Calculate the number of moles of excess reactant that will be left-over when 56.0g of CaCl2 reacts with 64.0g of Na2SO4: CaCl2+Na2SO4 -->CaSO4+2NaCl

There are approximately 4.31 × 10²² atoms of nitrogen in 1g of ammonia (NH₃).  There are approximately 8.62 × 10²² atoms of nitrogen in 1g of hydrazine (N₂H₄).

To calculate the number of atoms of nitrogen in a given amount of a compound, we need to use the molar mass of nitrogen and the formula of the compound.

The molar mass of nitrogen (N) is approximately 14.01 g/mol.

Ammonia (NH₃):

The formula for ammonia is NH₃. It contains one atom of nitrogen.

To calculate the number of moles of nitrogen element in 1g of ammonia, we divide the given mass by the molar mass of nitrogen:

Number of moles of nitrogen = 1g / 14.01 g/mol ≈ 0.0714 mol

Since 1 mole of a substance contains Avogadro's number of particles (6.022 × 10²³), the number of atoms of nitrogen in 0.0714 mol is:

Number of atoms of nitrogen = 0.0714 mol × 6.022 × 10²³ atoms/mol ≈ 4.31 × 10²² atoms

Therefore, there are approximately 4.31 × 10²² atoms of nitrogen in 1g of ammonia (NH₃).

Hydrazine (N₂H₄):

The formula for hydrazine is N₂H₄. It contains two atoms of nitrogen.

To calculate the number of moles of nitrogen in 1g of hydrazine, we again divide the given mass by the molar mass of nitrogen:

Number of moles of nitrogen = 1g / 14.01 g/mol ≈ 0.0714 mol

Since there are two atoms of nitrogen in each molecule of hydrazine, the number of atoms of nitrogen in 0.0714 mol is:

Number of atoms of nitrogen = 0.0714 mol × 2 × 6.022 × 10²³ atoms/mol ≈ 8.62 × 10²² atoms

Therefore, there are approximately 8.62 × 10²² atoms of nitrogen in 1g of hydrazine (N₂H₄).

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--The  question is incomplete, the given complete question is:

"What number of atoms of nitrogen are present in 1g of each of the compounds that is  ammonia (NH₃) and hydrazine (N₂H₄)?"--

Answer:

The specific heat of iron is 0.449 J/g°C.

Explanation:

First, let's see the formula of specific heat:

Now, we have to replace the given data in the formula, where q = 8980 J, m = 200 g and ΔT = Final temperature - Initial temperature = 120 °C - 20 °C = 100 °C:

The specific heat of iron is 0.449 J/g°C.

Answer:

i dont know thank you soo much

Answer: what question?

Explanation:

Answer:

theirs no question

Explanation:

no question or picture

Answer:

The main difference between the heat of formation and heat of reaction is that heat of formation is the amount of energy either absorbed or released during the formation of a compound whereas heat of reaction is the amount of energy either absorbed or released during any chemical reaction.

Answer:

i don't really know but i think  it's 61 g

Explanation:

if im wrong i soooooooooooooooooooooooooooooooooooooooooooooooooooooooooo sorry

The smallest and least massive atomic particle is the electron, which is negatively charged.Due to the electron's extremely small mass, it is not counted inside the element's atomic number.

Although they are very small and possess a mass of 1/1850 of that of a protons or neutron, electrons carry a negative charge.Since they are so tiny, they do not, in reality, add to the weight of the atom.

These particles are frequently referred to it as subatomic particles since they are the building blocks of atoms.There are protons, neutrons, and electrons, three types of subatomic particles.Protons and electrons, two of a subatomic particles, each have an electrical charge of one or the other.

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Answer:

Since pure natural gas (a.k.a. methane) has no smell, utility companies add smelly, sulfur-containing odorants called mercaptans, or thiols, to warn us if anything is amiss with our pipelines. ... Olfactory receptors are present in specialized sensory cells called olfactory sensory neurons, which line our noses

Explanation:

hope this helps have a good rest of your night :) ❤

Solids are the most organized state of matter. States of matter change when energy is added or removed. Gas is the state of matter has the most movement of its particles.

