Corrected, it's 2) 200
12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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a wave with a frequency of 500hz is traveling at a speed of 1000m/s whats the wavelength?
In the hydrogen atom, which electronic transition corresponds to the largest energy emission?
In hydrogen atom the electronic transition from n= ∞ to n=1 corresponds to largest energy emission.
What is electronic transition ?Electronic transition is the jump of an electron from one energy level to another energy level .
Which electronic transition in Hydrogen atom corresponds to highest energy emission?The fromula for energy emission isE = hc/λ
where E= emited energyh= plank constant =6.62*10^(-34)
c=speed of light
λ= wavelength of emited electron .
The electronic transition from infinity to ground state corresponds to lowest wavelength .Thus , we can conclude that the electronic transition from infinity to n=1 (ground state) corresponds to largest energy emission .
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Does an infrared wave or an x-ray travel faster in the vacuum of space?
Answer:
All electromagnetic radiation, of which radio waves and X-rays are examples, travels at the speed c in a vacuum. The only difference between the two is that the frequency of X-rays is very much higher than radio waves
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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prove the three laws of motion
Answer:
The first law, also called the law of inertia, was pioneered by Galileo. This was quite a conceptual leap because it was not possible in Galileo's time to observe a moving object without at least some frictional forces dragging against the motion. In fact, for over a thousand years before Galileo, educated individuals believed Aristotle's formulation that, wherever there is motion, there is an external force producing that motion.
The second law, $ f(t)=m\,a(t)$ , actually implies the first law, since when $ f(t)=0$ (no applied force), the acceleration $ a(t)$ is zero, implying a constant velocity $ v(t)$ . (The velocity is simply the integral with respect to time of $ a(t)={\dot v}(t)$ .)
Newton's third law implies conservation of momentum [138]. It can also be seen as following from the second law: When one object ``pushes'' a second object at some (massless) point of contact using an applied force, there must be an equal and opposite force from the second object that cancels the applied force. Otherwise, there would be a nonzero net force on a massless point which, by the second law, would accelerate the point of contact by an infinite amount.
Explanation:
15. a) The diagram below shows to answer the question that follow show State and explain the effect on the height, h, when the thistle funnel is of the liquids (2 marks) ved upwards towards the surface
When the thistle funnel is moved upwards towards the surface of the liquids, the height (h) decrease.
What happens when the thistle funnel is moved upward?
An important principle outlined by Pascal's law states that any fluid (in this instance, liquids) experiences equal transmission of force in every direction within it. Hence, there is an intimate relationship between the height of a liquid column and its pressure.
Raising a thistle funnel reduces this height causing loss of weight from above this point thus decreasing its pressure.
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A bucket begins weighing 20 pounds, including the sand it holds. The bucket is to be lifted to the top of a 25 foot tall building by a rope of negligible weight. However, the bucket has a hole in it, and leaks 0.1 pounds of sand each foot it is lifted. Find the work done lifting the bucket to the top of the building
ANSWER
\(\begin{equation*} 468.75\text{ foot-pound} \end{equation*}\)EXPLANATION
Let the bucket be lifted x feet.
The weight of the bucket at x feet is given by:
\(20-0.1x\)The work done in lifting the bucket by dx feet is:
\(dW=(20-0.1x)dx\)The total work done is the integral of the work done in lifting the bucket x feet, that is:
\(W=\int(20-0.1x)dx\)Hence, the work done in lifting the bucket 25feet is:
\(\begin{gathered} W=\int_0^{25}(20-0.1x)dx \\ \\ W=(20x-\frac{0.1x^2}{2})_0^{25} \\ \\ W=(20*25-\frac{0.1*25^2}{2})-(20*0-\frac{0.1*0^2}{2}) \\ \\ W=500-31.25 \\ \\ W=468.75\text{ foot-pound} \end{gathered}\)That is the answer.
A billiard ball moving horizontally, labeled 1, strikes another billiard ball at rest, labeled 2. Before impact, ball 1 was moving at a speed of 2.35 m/s, and after impact it is moving at 0.45 m/s at 45° counterclockwise from the direction of the initial velocity. If the two balls have equal masses of 160 g, what is the velocity of ball 2 after the impact? (Assume ball 1 initially moves along the +x-axis. Enter the magnitude in m/s and the direction in degrees counterclockwise from the +x-axis.)
the velocity of ball 2 after the impact is 2.05 m/s.
