The change in the potential energy is 3647.14 J.if the distance between floors is 3.93 m.
What is potential energy?The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.
Given data;
mass(m)=94.6 kg
Height,h= 3.93 m.
PE=?
The potential energy is mainly dependent upon the height of the object.
The potential energy is found as;
Potential energy change = mg(h₂-h₁)
Potential energy change = 94.6×9.81×(3.93-0)
Potential energy change= 3647.14 J.
Hence, the change in potential energy will be 3647.14 J.
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the maximum allowed coefficient of performance for a heat pump operating between temperatures of 2 oc and 15 o c is:
A heat pump's operating overall efficiency is just 15.88, claims the inquiry.
What is heat in reality? What is the name of heat energy?Heat energy is created by the movement of tiny atoms, ions, or atoms in solid, liquids, and gases. Overheating can be transferred of one thing to another. When two items are already at varying temperatures from one another, a movement or exchange called heat occurs. Atoms and molecules move more quickly and clash when the temperature rises, producing heat generated (also known as heat energy). The power that comes from the heated object's temperature is referred to as thermal energy.
Briefing:Maximum COP of heat pump:
COP = \(T_{H} /T_{H} - T_{C}\)
Here, \(T_{H}\) = 271 K and \(T_{C}\) = 288 K
Hence, COP = 271/288-271
COP = 15.88
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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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A 100 kg block slides down a frictionless ramp which is at an angle of 26.6 ∘ with the horizontal. Find the magnitude of the velocity of the block when it gets to the bottom of the ramp if the length of the incline is 50 meters. V=_____m/s
The block accelerates down the ramp due to the component of its weight that acts parallel to the ramp; this force has magnitude
(100 kg) g sin(26.6°) ≈ 438 N
(Note that the positive sign here means we take "down the ramp" to be the positive direction.)
Since the ramp is frictionless, this is the only force acting on the block in this direction. By Newton's second law, the block's acceleration is a such that
438 N ≈ (100 kg) a ⇒ a ≈ 4.38 m/s²
The block accelerates uniformly, so that it attains a speed v as it moves 50 m such that
v² = 2a (50 m)
Solve for v :
v = √(2a (50 m)) ≈ 20.9 m/s
SOMEBODY ONCE TOLD ME THE WORLD WAS GONNA ROLL ME
I AIN'T THE SHARPEST TOOL IN THE SHED~
SHE WAS LOOKING KINDA DUM WITH HER FINGER AND HER THUMB
IN THE SHAPE OF AN "L" ON HER FOREHEAD~
WELL THE YEARS START COMING AND THEY DON'T STOP COMING
FED TO THE RULES AND I HIT THE GROUND RUNNING
DIDN'T MAKE SENSE NOT TO LIVE FOR FUN
YOUR BRAIN GETS SMART BUT YOUR HEAD GETS DUM
SO MUCH TO DO, SO MUCH TO SEE--
SO WHATS WRONG WITH TAKING THE BACKSTREETS?
YOU'LL NEVER KNOW IF YOU DON'T GO
YOU'LL NEVER SHINE IF YOU DON'T GLOW.
Answer:
shrek
Explanation:
allstar
The index of refraction of n-propyl alcohol is 1.39. Find the angle of refraction of light in that medium if light comes from air with an angle of incidence of 55 degrees.
Answer:
36.11 degrees
Explanation:
index of refraction n = sin i/sinr
i is the angle of incidence
r is the angle of refraction
Substitute into the expression
1.39 = sin55/sin(r)
1.39 = 0.8191/sin(r)
sin(r) = 0.8191/1.39
sin(r) = 0.5893
r = arcsin(0.5893)
r = 36.11
hence the angle of refraction of light is 36.11 degrees
A heavy bank-vault door is opened by the application of a force of 300 N directed perpendicular to the plane of the door at a distance of 0.80 m from the hinges. What is the torque?
300 Nm
240 Nm
375 Nm
120 Nm
The torque would be 240 Nm
Which describes the reaction of a substance to form one or more new substances?
a physical change
a chemical change
a change of state
The angle of incidence always equals what?
Answer:
Angle Of Incidence Formula The angle of incidence is equal to the reflected angle through the law of reflection. The angle of incidence and the angle of reflection is always equal, and they are both on the same plane along with the normal. 2,44,451
Explanation:
that could help you with work.
Answer:
to the angle of reflection
Explanation:
Calculate how much work the force of gravity does on the sphere from B to C .