The states of matter are the different forms of the matter in which it can exist. They are solids, liquids and gases. Solids are the states of matter in which molecules are very near to each other. They have fixed shape and volume. Liquids is the states of matter in which molecules are a little far from each other. They have different shape and fixed volume. Gas is the states of matter in which molecules are a very far from each other. They have different shape and different volume.

There are two more states of matter which are called as Plasma, Bose Einstein Condensate.

Plasma have highest energy and Bose Einstein Condensate have lowest energy.

Therefore, Solids are the most organized state of matter. States of matter change when energy is added or removed. Gas is the state of matter has the most movement of its particles.

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The electron pair geometry of a molecule with sp3 hybridization and 1 lone pair is trigonal pyramidal.

This means that there are 4 electron pairs around the central atom, with 3 bonded atoms and 1 lone pair. The lone pair takes up more space than a bonded pair, causing the bond angles to be less than the ideal 109.5 degrees. Examples of molecules with this electron pair geometry include ammonia (NH3) and water (H2O). Overall, understanding electron pair geometry is important in predicting the physical and chemical properties of molecules, as well as their reactivity in chemical reactions. In a molecule with sp3 hybridization and 1 lone pair, the electron pair geometry is tetrahedral. In this configuration, there are four regions of electron density surrounding the central atom, including the lone pair and three bonded atoms. The presence of the lone pair causes a slight distortion in the molecular geometry, resulting in a trigonal pyramidal shape for the molecule itself. The bond angles in this type of geometry are approximately 109.5 degrees. Examples of molecules with sp3 hybridization and 1 lone pair include ammonia (NH3) and water (H2O).

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A - convection

B - conduction

C - radiation

D - convection

The process of fractionation is based on boiling point of the components of a solution.

What will separate out during the fractional distillation process depends on the boiling point of the substance. When the difference between the boiling points of two or more miscible liquids is less than 25 K, it is used to separate the mixture. The boiling point affects fractional distillation. Since different hydrocarbons have different boiling points, fractional distillation can be used to easily purify them.

Therefore, factional distillation makes use of boiling point. Due to the different boiling points of the various liquids, fractional distillation is effective. Vapors rise through a column that is hot at the bottom and cooler at the top when the mixture is heated.

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The value of the bond energy X in the reaction is 81 kJ/mol.

We know that the bond energy of the substance has to do with the energy that would have to be supplied so as to break the bond that is in the substance. This is also the energy that we would need so as to be able to form the bond.

Let us all now recall that we can be able to obtain the enthalpy of the reaction from the bond energies of the reactants and the products in the reactants in which case we would have;

Sum of bond energies of the reactants - Sum of bond energies of the products

56 = [5(413) + 339] - [431 + 4(413) + X + 346]

56 = (2065 + 339) - (2429 + X)

56 =  2429 - 2404  - X

X = 81 kJ/mol

Thus, we can see that the bond energy of the carbon carbon double bond as we can see is 81 kJ/mol.

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Answer:

Therefore mole ratio is \(H_{2}O\) : \(KAl(SO_{4} )_{2}\) is 12 :1  

Empirical formula is \(KAl(SO_{4} )_{2}. 12 H_{2}O\).

Explanation:

The chemical formula of a hydrate  

Moles of anhydrous \(KAl(SO_{4} )_{2}\)  

Molar mass of \(KAl(SO_{4} )_{2}\) = 258.21 g /mol  

Mass of anhydrous \(KAl(SO_{4} )_{2}\) = [mass of aluminum cup + alum after 2nd heating] –[ mass of empty cup]  

                                                   = 3.5 g – 2.4 g  

                                                   = 1.1 g

Moles of \(KAl(SO_{4} )_{2}\)= mass / molar mass  

                                    = 1.1 g / 258.21 g per mol  

                                   = 0.00426 mol \(KAl(SO_{4} )_{2}\)