Momentum is defined as mass times velocity. it tells about the moment of the body. it is denoted by p and expressed in kg.m/s. mathematically it is written as p = mv. A body having zero velocity or zero mass has zero momentum. its dimensions is [M¹ L¹ T⁻¹]. Momentum is conserved throughout the motion.
According to conservation law of momentum, momentum before impact is equal to final momentum after impact.
Given,
initial velocity of ball 1, v₁ = 2.35 m/s.
initial velocity of ball 2, V₁ =0 m/s.
final velocity of ball 1, v₂ = 0.45 m/s.(having 45 angle)
final velocity of ball 2, V₂ =? m/s.
mass of the both balls m = 0.16 kg
law conservation of momentum in x direction.
mv₁+mV₁ = mv₂ + mV₂
mv₁ = mv₂ + mV₂
0.16×2.35 = 0.16×0.45×Cos45 + 0.16×V₂
0.16×2.35 = 0.16×0.45×Cos45 + 0.16×V₂
0.376= 0.050+0.16×V₂
V₂(x) = 2.03 m/s
law conservation of momentum in y direction.
mv₁+mV₁ = mv₂ + mV₂
0 = mv₂sin45 + mV₂
mV₂ = -mv₂sin45
0.16V₂ = -0.16×0.45×0.7
V₂(y) = -0.31 m/s
the resultant velocity of the second ball 2 is,
v² = v²(x) + v²(y)
v² = 4.12 + 0.096
v= 2.05 m/s
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A baseball is popped straight up with an initial speed of 25.9 meters per second. What is the ball's velocity after it has traveled a total distance of 50.0 meters? Include units in your answer.
The ball's velocity after it has travelled a total distance of 50.0 meters is 40.63 m/s
Data obtained from the questionThe following data were obtained from the question:
Initial velocity (u) = 25.9 m/sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 50 mFinal velocity (v) = ?How to determine the final velocityWe can obtain the final velocity as illustrated below:
v² = u² + 2gh
v² = 25.9² + (2 × 9.8 × 50)
v² = 670.81 + 980
v² = 1650.81
Take the square root of both sides
v = √1650.81
v = 40.63 m/s
Thus, the velocity after travelling 50 m is 40.63 m/s
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How far is A(2, -6) and B (-15,-2)
The distance between these two points is approximately 17.46 units.
To identify the distance, we can use the distance formula of coordinate geometry:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Now, to plug our values in:
d = sqrt((-15 - 2)^2 + (-2 - (-6))^2)
sqrt((-17)^2 + (4)^2)
= sqrt(289 + 16)
= sqrt(305)
d ≈ 17.46
Hence, the distance between points A and B approximately equals 17.46 units.
1.The amount of food inside a bowl is an example of what? Mass or weight*
2. How much gravity is pulling down on a dog is an example of the dogs what?
Weight or mass
Answer:
1. Mass
2. Weight
Explanation:
1. All the physical quantities that exist in the universe that have mass, are measurable because they can be measured on instruments such as scales. For this example, the amount of food can be measured on a scale and its mass determined in grams or ounces.
2. When we talk about a mass of a body influenced by gravity we are talking about weight, weight is a force that points in the direction of Earth's gravitational acceleration. That is, weight depends on the gravitation that interacts with the body. For the example we have that the weight of the dog is equal to the product of the mass of the dog by the gravity of the Earth.
The figure below shows a box with a mass of m = 7.40 kg that starts from rest at point A and slides on a track with negligible friction. Point A is at a height of ha = 5.10 m. An illustration shows a wavy track, starting from a crest, moving to a trough, then again to a crest and trough, and finally to a crest that then moves downward. Three points in the track are highlighted, A, B, and C. Point A is at the top of the track where a box of mass m is placed ready to get released. It is at the height labeled ha from the ground. Point B is shown at the next crest and is at a height of 3.20 meters from the ground. Point C is shown at the following trough and is at a height of 2.00 meters from the ground. (a) What is the box's speed at point B (in m/s)? m/s What is the box's speed at point C (in m/s)? m/s (b) What is the net work (in J) done by the gravitational force on the box as it moves from point A to point C?