(a) The work done by the force of gravity from A to B is 4.41 Joules.
(b) The work done by the force of gravity from B to C is zero.
(c) The work done by the force of gravity from A to C is 4.41 Joules.
a) To calculate the work done by the force of gravity from A to B, we need to consider the change in potential energy. The potential energy at point A is maximum due to the maximum angle of 35.0∘ to the left of vertical, while at point B, the string is vertical, and the potential energy is zero.
The change in potential energy (ΔPE) is given by:
ΔPE = m * g * h
where m is the mass of the sphere (0.500 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the change in height.
Since the potential energy at point A is maximum, the change in height is equal to the length of the string (0.900 m).
ΔPE = 0.500 kg * 9.8 m/s^2 * 0.900 m = 4.41 J
Therefore, the work done by the force of gravity from A to B is 4.41 Joules.
b) From B to C, the change in height is zero since the string is already vertical. Hence, the work done by the force of gravity from B to C is zero.
c) The total work done by the force of gravity from A to C is the sum of the work done from A to B and from B to C.
Total work = Work from A to B + Work from B to C = 4.41 J + 0 J = 4.41 J
Therefore, the work done by the force of gravity from A to C is 4.41 Joules.
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I think it is the question:
A Pendulum Is Made Up Of A Small Sphere Of Mass 0.500 Kg Attached To A String Of Length 0.900 M. The Sphere Is Swinging Back And Forth Between Point A, Where The String Is At The Maximum Angle Of 35.0∘ To The Left Of Vertical, And Point C, Where The String Is At The Maximum Angle Of 35.0∘ To The Right Of Vertical. The String Is Vertical When The Sphere Is At
A pendulum is made up of a small sphere of mass 0.500 kg attached to a string of length 0.900 m. The sphere is swinging back and forth between point A, where the string is at the maximum angle of 35.0∘ to the left of vertical, and point C, where the string is at the maximum angle of 35.0∘ to the right of vertical. The string is vertical when the sphere is at point B.
a) Calculate how much work the force of gravity does on the sphere from A to B.
b) Calculate how much work the force of gravity does on the sphere from B to C.
c) Calculate how much work the force of gravity does on the sphere from A to C.
WILL DO BRAINLIEST A jar contains seven pink, 6 orange, and four blue marbles. If you pick one without looking, what is the probability that the marble you pick will be orange?
6/10
6/17
11/17
7/11
Answer:
Choice 2: 6/17
Explanation:
4+7=11. 6+11= 17. so it's 6/17
You have been contracted to map the Ryerson Campus at a scale of 1:1,000 using 1:3,000 photographs. It is required that you use photogrammetric techniques to perform the mapping using scanned (i.e., digitized) aerial photographs. The aerial photographs are taken with a focal length of 152.000 mm and have a 230mm by 230mm format. The aerial camera has both side and corner fiducials. The camera calibration information is available on a camera calibration report. Answer the following questions keeping in mind that you must choose a scanning resolution (in microns or dpi).
1. You must perform a fiducial transformation (i.e., interior orientation) using a 2-D transformation. What fiducial transformation model would you use and why? What magnitude of residuals would you expect?
2. If you adopted a local Cartesian coordinate system, which of the following image coordinate corrections would you apply and what would be their expected order of magnitude?
principal point offsets,
radial lens distortion,
atmospheric refraction,
earth curvature.
An aerial photographic image's corners, edge-centers, or both may contain a series of marks known as fiducial marks. These traces are recorded on the original film by the camera.
What are the purposes of fiducial marks?Fiducial markers are tiny metal objects, usually made of gold, that are positioned inside or close to a tumor to help direct the placement of radiation beams during therapy. They are about the size of a grain of rice.
Fiducial markers: how do they function?Tiny metal things are called fiducial markers (about the size of a grain of rice). They assist your healthcare professionals in aligning the radiation beams and guarantee that your radiation therapy is administered consistently.
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Fiducial marks are a set of marks that can be found in the corners, edge-centers, or both of an aerial photographic image. The camera captures these traces on the original film.