The mole ratio of the H2O to \(KAl(SO_{4} )_{2}\)

Mole ratio = moles of H2O/ moles of \(KAl(SO_{4} )_{2}\)

                  = 0.05 mol H2O / 0.00462 mol \(KAl(SO_{4} )_{2}\)

                 = 11.7

We can round the 11.7 to closest whole number = 12

Therefore mole ratio is \(H_{2}O\) : \(KAl(SO_{4} )_{2}\) is 12 :1  

Empirical formula = \(KAl(SO_{4} )_{2}. 12 H_{2}O\)  

So we have 12 moles of water as the water of hydration in the empirical formula.  

Alum hydrate is that the white crystalline solid after heating it'll start melting due to the water of hydration present in it then again solid will remain within the aluminum cup once all the water is given off within the sort of vapors.  

b) if the scholar used 2.20 g of the sample but within the calculation, he started with 2.0 g sample then  

when the mass of water is calculated using this data the mass of water is going to be higher therefore it gives more moles of water within the hydrate.  

So the final answer is going to be artificially high.

Helium: The new volume of the balloon is 0.6182 L.

Colorless, odourless , tasteless, inert, non-toxic helium is a monatomic gas. It is the lightest element in the periodic table and the second most abundant element in the universe.

The new volume of the balloon can be calculated using the ideal gas law, which states that PV = nRT, where P is the n represents the number cubic moles of gas, V represents the volume, R is the real gases constant, and the temperature is T.

First, we need to calculate the number of moles of helium in the balloon after the additional 0.670 grams have been added:
n = 0.670 g He/4.003 g/mol = 0.167 mol

The total number of moles in the balloon is now 0.267 mol. We can use the ideal gas law to calculate the new volume:

V = (0.267 mol)(0.0821 L·atm/K·mol)(273 K)/1 atm = 0.6182 L

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Answer:

Using the formula cards again, add the coefficient of 2 in front of the formula and have them recalculate the number of each element and the total number of atoms in each element.

Explanation:

The number of elements in a compound is counted by identifying and counting the chemical symbols represented in the chemical formula

A compound is a substance that is a mixture of more than one elements.

Compounds are made of two or more elements. These elements are represented by their symbols. These symbols can be identified and the number of elements represented by these symbols are counted.

For example, in the compound \(H_2O\):

H represents Hydrogen

O represents Oxygen

The elements in Water ( \(H_2O\)) are Hydrogen and Oxygen

Therefore, the number of elements in  \(H_2O\) is 2

Also in, \(NaCl\)

The elements are Sodium(Na) and Chlorine(Cl)

There are two elements in NaCl

Hence, the number of elements in a compound is counted by identifying and counting the chemical symbols represented in the chemical formula

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The mass of oxygen is 128 g

Given that a sample of gas consists of oxygen (molecular mass 32.0 g/mol) and neon (20.0 g/mol). The sample has a mass of 226 g and contains a total of 8.00 moles of gas. We are required to find the mass of oxygen in the sample.

Let us suppose that the number of moles of oxygen is x. Now, we know that the total number of moles of gas is 8 moles. Therefore, the number of moles of neon is (8 - x).

Molar mass of oxygen = 32 g/mol

We can calculate the mass of oxygen from the number of moles of oxygen and molar mass of oxygen as follows:

Number of moles of oxygen × Molar mass of oxygen = Mass of oxygenx × 32 = Mass of oxygen

Let us find the mass of oxygen:

Mass of neon = Total mass of gas – Mass of oxygen

226 – Mass of oxygen = Mass of neon

226 – Mass of oxygen = (8 – x) × 20

Simplifying the equation:

226 – Mass of oxygen = 160 – 20x + x

226 – Mass of oxygen = 160 – 19x

Mass of oxygen = 66 – 19x

The total number of moles of gas is 8 moles

Hence, Number of moles of oxygen + Number of moles of neon = Total number of moles of gasx + (8 - x) = 8⇒ 8 = 8Therefore, the value of x = 4

We can calculate the mass of oxygen as follows:

Number of moles of oxygen × Molar mass of oxygen = Mass of oxygen

4 × 32 = 128 g

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Chemical reactions are the various types of permanent changes which occur in substances and which produce new substances .