Work done by gravity when it moves from A to C will be 288.6 joule
How to calculate the valueApplying conservation of energy between point A and B,
7.4xgx5.9 = 1/2x7.4xv2 + 7.4xgx3.2
873.2 = 7.4v2 + 473.6
v = 7.34 m/s
It should be noted that to find velocity at C, which has come down to a height of 2 meter, it means it has travelled by 5.9-2 =3.9 m
so, v2 = 2gh = 20x3.9 =
v = 8.83 m/s
Work done by gravity when it moves from A to C = mxgx(5.9-2) = 288.6 joule
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how were the outer planets formed?
Answer:
All planets including the outer larger planets were formed at the same time somewhere around 4.5 Billion years ago.
Explanation:
the young sun drove away most of the gas from the inner solar system, leaving behind the rocky cores also known as the terrestrial planets.
Question 1 An object of mass 20kg accelerates from rest to a velocity of 10m/s in 5 sec. calculate the distance covered by the object
Answer:
25 m
Explanation:
Let's assume that its acceleration is constant. We can determine the acceleration of the object by its definition
\(a= \frac{\Delta v}{\Delta t} = \frac{10-0(\frac ms)}{5 s} = 2 \frac m{s^2}\)
Now we can write the equation of motion
\(s(t)= s_0 + v_0t + \frac12at^2\)
where, the two terms \(s_0\ v_0\) represent the initial position and velocity respectively. Replacing the values we have ("from rest" means that initial velocity is 0)
\(s(5) = 0+0(5)+\frac12 2 (5)^2 = 25 m\)
What is the only difference between the reactant and product side of a chemical reaction?
Answer:
Products is the result. Reactants produce the result
Explanation:
,,
Fill in the magnitude of net force for each case. Including the solution plss
Net forces in all above cases will be
A) F net = 0
B) F net = 1 N
C) F net = 5 N
D) F net = 5N
E) F net = 5 N
F) F net = 5 N
G) F net = 9.9 N
H) F net = 9.9 N
A) net force = upward force - downward force
= 4 - 4 = 0
B) net force = rightward force - leftward force = 4 - 3 = 1 N
C) net force
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = \(\sqrt{25}\) = 5 N
D) F net = \(\sqrt{-4^{2} + (-3)^{2} }\) = 5 N
E) balancing horizontal forces
rightward force - leftward force = 5 - 2 = 3 N
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = 5 N
F) balancing vertical forces
-5 + 2 = -3 N
using Pythagoras theorem
\(\sqrt{(-4)^{2} +(-3) ^{2} }\) = 5 N
G) using Pythagoras theorem
F net = \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
H ) balancing horizontal forces
10 - 3 = 7 N
\(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
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A 6kg block of ice on a table is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1
- 13N and F2 = 111, find (A) Draw a FBD (B) the acceleration of the ice and (C) The normal force exerted on it by
the table.
Answer:15n and 16n
Explanation:
a 6kg block of ice on a table is acted by 2 forces
When light travels through a small hole, it appears to be an observer that the light spreads out, blurring the outline of the hole. Does this observation support the theory of light as a wave, or light being made of particles? Explain.
Answer:
support lights as a wave
Explanation:
In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.
The mass on the spring in this diagram is in harmonic motion between x = -5
cm and x = 5 cm.
At which point does the mass have the most kinetic energy
Answer:
The mass will have the most KE at the midpoint of motion (velocity is a maximum)
Total Energy = KE + PE = constant
At zero displacement the potential energy equals zero and the kinetic energy is a maximum.
Answer:
I think it's point C but I'm not sure
A slanted surface used to raise an object is a(n)
Answer:
Inclined Plane
Explanation:
Explain why angular velocity of the Earth increases when it comes closer to the Sun in its orbit.
The angular velocity of the Earth refers to the rate at which the Earth rotates around its axis. When the Earth comes closer to the Sun in its orbit, its angular velocity increases. This can be explained by considering the conservation of angular momentum.