Given the Ryerson Campus is at a scale of 1:1000
Then the photographic scale (s) = 1:3000
The focal length of camera (f) = 152mm = 0152m
The format is (k) = 230 x 230mm = 0.23m
the photographic scale (s) = F/H where H is the image height
1/3000 = 0.152 /H Then H = 456m
Assume that there is longitudinal overlap as P1 = 60% and side to side overlap as 30%. Therefore margin of ground photograph = (1-P1) x k/s
(1-0.6) x 0.23/1/3000 = 276mm
Now width of ground photograph = (1-0.3) x 0.23/1/3000 = 483m
Hence the central points are plotted within the area range in 276m x 483m magnitude.
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_NO+_O2 > _NO2 balance this
Answer:
4NO+2O2------>4NO2
that's the answer
A light-year equals about how many kilometers?
Answer:
9.461 × 10^12 Km s
..............................
A certain wave has a compressions and rarefactions.How should this wave be classified?
A) As a longitudinal wave
B)As a surface wave
C)A transverse wave
D)As an electromagnetic wave
This question involves the concepts of compression and rarefraction.
This wave should be classified as "A) a longitudinal wave".
Types of WaveA surface wave is a mechanical wave which propagates on the boundary interface between two different media.
A longitudinal wave is the wave in which the direction of travel of the wave and medium are the same. This wave consists of compressions and rarefactions.
A transverse wave is the wave in which the direction of travel of the wave and medium are perpendicular to each other. It consists of crests and troughs.
An electromagnetic wave is the one which consists of electric field and magnetic field vibrating perpendicular to each other.
Hence, the wave with compressions and rarefactions is classified as a longitudinal wave.
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At the football game is a crowd goes wild and does the wave what kind of wave is this an example of
The given example of a wave in the football game is of 'transverse wave'. The transverse wave is a wave in which points oscillates along the path at the right angle to the direction of travelling wave.
Use the data from Table D of your Student Guide to answer the questions. Be sure to round your answers to the nearest tenth.
Answer:
table??
Explanation:
Need a 5 paragraph essay in the eartsh layers and how they function/ benefit the earth!
There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.
However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.
Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.
Explanation:
Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is
pitched to the right with a velocity of 41.26 m/s.
The momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s.
What is the momentum of the baseball?The momentum of the baseball is calculated by applying the following formula as shown below;
P = mv
where;
m is the mass of the baseballv is the speed of the baseballThe momentum of the baseball is calculated as follows;
mass of the baseball = 0.14 kg
velocity of the baseball = 41.26 m/s
momentum, P = mv
P = 0.14 kg x 41.26 m/s
P = 5.78 kgm/s.
Thus, the momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s by applying the formula for linear momentum.
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The complete question is below:
Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is pitched to the right with a velocity of 41.26 m/s. What is the momentum of the baseball?
hanging spring when a 0.30 kg mass is suspended from a massless spring, the spring stretches a distance of 2.0 cm. let 2.0 cm be the rest position for the mass-spring system. the mass is then pulled down an additional distance of 1.5 cm and released. results for question 7. 7 1.5 / 1.5 points calculate the period of resulting oscillation in si units. correct answer: 0.284 results for question 8. 8 0 / 1.5 points calculate the total mechanical energy of the system in si units. incorrect answer: 166
the total mechanical energy of the system is: 0.09187 Joule
What is spring constant?"spring constant" (plural: "spring constants") a property of a spring that is determined by the force acting on the spring to the displacement it produces. The stiffness of the spring is quantified by the spring constant, k. For various materials and springs, it varies. The spring becomes stiffer and more challenging to stretch as the spring constant increases.
Given that,
mass (m) = 0.30 kg
distance (x) = 2.0 cm. = 2 × 10⁻² m
Thus, for balancing condition,
kx = mg
or, k = mg /x
or, k = (0.30 × 10) / (2 × 10⁻²)
or, k = 150 N/m
So, the value of spring constant is 150 N/m
Next, time period (T) = 2π √(m /k)
or, T = 2π √(0.30 / 150)
or, T = 0.2808 sec
Total stretches in spring constant = 2 cm + 1.5 cm = 3.5 cm
Total mechanical energy = 1/2 k x²
Total mechanical energy = 1/2 × (150) × (2 × 10⁻²)²
Total mechanical energy = 0.09187 Joule
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Name two examples of conservative forces
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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Which of the following is a true statement for a child's toy spinning in a circle at constant speed?
a) The speed is constant, the velocity is constant, and the angular velocity is constant. b) The speed is constant, the velocity is not constant, and the angular velocity is constant. c) The speed is constant, the velocity is not constant, and the angular velocity is not constant. d) The speed is constant, the velocity is constant, and the angular velocity is not constant.
explain your answer.