Chemical reactions are changes which occur in the arrangement of atoms in a substance resulting in the formation of new substances.

There are many types of chemical reactions such as:

The various types of chemical reactions that occur contribute to the numerous compounds and substance in existence today.

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The mass equivalence of one photon of this wavelength if a sodium flame has a characteristic yellow color due to emissions of wavelength 953 nm is 2.317 * \(10^{-36}\) kg.

The wavelength of a wave explains the distance of the wave. It is described as the distance from the "crest" of one wave to the crest of the next wave is the wavelength. Wavelength can be measured from the "trough" that is the bottom of one wave to the trough of the next wave and get the same value for the wavelength.

Wavelength is said to be the distance between identical points in the adjacent cycles of a waveform signal which is propagated in space or along a wire. We can determine the mass equivalence by using the expression of wavelength,

λ = h/ mu

When a sodium flame has a characteristic yellow color due to emissions of wavelength 953 nm.

m = h / λ * u

    =>  6.626×\(10^{-34}\) / 953 . \(10^{-9}\) * 3 . \(10^{8}\)

    =>  2.317 * \(10^{-36}\) kg

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The complete question is,

A sodium flame has a characteristic yellow color due to emissions of wavelength 953 nm. what is the mass equivalence of one photon of this wavelength?

Answer: not sure on actual answer, but heres a answer on a similar question with just different quantities.

Explanation: just minus the terms i got and u should be okay

Taking into account the definition of dilution, the concentration of the diluted solution is 0.063 M.

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

0.197 M× 2.42 mL= Cf× 7.55 mL

Solving:

(0.197 M× 2.42 mL)÷ 7.55 mL= Cf

0.063 M= Cf

In summary, the concentration of the diluted solution is 0.063 M.

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The isotope symbols for the radioisotopes mentioned, which are used in medicine.
a) Technetium-99: ₄₃Tc₉₉                                                  b) Cobalt-60: ₂₇Co₆₀

Now, by elaborating the answer we found that :

a) Technetium-99:
To write the isotope symbol for Technetium-99, we need the element symbol for Technetium and its atomic number. Technetium has the element symbol "Tc" and an atomic number of 43. So, the isotope symbol for Technetium-99 is written as: ₄₃Tc₉₉

b) Cobalt-60:
To write the isotope symbol for Cobalt-60, we need the element symbol for Cobalt and its atomic number. Cobalt has the element symbol "Co" and an atomic number of 27. So, the isotope symbol for Cobalt-60 is written as: ₂₇Co₆₀

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Explanation:

To calculate the amount of water needed to dilute the solution of potassium hydroxide and change its pH from 12.0 to 11.0, we need to use the formula for calculating the pH of a diluted solution.

The formula is:

pH = -log[H+]

where [H+] is the concentration of hydrogen ions in moles per liter.

Since we are diluting the solution by adding water, the concentration of [OH-] (hydroxide ions) will decrease proportionally to the volume of water added. This means that we can use the following equation to calculate the new concentration of [OH-]:

[OH-]1V1 = [OH-]2V2

where V1 is the initial volume of the solution, [OH-]1 is the initial concentration of hydroxide ions, V2 is the final volume of the solution after dilution, and [OH-]2 is the final concentration of hydroxide ions.

We know that the initial pH is 12.0, which means that [OH-]1 = 10^-2.0 M = 0.01 M.

We want to change the pH to 11.0, which means that [OH-]2 = 10^-11.0 M = 1 x 10^-11 M.

We also know that we are adding water to dilute the solution, but we don't know how much water we need to add yet. Let's call this volume of water "Vw".