Angular momentum is a property of rotating objects and is defined as the product of the moment of inertia and angular velocity. In the case of the Earth, as it moves in its elliptical orbit around the Sun, its distance from the Sun changes. According to the conservation of angular momentum, the total angular momentum of the Earth-Sun system remains constant unless acted upon by external torques.
When the Earth is closer to the Sun in its orbit, its moment of inertia remains relatively constant since it is primarily determined by the distribution of mass within the Earth. Therefore, to conserve angular momentum, if the distance between the Earth and the Sun decreases, the angular velocity of the Earth must increase.
This increase in angular velocity results in a shorter rotational period, meaning the Earth completes one rotation around its axis in a shorter amount of time. This is why we experience shorter days when the Earth is closer to the Sun in its orbit.
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The current through an inductor of inductance L is given by I(t) = Imax sin(ωt).
(a) Derive an expression for the induced emf in the inductor as a function of time.
(b) At t = 0, is the current through the inductor increasing or decreasing?
(c) At t = 0, is the induced emf opposing or aiding the flow of the charge carriers? (Remember that the direction of a positive induced emf is the same as the current direction and the direction of a negative induced emf is opposite the current direction.)
(d) How are the answers to parts b and c consistent with the behavior of inductors discussed in the text?
Answer:
(a) \(emf_L=-LI_{max}\omega cos(\omega t)\)
(b) neither increasing or decreasing
(c) opposite to the flow of charge carriers
Explanation:
The current through an inductor of inductance L is given by:
\(I(t)=I_{max}sin(\omega t)\) (1)
(a) The induced emf is given by the following formula
\(emf_L=-L\frac{dI}{dt}\) (2)
You derivative the expression (1) in the expression (2):
\(emf_L=-L\frac{d}{dt}(I_{max}sin(\omega t))\\\\emf_L=-LI_{max}\omega cos(\omega t)\)
(b) At t=0 the current is zero
(c) At t = 0 the emf is:
\(emf_L=-\omega LI_{max}\)
w, L and Imax have positive values, then the emf is negative. Hence, the induced emf is opposite to the flow of the charge carriers.
(d) read the text carefully
At t zero, the current through the inductor neither increasing nor decreasing because current is zero.
The current through an inductor of inductance L can be calculated by
\(\bold {I_t = I_m_a_x sin (\omega t)}\).........1
(a) The induced emf can be calculated by
\(\bold {emf_L = - L \dfrac {dI}{dt}}\)............2
Derivative the equation (1) in the equation (2)
\(\bold {emf _L= -L \dfrac {d (I _m_a_x sin (\omega t)} {dt}}\\\\\bold {emf _L= -L (I _m_a_x \omega cos( \omega t) }\)
(b) At t=0 the current is zero,
(c) At t = 0 the emf is:
\(\bold {emf_L = -\omega LI _m_a_x}\)
Therefore, at t zero, the current through the inductor neither increasing nor decreasing because current is zero.
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A 0.414 kg object is at rest at the origin of a coordinate system. A 2.08 N force in the positive x direction acts on the object for 1.57 s. What is the velocity at the end of this interval
Answer:
The value is \(v = 7.89 \ m/s\)
Explanation:
From the question we are told that
The mass of the object is \(m = 0.414 \ kg\)
The force is \(F = 2.08 \ N\)
The time taken is \(t = 1.57 \ s\)
Generally the force acting on the object according to Newton's second law is
\(F = \frac{ m (v -u )}{t}\)
=> \(v = \frac{F * t}{m} + u\)
Here u is the initial velocity with value 0 m/s since the object was initially at rest
\(v = \frac{2.08 * .57}{0.414 } + 0\)
\(v = 7.89 \ m/s\)
A car with a mass of 1500 kg is traveling at a speed of 30 m/s what force must be applied to stop the car in 3 seconds
Answer:
15 000 N
Explanation:
Newtons Law 2. When a body is acted upon by a force, the time rate of change of its momentum equals the force.
F=ma
a=30m/s / 3s=10m/c²
F=1500kg*10m/c²=15 000 N
What are the effects of electric current. What are the factors affecting the heat produced in a conductor.