Answer:
B
Explanation:
I am pretty sure it is B as the speed is obviously constant but the velocity is not constant as it defines as the rate of speed AND DIRECTION meaning that it is not constant as it always changes direction. And angular velocity is constant.
A rocket has been fired upward to launch a stellite in its orbit name two forces acting on the rocket immediately after leaving the launching pad
Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.
1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.
This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.
2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.
The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.
Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.
However, the thrust force continues to be the dominant force propelling the rocket upward.
It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.
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How can you explain the process of reflection based from your experience?
Answer:
Reflection brings learning to life. Reflective practice helps learners find relevancy and meaning in a lesson and make connections between educational experiences and real life situations. It increases insight, and creates pathways to future learning. Reflection is called by many different names in the education field including processing, reviewing, and debriefing. I personally have moved towards referring to this key ingredient in teaching and group facilitation as reflection or reflective practice.
Explanation:
What does the slope represent? v^2/h = what variable?
Answer:
Slope measures the rate of change in the dependent variable as the independent variable changes.
Explanation:
A professor wants to conduct a study to investigate which kind of note-taking technique (hand-written or computer-based) is better for memory and recollection. He decides to split his class into two groups - hand-written notes and computer-based notes - and measure better memory and recollection via the next exam scores. The two note-taking groups are what variable in the study?
independent variable
dependent variable
control variable
extraneous variable
According to the professor's research, both handwritten notes and computer-based notes qualify as independent variables.
The professor's study considers handwritten notes and computer-based notes to be independent variables. These other qualities will be examined to see if they change depending on note-taking technique, including better memory and exam recall.
What kinds of variables are the groupings for taking notes?
Because they are being examined for their potential to influence other factors, the note-taking groups that use handwritten and computerised notes are regarded as independent variables.
Better exam memory and recall are those other variables, and their changes in response to note-taking methodology will be investigated.
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If a waterfall and a dam have the same height,
which one would have the most kinetic energy?
Explain why.
explain why a wrecking ball can destroy a building, but a yo-yo cant. Use the term kinetic energy in your explanation.
The kinetic energy of a body determines it's level of impact on the object in which it comes in contact with. Hence, the much larger kinetic energy exhibited by a wrecking ball compared to a yo-yo means that is has a much larger impact on a building than a yo-yo.
Kinetic Energy = 0.5mv²The kinetic energy of a body is a factor of it's velocity and mass as they are directly proportional.
The wrecking ball has a very large mass which is thousands of times larger than that of a yo-yo. Also, the velocity at which a wrecking ball is launched is higher than the velocity of a yo-yo.
This means that the kinetic energy of a wrecking ball is much higher than that of yo-yo. Hence, having much greater impact on a building compared to a yo-yo.
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you have water in two buckets of equal height.Your friend asked you which bucket contains the moat water.Now how did you find out .write short answer
To determine which bucket contains more water, I would pour the water from one bucket into the other until they are both at the same level. Then, I would compare the amount of water left in each bucket. The bucket with more water remaining is the one that originally had more water.
In Fig. 22−35 the four particles form a square of edge length a=5.00 cm and have charges q 1 =+10.0 nC,q 2 =−20.0 nC,q 3 =+20.0 nC, and q 4 =−10.0 nC, In unit vector notation, what net electric field do not particles produce at the square's center?
Net electric field produced by the four particles at the square's center is zero.
What is electric field?The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them is called an electric field.
Electric field produced by each particle at the center of the square can be calculated as:
E1 = k * q1 / (5/sqrt(2))^2 = 810^9 N/C * (1010^-9 C) / (5/sqrt(2))^2 = 410^9 N/C
E2 = k * q2 / (5/sqrt(2))^2 = 810^9 N/C * (-2010^-9 C) / (5/sqrt(2))^2 = -810^9 N/C
E3 = k * q3 / (5/sqrt(2))^2 = 810^9 N/C * (2010^-9 C) / (5/sqrt(2))^2 = 810^9 N/C
E4 = k * q4 / (5/sqrt(2))^2 = 810^9 N/C * (-1010^-9 C) / (5/sqrt(2))^2 = -410^9 N/C
So, E net = E1 + E2 + E3 + E4 = 410^9 N/C + (-810^9 N/C) + 810^9 N/C + (-410^9 N/C) = 0 N/C
Therefore, net electric field produced by the four particles at the square's center is zero.
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