Using the equation above, we can solve for V2:

[OH-]1V1 = [OH-]2V2

(0.01 M)(100 ml) = (1 x 10^-11 M)(100 ml + Vw)

V2 = (0.01 M)(100 ml)/(1 x 10^-11 M) - Vw

V2 = 10^12 ml - Vw

Now we can use this value for V2 in the pH formula to calculate the new pH:

pH = -log([H+])

[H+] = Kw/[OH-]

Kw is the ion product constant for water, which is equal to 1 x 10^-14 at room temperature.

[H+] = (1 x 10^-14)/(1 x 10^-11)

[H+] = 1 x 10^-3 M

pH = -log(1 x 10^-3)

pH = 3

We want to achieve a pH of 11.0, so we need to add enough water to bring down the pH from 12.0 to 11.0. This means that we need to add enough water so that V2 becomes:

V2 = (0.01 M)(100 ml)/(1 x 10^-11 M) - Vw = 10^11 ml

Therefore, we need to add:

Vw = V2 - initial volume of solution

Vw = (10^11 ml) - (100 ml)

Vw = 99999900 ml or approximately 100 million ml or 100 cubic meters of water.

So, in order to change the pH of a solution of potassium hydroxide with a pH of 12.0 to a pH of 11.0 by adding water only, you would need to add approximately 100 million milliliters or about 100 cubic meters of water.

Answer:

232.04u is the atomic weight of Thorium.

Answer:

oxidation-reduction reaction

Explanation:

na was oxidized and ag was reduced

ag^1 +1e = ag

na= na^1 +1e

Answer:

OJ.J. Thomson

Explanation:

Answer:

yes they are < 3

Explanation:

While there is 1 sodium atom on either side of the arrow in this equation, closer examination reveals that there are chlorine atom atoms inside the reactants and just one inside the products.

Both the sodium cation (Na+) as well as the chloride anion (Cl-), which are created when a sodium atom donates an electron to the a chlorine atom, have full valence shells and are therefore more stable energetically. The reaction is highly exothermic and generates a lot of heat energy in addition to a bright yellow light.

Ionic bonding exists in NaCl. In order for Na to become positive charge (Na+), an electron is lost, and for Cl to become negatively charged, an electron is gained (Cl-). Then, the ion pairs with opposing charges combine to make sodium chloride.

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The molecular formula of the unknown compound is C2H2O2.

To determine the molecular formula of the unknown compound, we need to calculate the empirical formula first and then find the multiple of its subscripts to obtain the molecular formula.

Given:

Percentage of carbon = 40.0%

Percentage of hydrogen = 6.7%

Percentage of oxygen = 53.3%

Molecular mass = 60.0 g/mol

Step 1: Convert the percentages to grams.

Assuming we have 100 grams of the compound:

Mass of carbon = 40.0 g

Mass of hydrogen = 6.7 g

Mass of oxygen = 53.3 g

Step 2: Convert the masses to moles using the molar masses of the elements.

Molar mass of carbon = 12.01 g/mol

Molar mass of hydrogen = 1.008 g/mol

Molar mass of oxygen = 16.00 g/mol

Number of moles of carbon = Mass of carbon / Molar mass of carbon

= 40.0 g / 12.01 g/mol

= 3.332 mol

Number of moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen

= 6.7 g / 1.008 g/mol

= 6.648 mol

Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen

= 53.3 g / 16.00 g/mol

= 3.331 mol

Step 3: Determine the empirical formula by dividing the moles by the smallest value.

Dividing the moles of carbon, hydrogen, and oxygen by 3.331 gives approximately 1 for each element.

So, the empirical formula of the compound is CHO.

Step 4: Determine the multiple of the subscripts to obtain the molecular formula.

To find the multiple, we divide the molecular mass by the empirical formula mass.

Molecular mass = 60.0 g/mol

Empirical formula mass = (12.01 g/mol) + (1.008 g/mol) + (16.00 g/mol) = 29.018 g/mol

Multiple = Molecular mass / Empirical formula mass

= 60.0 g/mol / 29.018 g/mol

= 2.07

Rounding to the nearest whole number, we get 2.

Therefore, the molecular formula of the unknown compound is C2H2O2.

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