Answer:
i got u
Explanation:
Effects of Electric Current:
Electric current is the flow of electric charges in a conductor. When a current passes through a conductor, it produces several effects, some of which include:
1. Heating effect: The heating effect of electric current occurs when the current passes through a conductor, and the resistance of the conductor converts some of the electrical energy into heat. This effect is utilized in electric heaters, electric stoves, and incandescent light bulbs.
2. Magnetic effect: When an electric current passes through a conductor, it produces a magnetic field around the conductor. This effect is utilized in devices like motors and generators.
3. Chemical effect: Electric current can also cause chemical reactions to occur. This effect is utilized in batteries and electrolysis.
4. Electric shock: When electric current passes through the human body, it can cause an electric shock, which can be fatal.
Factors Affecting the Heat Produced in a Conductor:
When an electric current flows through a conductor, some of the electrical energy is converted into heat due to the resistance of the conductor. The amount of heat produced in the conductor is dependent on several factors, including:
1. Current: The higher the current flowing through the conductor, the greater the amount of heat produced.
2. Resistance: The higher the resistance of the conductor, the greater the amount of heat produced.
3. Time: The longer the current flows through the conductor, the greater the amount of heat produced.
4. Material: Different materials have different resistances and will therefore produce different amounts of heat for the same current flowing through them.
5. Cross-sectional area: The larger the cross-sectional area of the conductor, the less the amount of heat produced for the same current flowing through it.
6. Temperature: The temperature of the conductor also affects the amount of heat produced. As the temperature of the conductor increases, its resistance also increases, and more heat is produced for the same current flowing through it.
An ideal spring has a spring constant (force constant) of 60 N/m. How much energy does it store
when it is stretched by 1.0 cm?
When the spring is stretched by 1.0 cm, it stores 0.003 J of energy.
What does a spring's spring constant mean?The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies. The stiffer the spring is and the harder it is to stretch, the larger the spring constant.
The following equation describes the energy held in an ideal spring that is stretched or compressed by a distance x from its equilibrium position:
E = (1/2) k x^2
where k = spring constant and x = distance stretched or compressed.
The spring constant k = 60 N/m
distance stretched x = 1.0 cm = 0.01 m.
Substituting these values,
E = (1/2) (60 N/m) (0.01 m)^2
E = 0.003 J
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Highschool Physics
1. The driver of a car traveling at 9.0m/s is honking their horn. The horn has a frequency of 625 Hz. If the car is moving toward a person waiting at the crosswalk, what frequency of the horn does the person hear?
2. As the same car from question#1 passes the person, what frequency of the horn does the person hear as the car moves away from them?
Using the formula for the Doppler effect:
f' = (v + vr) / (v + vs) * f
Given:
Source frequency (horn): f = 625 Hz
Speed of sound: v = 343 m/s (approximate value at room temperature)
The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.
The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.
Thus:
f' = (v + vr) / (v + vs) * f
= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz
= (343 m/s) / (352 m/s) * 625 Hz
≈ 609 Hz
Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.
(2)Using the same Doppler effect formula:
f' = (v - vr) / (v - vs) * f
In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.
The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.
Thus:
f' = (v - vr) / (v - vs) * f
= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz
= (343 m/s) / (352 m/s) * 625 Hz
≈ 609 Hz
In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.
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A spring stretches 5 cm when a 300-N mass is suspended from it. Calculate the spring constant in N / m .
Answer:
Spring constant in N / m = 6,000
Explanation:
Given:
Length of spring stretches = 5 cm = 0.05 m
Force = 300 N
Find:
Spring constant in N / m
Computation:
Spring constant in N / m = Force/Distance
Spring constant in N / m = 300 / 0.05
Spring constant in N / m = 6,000
Dimensional Analysis
9.52 x 104 m to um
the calculated answer in micrometer is 9.52 x 10⁻²
Dimensional analysis is the analysis of the relationships between different physical quantities by identifying their base quantities (such as length, mass, time, and electric current) and units of measure (such as miles vs. kilometers, or pounds vs. kilograms) and tracking these dimensions as calculations or comparisons are performed. The conversion of units from one dimensional unit to another is often easier within the metric or SI system than in others, due to the regular 10-base in all units.
9.52x 10⁴
1 m= 10⁶ μm
dimensional analysis = 9.52 x 10⁴ x 10⁻⁶
=9.52 x 10⁻² μm
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