sine of the angle of refraction, which means that as the angle of refraction increases, so does the index of refraction. Now, let's assume that light is passing from vacuum (with index of refraction n1=1) to a medium with an unknown index of refraction n2.

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Answer: The work done by a horizontal spring with spring constant k expanding from a compression distance of x to an extension distance of x due to an attached mass is kx².

Explanation:

When a spring expands or compresses, it does work on the object attached to it. The work done by a spring on an object is given by the formula:

W = (1/2) k (x₂² - x₁²)

where W is the work done by the spring, k is the spring constant, x₁ is the initial compression distance, and x₂ is the final extension distance.

In the given scenario, the spring is expanding from a compression distance x to an extension distance of x due to an attached mass. The initial compression distance is x₁ = -x, and the final extension distance is x₂ = x. Therefore, the work done by the spring is:

W = (1/2) k (x₂² - x₁²) = (1/2) k [(x)² - (-x)²] = (1/2) k (2x²) = kx²

Hence, the work done by a horizontal spring with spring constant k expanding from a compression distance of x to an extension distance of x due to an attached mass is kx².

The periosteal layer and the meningeal layer together compose the dura mater in the cranial cavity. The subarachnoid space contains a protective cerebrospinal fluid (CSF). The falx cerebri, a dural septum, is located within the longitudinal fissure between the cerebral hemispheres. The superior sagittal sinus collects and contains venous blood. The delicate membrane is located on the surface of the brain.

The dura mater, one of the cranial meninges, is composed of two layers: the periosteal layer, which is attached to the inner surface of the skull, and the meningeal layer, which is deeper and forms a protective covering around the brain. The subarachnoid space is a region filled with cerebrospinal fluid (CSF) that surrounds the brain and spinal cord, acting as a cushion and providing protection. The falx cerebri is a dural septum that runs within the longitudinal fissure, separating the two cerebral hemispheres. It helps to stabilize and support the brain's structures. The superior sagittal sinus is a large venous channel located within the falx cerebri. It collects deoxygenated blood from the brain and carries it back towards the heart. On the surface of the brain, there is a delicate membrane known as the arachnoid mater. It lies between the dura mater and the pia mater and plays a role in protecting the underlying brain tissue. Together, these structures and spaces form part of the complex system of cranial meninges, providing protection, support, and fluid-filled spaces within the cranial cavity.

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Answer:

The concept of unstable equilibrium can be used in the design of everyday objects such as switches or alarms by ensuring that an object is positioned in a way that requires a small amount of force to cause it to tip over and trigger the switch or alarm.

For example, in a light switch, the switch lever can be designed to be in a position where it is balancing on a pivot point, such that a slight push up or down will cause it to tip one way or the other, and thus activate or deactivate the switch.

Similarly, in an alarm system, a small amount of force applied to a specific point can tip over a weight, causing it to fall and trigger the alarm.

By using unstable equilibrium designs in the design of switches or alarms, the objects can be made more sensitive and responsive to user actions, without requiring a significant amount of force to activate them.